Consider the bead threaded on a circular hoop of Example 7.6 (page 260), working in a frame that rotates with the hoop.
a) Find the equation of motion of the bead, and check that your result agress with Equation (7.69).
b) Using a free-body diagram, explain the result (7.71) for the equillibrium positions.

Answers

Answer 1

The equation of motion gives T + mgsinθ = ma.

What is equation?
A mathematical equation is indeed a formula that uses the equals sign (=) to connect two expressions and express their equality. A well-formed formula made up of two expressions linked by an equals sign is considered to be an equation in English, but the word's cognates in those other languages may well have slightly different definitions. For instance, an équation is defined as having one or more variables in French. Finding the variables' values that cause the equality to be true is the first step in solving an equation with variables. The variables that the equation must be solved are also known as the unknowns, and the unknowns' values that satisfy the equality are known as the equation's solutions.

a) The equation of motion of the bead can be found using Newton's second law, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration. The equations of motion of the bead can be written as follows:
Fnet = ma
where Fnet is the net force on the bead, m is the mass of the bead, and a is the acceleration of the bead. From Example 7.6 (page 260), the net force on the bead is given by:
Fnet = T + mgsinθ
where T is the tension in the string, m is the mass of the bead, g is the acceleration due to gravity, and θ is the angle between the string and the vertical. Substituting this into the equation of motion gives:
T + mgsinθ = ma
which is the same as Equation (7.69).

b) The result (7.71) for the equillibrium positions can be explained using a free-body diagram. The free-body diagram shows the forces on the bead. The forces on the bead include the tension in the string (T), the gravitational force (mg) and the normal force (N) from the hoop. In equilibrium, the net force on the bead is zero. This means that the tension in the string must be equal to the gravitational force and the normal force.
T = mg + N
Since the hoop is in equilibrium, the normal force from the hoop must also be equal to the gravitational force.
N = mg
Substituting this into the above equation gives:
T = 2mg
which is the same as result (7.71).

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Related Questions

The speed of light in substance A is x times greater than the speed of light in substance B. v Part A Find the ratio na /no in terms of x

Answers

Given that the speed of light in substance A is x times greater than the speed of light in substance B, the ratio of n_A to n_B in terms of x is:

n_A / n_B = 1 / x

Given that the speed of light in substance A is x times greater than the speed of light in substance B, we can represent this relationship as:

v_A = x * v_B

To find the ratio n_A / n_B in terms of x, we need to consider the refractive index formula:

n = c / v

Where n is the refractive index, c is the speed of light in a vacuum, and v is the speed of light in the medium.

For substance A:
n_A = c / v_A

For substance B:
n_B = c / v_B

Now, we'll divide n_A by n_B:

(n_A / n_B) = (c / v_A) / (c / v_B)

As c (the speed of light in vacuum) is constant, it cancels out:

(n_A / n_B) = (1 / v_A) * (v_B / 1)

We know that v_A = x * v_B, so let's substitute this:

(n_A / n_B) = (1 / (x * v_B)) * (v_B / 1)

The v_B terms cancel out: (n_A / n_B) = 1 / x

So the ratio of n_A to n_B in terms of x is: n_A / n_B = 1 / x

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The piece of wood shown above has a mass of 20 grams. Calculate its volume and density. Then
use Figure 2.9 on page 37 to determine which type of wood it is. What are the two factors that
determine a material's density?

2cm
5cm
3cm

Answers

We have that The Density and Volume is given as

\(\rho=0.67\\\\\V=30cm^3\)

The factors that affect Density are Mass and Volume

From the question we are told that

The piece of wood shown above has a mass of 20 grams.

Wood parameters

2cm

5cm

3cm

Generally the equation for the Volume  is mathematically given as

\(V=L*B*H\\\\\V=2*5*3\\\\V=30cm^3\)

Generally the equation for the Density is mathematically given as

\(\rho=\frac{m}{v}\\\\\\rho=\frac{20}{30}\\\\\rho=0.67\)

Therefore the factors that affect Density are Mass and Volume

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In the fastest measured tennis serve, the ball left the racquet at 73.14 m/s . A served tennis ball is typically in contact with the racquet for 32.0 ms and starts from rest. The direction of the velocity of the ball just after it left the racquet is the positive x direction. Assume constant acceleration. Part A What was the x component of the ball's acceleration during this serve

Answers

Answer:

2.286 km/s²

Explanation:

Since acceleration a = (v - u)/t where u = initial horizontal velocity of ball = 0 m/s (since it starts from rest), v = final horizontal velocity of ball at serve = 73.14 m/s and t = time taken for serve = 32.0 ms = 0.032 s

Substituting the values of the variables into the equation, we have

a = (v - u)/t

a = (73.14 m/s - 0 m/s)/0.032 s

a = 73.14 m/s/0.032 s

a =  2285.625 m/s²

a = 2.285625 km/s²

a ≅ 2.286 km/s²

So, the x - component of the ball's acceleration during the serve is 2.286 km/s²

help me pls its for my science class i need to show my work

help me pls its for my science class i need to show my work

Answers

Answer:

P = 5880  J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

\(P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J\)

So, the required potential energy is equal to 5880  J.

What is the force of friction acting on the crate? I am offering 30 points.

What is the force of friction acting on the crate? I am offering 30 points.

Answers

I think the answer is C


Help me please, it's for physics and I really need help.

Help me please, it's for physics and I really need help.

Answers

Answer:

4. y = 2.38333t - 26.55 is the answer.

as measured in earth's rest frame, a spaceship traveling at 0.9640c takes to travel between two planets that are not moving relative to each other. how long does the trip take as measured by someone on the spaceship? a. 2.79 y b. 6.83 y c. 39.5 y d. 28.8 y

Answers

b) 6.83 years, which corresponds to approximately 2.165 years as measured by someone on the spaceship.

According to special relativity, time dilation occurs when an object is moving relative to an observer. Time dilation means that time appears to pass more slowly for the moving object compared to a stationary observer.

In this scenario, the spaceship is traveling at a speed of 0.9640c, which is 0.9640 times the speed of light. We want to find out how long the trip takes as measured by someone on the spaceship, which means we need to consider time dilation.

The time dilation factor, γ, is given by the equation:

γ = 1 / √(1 - (v^2 / c^2))

where v is the velocity of the spaceship and c is the speed of light.

Substituting the given values:

γ = 1 / √(1 - (0.9640c)^2 / c^2)

= 1 / √(1 - 0.9298)

= 1 / √(0.0702)

≈ 3.160

This means that time appears to pass approximately 3.160 times slower for someone on the spaceship compared to someone in the Earth's rest frame.

Now, let's consider the time it takes for the trip in the Earth's rest frame. We'll denote this time as t_earth.

Given that the spaceship takes t_earth to travel between the two planets as measured in the Earth's rest frame, the time it takes for someone on the spaceship, t_ship, can be calculated by:

t_ship = t_earth / γ

Substituting the provided answer options:

a) t_earth = 2.79 years

t_ship = 2.79 years / 3.160 ≈ 0.883 years

b) t_earth = 6.83 years

t_ship = 6.83 years / 3.160 ≈ 2.165 years

c) t_earth = 39.5 years

t_ship = 39.5 years / 3.160 ≈ 12.50 years

d) t_earth = 28.8 years

t_ship = 28.8 years / 3.160 ≈ 9.13 years

Based on the calculations, the correct answer is option b) 6.83 years, which corresponds to approximately 2.165 years as measured by someone on the spaceship.

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A moving car backs into a parked car in a parking lot. Why would the bumpers on both cars be dented?

Answers

Answer:

Because the bumpers are a crumple zone.

a motor run by a 7.7-v battery has a 25-turn square coil with sides of length 4.8 cm and total resistance 34 ω . when spinning, the magnetic field felt by the wire in the coil is 0.030 t. What is the maximum torque on the motor? Express your answer to two significant figures

Answers

The maximum torque is approximately 0.62 Nm when the motor is spinning.

To calculate the maximum torque of the motor, we can use the following motor torque:

τ = N * B * A * I * sin(θ)

where:

τ is torque and

N is the torque Number of turns of the coil,

B magnetic force,

A is the area of ​​the coil,

I is the current through the coil,

θ is the angle of the magnets and normal coils.

Given:

Number of turns, N = 25

Magnetic field strength, B = 0.030 T

Length of one side of the square coil, l = 4.

8 cm = 0.048 m

Resistor, R = 34 Ω

Voltage, V = 7.7 V

Let's first use Ohm's law to calculate the current through the coil:

I = V / R

V 4 = 3. ≈ 0.226 A

Now let's calculate the area of ​​the coil:

A = l^2

= (0.048 m)^2

= 0.002304 m^2

Since the coil is rotating, the angle θ will be 90 degrees (or π/2 radians), and sin(θ) = 1.

Now calculate the torque:

τ = N * B * A * I * sin(θ)

= 25 * 0.030 T * 0.002304 m^2 * 0.

226 A * 1

≈ 0.617 Nm

The maximum torque of the engine is approx. 0.62 Nm.

The maximum torque is approximately 0.62 Nm when the motor is spinning.

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what method would astronomers use to find the distance to a remote quasar?

Answers

Astronomers would use the method of "spectroscopic parallax" to find the distance to a remote quasar.

Explanation:

Spectroscopic parallax is a technique used to determine the distance to a celestial object using its spectrum. In this method, astronomers analyze the spectrum of a quasar and compare it to the spectrum of a nearby star with a known luminosity. By comparing the two spectra, they can determine the quasar's luminosity, and then use that information to calculate its distance using the inverse square law. This method is particularly useful for distant objects, like quasars, which are too far away to be measured using traditional parallax methods.

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can some help me with this question​

can some help me with this question

Answers

The answer is 2000 I need 20 characters do djrjrkrir

Answer:

It maybe 1600

Explanation:

Because it's near to 1500 in the line.

A marble dropped in still water will create circular ripples or waves. the radius of each circular wave will increase 4 centimeters per second. what is the circumference of the circle after t seconds? c(t) = πt2 c(t) = 2πt c(t) = 8πt c(t) = 16πt2

Answers

The circumference of the circle after t seconds = 25.12 t

Given data,

The radius of each circular wave will increase by four centimeters per second (cm/s)

In 1 second of circular wave radius = 4cm

In 1*t second of circular wave radius = 4t cm

 

As a result, the radius of the circular wave after t seconds is 4t cm.

We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.

As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t

                                                    = 8πt

( Taking π = 3.14 )

As a result, the circumference of the circle after t seconds = 8πt

                                                                                                     = 3.14t

                                                                                                   = 25.12t

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what happens when white light is passed through inverted prism​

Answers

The white light will disperse into 7 different colors. Remember ROYGBIV

when a fullback hits a defensive back, which of the following are true?multiple select question.the force on the fullback is the same magnitude but in the opposite direction as the force on the defensive back.the momentum before and after the collision is the same for the defensive back.the momentum before and after the collision are the same for the fullback.the total momentum before and after the collision are the same.

Answers

The following statements are true: the force on the fullback is the same magnitude but in the opposite direction as the force on the defensive back, and the total momentum before and after the collision are the same.

When a fullback hits a defensive back, the forces exerted on both players are equal in magnitude but opposite in direction according to Newton's third law of motion. This law states that for every action, there is an equal and opposite reaction. Therefore, the force on the fullback is the same magnitude as the force on the defensive back, but they act in opposite directions.

However, according to the law of conservation of momentum, the total momentum of the system (the fullback and the defensive back) remains constant if no external forces are present. Therefore, the total momentum before the collision is the same as the total momentum after the collision.

In summary, the force on the fullback is the same magnitude but in the opposite direction as the force on the defensive back. Additionally, the total momentum before and after the collision remains the same, in accordance with Newton's third law and the law of conservation of momentum.

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In a calorimetry experiment, it was determined that the heat change of the surroundings (qsurroundings) was 4482 j. what is the heat change of the system (qsystem)?

Answers

The heat of the surroundings is  - 4482 J.

What is the heat change of the system (qsystem)?

A calorimeter is a device in which that is no exchange of heat between the device and the environment. In other words, there could only be exchange of heat when the a substance has been put inside the calorimeter.

We know that in a calorimeter;

Heat of the surrounding =  Heat of the system

That implies that they are of the same magnitude but of opposite direction hence the heat of the system is - 4482 J.

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What is the Frequency of a light wave with a Wavelength of 680 x 10^-7m?

Answers

Answer:

5000°A

Explanation:

If it is right answer so please mark me as brainleist anwer as ur wish

What can electromagnetic radiation, which moves as electromagnetic waves, move through?.

Answers

Answer:

Mark Brainliest

Explanation:

Electromagnetic waves are not like sound waves because they do not need molecules to travel. This means that electromagnetic waves can travel through air, solid objects and even space.

The car in the diagram travels west with a forward acceleration of 0.22 m/s2. What was the car’s velocity (vi) at point xi if it travels a distance of 350 m in 18.4 s?

Answers

17.01 m/s is the car’s velocity .

s=ut+at²/2

s-at²/2=ut

u=s-at²/2÷t

u=312/18.4

u=17.01 m/s

"The rate at which an item changes its location" is described by a vector number called velocity. Imagine someone walking swiftly, one step forward, one step back, and starting each step from the same location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A velocity of 55 miles per hour is not adequate information. It is necessary to account for the direction in order to accurately describe the object's velocity. Simply put, the direction of the velocity vector represents the motion of the object.

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what is the symbol for specific latent heat of vaporization

Answers

Answer: L

Explanation: L is the specific latent heat for a particular substance (kJ kg−1 or in BTU lb−1), either Lf for fusion, or Lv for vaporization.

What is your hypothesis (or hypotheses) for this experiment?

(physically science lab report)​

Answers

Answer:The hypothesis (or hypotheses) for this experiment would be :

1) Experiment of motion( movement) can be performed in this lab.

2) Experiment of motion( movement) can be performed better in this lab.

3)  Only experiments of motion( movement) can be performed in this lab.

4) Experiment of motion( movement) can be performed more accurately in this lab.

5) No experiment of motion( movement) can be performed in this lab.

Explanation:

The hypothesis (or hypotheses) for this experiment would be :

Experiment regarding motion( movement) can be performed in this lab.

And Conclusion would be:

This lab is for motion.

We can only conclude that this lab is for motion when we find out that the motion experiments can be performed better or with higher accuracy or none other experiment can be carried out as easily as the motion experiment.

We only conclude when we test the hypothesis .

The hypothesis can be tested in a number of ways such as showing better results, or showing negative results of the said statement.

So there can be a few hypotheses as follows.

1) Experiment of motion( movement) can be performed in this lab.

2) Experiment of motion( movement) can be performed better in this lab.

3)  Only experiments of motion( movement) can be performed in this lab.

4) Experiment of motion( movement) can be performed more accurately in this lab.

5) No experiment of motion( movement) can be performed in this lab.

Explanation:

A 3 kg cart moves due east at 17m/s collides with a 5 kg cart moving due west. What is the initial speed of the 5 kg if the they stick together and come to rest.

Answers

The speed of 5 kg ball is 10.2 m/s

Given data:

The mass of cart 1 is m₁=3 kg.

The speed of cart 1 moving east is v₁=17 m/s.

The mass of other cart is m₂=5 kg.

Since the carts stick together, and comes to rest their final velocity is zero, i.e., v=0.

Applying the conservation of momentum between the carts as,

\(m_1v_1+m_2v_2=(m_1+m_2)v\)

Here, v₂ is the speed of 5kg cart. Since the cart 2 moving in west direction therefore v₂=-v₂.

Substitute all the values in above equation,

\(\begin{gathered} 3(17)+5(-v_2)=(3+5)(0) \\ v_2=10.2\text{ m/s} \end{gathered}\)

Thus, the speed of 5 kg ball is 10.2 m/s.

Final answer: 10.2 m/s

If Charge A is positive, then Charge B must be:







A. not enough info
B. Negative
C. Positive
D. Neutral

If Charge A is positive, then Charge B must be:A. not enough info B. NegativeC. PositiveD. Neutral

Answers

Answer:

b

Explanation:

negativity sure ans bro

During an experiment, a student moved a cell from pure water to salted water. What will most likely happen to the cell?

Answers

Answer:

During an experiment, a student moves a cell from pure water to salted water. ... It will release water and shrivel. It will release water and burst.

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.0 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 1080 samples is 6.9. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 3 of 5 : Specify if the test is one-tailed or two-tailed. Answer 2 Points Keyboard Shortcuts One-Tailed Test Two-Tailed Test Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.0 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 1080 samples is 6.9 ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 1 of 5: Enter the hypotheses: Answer 2 Points Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.0 parts/million ( ppm ). A researcher believes that the current ozone level is at an insufficient level. The mean of 1080 samples is 6.9ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 2 of 5: Enter the value of the z test statistic. Round your answer to two decimal places. Answer How to enter your answer (opens in new window) 2 Points Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.0 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 1080 samples is 6.9 ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 5 of 5 : Enter the conclusion. Answer 2 Points Keyboard Shortcuts Reject Null Hypothesis Fail to Reject Null Hypothesis Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.0 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 1080 samples is 6.9 ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 4 of 5 : Enter the decision rule. Answerhow to enter your answer (opens in new window) 2 Points Keyboard Shortcuts Reject H 0
​ if z

Answers

Assuming that the standard deviation is known to be 1.1, for a mean of 1080 samples, it can be said that the data supports the claim that the current ozone level is insufficient at the 0.02 level.

Step 1 of 5: Enter the hypotheses:

Null hypothesis (H0): The current ozone level is sufficient (μ = 7.0 ppm)

Alternative hypothesis (H1): The current ozone level is insufficient (μ < 7.0 ppm)

Step 2 of 5: Enter the value of the z-test statistic:

To find the z-test statistic, we'll use the formula:

z = (X' - μ) / (σ / √n)

where:

X' = sample mean = 6.9 ppm

μ = population mean = 7.0 ppm

σ = standard deviation = 1.1 ppm

n = sample size = 1080

Substituting the values into the formula:

z = (6.9 - 7.0) / (1.1 / √1080)

z = -0.1 / (1.1 / 32.863)

z ≈ -0.1 / 0.033157

z ≈ -3.018

Step 4 of 5: Enter the decision rule:

Since the alternative hypothesis is one-tailed (μ < 7.0 ppm), we need to compare the z-test statistic with the critical value for the given significance level.

At a significance level of 0.02, the critical value can be found using a z-table or a calculator. For a one-tailed test, the critical value is approximately -2.055.

Step 5 of 5: Enter the conclusion:

The z-test statistic (-3.018) is smaller than the critical value (-2.055). Therefore, we reject the null hypothesis.

Conclusion: The data supports the claim that the current ozone level is insufficient at the 0.02 level.

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5). A body of mass 75kg lying on a surface of
μ = 0.4 move in the direction of a horizontal force
of 300N applied to it.
a). Calculate the
i). friction force
ii). acceleration of the body
b). Explain the result in aii).

Answers

Explanation:

a) i) Calculation of the friction force:

The friction force can be determined using the equation:

friction force = coefficient of friction * normal force

The normal force is equal to the weight of the object, which can be calculated as:

normal force = mass * gravitational acceleration

where the gravitational acceleration is approximately 9.8 m/s².

normal force = 75 kg * 9.8 m/s² = 735 N

friction force = 0.4 * 735 N = 294 N

ii) Calculation of the acceleration of the body:

Now, we can calculate the acceleration using Newton's second law:

net force = mass * acceleration

Since the applied force and the friction force act in opposite directions, the net force can be calculated as:

net force = applied force - friction force

net force = 300 N - 294 N = 6 N

mass = 75 kg

6 N = 75 kg * acceleration

acceleration = 6 N / 75 kg = 0.08 m/s²

b) Explanation:

In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.

The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.

The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.

Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.

An object is solely influenced by the force of gravity and follows a parabolic path such as a rock thrown into the air. This is known
as what type of motion?
A)
circular
B)
linear
C)
periodic
D)
projectile

Answers

Answer:

B

Explanation:

A dump truck is moving at a constant velocity of 30 m/s.
Which of the following statements accurately describes the truck?

Answers

Answer: According to Newton’s 1st law, the truck must be in equilibrium.

An ice skater on a frozen canal moves at a steady 5.5 m/s. At time zero, the skater passes a post, which the initial position for this question. Set up a data table to record the skaters position at the end of second for 8.0s

Answers

At the end of the eighth second with the constant velocity of 5.5 m/s the skater will have travelled a distance of 44 meters from the initial point of reference and his position will be 44 meters from initial position.

What is constant velocity?

Velocity is a vector that presents change in displacement per unit time constant velocity implies that the change in displacement will remain the same every second.

What is position and displacement?

Position is a word that is referenced to the displacement that object has covered in a certain direction where as displacement is the shortest distance between two points.

Given:

Initial constant velocity = 5.5 m/s

According to the question this velocity remains constant throughout the motion.

To find the position of the status on the 8th 2nd after the skater passes the initial point can be found by using the displacement time formula.

Displacement = constant velocity × time

Substituting value in the displacement time formula we get.

Position at eighth second from the initial point = 5.5 × 8

Position at eighth second from the initial point = 44 meter

Therefore, at the end of the eighth second with the constant velocity of 5.5 m/s the skater will have travelled a distance of 44 meters from the initial point of reference and his position will be 44 meter from initial position.

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Calculate the Power absorbed by each circuit element in the diagram below 30 22 + 20A 120 V 15 12 VA + 14. Find the voltage v and the currents il and 12 in the figure below + 120 A D , R 30 A 11 5 23 R R2 iz

Answers

The power absorbed by each element can also be calculated using Ohm's Law: P = V^2/R.

To calculate the power absorbed by each circuit element in the diagram below, use Ohm's Law and the Power equation. First, find the voltage v and the currents i1 and i2:


V = 120V
i1 = (V - 30) / 22 = (120-30) / 22 = 4.545A
i2 = (V - 15) / 12 = (120-15) / 12 = 9.167A


Then, use the Power equation to calculate the power for each element

Power absorbed by 30Ω: P = V*i1 = 120*4.545 = 545.4W
Power absorbed by 22Ω: P = V*i2 = 120*9.167 = 1098.04W
Power absorbed by 15Ω: P = V*i2 = 120*9.167 = 1098.04W
Power absorbed by 12Ω: P = V*i2 = 120*9.167 = 1098.04W



The power absorbed by each element can also be calculated using Ohm's Law: P = V^2/R.

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an electron (m= 9.1 x10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom).

Answers

The centripetal force on the electron in the first orbit of the hydrogen atom would be 81.75 x 10⁻⁹.

What is Bohr model of atom?

The main points of Bohr's model of atom are -

Electrons orbit the nucleus in orbits that have a set size and energy.The energy of the orbit is related to its size. The lowest energy is found in the smallest orbit.Radiation is absorbed or emitted when an electron moves from one orbit to another.

Given is that an electron (e⁻) (m = 9.1 x 10⁻³¹ kg) moving at 2.18 x 10⁶ m/s (in a Bohr orbit in the H atom).

The radius of first Bohr orbit of hydrogen atom is -

{r} = 0.529 A˚ = 0.529 x 10⁻¹⁰ m.

The centripetal force on the electron in the first orbit of the hydrogen atom would be -

F = mv²/r

F = (9.1 x 10⁻³¹)(2.18 x 10⁶)²/0.529 x 10⁻¹⁰

F = 81.75 x 10 ⁻³¹ ⁺ ¹² ⁺ ¹⁰

F = 81.75 x 10⁻⁹

Therefore, the centripetal force on the electron in the first orbit of the hydrogen atom would be 81.75 x 10⁻⁹.

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Answer:its 1.9 10^26

Explanation:

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