Convert 9.85 x 10^3 kg to cg ​

Answer:

6.76 mol/L

Explanation:

A chemist prepares a solution 0.607 kg of calcium bromide by measuring out of calcium bromide into a 450. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Step 2: Calculate the moles of solute

The molar mass of calcium bromide is 199.89 g/mol.

607 g × 1 mol/199.89 g = 3.04 mol

Step 3: Convert "V" to liters

We will use the conversion factor 1 L = 1000 mL.

450. mL × 1 L/1000 mL = 0.450 L

Step 4: Calculate the concentration of calcium bromide in mol/L

[CaBr₂] = 3.04 mol/0.450 L = 6.76 mol/L

The mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur .

The molecular formula of Aluminum Sulfate is \(Al_2(SO_4)_3.\) In one molecule of aluminum sulfate, there are 3 sulfur atoms. To calculate the mass of aluminum sulfate, follow the steps below:

Step 1: Calculate the molar mass of aluminum sulfate using the periodic table.Al = 27.0 g/molS = 32.1 g/molO = 16.0 g/mol

(2 × Al) + (3 × S) + (12 × O) = molar mass of \(Al_2(SO_4)_3.\) = 342.2 g/mol

Step 2: Find the number of moles of sulfur in the given number of atoms of sulfur.2\(2.837*10^{26\) atoms of sulfur × 1 mol S/\(6.022 * 10^{23\)atoms S = 0.0470 mol S

Step 3: Use the molar ratio of sulfur to aluminum sulfate to calculate the number of moles of aluminum sulfate.1 mol \(Al_2(SO_4)_3.\) / 3 mol S = 0.333 mol\(Al_2(SO_4)_3.\) per mol S0.0470 mol S × 0.333 mol \(Al_2(SO_4)_3.\)/mol S = 0.0157 mol \(Al_2(SO_4)_3.\)

Step 4: Calculate the mass of aluminum sulfate.0.0157 mol \(Al_2(SO_4)_3.\) × 342.2 g/mol\(Al_2(SO_4)_3.\)= 5.373 g\(Al_2(SO_4)_3.\)

Therefore, the mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur.

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The sample response is : how do mass and the type of material affect thermal energy transfer?

So one need to have include the below factors in your answer:

The mass of an object influences allure thermal strength transfer traits. Generally, objects accompanying best public have greater warm strength depository volume.

They can absorb more heat strength before experience a meaningful change in hotness. If an equal amount of heat is used to both objects, the object accompanying better mass will demand more heat strength to raise allure temperature distinguished to the object accompanying tinier mass .

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. In this experiment, you need to examine the idea of the thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, be limit your question to only two. What did you include in your question?

The denstiy of the gold bar of mass 3300 g is 18.3 g/cm³.

Density is the ratio of mass and volume.

To calculate the density of the bar gold, we use the formula below.

Formula:

Where:

From the question,

Given:

Susbtitute these values into equation 1

The bar is not a pure gold.

Hence, the denstiy is 18.3 g/cm³.

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Answer:

b

Explanation:

Answer:

b

Explanation:

Answer:

There will be no observed impact of adding twice as much Na2CO3 on the product

Explanation:

Stoichiometry gives the relationship between reactants and products in terms of mass, mole and volume.

If we consider the stoichiometry of the reaction, we will discover that the reaction occurs in a 1:1 ratio. This implies that use of twice the amount of Na2CO3 will only lead to an excess of Na2CO3 making the other reactant the limiting reactant. Once the other reactant is used up, the reaction quenches.

Hence, use of twice as much Na2CO3 has no impact on the quantity of product produced.

Answer:

Percent yield  = 72.07 %

Explanation:

Our reaction is:

C₄H₁₀O + NaBr + H₂SO₄ → C₄H₉Br + NaHSO₄ + H₂O

It is correctly balanced.

Let's determine which is the limiting reagent:

45 g . 1 mol / 74 g = 0.608 moles of C₄H₁₀O

67.1 g . 1 mol / 102.9 g = 0.652 moles of NaBr

97 g . 1 mol / 98 g = 0.990 moles of sulfuric acid

Ratio is always 1:1, so for 1 mol of NaBr and 1 mol of sulfuric acid we need 1 mol of C₄H₁₀O. We have 0.652 moles of NaBr, we need the same amount of C₄H₁₀O and we have 0.990 moles of acid, we need the same amount of C₄H₁₀O; we only have 0.608 moles, that's why C₄H₁₀O is the limiting reactant, there's no enough C₄H₁₀O.

Ratio is also 1:1, between reactant and product.

1 mol of C₄H₁₀O produces 1 mol of C₄H₉Br

Then, 0.608 moles will produce 0.608 moles of C₄H₉Br

We convert moles to mass: 0.608 mol . 136.9 g/mol = 83.25 g

That's the 100 % yield reaction

Percent yield  = (Yield produced / Theoretical yield) . 100

Percent yield = (60 g / 83.25 g) . 100 = 72.07 %

Answer:

b) warm

Explanation:

A warm weather front forms when a warm air mass pushes into a cooler air mass. Therefore, the answer is b) warm.

I'm sorry to bother you but can you please mark me BRAINLEIST if this ans is helpfull

Answer: b

Explanation:

Answer:

The correct order for the stages of melting candle wax is:

Explanation:

Grams are the unit of measurement of the mass or the weight of the substance. There are 1.17 gms of chlorine atoms in the sample.

The mass of the substance is the multiplication of the moles and the molar mass.

Barium chloride dissociates as:

BaCl₂ ⇄  Ba²⁺ + 2 Cl⁻

From the reaction, it can be said that 1 mole of barium chloride dissociates into 1-mole barium ion and 2 moles of chloride ions.

Moles of barium chloride are calculated as:

Moles = mass ÷ molar mass

= 3.45 gm ÷ 208.23 g/mol

= 0.016 moles

If 1 mole of Barium chloride has 2 moles then 0.016 moles of the sample will have, 0.0331 moles of chloride ions.

The mass of chlorine atoms is calculated as:

Mass = moles × molar mass

= 0.0331 × 35.45

= 1.17 gms

Therefore, 1.17 gms of chlorine atoms are present in barium chloride.

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Answer: 184 g of nitrogen dioxide that are produced from 4 moles of nitric oxide

Explanation:

The balanced chemical reaction is:

\(2NO(g)+O_2(g)\rightarrow 2NO_2(g)\)  

According to stoichiometry :

2 moles of \(NO\) produce = 2 moles of \(NO_2\)

Thus 4 moles of \(NO\) will require=\(\frac{2}{2}\times 4=4moles\)  of \(NO_2\)

Mass of \(NO_2=moles\times {\text {Molar mass}}=4moles\times 46g/mol=184g\)

Thus 184 g of nitrogen dioxide that are produced from 4 moles of nitric oxide

Answer:

lungs

Explanation:

Dios mío, vaya, eso es una locura, no lo sabía, pero gracias por la información. :)

Explanation:

The frequency of a wave is the number of times per second that the wave cycles. Frequency is measured in Hertz or cycles per second. The frequency is often represented by the lower case "f." The period of the wave is the time between wave crest

Answer:its b

Explanation:

jusut bcss

Answer:

Water acts as a solvent of carbon dioxide excreted from tissues, in blood and helps in regulating pH (because it forms carbonic acid that lowers pH when it tends to get higher). Blood pH should be maintained at about 7.4. One major reason is that the structure of protein is dependent ton pH because pH determines its ionization hence also affecting the charges and interaction between side groups of amino acids. A change in pH may, therefore, denature proteins and negatively affect cellular functions.

Explanation:

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Answer:

Calculate the frequency of light having wavelength of 456 nm.

1.22*10^8nm

Explanation:

In the given question, \(6.58 \times 10^{14}\) Hz is the frequency of the light with a wavelength of 456 nm.

Frequency is a measure of the number of cycles of a periodic wave that occur per unit of time.

The frequency of light can be calculated using the following equation:

frequency = speed of light / wavelength

where the speed of light is a constant equal to \(\rm 3 \times 10^8 \ m/s\).

To use this equation, we need to convert the wavelength from nanometers to meters:

456 nm = \(\rm 456 \times 10^{-9}\ m\)

Now, we can substitute the values into the equation:

frequency =  \(\rm 3 \times 10^8 \ m/s\) / \(\rm 456 \times 10^{-9}\ m\)

=  \(6.58 \times 10^{14}\) Hz

Therefore, the frequency of light with a wavelength of 456 nm is  \(6.58 \times 10^{14}\) Hz.

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The volume in milliliters is 7357.8 mL.

The term conversion factor refers to the factor that could be used to express the measurement in one unit conveniently in a different unit. This is very important to ensure that the meaning of the measurement can easily be grasped and adapted to different settings.

Now we have the volume of the ball as 449 cubic inches and we know that;

1 cubic inch = 16.3871 milliliter

449 cubic inches =  449 cubic inches * 16.3871 milliliter /1 cubic inch

= 7357.8 mL

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Answer:

A

Explanation:

The equilibrium constant Kp for this reaction is 1.03×10^(-5) atm.

What is equilibrium constant?

The equilibrium constant, represented by K, is a quantitative measurement of the extent to which a chemical reaction has reached equilibrium. It describes the ratio of the concentrations (or partial pressures) of the products and reactants at equilibrium, with each concentration raised to a power equal to its coefficient in the balanced chemical equation.

We can use the relationship between Kp and Kc to solve this problem:

Kp = Kc(RT)^(Δn)

where R is the gas constant, T is the temperature in Kelvin, and Δn is the change in the number of moles of gas between the products and the reactants.

First, let's find Δn:

Δn = (moles of gas in products) - (moles of gas in reactants)

Δn = (2 moles) - (3 moles)

Δn = -1

Next, we can plug in the values and solve:

Kp = Kc(RT)^(-1)

Kp = (2.1)((0.0821 L·atm/mol·K)(295 K))^(-1)

Kp = 1.03×10^(-5) atm

Therefore, the equilibrium constant Kp for this reaction is 1.03×10^(-5) atm.

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Answer:

a, c, d

Explanation:

biosphere atmosphere hydrosphere lithosphere

Answer:

all animals live on land

Explanation:

Answer:

H2O

Explanation:

There is more than one element

Answer:

There are  \(\mathbf{8.90172 \times 10^{-14}}\) moles of bactoX present in a 3.0 μL sample volume that contains 7.512×106 bacterial cells

Explanation:

Given that:

The number of molecules present in one bacterial cell is \(7.140 \times 10^3\) molecules

and the sample  contains \(7.512 \times 10^6\) molecules.

Number of moles = number of molecules /Avogadro's number

where;

Avogadro's number = 6.023 × 10²³

Number of moles = \(\dfrac{7.140 \times 10^3}{6.023 \times 10^{23}}\)

Number of moles = \(1.185 \times 10^{-20}\) moles

So;  \(1.185 \times 10^{-20}\) moles  is present in one bacteria cell

Similarly;  the sample  contains \(7.512 \times 10^6\) molecules.

Therefore; the number of moles present in the bactoX is = \(1.185 \times 10^{-20} \times 7.512 \times 10^6\)

= \(\mathbf{8.90172 \times 10^{-14}}\) moles

i think its 2.0

Why do i think this-If you add 0.73g to 1.3g it comes to 2.0g

Answer:

1) Oxidation-Reduction (Redox) Reaction

2) Combustion Reaction

3) Decomposition Reaction

4) Synthesis Reaction

5) Single Displacement (Substitution) Reaction

6) Double Displacement (Metathesis) Reaction

7) Acid-Base Neutralization Reaction

8) Precipitation Reaction

Here are the Answer:

1. Oxidation-Reduction (Redox) Reaction

2. Combustion Reaction

3. Decomposition Reaction

4. Synthesis Reaction

5. Single Displacement (Substitution) Reaction

6. Double Displacement (Metathesis) Reaction

7. Acid-Base Neutralization Reaction

8. Precipitation Reaction

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The mass of sodium chloride produced by the chemical reaction between sodium bicarbonate and hydrochloric acid is 8.37g.

The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl):

NaHCO₃ + HCl → NaCl + H₂O + CO₂

1 mole of sodium bicarbonate (NaHCO3) reacts with 1 mole of hydrochloric acid (HCl) to produce 1 mole of sodium chloride (NaCl), 1 mole of water (H₂O), and 1 mole of carbon dioxide (CO₂).

NaCl: Molar mass = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

The number of moles of sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl) using their respective masses:

Number of moles of NaHCO₃ = Mass of NaHCO₃ / Molar mass of NaHCO₃

Number of moles of NaHCO₃ = 12 g / (22.99 g/mol + 1.01 g/mol + 48.00 g/mol + 16.00 g/mol)

Number of moles of NaHCO₃ = 12 g / 84.00 g/mol ≈ 0.143 moles

Number of moles of HCl = Mass of HCl / Molar mass of HCl

Number of moles of HCl = 5.58 g / (1.01 g/mol + 35.45 g/mol)

Number of moles of HCl = 5.58 g / 36.46 g/mol ≈ 0.153 moles

Since the reaction stoichiometry is 1:1 between NaHCO₃ and NaCl, the number of moles of NaCl produced will be the same as the number of moles of NaHCO₃ reacted. Therefore, the mass of NaCl produced can be calculated as follows:

Mass of NaCl produced = Number of moles of NaCl × Molar mass of NaCl

Mass of NaCl produced = 0.143 moles × 58.44 g/mol

The Mass of NaCl produced ≈ 8.37 g

Hence, the mass of sodium chloride produced is approximately 8.37 grams.

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