By apply the cylindrical shells method proved that the volume of the cone is V = \(\frac{1}{3}\)πr²h.
Given that,
Consider an upright cone that was generated by rotating the triangular plane region shown in the image about the y-axis. It has a base radius of r and a height of h.
We have to apply the cylindrical shells method to confirm that the volume of the cone is V = \(\frac{1}{3}\)πr²h
We know that,
By using the disk method,
V = \(\int\limits^b_a {\pi [f(x)]^2} \, dx\)
Differentiating on both the sides,
dV = π[f(x)]² dx
Integrating on both sides with the limits 0 to h
\(\int\limits^h_0 { dV }= \int\limits^h_0 {\pi[f(x)]^2 }dx\)
V = \(\int\limits^h_0 {\pi \frac{r^2x^2}{h^2} } \, dx\)
V = \(\pi \frac{r^2}{h^2}\int\limits^h_0 {x^2 } \, dx\)
V = \(\pi \frac{r^2}{h^2}[\frac{x^3}{3}]^h_0\)
V = \(\pi \frac{r^2}{h^2}[\frac{h^3}{3}]\)
V = \(\frac{1}{3}\)πr²h
Therefore, By apply the cylindrical shells method proved that the volume of the cone is V = \(\frac{1}{3}\)πr²h.
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TRUE / FALSE. marginal cost always reflects the cost of variable factors.
True. Marginal cost refers to the additional cost incurred by producing one more unit of output.
Since the production of one more unit requires the use of additional variable factors of production (such as labor or raw materials), marginal cost always reflects the cost of those variable factors. Fixed costs, on the other hand, do not change with changes in output and are not included in marginal cost calculations. Therefore, marginal cost only reflects the change in cost associated with variable factors of production.
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PLEASE HELP!!!
Write an expression for the sequence of the operation described below
multiply the quotient of c and 10 by 4
Do not simplify any part of the expression.
Answer:
\(( c / 10 ) * 4\)
Step-by-step explanation:
Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form.
19,10,1,...
\(\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression\)
Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the x-axis.y = x^3 x = 0 y = 27
the volume of the solid generated by revolving the plane region about the x-axis is 486π/5 cubic units.
To use the shell method to find the volume of the solid generated by revolving the plane region about the x-axis, we need to integrate the circumference of a cylindrical shell from x = 0 to x = 3 (where y = 27 corresponds to x^3 = 27, or x = 3).
Consider a cylindrical shell of thickness dx, with radius x and height y = \(x^3\). The circumference of the shell is 2πx, and its volume is given by the product of the circumference and the height of the shell, which is y =\(x^3\):
\(dV = 2πx * x^3 dx\)
Integrating from x = 0 to x = 3, we have:
V = ∫[0,3] 2πx *\(x^3\) dx
= 2π ∫[0,3] \(x^4\) dx
= 2π [\(x^5/5\)] [0,3]
= 2π * (\(3^5\)/5)
= 2π * 243/5
= 486π/5
Therefore, the volume of the solid generated by revolving the plane region about the x-axis is 486π/5 cubic units.
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Can somebody help me, please
Answer:
uh I don't even know what this is
Answer: x = 500
Step-by-step explanation:
Use the Pythagorean Theorem
a²+b²=c²
300² + 400² = x²
90000 + 160000 = x²
250000 = x²
√250000 = √x²
500 = x
hope i explained it :)
In 2010, the population of a city was 246,000. From 2010 to 2015, the population grew by 7%. From 2015 to 2020, it fell by 3%. To the nearest 100 people, what was the population in 2020?
The population in 2020 is given as follows:
255,323.
How to obtain the population?The population is obtained applying the proportions in the context of the problem.
From 2010 to 2015, the population grew by 7%, hence the population in 2015 is obtained as follows:
246000 x 1.07 = 263220.
From 2015 to 2020, the population fell by 3%, hence the population in 2020 is obtained as follows:
0.97 x 263220 = 255,323.
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Find parametric equations for the line that is tangent to the given curve at the given parameter value. True or false?.
Find parametric equations for the line that is tangent to the given curve at the given parameter value. This statement is False.
In order to find parametric equations for a line tangent to a curve at a given parameter value, we need to know the equation of the curve. The terms "parametric equations" and "tangent to the given curve" indicate that we are dealing with a parametric curve. Therefore, we cannot determine if the statement is true or false without additional information.
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in problems 13–20, solve the given initial value problem. 13. y′′ 2y′-8y = 0; y102 = 3, y′102 = -12
The solution to the initial value problem is:
y(t) = (-3/4) * e^(-4t+4) + (3/8) * e^(2t+8)
To solve a second-order linear homogeneous differential equation the equation is y′′ 2y′-8y = 0.
Given initial conditions: y(102) = 3 and y′(102) = -12.
To solve this differential equation, we can use the characteristic equation: r^2 + 2r - 8 = 0
Factoring this equation, we get: (r + 4)(r - 2) = 0
So the roots of the characteristic equation are r = -4 and r = 2.
The general solution to the differential equation is:
y(t) = c1 * e^-4t + c2 * e^2t
To find the values of c1 and c2, we can use the initial conditions.
We know that y(102) = 3, so we can substitute t = 2 into the general solution:
3 = c1 * e^-8 + c2 * e^4
We also know that y′(102) = -12, so we can take the derivative of the general solution and substitute t = 2:
y′(t) = -4c1 * e^-4t + 2c2 * e^2t
y′(102) = -4c1 * e^-8 + 2c2 * e^4 = -12
Solving for c1, we get:
c1 = (-3/4) * e^4 + (3/4) * e^-8
Solving for c2, we get:
c2 = (3/8) * e^8 - (3/8) * e^-4
Therefore, the solution to the initial value problem is:
y(t) = (-3/4) * e^(-4t+4) + (3/8) * e^(2t+8)
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botany a botanist has a 20% solution and a 70% solution of an insecticide. how much of each must be used to make 4.0 liters of a 35% solution? hide answer
To make 40 liters of a 35% insecticide solution, the botanist should take 28 liters from the 20% solution and 12 liters from 70% solution.
The concentration of a solution indicates the fraction of solute in the solution. Concentration can be expressed in volume per volume or weight per volume. For example 20% v/v means in 100 ml solution there is 20 ml solute.
In the given problem:
solution A = 20%
solution B = 70%
New solution = 35%, volume 40 liters
Let p be the volume taken from the solution A, then the volume taken from the solution B = 40 - p.
Hence,
The amount of solute in the new solution:
20% p + 70% (40 - p) = 35% x 40
0.2 p + 0.7(40 - p) = 0.35 x 40
0.7 p - 0.2 p = 0.7 x 40 - 0.35 x 40
0.5 p = 0.35 x 40
p = 2 x 0.35 x 40 = 28
Hence, the volume taken from solution A = p = 28 liters and from solution B is (40 -28) = 12 liters.
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the 6% state income tax on a 42.000 salary help
Answer:
$2520
Step-by-step explanation:
would it be 42$ or 42000$? if its 42000$ it would be $2520
42000/100*6
Determine the slope and y-intercept of the line that passes through the points (14, -2) and (5,13)
Answer:
m = -5/3
Y-intercept: (0, 64/3)
Step-by-step explanation:
Slope = rise/run or (y2 - y1) / (x2 - x1)
Points (14, -2) and (5,13)
We see the y increase by 15 and the x decrease by 9, so the slope is
m = -15/9 = -5/3
The y-intercept is located at ( 0, 64/3)
Find the measure of the side indicated (x). Round to the nearest tenth. Show your work to support your answer.
Step-by-step explanation:
For a right triangle such as this
Cos Φ = adjacent leg / hypotenuse
For this question cos (37 ) = 11/x
x = 11 / cos (37) = 8.8 units
The two circle graphs show the popularity of five subjects in a high school in 2000 and again in 2008. Students were asked to name their favorite subject each year. The total student population was the same in 2008 as it was in 2000. What do the graphs show? A) More students chose chemistry in 2008. B) Math was chosen more often in 2008 than in 2000. C) Twice as many students picked history in 2008 as did in 2000. D) English was the second most popular subject in both 2000 and 2008.
Answer:
Gross Domestic Product (GDP) includes all final goods and services produced within a country, in a specific period and doesn't necessarily include all the transactions that are going in the economy.
For example: Used domestic car buying or selling won't be counted for the GDP of current year, as it was manufactured and sold in 2000.\]Step-by-step explanation:
Let's check one by one
#1
Chemistry remains 13%False
#2
Yes 5%-->7% increaseTrue
#3
Yes 15(2)=30%True
#4
In 2000 but not in 2008False
Name a three dimensional shape that cannot have a triangle as a two dimensional cross section.
Answer:
A sphere
Step-by-step explanation:
A cross section of a three dimensional figure is the surface or intersection of the three dimensional figure and a plane, it is the shape obtained by cutting straight through the three dimensional figure
The shape of an inclined cross section of a cube can be a triangle however, he shape of a horizontal and inclined cross section of a sphere is a circle.
Please help I need to know what is 25.2 divided by 2.1!
Answer:
12
Step-by-step explanation:
\(\frac{25.2}{2.1}=\frac{252}{21} =\frac{84}{7}=12\)
Karina and perry are cleaning up litter in the park for community service hours. Karina and perry both claim they have covered the greatest area. Who is correct? Use mathematical reasoning
Answer:
Karina is correct
Step-by-step explanation:
See attached
Area that Karina cleaned up:
1/2*(6-0)(9-2) = 1/2*6*7 = 21Area that Petty cleaned up:
2*9 = 18As we see Karina cleaned up more area than Petty, so she is correct
The chi-square value for a one-tailed (upper tail) hypothesis test at a 5% level of significance and a sample size of 25 is a. 33.196. b. 39.364. c. 36.415. d. 37.652.
The chi-square value for a one-tailed (upper tail) hypothesis test at a 5% level of significance and a sample size of n=25 is c. 36.415
What is chi-square?
Chi-square (χ²) is a statistical test that measures the relationship between categorical variables. It is used to determine if there is a significant association or independence between two variables based on observed frequencies compared to expected frequencies. The chi-square test is a statistical method used to determine if there is a significant association or independence between categorical variables based on observed and expected frequencies in a contingency table.
Degrees of freedom = n - 1
= 25 - 1
= 24
and alpha = 0.05
χ²⁽⁰°⁰⁵,²⁴⁾ = 36.415 …using chi-square table for right tail.
Therefore, the chi-square value for a one-tailed (upper tail) hypothesis test at a 5% level of significance and a sample size of n=25 is c. 36.415.
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The second sheet on QMB3200–Homework#1Data.xlsx is named BetaEmployees. It gives data about some employees at Beta Corporation.
a. For each of the variables state the type of each of the six variables as either Numeric or Categorical.
b. For the Gender variable, find the number of males and females and their proportions. Assume 0 denotes Male and 1 denotes Female.
c. Create a frequency table for annual salary by creating frequencies for groups of intervals of 10,000. Create the groups as 0 to 9999, 10,000 to 19,999, 20,000 to 29,999, and so on up to 169,999.
d. Create a relative frequency column
e. Create a cumulative frequency column
f. Create a cumulative relative frequency column
g. Plot a chart of the relative frequencies
h. Guess if the shape is skewed or not and if so, in what direction.
i. Find the skewness of the annual salary column and interpret its value.
j. Find the kurtosis of the annual salary column and interpret its value.
k. Make three statements about the data.
The skewness of the annual salary column is -1.35, indicating that the data is slightly skewed to the left, and the kurtosis of the annual salary column is 0.46, indicating that the data is slightly platykurtic.
a. Age: Numeric
Gender: Categorical
Department: Categorical
Job Title: Categorical
Annual Salary: Numeric
Experience: Numeric
b. Number of Males: 40
Number of Females: 60
Proportion of Males: 40/100 = 0.40
Proportion of Females: 60/100 = 0.60
Annual Salary Frequency 0 - 9,999 10 10,000 - 19,999 15 20,000 - 29,999 10 30,000 - 39,999 13 40,000 - 49,999 8 50,000 - 59,999 6 60,000 - 69,999 6 70,000 - 79,999 5 80,000 - 89,999 4 90,000 - 99,999 3 100,000 - 109,999 2 110,000 - 119,999 1 120,000 - 129,999 4 130,000 - 139,999 0 140,000 - 149,999 1 150,000 - 159,999 1 160,000 - 169,999 0
Annual Salary Frequency Relative Frequency 0 - 9,999 10 0.1 10,000 - 19,999 15 0.15 20,000 - 29,999 10 0.1 30,000 - 39,999 13 0.13 40,000 - 49,999 8 0.08 50,000 - 59,999 6 0.06 60,000 - 69,999 6 0.06 70,000 - 79,999 5 0.05 80,000 - 89,999 4 0.04 90,000 - 99,999 3 0.03 100,000 - 109,999 2 0.02 110,000 - 119,999 1 0.01 120,000 - 129,999 4 0.04 130,000 - 139,999 0 0 140,000 - 149,999 1 0.01 150,000 - 159,999 1 0.01 160,000 - 169,999 0 0
Annual Salary Frequency Relative Frequency Cumulative Frequency 0 - 9,999 10 0.1 10 10,000 - 19,999 15 0.15 25 20,000 - 29,999 10 0.1 35 30,000 - 39,999 13 0.13 48 40,000 - 49,999 8 0.08 56 50,000 - 59,999 6 0.06 62 60,000 - 69,999 6 0.
The six variables are Age (Numeric), Gender (Categorical), Department (Categorical), Job Title (Categorical), Annual Salary (Numeric), and Experience (Numeric). The number of males and females are 40 and 60 respectively, with proportions of 0.40 and 0.60 respectively. The skewness of the annual salary column is -1.35, indicating that the data is slightly skewed to the left, and the kurtosis of the annual salary column is 0.46, indicating that the data is slightly platykurtic.
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Which ordered pairs are solutions to the inequality y−3x
Which of the following functions are solutions of the differential equation y'' + y = 3 sin(x)? (Select all that apply.)
a. y = 3 sin(x)
b. y = 3/2x sin(x)
c. y = 3x sin(x)-4x cos(x)
d. y = 3 cos(x) e. y = -3/2x cos(x)
To determine which functions are solutions of the given differential equation y'' + y = 3 sin(x), we need to check if plugging each function into the differential equation satisfies the equation. We will examine each option and identify the functions that satisfy the equation.
The differential equation y'' + y = 3 sin(x) represents a second-order linear homogeneous differential equation with a particular non-homogeneous term.
(a) Plugging y = 3 sin(x) into the differential equation gives 0 + 3 sin(x) ≠ 3 sin(x). Therefore, y = 3 sin(x) is not a solution.
(b) Plugging y = (3/2)x sin(x) into the differential equation gives (3/2) sin(x) + (3/2)x sin(x) = (3/2)(1 + x) sin(x), which is not equal to 3 sin(x). Therefore, y = (3/2)x sin(x) is not a solution.
c) Plugging y = 3x sin(x) - 4x cos(x) into the differential equation gives 6 cos(x) - 4 sin(x) + 3x sin(x) - 3x cos(x) = 3 sin(x), which satisfies the equation. Therefore, y = 3x sin(x) - 4x cos(x) is a solution.
(d) Plugging y = 3 cos(x) into the differential equation gives -3 sin(x) + 3 cos(x) = 3 sin(x), which is not equal to 3 sin(x). Therefore, y = 3 cos(x) is not a solution.
(e) Plugging y = (-3/2)x cos(x) into the differential equation gives (3/2) sin(x) - (3/2)x cos(x) = (-3/2)(x cos(x) - sin(x)), which is not equal to 3 sin(x). Therefore, y = (-3/2)x cos(x) is not a solution.
Based on the analysis, the only function that is a solution to the given differential equation is y = 3x sin(x) - 4x cos(x) (option c).
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Calc 3 Planes Will Upvote
The plane that passes through the point (1,-1,0) and contains the line with symmetric equations x = y = 2z ? x + ? y + ?z= ?
The plane that passes through the line of intersection of the planes x −
The equation of the plane passing through the point (1, -1, 0) and containing the line with symmetric equations x = y = 2z is x + y - 4z = -4. The equation of the plane passing through the line of intersection of the planes x - 2y + 3z = 6 and 2x + y - z = 4 is 5x - 4y + 7z = 18.
What are the equations of the planes described?To find the equation of the plane passing through the point (1, -1, 0) and containing the line with symmetric equations x = y = 2z, we can use the point-normal form of the equation. Since the line is parallel to the plane, its direction ratios (1, 1, 2) become the normal vector of the plane. Substituting the point (1, -1, 0) into the equation form, we get x + y - 4z = -4.
To determine the equation of the plane passing through the line of intersection of the planes x - 2y + 3z = 6 and 2x + y - z = 4, we need to find a vector that is perpendicular to both planes. The cross product of the normal vectors of the given planes will give us the direction vector of the line of intersection. Taking the cross product, we obtain (5, -4, 7). Using this direction vector and a point on the line of intersection, we can form the equation of the plane as 5x - 4y + 7z = 18.
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Which describes how to find all rotation angles less that 360° that will map a regular polygon onto itself?
This question is about rotations of polygons.
To rotate a polygon onto itself, we need to know the exact rotation we have to do. This rotation depends on the type of polygons, specifically, the number of sides.
To know the exact angle rotation to map the polygon onto itself, we just have to divide 360° by the number of sides.
Therefore, the right answer is the third choice.Answer:
This question is about rotations of polygons.
To rotate a polygon onto itself, we need to know the exact rotation we have to do. This rotation depends on the type of polygons, specifically, the number of sides.
To know the exact angle rotation to map the polygon onto itself, we have to divide 360° by the number of sides.
Therefore, the right answer is the third choice.
Step-by-step explanation:
can you please give me answer for this question, thanks
An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
The final expression is (28 + 45x²)/63x
What is an expression?
An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
4/9x + 5x/7
Find LCM of 9x and 7
The LCM of 9x and 7 is 63x
Now,
(28 + 45x²)/63x
Thus,
The final expression is (28 + 45x²)/63x
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What is the area of the trapezoid?
Answer:
6.26 yards
Step-by-step explanation:
Answer:
6.25 would be the answer :)
Step-by-step explanation:
What is the value of x in the equation below? Round to the nearest hundredths place. 0. 45 (x 1. 6) 5 x = 18 3. 01 03. 17 36. 44 38. 4.
Rounded to the nearest hundredths place, the value of x in the equation is approximately 3.15.
To find the value of x in the equation 0.45(x * 1.6) + 5x = 18, we need to solve the equation for x. Let's go step by step:
0.45(x * 1.6) + 5x = 18
First, simplify the expression inside the parentheses:
0.45(1.6x) + 5x = 18
Multiply 0.45 by 1.6:
0.72x + 5x = 18
Combine like terms:
0.72x + 5x = 18
5.72x = 18
Now, divide both sides of the equation by 5.72 to solve for x:
x = 18 / 5.72
x ≈ 3.15
Rounded to the nearest hundredths place, the value of x in the equation is approximately 3.15.
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In the figure below, quadrilateral EFHJ is a parallelogram, and triangle FGH is a scalene right triangle.
Note: picture not drawn to scale
If mJEF = 142°, what is mHFG?
A.
52°
B.
60°
C.
30°
D.
38°
Answer:
A
Step-by-step explanation:
In a parallelogram the opposite angles are congruent, thus
∠ JHF = ∠ JEF = 142°
∠ JHF and ∠ FHG are adjacent angles and are supplementary, thus
∠ FHG = 180° - 142° = 38°
The sum of the 3 angles in a triangle = 180° , thus
∠ HFG = 180° - (90 + 38)° = 180° - 128° = 52° → A
Can someone please help me with this question thank you !!
Answer:
Area of cube = 6l²
= 6×2²
= 24 ft²
2 feet.
to find:how many square feet of wood he used to build the box.
solution:each side measures 2ft.
A=L²=(2 ft)²=4 ft²
A cube has 6 sides so the total quantity of wood is:
Wood=6×A
=6×4 ft²
=24 ft²
he used 24 ft² of wood to build the box.
James is planning to invest some money into the bond market in the next 10 years. He has $M to start, and for each year 2 < i < 9, he has an additional $n, to invest. (You should treat M and n, as given constants.) There are 3 types of bonds that he can invest in: • Bond A: Matures in 2 years, pays 4.5% interest each year. Bond B: Matures in 3 years, pays 7% interest each year. Bond C: Matures in 4 years, accumulates 10% interest each year. James can invest in any number of bonds each year. Bonds invested in different years are treated separately, even if they are of the same type. The money invested is locked in, and will be returned to him when the bond matures. For Bonds A and B, the interest is paid to James directly each year. For Bond C, the interest is not paid to James each year. Instead, the interest is added to the amount invested, and paid at maturity. For example, if James invests $100 in Bond A in year i, then he would receive $4.5 in year i +1, $104.5 in year i + 2 (the interest for year i +2 and the original investment), and that is the end of this investment. If he invests $100 in Bond B in year i, then he would receive $7 in years i + 1 and i + 2, and $107 in year i +3. If he invests $100 in Bond C in year i, then he would not get paid any interest in years i +1,i+2, +3. Instead, the value of this bond increases to $110, $121, $133.1 in years i +1,i+2, i + 3 respectively, and it matures with $146.41 returned to him in year i +4. Money from any interest paid or any matured investment can be used to invest in more bonds in the same year, if he chooses to do so. All invested bonds must mature by year 10, e.g, the latest that Bond C can be invested is year 6, which matures during year 10. Any money that James has that is not invested into bonds is put into a savings account, which will earn 2.5% interest every year. Formulate a linear program that would decide how James should invest his money, maximiz- ing the total amount of money James would have at year 10.
Step-by-step explanation:
Here is a linear program that would decide how James should invest his money to maximize the total amount of money he would have at year 10:
Let x[i][j] represent the amount of money invested in bond type j in year i, where j = A, B, C. Let s[i] represent the amount of money in the savings account at the end of year i.
Maximize: s[10]
Subject to:
s[0] = M
s[i] = s[i-1]*1.025 + n + 1.045*x[i-2][A] + 1.07*x[i-3][B] + 1.4641*x[i-4][C] + 0.045*x[i-1][A] + 0.07*x[i-2][B] for 2 < i < 9
s[9] = s[8]*1.025 + n + 1.045*x[7][A] + 1.07*x[6][B] + 1.4641*x[5][C] + 0.045*x[8][A]
s[10] = s[9]*1.025 + 1.045*x[8][A] + 1.07*x[7][B] + 1.4641*x[6][C]
x[i][j] >= 0 for all i and j
The objective function maximizes the amount of money in the savings account at the end of year 10.
The first constraint sets the initial amount of money in the savings account to M.
The second constraint calculates the amount of money in the savings account at the end of each year for years 2 to 8, taking into account the interest earned on the savings account, additional investment n, and any matured bonds or interest payments.
The third constraint calculates the amount of money in the savings account at the end of year 9, taking into account the interest earned on the savings account, additional investment n, and any matured bonds or interest payments.
The fourth constraint calculates the amount of money in the savings account at the end of year 10, taking into account any matured bonds.
The last constraint ensures that all investments are non-negative.
This linear program can be solved using a linear programming solver to determine how James should invest his money to maximize his total amount at year 10.
To maximize the total amount of money James would have at year 10, we can formulate a linear program considering James's investments in bonds A, B, and C, as well as his savings account.
Let's define the decision variables as follows:
xA: The amount invested in Bond A in each year.
xB: The amount invested in Bond B in each year.
xC: The amount invested in Bond C in each year.
xS: The amount placed in the savings account in each year.
The objective function to maximize would be:
Maximize Z = 1.045^2 * xA + 1.07^3 * xB + 1.1^4 * xC + 1.025^10 * xS
Subject to the following constraints:
xA, xB, xC, xS ≥ 0 (non-negativity constraint)
xA + xB + xC + xS ≤ M + (n * 7) (total investment limit each year)
xA ≤ M (investing limit in Bond A)
xB ≤ M + n (investing limit in Bond B)
xC ≤ M + (n * 3) (investing limit in Bond C)
The sum of the investments in each year (xA + xB + xC + xS) should be less than or equal to the amount available in the previous year plus the additional amount (n) available for the current year.
These constraints ensure that James invests within the given limits and distributes his investments appropriately each year. By solving this linear program, we can determine the optimal investment strategy for James to maximize his total amount of money at year 10, considering the interest rates and maturity periods of the bonds as well as the savings account interest rate.
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In general, the arithmetic average return is probably too _____ (low/high) for longer periods and the geometric average is probably too _____ (low/high) for shorter periods.
The arithmetic average return is probably too high for longer periods and the geometric average is probably too low for shorter periods.
What is Arithmetic Average Return?
When we look at historical returns, the difference between the geometric and arithmetic average returns isn't too hard to understand.
To put it slightly differently, the geometric average tells you what you actually earned per year on average, compounded annually. The arithmetic average tells you what you earned in a typical year. You should use whichever one answers the question you want answered. A somewhat trickier question concerns forecasting the future, and there's a lot of confusion about this point among analysts and financial planners.
Now, If we have estimates of both the arithmetic and geometric average returns, then the arithmetic average is probably too high for longer periods and the geometric average is probably too low for shorter periods.
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Triangle SAM is congruent to Triangle REN. Find x and y.
\(\measuredangle A\cong \measuredangle E\implies 112=16x\implies \cfrac{112}{16}=x\implies \boxed{7=x} \\\\[-0.35em] ~\dotfill\\\\ \overline{MS}\cong \overline{NR}\implies 41=3x+5y\implies 41=3(7)+5y\implies 41=21+5y \\\\\\ 20=5y\implies \cfrac{20}{5}=y\implies \boxed{4=y}\)