The line L(t) = ⟨4+3t,2t⟩ is parallel to the line ⟨1+2t,3t−3⟩ and perpendicular to the line ⟨2+6t,1−9t⟩.
To determine whether two lines are parallel or perpendicular, we need to compare their direction vectors. The direction vector of a line can be obtained by subtracting the coordinates of any two points on the line.
For line L(t) = ⟨4+3t,2t⟩, we can choose two points on the line, let's say A(4,0) and B(7,2). The direction vector of line L is given by AB = ⟨7-4,2-0⟩ = ⟨3,2⟩.
For the line ⟨1+2t,3t−3⟩, we can choose two points, C(1,-3) and D(3,0). The direction vector of this line is CD = ⟨3-1,0-(-3)⟩ = ⟨2,3⟩.
Comparing the direction vectors, we see that the direction vectors of L and ⟨1+2t,3t−3⟩ are proportional, i.e., ⟨3,2⟩ = k⟨2,3⟩, where k is a nonzero constant. This indicates that the lines L and ⟨1+2t,3t−3⟩ are parallel.
Now, let's consider the line ⟨2+6t,1−9t⟩. Choosing two points E(2,1) and F(8,-8), we can calculate the direction vector EF = ⟨8-2,-8-1⟩ = ⟨6,-9⟩.
The direction vectors of L and ⟨2+6t,1−9t⟩ are not proportional, and their dot product is zero (3*6 + 2*(-9) = 0). This implies that the lines L and ⟨2+6t,1−9t⟩ are perpendicular.
Therefore, we can conclude that the line L(t) = ⟨4+3t,2t⟩ is parallel to the line ⟨1+2t,3t−3⟩ and perpendicular to the line ⟨2+6t,1−9t⟩.
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An oil of specific gravity 0.9 is flowing through the pipe of diameter 30cm. one end of the simple U tube manometer which contains mercury, is inserted with the center of pipe and other end is open to atmosphere. The level difference in mercury is found in the right limb as 36 cm. The distance between the center of the pipe and the mercury level in right limb is 14 cm. Find the pressure of oil in the pipe in kPa. (2.5 MARKS) (Enter only the values in the boxes by referring to the unit given in the bracket. Do not send the hand written answer sheets to my mail) The pressure of oil in the pipe Unit in kPa =
The pressure difference between the two limbs of the manometer is equal to the pressure of the oil in the pipe, the pressure of the oil in the pipe is approximately 47.2992 kPa.
To find the pressure of the oil in the pipe, we can use the concept of hydrostatic pressure.
Given:
Specific gravity of oil = 0.9
Diameter of the pipe = 30 cm
Level difference in mercury (h) = 36 cm
Distance between the center of the pipe and the mercury level in the right limb (d) = 14 cm
First, we need to calculate the pressure difference between the two limbs of the manometer. Since the right limb is open to the atmosphere, the pressure in the right limb is atmospheric pressure (Patm).
The pressure difference (ΔP) between the two limbs is given by:
ΔP = ρgh
where ρ is the density of mercury, g is the acceleration due to gravity, and h is the level difference in mercury.
The density of mercury (ρ) is approximately 13,600 kg/m³.
Converting the given values to SI units:
h = 36 cm = 0.36 m
Substituting the values:
ΔP = (13,600 kg/m³) * (9.8 m/s²) * (0.36 m)
ΔP ≈ 47,299.2 N/m²
Next, we need to convert the pressure difference to kilopascals (kPa):
1 N/m² = 1 Pascal (Pa)
1 kPa = 1000 Pa
Converting ΔP:
ΔP ≈ 47,299.2 N/m² ≈ 47,299.2 Pa ≈ 47.2992 kPa
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Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest whole number.)
you find a piece of bone that has a 14c/12c ratio that is 1/16 that of the atmospheric 14c/12c ratio. what is the approximate age of the bone?
The approximate age of the bone is 22920
The half-life of an isotope is characterized as the sum of time it takes for there to be half the beginning sum of the radioactive isotope present.
since we know for half time
N = N₀(1/2) n ..........1
where n is the new amount whereas N₀ is the initial amount and n is the number of half time
since the ratio of 14c:12c is 1/16
so the equation 1 gets converted to
N/No =(1/2)n
=>1/16 = (1/2)n
=>(1/2)4 = (1/2)n
=> n= 4
So the age of the bone will be 4* 5730 =22920
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You find a piece of bone that has a 14c/12c ratio that is 1/16 that of the atmospheric 14c/12c ratio. If the half-life of 14C is 57305730 years what is the approximate age of the bone?
a fair coin is tossed three times. let x be the number of heads on the first toss and y be the total number of heads. create a table that describes the joint pmg
The joint probability mass function (PMF) for the random variables x and y can be represented in a table with rows and columns corresponding to the possible values of x and y, respectively.
In this case, x represents the number of heads on the first toss, and y represents the total number of heads over all three tosses. There are two possible outcomes for each coin toss: heads (H) or tails (T). Thus, there are 2^3 = 8 possible outcomes for three coin tosses, which can be listed as follows: HHH, HHT, HTH, THH, HTT, THT, TTH, TTT. For the first toss, there are two possible outcomes: H or T. Thus, x can take on the values x = 0 or x = 1, with probabilities P(x = 0) = 1/2 and P(x = 1) = 1/2.
For the total number of heads over all three tosses, there are four possible outcomes: 0, 1, 2, or 3 heads. The joint probabilities can be calculated by considering the possible outcomes for each value of x. For example, if x = 0 (i.e., the first toss is a tail), then y can only be 0 or 1, depending on the outcomes of the second and third tosses. The probabilities of these outcomes are P(x = 0, y = 0) = 1/8 and P(x = 0, y = 1) = 3/8. The joint probability mass function for x and y can be summarized in a table as follows:
y=0 y=1 y=2 y=3
x=0 1/8 3/8 3/8 1/8
x=1 1/8 3/8 3/8 1/8
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6. Find the focus for the parabola.
2x=(y+3)^2+14
Focus: (x,y) =
Answer: Focus = (7.5, -3)
Step-by-step explanation:
The Vertex form of a horizontal parabola is: x = a(y - k)² + h where
a is the vertical stretch; \(a=\frac{1}{4p}\)p is the distance from the vertex to the focus(h, k) is the vertexRewrite the equation in Vertex form to identify a, h, & k:
2x = (y + 3)² + 14
\(x=\dfrac{(y+3)^2+14}{2}\\\\x=\dfrac{1}{2}(y+4)^2+7\)
Vertex: (h, k) = (7, -3)
\(a=\dfrac{1}{2}\)
Find p and then find the focus: Focus = (h + p, k)
\(a=\dfrac{1}{4p}\quad \rightarrow \quad \dfrac{1}{2}=\dfrac{1}{4p}\quad \rightarrow \quad 4p=2\quad \rightarrow \quad p=\dfrac{2}{4}\quad \rightarrow p=\dfrac{1}{2}\\\)
Focus: (7 + \(\frac{1}{2}\) , -3) = (7.5, -3)
1/2 minus 1/6 equals.
Answer:
1/3
Step-by-step explanation:
On a test called the MMPI-2, a score of 30 on the Anxiety Subscale is considered
very low. Felipe participates in a yoga group at his gym and decides to give this
subscale to 18 people in his yoga group. The mean of their scores is 35.2, with a standard deviation of 10.4. He wants to determine whether their anxiety scores are statistically equal to 30.
What are the groups for this one-sample t-test?
What is the null hypothesis for this one-sample t-test?
What is the value of "?
Should the researcher conduct a one- or two-tailed test?
What is the alternative hypothesis?
What is the value for degrees of freedom?
What is the t-observed value?
What is(are) the t-critical value(s)?
Based on the critical and observed values, should Felipe reject or retain the null
hypothesis? Does this mean that his yoga group has scores that are above 30, below 30, or
statistically equal to 30?
What is the p-value for this example?
What is the Cohen’s d value for this example?
If the " value were dropped to .01, would Felipe reject or retain the null hypothesis?
Calculate a 42% CI around the sample mean.
Calculate a 79% CI around the sample mean.
Calculate a 95% CI around the sample mean.
The MMPI-2 test is used for the assessment of psychopathology and personality of patients.
It includes 567 true-false questions, resulting in 10 clinical scales, among which one is the anxiety subscale.
A score of 30 or less is usually considered very low.
The questions are answered by the patient, usually in a clinical or research setting.
A one-sample t-test is conducted in the problem, whereby a sample of 18 participants in a yoga group is tested for anxiety scores.
The following are the parameters of the one-sample t-test:Groups:
18 participants
Null hypothesis: The anxiety scores of Felipe's yoga group are statistically equal to 30." value: 30
Type of test: One-tailed test
Alternative hypothesis: The anxiety scores of Felipe's yoga group are greater than 30.
Degrees of freedom: n - 1 = 17T-observed value: (35.2 - 30) / (10.4 / sqrt(18)) = 2.41T-critical value: 1.734
Reject or retain null hypothesis: Since the t-observed value (2.41) is greater than the t-critical value (1.734), Felipe should reject the null hypothesis, which implies that his yoga group's scores are greater than 30.P-value: 0.014Cohen’s d value: (35.2 - 30) / 10.4 = 0.5
If the " value were reduced to 0.01, Felipe would still reject the null hypothesis, since the p-value (0.014) is lower than the alpha level (0.01).
For the sample mean: 35.2CI for 42%: 35.2 ± 0.58CI for 79%: 35.2 ± 1.16CI for 95%: 35.2 ± 2.13
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25+14 please answer this
Answer:
39
Step-by-step explanation:
Step-by-step explanation:
\(39 \: is \: the \: answer\)
A rectangular painting has an area of 420 square inches. If the length is (2x + 5) inches and the width is (x) inches, then what is the value of x? Use completing-the-square and round the value of x to the nearest tenth. (Hint: You may find 2 solutions, but you only need the positive solution because the length and width must be positive values)
Answer:
12.1 inches
Step-by-step explanation:
Since the length of the rectangular painting is (2x + 5) inches and its width is x inches, it area A = (2x + 5)x square inches = 2x² + 5x.
Also, A = 420 square inches. So,
2x² + 5x = 420
2x² + 5x - 420 = 0
diving through by 2, we have
2x²/2 + 5x/2 - 420/2 = 0/2
x² + 5x/2 - 210 = 0
adding halt the coefficient of x squared to both sides, that is (5/2 ÷ 2)² = (5/4)² to both sides, we have
x² + 5x/2 + (5/4)² - 210 = 0 + (5/4)²
Simplifying, we have
(x + 5/2)² - 210 = 25/16
adding 210 to both sides, we have
(x + 5/2)² - 210 + 210 = 25/16 + 210
(x + 5/2)² = 25/16 + 210
(x + 5/2)² = (25 + 3360)/16
(x + 5/2)² = 3385/16
taking square root of both sides, we have
√(x + 5/2)² = ±√(3385/16)
(x + 5/2) = ±√3385/4
(x + 5/2) = ±58.18075/4
(x + 5/2) = ±14.55
x = -5/2 ±14.55
x = -2.5 ±14.55
x = -2.5 - 14.55 or -2.5 + 14.55
x = - 17.05 or 12.05
Since x = width and it cannot be negative, we choose the positive answer. So, x = 12.05 inches ≅ 12.1 inches (to the nearest tenth)
Can anyone factor these equations?
The factoring of the expressions would yeild;
a) (3x + 1) (x + 2)
b) Can not be factored
c) 2[(4x - 5) (x - 3)]
How do we carry out factoring?
Factoring is the process of finding the prime factorization of an integer, which is finding the prime numbers that multiply together to give the original number. There are several methods for factoring including:
It is important to choose the right method based on the type of number being factored and the problem at hand.
The factoring of the quadratic expressions would give;
a) (3x + 1) (x + 2)
b) Can not be factored
c) 2[(4x - 5) (x - 3)]
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Lucas is planning to attend a state university and qualifies for financial aid. Which of the sets below can Lucas apply for solely based on his financial need?
Answer: hello the options related to your question is not available but I will give a general answer based on Financial aid.
answer :
Scholarship , Grant and student Loan
Step-by-step explanation:
Since Lucas is planning to attend a state university and not a Federal university and he qualifies for a financial aid . The sets of financial aid that Lucas can apply for are :
Scholarship , Grant and student Loan
Note : Lucas would have qualified for work-study loan if he was a Federal student
Work-study loans are granted only to Federal college student by the federal government to aid them get a job while they study.
expand 4(q+4)? pls help :)
Answer:
4q + 16
Step-by-step explanation:
4 × q = 4q
4 × 4 = 16
4q + 16
Find the coordinates of the vertex of the following parabola using graphing
technology. Write your answer as an (x,y) point.
y = x2 – 2x - 3
(X2) the 2 pose to be on the top right of x as in power to the 2
(1,-4)
build a table to plot the curve
y=x^2 - 2x - 3
x ¦ y
-2. 5
-1 0
0. -3
1. -4
2. -3
graph from desmos
if i was born on september 13, 2004 what horoscope am i?
Answer:
virgo
Step-by-step explanation:
Answer:
\( \huge\red{\boxed{\mathfrak{Virgo}}}\)
➳ People born from September 1st to September 22nd are members of the Virgo sign. Since you were born on September 13, you are a Virgo (♍). As one of the zodiac's most understanding and caring signs, a Virgo can be easily spotted by their innate compassion.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
\( \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}\)
ayuda porfavor cuanto es h+3cm=? y cuanto es b+4cm=? y cual seria el resustado de las dos calculacion
GOOD MORNING,
HAVE A GREAT DAY AHEAD
Please help, I don’t need the explanation I just need the answer I don’t have a lot of time before the wakes took disappears so please be fast if u can
given data:
The function
\(G(x)=x^2\)The graph in the figure is asme as the graph of the above function, but it is shifted 3 units upwards that is vertically.
The equation of the graph would be,
\(F(x)=x^2+3\)Thus, the answer is option A).
Consider the following common approximation when X is near zero Estimate f(0.4) and give the maximum error In the approximation using n =2. Estimate f(0.7) and give the maximum error in the approximation using n = 2. f(x) = sin (X)~x (0.4) = (Type an Integer or a decimal:)
The common approximation when X is near zero is sin(x) ~ x. The maximum error in the approximation using n =2 is:
Sin(0.4) is approximately 0.4 with a maximum error of 0.0010667.
Sin(0.7) is approximately 0.7 with a maximum error of 0.11765.
1. For x = 0.4, sin(0.4) ~ 0.4.
The maximum error in the approximation using n = 2 is given by the Taylor remainder term with x = 0.4 and n = 2:
|R2(0.4)| <= (0.4)^3 / 3! * |cos(c)|, where c is between 0 and 0.4.
The maximum value of |cos(c)| is 1, so we have:
|R2(0.4)| <= (0.4)^3 / 3! = 0.0010667
Therefore, sin(0.4) is approximately 0.4 with a maximum error of 0.0010667.
2. For x = 0.7, sin(0.7) ~ 0.7:
The maximum error in the approximation using n = 2 is given by:
|R2(0.7)| <= (0.7)^3 / 3! * |cos(c)|, where c is between 0 and 0.7.
The maximum value of |cos(c)| is 1, so we have:
|R2(0.7)| <= (0.7)^3 / 3! = 0.11765
Therefore, sin(0.7) is approximately 0.7 with a maximum error of 0.11765.
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Solve for N.
N - 26 = 72
N - 26 +
= 72 +
N =
Answer:
98
Step-by-step explanation:
Solve : n-98 = 0
Add 98 to both sides of the equation :
n = 98
Select the correct answer from each drop-down menu. the expression equivalent to sin 3x sin x is . the expression equivalent to sin 3x− sin x is .
The simplified trigonometric expression in this problem is defined as follows:
sin(3x)/sin²(x) = 3csc(x) - 4sin(x).
How to simplify the trigonometric expression?The trigonometric expression in this problem is defined as follows:
sin(3x)/sin²(x).
The equivalent expression for the sine of 3x is given as follows:
sin(3x) = 3sin(x) - 4 sin³(x).
Then the expression can be written as follows:
(3sin(x) - 4 sin³(x))/sin²(x)
The subtraction is in the numerator, hence the expression can be simplified as follows:
3sin(x)/sin²(x) - 4sin³(x)/sin²(x)
3/sin(x) - 4sin(x)
One divided by the sine is equivalent to the cossecant, hence:
3/sin(x) - 4sin(x) = 3csc(x) - 4sin(x).
Meaning that the first option among those given on the image at the end of the answer is correct.
Missing InformationThe problem is given by the image shown at the end of the answer.
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Find the value of z.
this is a graphing problem and I am trying to figure out what the x-intercepts and the y-intercepts are. "Pleas show the steps"
Answer:
x- intercept = 4 , y- intercept = - 2
Step-by-step explanation:
To find the x- intercept let f(x) = 0 , that is
\(\frac{x-4}{-x+2}\) = 0
The denominator cannot be zero as this would make f(x) undefined
Equating the numerator to zero
x - 4 = 0 ⇒ x = 4 ← is the x- intercept
To find the y- intercept let x = 0 , that is
f(0) = \(\frac{0-4}{-0+2}\) = \(\frac{-4}{2}\) = - 2 ← is the y- intercept
I need to find the easiest way to learn how to divide fractions
Step-by-step explanation:
to divide fractions you just flip the fraction after the divide symbol then you multiple.
e.g. \(\frac{1}{2}\)÷\(\frac{2}{3}\) = \(\frac{1}{2}\)×\(\frac{3}{2}\)..... then multiply!
Answer:
you can get chance to learn various types of fraction if you meet to your math teacher.
Step-by-step explanation:
I couldn't do because there is no system for making questions of fraction and solutions because keyboard goes give me to keep denominator.
answer and I’ll give you brainlist !!
graph y <1-3x
Answer:
Step-by-step explanation:
b
Answer:
yea its b
Step-by-step explanation:
graphed
Using traditional methods it takes 93 hours to receive an advanced flying license. a new training technique using computer aided instruction (cai) has been proposed. a researcher used the technique on 60 students and observed that they had a mean of 95 hours. assume the population variance is known to be 49. is there evidence at the 0.05 level that the technique lengthens the training time? step 2 of 6 : find the value of the test statistic. round your answer to two decimal places.
To find the value of the test statistic, we need to perform a hypothesis test. In this case, we want to test if the new training technique using computer-aided instruction (CAI) lengthens the training time.
Let's set up the hypotheses:
Null Hypothesis (H0): The new training technique does not lengthen the training time.
Alternative Hypothesis (H1): The new training technique lengthens the training time.
We can conduct a one-sample t-test since we have the sample mean and the population variance is known.
The test statistic formula for a one-sample t-test is:
t = (sample mean - population mean) / (population standard deviation / sqrt(sample size))
Here, the sample mean is 95, the population mean is 93 (from traditional methods), the population variance is 49, and the sample size is 60.
Plugging in the values into the statistic equation, we get:
t = (95 - 93) / (sqrt(49) / sqrt(60))
t = 2 / (7 / 2.449)
t ≈ 2 / 2.857
t ≈ 0.699
The value of the test statistic is approximately 0.699.
So, the value of the test statistic is approximately 0.699.
Now, we can compare this test statistic to the critical value from the t-distribution table to determine if there is evidence at the 0.05 level to support the claim that the new training technique lengthens the training time.
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Using the analemma, calculate the approximate noon Sun angle at 41 ∘
N latitude (on Long Island) February 14th. Choose the correct answer below. a. 14 ∘
b. 23.5 ∘
c. 35 ∘
d. 41 ∘
e. 90 ∘
The approximate noon Sun angle at 41°N latitude (on Long Island) on February 14th is 61°. None of the provided answer choices match the correct answer.
To calculate the approximate noon Sun angle at 41°N latitude (on Long Island) on February 14th, we can use the analemma.
The analemma is a figure-8 shaped curve that represents the position of the Sun in the sky at the same time each day over the course of a year. It accounts for the Earth's axial tilt and elliptical orbit around the Sun.
To find the approximate noon Sun angle, we need to consider the declination of the Sun on February 14th and the latitude of Long Island.
On February 14th, the Sun's declination is approximately -12°.
The Sun angle at noon can be calculated using the following formula:
Sun angle = 90° - (latitude - declination)
Substituting the values, we have:
Sun angle = 90° - (41° - (-12°))
Simplifying this equation, we get:
Sun angle = 90° - 41° + 12°
Sun angle = 61°
Therefore, the approximate noon Sun angle at 41°N latitude (on Long Island) on February 14th is 61°.
None of the provided answer choices match the correct answer.
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Find the smallest square number that is divisible by each of the numbers 8, 9 and 10
Answer:
Step-by-step explanation:
Find the LCM of 8,9 and 10.
Prime Factorization to find LCM,
8 = 2 × 2 × 2
9 = 3 × 3
10 = 2 × 5
LCM ( 8 , 9 , 10 ) = 2 × 2 × 2 × 3 × 3 × 5 =360
But 360 is not square
Now we make the pairs complete by multiplying same numbers in prime factorization of LCM.
We need one 2 and one 5 to complete the pair.
We get, Least Square number = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 3600
Hope this helps
good Luck
Answer:
Step-by-step explanation:
Find Least common denominator of 8, 9 & 10
8 = 2 * 2 * 2
9 = 3* 3
10 = 5*2
LCM = 2*2*2*3*3*5 = 8 * 9 * 5 = 360
To make 360 a perfect square,multiply by 10
360*10 = 3600 is a perfect square
Nina has one job babysitting another job walking dogs. Each week she babysits for 21 hours and walk stocks for nine hours Sharon $7.50 per hour for dog walking. She earns $1.50 more per hour for babysitting them for dog walking there are 4 1/2 weeks in the month of July. What is the best estimate for the total amount of money Nina earns in July.
Answers :
$250
$750
$1200
$1500
Answer:
The best estimate for her earnings is $1200
Step-by-step explanation:
Number of time spent babysitting each week = 21 hours = BBS
Number of time spent dog walking each week = 9 hours = DW
She earns $7.50 per hour for dog walking,
She earns $(7.50+1.50) = $9 for baby sitting,
There are 4 1/2 weeks = 9/2 weeks in July,
Now, for each week she earns 21(9) = $189 from baby sitting
and 9(7.5) = $67.5 from dog walking,
So, for the month of July, i.e. 9/2 weeks, she earns,
9/2(189) = $ 850.5 from baby sitting,
and (9/2)(67.5) = $303.75 from dog walking,
In total for the month, she earns,
850.5 + 303.75 = $1154.25
Hence the best estimate for her earnings is $1200
Can I get help on this one
Answer:
150
Step-by-step explanation:
The angle as a whole is 180 degrees. 150 and 30 are supplementary angles because they add up to equal 180.
Solve the following Linear Programming Problem by Graphical Method:
Max z = 15x1 + 20 xz x₁ + 4x₂ ≥ 12 x₁ + x₂ ≤ 6 s.t., and x₁, x₂ ≥ 0
The solution to the linear programming problem is:
Maximum value of z = 120
x₁ = 0, x₂ = 6
To solve the given linear programming problem using the graphical method, we first need to plot the feasible region determined by the constraints and then identify the optimal solution.
The constraints are:
x₁ + x₂ ≥ 12
x₁ + x₂ ≤ 6
x₁, x₂ ≥ 0
Let's plot these constraints on a graph:
The line x₁ + x₂ = 12:
Plotting this line on the graph, we find that it passes through the points (12, 0) and (0, 12). Shade the region above this line.
The line x₁ + x₂ = 6:
Plotting this line on the graph, we find that it passes through the points (6, 0) and (0, 6). Shade the region below this line.
The x-axis (x₁ ≥ 0) and y-axis (x₂ ≥ 0):
Shade the region in the first quadrant of the graph.
The feasible region is the overlapping shaded region determined by all the constraints.
Next, we need to find the corner points of the feasible region by finding the intersection points of the lines. In this case, the corner points are (6, 0), (4, 2), (0, 6), and (0, 0).
Now, we evaluate the objective function z = 15x₁ + 20x₂ at each corner point:
For (6, 0): z = 15(6) + 20(0) = 90
For (4, 2): z = 15(4) + 20(2) = 100
For (0, 6): z = 15(0) + 20(6) = 120
For (0, 0): z = 15(0) + 20(0) = 0
From the evaluations, we can see that the maximum value of z is 120, which occurs at the corner point (0, 6).
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Write the statement "--5 times x subtracted from 22 is less than 9 more than
x" as a mathematical inequality. I dont know this sorry
Answer:
5x-22<9<x
Step-by-step explanation:
5 times x = 5x
subtract 22 = 5x-22
less then = 5x-22<
9 more then x = 5x-22<9<x