Consider light energy that is momentarily absorbed in glass and then re-emitted. Compared to the absorbed light, the frequency of the re-emitted light is?

Answers

Answer 1

The frequency of the re-emitted light is identical to that of the absorbed light.

To find the answer, we need to know more about the frequency of light.

Why the re-emitted light has the same frequency?The wavelength of the light that is momentarily absorbed in glass and then re-emitted is the same, which explains why the re-emitted light has the same frequency as the absorbed light and the frequency of the absorbed light is the same. An electromagnetic wave's energy is inversely related to its frequency. The relationship between the wave's wavelength and frequency depends on the speed of light:

                              \(frequency=\frac{c}{wave length}\) , c is the speed of light.

Despite not having mass, light still has energy, and that energy is conserved. As a result, in order for there to be energy conservation, the energy of the light that is received and reemitted must be equal.

Thus, we can conclude that, the re-emitted light's frequency matches the absorbed light's frequency.

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Related Questions

Although nuclear energy is considered a cleaner energy source than fossil fuels, some scientists argue this does not support the claim that nuclear energy is renewable. Which of the following claims best supports the argument that nuclear energy is a nonrenewable energy source?
A. Nuclear energy has low carbon emissions and does not contribute to global warming.
B. The uranium deposits on Earth are finite.
C. Nuclear energy is generated by the process of nuclear fission.
D. Nuclear power plants convert water to steam, similar to fossil fuel–burning power plants.

Answers

Nuclear energy can be considered a nonrenewable energy source because uranium deposits on Earth are exhaustible.

Nonrenewable resources

Nonrenewable energy or resources are those that are used at a rate that is faster than the rate at which they are naturally replenished.

The source of the world's nuclear energy is uranium deposits, a mineral that is nonrenewable. In other words, the uranium mineral deposit that fuels nuclear reactors can be exhausted one day because they are not replenished naturally.

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Michael uses his bike to apply 452 N to himself and the bike by pedaling as he approaches a 1.9 m tall ramp which is 5.0 m away. He starts from rest to accomplish this feat. How fast will he be moving just before he hits the ramp? (Mike and the bike have a combined mass of 151 kg)

Answers

The final velocity of Michael and his bike before he hits the ramp is 5.47 m/s.

What is the acceleration of Michael and his bike?

The acceleration of Michael and his bike is calculated by applying Newton's second law of motion as follows;

F = ma

a = F/m

where;

F is the applied forcem is the mass

a = 452 / 151

a = 2.99 m/s²

The final velocity of Michael and his bike before he hits the ramp  is calculated as follows;

v² = u + 2as

where;

u is initial velocity = 0s is the distance travelled = 5 m

v² = 0 + 2(2.99)(5)

v² = 29.9

v = √29.9

v = 5.47 m/s

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Baby Yoda weighs 53. 85N on Mercury; the gravitational force strength on Mercury is 3. 59 m/s2
[6 marks]

What is his mass on Mercury?
What is his weight on Earth?
If Baby Yoda is riding in an elevator that is accelerating down at a rate of 1. 25 m/s2, determine his apparent weight. (it may help if you draw a FBD)

Answers

Baby Yoda's mass on Mercury is 5.98 kg. His weight on Earth is 11.18 kg. His apparent weight in the elevator is 47.38 N.

To find Baby Yoda's mass on Mercury, we can use the formula:

weight = mass x gravitational force strength

Rearranging the formula to solve for mass, we get:

mass = weight / gravitational force strength

Plugging in the given values, we get:

mass = 53.85N / 3.59 m/s² = 5.98 kg

To find Baby Yoda's weight on Earth, we can use the formula:

weight = mass x gravitational force strength

where the gravitational force strength on Earth is 9.81 m/s².

Plugging in the mass of 5.98 kg, we get:

weight = 5.98 kg x 9.81 m/s² = 11.18 kg

To find Baby Yoda's apparent weight in the elevator, we need to draw a free body diagram (FBD) and use Newton's second law:

apparent weight - weight = mass x acceleration

The weight is the gravitational force strength on Mercury, which we already know to be 53.85N. The apparent weight is the force that Baby Yoda feels in the elevator. The mass is still 5.98 kg, and the acceleration is -1.25 m/s² (negative because the elevator is accelerating downwards).

Plugging in the values, we get:

apparent weight - 53.85N = 5.98 kg x (-1.25 m/s²)

Simplifying, we get:

apparent weight = 47.38 N

Therefore, Baby Yoda's apparent weight in the elevator is 47.38 N.

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how many tries did it take to invent the lightbulb?

Answers

It took 1,00 attempts

a bodybis thrown vertically upward with velocity of 30m/s calculate the the maximum height attained​

Answers

Explanation:

Initial velocity(v)=30 m/sFinal velocity(u)=0 m/sAcceleration due to gravity(g)=9.8m/s²Height(h)=?

Now,

By the third equation of motion, we have

v²=u²+2gh30²=0²+2×9.8×h900=0+19.6h900=19.6h900/19.6=hh=45.918 m

All of the following are factors affecting flow rate except what?
a. viscosity
b. catheter length
c. vessel sideholes
d. injection pressure

Answers

c. Vessel side holes

The "Poiseuille formula" which is given by \(\\\begin{aligned} \small Q& = \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned}\) describes the volumetric flow rate (\(\small Q\)) through tubular sections.Here, \(\Delta P,\,\, \Delta L,\,\, r,\,\, \eta\) represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.With this, one can confirm that all the factors except the vessel side holes affect the flow rate.Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.

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The star Merak has an apparent magnitude of 2.4 while star Sirius has an apparent magnitude of -1.5. Which star appears brighter in the sky

Answers

Sirius is approximately \(2.5^{3.9}\) times brighter than Merak when observed from Earth. The apparent magnitude is a scale used to measure the brightness of celestial objects as they appear to an observer on Earth. In this scale, a lower value indicates a brighter object.

The star Merak has an apparent magnitude of 2.4, while Sirius has an apparent magnitude of -1.5. Since Sirius has a lower apparent magnitude value (-1.5) compared to Merak (2.4), Sirius appears brighter in the sky.

This difference in brightness is due to the difference in both their intrinsic luminosities and their distances from Earth. Sirius is not only intrinsically more luminous than Merak but also closer to Earth, which makes it appear even brighter. The apparent magnitude scale is logarithmic, meaning that a difference of 1 magnitude corresponds to a brightness ratio of approximately 2.5 times. In this case, the difference in magnitude between Merak and Sirius is 3.9 (2.4 - (-1.5)). Therefore, Sirius is approximately \(2.5^{3.9}\) times brighter than Merak when observed from Earth.

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_______ is the point in the object around which its weight is evenly distributed.

Answers

Answer:

CENTER OF GRAVITY is the point in the object around which its weight is evenly distributed.

Explanation:

An object's center of gravity (CG) is the equilibrium point where its constituent parts are uniformly distributed. In this situation, the object may behave as though its entire weight were concentrated at the center of gravity (CG).

Applications include the concept that a weighted object always rotates freely about its center of mass and that a weighted object will fall over if its center of gravity is beyond its base of support. Additionally, the center of gravity is where the most force is applied.

The point in the object around which its weight is evenly distributed is known as the center of gravity.

It is also referred to as the center of mass. The center of gravity is the point around which the mass of an object is evenly distributed in all directions. There are different ways to find the center of gravity of an object. However, one common method involves suspending the object from different points and then marking the vertical line. The intersection of these lines is the center of gravity. The center of gravity has applications in physics and engineering. For instance, in the design and construction of buildings, it is essential to determine the center of gravity to ensure the stability and safety of the structure. In summary, the center of gravity is an important concept in physics and engineering that helps in understanding the distribution of weight and stability of objects.

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a toy car travels from A to B at constant speed 30km/hr and without stopping at B return A at constant speed v. if the average speed of the car is 24km/h then v is​

Answers

Answer:

Speed BA = 18 km/hr.

Explanation:

Given the following data;

Speed AB = 30km/hr

Speed BA = x km/hr

Average speed = 24 km/hr

To find the value of x;

Average speed = (Speed AB + Speed BA)/2

Substituting into the equation, we have

24 = (30 + x)/2

48 = 30 + x

x = 48 - 30

x = 18 km/hr

In projecting statments, the analyst makes judgments about the firm's? Select one: a. working capital policies b. cash reserves c. capital expenditures d. all of the above

Answers

Option d is correct. all of the above. In projecting statements, the analyst makes judgments about various aspects of the firm's financial decisions and strategies, including working capital policies, cash reserves, and capital expenditures.

These projections involve making estimations and assumptions based on historical data, industry trends, and the company's future plans.

a. Working capital policies: Working capital refers to the funds a company uses for day-to-day operations and managing its short-term obligations. The analyst assesses the firm's working capital policies, such as how it manages its current assets and liabilities, to project future cash flows and liquidity.

b. Cash reserves: Cash reserves refer to the amount of cash and cash equivalents a company holds to meet its immediate financial obligations or take advantage of investment opportunities. The analyst considers the firm's cash position, cash flow projections, and cash management strategies to project future cash reserves.

c. Capital expenditures: Capital expenditures (CapEx) represent the funds invested by a company in long-term assets, such as property, plant, and equipment. The analyst evaluates the firm's CapEx plans, growth strategies, and investment decisions to project future capital expenditures.

When projecting statements, the analyst considers multiple factors, including working capital policies, cash reserves, and capital expenditures. These judgments are essential for estimating future financial performance and evaluating the firm's financial health and investment potential. By analyzing these aspects, the analyst provides insights into the firm's financial outlook and helps stakeholders make informed decisions.

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when you look at an object in a mirror, the image is:

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Answer:

When you place an object in front of a mirror, you see the same object in the mirror. This image that appears to be behind the mirror is called the image. The object is the source of the incident rays, and the image is formed by the reflected rays. An image formed by reflection may be real or virtual.

Which of the following statements regarding lightning strikes is correct?
Select one:
A. Victims who are struck by lightning often experience severe full-thickness burns.
B. Cervical spine fractures are the most common cause of lightning-related deaths.
C. The tissue damage pathway caused by lightning usually occurs through the skin. Incorrect
D. Lightning often results in a brief period of asystole that resolves spontaneously.

Answers

The correct statement regarding lightning is as follows: Victims who are struck by lightning often experience severe full-thickness burns (option A).

What is lightning?

Lightning is an electrical discharge caused by imbalances between storm clouds and the ground, or within the clouds themselves.

Lightning strike is a lightning bolt, stroke of lightning, one of the events during an electrical storm when lightning strikes (an object on) the ground or an aircraft in flight.

Most deaths after lightning strikes occur either because of primary cardiac arrest or hypoxia-induced secondary cardiac arrest, however, survivors have experienced debilitating injuries, burns and ongoing disability, including symptoms like seizures and memory loss.

Therefore, severe full-thickness burns are the symptoms or signs of lightning strike.

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A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test charge from a point midway between them to a point 12 cm closer to either of the charges?

Answers

Answer:

512.5 mJ

Explanation:

Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.

The electric potential at this point due to the two charges q is thus

V = kq/r₂ + kq/r₂

= 2kq/r₂

= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m

= 630/0.23  × 10³ V

= 2739.13 × 10³ V

= 2.739 MV

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

So, the new electric potential at this point is

V' = kq/r₃ + kq/r₄

= kq(1/r₃ + 1/r₄)

= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)

= 315 × 10³(2.857 + 9.091) V

= 315 × 10³ (11.948) V

= 3763.62 × 10³ V

= 3.764 MV

Now, the work done in moving the charge q' to the point 12 cm from either charge is

W = q'(V' - V)

= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)

= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V

= 0.5125 J

= 512.5 mJ

Work done will be:  \(512.5 \mu J\).

Given:

q = +35 µC

q' = +0.50 µC

r₁ = 46 cm

r₂ = 46 cm/2 = 23 cm = 0.23 m

The electric potential at this point due to the two charges q is thus

\(V = \frac{kq}{r_2}+\frac{kq}{r_2}\\\\ V= \frac{2kq}{r_2}\\\\V= \frac{2 * 9 * 10^9Nm^2/C^2 * 35 * 10^{-6} C}{0.23 m}\\\\V= \frac{630}{0.23*10^3}V\\\\V= 2739.13 * 10^3 V\\\\V= 2.739 \mu V\)

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now;

r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and

r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

Thus, the new electric potential at this point is

\(V' = \frac{kq}{r_3} + \frac{kq}{r_4}\\\\V= kq(\frac{1}{r_3}+\frac{1}{r_4})\\\\V= 9 * 10^9 Nm^2/C^2 * 35 * 10^{-6} C (\frac{1}{0.35m}+\frac{1}{0.11m})\\\\V= 315 * 10^3(2.857 + 9.091) V\\\\V= 315 * 10^3 (11.948) V\\\\V= 3763.62 * 10^3 V\\\\V= 3.764 \mu V\)

Now, the work done in moving the charge q' to the point 12 cm from either charge is:

\(W = q'(V' - V)\\\\W= 0.5 * 10^{-6} C(3.764 MV - 2.739 MV)\\\\W= 0.5 *10^{-6} C(1.025 * 10^6) V\\\\W= 0.5125 J\\\\W= 512.5 \mu J\)

Thus, the work done will be: \(512.5 \mu J\).

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Which has more momentum: a large parked car or a slow moving feather?

Answers

Answer: Slow moving feather

The parked car has 0 velocity since it is stationary. The momentum of the car is 0 because momentum = mass*velocity.

On the other hand, the feather is moving, so its velocity is some positive value. Even if it's a small velocity value and the mass of the feather is small, the two will multiply to some positive momentum which is larger than 0.

So the feather has larger momentum compared to the parked car.

an electromagnetic wave with a peak magnetic field magnitude of 1.50 10-7 t has an associated peak electric field of what magnitude?

Answers

45 V/m is the corresponding maximum component of the related peak electric field.

Given:

Electromagnetic pulse with a maximum magnetic field strength of \(1.5 * 10^{-7}\)T

The following is the relationship between the magnetic and electric fields:

E = B × c,

where c = \(3 * 10^{8}\) m/s.

\(E = (1.5 * 10^{-7}) * (3 * 10^{8})\)

= 45 V/m

Electric fields are created by magnetic fields that are changing and electric charges.

With an electric charge or a collection of charges, an electric field will also exist. Any charged object placed in this field will experience an electrostatic attraction as a result of the field's interactions with the charge of the object. Field lines show the force that would act on a positively charged particle at that instant if it were within the field.

In the end, charge transport results in the development of magnetic fields. The magnetic field surrounding the straight wire may be seen as electricity passes across it. Motors and even computer data storage are also powered by this phenomenon.

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What is freezing and does it require the addition or removal of energy? What is an example

Answers

Freezing is the process by which a substance changes its state from a liquid to a solid, requiring the removal of energy through cooling. Water turning into ice is an example of freezing.

Freezing is the process by which a substance changes its state from a liquid to a solid due to the reduction of temperature. During freezing, the molecules in the substance lose energy and slow down, eventually coming together in a more organized and tightly packed structure, forming a solid.

In order for a substance to freeze, it requires the removal of energy from the substance. This is because the kinetic energy of the molecules needs to be reduced so that they can come together in a more ordered arrangement. This energy removal is typically done by cooling the substance, either by decreasing the temperature or by exposing it to a cold environment. As energy is removed from the substance, the temperature of the substance drops until it reaches its freezing point, at which point it solidifies.

An example of freezing is the process of water turning into ice. When water is cooled below its freezing point of 0 degrees Celsius (32 degrees Fahrenheit), the energy is removed from the water, and its molecules begin to slow down and lose kinetic energy. Eventually, the water molecules form a lattice structure, and the water becomes solid ice. Similarly, other substances can also freeze when their temperature is reduced below their freezing point, such as when liquid nitrogen is cooled to a low enough temperature to solidify.

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1. Find the Work and the Power done to increase the velocity of a 9 kg ball from 14
m/s to 30 m/s in 4 s.

Answers

Answer:

65

Explanation:

because everyday my birthday

what force pushes groundwater from pore space to pore space when below the water table?

Answers

The force that pushes groundwater from pore space to pore space when below the water table is primarily due to the pressure gradient within the aquifer. This pressure gradient is caused by the weight of the overlying water and the force of gravity.

Below the water table, the spaces between soil or rock particles are filled with water. These spaces are known as pore spaces. The water table represents the upper surface of the saturated zone, where all the pore spaces are filled with water. gravity acts vertically downward, causing the weight of the water above a particular point to exert a downward force. As a result, the water pressure increases with depth. This increase in pressure creates a pressure gradient within the aquifer.

The pressure gradient drives the flow of groundwater from areas of higher pressure to areas of lower pressure. When a well is drilled into the aquifer below the water table, water will naturally flow into the well and rise to the level of the water table. This is because the pressure is higher below the water table compared to the lower pressure in the well.

The movement of groundwater from pore space to pore space occurs due to the pressure difference between adjacent spaces. Water will flow from areas of higher pressure to areas of lower pressure until the pressures equalize. This movement of water is known as groundwater flow or hydraulic conductivity.

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Can the co-efficient of friction ever have a value such that a skier would be able to slide uphill at a constant velocity?

Answers

No, the co-efficient of friction cannot have a value such that a skier would be able to slide uphill at a constant velocity.

The co-efficient of friction represents the amount of resistance to motion between two surfaces in contact. When moving uphill, the force of gravity is acting against the skier's motion, which increases the frictional force. In order to maintain a constant velocity, the force of the skier pushing forward would have to match the force of friction, but with an increased frictional force, it would require a greater force from the skier to maintain that velocity. Therefore, it is not possible for a skier to slide uphill at a constant velocity due to the increased co-efficient of friction.
The answer is no, the coefficient of friction cannot have a value that would allow a skier to slide uphill at a constant velocity. The coefficient of friction is a measure of the resistance between two surfaces, in this case, the skis and the snow. When sliding uphill, the skier must overcome both friction and the gravitational force pulling them downhill. To slide uphill at a constant velocity, an external force would need to be applied, such as pushing or propelling themselves uphill. The coefficient of friction cannot be adjusted to overcome the force of gravity without an external force being applied.

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Suppose a luminous cloud of gas is discovered emitting an emission spectrum. What can be learned about the cloud from this observation

Answers

suppose a luminous cloud of gas is discovered emitting an emission spectrum. what can be learned about the cloud from this observation? we would learn that the cloud's atoms or molecules are transferring from a high energy state to a lower energy state.

A car changes its speed by 2 meters per second each second. What is its acceleration?
A. 4 m/s2
B. 0.5 m/s2
C. 2 m/s2

Answers

Answer:

2 m/s²

Explanation:

If changes speed by 2 meters per second each second means:

2 m/s²

Because it changes constantly it veloctity.

Remember the aceleration changes the velocity.

Answer:

c. 2 m/s2

is the right answer.

suppose you stand on a swing instead of sitting on it will your frequency of oscillation increase or decrease​

Answers

If you stand on a swing instead of sitting on it, the frequency of oscillation will decrease.

Frequency of oscillations

The frequency of oscillation of a swing depends on its length and acceleration due to gravity. The longer the swing, the slower it oscillates, and the shorter the swing, the faster it oscillates. The acceleration due to gravity provides the restoring force that pulls the swing back toward its equilibrium position.

When you stand on a swing instead of sitting on it, you effectively shorten the length of the swing. This is because your center of mass is higher up on the swing, which reduces the length of the pendulum from the pivot point to your center of mass. A shorter pendulum has a higher frequency of oscillation than a longer pendulum, so the frequency of oscillation of the swing will increase.

However, when you stand on a swing, you also make it harder for the swing to move. This is because your legs are now acting as shock absorbers, and they absorb some of the energy that would otherwise be used to swing the swing. This makes it harder for the swing to oscillate, which reduces the frequency of oscillation.

The net effect of these two factors is that the frequency of oscillation of the swing decreases when you stand on it instead of sitting on it.

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A hot-air balloon is descending at a rate of 1.7 m/s when a passenger drops a camera.
If the camera is 43 m above the ground when it is dropped, how much time does it take for the camera to reach the ground?
If the camera is 43 m above the ground when it is dropped, what is its velocity just before it lands? Let upward be the positive direction for this problem.

Answers

The required solutions of both part of the question are a)  t = 2.83 s, b) 27.7 m/s.

What is equation of motion?

The fundamental equation of motion in classical mechanics is Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration an of its center of mass, or F = ma.

According to question:

a.) Before commencing the calculation, we need to specify the information.

Data:

acceleration dues to gravity, g = 9.81 m/s²

initial velocity u = 1.7 m/s

height, s = 45 m

t = ?

The formula for finding the distance is s = ut + 1/2at²

Therefore, 45 = 2t + 1/2×(9.81) ×t²

                 90 = 4t + 9.81 t²

Solving for t by the quadratic equation gives t = 2.83 s [Note the other negative value for t is rejected because there is no negative time]

b) The final velocity is given by the following equation:

v = u + at

where v = final velocity just before the camera lands on the ground

           u = initial velocity

           t = time taken

           a = g = acceleration dues to gravity = 9.81 m/s²

Calculating gives

v = 2 + 9.81×2.83

= 27.7 m/s Ans

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The most common cause for the P wave, QRS complex, and T wave to be inverted in Lead I is _________.

Answers

The most common cause for the P wave, QRS complex, and T wave to be inverted in Lead I is right bundle branch block (RBBB)

A right bundle branch block (RBBB) is a heart condition that happens when the electrical impulses that stimulate the heart’s right ventricle are delayed or interrupted. This condition results in the right ventricle contracting slower than the left ventricle. RBBB is frequently an incidental finding that causes no issues, and some people are born with it. In RBBB, the left ventricle is activated normally, thus the early part of the QRS complex correlating to septal depolarisation is unchanged

However, RBBB may occur as a consequence of several heart conditions, including: Coronary artery disease. High blood pressure. Lung problems, such as pulmonary embolism. Valvular heart disease. Cardiomyopathy.

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For the circuit shown in the figure, the current in the 8 resistor is 0.50 A, and all quantities are accurate to 2 significant figures. What is the current in the 2 resistor?

For the circuit shown in the figure, the current in the 8 resistor is 0.50 A, and all quantities are

Answers

The current through the 2Ω resistor is 9.5A

The terminal voltage is 10.8 V

How to calculate

a) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V

the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A

the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A

voltage across 20Ω is V = I*R = 0.75*20 = 15 V

the source voltage is Vs = V8 + V20 = 4+15 = 19 V

therefore the current through 2Ω resistor is

I = V/R = 19/2 = 9.5 A

b) The terminal voltage is

Vterminal = VR = I*R = 0.450*24 = 10.8 V

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please help me and give an explanation

please help me and give an explanation

Answers

Explanation:

The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still. Scientists call this synchronous rotation

We can rule out a connection between changes in the Sun's luminosity and the global warming that is currently occurring on Earth because

changes in the Sun's luminosity cannot occur on the time scale over which global warming has occurred.

the Sun is too far away to affect Earth's climate.

Earth's atmosphere prevents changes in the Sun's luminosity from having any effect on Earth's surface.

the Sun's luminosity has remained fairly steady even as Earth's temperature as increased

Answers

The statement that best answers the question is "the Sun's luminosity has remained fairly steady even as Earth's temperature has increased."

It is not possible to rule out a connection between the changes in the Sun's luminosity and the global warming that is currently happening on Earth because the changes in the Sun's luminosity cannot occur on the time scale over which global warming has occurred since the luminosity of the Sun has been constant for more than 150 years.

Hence, changes in the Sun's luminosity cannot be the cause of global warming.

The Sun is too far away to affect Earth's climate is not true because the Sun does affect the Earth's climate as it is the source of heat and light that sustains life on Earth. In fact, if the Sun's luminosity were to change, it could affect the Earth's climate. Hence, it is not a valid statement.

Earth's atmosphere prevents changes in the Sun's luminosity from having any effect on Earth's surface is also not true because the Earth's atmosphere does not prevent the Sun's rays from reaching the surface. If there is a decrease in the Sun's luminosity, the Earth's atmosphere will not prevent the effects of that decrease from being felt on Earth.

The Sun's luminosity has remained fairly steady even as Earth's temperature has increased is the correct statement because the Sun's luminosity has not increased in the last 150 years, but the Earth's temperature has increased in the last century, so there is no direct correlation between the two.

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A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of
motion to calculate the amount of acceleration the object will experience. Then explain how the
amount of acceleration will change if the net force or the mass of the object increases.

Answers

Answer:

Explanation:

F = ma. For us, this looks like

60 = 30a and

a = 2 m/s/s

If the force goes up to, say, 90, then

90 = 30a and

a = 3...if the force goes up, the acceleration also goes up.

If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.

g what is the minimum diameter for an objective lens that will just barely resolve jupiter and the sun? the radius of jupiter's orbit is 780 million km

Answers

The minimum diameter for an objective lens that will just barely resolve Jupiter and the Sun is 5.3 mm.

What is diameter ?

Diameter is a term used to describe the width of an object, typically a circle. It is the length of a straight line passing through the center of a circle, and is the longest possible distance between two points on the circle. Diameter is also used to measure the size of many other shapes, such as ellipses, hexagons, and rectangles. Diameter can also refer to the size of a cylinder or a cone.

The minimum diameter for an objective lens that will just barely resolve Jupiter and the Sun is determined by the angular resolution of the lens. To calculate this, we can use the formula:
Angular Resolution = 1.22 * (wavelength/(diameter of the objective lens))
Assuming a wavelength of 550 nm (the average visible light wavelength), the diameter of the objective lens is calculated as follows:
Diameter of Objective Lens = 1.22 * (550 nm/Angular Resolution)
Since the radius of Jupiter's orbit is 780 million km, the angular resolution of the lens must be at least 780 million km/1.22, or 641 million km. Plugging this into the formula, we get:
Diameter of Objective Lens = 1.22 * (550 nm/641 million km)
Diameter of Objective Lens = 5.3 mm
Therefore, the minimum diameter for an objective lens that will just barely resolve Jupiter and the Sun is 5.3 mm.

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What are the factors that change the pattern observed on a screen during Young’s double-slit experiment?

Answers

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:

1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.

2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.

3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.

4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.

5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.

When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.

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