compute the limits of the following sequence : (a) Yn : Zi. Boleti (6) Zn · Note thatn! : IX 2 * 3x ... Xy is the factorial of n! 2n n!

The solutions to the equations are

1. x = 4

2. x = -12

3. x = 0 and x = 4

The solutions to the inequalities are

4. -5 < x < 1

5. x ≤ -3 and x ≥ 4

From the question, we have the following equations

1. 4x + 6 = 8x - 10

2. -3/4x - 2 = -1/2x + 1

3. |4 - 2x| + 5 = 9

Next, we split the equations to 2

So, we have

1. y = 4x + 6 and y = 8x - 10

2. y = -3/4x - 2 and y = -1/2x + 1

3. y = |4 - 2x| + 5 and y = 9

Next, we plot the system of equations (see attachment) and write out the solutions

The solutions are

1. x = 4

2. x = -12

3. x = 0 and x = 4

From the question, we have the following inequalities

4. x² + 4x - 5 < 0

5. x² - x - 12 ≥ 0

Next, we plot the system of inequalities (see attachment) and write out the solutions

The solutions are

4. -5 < x < 1

5. x ≤ -3 and x ≥ 4

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The output when the given pseudocode is executed with A = 5 and B = 3 will be "25, 16, 9, 4, 1".

The given pseudocode includes a loop that iterates as long as A is greater than or equal to B. In each iteration, the square of A is displayed, and A is decremented by 1. We are asked to determine the output when A is initially 5 and B is 3.

Step 1: Initialization

A is set to 5 and B is set to 3.

Step 2: Iteration 1

Since A (5) is greater than or equal to B (3), the loop executes.

The square of A (5²) is displayed, resulting in the output "25".

A is decremented by 1, so A becomes 4.

Step 3: Iteration 2

A (4) is still greater than or equal to B (3).

The square of A (4²) is displayed, resulting in the output "16".

A is decremented by 1, so A becomes 3.

Step 4: Iteration 3

A (3) is still greater than or equal to B (3).

The square of A (3²) is displayed, resulting in the output "9".

A is decremented by 1, so A becomes 2.

Step 5: Iteration 4

A (2) is still greater than or equal to B (3).

The square of A (2²) is displayed, resulting in the output "4".

A is decremented by 1, so A becomes 1.

Step 6: Iteration 5

A (1) is still greater than or equal to B (3).

The square of A (1²) is displayed, resulting in the output "1".

A is decremented by 1, so A becomes 0.

Step 7: Loop termination

Since A (0) is no longer greater than or equal to B (3), the loop terminates.

Therefore, The output generated by the code execution will be "25, 16, 9, 4, 1" as the squares of A (starting from 5 and decreasing by 1) are displayed in each iteration of the loop.

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The slope between point X and point C is also 2/3.

Since triangle ABC is similar to triangle XYC, we know that the corresponding angles of the two triangles are equal. Therefore, angle A in triangle ABC is equal to angle X in triangle XYC.

Both triangles have their hypotenuses lying on AX. Therefore, the ratio of the lengths of the hypotenuses is equal to the ratio of the lengths of the sides opposite these hypotenuses. That is,

AC/AB = XC/XY

We know that AC/AB = 2/3 from the given information. Therefore,

2/3 = XC/XY

Since the coordinates of points C and X are not given, we cannot determine their slope directly. However, we know that the slope between point A and point C is 2/3 from the given information.

Since triangle ABC is similar to triangle XYC, we can conclude that the slope between point X and point C is the same as the slope between point A and point C. Therefore, the slope between point X and point C is also 2/3.

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Answer:

Total book in the book case=42 books

Step-by-step explanation:

Bottom three shelves

First shelf= one book taken

Second shelf=two books taken

Third shelf=3 books taken

Total books taken=1+2+3

=6 books

All taken books are placed on the top fourth shelf

Top fourth shelf=6 books

The quantity of books on all the shelves became equal when 6 books are placed on the top fourth shelf.

This means, there are 6 books in each shelf

Total shelves=bottom 3 shelves+ top 4 shelves

=3+4

=7 shelves

The book case has 7 shelves in total.

Each book shelf has 6 books

Total books in the book case=7 shelves × 6 books

=42 books

Answer:What do you need help with?   My name is woods245 and whatever you need help with?

Step-by-step explanation:

The advantages of the superposition theorem compared to other circuit theorems are its simplicity and modularity in circuit analysis, as well as its applicability to linear circuits.

Superposition theorem is a powerful tool in circuit analysis that allows us to simplify complex circuits and analyze them in a more systematic manner. When compared to other circuit theorems, such as Ohm's Law or Kirchhoff's laws, the superposition theorem offers several advantages. Here are two key advantages of the superposition theorem:

Simplicity and Modularity: One major advantage of the superposition theorem is its simplicity and modular approach to circuit analysis. The theorem states that in a linear circuit with multiple independent sources, the response (current or voltage) across any component can be determined by considering each source individually while the other sources are turned off. This approach allows us to break down complex circuits into simpler sub-circuits and analyze them independently. By solving these individual sub-circuits and then superposing the results, we can determine the overall response of the circuit. This modular nature of the superposition theorem simplifies the analysis process, making it easier to understand and apply.

Applicability to Linear Circuits: Another advantage of the superposition theorem is its applicability to linear circuits. The theorem holds true for circuits that follow the principles of linearity, which means that the circuit components (resistors, capacitors, inductors, etc.) behave proportionally to the applied voltage or current. Linearity is a fundamental characteristic of many practical circuits, making the superposition theorem widely applicable in real-world scenarios. This advantage distinguishes the superposition theorem from other circuit theorems that may have limitations or restrictions on their application, depending on the circuit's characteristics.

It's important to note that the superposition theorem has its limitations as well. It assumes linearity and works only with independent sources, neglecting any nonlinear or dependent sources present in the circuit. Additionally, the superposition theorem can become time-consuming when dealing with a large number of sources. Despite these limitations, the advantages of simplicity and applicability to linear circuits make the superposition theorem a valuable tool in circuit analysis.

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Answer:

So, the probability of selecting a number from 1 to 100 that is divisible by 5 or 7 is 0.32.

Hope this helped!

Answer:

1/125

Step-by-step explanation:

(1/5)³ = 1/125

1³ = 1

5³ = 125

Answer:

Step-by-step explanation:

this looks like  1/5 * 1/5 * 1/5

multiply the tops ( numerators) and the bottoms (denominators)

tops are 1

bottoms are 125

1/125  

:)

Answer:

0

Step-by-step explanation:

First you find what f(4) is equal to then you plug that into g(x), so in this situation f(4)=4 so we then look at g(4), which is equal to 0

Answer:

let,

x=ky

y=39 when x=7 so,

7=39k

or, k=7/39

now, when x=22

22=7y/39

or, y=39×22/7

or, y=858/7

or, y=122.57 (rounded to the nearest hundredth)

Answer:

y=2

Step-by-step explanation:

Hey there!

The answer is y=2 because the x-axis is not defined (there's no value for it as the line didn't pass through it)

The Niagara Falls incline railway rises vertically by approximately 98 feet.

The angle of elevation of 30° indicates the angle between the incline railway and the horizontal ground. The total length of the incline railway is given as 196 feet.

To find the vertical rise, we can use trigonometry. The vertical rise can be determined by calculating the sine of the angle of elevation and multiplying it by the total length of the incline railway:

Vertical rise = Total length × sine(angle of elevation)

Vertical rise = 196 ft × sin(30°)

Vertical rise ≈ 196 ft × 0.5

Vertical rise ≈ 98 ft

Therefore, the Niagara Falls incline railway rises vertically by approximately 98 feet.

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The end of the plank is sliding along the ground at a rate of approximately -0.08 m/s when it is 1.4 meters from the wall of the building. The negative sign indicates that the end of the plank is sliding in the opposite direction.

To find how fast the end of the plank is sliding along the ground, we can use related rates. Let's consider the position of the end of the plank as it moves along the ground.

Let x be the distance between the end of the plank and the wall of the building, and y be the distance between the end of the plank and the ground. We are given that dx/dt = 0.26 m/s, the rate at which the worker pulls the rope.

We can use the Pythagorean theorem to relate x and y:

x² + y² = 5²

Differentiating both sides of the equation with respect to time, we get:

2x(dx/dt) + 2y(dy/dt) = 0

At the given moment when x = 1.4 m, we can substitute this value into the equation above and solve for dy/dt, which represents the rate at which the end of the plank is sliding along the ground.

2(1.4)(0.26) + 2y(dy/dt) = 0

2(0.364) + 2y(dy/dt) = 0

0.728 + 2y(dy/dt) = 0

2y(dy/dt) = -0.728

dy/dt = -0.728 / (2y)

To find y, we can use the Pythagorean theorem:

x² + y² = 5²

(1.4)² + y² = 5²

1.96 + y² = 25

y² = 23.04

y = √23.04 ≈ 4.8 m

Substituting y = 4.8 m into the equation for dy/dt, we have:

dy/dt = -0.728 / (2 * 4.8) ≈ -0.0757 m/s

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This is the closed-form expression for the summation, which can be directly computed from k.

The expression "3 + 5 + 7 + 9 + ... + 2k+1" is a finite arithmetic series, which can be expressed in closed form using the formula:

Sn = n/2 * (2a + (n-1)d)

where:

n = number of terms

a = first term

d = common difference

In this case, we have:

n = k

a = 3

d = 2

Substituting the values in the formula, we get:

Sn = k/2 * (2 * 3 + (k-1) * 2)

= k/2 * (6 + 2k - 2)

= k/2 * (2k + 4)

Thus, This is the closed-form expression for the summation, which can be directly computed from k.

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The equation of the elastic curve for the beam using method of double integration is EI.y′′=M .

Because we can obtain the equation of the elastic curve using the double integration method, it is an effective method for determining the deflection and slope of a beam at any point.

The formula for a calculus curve's radius of curvature, y = f(x), is

\(P=\frac{[1+(\frac{dy}{dx}) ^{2} ]^{\frac{3}{2} } }{|\frac{d^{2}y }{d^{2}x } |}\)

The radius of curvature of a beam is given as in the derivation of the flexure formula.

\(P=\frac{El}{M}\)

Because the slope of the elastic curve dy/dx is so minimal due to the tiny amount of beam deflection, squaring this calculation reduces the value to practically nothing.

\(P=\frac{1}{\frac{d^{2}y }{d^{2}x }}\)

   \(=\frac{1}{y"}\)

Thus, EI / M = 1 / y''

y" = M/El

   = (1/El)*M

If EI is constant, the equation may be written as:

EI.y′′=M

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Answer:

h

Step-by-step explanation:

Answer:

hi i think the answer is that we all might be sus im not sure but i like yo cut my G

Answer:

First we write y and its derivatives as power series:

y=∑n=0∞anxn⟹y′=∑n=1∞nanxn−1⟹y′′=∑n=2∞n(n−1)anxn−2

Next, plug into differential equation:

(x+2)y′′+xy′−y=0

(x+2)∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

x∑n=2∞n(n−1)anxn−2+2∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

Move constants inside of summations:

∑n=2∞x⋅n(n−1)anxn−2+∑n=2∞2⋅n(n−1)anxn−2+∑n=1∞x⋅nanxn−1−∑n=0∞anxn=0

∑n=2∞n(n−1)anxn−1+∑n=2∞2n(n−1)anxn−2+∑n=1∞nanxn−∑n=0∞anxn=0

Change limits so that the exponents for  x  are the same in each summation:

∑n=1∞(n+1)nan+1xn+∑n=0∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−∑n=0∞anxn=0

Pull out any terms from sums, so that each sum starts at same lower limit  (n=1)

∑n=1∞(n+1)nan+1xn+4a2+∑n=1∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−a0−∑n=1∞anxn=0

Combine all sums into a single sum:

4a2−a0+∑n=1∞(2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an)xn=0

Now we must set each coefficient, including constant term  =0 :

4a2−a0=0⟹4a2=a0

2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an=0

We would usually let  a0  and  a1  be arbitrary constants. Then all other constants can be expressed in terms of these two constants, giving us two linearly independent solutions. However, since  a0=4a2 , I’ll choose  a1  and  a2  as the two arbitrary constants. We can still express all other constants in terms of  a1  and/or  a2 .

an+2=−(n+1)nan+1+(n−1)an2(n+2)(n+1)

a3=−(2⋅1)a2+0a12(3⋅2)=−16a2=−13!a2

a4=−(3⋅2)a3+1a22(4⋅3)=0=04!a2

a5=−(4⋅3)a4+2a32(5⋅4)=15!a2

a6=−(5⋅4)a5+3a42(6⋅5)=−26!a2

We see a pattern emerging here:

an=(−1)(n+1)n−4n!a2

This can be proven by mathematical induction. In fact, this is true for all  n≥0 , except for  n=1 , since  a1  is an arbitrary constant independent of  a0  (and therefore independent of  a2 ).

Plugging back into original power series for  y , we get:

y=a0+a1x+a2x2+a3x3+a4x4+a5x5+⋯

y=4a2+a1x+a2x2−13!a2x3+04!a2x4+15!a2x5−⋯

y=a1x+a2(4+x2−13!x3+04!x4+15!x5−⋯)

Notice that the expression following constant  a2  is  =4+  a power series (starting at  n=2 ). However, if we had the appropriate  x -term, we would have a power series starting at  n=0 . Since the other independent solution is simply  y1=x,  then we can let  a1=c1−3c2,   a2=c2 , and we get:

y=(c1−3c2)x+c2(4+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(4−3x+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(−0−40!+0−31!x−2−42!x2+3−43!x3−4−44!x4+5−45!x5−⋯)

y=c1x+c2∑n=0∞(−1)n+1n−4n!xn

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Answer:

See Explanation

Step-by-step explanation:

If a Function is differentiable at a point c, it is also continuous at that point.

but be careful, to not assume that the inverse statement is true if a fuction is Continuous it doest not mean it is necessarily differentiable, it must satisfy the two conditions.

                                          And

If function is differentiable at a point x, then function must also be continuous at x. but The converse does not hold, a continuous function need not be differentiable.

In conclusion, to compute the chi-square value, we need to know the number of categories and use the appropriate formula or table to find the critical value. The degrees of freedom (df) will be equal to the number of categories minus one (df = k-1).

In the given question, we need to compute the chi-square value to determine the upper bound of the interval. The chi-square value depends on the degrees of freedom (df). To calculate it, we need to know the significance level (α) and the number of categories (k).

Since the question does not provide information about the number of categories, we cannot determine the exact degrees of freedom. However, we can assume that the number of categories is given, and proceed accordingly.

Assuming k is the number of categories, the degrees of freedom (df) will be (k-1).

For example, if there are 5 categories, the degrees of freedom will be (5-1) = 4.

The chi-square value is computed using a chi-square distribution table or a calculator. By using the significance level (α) and the degrees of freedom (df), we can determine the critical value.

In conclusion, to compute the chi-square value, we need to know the number of categories and use the appropriate formula or table to find the critical value. The degrees of freedom (df) will be equal to the number of categories minus one (df = k-1).

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Answer:

8 seeds

Step-by-step explanation:

16 = 32

4 = ?

16 ÷4 = 4

32 ÷ 4 = 8

Answer:

1458/3456 = 27/64 (simplification)

cube root of 27/64 = 3/4

square of 3/4 = 9/16

9/16 multplied by 1024 = 576.

THIS IS THE REAL WORKING AND ANSWER

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The surface area of the smaller container is 576 cm²

Two shapes or solids are similar if their corresponding sides are in the same proportion and their corresponding angles are equal.

Given that, The two containers are mathematically similar in shape, the larger container has a volume of 3456 cm³ and a surface area of 1024 cm². The smaller container has a volume of, 1458 cm³.

We know, that the cube of scale factor is equal to ratio of volumes of given shape and ratio of surface area is equal to square of scale factor.

1458/3456 = 27/64

∛27/64 = 3/4

Therefore, the scale factor = 3/4

(3/4)² = 9/16

9/16x1024 = 576.

Hence, The surface area of the smaller container is 576 cm²

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The probability that the athlete has actually been using the prohibited drug given that they tested positive is approximately 0.5789 or 57.89%.

To solve this problem, we can use Bayes' theorem, which relates the conditional probabilities of two events.

Let A be the event that the athlete has been using the prohibited drug, and let B be the event that the athlete tests positive.

We want to find the probability of A given B, which we can write as P(A | B).

Using Bayes' theorem, we have:

P(A | B) = P(B | A) * \(\frac{P(A) }{P(B)}\)

where P(B | A) is the probability of testing positive given that the athlete has been using the prohibited drug, P(A) is the prior probability of the athlete using the prohibited drug, and P(B) is the overall probability of testing positive, which can be calculated using the law of total probability:

P(B) = P(B | A) * P(A) + P(B | not A) * P(not A)

where P(B | not A) is the probability of testing positive given that the athlete has not been using the prohibited drug, and P(not A) is the complement of P(A), i.e., the probability that the athlete has not been using the prohibited drug.

Using the given information, we can plug in the values:

P(B | A) = 1 - 0.12 = 0.88 (probability of testing positive given the athlete is using the drug)

P(A) = 0.05 (prior probability of the athlete using the drug)

P(B | not A) = 0.04 (probability of testing positive given the athlete is not using the drug)

P(not A) = 1 - P(A) = 0.95 (probability that the athlete is not using the drug)

Then, we can calculate P(B) as:

P(B) = P(B | A) * P(A) + P(B | not A) * P(not A)

= 0.88 * 0.05 + 0.04 * 0.95

= 0.076

Finally, we can calculate P(A | B) as:

P(A | B) = P(B | A) * \(\frac{P(A) }{ P(B)}\)

= 0.88 * \(\frac{0.05 }{ 0.076}\)

= 0.5789

Therefore, the probability that the athlete has actually been using the prohibited drug given that they tested positive is approximately 0.5789 or 57.89%.

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Answer:

To make a profit of course

Step-by-step explanation:

it

then

yes

Possibly.

Answer:

20 cm is the side of the bigger square.

Step-by-step explanation:

Let one square's side be x,

Then another squares side will be ( x + 5 )

Total area:

So one square's side is 15 cm

Then the bigger square has:

Let the length of each side of the smaller square be \(x\). Then area of the square is \(x^2\).

The length of each side of the larger square will be \(x+5\).

Then the area of the square will be \((x+5)^2\)

As per the question the area of the larger square is four times the square of the smaller square.

Therefore \((x+5)^2 = 4x x^2\)

\(→ x^2 +10x +25 = 4x^2\)

\(→ 3x^2 -10x -25 = 0\)

\(→ 3x^2 +5x-15x - 25 = 0\)

\(→ (3x + 5)(x-5) = 0\)

We get \(x=5\), and \(x=-\frac{5}{3}\)

Considering the positive value we get \(x+5=5+5=10\)

Therefore the side of the squares are \(5\) cms and \(10\)cm.

Answer Hi! you would do 15.34- 5.75

so do 75-34 =  41 and then 15- 5 = 10 so your anwser is -10.41 MAKE SURE ITS NEGTIVE

Step-by-step explanation:

Answer:

10 ft

Step-by-step explanation:

In all circles, there is diameter and a radius

A diameter is the line going from one side of the circle to their other through the center. It is twise the size of the radius

A radius is half of the diameter, it is a line going from the center to any point on the edge of the circle

In this case, we have the radius shown to us

Since we know the radius, it is very easy to find out the length of the diameter

The diameter is twice the radius, equation D= R x 2

So we just multiply 5 by 2

This gets us to 10 so that is our final answer!

I hope this helps, and please award brainliest if possible!

Have a great day!

Answer:

y = 51.32º

Step-by-step explanation:

z = 180 - 47 - 90

z = 43º

sin43 = opp/hyp

sin43 = 35/y

y = 35/sin43

y = 51.32º