Consider the linear regression model Y
i


0


1

X
1i


2

X
2i

+u
i

. a) Suppose you multiply all the X
2

values by 2 . What will be the effect of this rescaling, if any, on the estimates of the parameters and their standard errors? b) Now instead of (a), suppose you multiply all the Y values by 2. What will be the effect of this, if any, on the estimated parameters and their standard errors?

Answers

Answer 1

To generate data for the linear regression model, simulate x₁, x₂, and ε from appropriate distributions. Fit the data into the model to estimate β₀, β₁, β₂, and σ² using linear regression.

To generate data for the linear regression model and estimate the parameters, follow these steps:

Specify the parameter values:

Choose values for β₀, β₁, β₂, and σ². For example, let's set β₀ = 2, β₁ = 0.5, β₂ = -1, and σ² = 0.1.

Generate the predictor variables:

Simulate x₁ and x₂ from suitable distributions. For instance, x₁ can be generated from a uniform distribution U(0, 10), and x₂ from a normal distribution N(5, 2).

Generate the error term:

Sample ε from a normal distribution with mean 0 and variance σ². For example, ε ~ N(0, 0.1).

Calculate the response variable:

Compute y using the linear regression model: y = β₀ + β₁x₁ + β₂x₂ + ε.

Perform linear regression:

Fit the generated data into a linear regression model to estimate the parameters β₀, β₁, β₂, and σ².

Assess the estimated parameters:

Examine the estimated values of β₀, β₁, β₂, and σ² obtained from the linear regression analysis.

These estimates represent the best-fit values of the parameters based on the generated data.

By following these steps, you can simulate the predictor variables x₁ and x₂, generate the error term ε, calculate the response variable y, and perform linear regression to estimate the parameters β₀, β₁, β₂, and σ². The estimated values will provide insights into the relationships between the predictors and the response variable in the simulated linear regression model.

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Question

Consider linear regression model y=β_0+β_1 x_1+β_2 x_2+ε, where ε~N(0,σ^2). You can define your own β_0, β_1, β_2 and σ^2. 1. Generate your data by simulating x_1, x_2 and ε, and fit them into the above model to generate y. For example, x_1 and x_2 can be generated from some uniform distribution. Make sure the noise variance is smaller enough compared to the value of y. Then do a linear regression to estimate β_0, β_1, β_2 and σ^2.


Related Questions

Solve the following equation for x.

Answers

What’s the equation? It’s not a showing a picture attached.

Answer:

Step-by-step explanation: what’s the equation?

A test for ovarian cancer has a 5 percent rate of false positives and a 0 percent rate of false negatives. On average, 1 in every 2,500 American women over age 35 actually has ovarian cancer. If a woman over 35 tests positive, what is the probability that she actually has cancer? Hint: Make a contingency table for a hypothetical sample of 100,000 women. Explain your reasoning.

Answers

Given the provided information, if a woman over 35 tests positive for ovarian cancer, the probability that she actually has cancer is approximately 1.96%.

To determine the probability that a woman over 35 actually has ovarian cancer given a positive test result, we can create a contingency table and use conditional probability. Let's consider a hypothetical sample of 100,000 women:

Out of 100,000 women, 1 in every 2,500 (or 40 out of 100,000) actually has ovarian cancer. Since the test has a 0% rate of false negatives, all the women with ovarian cancer will test positive.

The test also has a 5% rate of false positives. This means that out of the remaining 99,960 women who do not have ovarian cancer, approximately 5% (or 4,998) will test positive incorrectly.

Therefore, out of a total of 5,038 positive test results (40 true positives + 4,998 false positives), only 40 are true positives for ovarian cancer. The probability that a woman who tests positive actually has ovarian cancer can be calculated as the ratio of true positives to the total positive tests:

Probability = (True Positives) / (Total Positive Tests) = 40 / 5,038 ≈ 0.00795 ≈ 0.795%

Thus, the probability that a woman over 35 actually has ovarian cancer given a positive test result is approximately 1.96%. This calculation highlights the importance of considering both the prevalence of the disease and the accuracy of the test in interpreting the results correctly.

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need ASAP BEFORE 10:30PM
The heights of two vertical posts are 2 meters and 0.45 meter. When the shorter post casts a shadow that is 0.85 meter long, what is the length of the longer post's shadow to the nearest hundredth?
explain please​

Answers

Answer: 3.78m

Step-by-step explanation: I hope that helps

true or false In the equation 3x+6 the 3 is known as the constant?

Answers

Answer:

the 3 and 6 are constants.

the x is a variable

hope it helped:)))))))))))))))))

false I believe

hope this helps.

what is the slope of (-2,13) and (1,1)

Answers

Answer:

y = -4x + 5

Step-by-step explanation:

hope this helps


A square floor tile has a diagonal 19 inches long. What is the area of the tile?
A) 53.7 in.2
B 107.5 in.2
C 180.5 in.2
D 361.0 in.2

Answers

Answer:

C

Step-by-step explanation:

The answer is C because you plugin using the area formula.


1. There are 130 boys. 100. girls, and 20 adults. Write the ratio of the
number of girls to the number of adults. *

Answers

Answer:

100:20 or 100/20 or 100 to 20

15 x 15 x 15 as a power

Answers

15^3 is the answer to the question

Answer:

\(15^{3}\)

Step-by-step explanation:

\(15 * 15 *15 \\15^{3}\)

find f '(0.4) for f of x equals the integral from 0 to x of the arcsine of t, dt. 0.081 0.412 0.389 1.091

Answers

The task is to find f '(0.4) for the function f(x) = ∫[0 to x] arcsin(t) dt. The possible answers are: 0.081, 0.412, 0.389, and 1.091. The closest value to 0.4115 is 0.412. Thus, the answer is 0.412.

To find f '(0.4), we need to differentiate the function f(x) with respect to x. Applying the Fundamental Theorem of Calculus, we have f '(x) = arcsin(x). Therefore, to find f '(0.4), we substitute x = 0.4 into the derivative expression: f '(0.4) = arcsin(0.4). Evaluating this trigonometric function, we find that arcsin(0.4) is approximately 0.4115. Among the given options, the closest value to 0.4115 is 0.412. Thus, the answer is 0.412.

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The area of the garden was 2 2/5yd2. if the lrngth is 1 1/2 yd, find the width

Answers

The area of any quadrilateral can be determined by multiplying the length of its base by its height. Since we know the shape here is square, we know that all sides are of equal length. From this we can work backwards by taking the square root of the area to find the length of one side.

Hey. I kindly ask for instant help!

Hey. I kindly ask for instant help!

Answers

Using the combination formula, the probabilities are given as follows:

a) P(4 seniors) = 0.0008.

b) P(1 of each) = 0.0999.

c) P(2 sophomore, 2 freshmen) = 0.0225.

d) P (at least one senior) = 0.5866.

Combination Formula

\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the formula presented below, involving factorials.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

In this problem, 4 captains are taken from a set of 13 + 13 + 10 + 16 = 52, hence the number of outcomes is:

\(C_{52,4} = \frac{52!}{4!48!} = 270725\)

The number of outcomes with four seniors is given as follows:

\(C_{10,4} = \frac{10!}{4!6!} = 210\)

Hence the probability is:

p = 210/270725 = 0.0008.

With no seniors, the number of outcomes is:

\(C_{42,4} = \frac{42!}{4!38!} = 111930\)

Hence with at least one senior, the number of outcomes is:

270725 - 111930 = 158795.

Hence the probability is:

p = 158795/270725 = 0.5866.

With one of each, the number of outcomes is:

13 x 13 x 10 x 16 = 27040

Then the probability is:

27040/270725 = 0.0999.

With two sophomores and two freshmen, the number of outcomes is:

\(C_{13,2} \times C_{13,2} = \frac{13!}{2!11!} \times \frac{13!}{2!11!} = 6084\)

Then the probability is:

6084/270725 = 0.0225.

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1. At time t > 0, a particle moving in the xy-plane has velocity vector given by v(t) = (3t2,7t). What is

the acceleration vector of the particle at time t = 2?

Answers

The acceleration of a particle is given by the derivative of its velocity vector with respect to time. The acceleration vector of the particle at time t = 2 is (12, 7).

So, to find the acceleration of the particle at time t = 2, we need to find the derivative of its velocity vector with respect to time and then evaluate it at t = 2.

The velocity vector is\(v(t) = (3t^2, 7t)\), so its derivative with respect to time is:

\(dv(t)/dt = (d/dt)(3t^2, 7t) = (6t, 7)\)

Evaluating this at t = 2, we have:

dv(t)/dt = (6 * 2, 7) = (12, 7)

So, the acceleration vector of the particle at time t = 2 is (12, 7).

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1. At time t > 0, a particle moving in the xy-plane has velocity vector given by v(t) = (3t2,7t). What is the acceleration vector of the particle at time t = 2?

PLEASE HELP!Find the slope of the line on the graph.
Write your answer as a fraction or a whole
number, not a mixed number or decimal

PLEASE HELP!Find the slope of the line on the graph.Write your answer as a fraction or a wholenumber,

Answers

Answer:

3/1 or 3

Step-by-step explanation:

It rises up three and to the side one

Answer: The slope is 3.

It costs mrs. richardson $13.67 to arrange a flower bouquet for a wedding. she charges the bride $35 for the arrangement. how much money does mrs. richardson profit from each arrangement?

Answers

Mrs. Richardson makes a profit of $21.33 from each flower arrangement for the wedding.

To calculate the profit, we subtract the cost from the selling price. Mrs. Richardson's cost for arranging the bouquet is $13.67, and she charges the bride $35 for the arrangement.

Profit = Selling Price - Cost

Profit = $35 - $13.67

Profit = $21.33

Therefore, Mrs. Richardson makes a profit of $21.33 from each flower arrangement for the wedding.

In this scenario, the profit is calculated by subtracting the cost of arranging the bouquet from the selling price. The cost incurred by Mrs. Richardson is $13.67, which includes the expenses for materials, labor, and any other associated costs. On the other hand, the selling price is $35, which is what the bride pays for the arrangement.

By subtracting the cost from the selling price, we find that the profit per arrangement is $21.33. This means that Mrs. Richardson earns $21.33 for each bouquet she arranges for a wedding, after covering her costs.

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Find the quotient of the quantity negative 12 times x to the 3rd power plus 21 times x to the 2nd power minus 6 times x all over negative 3 times x

Answers

The  quotient of the expression \((-12x^3 + 21x^2 - 6x) / (-3x)\) is \(4x^2 - 7x + 2.\)

How to find the quotient

To find the quotient of the given expression, we divide the numerator by the denominator.

Expression:\((-12x^3 + 21x^2 - 6x) / (-3x)\)

Factoring  out the common term 'x' from the numerator:

\(x * (-12x^2 + 21x - 6) / (-3x)\)

Simplify the expression by canceling out the common terms 'x':

\((-12x^2 + 21x - 6) / (-3)\)

Dividing  each term in the numerator by -3:

\((-12x^2 / -3) + (21x / -3) + (-6 / -3)\)

Simplifying y each term:

\(4x^2 - 7x + 2\)

Therefore, the quotient of the expression \((-12x^3 + 21x^2 - 6x) / (-3x)\) is \(4x^2 - 7x + 2.\)

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Find the surface area of the figure. Be sure to show all of your work and steps in solving
for your answer.

Please show me the steps and solutions not just answers pls pls pls help me, tysm!!

Find the surface area of the figure. Be sure to show all of your work and steps in solvingfor your answer.Please

Answers

The surface area of the figure which comprises two rectangular prisms is: 328 in.²

What is the Surface Area of a Rectangular Prism?

Surface area = 2(wl+hl+hw)

Decompose the given figure into two.

Surface area of the figure = surface area of the top rectangular prism + surface area of the bottom rectangular prism - 2(area of base of the top rectangular prism)

Surface area of top rectangular prism:

l = 6 in.

w = 4 in.

h = 5 in.

Surface area = 2(wl+hl+hw) = 2(4×6 + 5×6 + 5×4) = 148 in.²

Surface area of bottom rectangular prism:

l = 6 in.

w = 9 in.

h = 4 in.

Surface area = 2(wl+hl+hw) = 2(9×6 + 4×6 + 4×9) = 228 in.²

Area of base of the top rectangular prism:

Area = (l)(w) = (6)(4) = 24 in.²

Surface area of the figure = 148  + 228 - 2(24)

Surface area of the figure = 328 in.²

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4 Suki watches a movie and eats a snack afterward. The movie starts at 7:15 PM
and is 1 hours long. Suki finishes her snack at 9:10 PM. How long does Suki
spend eating a snack?
Show your work.


It’s question 4 btw

4 Suki watches a movie and eats a snack afterward. The movie starts at 7:15 PMand is 1 hours long. Suki

Answers

Answer:

25 minutes long

Explanation:

Hope this helps!

Ok so we know that the movie starts at 7:15 PM. The duration of the movie is 1.5 hours long. She begins eating her snack after the movie which, sense 7:15 plus 1.5 hours is 8:45, is 8:45. She finishes her snack at 9:10. What is the difference between 9:10 and 8:45?

For me, the easiest thing to do we would be to add a half hour (30 minutes) to the 8:45. This gets 9:15. Since 9:15 is past 9:10, I subtract the difference to get 5 minutes. I then take the 30 minutes I added to the 8:45 and subtract the 5 minutes that it went over to get 25 minutes. This is the easiest way to get the answer in my opinion. Sorry if this could not be of help to you!

Diagram to better understand maybe? (I did the best I could with this lol)

                                              x (the 25 minutes you found once you solved it)

                                                                                      ^

7:15 PM ----------------------------- 1.5 hours later----------------------------------- 9:10 PM

^                                                          ^                                                            ^

Time the movie started          Movie length             When she finished eating

♡ I am so proud of you! You are doing amazing and you are glowing! Keep up the great work and have a good day! ♡

Fill in the blank to make this statement true: (0,0) is a solution to _________ equation(s) in the form y=kx. no one some all

Answers

Answer:

All

Explanation:

When an equation is in the form of y=kx, it displays direct variation, meaning that the y-intercept is 0. For example, take an equation in slope-intercept form, it has an equation of y=mx+b. Since there is no "b", in the form y=kx, that means that the line must pass through the origin, or (0,0)

Answer:

one

Step-by-step explanation:

Plug in (0,0) for the solution.

0(y)=k x 0(x)

simplify

0=0

that is true so that would be the answer.

Trigonometry:
Find the value of θ

Trigonometry:Find the value of

Answers

Answer:

θ ≈ 50.1°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cosθ = \(\frac{adjacent}{hypotenuse}\) = \(\frac{61}{95}\) , then

θ = \(cos^{-1}\) ( \(\frac{61}{95}\) ) ≈ 50.1° ( to the nearest tenth )

Evaluate b^2c^1 for b=-4 and c= 2.

Answers

Answer:

32

Step-by-step explanation:

b^2c^1

Let b=-4 and c= 2

(-4)^2 ( 2)^1

16 * 2

32

Answer:

The correct answer is

-32

Step-by-step explanation:

All you need to do is plug in -4 and 2 into the equation to get:

4^2 times 2^1

This equals ...

-32

Hope this helps!

- xoxo Quinnisa

24.4 divided by 0.4 im stuck like step bro

Answers

Answer is : 61

We then have the equations:
244 ÷ 4 = 61.000
and therefore:
24.4 ÷ 0.4 = 61.000
Both calculated to 3 decimal places.

coin aa is flipped three times and coin bb is flipped four times. what is the probability that the number of heads obtained from flipping the two fair coins is the same?

Answers

P = 35/128  is the probability that the number of heads obtained from flipping the two fair coins is the same.

Describe probability using an example?

By dividing the number of preferable possibilities by the total number of potential outcomes, probability, which measures the likelihood that an event will occur, is obtained. The most basic illustration is a coin toss. There are only two outcomes that can occur when you flip a coin: either heads or tails.

P( oH )  = ³C₀ (1/2)³ . ⁴C₀ (1/2)⁴  = 1 . 1/128

P( 1H) = ³C₁ (1/2)³ . ⁴C₁( 1/2 )⁴ = 12/128

P( 2H ) = ³C₂ (1/2)³ . ⁴C₂ (1/2)⁴ = 18/128

P( 3H) = ³C₃ ( 1/2)³ . ⁴C₃ ( 1/2)⁴ = 4/128

P = 1/128 + 12/128 + 18/128 + 4/128

P = 35/128

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Functions f(x) and g(x) are shown:

f(x) = x2
g(x) = x2 − 8x + 16

In which direction and by how many units should f(x) be shifted to match g(x)?

Left by 4 units
Right by 4 units
Left by 8 units
Right by 8 units

Answers

it needs to be shifted to the positive side of the graph by 4 units so right by 4 units is the correct answer

The answer is A. Left by four units. I took the test so it is correct, here is photographic proof:

Please hurry and no links, thank you!Functions f(x) and g(x) are shown:f(x) = x2g(x) = x2 8x + 16In which

In each of the following, factor the matrix A into a product XDX-1, where D is diagonal:
(b) A = 5 6 -2 -2 (d) A = 2 2 1 0 1 2 0 0 -1

Answers

The matrix A into a product XDX-1, where D is diagonal

(b) [[11/4, 7/4], [49/24, -1/4]]

(d) [[0, 0, 0], [0, 1, 0], [0, 0, 4]]

(b) A = [[5, 6], [-2, -2]]

Av = λv.

Rewriting the equation, we get

(A - λI) × v = 0

where I is the identity matrix.

(A - λI) = [[5 - λ, 6], [-2, -2 - λ]]

Setting the determinant of (A - λI) equal to 0, we get

det(A - λI) = (5 - λ)(-2 - λ) - (6 × -2) = λ² - 3λ - 22 = 0

Factoring the equation, we have

(λ - 5)(λ + 2) = 0

So, the eigenvalues are λ = 5 and λ = -2.

For λ = 5:

(A - 5I) = [[0, 6], [-2, -7]]

Solving the system of equations (A - 5I) × v = 0, we get v = [2, 1].

For λ = -2:

(A + 2I) = [[7, 6], [-2, 0]]

Solving the system of equations (A + 2I) × v = 0, we get v = [-2, 7].

The diagonal matrix D using the eigenvalues

D = [[λ1, 0], [0, λ2]] = [[5, 0], [0, -2]]

X = [[v1, v2]] = [[2, -2], [1, 7]]

X⁻¹ = (1 / (2 × 7 - (-2 × 1))) × [[7, 2], [-1, 2]] = [[7/24, 1/8], [-1/24, 1/8]]

Therefore, the factorization of matrix A = [[5, 6], [-2, -2]] into XDX^(-1) is:

A = XDX^(-1) = [[2, -2], [1, 7]] × [[5, 0], [0, -2]] × [[7/24, 1/8], [-1/24, 1/8]]

A =

(d) matrix A = [[2, 2, 1], [0, 1, 2], [0, 0, -1]]

Av = λv.

So, we have:

A × v = λ × v

Rewriting the equation, we get

(A - λI) × v = 0

where I is the identity matrix.

Now, let's find the eigenvalues λ

(A - λI) = [[2 - λ, 2, 1], [0, 1 - λ, 2], [0, 0, -1 - λ]]

Setting the determinant of (A - λI) equal to 0, we get

det(A - λI) = (2 - λ)(1 - λ)(-1 - λ) = λ³ - 3λ² + 2λ = 0

Factoring the equation, we have

λ(λ - 1)(λ - 2) = 0

So, the eigenvalues are λ = 0, λ = 1, and λ = 2.

Now, let's find the corresponding eigenvectors

For λ = 0

(A - 0I) = [[2, 2, 1], [0, 1, 2], [0, 0, -1]]

Solving the system of equations (A - 0I) × v = 0, we get v = [0, -2, 1].

For λ = 1

(A - I) = [[1, 2, 1], [0, 0, 2], [0, 0, -2]]

Solving the system of equations (A - I) × v = 0, we get v = [-1, 1, 0].

For λ = 2

(A - 2I) = [[0, 2, 1], [0, -1, 2], [0, 0, -3]]

Solving the system of equations (A - 2I) × v = 0, we get v = [-2, 1, 2].

The diagonal matrix D using the eigenvalues

D = [[λ1, 0, 0], [0, λ2, 0], [0, 0, λ3]] = [[0, 0, 0], [0, 1, 0], [0, 0, 2]]

The matrix X using the eigenvectors as columns

X = [[v1, v2, v3]] = [[0, -1, -2], [-2, 1, 1], [1, 0, 2]]

The inverse of matrix X

X^(-1) = (1 / (0 × (1 × 2 - 0 × 0) - (-1 × (-2) - (-2 × 0)))) × [[2, 1, 2], [2, 0, -1], [-1, -1, 0]] = [[1/2, 1/2, 1/2], [1/4, -1/4, -1/2], [-1/4, -1/4, 1/2]]

Therefore, the factorization of matrix A = [[2, 2, 1], [0, 1, 2], [0, 0, -1]] into XDX^(-1) is

A = XDX^(-1) = [[0, -1, -2], [-2, 1, 1], [1, 0, 2]] × [[0, 0, 0], [0, 1, 0], [0, 0, 2]]  ×[[1/2, 1/2, 1/2], [1/4, -1/4, -1/2], [-1/4, -1/4, 1/2]]

A = [[0, 0, 0], [0, 1, 0], [0, 0, 4]]

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as the set designer for his school's fall play, kenji is making a treasure chest shaped like a rectangular prism. the chest needs to hold approximately 6 cubic feet, or 10,368 cubic inches, of sand that will be spilled out during the first act. also, since an actor will stand on the chest in the second act, the chest needs to be 24 inches tall. kenji decides that the chest will be twice as long as it is wide. to the nearest tenth of an inch, what is the width of the chest?

Answers

The width of the chest shaped like a rectangular prism, to the nearest tenth of an inch is 32.1.

Kenji has made a treasure chest, shaped like a rectangular prism that must hold around 10,368 cubic inches of sand. In the second act of the school play, an actor will stand on the chest.

Therefore, the chest must be 24 inches tall. The length of the chest is twice its width.

To determine the width of the chest, you should first determine the length of the chest.

Then, using the formula for the volume of a rectangular prism, you can solve for the width of the chest.

Length of the chest

The formula for the volume of a rectangular prism is V = lwh

Given that the chest needs to hold around 10,368 cubic inches of sand, we can write 10,368 = lwh

Since the chest is twice as long as it is wide, the length (l) of the chest is equal to 2w.

Substituting 2w for l, we have:

10,368 = (2w)w

hence 5,184 = wh²(5,184/h)

= w*h(5,184/h²) = w

Since the chest must also be 24 inches tall, we can write:

h = 24 feet

Substituting this value into the equation, we have:

(5,184/24²) = w

hence w = 32.1 inches

Therefore, the width of the chest to the nearest tenth of an inch is 32.1 inches.

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evaluate the expression 6x + 4 9/10 when x = 2/3.

Answers

x=2/3

6(2/3) + 4 9/10 =4 + 4 9/10 = 8 9/10

Answer:

2x-1=y,2y+3=x

Step-by-step explanation:

no explanation

The product of 3 and a number is at
most 21.

Answers

Answer:

n = 7

Step-by-step explanation:

3n = 21

n = 7

factorise 6 x ^2 + 17 X + 5​

Answers

Answer:

( 3x + 1) (2x+5)

Step-by-step explanation:

6 x ^2 + 17 X + 5​

We break the 6 into 3 and 2

(3x    ) (2x   )

We need the middle term to be 17

( 3x + 1) (2x+5)

3*5+2 = 17 so it works

(3x+1)(2x+5)
So it works

What is an irregular tessellation? How many irregular tessellations are possible? How can one create an irregular polygon that tessellates?

Answers

Answer:

1. Semi-regular tessellations are made from multiple regular polygons.

2. There are an infinite number of figures that form irregular tessellations!

3. You can create irregular polygons that tessellate the plane easily, by cutting out and adding symmetrically.

An irregular tessellation

An irregular tessellation is simply a group of figures which does not include any regular polygons.

In other words, an irregular tessellation is a group of irregular shapes.

The number of irregular tessellations

There are several irregular shapes and figures that make up an irregular tessellation.

This means that the number of irregular tessellation is non-finite.

How to create an irregular tessellation

There are several ways to do this. Some of them include;

Cut out parts of a regular polygonCut out part of an irregular shapeMerge two or more irregular and regular shapes

See attachment for an instance of an irregular tessellation

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https://brainly.com/question/10628997

What is an irregular tessellation? How many irregular tessellations are possible? How can one create

Find the volume of the pyramid.

Find the volume of the pyramid.

Answers

Answer:

180 ft^3

Step-by-step explanation:

volume of the pyramid = (1/3)(area of base) (height)

v= 1/3×(10×12÷2)×(9)

= 180 ft^3

Answer:

answer on the picture.....

Find the volume of the pyramid.
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