compare concentric and eccentric contractions. concentric contractions occur when the muscle tension exceeds the load, and the muscle shortens. eccentric contractions occur when the muscle tension is less than the load, and the muscle elongates. concentric contractions consist of equal lengths of time contracting and relaxing. eccentric contractions consist of a longer time relaxing than contracting. concentric contractions occur when the tension produced never exceeds the load, and the muscle does not change length. eccentric contractions occur when the tension produced exceeds the load, and the muscle shortens. concentric contractions occur when the muscle tension is less than the load, and the muscle elongates. eccentric contractions occur when the muscle tension exceeds the load, and the muscle shortens. concentric contractions consist of equal lengths of time contracting and relaxing. eccentric contractions consist of a longer time contracting than relaxing.

The strength of an electric field in which a charged particle of 3.0 X 10-9 C is 0.05m from the test charge is \(\[3.6 \times 10^8 \, \text{N/C}\]\).

The strength of an electric field can be calculated using the formula:

Electric field strength (E) = Force (F) / Test charge (q)

In this case, we are given the charge of the test particle (\(\[q = 3.0 \times 10^{-9} \, \text{C}\]\)) and the distance from the test particle to the charge creating the electric field (r = 0.05 m).

The force between two charges can be calculated using Coulomb's Law:

Force \(\[(F) = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}}\]\)

where k is the electrostatic constant \(\[(k \approx 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2)\]\), q1 and q2 are the charges, and r is the distance between them.

In this scenario, we have a single charge creating the electric field, so q2 = 1 C (unit test charge). Substituting the given values into the formula, we get:

\(\[(F) = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}}\]\)

\(\[F = \frac{{(8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2) \cdot (3.0 \times 10^{-9} \, \text{C}) \cdot (1 \, \text{C})}}{{(0.05 \, \text{m})^2}}\]\)

Simplifying the equation gives us:

F ≈ 1.0792 N

Now, we can calculate the electric field strength:

E = F / q

\(\[E = \frac{{1.0792 \, \text{N}}}{{3.0 \times 10^{-9} \, \text{C}}}\]\)

E ≈ 359,733,333 N/C

Rounded to the appropriate number of significant figures, the strength of the electric field is approximately\(\[3.6 \times 10^8 \, \text{N/C}\]\).

Therefore, the correct answer is \(\[3.6 \times 10^8 \, \text{N/C}\]\)

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Answer:

Magnitude of the change in momentum = 0.45kgms-1

Force exerted = 1.13N

Explanation:

The magnitude of the change in momentum of the fly can be calculated using the equation Δp = mv, where m is the mass of the fly and v is the velocity of the fly. In this case, the fly has a mass of 0.30g and an initial velocity of 1.5ms-1. Therefore, the change in momentum of the fly is

Δp = (0.30g) x (1.5ms-1) = 0.45kgms-1.

The average force exerted by the web on the fly can be calculated using the equation F = Δp/Δt, where F is the average force, Δp is the change in momentum of the fly, and Δt is the time taken for the fly to come to rest. In this case, the change in momentum of the fly is 0.45kgms-1 and the time taken for the fly to come to rest is 0.40s. Therefore, the average force exerted by the web on the fly is

F = (0.45kgms-1)/(0.40s) = 1.13N.

A fighter jet being launched from such an aircraft carrier using a steam-powered catapult and its own engines. Its engines produce 2.3 x 105 N of thrust.

What speed is reached when a jet fighter aircraft is fired from a slingshot on an aircraft carrier?

42 m/s On an aircraft carrier, a catapult is used to launch a jet fighter. Just at end of the sling, it takes 2 seconds to achieve velocity of 42 m/s. What is the catapult's length if the acceleration is constant?

How strong is the aircraft carrier's catapult?

Catapults A 48,000-pound aeroplane was launched 300 feet and increased in speed from 0 to 165 miles an hour in two seconds by four steam-powered catapults. On every

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The magnitude of the tension T is = 60N

The mass of the object held at rest = 6kg

The angle of the object at rest is = 30°

The magnitude of force F acting vertically downwards = 410N

Acceleration due to gravity= 10m/s²

The magnitude of tension T = ?

Using the formula; 2T sin(α) = m × g

make T the subject of formula,

T = m × g/ 2sin(α)

T = 6 × 10/ 2 sin (30)

T= 60/2 × 0.5

T = 60/1

T= 60N

Therefore, the magnitude of the tension T is = 60N

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A 20.0 kg cannonball is fired from a cannon with a muzzle speed of 100 m/s at an angle of 20.0°. Using conservation of energy, the maximum height reached by the cannonball is approximately 510.2 meters.

A cannon ball weighing 20.0 kg is launched from a cannon with an initial velocity of 100 m/s at an angle of 20.0° above the horizontal.

To determine the maximum height reached by the cannonball using the conservation of energy principle, we consider the conversion of kinetic energy into gravitational potential energy.

Initially, the cannonball has only kinetic energy, given by the equation KE = (1/2)mv², where m is the mass and v is the velocity.

At the highest point of its trajectory, the cannonball has no vertical velocity, meaning it has no kinetic energy but possesses gravitational potential energy, given by the equation PE = mgh, where h is the height and g is the acceleration due to gravity (approximately 9.8 m/s²).

Using the conservation of energy, we equate the initial kinetic energy to the maximum potential energy:

(1/2)mv² = mgh

Canceling the mass and rearranging the equation, we find:

v²/2g = h

Plugging in the given values, we have:

(100²)/(2*9.8) = h

Simplifying the equation, we find:

h ≈ 510.2 m

Therefore, the maximum height reached by the cannonball is approximately 510.2 meters.

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Given that Star A and Star B are nearly the same distance from Earth. And, Star A is half as bright as Star B, Star B is twice as luminous as Star A. Option b.

The luminosity of a star is related to the star's size, temperature, and age. It is a measure of the total amount of energy emitted by the star every second. Therefore, if we know that two stars have the same distance from Earth and one is half as bright as the other, the only conclusion we can draw is that the star which is twice as luminous as star A is star B.

Hence, the correct option is as follows :Option (b): Star B is twice as luminous as Star A. There is no sufficient information available to determine which star is farther away or hotter or larger. Therefore, options (a), (c), and (d) are incorrect.

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One career that  believe benefits greatly from a degree in Psychology is Human Resources (HR). HR professionals are responsible for managing employee relations, recruiting, training, and ensuring compliance with labor laws and company policies.

A degree in Psychology can provide HR professionals with a deeper understanding of human behavior and the ability to better manage workplace dynamics.

Firstly, a degree in Psychology can help HR professionals understand and navigate the complexities of human behavior. HR professionals often deal with sensitive issues such as workplace conflict, discrimination, and harassment. A strong foundation in psychology can help HR professionals better understand the motivations and behaviors of employees, allowing them to handle these situations with greater sensitivity and compassion.

Secondly, psychology can help HR professionals develop effective communication and leadership skills. HR professionals are often responsible for training employees, providing feedback, and managing performance. A degree in Psychology can provide HR professionals with a deeper understanding of communication patterns and techniques, allowing them to better convey information to employees and resolve conflicts.

Lastly, a degree in Psychology can help HR professionals develop critical thinking and problem-solving skills. HR professionals often face complex issues that require careful analysis and creative solutions. Psychology provides a strong foundation in research methods, statistics, and analytical thinking, which can help HR professionals make informed decisions and develop effective policies.

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Answer:

crest

hope It helped you!

The term which cannot be used to describe a longitudinal wave is crest. Crests are formed in transverse waves.  Longitudinal waves are composed of rarefactions and compressions.

Unlike electromagnetic waves, mechanical waves only travels through a medium and through vacuum. There are two  types of mechanical waves namely, longitudinal waves and transverse waves.

In transverse waves, oscillation of particles is in a direction opposite to the wave propagation. In longitudinal waves, oscillation is along the wave propagation.

Transverse waves are composed of crests and troughs. Whereas, longitudinal waves are composed of regions of low pressure and regions of high pressures that are, rarefactions and compressions respectively.

Therefore, option D does not describes a longitudinal wave.

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Answer:   True

Explanation:

When drawing a vector, you should represent the magnitude of the vector by the length of the arrow is true.

What are vectors?
The term "vector" in mathematics and physics is used informally to refer to some values that cannot be stated by a single integer (a scalar) or to certain members of vector spaces. In the past, vectors were first used to represent quantities with both a magnitude and a direction, such as displacements, forces, and velocity, in geometry and physics (usually in mechanics). Similar to how distances, masses, and time are represented by real numbers, these quantities are represented by geometric vectors.

In some circumstances, tuples—finite sequences of numbers with a definite length—are sometimes referred to as vectors.

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Answer:

The USA, Liberia, and Myanmar (Burma) are the only countries that do not use the metric system

a ) When they reach the ground, rock B has greater velocity.

b ) Both rocks have the same acceleration

c ) Rock A and Rock B arrives at the same time

According to law of conservation of energy,

1 / 2 m u² + m g hi = 1 / 2 m v² + m g hf

u = 0

hf = 0

m g hi = 1 / 2 m v²

v = √ ( 2 g / m ) √ hi

v ∝ √ hi

a ) hi of rock A will be higher because it reaches a certain height above the ground which will be considered as initial height for rock A. So, the final velocity of rock A is higher.

b ) Both the rock are affected by only the force of gravity. So they will have the same acceleration of 9.8 m / s²

c ) If air resistance is ignored,

s = u t + 1 / 2 at²

For an object that is dropped,

u = 0

a = g

s = at² / 2

t = √ ( 2 s / g )

It can clearly be seen that no matter what height an object might be dropped from, if air resistance is ignore they will fall at the same time.

Therefore,

a ) When they reach the ground, rock B has greater velocity.

b ) Both rocks have the same acceleration

c ) Rock A and Rock B arrives at the same time

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The first-quarter moon and the third-quarter moon in the same lunar cycle are approximately 14.77 days apart.

In a lunar cycle, the moon goes through different phases, including the first-quarter and third-quarter phases. The first-quarter moon occurs about halfway between the new moon and the full moon, while the third-quarter moon occurs halfway between the full moon and the new moon. The average duration of a lunar cycle is approximately 29.53 days. Since the first and third-quarter moons are evenly spaced within the cycle, they are roughly 14.77 days apart. This duration can vary slightly due to the moon's elliptical orbit around the Earth.

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Answer:

Please find attached the required graph of the data points

The graph can be interpreted as showing that which was at rest starts  moving at a constant speed of 2 km/min

Explanation:

The table is presented as follows;

\(\begin{array}{lcl}Time \ (min)&& Distance \ (km)\\0&&0\\5&&10\\10&&20\\15&&30\\20&&40\\25&&50\\30&&60\end{array}\)

The graphic representation of the above data can be created by plotting the Time on the x-axis and the Distance on the y-axis on a graph paper

The graph of the data can be created also using a spreadsheet application such as MS Excel by using the Chart function under the Insert menu, after selecting the points input into cells on the spreadsheet as shown in the attached drawing

The distance travelled by the car in a given time is found by obtaining the rate of change of the values of the graph, m, as follows;

\(m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

Where (y₁, x₁), and (x₂, y₂) are a pair of chosen points on the given line

When, the chosen points are (y₁, x₁) = (0, 0), and (x₂, y₂) = (30, 60), we get;

\(m =\dfrac{60 \, km-0 \, km}{30 \, min-0 \, min} = 2 \, km/min\)

The graph can be interpreted as showing that the rate of change of the distance travelled by the car per  unit time which is the speed of the car starting from rest is 2 km/min

Answer: Does this help???

The centripetal force is required.

The centripetal force is 243.47 N.

m = Mass of runner = 78.6 kg

v = Velocity of runner = 8.8 m/s

r = Radius = 25 m

Centripetal force is given by

\(F_c=\dfrac{mv^2}{r}\\\Rightarrow F_c=\dfrac{78.6\times 8.8^2}{25}\\\Rightarrow F_c=243.47\ \text{N}\)

The centripetal force is 243.47 N.

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Answer:

reflected by clouds so a is correct

Answer:

This answers idReflected by clouds

The type of galaxy that has a stellar disk but without gas and dust is an **elliptical galaxy**.

Elliptical galaxies are characterized by their smooth and featureless appearance, lacking the distinct spiral arms seen in disk galaxies like the Milky Way. They are composed mostly of old stars and have little to no ongoing star formation. As a result, they have depleted their interstellar gas and dust reservoirs over time, leaving behind primarily stellar populations. Elliptical galaxies can vary in size from small to massive, and their shape ranges from nearly spherical to elongated ellipsoids. They are commonly found in dense regions of galaxy clusters, where interactions and mergers between galaxies have stripped away their gas and disrupted their original disk structures.

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The chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level of measurement.

In statistics, the level of measurement refers to the nature and properties of the data being collected. There are four levels of measurement: nominal, ordinal, interval, and ratio. Nominal and ordinal levels are considered categorical, while interval and ratio levels are considered numerical. The chi-square test is specifically designed for analyzing categorical data, where the observations can be classified into distinct categories or groups. It is used to determine whether there is a significant association or relationship between two categorical variables.

The test calculates the difference between the observed frequencies and the expected frequencies under the assumption of independence between the variables. It compares the observed and expected frequencies using a chi-square statistic and determines the p-value to assess the statistical significance of the association. Therefore, the chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level because it deals with categorical data and evaluates the relationship between different categories or groups.

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a. The distribution of the random variable X is a binomial distribution.

b. The expected value E(X) is 5.

c. The probability that none of the computers in the batch of 100 are defective is approximately 0.006 or 0.6%.

a. The distribution of the random variable X, representing the number of defective computers in a batch of 100, follows a binomial distribution.

b. The expected value E(X) of a binomial distribution can be calculated using the formula:

E(X) = n * p

where n is the number of trials (100 computers) and p is the probability of success (defective rate of 5% or 0.05).

E(X) = 100 * 0.05 = 5

Therefore, the expected value of X is 5.

c. To find the probability that none of the computers in the batch of 100 are defective, we need to calculate the probability of zero successes (defective computers) in a binomial distribution.

The probability of zero successes can be calculated using the formula:

P(X = k) = (n C k) * p^k * (1 - p)^(n - k)

where (n C k) represents the binomial coefficient, n is the number of trials, p is the probability of success, and k is the number of successes.

In this case, k = 0, n = 100, and p = 0.05.

P(X = 0) = (100 C 0) * 0.05⁰* (1 - 0.05)⁽¹⁰⁰⁻⁰⁾

The binomial coefficient (100 C 0) is equal to 1, and any number raised to the power of 0 is 1.

P(X = 0) = 1 * 1 * (0.95)¹⁰⁰

P(X = 0) ≈ 0.006

Therefore, the probability that none of the computers in the batch of 100 are defective is approximately 0.006 or 0.6%.

d. To find the probability that at least 4 computers in the batch of 100 are defective, we need to calculate the cumulative probability of the binomial distribution from 4 to 100.

P(X ≥ 4) = 1 - P(X < 4)

To calculate P(X < 4), we can sum up the probabilities for X = 0, 1, 2, and 3

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

We have already calculated P(X = 0) in part c.

P(X = 1) = (100 C 1) * 0.05^1 * (1 - 0.05)^(100 - 1)

P(X = 2) = (100 C 2) * 0.05^2 * (1 - 0.05)^(100 - 2)

P(X = 3) = (100 C 3) * 0.05^3 * (1 - 0.05)^(100 - 3)

Summing up these probabilities will give us P(X < 4).

Finally, subtracting P(X < 4) from 1 will give us P(X ≥ 4).

The calculations for P(X = 1), P(X = 2), and P(X = 3) can be quite involved, but you can use a binomial calculator or software to get the precise values.

a. The distribution of the random variable X is a binomial distribution.

b. The expected value E(X) is 5.

c. The probability that none of the computers in the batch of 100 are defective is approximately 0.006 or 0.6%.

d. The probability that at least 4 computers in the batch of

100 are defective can be calculated by subtracting P(X < 4) from 1.

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Answer:

wavelength is λ=fv=440340=0. 77m.

Answer:

from 0 to 20 m/s

a = ( v- u)/t

a = (20 - 0)/7

a = 20/7 =2.9m/s^2

from 30m/s to 0m/s

a = (0-30)/10

a = -30/10

a= -3 m/s^2

Answer: True

Answer:

When sunlight shines through an orange solution, the violet, blue and green wavelengths are absorbed. The other colors pass through. The transmitted light is the light we see, and it looks orange. Colored objects look the way they do because of reflected light.

Explanation:

The wavelength of an electromagnetic wave that has a frequency of 3 kHz is 100 km.

The speed of electromagnetic waves in a vacuum is known to be 3 × 10⁸ meters per second. To calculate the wavelength of an electromagnetic wave, we'll need to use the equation: c = fλ, Where c is the speed of light, f is the frequency of the wave, and λ is the wavelength. Here is the equation rearranged for λ:λ = c / f. Now we can insert the values given into the formula and solve for λ.λ = c / fλ = 3 × 10⁸ m/s ÷ 3 kHz. Since the units need to be in the same type, we will convert kHz to Hz as follows:3 kHz = 3,000 Hz. So we can now substitute f into the formula:

λ = 3 × 10⁸ m/s ÷ 3,000 Hzλ = 100,000 meters or 100 km

Electromagnetic waves are transverse waves with a combination of electrical and magnetic fields. Their speed is a constant 3 × 10⁸ meters per second in a vacuum. The distance between two successive crests of an electromagnetic wave is known as the wavelength. The wavelength of an electromagnetic wave that has a frequency of 3 kHz is the calculation we've performed above, which is equal to 100 km. Radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays are all examples of electromagnetic waves. Electromagnetic radiation is energy that travels through space in the form of a wave and exhibits wave-like behavior. It has a speed of 3 × 10⁸ meters per second in a vacuum and does not need a medium to propagate. The frequency of the wave determines its wavelength, and this relationship is inversely proportional. As a result, as frequency increases, wavelength decreases, and vice versa.

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Answer:

lado

Explanation:

because it is easy to do

Answer:

E' = Qa/4πε[√(a² + z²)]³

Explanation:

Since the non-conducting plate is symmetric, a small charge element dq generates an electric field dE at a distance R from itself and a distance z above the center of the plate. Since the plate is symmetric, we only have the vertical component of the electric field acting at the center so dE' = dEcosθ where θ is the angle between R and the plate.

So, dE' = dEcosθ = dqcosθ/4πεR²

Let σ represent the surface charge density of the plate. So, for a small elemental area dA, dq = σdA.

Substituting this into dE' we have

dE' = σdAcosθ/4πεR²

Also cosθ = a/R where a is half the length of side of the plate of side length, 2a.

So, dE' = σdAa/4πεR³

Also R² = a² + z²

R = √(a² + z²)

So,  dE' = σdAa/4πε[√(a² + z²)]³

Now, dA = dxdy

dE' = σadxdy/4πε[√(a² + z²)]³

So, the total electric field at z is obtain by integrating dE'

E' = ∫dE' = ∫σadxdy/4πε[√(a² + z²)]³ = σa∫dxdy/4πε[√(a² + z²)]³

We integrate dx and dy from -a to a.

So,

E' = σa[2a][2a]/4πε[√(a² + z²)]³

E' = σa³/πε[√(a² + z²)]³

Since the total chare Q = σA where A is the are of the plate. A = (2a)² = 4a²

Q = σA = 4σa²

σ = Q/4a²

substituting σ into E', we have

E' = (Q/4a²)a³/πε[√(a² + z²)]³

E' = Qa/4πε[√(a² + z²)]³

In materials such as metals the outer most electrons are loosely bound and therefore their movement is chaotic, this allows for the transportation of energy in form of electricity therefore, this materials are good conductors. The statement is true.

Answer:

The value of the water pressure force on the window is 150,000 N.

Wartość siły nacisku wody na okno wynosi 150000 N.

Explanation:

English Translation

The submarine window has an area of ​​0.3 m2 and is located at a depth at which the pressure exerted by the water column is 500 kPa. Finish the sentence. The value of the water pressure force on the window is.

Solution.

Pressure exerted by a force on a surface area perpendicular to the line of action of that force is given by the formula

P = (F/A)

where F = applied force, in this case, water pressure force on the window = ?

A = Area upon which the force is acting = Area of the window = 0.3 m²

P = 500 kPa = 500,000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

In Polish/Po Polsku

Ciśnienie wywierane przez siłę na pole powierzchni prostopadłe do linii działania tej siły jest określone wzorem

P = (F / A)

gdzie F = przyłożona siła, w tym przypadku siła nacisku wody na okno =?

A = Obszar, na który działa siła = Powierzchnia okna = 0,3 m²

P = 500 kPa = 500000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

Answer:

12 121 J

Explanation:

PE gained each time = m g h

  now 30 times:        30  mgh = 30 * 68.6 * 9.8 * .601 = 12 121 J

Answer: 12121.2084

Explanation:

Studies of sunquakes, or helioseismology, have revealed that our mathematical models of the solar interior are fairly accurate. The correct option is (B).

Helioseismology is the study of the Sun's internal structure and dynamics by analyzing its oscillations.

These oscillations, often referred to as sunquakes, are caused by sound waves trapped and bouncing within the Sun. By studying the properties and behavior of these waves, scientists can gain valuable insights into the solar interior.

Through helioseismology, scientists have found that our mathematical models of the Sun's interior, based on principles of physics and stellar evolution, align quite well with the observed data.

The oscillation patterns and frequencies detected from the Sun match the theoretical predictions, providing confidence in our understanding of the Sun's internal structure, composition, and energy generation mechanisms.

A) the Sun vibrates only on the surface.

Helioseismology studies have revealed that the Sun vibrates not only on its surface but throughout its interior as well. Therefore, option A is incorrect.

Overall, helioseismology has contributed significantly to our knowledge of the Sun's dynamics and has validated our mathematical models, making option B the correct answer.

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