Step-by-step explanation:
divide 1 by seven in long division it will be 0.142857 then it repeat it self ...so to the nearest thousand is 0.143
Answer:
Step-by-step explanation:
a graphical tool used to help determine whether a process is in control or out of control is a
A graphical tool used to help determine whether a process is in control or out of control is known as a Control Chart.
Control charts are essential in quality control and statistical process control (SPC). They allow you to monitor process performance and variability over time, enabling you to identify trends, shifts, or deviations from the established process baseline.
Control charts typically consist of a centerline, representing the process mean, and upper and lower control limits, which indicate the acceptable range of variation. Data points are plotted on the chart, and if they fall within the control limits, the process is considered to be in control. If data points fall outside the control limits or display non-random patterns, the process is considered out of control, signaling potential issues that need to be investigated and addressed.
In summary, control charts are a valuable graphical tool that assists in determining the stability of a process, facilitating continuous improvement efforts and ensuring product quality. They provide a visual representation of process variation and help identify when corrective actions are needed to bring a process back into control.
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Find the distance between 7 and -4
11 is the distance between given two numbers.
To find the distance between 7 and -4,
we need to find the absolute value of the difference between them:
|7 - (-4)| = |7 + 4| = |11| = 11
Therefore, the distance between 7 and -4 is 11.
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The figure is cut into 8 equal pieces. Shade 1/2 of the figure.
What is the approximate area of a circle with a diameter of 10 in?
A. 314 in2
B. 78.5 in2
C. 31.4 in2
D. 15.7 in2
Answer:
Hello! answer: 78.5 in2
Step-by-step explanation:
IMPORTANT ATTENTION: Im using 3.14 for pi so answers might vary if you are using say 22/7 for pi so please know that since this problem doesn't tell to use a certain method I will use 3.14
area can be found by doing radius × radius × 3.14 so... diameter is just twice the radius so... 10 ÷ 2 = 5 5 × 5 = 25
25 × 3.14 = 78.5 therefore 78.5 is the answer HOPE THAT HELPS!
The approximate area of a circle with a diameter of 10 in is,
⇒ Area of circle = 78.5 in²
Given that;
Diameter of circle = 10 in.
Now, We know that;
⇒ Area of circle = πr²
Where, 'r' is radius of circle.
Here, Diameter of circle = 10 in.
Hence, Radius = 10 / 2 = 5 in
Thus, We get;
⇒ Area of circle = πr²
⇒ Area of circle = 3.14 x (5)²
⇒ Area of circle = 78.5 in²
Thus, The approximate area of a circle with a diameter of 10 in is,
⇒ Area of circle = 78.5 in²
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write an equation of the parabola in vertex form calculator
A parabola's vertex form equation is as follows:
y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.
To use a calculator to find the equation of a parabola in vertex form, you would typically need to know the coordinates of the vertex and at least one other point on the parabola.
Determine the vertex coordinates (h, k) of the parabola.
Identify at least one other point on the parabola (x, y).
Substitute the values of the vertex and the additional point into the equation y = a(x - h)^2 + k.
Solve the resulting equation for the value of 'a'.
Once you have the value of 'a', substitute it back into the equation to obtain the final equation of the parabola in vertex form.
Note: If you provide specific values for the vertex and an additional point, I can assist you in calculating the equation of the parabola in vertex form.
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What are the domain and range of the function represented by the set of ordered pairs? {(–3, 2), (–2, 1), (–1, 0), (0, –1)} 
Fewer young people are driving. In 1995, 63.9% of people under 20 years old who were eligible had a driver's license. Bloomberg reported that percentage had dropped to 41.7% in 2016. Suppose these results are based on a random sample of 1,200 people under 20 years old who were eligible to have a driver's license in 1995 and again im 2016.
The proportion of young people with driver's licenses in 2016 is significantly lower than in 1995.
We can use a hypothesis test to determine if the decrease in the percentage of young people with driver's licenses is statistically significant. The null hypothesis would be that the proportion of young people with driver's licenses is the same in 1995 and 2016, while the alternative hypothesis would be that the proportion of young people with driver's licenses in 2016 is lower than in 1995.
Let p1 be the proportion of young people with driver's licenses in 1995, and p2 be the proportion of young people with driver's licenses in 2016. Our null hypothesis is:
H0: p1 = p2
The alternative hypothesis is:
Ha: p2 < p1
We can use a two-sample proportion z-test to test this hypothesis. The test statistic is:
\(z = (p1 - p2) / \sqrt{(P(1 - P)} * (1/n1 + 1/n2))\)
where P is the pooled proportion of young people with driver's licenses, and n1 and n2 are the sample sizes for 1995 and 2016, respectively.
Using the given sample sizes of 1,200 and the given proportions of 0.639 and 0.417, we can calculate the pooled proportion:
\(P = (p1 * n1 + p2 * n2) / (n1 + n2) = (0.639 * 1200 + 0.417 * 1200) / (1200 + 1200) = 0.528\)
Plugging in the values, we get:
\(z = (0.639 - 0.417) / \sqrt{(0.528(1-0.528) * (1/1200 + 1/1200))} = 13.38\)
Using a standard normal distribution table, we find that the probability of getting a z-score of 13.38 or higher is essentially zero (less than 0.0001). Therefore, we can reject the null hypothesis and conclude that the proportion of young people with driver's licenses in 2016 is significantly lower than in 1995.
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if a and b are directly proportional and b and c are directly proprtional, then how are a and c related
a and c are directly proportional to each other when a and b are directly proportional and b and c are directly proportional.
If a and b are directly proportional and b and c are directly proportional, it means that their ratios are equal. Direct proportionality implies that as one variable increases, the other also increases in proportion and as one variable decreases, the other also decreases in proportion.
Mathematically, this can be written as
a = kb and b = mc, where k and m are constants of proportionality.
Multiplying these two equations gives: a = kbm
Substituting the value of b from the second equation in the first equation, we get: a = kmc
Therefore, a and c are also directly proportional to each other with a constant of proportionality km.
Thus, if a increases by a certain factor, c will also increase by the same factor.
If a and b are directly proportional and b and c are directly proportional, then it can be concluded that a and c are directly proportional as well.
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Which of the following sequences is an arithmetic sequence? Why?
1. 3, 7, 11, 15, 19
2. 4, 16, 64, 256
3. 48, 24, 12, 6, 3, ...
4. 1, 4, 9, 16, 25, 36
5. 1, 1/2, 0, -1/2
6. -2, 4, -8, 16, ...
7. 1, 0, -1, -2, -3
8. 1/2, 1/3, 1/4, 1/5, ...
9. 3x, x, x/3, x/9, ...
10. 9.5, 7.5, 5.5, 3.5, ..
Answer: sequences 1,5,7,9,10
Step-by-step explanation:
An arithmetic sequence is defined by a sequence of numbers with a common difference between terms. Technically if x=0 in q9 we have a constant sequence, which by definition is arithmetic. However if x does not equal 0 it is not arithmetic.
express (1)/(2\sqrt(2)) as a power of 2
\(( \frac{1}{2 \div \sqrt{2} }) {}^{2} \\t aking \: square \: we \: get \\ \frac{ {1}^{2} }{2 {}^{2} \div ( { \sqrt{2} })^{2} } \\ = \frac{1}{4 \div 2} = \frac{1}{2} \)
The Wonder Wings Insect Museum sells bug-shaped notebooks in their gift shop. Last month, they sold 35 butterfly notebooks and 55 ladybug notebooks. The notebooks were so popular that they want to order more this month. They plan to order 110 ladybug notebooks. If they keep the same ratio, how many butterfly notebooks should they order this month?
Answer:
70
Step-by-step explanation:
35/55= 70/110
55 was mulitiplied 2 to get 110 so I mulitply the 35 by two to 70
what is 18/5 as a terminating decimal (use long division)
Answer:
3.6
Step-by-step explanation:
sorry for the weird looking numbers, I used my mouse to write this
What i the um of the fraction? Ue the number 18 equivalent fraction to help find the anwer -3/41/2
fractions with the same denominator added together
You must add the numerators and keep the same denominator when adding fractions with the same denominator. Since the denominators of the two fractions are the same, we must add the numerators while maintaining the same denominator, which is 4.
What are the parts of fraction?
A fraction consists of two components. The numerator is the figure at the top of the line. It details the number of equal portions that were taken from the total or collection. The denominator is the figure that appears below the line.
The number below the bar is called the denominator . It tells the number of equal parts into which the whole has been divided. The number above the bar is called the numerator. It tells how many of the equal parts are being considered.
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How can we ensure that we choose a sample of students that is representative of all 8:00 am classes that take place on a given morning?
By using a sampling technique we ensure that we choose a sample of students that is representative of all 8:00 am classes.
There are varieties of sampling strategies: chance sampling includes random selection, permitting you to make sturdy statistical inferences approximately the complete organization. Non-opportunity sampling entails non-random selection primarily based on convenience or different standards, permitting you to without problems gather records.
Random sampling is part of the sampling technique wherein every sample has an same possibility of being chosen. A sample chosen randomly is meant to be an unbiased representation of the overall population.
explanation;
we conclude the
6 buildings in the college 4 lecture halls in each building100 students in each lecture hallSince the students' lecture hallsare on different building the samples are
Dividing the students into groups, the students will be grouped by the buildings of their lecture halls.
The number of students in each building is:
There are 100 students in each building
Then select at random an equal proportion of student from each building let 20 students in each building.
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Water sloshes back and forth in a tank as shown in figure below. The frequency of sloshing, omega, is assumed to be a function of the acceleration of gravity g, the average depth of the water, h, and the length of the tank t. Develop a suitable set of dimensionless parameters for this problem using g and l as repeating variables.
The dimensionless parameters for this problem can be expressed using the repeating variables of g and l.
To develop dimensionless parameters, we need to identify the relevant variables and express them in terms of the repeating variables (g and l). In this case, the variables of interest are the frequency of sloshing (ω), the average depth of the water (h), and the length of the tank (t).
Determine the dimensions of the repeating variables:
- g represents acceleration due to gravity, which has dimensions of length/time².
- l represents length, which has dimensions of length.
Express the variables of interest in terms of g and l:
- ω is the frequency of sloshing. It can be expressed in terms of g and l as ω = f(g,l), where f is some function.
- h is the average depth of the water. It has dimensions of length.
- t is the length of the tank. It also has dimensions of length.
Define the dimensionless parameters:
- Let's define a dimensionless parameter α that represents the ratio of the frequency of sloshing to the square root of the acceleration due to gravity. We can express it as α = ω/√g.
- Similarly, let's define a dimensionless parameter β that represents the ratio of the average depth of the water to the length of the tank. We can express it as β = h/t.
Verify the dimensionless parameters:
- α has no dimensions since it is a ratio of frequencies. It is a dimensionless parameter.
- β is also dimensionless since it is a ratio of lengths.
Therefore, the suitable set of dimensionless parameters for this problem using g and l as repeating variables are α and β.
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The slope is 4 one point on the line is (-2,7). What is the y intercept
Answer:
y-intercept: (0, 15).
Step-by-step explanation:
y-y1=m(x-x1)
y-7=4(x-(-2))
y-7=4(x+2)
y=4x+8+7
y=4x+15 where m=slope and b=y-intercept.
y=mx+b
how many bit strings of length seven either begin with two 0s or end with three 1s?
There are 40 such bit strings.
To count the number of bit strings of length seven that either begin with two 0s or end with three 1s, we need to use the principle of inclusion-exclusion.
Let A be the set of bit strings that begin with two 0s, and let B be the set of bit strings that end with three 1s.
Then, we want to find the size of the set A ∪ B, which consists of bit strings that satisfy either condition.
The size of A can be calculated as follows:
since the first two digits must be 0, the remaining five digits can be any combination of 0s and 1s,
so there are \(2^5 = 32\) possible strings that begin with two 0s.
Similarly, the size of B can be calculated as follows:
since the last three digits must be 1, the first four digits can be any combination of 0s and 1s,
so there are\(2^4 = 16\) possible strings that end with three 1s.
However, we have counted the strings that both begin with two 0s and end with three 1s twice.
To correct for this, we need to subtract the number of strings that belong to both A and B from the total count.
The strings that belong to both A and B must begin with two 0s and end with three 1s, so they have the form 00111xxx,
where the x's can be any combination of 0s and 1s.
There are \(2^3 = 8\) such strings.
Therefore, the total number of bit strings of length seven that either begin with two 0s or end with three 1s is:
|A ∪ B| = |A| + |B| - |A ∩ B| = 32 + 16 - 8 = 40.
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Please somebody help me
Answer:
g = \(\frac{4}{3}\)
Step-by-step explanation:
4 - \(\frac{1}{12}\) g - 2 = \(\frac{3}{2}\) g + 1 - \(\frac{5}{6}\) g
multiply through by 12 ( the LCM of 12, 2 and 6 ) to clear the fractions
48 - g - 24 = 18g + 12 - 10g
- g + 24 = 8g + 12 ( subtract 8g from both sides )
- 9g + 24 = 12 ( subtract 24 from both sides )
- 9g = - 12 ( divide both sides by - 9 )
g = \(\frac{-12}{-9}\) = \(\frac{12}{9}\) = \(\frac{4}{3}\)
Help me !!??!!!????please
a circular pool is surrounded by a brick walkway 3 m wide. find the ra- dius of the pool if the area of the walk- way is 198 m*.
The radius of the pool is 9.01 m.
Given,
In the question:
A circular pool is surrounded by a brick walkway 3 m wide.
The area of the walk- way is 198 m^2.
To find the Radius of the pool.
Now, According to the question:
"Area of the circle bounded by the outside edge of the walkway" minus "area of the pool" = "area of the walkway".
Let R = Radius of the pool
Area of the circle bounded by the outside edge of the walkway is:
\(\pi\)(R +3)^2
Area of the pool is:
\(\pi R^2\)
Now, Our equation is:;
\(\pi\)(R +3)^2 - \(\pi R^2\) = 198
\(\pi\)((R+3)^2 - \(R^2\)) = 198
Open the inner bracket :
\(\pi\)(\(R^2+6R+9-R^2\)) = 198
\(\pi\)(6R +9) = 198
6R+9 = 198/\(\pi\)
6R = 198/\(\pi\) - 9
R = (198/\(\pi\) - 9)/6
R = (198/(3.14) - 9)/6
R = (63.057 - 9)/6
R = 54.057/6
R = 9.01 meters
Hence, The radius of the pool is 9.01 m.
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an $m \times n \times p$ rectangular box has half the volume of an $(m 2) \times (n 2) \times (p 2)$ rectangular box, where $m, n$, and $p$ are integers, and $m \le n \le p$. what is the largest possible value of $p$?
The largest possible value of p can be determined by analysing the ratio of the volumes of the two rectangular boxes.
The volume of the first box is V1 = m*p*n and the volume of the second box is \($V2 = (m2)\cdot (n2)\cdot (p2)$\). Therefore, we can set up the following equation to solve for p:
\($\frac{V1}{V2} = \frac{mnp}{(m2)(n2)(p2)} = \frac{1}{2}$\)
Solving for p gives us the following:
\($p = \sqrt[3]{\frac{2(m2)(n2)}{mn}}$\)
Since m, n, and p must all be integers, the largest possible value of p is the largest integer such that
\($p \le \sqrt[3]{\frac{2(m2)(n2)}{mn}}$.\)
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10x-2=3x-12 NoFraction
Answer:−1.429
I need brainliest
Step-by-step explanation:
I need help on this please
Answer:
-22
Step-by-step explanation:
each mark decreases by three, two marks down from 16 would be 16+3+3; which equals 22, and it has to be negative
hope this helped!
pls help, it is due now. Thank You so much to whoever helps!
Answer:
(7, -1)
Step-by-step explanation:
3x + 7y = 14
y = x - 8
3x + 7(x - 8) = 14
3x + 7x - 56 = 14
10x - 56 = 14
Add 56 to both sides.
10x = 70
Divide both sides by 10.
x = 7
3(7) + 7y = 14
21 + 7y = 14
Subtract 21 from both sides.
7y = -7
Divide both sides by 7.
y = -1
(7, -1)
PLEASE HELP FAST! problem is attached as a picture!
Answer: (4 , 5.5)
Step-by-step explanation: it is 1:3 on the line AB
esto es verdadero oh falso
como se resuelve
3/4 + 1/2 + 1/3 + 2/9 + ...... = 9/4
Answer
The missing value is 4/9
what is the radius of a circle with the ratio 1:4 when the smaller one is 12cm
Answer:
48
Step-by-step explanation:
1 to 4 = 12 to ?
multiply the small one by 4 to get the bigger one
Step-by-step explanation:
1:4
12:x
1=4
12=x
cross multiply
x=4×12
x=48
i’m honestly very confused on how to figure this out
Answer:
y = -1/2 = -0.500
Step-by-step explanation:
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b/11-6b/11=10/11 solve for b asap
I hope this helps you
b-6b/11=10/11
-5b=10 (divide -5 both of sides)
b=-2
PLZ HELP PLZ (1a) Use long division to show the fraction and decimal in each pair are equivalent? 3/4 & 0.75. Hint: Divide 3/4.
Answer:
3 divided by 4 will equal 0.75 which is equivalent to 0.75. or you can do 6/8 which will also equal 0.75. and 6/8 is equivalent to 3/4. so therefore it's confirmed that 3/4 is equivalent to 0.75