Complete and balance each of the following equations for acid-base reactions.
HC2H3O2(aq)+NaOH(aq)→

Answer: 2.4e+24

Explanation:

It could just as easily have been selected to be 1/24th of the mass of one atom of a carbon atom, or 1/10th the mass of a calcium atom, A sample of 250 grams is equivalent to 1.58 moles of potassium permanganate.

Answer:

the answer to this is non impact

The value of ΔG at 25 °C for the given reaction is: ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol So, the correct answer is -370.4 kJ/mol

To determine the value of ΔG (Gibbs free energy) at 25 °C for the given reaction:

25 (s, rhombic) + 3/2 \(O_2\)(g) → \(2SO_3\)(g)

We can use the equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG is the standard Gibbs free energy change

ΔG° is the standard Gibbs free energy change under standard conditions

R is the gas constant (8.314 J/(mol·K) or 0.008314 kJ/(mol·K))

T is the temperature in Kelvin (25 °C = 298 K)

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants at a given point during the reaction.

Given that ΔG° is -370.4 kJ/mol, we can plug the values into the equation:

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(Q)

Now, we need to determine the value of Q. Since all reactants and products are in their standard states, Q = 1, as their concentrations are taken to be 1.

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(1)

Since ln(1) = 0, the term (0.008314 kJ/(mol·K) * 298 K) * ln(1) becomes 0.

Therefore, the value of ΔG at 25 °C for the given reaction is:

ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol

So, the correct answer is -370.4 kJ/mol.

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The kJ of the energy absorbed for the every mole of the carbon reacted is 104.8 kJ.

The chemical equation is as :

2C + 2H ---> C₂H₄   ,     ΔH = + 52.4 kJ/mol

The ΔH is the enthalpy change that is determined by the subtracting the energy of the reactants to the products.

The  ΔH = energy of the products - energy of the reactants

The expression for the energy is as :

q = n ΔH

Where,

n = number of the moles

ΔH = enthalpy change

The kJ of the energy absorbed for the every mole of the carbon reacted :

q = 2 mol × 52.4 kJ/mol

q = 104.8 kJ

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Taking into account the Brønsted-Lowry acid-base theory, HPO₄⁻² is conjugate base of H₂PO₄⁻.

The Brønsted-Lowry acid-base theory (or the Brønsted-Lowry theory) identifies acids and bases based on whether the species accepts or donates protons or H⁺.

According to this theory, acids are proton donors while bases are proton acceptors.

So, reactions between acids and bases are H⁺ proton transfer reactions, causing the acid to form its conjugate base and the base to form its conjugated acid by exchanging a proton.

In other words, a conjugate base is an ion or molecule resulting from the acid that loses the proton, while a conjugate acid is an ion or molecule resulting from the base that gains the proton:

acid + base ⇄ conjugate base + conjugate acid

In this case, you know:

H₂PO₄⁻ + NH₃ → HPO₄⁻² + NH₄⁺

H₂PO₄⁻ behaves like acid because donates an H⁺ proton while NH₃ behaves like base because accepts an H⁺ proton from the acid.

So, NH₄⁺ is the conjugate acid of the NH₃ and HPO₄⁻² is conjugate base of H₂PO₄⁻.

In summary, HPO₄⁻² is conjugate base of H₂PO₄⁻.

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The oceans are fundamental because provide oxygen, climate regulation, and food and medicines.

The term ocean resources make reference to the sources of energy and materials obtained from the ocean.

The ocean produces more than 50% oxygen we can breathe from the air and also absorbs carbon dioxide.

The ocean is also fundamental in climate regulation to dissipate heat from the equator to the North and South poles.

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(a) The mass of hydrogen sulfide produced in the reaction is 9.44 g.

(b) Water is the limiting reagent in the given reaction.

Al2S3 + 6H2O ---> 2Al(OH)3 + 3H2S

mass of water in the reaction = 6(18 g/mol) = 108 g/mol

mass of hydrogen sulfide in the reaction: = 3(34) = 102 g/mol

108 g/mol of H2O ------- > 102 g/mol of H2S

10 of H2O -----------> ?

= 9.44 g

Aluminum sulfide will be completely consumed by the reaction while some fraction of water will remain. Thus, water is the limiting reagent in the given reaction.

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Answer:

True

Explanation:

They are actually the same

The answer is False.

The oxidation number is the number of electrons removed or added to an element or compound. This is also equal to the charge on the ion.

For example, if Sodium atom loses one electron, it becomes oxidized to the + 1 state.

Na → Na⁺ + e⁻.

So, the oxidation number of Sodium is the charge on the Sodium ion which is + 1.

So, the oxidation number is equal to the charge on the ion.

So, the answer is False.

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Since then, it has spread to other rivers, colonized them, clogged the water intake pipes, and competed with local species for food. Zebra mussels are the method for removing a lot of plankton from the water column.

The Caspian Sea in Asia is where zebra mussels, or Driessen polymorpha, are found naturally. They arrived in the Great Lakes region in the late 1980s via ballast water from a transatlantic ship. The Great Lakes, Mississippi, Tennessee, Hudson, and Ohio river basins were all overrun by these mussels within ten years. The lake's brilliant blue hue is a result of Tahoe's clean air and water. There is more to this phenomenon than just the fact that Lake Tahoe's surface reflects the sky, which contributes to its blue color.

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Answer:

The answer is True.

To verify if an equation is balanced, you have the count each one of the present atoms on both sides of it. Let's count on each one of the options until finding the one that's balanced:

A.

The Ag and the K are not balanced.

B.

It means that this equation is balanced.

The answer is B.

Answer: 160

Explanation:

Answer:150/ms behfhefjioweufioefwebveour

First, we need to write out the balanced chemical equation for the reaction: 4 KO2 + 2 CO2 → 2 K2CO3 + 3 O2

From the equation, we can see that 4 moles of KO2 react with 2 moles of CO2 to produce 3 moles of O2. Therefore, we need to convert the given masses of KO2 and CO2 into moles:

moles of KO2 = 2.61 g / molar mass of KO2 = 2.61 g / 71.10 g/mol = 0.0367 mol
moles of CO2 = 4.46 g / molar mass of CO2 = 4.46 g / 44.01 g/mol = 0.1013 mol

Next, we need to determine the limiting reagent (the reactant that will be completely consumed in the reaction) by comparing the mole ratios of KO2 and CO2 in the balanced equation. The ratio of moles of KO2 to moles of CO2 is:
0.0367 mol KO2 / 4 mol KO2 per 2 mol CO2 = 0.0184 mol CO2

Since this ratio is less than the actual number of moles of CO2 we have (0.1013 mol), CO2 is in excess and KO2 is the limiting reagent.

Using the mole ratio from the balanced equation, we can calculate the number of moles of O2 produced:

moles of O2 = 3 mol O2 per 4 mol KO2 × 0.0367 mol KO2 = 0.0275 mol O2

Finally, we can convert the moles of O2 to grams:

mass of O2 = moles of O2 × molar mass of O2 = 0.0275 mol × 32.00 g/mol = 0.88 g
Therefore, 2.61 g of KO2 and 4.46 g of CO2 would produce 0.88 g of O2.

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1) Plasma. This is called the fourth state of matter. It is characterized because part of its particles is charged. In order to maintain the ionization, high temperatures are needed.

According to this information, plasma is a superheated gas.

Answer:

The retention factor would be high

Explanation:

The retention factor can be affected by the temperature, or affected by the composition of the solvent, when the FM are liquid.

Heptene is a derivative of the distillation of oil, it is a chemical compound that is made up of seven carbons, that is why it begins with the prefix hept.

The minimum entropy change of the heat-supplying source is -0.87 kJ/K.

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.

S₁ = 1.485  +  (0.1)(5.6865) = 2.0537 kJ/kg K

The entropy at the final state given the new 40-% quality:

S₂ = 1.4337  +  (0.4)(5.7894) = 3.7495 kJ/kg K

m₁ = 0.026/(0.001057   +  0.1 x 1.002643) = 0.257 kg

m₂ = 0.026/(0.001053   +  0.4 x 1.158347)  = 0.056 kg

ΔS + S₁  - S₂  + S₂m₂  - S₁m₁  -  sfg(m₂  -  m₁)  > 0

ΔS + 2.0537 -  3.7495 + (3.7495 x 0.056)  -   (2.0537 x 0.257)  - 5.6865( 0.056 - 0.257)  >  0

ΔS > -0.87 kJ/K

Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.

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The reaction of 2-Bromo-2-Ethyl-3-Methylbutane with methanol is an example of a nucleophilic substitution reaction.

In this reaction, the methanol molecule acts as a nucleophile and attacks the carbon atom of the bromoalkane, resulting in the displacement of the leaving group (bromine) and the formation of a new carbon-oxygen (C-O) bond.

The reaction mechanism can be described as follows:

Protonation: In the first step, the methanol molecule acts as a base and abstracts a proton from the sulfuric acid catalyst to form the methoxide ion (CH3O-).

Nucleophilic attack: The methoxide ion then attacks the carbon atom of the bromoalkane, which is electrophilic due to the electron-withdrawing effect of the bromine atom. The attack results in the formation of a transition state in which the carbon-bromine bond is weakened and the carbon-oxygen bond is forming.

Elimination: The transition state then collapses to form the product, methylethylmethylcarbinol, with the simultaneous loss of the bromide ion. This step is known as the elimination step and occurs as the newly formed C-O bond is more stable than the weakened C-Br bond.

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The mole ratio of acid to base when neutralizing hydrochloric acid with sodium hydroxide is 1:1. A mole of NaOH would completely neutralize one mole of HCl.

The mole ratio would be 2:1 if the hydrochloric acid and barium hydroxide were to be combined instead. Assuming they react in a 1:1 ratio in accordance with the balanced neutralization equation, the moles of acid and base are identical at the equivalence point in a neutralization. Using the reaction between solutions of hydrochloric acid and sodium hydroxide as an example, let's examine how a neutralization reaction creates both water and a salt. This reaction's general equation is NaOH + HCl H2O and NaCl.

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A good example of equilibrium would be the mixing of oil and water in a closed container.

Chemical equilibrium is a condition in which the concentrations of components of a chemical reaction remain unchanged and have no tendency to change.

Of all the options, the only one where the concentrations of the component reactants cannot change is a mixture containing oil and water in a closed container.

Oil and water are immiscible and thus, their concentrations remain constant.

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Answer:

The total energy absorbed is 32.171 kilojoules.

Explanation:

The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:

\(Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]\) (1)

Where:

\(m\) - Mass of the ice, in kilograms.

\(c_{i}\) - Specific heat of ice, in kilojoules per kilogram-degree Celsius.

\(c_{w}\) - Specific heat of water, in kilojoules per kilogram-degree Celsius.

\(L_{f}\) - Latent heat of fusion, in kilojoules per degree Celsius.

\(T_{1}\) - Initial temperature of water, in degrees Celsius.

\(T_{2}\) - Fusion point of water, in degrees Celsius.

\(T_{3}\) - Final temperature of water, in degree Celsius.

\(Q\) - Total energy absorbed, in kilojoules.

If we know that \(m = 50.5\times 10^{-3}\,kg\), \(c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}\), \(c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}\), \(L_{f} = 334\,\frac{kJ}{kg}\), \(T_{1} = -15\,^{\circ}C\), \(T_{2} = 0\,^{\circ}C\) and \(T_{3} = 65\,^{\circ}C\), then the total energy absorbed is:

\(Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right]\)\(Q = 32.171\,kJ\)

The total energy absorbed is 32.171 kilojoules.

Answer:

the average speed of \(V_{av} CO_2\) is 5.24 ×  104 cm/s

Explanation:

The computation of the average speed of a \(CO_2\) is as follows:

\(\sqrt{average} = \sqrt{\frac{8 RT}{\pi M} }\)

where,

M = Molar mass

\(V_{av} = \frac{\sqrt{1}}{M}\)

Given that

\(V_{av} \ of\ oxygen= 6.14 \times 10^4 cm/s\)

The molar mass of oxygen i.e. (MO_2) = 31.9988 g/mol

And, the molar mass of CO_2 is  44.0098 g/mol

Now

\(\frac{V_{av} CO_2}{V_{av} O_2} = \frac{\sqrt{M_{O2} }}{M_{CO2}}\)

Now place these values to the above formula

\(\frac{V_{av}CO_2}{6.14\times 104 cm/s} = \frac{\sqrt{31.9988} }{44.0098}\)

So,

V_av CO_2 is 5.24 ×  104 cm/s

hence, the average speed of \(V_{av} CO_2\) is 5.24 ×  104 cm/s

Answer:

x = 5 and y =4

Explanation:

An alkane is a hydrocarbon of general molecular formula CnH2n+2. The general formula for balancing the combustion equation of any alkane is;

CnH2n+2 + 3n+1/2O2 ------> nCO2 + (n+1) H2O

Where n is the number of carbon atoms in the alkane.

In C3H8 , n=3 so;

C3H2(3)+2 + 3(3)+1/2O2 ------> 3CO2 + (3+1) H2O

Then;

C3H8 + 5O2  ------> 3CO2 + 4H2O

Therefore;

x = 5 and y =4

Answer:

The density of the gas will increase.

Explanation:

From the Charles's law of Ideal gases, we know that, if the pressure is constant, the behavior of the gas will be represented like:

So, if the temperature of a gas is increased, the volume of the gas will decrease, because temperature and volume (in the charles's law, that is with constant pressure) are inversely proportional.

Now, to analyze what happens with the density, we can see the density formula:

So, if the volume of the gas decrease, the density of the gas will increase, because in the density formula, volume and density are inversely proportional.

Finally, if the temperature of a gas is increased and the pressure is held constant, the density of the gas will increase.

Glycolysis and photosynthesis are fundamental processes that are necessary for the survival of living organisms. They are similar in that they both involve the conversion of energy, but differ in the source of energy used, the location of the process, and the requirement for oxygen.

Glycolysis and photosynthesis are two necessary fundamental processes. Glycolysis is a metabolic pathway that occurs in the cytoplasm of cells. The glycolysis process is necessary because it produces ATP, which is the energy required for all cellular activities.

The energy is produced by breaking down glucose into two pyruvate molecules.Photosynthesis is the process by which green plants make their food. During photosynthesis, light energy is converted into chemical energy, which is stored in glucose molecules. This process is also necessary as it provides food and oxygen for most living organisms to survive.In terms of similarities, both glycolysis and photosynthesis are processes that involve the conversion of energy.

In glycolysis, glucose is converted into pyruvate and ATP, while in photosynthesis, light energy is converted into chemical energy. Both processes are also vital to the survival of living organisms.The primary difference between the two processes is the source of energy used. Glycolysis uses glucose as the primary energy source while photosynthesis uses light energy from the sun.

Glycolysis occurs in the cytoplasm of cells while photosynthesis takes place in the chloroplasts of plant cells. Glycolysis is an anaerobic process that does not require oxygen, while photosynthesis is an aerobic process that requires oxygen and releases it as a byproduct.

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The mass of water produced when 9.60 g of butane reacts with excess oxygen is 14.85 gram.

The chemical reaction between substances, usually considering oxygen and usually accompanied by the generation of heat and light in the form of flame is called as combustion reaction.

C4H10(g) + 13 /2 O2(g) → 4CO2(g) + 5H2O(l)

Moles of butane = 9.60⋅g / 58.12⋅g⋅mol−1

= 0.165mol.

We assume complete combustion, and know that each mole of butane gives off 5 mol of water upon combustion.

Given that we know the molar quantity of butane, we simply perform the operation,

= 5 × 0.165 × 18.01

= 14.85 gram

Thus, the mass of water produced when 9.60 g of butane reacts with excess oxygen is 14.85 gram.

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The correct option is (g) i.e. 10 is the sum of all the stoichiometric coefficients in the balanced chemical equation for the reaction given in the question.

To find the sum of all the stoichiometric coefficients in a balanced chemical equation, we need to add up all the coefficients in front of the chemical formulas on both sides of the equation.

The balanced chemical equation for the reaction of aluminium with platinum (IV) nitrate is:

2 Al + 3 Pt(NO3)4 ---> 2 Al(NO3)3 + 3 Pt

The sum of all the stoichiometric coefficients is

2 + 3 + 2 + 3 = <<2+3+2+3=10>>10.

Therefore, the answer is (g) i.e. 10.

Stoichiometry coefficients is based on the law of conservation of mass, which states that the sum of the masses of the reactants and products must be equal to one another. This insight led scientists to the conclusion that the ratio of positive integers is frequently produced by the relationships between the amounts of the reactants and products. This implies that the amount of the product may be determined if the amounts of the various reactants are known. However, if the quantity of one reactant is known and the quantity of the products can be established using empirical data, the quantity of the other reactants can likewise be computed. Stoichiometry is founded on some basic rules, which make it simpler to understand. These laws include the law of conservation of mass, the law of definite proportions (also known as the law of constant composition), the law of multiple proportions, and the law of reciprocal proportions.

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