complete equation for combustion of 3-methylheptane​

This experiment shows that the elements of pure solid substance in a system closed off from the surroundings has increased temperature very fast.

Pure substances are substances that are built up of only one kind of particle and have a fixed or abiding structure. Pure substances are further confidential as elements and compounds. An element is a substance that comprises only one type or kind of atom. a pure substance has a constant chemical composition.

No affair where you sample a substance, it is the same. For chemistry, the safest examples of pure substances are elements and compounds. So, examples cover gold, silver, helium, sodium chloride, and pure water.

So we can conclude that In chemistry, a pure substance is an element or compound made up of one type of particle.

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Answer:

Meteorology

Explanation:

Meteorology focuses on Earth's atmosphere and, especially, how changes in the atmosphere affect weather and climate on Earth's surface.

Answer:

chloroplast photosynthesis

Explanation:

Photosynthesis is the process by which green plants create their own food by turning light energy into chemical energy. ... Cellular respiration, on the other hand, is the process by which living things convert oxygen and glucose to carbon dioxide and water, thereby yielding energy.

Hi!

\(\\ \sf\rightarrow pH=-log[H^+]\)

\(\\ \sf\rightarrow -log[H^+]=6.1\)

\(\\ \sf\rightarrow log[H^+]=-6.1\)

\(\\ \sf\rightarrow [H^+]=10^{-6.1}\)

\(\\ \sf\rightarrow [H^+]=7.94M\)

Answer:

\(\boxed {\boxed {\sf Almost \ all \ phosphates \ are \ insoluble}}\)

Explanation:

For magnesium phosphate to make an aqueous solution, it must be soluble in water.

Let's check the solubility rules. There are many different lists and versions, but it should mention a rule about phosphates.

Magnesium phosphate is included in "all phosphates" so it is insoluble and can't become an aqueous solution.

Magnesium Phosphate (Mg₃(PO₄)₂) would not make an aqueous solution because it is insoluble in water.

A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.

According to the solubility rule, all phosphates are insoluble in water except sodium and potassium phosphates and thus magnesium phosphate does not form an aqueous.

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Answer:

15.32 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 3.83 days

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Time (t) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Number of half-lives (n) =?

N = N₀ / 2ⁿ

14.06 = 225 / 2ⁿ

Cross multiply

14.06 × 2ⁿ = 225

Divide both side by 14.06

2ⁿ = 225 / 14.06

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 3.83 days

Number of half-lives (n) = 4

Time (t) =.?

n = t / t½

4 = t / 3.83

Cross multiply

t = 4 × 3.83

t = 15.32 days

Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days

The equilibrium constant has a definite value for every reversible reaction at a particular temperature. It varies with change in temperature. The equilibrium constant for the reaction is 2.92. The correct option is B.

The equilibrium constant can be defined as the ratio of the product of molar concentrations of the products to that of the reactants with each concentration term raised to a power equal to its coefficient in a balanced chemical equation.

The equation of the equilibrium constant is:

Keq = Kf / Kb

Kf - Forward rate constant

Kb - Backward rate constant

2.38 × 10⁻⁴ /  8.15×10⁻⁵

Keq  = 2.92

Thus the correct option is B.

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The other compound that makes up most of the other gases in the table is water vapor.

Water vapor is not listed in the table because it is not a pollutant. However, it is a significant component of exhaust gas, and it can contribute to smog formation. Water vapor is formed when the fuel in a petrol engine is burned. The combustion process produces water as a byproduct.

The amount of water vapor in the exhaust gas depends on the temperature of the combustion process. At higher temperatures, more water vapor is produced. Water vapor is not a pollutant in itself, but it can contribute to smog formation.

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Complete question:

this table shows the percentages of some gases in the exhaust from a petrol engine

nitrogen 68

carbon dioxide 15

carbon monoxide 1

oxygen 0.75

nitrogen oxides 0.24

hydrocarbons 0.005

sulphur dioxide 0.005

other gases

what is the name of the other compound that makes up most of the other gases in the table?

NO₂ is the limiting reactant.

The theoretical yield is 77.38 grams.

Given the balanced chemical reaction as shown below:

We are to find the theoretical yield of HNO₃ and the limiting reactant. To find the limiting reactant, we need to calculate the moles of each reactant and divide them by the total moles in the reaction.

For the moles of Oxygen:

For the moles of water

Determine the moles of NO₂

Since the compound with the least amount of moles is 0.307 moles, hence NO₂ is the limiting reactant.

Determine the mass of HNO₃(theoretical yield)

Hence the mass of HNO₃ produced is 77.38 grams.

Answer &

Explanation:

eukaryotic: Having complex cells in which the genetic material is contained within membrane-bound nuclei. cell: The basic unit of a living organism, consisting of a quantity of protoplasm surrounded by a cell membrane, which is able to synthesize proteins and replicate itself.

therefore it is cell

Answer:

If the reaction is zero order, the rate constant has exactly the same units as the rate of the reaction mol L-1 s -1.

If the reaction is first order, then the concentration of one reactant takes care of the units of concentration, thus the rate constant is simply given in units of reciprocal time, s-1.

If the reaction is second order, then two units of concentration are already present so the rate constant needs reciprocal time plus inverse units of concentration, L mol-1 s-1.

If the reaction is third order, the rate constant should have units of L2 mol-2 s-1.

For a first order reaction, the unit of the rate constant is  s^–1 while for  a second order reaction, the unit of the rate constant is M∙s^–1.

The accurate order of reaction can only be determined from experimental values. We have the following orders of reactions;

For a first order reaction, the unit of the rate constant is  s^–1 while for  a second order reaction, the unit of the rate constant is M∙s^–1.

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Answer:

Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.

Explanation:

Answer:

CuSO4·xH2O is a hydrated copper(II) sulfate compound where x represents the number of water molecules associated with each copper(II) sulfate molecule.

To determine the value of x, we need some additional information, such as the mass of the hydrated compound or the percentage of water by mass.

For example, if we have the mass of the hydrated compound, we can use it to determine the mass of copper(II) sulfate and the mass of water. Then, we can use the molar mass of CuSO4 and H2O to calculate the number of moles of each substance. Finally, we can use the molar ratios to find the value of x.

Let's take an example: suppose we have 5 grams of CuSO4·xH2O and upon heating, we found that 1.25 grams of water is lost. We can use this information to calculate the value of x as follows:

Calculate the mass of copper(II) sulfate:

mass of CuSO4 = mass of CuSO4·xH2O - mass of water lost

mass of CuSO4 = 5 g - 1.25 g

mass of CuSO4 = 3.75 g

Calculate the number of moles of copper(II) sulfate:

moles of CuSO4 = mass of CuSO4 / molar mass of CuSO4

moles of CuSO4 = 3.75 g / 159.61 g/mol (molar mass of CuSO4)

moles of CuSO4 = 0.0235 mol

Calculate the number of moles of water:

moles of H2O = mass of water lost / molar mass of H2O

moles of H2O = 1.25 g / 18.02 g/mol (molar mass of H2O)

moles of H2O = 0.0693 mol

Use the molar ratio of CuSO4 to H2O to find the value of x:

moles of H2O / moles of CuSO4 = x

0.0693 mol / 0.0235 mol = x

x = 2.95

Therefore, in this example, the value of x is approximately 2.95, which means that each copper(II) sulfate molecule in the hydrated compound is associated with approximately 2.95 water molecules

Explanation:

If any Wrong Comment on this I edit it. Thank You

It is equal to epsilon busy when we discuss birds. Very is the way things are done. The moller observed bees constantly. The person sees theconcentration. The concentration of the solution has a direct correlation to observable behavior. We should take a copper sulfate solution, proper salve and eight pen. The blue solution is of copper sulfate hydrate. It's local resolution? As the solution is blue. Its maximum absorption is shown. Go to the red region and read the electrical signals. There is a direct correlation between the concentration and the observing. We have provided the volume of the copper sulfate solution, so we have to find the concentration. The copper sulfate solution has a volume of 50 liter. What mass of copper self should be added to the stock solution of discovered separate solution is zero. Recovery is needed to prepare the stock solution, stock solution itself. We know the mass of copper sulfate is required. After finding the stock solution, we have to do the diluting. We have to applaud the standard curve to explain the beads lock at a different dilution first, as we have provided with the volume concentration, we can find the malls by using it. There is a relation to the direction. charity is equal to mass by solar mass of the substance into 1000 by volume, if you write the equation formula. The values were replaced in this equation. Concentration of capital or polarity is what it is. What mass of copper sulfate is added to the stock solution if it is zero? The mass of copper sulfate has to be found and divided by the volume of Ml to arrive at the molar mass. The stock solution has 250. It is to 50 liter. The mass of copper sulfate is equal to 12 point 475 by solving this. The mass of copper sulfate needed to prepare the stock solution is equal to 12.47 g. The simple volumetric equation can be used with stock solution of copper sulfate. The young man is equal to the other one. 15 zero point one moller dilution is required to prepare the stock solution concentration 0.2 molar. All these other things. They have to make a small amount of this. Money is equal to this by using it. The stock solution's polarity is zero 0.2 Into. What amount of stock solution should be added to make up the 50ml? There is a 0.1 solution. The revolution can be done with 0.1 and the volume required. The man is 50. Even is equal to 0.1. They don't point by this so we will get 25. The stock selection is required. We will see more of that. To prepare for these revolutions, we have to use the same equation and money. 0.25 Molar is a standard concentration. The stock solution concentration is determined by the volume added to it. The man is the solution. So it is equal to 0.05 into 50. Well.5 women will be given for this volume of stock solution queries by women. 0.2 is the stock solution concentration, we will be for this one. Everyone is equal to one point. In the everyone is equal to 0.025 into mhm divided by zero, we will get dilution volume of 6.25. Volume of stock solution needed is explained. The final dilution is five and make. 0.2 stop solution concentration into Even is equal to 0.0125 into So even is equal to 0.0 1-5 in two D. The volume of stock solution needs three 125mm. Hope you found something useful.

The relationship between observable behavior and solution concentration is direct.

Solution is defined as a continuous variation of two or more substances in their relative proportions up to what is known as the limit of solubility. An aqueous solution that has more OH-ions than H+ ions is referred to be a basic solution.

The volume of the copper sulfate solution is 50 liters.

To determine the molar mass, the mass of copper sulfate must be determined and divided by the volume of Ml.

250 are in the stock solution. It contains 50 liters.

By solving this, we obtain that the mass of copper sulfate is equal to 12 point 475.

12.47 g of copper sulfate are required to create the stock solution.

It is five and make for the final dilution. Even is equal to 0.0125 into 0.2 stop solution concentration, so even is equal to 0.0 1-5 in two D.

Three 125mm are required for the volume of stock solution.

Thus, the relationship between observable behavior and solution concentration is direct.

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Answer:

148.04 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

NO(g) + 1/2 O₂(g) → NO₂(g)      ΔH°rxn = -114.14 kJ/mol

We can find the standard enthalpy of formation (ΔH°f) of NO(g) using the following expression.

ΔH°rxn = 1 mol × ΔH°f(NO₂(g)) - 1 mol × ΔH°f(NO(g)) - 1/2 mol × ΔH°f(O₂(g))

ΔH°f(NO(g)) = 1 mol × ΔH°f(NO₂(g)) - ΔH°rxn - 1/2 mol × ΔH°f(O₂(g)) / 1 mol

ΔH°f(NO(g)) = 1 mol × 33.90 kJ/mol - (-114.14 kJ) - 1/2 mol × 0 kJ/mol / 1 mol

ΔH°f(NO(g)) = 148.04 kJ/mol

Answer:

To resolve this, we need to place the coefficient “2” in front of the sodium in the reactant, to give the equation shown below. 2 Na (s) + Cl 2 (g) → 2 NaCl (s) In this equation, there are two sodiums in the reactants, two sodiums in the products, two chlorines in the reactants and two chlorines in the products; the equation is now balanced.

Explanation:

The element that has the following electronic configuration are :

a) the atomic number of selenium is 34. the electronic configuration is given as :

electronic configuration : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰  4p⁴

b) the atomic number of bromine is 35 . the electronic configuration is given as :

electronic configuration : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰  4p⁵

c) the atomic number of krypton is 36 . the electronic configuration is given as :

electronic configuration : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰  4p⁶

d)  the atomic number of francium is 87. the electronic configuration is given as :

electronic configuration : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰  4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d¹⁰ 6p⁶ 7s¹

Thus, The element that has the following electronic configuration are :

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10.0 g of ethanol would require more heat to raise the temperature by 10.0°C Because it has a higher boiling point.

The boiling point of a liquid is the temperature at which the vapour pressure of the liquid becomes equal to the atmospheric pressure of the liquid’s environment. At this temperature, the liquid is converted into a vapour.

The normal boiling point is high for liquids with strong intermolecular attractions and low for liquids with weak intermolecular attractions.

10.0 g of ethanol would require more heat to raise the temperature by 10.0°C because it has a higher boiling point.

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Answer:

D. no definite shape or. definite volume

Explanation:

Gases do not have a definite shape or volume because the molecules in gases are very loosely packed, they have large intermolecular spaces and hence they move around. The particles of solid are closely packed and occupy less space while particles of gases are loosely packed and occupy the complete space available.

In 4.38 × 10^21 molecules of water, there are approximately 0.073 moles.

To calculate the number of moles, we can use Avogadro's number, which states that 1 mole of a substance contains 6.022 × 10^23 molecules. So, by dividing the given number of molecules (4.38 × 10^21) by Avogadro's number, we can find the number of moles.

Now, let's explain the process in detail. Avogadro's number is a constant that represents the number of particles (atoms, molecules, etc.) in one mole of a substance. It is approximately 6.022 × 10^23. Therefore, if we divide the given number of molecules by Avogadro's number, we can determine the number of moles.

In this case, we divide 4.38 × 10^21 molecules by 6.022 × 10^23 molecules/mole, resulting in approximately 0.073 moles.

Significant figures play an important role in reporting the answer. The given number of molecules has three significant figures (4, 3, and 8), so our answer should be reported with three significant figures as well. Therefore, the number of moles is approximately 0.073.

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The pressure equilibrium constant for the reaction, 4HBr (g) + \(O_{2}\) (g) -------> 2Br2 (g) + 2H2O (g) is,

              \(K_{P}\) = \(P_{Br2^{2} }\) . \(P_{H20^{2} }\) / \(P_{HBr^{4} }\) . \(P_{O2}\)

The equilibrium constant is a variable that describes a chemical reaction's tendency to proceed to completion. All the reactants are converted to products. The equilibrium is the point at the reaction at which the conversion of reactants into products equals the conversion of products back into reactants. The Hydrogen bromide and oxygen react to form bromine and water.  The reaction can be written as,

          4HBr (g) + \(O_{2}\) (g) -------> 2Br2 (g) + 2H2O (g)

pressure equilibrium constant expression can be written as,

             \(K_{p}\)  = pressure of the product / pressure of the reactant

             \(K_{P}\) = \(P_{Br2^{2} }\) . \(P_{H20^{2} }\) / \(P_{HBr^{4} }\) . \(P_{O2}\)

Equilibria increases in the number of gaseous molecules represented in the equilibrium equation. If the number of gaseous molecules does not change both equilibrium constants are dimensionless quantities. The equilibrium constant is not dependent on pressure.

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Enzymes are specialized proteins which can speed the reactions to a very great extent and thereby acts as efficient catalysts. The enzyme activity depends on pH and temperature.

The biological catalysts which catalyze the chemical reactions taking place inside the cells and are capable of acting independently on the cells are defined as the enzymes.

Enzymes catalyze and control several chemical reactions that occur in our living cells. They helps in digestion, liver function, breathing, reproduction, nerve function, etc. The enzyme urea catalyzes the hydrolysis of urea.

The enzyme activity is sensitive to the temperature changes. All the enzymes shows maximum catalytic activity at optimum temperature. They are found to be denatured by heat and hence their activity is destroyed at high temperatures.

Thus at high temperature the enzymes will be inactive and this will affect the vital organs and lead to death.

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Answer:

Br > Se > Ge > K> Ca

Explanation:

Generally in the periodic table, we know that electron affinity increases across a period. Electron affinity refers to the energy released when an extra electron is added to a neutral gaseous atom. Most times, the addition of an electron leads to the formation of a uninegative ion.

The sequence of decrease in electro affinity values appears to be consistent until we get to calcium and potassium. One would have ordinarily expected potassium to have a lower electron affinity than calcium. However, if potassium accepts an electron, that electron goes on to fill the 4s level. This process is more exothermic than in the case of calcium where the extra electron is added to the 3d level. The energy difference between the 4s and 3d levels is enough to make the process less exothermic (only 2.37KJmol-1) compared to that of potassium (48.4 KJmol-1). This explains the order of arrangement seen in the answer above.

Answer:

CaCO₃(s) => CaO(s) + CO₂(g) ... GpIIA Decomp

Explanation:

Metallic Carbonates decompose into a metallic oxide and carbon dioxide.

Examples:

Na₂CO₃(s) => Na₂O(s) + CO₂(g) ... GpIA Decomp

MgCO₃(s) => MgO(s) + CO₂(g) ... GpIIA Decomp

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Based on the role of ubiquitin in protein deconstruction as stated in the passage, the correct options are as follows:

Phrases refers to a group of words which contains a verb but which on their own do not make complete sense.

In the description of the role of Ubiquitin, it is described as a small polypeptide chain containing 76 amino acids. The main tole of ubiquitin is to tag proteins for deconstruction in the proteasomes.

Therefore, the phrase describes the purpose of ubiquitin is to tag waste proteins for recycling in the proteasomes; option A.

Based on the passage, the statement that describes the overall consequence of proteins containing mutations is: Wastes will build up in vital organs, and the organism will experience disease; option D

Individuals with spinocerebellar ataxia experience loss of muscle control, even though the ataxin-1 protein builds up only in the brain and spinal cord because the neurons affected by the ataxin-1 protein buildup are in a region of the brain that manages muscle control; option D.

In conclusion, mutations in ubiquitin-tagged proteins will result in accumulation in the body since they cannot be deconstructed in the proteasomes.

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Answer:

b. Hydrofluoric acid/sodium fluoride (pKa=3.14).

Explanation:

Hello!

In this case, since the buffer capacity is related to how good a buffer behaves under the addition of acidic or basic substances in the light of holding the pH as constant as possible, we need to keep in mind that the best buffer must have a pKa as close as possible to the desired pH, that is, if the desired pH here is 3.20, we must pick the acid/base pair which the pKa cosest to 3.20.

In such a way, since b. Hydrofluoric acid/sodium fluoride (pKa=3.14 ) and c. Nitrous acid/sodium nitrite (pKa=3.34) have a pKa close to 3.20, the closest one is b. Hydrofluoric acid/sodium fluoride pKa=3.14 which is 0.06 pH units away from the desired pH, therefore the answer is b. Hydrofluoric acid/sodium fluoride pKa=3.14.

Best regards!

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.