complete and balance the following half-reaction: o2(g)→h2o(l)(acidic solution)

Answer:

C

Explanation:

view the Attached photo i added to see how i got that answer

Answer:

B is the outer part atom .

The outermost regions of the atom are called electron shells and contain the electrons (negatively charged). The atoms have different properties based on the arrangement and number of their basic particles.SO the hydrogen atom (H) contains only one proton, one electron, and no neutrons

Explanation:

The statement that identifies an oxidation-reduction reaction is a reaction in which oxidation numbers change (option C).

A redox or oxidation-reduction reaction is a chemical reaction in which some of the atoms have their oxidation number changed.

In a chemical reaction that involves oxidation and reduction, the oxidation number of the involved ions either decreases or increases.

Therefore, the statement that identifies an oxidation-reduction reaction is a reaction in which oxidation numbers change.

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The current atmospheric concentration of carbon dioxide is 40 in 250 years ago

Long-term changes to weather patterns and temperatures are a result of climate change.

The use of fossil fuels (such as coal, oil, and gas), which release heat-trapping gases, has been the primary cause of climate change since the 250s, despite the fact that these changes are natural.

Global warming is the long-term increase in the planet's average temperature.

Even while there has been a long-term warming trend, the usage of fossil fuels over the past century has caused the pace of acceleration to increase.

The usage of fossil fuels has expanded along atmospheric concentration  with the global population.

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Answer:

The nucleus is a collection of particles called protons, which are positively charged, and neutrons, which are electrically neutral. Protons and neutrons are in turn made up of particles called quarks. The chemical element of an atom is determined by the number of protons, or the atomic number, Z, of the nucleus.

Answer:

THE CORRECT ANSWER IS D

Explanation:

A, B, and C are incorrect. I took the test so I know. Hope this helps

When we bring a magnet near the doorbell when it is not connected to the battery, we feel a pull, or an attractive force.

For this the hypothesis can be:

Hypothesis: If there is no permanent magnet in the doorbell, just metal like iron, then when we bring a paper clip to the doorbell, we will observe an attractive force between the paper clip and the doorbell due to the interaction between the magnet and the iron in the doorbell.

Hypothesis: If there is a permanent magnet in the doorbell, then when we bring a paper clip to the doorbell, we will observe a stronger attractive force between the paper clip and the doorbell due to the interaction between the magnet and the metal components (such as iron) in the doorbell.

Thus, these can be the Hypothesis for the given scenario.

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The synthetic organic chemist who successfully synthesized physostigmine was Robert Burns Woodward.

He was an American organic chemist who is considered by many to be the preeminent organic chemist of the twentieth century. Woodward's synthesis of physostigmine, an alkaloid found in the Calabar bean, was an important milestone in modern organic chemistry. Physostigmine works by obstructing acetylcholine metabolism. The enzyme that breaks down acetylcholine in the synaptic cleft of the neuromuscular junction, acetylcholinesterase, is inhibited in a reversible manner by this substance.Woodward's method of synthesizing physostigmine was the first successful total synthesis of a complex natural product, and it established the precedent for modern organic synthesis.

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Aluminum ion has a charge of 3+, Al³⁺, and sulfate is SO₄²⁻, so the compound aluminum sulfate has to have a number of aluminum and sulfate such that the final charge is zero, so the proportion on aluminum sulfate is:

That way we have 6+ and 6-, so neutral compound.

This means that for 1 mol of aluminum sulfate, we have 2 moles of aluminum ion. The molar concentration is the number of moles of solute divided by the volume of solution, so it is directly proportional to the number of moles.

So, we can use a rule of three as follows:

aluminum ion --- aluminum sulfate

2 --- 1

x --- 0.646 M

So:

So, the concentration of aluminum ion in this solution is 1.292 M.

Based on the given information, the enzyme produced the most oxygen at 40 °C.

Enzymes are biological catalysts that facilitate biochemical reactions. They are sensitive to temperature, and their activity can be influenced by changes in temperature. Generally, enzymes have an optimal temperature at which they exhibit maximum activity.

In the given experiment, the enzyme's oxygen production was measured at different temperatures: 10 °C, 80 °C, 21.5 °C, and 40 °C. The highest oxygen production was observed at 40 °C, indicating that the enzyme had the highest activity and efficiency at this temperature.

At lower temperatures, the enzyme's activity may be slower due to reduced kinetic energy, while at higher temperatures, the enzyme may become denatured and lose its catalytic ability.

Therefore, based on the results of the experiment, the enzyme produced the most oxygen at 40 °C.

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The total masses of benzoic acid and sodium benzoate needed to make 100 ml of a benzoic acid/sodium benzoate buffer with a pH of 4.30 will be 12.21 g and 11.19 g, respectively.

To make 100 ml of a benzoic acid/sodium benzoate buffer with a pH of 4.30, we need to determine the amount of benzoic acid and sodium benzoate that needs to be added.

Let's assume that the initial concentration of benzoic acid

(Ka = \(6.5 \times 10^{-5}\)) is C1

and the final concentration of benzoic acid (C2) and sodium benzoate (C3) is equal.

Then the [H3O+] = Ka x \(\frac{C_2^{2}}{C_1}\)

= >\(6.5 \times 10^{-5}\) x  \(\frac{C_2^{2}}{C_1}\)

The buffer pH is 4.30, so the [H3O+] = \(10^{-4.3}\)

The ratio of [HA]/[A-] = 0.78,

so [A-] = 0.78 x [HA]

[H3O+] =\(Ka \times \frac{ [A-]^2} {[HA]}\)

=\(\frac { 6.5 \times 10^{-5} x 0.78^2} { [HA] }\)

= \(\frac { 4.7 \times 10^{-4} \times [HA] } {[A-]}\)

= [HA] / 0.78 [A-]

[H3O+] x [A-] / [HA]

= \(\frac {4.7 \times 10^{-4} \times [A-] } {0.78 [HA] }\)

= \(10^{-4.3}\)

[A-] =\(\frac { 10^{-4.3} \times 0.78 [HA]} {4.7 \times 10^{-4}}\)

[HA] = \([A-] \times \frac{ 4.7 x 10^{-4} } {0.78 \times 10^{-4.3}}\)

Let's assume that [HA] = C1 = 1 M (1 mole/L).

Then [A-] = 0.78 [HA]

= 0.78 M (0.78 mole/L)

The total moles of benzoic acid in 100 ml of buffer solution (n1) = C1 x V1 = 1 M x 0.100 L = 0.100 moles.

The total moles of sodium benzoate in 100 ml of buffer solution (n2) = C3 x V2 = 0.78 M x 0.100 L = 0.078 moles.

The mass of benzoic acid (m1) = n1 x molar mass of benzoic acid = 0.100 moles x 122.12 g/mol = 12.21 g

The mass of sodium benzoate (m2) = n2 x molar mass of sodium benzoate = 0.078 moles x 144.11 g/mol = 11.19 g

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An unknown gas diffuses half as fast as nitrogen the molecular mass of the unknown gas is approximately 7 g/mol.

The rate of diffusion of a gas is inversely proportional to the square root of its molecular mass, according to Graham's law of effusion. Therefore, we can use the following formula to solve the problem:

Rate of diffusion = k / sqrt(molecular mass)

where k is a constant of proportionality.

If the unknown gas diffuses half as fast as nitrogen, then its rate of diffusion is 1/2 that of nitrogen. Therefore, we can write:

Rate of diffusion of unknown gas = (1/2) x Rate of diffusion of nitrogen

Let's assume that nitrogen has a molecular mass of M, and the unknown gas has a molecular mass of m. Then, we can write:

(1/2) x (k / sqrt(m)) = k / sqrt(M)

Simplifying this equation, we get:

sqrt(m) / sqrt(M) = 1 / 2

Cross-multiplying, we get:

2 sqrt(m) = sqrt(M)

Squaring both sides, we get:

4m = M

Therefore, the molecular mass of the unknown gas is one-fourth that of nitrogen. If we know the molecular mass of nitrogen, we can easily calculate the molecular mass of the unknown gas.

The molecular mass of nitrogen is approximately 28 g/mol. Therefore, the molecular mass of the unknown gas is:

m = M/4 = 28/4 = 7 g/mol

Thus, the molecular mass of the unknown gas is approximately 7 g/mol.

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Answer:

i think its solar radiation

According to fundamental thermodynamics, a material has more thermal energy the hotter it is. The heat required to raise the heat content of one mole of material by precisely one degree Celsius is known as the heat capacity or Cp. Here the specific heat of the metal is -0.312 J / g°C. The correct option is A.

The amount of energy needed to raise a material's heat content by precisely 1°C per gram is known as specific heat or Csp. Therefore, a substance's heat capacity is the amount of heat needed to raise its overall temperature by one degree.

The heat capacity is known as the specific heat capacity or the specific heat if the substance's mass is unity.

The equation is:

q = m × cΔT

c = q / mΔT

2421.6 / 90.0 (28.9 - 115.0) = -0.312 J / g°C

Thus the correct option is A.

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The name of adenine when connected to the deoxyribose sugar and a phosphate is "C) adenosine monophosphate."

When adenine is connected to the deoxyribose sugar and a phosphate, its name becomes "C) adenosine monophosphate."

Adenine is one of the four nitrogenous bases found in DNA and RNA. When adenine is connected to the deoxyribose sugar and a phosphate group, it forms a nucleotide known as adenosine monophosphate (AMP).

AMP consists of three components:

The combination of these three components forms adenosine monophosphate (AMP), which is a nucleotide involved in various cellular processes and serves as a building block for the synthesis of RNA.

Therefore, the correct answer is "C) adenosine monophosphate."

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Answer:

Explanation:

Driving a car (burning gas is a chemical change) and almost all the plastics we use are made by chemical reactions of different components.

193 grams of NaCl are needed to make 1.50 L of a 2.20-M NaCl solution.

Calculation of the mass of NaCl required:

The only thing we need to know is that a solution's molarity informs us of the exact amount of moles of solute that are contained in 1 L of a solution.

In this situation, a NaCl (sodium chloride) solution with a 2.20-M concentration will have 2.20 moles of the solute (sodium chloride) in every 1 L of the solution.

The solution's molarity of 2.20 M requires that every 1 L of this solution include 2.20 moles of sodium chloride, which implies that every 1.50 L of this solution needs to contain

\(1.5 L solution .\frac{2.20 moles NaCl}{1L solution} = 3.30 moles NaCl\)

Utilize the compound's molar mass to translate the amount of NaCl (sodium chloride) in moles to grams.

\(3.30 moles NaCl . \frac{58.4 gm}{1 mole NaCl} = 192.7 gm\) ≈ 193 gm

Therefore it is concluded that the final answer is 193 gm.

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Answer:

P3O6

Explanation:

Tri=3 Hex=6

1. Cl2 + H2O → HOCl + HCl

2. Tooth decay starts when when the pH of the mouth is lower than 5.5. Tooth enamel is made up of calcium phosphate and it is one of the hardest substances of the body. But it is corroded when the pH is less than 5.5. The bacteria of our mouth produce acids by degradation of sugar and food particles remaining in our mouth after eating food.

3. Fluorine salts are added in toothpaste to protect our teeth from tooth decay. Fluorine salts are mildly basic, so they neutrelise the acid in our mouth that leads to tooth decay.

4. Tincture of iodine is iodine, pottasium iodide and sodium iodide dissolved in ethanol. Iodine acts in an antiseptic manner by destroying microbial proteins and DNA.

5. Tincture of iodine is clear and reddish brown liquid.

Increasing LED brightness with a lampshade or reflection and choosing LED lights with high luminous efficiency can be useful  to obtain a brighter lamp.

Lamp, lighting device, initially a jar housing a flame soaked in flammable substance, and later such light-producing devices as gas and electrical lamps.

The light was developed at least 70,000 years ago. Originally, it was a sunken rock filled in moss or other absorbent substance, saturated in animal fat, and burned. The ways to obtain a brighter lamp are

Increasing LED brightness with a lampshade or reflection.

To boost brightness, use greater color temperature LED lights.

Choosing LED lights with high luminous efficiency.

With increased voltage, LED lights get brighter.

Therefore, in above ways we can get brighter lamp.

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Answer:

9.68x10^21 molecules of nitrogen

Explanation:

I will assume that r.t.p. is supposed to be STP, Standard Temperature and Pressure.  rtp might refer to room temperature and pressue, but no value is given for room temperature, so let's assume standard temperature (0 degrees Celsius).  Here is a marvelous, and useful, property of gasses at STP:  One mole of gas at STP occupies 22.4 liters.  Let's make that a conversion factor:  (1 mole/22.4 liters).

We have the volume of gas at STP:  360 cm^3.  Convert that into liters:

(360cm^3)*(1 ml/cm^3)*(1 liter/1000 ml) = 0.360 liters(L)

Now use the conversion factor from above to convert the volume of gas into moles of gas:

 (0.360L)*(1 mole/22.4 liters) = 0.0161 moles of gas

By definition, 1 mole is 6.02x10^23 particles, or molecules of the gas.

Convert moles of the gas to molecules:

(0.0161 moles)*((6.02x10^23 molecules)/mole) = 9.68x10^21 molecules of nitrogen.

Answer:

the answer is wurkey churkey since the birdy is really really cute

Explanation:

if the birdy was not squishy then it would have died already?!?!?

When one mole of the sulfur allotrope with eight sulfur atoms is burned to form sulfur trioxide, 12 moles of molecular oxygen are consumed. The correct answer is option (c) 12. The balanced chemical equation of the combustion of a sulfur ring containing eight sulfur atoms is: S₈ + 12O₂ → 8SO₃

This equation shows that one mole of the sulfur ring (S₈ ) reacts with 12 moles of molecular oxygen (O₂) to produce 8 moles of sulfur trioxide (SO₃).

The combustion of one mole of elemental sulfur in the form of a ring of eight sulfur atoms (S₈ ) to produce sulfur trioxide (SO₃) requires the consumption of molecular oxygen (O₂). To determine the number of moles of O₂ consumed, we need to first write the balanced chemical equation for this reaction: S₈ + 12O₂ → 8SO₃

Here, one mole of S₈  reacts with 12 moles of O₂ to produce 8 moles of SO3. In the given question, we have one mole of S₈. Therefore, to find the number of moles of O₂ consumed, we can use the stoichiometry from the balanced equation: 1-mole S₈  × (12 moles O2 / 1-mole S₈ ) = 12 moles O₂

So, when one mole of the sulfur allotrope with eight sulfur atoms is burned to form sulfur trioxide, 12 moles of molecular oxygen are consumed. The correct answer is option (c) 12.

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To find the specific heat capacity of the metal, we need to use the equation:

q = mcΔT

Where q is the heat transferred, m is the mass of the metal, c is the specific heat capacity of the metal, and ΔT is the change in temperature.

First, we need to find the heat transferred (q) from the metal to the water. We can use the equation:

q = mwater x cwater x ΔTwater

Where mwater is the mass of the water, cwater is the specific heat capacity of water (4.18 J/g°C), and ΔTwater is the change in temperature of the water.

Using the given values, we have:

q = (10.0 g) x (4.18 J/g°C) x (23.83°C - 22.00°C)
q = 88.75 J

Next, we can use the same equation to find the mass of the metal:

q = mm x cm x ΔTm

Where mm is the mass of the metal and ΔTm is the change in temperature of the metal. We know that the initial temperature of the metal was 100.00°C, so ΔTm = 100.00°C - 23.83°C = 76.17°C.

Substituting the given values, we have:

88.75 J = (5.19 g) x cm x (76.17°C)
cm = 0.193 J/g°C

Therefore, the specific heat capacity of the metal is 0.193 J/g°C.

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Answer:

The iron present in the solution is reduced because of the presence of SCN⁻ ions in solution

Explanation:

The clue in this problem is the color of the solution:

A solution of Fe³⁻ is yellow but when the Fe³⁺ is reduced by an oxidant to Fe²⁺ the solution change to orange color.

The SCN⁻ ion is a reducing agent than, in presence of a substance that can be reducted as Fe³⁺ ion will promote the reaction. That means the best explanation is:

Answer:

- 24549091

Explanation:

At low temperatures, the system cannot compensate for the unfavorable ΔH with the increase in entropy. Hence, the process becomes nonspontaneous.

A process is spontaneous when the total entropy change (ΔS) is positive and the total enthalpy change (ΔH) is negative. Therefore, the condition in which a process is spontaneous at high temperatures and nonspontaneous at low temperatures is when ΔH is negative and ΔS is positive. At high temperatures, the positive value of ΔS dominates, leading to a spontaneous process. However, at low temperatures, the negative value of ΔH dominates, resulting in a nonspontaneous process. This is because, at low temperatures, the system cannot compensate for unfavorable ΔH with the increase in entropy. Hence, the process becomes nonspontaneous.

Endothermic reactions are those in which heat is produced as a result of the absorption of energy. After the reaction, the reaction mixture typically cools.The temperature drops. An endothermic reaction has a positive sign (H). Exothermic reaction H is negative because energy in the form of heat is emitted during the freezing of the liquid ethanol. As a result of the conversion of liquid to solid during freezing, entropy and randomness both decrease, and as a result, S is negative.

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Answer: do you syill need help on it i am happy to help

Explanation: TELL ME

Explanation:

We have to balance the following equation:

__ H₂O + __ F₂ -------> __ HF + __ O₂

First we have to determine the number of atoms of each element that we have on both sides of the equation.

__ H₂O + __ F₂ -------> __ HF + __ O₂

O: 1 O: 2

H: 2 H: 1

F: 2 F: 1

We have 2 atoms of O on the right side and 1 atom of O on the left side. To balance the O atoms we can change the coefficient for H₂O and write a 2 in front of it.

2 H₂O + __ F₂ -------> __ HF + __ O₂

O: 2 O: 2

H: 4 H: 1

F: 2 F: 1

Then we have 4 atoms of H on the left and 1 atom of H on the right side of the equation. We can change the coefficient for HF to balance the H atoms.

2 H₂O + __ F₂ -------> 4 HF + __ O₂

O: 2 O: 2

H: 4 H: 4

F: 2 F: 4

And finally we have 2 atoms of F on the left and 4 atoms of F on the right. We can change the coefficient for F₂ and write a 2 there.

2 H₂O + 2 F₂ -------> 4 HF + __ O₂

O: 2 O: 2

H: 4 H: 4

F: 4 F: 4

The equation is balanced.

Answer: 2 H₂O + 2 F₂ -------> 4 HF + O₂