Consider the reaction:
A (aq) <—> B (aq)
at 287 K under standard conditions. If Delta G standard is -5.17 kJ at this temperature, how much must the concentration of
"reactant A" change for the non-standard Gibb's Free energy to be -1.69 kJ? (The answer should be in M)

Answer:

0.1734

this is the answer to the question

Answer:

no.3 is your correct answer

Answer:

2 moles!

Explanation:

Hi i hope this helped! I researched it and 2 moles was what came up first.

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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22.704 grams of CO2 are produced by burning 7.49 g of C4H10

This can be calculated as :

The basic reaction is: C4H10 + O2 = CO2 + H2O

We have 4 carbons for each reactant molecule, and this reacts with oxygen to form carbon dioxide and water.  We, therefore, need to show 4 CO2 molecules to consume these 4 carbons.

Next, let's balance the H atoms.  The 10 H atoms from the C4H10 must find a home in the water molecules.  5 water molecules can be made from 10 hydrogen atoms.

The only atom left is oxygen.  So far, the product side contains 13 O atoms (8 from the CO2 and 5 from the H2O).  Awkward, since oxygen only comes in pairs, an even number.  Let's use a fraction, 6.5, for the O2 for now, just to get it balanced:

This equation is balanced, but not legal since we can't have 1/2 of an O2 molecule.  So simply multiply all coefficients by 2:

The equation is now properly balanced.  It is telling us that we'll get 8 moles of CO2 for every 2 moles of C4H10.  That's a molar ratio of 4CO2/1 C4H8.

Let's find the moles of C4H8.  Divide the grams of C4H8 by its molar mass (58.04g/mole).

Now multiply moles C4H8 by the molar ratio we calculated above:

Convert to grams CO2 by multiplying by CO2's molar mass:

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A typical aspirin tablet contains 321 mg of the active ingredient acetylsalicylic acid and 321 mg makes 0.321 g.

The nonsteroidal anti-inflammatory medicine (NSAID) aspirin, often referred to as acetylsalicylic acid (ASA), is used to treat a variety of inflammatory disorders by lowering pain, fever, and/or inflammation. These conditions include Kawasaki disease, pericarditis, and rheumatic fever.

Long-term usage of aspirin is also used to help those at high risk avoid further heart attacks, ischemic strokes, and blood clots. Effects of pain or fever often start within 30 minutes. Aspirin functions similarly to other NSAIDs but also inhibits platelet function.

Your doctor should be consulted when deciding whether or not to take aspirin because it depends on your cardiovascular risk, according to Wong. While aspirin is often taken safely by many people, it can also result in life-threatening stomach, intestinal, and brain bleeding.

1 mg = 1/1000 g

so,

321 mg = 321/ 1000g

            = 0.321g

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From the given data, the name of the hydrated salt would be  \(CoCl_2.83H_2O\).

The formula of the hydrated salt can be determined using the empirical formula approach. That is, we will find the mole equivalent of the anhydrous salt and the water of hydration and then combine them into a single formula after dividing by the smallest mole.

First, we need to determine the mass of the anhydrous salt and the water of hydration.

Mass of crucible (x) = 12.090 g

Mass of hydrated salt + crucible (y) = 16.250 g

Thus, the mass of the hydrated salt can be determined by subtracting x from y.

Mass of hydrated salt = 16.250 - 12.090 = 4.16 g

Mass of hydrate + crucible after evaporating off the water (z) = 12.424 g

Mass of anhydrous salt = z - x

                                      = 12.424 - 12.090

                                      = 0.334 g

Mass of water = 4.16 - 0.334

                        = 3.826 g

Now, let's find the moles:

Molar mass of \(CoCl_2\) = 129.839 g/mol

Molar mass of water = 18.01 g/mol

Mole of \(CoCl_2\) = 0.334/129.839 = 0.00257 mol

Mole of water = 3.826/18.01 = 0.2124 mol

Dividing through by the smallest mole

\(CoCl_2\) =  0.00257 / 0.00257  = 1

water = 0.2124/ 0.00257 = 83

Thus, the formula of the hydrate would be \(CoCl_2.83H_2O\)

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Answer:

the correct option is that C. The reaction is exothermic.

Explanation:

When the temperature decreases, and that the final temperature is lower than the initial, it indicates that less calories were perceived in the calorimeter, therefore said reaction releases heat to the external environment, thus being an exothermic reaction.

The reaction of given two liquids that have been resulted in the lowering of the temperature of the solution has been an exothermic reaction. Thus option C is correct.

There has been a decrease in the temperature of the solution after the mixing of the two solutions.

This can be described as the reaction between the two molecules that will result in the release of the energy from the system to the surroundings. The release of energy will result in the lowering of the temperature of the system.

The reaction in which the release of energy has been there is termed an exothermic reaction. Thus the reaction of given two liquids that have been resulted in the lowering of the temperature of the solution has been an exothermic reaction. Thus option C is correct.

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For this question, we have the following reaction:

Fe2O3 + 3 CO -> 2 Fe + 3 CO2

For letter D, we have:

10 grams of Fe2O3, molar mass = 159.7g/mol

6 grams of CO, molar mass = 28g/mol

In this case, we need to find which compound is the limiting and which is the excess reactant, and it is important to have in mind the molar ratio concept, which we use the coefficients in front of the compound to determine the ratios, like for Fe2O3 and CO, the molar ratio is 1:3. Now let's check if Fe2O3 is in excess, finding the number of moles first:

159.7g = 1 mol

10g = x moles

x = 0.063 moles of Fe2O3

According to the molar ratio, we need 3 times this value for CO, therefore, 0.063 * 3 = 0.189 moles of CO, now we need to check if this is the amount that we have of CO, or if we have more than that:

28g = 1 mol

6g = x moles

x = 0.214 moles of CO, this means that we have more CO than we actually need, making it the excess reactant and Fe2O3 the limiting reactant

Now to find the mass of Fe, we will be using the number of moles of the reactant, which is Fe2O3, 0.063 moles, and according to the molar ratio, we have twice this value for Fe, therefore, 0.063 * 2 = 0.126 moles of Fe, now using the molar mass of Fe, 55.84g/mol, we can find the final mass:

55.84g = 1 mol

x grams = 0.126 moles of Fe

x = 7.03 grams of Fe are produced, or if it is possible to round up, 7 grams of Fe, this is letter D

E. In this case, we need to see how much CO remains in the reaction, and since we need only 0.189 moles of CO and we actually have 0.214 moles, we have a 0.025 moles leftover, which is, in grams:

28g = 1 mol

x grams = 0.025 moles

x = 0.7 grams of CO remaining, only 5.3 grams will react

F. The percent yield is calculated having the actual yield, given in the question and the theoretical yield, which is the value we found in letter D, the formula for it is:

%yield = (actual yield/theoretical yield)*100

%yield = (6.75g/7.03g)*100

%yield = 0.964*100

The percent yield will be 96.4% for this reaction

Answer:

angle of incidence.

The calcium symbol is Ca. its atomic number is 20 and it is an alkaline earth metal. It is the fifth most abundant element on Earth.

Ca is on the second column from the left to right. It is a

An electrochemical cell can generate or use electrical energy. The mass of solid chromium that will be deposited on the electrochemical plate is 7.17 gm.

Current in an electrochemical cell is the ratio of the quantity of electricity in columns and time in seconds.

Given,

Current (I) = 0.350 A

Time = 21.7 hours

Molar mass of chromium = 52.0 g/mol

First time is converted into seconds:

1 hour = 3600 seconds

21.7 hours = 76020 seconds

The quantity of electricity flowing in the electrochemical solution is calculated as:

\(\begin{aligned} \rm Q & = \rm It\\\\& = 0.350 \times 76020 \\\\& = 26607\;\rm C \end{aligned}\)

Electricity required for depositing 1 mole or 52.0 g chromium is calculated as:

In electrochemical solution, chromium chloride is dissociated as:

\(\rm CrCl_{2} \rightarrow Cr^{2+} + 2 Cl^{-} \\\\\rm Cr^{2+} +2 e^{-} \rightarrow Cr\)

Two moles of electrons are needed to deposit 52.0 g of chromium.

If, 1 electron = 96500 C

Then, 2 electron = 193000 C

The mass of chromium deposited is calculated as:

193000 C = 52 g chromium

So, 26607 C = \(\dfrac{26607 \times 52}{193000} = 7.17 \;\rm gm\)

Therefore, 7.17 gm of chromium is produced.

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The formula for Co3+ is Co3+ because it represents the ion of cobalt that has lost three electrons, leaving it with a 3+ charge.

What is chemical formula and how they are formed ?

A chemical formula is a symbolic representation of a chemical compound that shows the types of elements present in the compound and the relative number of atoms of each element. For example, the chemical formula for water is H2O, which indicates that it is made up of two hydrogen atoms and one oxygen atom.

Chemical formulas are formed by identifying the elements that make up a compound and determining the relative number of each element in the compound. The number of each element is represented by a subscript following the chemical symbol of the element. For example, the chemical formula for methane is CH4, which indicates that there is one carbon atom and four hydrogen atoms in each molecule of methane.

The formula for Se2- is Se2- because it represents the ion of selenium that has gained two electrons, giving it a 2- charge.

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Answer: its combustion

Explanation:

Answer:

its letter b

Explanation:

it represents the spectrum of stars

The temperature of the mixture will be approximately 32°C.

To determine the final temperature of the mixture, we can use the principle of conservation of energy. The energy gained or lost by a substance can be calculated using the equation:

Q = m * c * ΔT

where:
Q = heat energy gained or lost
m = mass of the substance
c = specific heat capacity of the substance
ΔT = change in temperature

Let's calculate the heat energy gained or lost by each component separately and then equate them to find the final temperature.

For ice:
m_ice = 40 g
c_ice = 2.09 J/g°C (specific heat capacity of ice)
ΔT_ice = final temperature - 0°C (change in temperature)

Q_ice = m_ice * c_ice * ΔT_ice

For water:
m_water = 80 g
c_water = 4.18 J/g°C (specific heat capacity of water)
ΔT_water = final temperature - 40°C (change in temperature)

Q_water = m_water * c_water * ΔT_water

According to the principle of conservation of energy, the heat lost by the water will be equal to the heat gained by the ice:

Q_water = -Q_ice

Now let's substitute the respective values and solve for the final temperature:

m_water * c_water * ΔT_water = -m_ice * c_ice * ΔT_ice

80 g * 4.18 J/g°C * (final temperature - 40°C) = -40 g * 2.09 J/g°C * (final temperature - 0°C)

Simplifying the equation:

334.4 * (final temperature - 40) = -83.6 * final temperature

334.4 * final temperature - 13376 = -83.6 * final temperature

334.4 * final temperature + 83.6 * final temperature = 13376

418 * final temperature = 13376

final temperature = 13376 / 418

final temperature ≈ 32°C

Therefore, the temperature of the mixture will be approximately 32°C.

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The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer:1

Explanation: friction is showing us how in the past

Covalent and ionic bonds refer to atoms joined by their electrons. In covalent bonds, electrons are shared by the involved non-metal atoms. Option 2 is correct. Occurs due to the sharing of electrons between two non-metal atoms.

Both of them, covalent and ionic bonds, are chemical bonds that can form between atoms.

Ionic bonds occur between atoms with different electronegativity. When they bind, they transfer electrons from one atom to the other creating ions with opposite charges that attract each other.

Ionic compounds are formed by anions and cations.

• Cations are positive ions derivated from metals.

• Anions are negative ions derivated from non-metals.

The metal atoms share its electrons with the non-metal ones, creating stable configurations. Ionic bonds do not create molecules.

Covalent bonds are formed between atoms share electrons to be more stable. Atoms involved share electrons equally, creating a strong bond between them.

Covalent bonds are usually formed between non-metal atoms.

Option 2 is correct. Occurs due to the sharing of electrons between two non-metal atoms

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Complete question

A template of a Venn diagram representing common and differentiating characteristics of covalent and ionic bonds is shown.

Which of the following characteristics can be written only in space C?

On the diagram,

Options,

Answer:

0.25 of the original

Explanation:

(0.5)^(90/45)

The fraction of iron-59 after 90 days is 0.25.

Iron-59 decays following first-order kinetics. Given the half-life (\(t_{1/2}\)) of 45 days, we can calculate the rate constant (k) using the following expression.

\(k = \frac{ln2}{t_{1/2}} =\frac{ln2}{45day} = 0.015 d^{-1}\)

For first-order kinetics, we can find the fraction of Fe ([Fe]/[Fe]₀) after and an elapsed time (t) of 90 days, using the following equation.

\(\frac{[Fe]}{[Fe]_0} =e^{-k \times t } = e^{-0.015 d^{-1} \times 90 d } \approx 0,25\)

The fraction of iron-59 after 90 days is 0.25.

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There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

Explanation:

HOPE THIS HELPS!!!

Answer:

\(224 \times 13313\frac{.131?}{?244} \)

Answer:

Milk's heavy

Explanation:

Answer:

The answer should be Skeptical

The mass-balance expressions for the system are:

[NH₃]initial - [NH₃]dissociated = [NH₃]remaining

[AgBr]initial - [AgBr]initial = [AgBr]remaining

And the charge-balance expressions are:

[Ag⁺] = [NH₄⁺]

[Br⁻] = [OH⁻]

To write mass-balance and charge-balance expressions for the system formed when a 0.010 M NH3 solution is saturated with AgBr, we need to consider the dissociation reactions of NH₃ and AgBr.

The dissociation of NH₃ (ammonia) in water can be represented as follows:

NH₃ + H₂O ⇌ NH₄⁺ + OH⁻

The dissociation of AgBr (silver bromide) in water can be represented as follows:

AgBr ⇌ Ag⁺ + Br⁻

Now, let's write the mass-balance expressions:

For NH₃:

[NH₃]initial - [NH₃]dissociated = [NH₃]remaining

For AgBr:

[AgBr]initial - [AgBr]dissociated = [AgBr]remaining

Since AgBr is a sparingly soluble salt, we can assume that it dissociates completely, so [AgBr]dissociated is equal to [AgBr]initial.

Next, let's write the charge-balance expressions:

For positive ions (cations):

[Ag⁺] = [NH4⁺]

For negative ions (anions):

[Br⁻] = [OH⁻]

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As a result, the silver atomic radius in an FCC crystal lattice is roughly 1.44 angstroms.

There are 6 atoms in each unit cell of the hexagonal closest packed (HCP), which has a coordination number of 12. Four atoms make up each unit cell of the face-centered cubic (FCC), which has a coordination number of 12.

The following equation can be used to connect the silver crystal's density to its atomic radius (r) and molar mass (M):

density = (4 x M) / [(a)³ x Avogadro's number]

For FCC unit cells, the length of one edge (a) is related to the atomic radius (r) by the following equation: a = 2^(1/2) * r

Substituting this expression for a into the density equation and solving for r, we get:

r = [(3 x M) / (32 x density x pi)]^(1/3)

where pi is the mathematical constant, pi.

The molar mass of silver is approximately 107.87 g/mol.

Substituting the given values into the equation, we get:

r = [(3 x 107.87 g/mol) / (32 x 10.6 g/cm³ x pi)]^(1/3)

= 1.44 angstroms (rounded to two significant figures)

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Respuesta:

Las fuerzas intermoleculares que actúan entre las moléculas se clasifican en : Dipolos permanentes. Dipolos inducidos. Dipolos dispersos.

Explicación:

Dentro de una molécula, los átomos están unidos mediante fuerzas intramoleculares (enlaces iónicos, metálicos o covalentes, principalmente). Estas son las fuerzas que se deben vencer para que se produzca un cambio químico. Son estas fuerzas, por tanto, las que determinan las propiedades químicas de las sustancias.

Sin embargo existen otras fuerzas intermoleculares que actúan sobre distintas moléculas o iones y que hacen que éstos se atraigan o se repelan. Estas fuerzas son las que determinan las propiedades físicas de las sustancias como, por ejemplo, el estado de agregación, el punto de fusión y de ebullición, la solubilidad, la tensión superficial, la densidad, etc.

Because it is not very effective at transferring \(H^{+}\) ions to water, vinegar is a weak acid. Less than 0.4% of the \(CH_{3}CO_{2}H\)molecules in a 1 M solution interact with water to create \(H_{3}O^{+}\)and \(CH_{3}CO_{2}^{-}\) ions. More than 99.6% of the acetic acid molecules are still whole.

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