Consider the following reference string: 2 3 2 1 5 2 4 5 3 2 5 2 How many page faults would occur for the following replacement algorithms, assuming 3 page frames. Assume all frames are initially empty. a. LRU replacement algorithm b. Enhanced second chance replacement algorithm
Answers
a. LRU replacement algorithm: The LRU replacement algorithm would result in a total of 9 page faults.
Initially, all frames are empty.
The first reference is to page 2, which requires a page fault.
The next reference is to page 3, which also requires a page fault since the frame only contains page 2.
The third reference is again to page 2, which is already present in a frame and, thus, no page fault occurs.
The fourth reference is to page 1, which requires a page fault since no frame contains this page.
The fifth reference is to page 5, which requires a page fault since no frame contains this page.
The sixth reference is again to page 2, but since it has been referenced before, it is considered the least recently used page and is replaced with page 1. This causes a page fault.
The seventh reference is to page 4, which requires a page fault since no frame contains this page.
The eighth reference is again to page 5, but since it has been referenced before, it is considered the least recently used page and is replaced with page 4. This causes a page fault.
The ninth reference is to page 3, which requires a page fault since no frame contains this page.
The tenth reference is again to page 2, which is already present in a frame and, thus, no page fault occurs.
The eleventh reference is again to page 5, which is already present in a frame and, thus, no page fault occurs.
The twelfth reference is again to page 2, which is already present in a frame and, thus, no page fault occurs.
Therefore, the LRU algorithm results in a total of 9 page faults for this reference string with 3 page frames.
b. Enhanced Second-Chance replacement algorithm:
The Enhanced Second-Chance replacement algorithm would result in a total of 8 page faults.
Initially, all frames are empty.
The first reference is to page 2, which requires a page fault.
The next reference is to page 3, which requires a page fault since the frame only contains page 2.
The third reference is again to page 2, which is already present in the frame and is given a "second chance" and its reference bit is marked to 1.
The fourth reference is to page 1, which requires a page fault since no frame contains this page.
The fifth reference is to page 5, which requires a page fault since no frame contains this page.
The sixth reference is again to page 2, which is already present in the frame and is given a "second chance" and its reference bit is marked to 1.
The seventh reference is to page 4, which requires a page fault since no frame contains this page.
The eighth reference is again to page 5, which is already present in a frame and is given a "second chance" and its reference bit is marked to 1.
The ninth reference is to page 3, which requires a page fault since no frame contains this page.
The tenth reference is again to page 2, which is already present in a frame and is given a "second chance" and its reference bit is marked to 1.
The eleventh reference is again to page 5, which is already present in a frame and is given a "second chance" and its reference bit is marked to 1.
The twelfth reference is again to page 2, which is already present in a frame and is given a "second chance" and its reference bit is marked to 1.
Therefore, the Enhanced Second-Chance algorithm results in a total of 8 page faults for this reference string with 3 page frames.
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Related Questions
Raven is adding FSMO roles to domain controllers in the domain1.com forest. The forest contains a single domain and three domain controllers, DC1, DC2, and DC3. DC1 contains a copy of the global catalog, and all three domain controllers have the latest version of Windows Server 2019 installed. Which of the following is a best practice that Raven should follow? She should use DC2 or DC3 as the Domain Naming Master. B She should create the Domain Naming Master role on DC1. She should create three Domain Naming Master roles, one for each domain controller. She does not need to create the Domain Master role because DC1 contains a copy of the global catalog.
Answers
The best practice that Raven should follow is to use DC2 or DC3 as the Domain Naming Master of the following is a best practice that Raven should follow. The correct option is A.
The management of the addition or deletion of domains from the forest is the responsibility of the Domain Naming Master. For redundancy and fault tolerance, it is advised to split the FSMO roles among several domain controllers.
Since DC1 already has a copy of the global catalog, it is advantageous to choose a different domain controller (DC2 or DC3) as the Domain Naming Master to disperse the workload and guarantee high availability. This ensures that the forest's operations may continue even if one domain controller goes offline and prevents the creation of a single point of failure.
Thus, the ideal selection is option A.
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How did engineers help to create a ceiling fan
Answers
Answer:
The electric ceiling fan was invented in 1882 by engineer and inventor, Philip Diehl. He had earlier invented an electric sewing machine and adapted the motor from this invention to create the ceiling fan. He called his invention the “Diehl Electric Fan” and it was such a success that he soon had many other people competing with him.
Explanation:
if the oil pressure gauge fluctuates over a wide range from zero to normal operating pressure, the most likely cause is group of answer choices low oil supply. broken or weak pressure relief valve spring. air lock in the scavenge pump intake.
Answers
If the oil pressure gauge fluctuates over a wide range from zero to normal operating pressure, the most likely cause is air lock in the scavenge pump intake.
Oil pressure gauge fluctuation is a common problem for the engine. It can occur due to various reasons such as faulty oil pressure gauge, oil pump failure, improper maintenance of the engine, oil leakage, and much more. But if the oil pressure gauge fluctuates over a wide range from zero to normal operating pressure, the most likely cause is air lock in the scavenge pump intake.The scavenge pump in the engine is used to remove the oil from the engine's crankcase and delivers it back to the oil tank. If there is an air lock in the scavenge pump intake, then it will not pump the oil properly from the crankcase and deliver it back to the oil tank. It will cause the oil pressure to fluctuate over a wide range from zero to normal operating pressure.To fix this issue, you should first check the oil level in the engine and make sure that it is at the proper level. After that, you can check the scavenge pump intake for any air lock or blockage. If there is an air lock, then you need to remove it. If there is a blockage, then you need to remove the blockage to get the oil pump working again properly.
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Encryption is the process of transforming a message, called plain text,
into ______ text.
which one:
cipher
hidden
abstract
virtual
Answers
The correct answer is "cipher" text. Encryption involves transforming plain text into cipher text using cryptographic algorithms and techniques to protect the confidentiality and integrity of the message.
Encryption is a fundamental concept in cryptography, which is the practice of secure communication. It involves transforming plain text, which is the original message that is readable and understandable, into cipher text, which is the encrypted version of the message that is not easily readable or understandable without the appropriate decryption key.
The process of encryption uses cryptographic algorithms and keys to perform the transformation. The algorithms define the specific mathematical operations and transformations applied to the plain text to produce the cipher text. The keys, which are typically secret and known only to the authorized parties involved, determine the specific parameters and configurations used by the encryption algorithm.
The purpose of encryption is to ensure confidentiality and privacy of sensitive information. By converting the plain text into cipher text, unauthorized individuals or attackers who intercept or gain access to the encrypted message cannot easily understand its contents. Encryption helps protect data from unauthorized disclosure and maintain the secrecy and integrity of the information being transmitted or stored.
To decrypt the cipher text and retrieve the original plain text, the authorized recipient or user must possess the appropriate decryption key or keys, which allow the reversal of the encryption process. Decryption involves applying the reverse transformations specified by the encryption algorithm using the correct key, resulting in the retrieval of the original plain text.
Overall, encryption plays a vital role in various areas, such as secure communication over networks, data protection in storage systems, safeguarding sensitive information, and ensuring the security of transactions and online interactions. It provides a powerful tool for maintaining confidentiality and securing data in today's digital world.
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Which of these was not part of the OBD II implementation?
OA. Common Codes
OB. Readiness Monitors
OC. Digital Processing
OD. Standard Terminologies
Answers
The Digital Processing is not part of the OBD II implementation.
What is an OBD II system?OBD II is known to be a kind of acronym for On-Board Diagnostic II. This is known to be the second generation of on-board self-diagnostic equipment that is needed for light- and medium-duty California vehicles.
The OBD-II is said to be a kind of on-board computer that handles emissions, , speed, etc.
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A heat engine with a thermal efficiency of 25% is connected to an electric generator with an efficiency of 95%. A liquid fuel providing heat is consumed at 2.29 litres per hour. What is the power output in kW from the generator?
Heat of Combustion: 43.7 MJ/kg
Density of the fuel: 0.749 g/ml
Answers
Answer:
4.94 kW
Explanation:
The heat energy produced by the fuel in one hour is ...
(2.29 L/h)(0.749 kg/L)(43.7 MJ/kg) = 74.954677 MJ/h
Then the power output is ...
(74.954677 MJ/h)(1 h)/(3600 s) = 20.8207 kJ/s
Multiplying this heat energy by the efficiencies of the processes involved, the output power is ...
(20.8207 kW)(0.25)(0.95) = 4.94 kW
Pls list up to five key lessons and knowledge areas that you have acquired in this course about operations management. How do you believe they help you in your future professional career?
Try to describe your response in brief detail.
Answers
Explanation:
Production planning: Planning is ideal so that there are the right resources, at the right time and in the right quantity that can meet the production needs of a period.
Strategies: The strategic development of production is the area that will assist in organizational competitiveness and in meeting consumer demand and needs.
Product and service design: Development of new products and services and their improvement, innovations and greater benefits
Production systems: Study of physical arrangements so that production takes place effectively according to the ideal layout for each type of product or service.
Production capacity planning: Analysis of the short, medium and long term related to production, and identification if necessary to obtain more resources, increase in staff, machinery, etc., to meet present and future demands.
Each area of knowledge acquired will assist in the development of a professional career, as technical knowledge is essential in decision-making, provision, problem solving, the development of new ideas and innovation.
1) I love to swim. 2) A few years ago, my new year's resolution was to become a faster swimmer. 3) First, I started eating better to improve my overall health. 4) Then, I created a training program and started swimming five days a week. 5) I went to the pool at my local gym. 6) To measure my improvement, I tried to count my laps as I was swimming, but I always got distracted and lost track! 7) It made it very hard for me to know if I was getting faster. 8) This is a common experience for swimmers everywhere. 9) We need a wearable device to count laps, calories burned, and other real-time data. Summarey of the story
Answers
Stack memory is implemented as a stack data structure. Provide the sequence of push and pop operations on stack memory when the collatz method (provided below) is called with n = 5. Note that an enqueue and dequeue is associated with a method call. For example, the first and last operations in the sequence should be push(collatz(4)) and pop(collatz(4)) respectively. public void collatz(int n) { if (n == 1) return; else if (n % 2 == 0) collatz(n / 2); else collatz(3*n + 1); }
Answers
Answer:
attached below is the solution
Explanation:
hello attached below is the sequence of push and pop operations on stack memory
For The collatz method below
public void collatz(int n) {
if (n == 1) return;
else if (n % 2 == 0)
collatz(n / 2);
else collatz(3*n + 1); }
A 10 Kw heating element, operating on rated 240 V, will have a Btu/h output of _____.
Answers
With a rated 240 V, a 10 kW heating element would unsurprisingly yield approximately 34,121.42 BTU/h.
How to solveTo determine the power of a 10 kW heating element functioning at a constant 240 V in BTU/h (British Thermal Units per hour), we must initially convert from kilowatts to watts and then use an appropriate conversion factor.
1 kW = 1,000 W
So, 10 kW equates to 10,000 W
To arrive at BTU/h, we can apply the following conversion factor:
1 W = 3.412142 BTU/h
Thus, by multiplying the wattage amount with the conversion rate, we come up with the total BTU/h output:
BTU/h = 10,000 W * 3.412142 BTU/h/W = 34,121.42 BTU/h
To conclude, with a rated 240 V, a 10 kW heating element would unsurprisingly yield approximately 34,121.42 BTU/h.
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In each of the scenarios, two spheres of the same size and shape hang from a common attachment point. Each sphere is electrically charged and is either perfectly conductive or perfectly insulating (gray is conductive, orange is insulating). The magnitude of charge Q is greater than the magnitude of charge q.
Each pair of spheres is allowed to swing freely and comes to rest in some equilibrium position. In each scenario, determine whether the spheres come to rest in contact, or separated by some distance. Assume that the weight of the spheres is small enough that electrostatic forces are significant.
Spheres come to rest in contact:
- both gray, charges -q and +q
- both orange, charges -q and +q
- both orange, charges +Q and -q
- gray, charge -Q, orange, chargef +q
Spheres come to rest separated
- both gray, +Q and +q
- both gray, -Q and +q
- both orange, -q and -Q
Answers
Spheres come to rest in contact:
- both gray, charges -q and +q
- both orange, charges -q and +q
- both orange, charges +Q and -q
- gray, charge -Q, orange, chargef +q
Spheres come to rest separated
- both gray, +Q and +q
- both gray, -Q and +q
- both orange, -q and -Q
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The weight of the spheres is small enough that electrostatic forces are significant. Spheres come to rest in contact:
- both gray, charges -q and +q
- both orange, charges -q and +q
- both orange, charges +Q and -q
- gray, charge -Q, orange, charge f +q
Spheres come to rest separated
- both gray, +Q and +q
- both gray, -Q and +q
- both orange, -q and -Q
Where can electrostatic force be found?The distance between two charges creates an electrostatic force. The distance between two charges and their respective magnitudes determine the magnitude of the electrostatic force. When two charges, either positive or negative, are brought together, they repel one another.
What is electrostatics?The phenomena and properties of electric charges that are either stationary or moving slowly are the focus of the physics branch known as electrostatics. Coulomb's law describes electrostatic phenomena, which are caused by the forces that electric charges exert on one another.
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Select the correct answer. What does a mechanical engineer do? O A. Designs buildings. OB. Designs roads. C. Designs consumer products. D. Designs machines,
Answers
Answer:
d
Explanation:
The ans is d, from the word mechanical dealing with machines
Pls help!!! will give brainly!!!
Bridge collapses have hit the news recently with more frequency. Do some research online and state two possible reasons for these collapses. How might those employed in the Health, Safety, & Environmental Management pathway help prevent these collapses and keep us safe?
Answers
Answer:
The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.
Explanation:
hope this helps
Using the correlation for the second virial coefficient (Pitzer correlation), find the molar volume of acetylene vapour at 247.1 K and 13.5 bar, giving your answer to the nearest cm3/mol. The critical temperature is 308.3 K and the critical pressure of acetylene is 61.39 bar. Take R = 8.314 J/mol-K and the acentric factor for acetylene is 0.187.
Answers
The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.
Explanation:
The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.
Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.
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Chlorine is one of the important commodity chemicals for the global economy. Before the advent of large scale
production of chlorine from electro-chemical processes, the direct catalytic oxidation of hydrochloric acid with oxygen
is used to produce chlorine. It is known as ‘Deacon process’
In production of chlorine gas by oxidation of hydrochloric acid gas, air is used 30% excess of the theoretically used.
4kmol/h of hydrochloric acid is fed to the reactor. The percentage conversion of reaction is 80%.
Reaction: 4 HCL + O2 −−→ 2 Cl2 + 2 H2O
a Calculate the composition of gas in the product stream on mole basis
Answers
The composition of gas in the feed, the percentage conversion and the
theoretical yield are combined to give the product stream composition.
Response:
The composition of gas in the product stream are;
HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/hHow can percentage conversion give the contents of the product stream?The amount of oxygen used = 30% exceeding the theoretical amount
Number of moles of hydrochloric acid = 4 kmol/h
Percentage conversion = 80%
Required:
The composition of the gas in the product feed.
Solution;
The given reaction is; 4HCl + O₂ \(\longrightarrow\) 2Cl₂ + 2H₂O
\(Percentage \ conversion = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{Moles \ of \ limiting \ reactant \ supplied \ in \ the \, feed}}\)
Which gives;
\(80 \% = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{4 \, kmol/h}}\)
Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h
Which gives;
Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h
Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Similarly;
Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h
The composition of the production stream is therefore;
HCl: 0.4 kmol/hCl₂: 1.6 kmol/hH₂O: 1.6 kmol/hO₂: 0.5 kmol/hLearn more about theoretical and actual yield here:
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Which three items below should a driver be able to identify under the hood of a car?
Answers
Answer:
Engine oil level.
Brake fluid.
Power steering fluid.
Which of the following justifies the need for an already-certified engineer to continue to take classes?
Answers
Without the choices, I’d say so that they can further progress their engineering education. New technologies and new mechanical advancements are always coming out so it would be beneficial for the engineer to keep up to date by taking classes.
A 5-m-long, 4-m-high tank contains 2.5-m-deep water when not in motion and is open to the atmosphere through a vent in the middle. The tank is now accelerated to the right on a level surface at 2 m/s2. Determine the maximum gage pressure in the tank. Mark that point at the interior bottom of the tank. Draw the free surface at this acceleration.
Answers
Answer: hello your question lacks the required diagram attached below is the diagram
answer : 29528.1 N/m^2
Explanation:
Given data :
dimensions of tank :
Length = 5-m
Width = 4-m
Depth = 2.5-m
acceleration of tank = 2m/s^2
Determine the maximum gage pressure in the tank
Pa ( pressure at point A ) = s*g*h1
= 10^3 * 9.81 * 3.01
= 29528.1 N/m^2
attached below is the remaining part of the solution
The host at the end of the video claims that ___________ is crucial to his success as a driver. A. Reaction time B. A safe space C. His seat belt
Answers
Answer:
answer is C. his seat belt
If your truck has a(n) _____, you must first turn the engine key to the ‘on’ position before engaging it.
Answers
If your truck has a starter button , you must first turn the engine key to the ‘on’ position before engaging it.
What is a Starter Button?An ignition switch, starter switch, or start switch is a switch in a motor vehicle's control system that activates the vehicle's primary electrical systems, including "accessories."
The ignition switch is a critical component of an automobile. It starts and stops the car's engine, as well as the electrical in-car devices. It also powers the starting motor of the automobile. The ignition switch not only turns on and off the engine, but it also powers the lights and radio.
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Full Question:
If your truck has a(n) _____, you must first turn the engine key to the 'on' position before engaging it. *
10 points
A. starter button
B. engine brake
C. clutch button
D. cruise control
In this lab, we assumed that the flip-flops did not contribute to the timing constraints of the circuit. Unfortunately, this is not the case. As you saw when you simulated the D flip-flop, the sampling action does not happen instantaneously. In fact, a flip-flop will become unstable if the inputs do not remain stable for a certain amount of time prior to the rising-edge event (setup time) and a certain amount of time after the rising-edge event (hold time). Assume a setup and hold time of 2ns and 1ns, respectively. What would the theoretical maximum clock rate for the synchronous adder be in this scenario
Answers
Cast-in-place concrete beams are identified on a plan view with letters and numbers that correspond to the ___.
Answers
Cast-in-place concrete beams are identified on a plan view with letters and numbers that correspond to the beam schedule.
What are concrete beams?Concrete beams refer to a load-bearing unit that can be used to carry both horizontal and vertical loads.
Cast-in-place concrete beams are identified on a plan view with letters and numbers corresponding to the beam schedule.
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Considering the CIA triad and the Parkerian hexad, what are the advantages and disadvantages of each model?
Answers
The CIA triad and the Parkerian hex are the fundamental principles of information security.
CIA triad and the Parkerian hexadParkeriano, or Parkerian hexad: is a set of six elements of information security proposed by Donn B. Parker.
1. Confidentiality.
2. Ownership or Control.
3. Integrity.
4. Authenticity.
5. Availability.
6. Utility
The Parkerian hexagram adds three more attributes to the three classic security attributes of the CIA triangle
Confidentiality Integrity Availability
these are the fundamental principles of information security.
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To prevent jammiong the distance between the work rest and grinder wheel should not exceed
Answers
The distance between the work rest and the grinder wheel should not exceed a certain limit in order to prevent jamming. This is because when the distance is too large, it can lead to instability and increase the risk of the workpiece getting caught or stuck in the grinder wheel.
To determine the maximum allowable distance, it is important to consider the specific grinder being used, as different grinders may have different specifications and safety guidelines. Generally, the manufacturer of the grinder will provide recommendations on the maximum distance between the work rest and grinder wheel.
For example, let's say you are using a bench grinder. The manufacturer's guidelines may specify that the distance between the work rest and grinder wheel should not exceed a certain measurement, such as 1/8 inch (or approximately 3.2 millimeters). This means that the work rest should be positioned close enough to the grinder wheel, ensuring that there is minimal space for the workpiece to become wedged or jammed.
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A cylindrical vessel is pressurized to 1.7 MPa. The structure on which the vessel rests becomes damaged, resulting in uneven support that causes a twisting moment T0 of 8 106 N-m on the vessel. The vessel has an outer diameter of 2.5 m and a wall thickness of 50 mm. The steel wall has a uniaxial yield strength of 600 MPa. Determine the factor of safety with respect to yielding (a) assuming a maximum shear stress yield criterion and (b) assuming a von Mises yield criterion.
Answers
Answer:
a) 15.075 , b ) 12.9
Explanation:
pressure on cylindrical vessel = 1.7 MPa
Twisting moment due to pressure = To of 8( 10^6 ) N-m
outer diameter of vessel = 2.5 m
wall thickness of vessel = 50 mm
Steel wall uniaxial yield strength = 600 MPa
Calculate the factor of safety
a) assuming a max shear stress yield criterion
safety factor = 15.075
b) assuming a von Mises yield criterion
safety factor = 12.9
attached below is the detailed solution of the problem
Select the correct answer.
What is the output of P.P( theres three lines over the second P) ?
A. P.P
B. P
C. P.P(one line over the second P)
D. P.P(one line over both ps)
Answers
Some full-time 4WD sedans use a front engine and transaxle, with a drive shaft connected to drive the rear wheels.
Select one:
True
O False
Answers
Answer:true
Explanation:
A roller support allows a beam to at that point. Select all that apply. 1)translate 2)lift off the ground 3)rotate
Answers
A roller support allows a beam to translate and rotate at that point. It does not lift off the ground. A roller support is a structural element used to support a beam, allowing it to move horizontally (translate) and/or rotate while transferring the loads acting on it to the supports on either end.
The roller support is used when a beam is required to move with temperature changes, to allow the beam to deflect without transferring load onto adjacent structures. Roller supports are used in long-span bridges and roofs, as well as industrial applications like conveyors and piping.
They are also used in structures that experience significant temperature fluctuations. When the temperature rises or falls, a beam expands or contracts. If it is fixed to the supports at both ends, it will experience large stresses that can cause damage or failure.
A roller support allows the beam to move without experiencing those stresses. Therefore, it is one of the essential structural elements that can be used in construction and other industries.
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the interior angles of a five-sided closed polygon are as follows: a, 11736127; b, 96°32°50°; c, 142°54"36"; d, 132°18*24*. the angle at e is not measured. compute the angle at e, assuming the given values to be correct
Answers
We can compute the angle at e by using the fact that the sum of the interior angles of any polygon is equal to (n-2) times 180 degrees, where n is the number of sides of the polygon.
For a five-sided polygon, the sum of the interior angles can be found using the formula:
Sum of interior angles = (5-2) x 180 degrees = 540 degrees
We know the measurements of four of the interior angles:
a = 11736127
b = 96°32°50°
c = 142°54"36"
d = 132°18*24*
To find the measurement of the angle at e, we can subtract the sum of the other four angles from the total sum of the interior angles:
Angle at e = 540 degrees - (a + b + c + d)
Angle at e = 540 degrees - (11736127 + 96°32°50° + 142°54"36" + 132°18*24*)
We need to convert all the angle measurements to degrees:
a = 11736127 degrees
b = 96.5461 degrees
c = 142.9100 degrees
d = 132.3067 degrees
Angle at e = 540 degrees - (11736127 + 96.5461 + 142.9100 + 132.3067)
Angle at e = 540 degrees - 11736198.7528
Angle at e = -11735658.7528 degrees
This answer doesn't make sense because an angle cannot have a negative measurement. It's possible that one of the given angle measurements is incorrect or that we made an error in our calculations.
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What is not a duty of a general service technician?
Answers
Order the parts needed is NOT a duty of the General Service Technician.
General service technicians are knowledgeable workers who are in charge of carrying out repair tasks on cars and other light vehicles. Customers must interact with these specialists in order to discuss pricing estimates for undertaking car maintenance services. They are required to undertake any required repairs or part replacements as well as visual vehicle inspections. They must possess the necessary skills to operate equipment that mounts and balances vehicle tyres. General service personnel should be able to install car batteries and inspect the electrical systems of vehicles.
Therefore, order the parts needed is NOT a duty of the General Service Technician.
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