Correctly label the following parts of the small intestine. Mesentery Jejunum Cecum Appendix Duodenum Duodenal flexure leum lleocecal junction leum Reset Zoom
Answers
Duodenum, duodenal flexure, mesentery, ileocecal junction, Ileum, jejunum.
A section of the small intestine. It is linked to the stomach. Food that has just left the stomach is further digested in the duodenum. It absorbs water and nutrients from meals so that the body can use the vitamins, minerals, carbs, fats, and proteins. The big intestine receives food that has been broken down in the small intestine (also called the large bowel or colon). The large intestine, which is approximately five feet long, removes the majority of the water from the meal and gives it to the body. The remainder travels via the colon and is expelled from the body as feces (stool).
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Related Questions
How much ibs does ur backpack weigh?
Answers
Answer:
12 pounds mine does
Explanation:
Answer: 10 pnds
Explanation:
A pebble and a bowling ball would have zero weight in gravity-free space. If they were moving toward you with the same speed, would they have the same effect if they collided with your head? Explain your answer. PLEASE HELP
Answers
A massive and fast moving bowling ball must have a large momentum while a light and slow moving tennis ball must have a small momentum. However, a fast tennis ball may have the same momentum as a slow rolling bowling ball due to its high velocity. Given two objects of the same size but of different materials, the heavier (denser) object will fall faster because the drag and buoyancy forces will be the same for both, but the gravitational force will be greater for the heavier object.
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Our mission to Mars have allowed us to observe the skies from the surface of another planet. From a martian point of view, what do you predict we would see in this geocentric solar system, but not in our heliocentric model?
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From a Martian point of view, the most notable difference between observing the solar system in a geocentric model versus a heliocentric model would be the relative positions of the planets in the sky. In a geocentric model, the Earth is at the center of the solar system and all the other planets orbit around it. In contrast, in a heliocentric model, the sun is at the center of the solar system and all the planets, including Earth, orbit around it.
If we were observing the solar system from the surface of Mars, we would see the planets from Mars' point of view. In this scenario, the planets would appear to move in the sky in ways that are different from what we observe from Earth. For example, Mars and Earth would appear to be orbiting around the sun at different rates, and thus their relative positions to each other would change over time, but the relative positions of the other planets to the Earth would not change as much as in our heliocentric model.
Additionally, the apparent size and brightness of the planets would also appear different from Mars than they do from Earth. This is due to the fact that the distance between Mars and the other planets is not the same as the distance between Earth and the other planets.
In summary, from a Martian point of view, the relative positions of the planets in the solar system would appear different than what we observe from Earth due to the geocentric model of the solar system and the difference in the distance between Mars and the other planets.
Sitting at the top of a steep hill on a roller coaster (not moving), is an example of:
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Which energy is stored in water present at height? how this store energy can be utilized to generate electricity?
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Answer:
a energía hidráulica o energía hídrica se obtiene del aprovechamiento de las energías cinética y potencial de la corriente del agua o los saltos de agua naturales. En el proceso, la energía potencial, durante la caída del agua, se convierte en cinética y mueve una turbina para aprovechar esa energía.
Explanation:
Explanation:
potential energy
Because of kinetic energy water can flow and waves can exist. But water can also contain potential energy. This is energy that is stored in the water.
how do atomic structures apply to the formation of stars?
Answers
Answer:
Stars create new elements in their cores by squeezing elements together in a process called nuclear fusion. First, stars fuse hydrogen atoms into helium. Helium atoms then fuse to create beryllium, and so on, until fusion in the star's core has created every element up to iron.
Explanation:
Hope this helps.
Answer:
hahahahahaha hahahahaha hahah
how can the conductivity of a semiconductor be increased?
Answers
Three reasons why the use of electronic media has become increasingly important in a democratic society
Answers
The use of electronic media has become increasingly important in a democratic society due to its ability to facilitate communication, disseminate information, foster collective action, and promote transparency and accountability.
Firstly, electronic media has made communication faster, easier and more efficient than ever before. With the rise of social media platforms, individuals are able to share their opinions and perspectives with a wider audience in real-time. This has allowed for greater participation and engagement in political discourse, and has encouraged citizens to become more informed and active in democratic processes.
Secondly, electronic media has facilitated the dissemination of information and news, allowing citizens to stay up-to-date with the latest developments in politics and government. This has helped to increase transparency and accountability, and has enabled citizens to hold their elected officials and government institutions to a higher standard of scrutiny.
Finally, electronic media has played a significant role in mobilizing citizens and fostering collective action. Through social media campaigns and online activism, individuals are able to organize and coordinate their efforts, making it easier to bring about change and hold those in power accountable. This has been particularly important in recent years, as we have seen numerous social and political movements emerge that have brought about significant change and progress.
In summary, the use of electronic media has become increasingly important in a democratic society due to its ability to facilitate communication, disseminate information, foster collective action, and promote transparency and accountability.
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Rahul wants to change the motion map shown so that it shows uniform circular motion. An illustration of a circle with four black dots on the top, bottom, left and right of the circle. Each dot has a vector toward the center of the circle of equal length and a vector tangent to the circle in a counterclockwise direction and of increasing length staring from the one on the right. What change should Rahul make? He should change the length of each vector that points toward the center so that it is the same length as the vector pointing tangent to the circle at that point. He should change the lengths of the vectors that point tangent to the circle so that each is the same length. He should change the direction of the vectors that are tangent to the circle so that each points away from the center of the circle. He should change the direction of the vectors that are tangent to the circle so that each points toward the center of the circle.
Answers
Rahul should change the lengths of the vectors that point tangent to the circle so that each is the same length.
Uniform Circular Motion:
A uniform circular motion is a motion in a circle where the tangential speed of the object is constant.
In the motion map:
The arrows pointing towards the center of the circle represent the centripetal acceleration, and their length represents the magnitude of the acceleration.The arrows pointing tangentially to the circle represent the tangential speed, and their length represents the magnitude of the speed.In this motion map, the length of the vectors pointing tangent to the circle is not constant: this means that the speed is not constant. In order to have a uniform circular motion, the speed must be constant, therefore the lengths of the vectors that point tangent to the circle must be the same.
Thus, we can conclude that Rahul should change the lengths of the vectors that point tangent to the circle so that each is the same length.
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A round ball is kicked into the air at an angle of 39 degrees above the horizontal. The
initial velocity of the ball is 32 m/s.
A. How long is the ball in the air?
B. What is the horizontal distance traveled by the ball?
C. What is the maximum height reached by the ball?
Answers
Answer:
b
Explanation:
How do you do thisss
Answers
Answer:
Its 13n
Explanation:
for 1n its 0.2 times that by 13 and you get 2.6
Answer:
the answer is 8n
Explanation:
hope this helps
A force of 100 N is used to move a chair 2 m. How much work is done
Answers
Answer:
200 J
Explanation:
In the case of a rectilinear movement, the work is calculated as the product of Force (N) * movement (m). In your case, unless the angle between the force vector and the displacement vector is different from 0, the work is:
100 N * 2 m = 200 J
Jane measures a piece of metal and determines it has a mass of 10 grams and a volume of 2 mL. What is the density of the piece of metal?
Answers
Answer: 5g/ml
Explanation:
Fred (m=67 kg) foolishly attempts top jump from a canoe (45kg) to the dock. if he jumps forward with a speed of 3.3 m/s how fast will the canoe move backward
Answers
Answer:
Approximately \(4.9\; {\rm m\cdot s^{-1}}\) backward, assuming that the canoe was initially stationary.
Explanation:
When an object of mass \(m\) is moving at a velocity of \(v\), the momentum \(p\) of that object would be \(p = m\, v\).
With a mass of \(m = 67\; {\rm kg}\) and a velocity of \(v = 3.3\; {\rm m\cdot s^{-1}}\) forward, the momentum of Fred would be \(p = m\, v = 67\; {\rm kg} \times 3.3\; {\rm m\cdot s^{-1}} = 22.11\; {\rm kg \cdot m \cdot s^{-1}}\) (forward.)
Before the jump, the velocity of the boat and Fred were both \(0\; {\rm m \cdot s^{-1}}\). Hence, the momentum of both Fred and the boat would initially be \(0\; {\rm kg \cdot m \cdot s^{-1}}\).
Momentum is preserved immediately after the jump. Thus, the momentum of Fred plus the momentum of the boat would still be \(0\; {\rm kg \cdot m \cdot s^{-1}}\) after the jump.
Since the momentum of Fred was \(22.11\; {\rm kg \cdot m \cdot s^{-1}}\), the momentum of the boat would be \((-22.11\; {\rm kg \cdot m \cdot s^{-1}})\) (backward, as the negative sign indicates.)
Rearrange \(p = m\, v\) to find velocity in terms of mass \(m\) and momentum \(p\):
\(\begin{aligned} v &= \frac{p}{m} \\ &= \frac{-22.11\; {\rm kg \cdot m \cdot s^{-1}}}{67\; {\rm kg}} \\ &\approx (-4.9)\; {\rm m \cdot s^{-1}}\end{aligned}\).
In other words, the velocity of the boat would be approximate \(4.9\; {\rm m\cdot s^{-1}}\) backwards.
Planet X has a mass of M and a radius of R. Planet Y has a mass of 3M and a radius of 3R. Identical satellites orbit both planets at a distance R above their surfaces, as shown above. The planets are separated by such a large distance that the gravitational forces between them are negligible.
How does the magnitude of the gravitational force FY exerted by Planet Y on its satellite compare to the gravitational force FX exerted by Planet X on its satellite?
Answers
Answer:
\({FY} = \dfrac{3}{4} \times FX\)
Explanation:
The parameters given for the planets are;
The mass of planet X = M and the radius of planet X = R
The mass of planet Y = 3·M and the radius of planet Y = 3·R
The magnitude of the gravitational force of the planets on their satellites are given by the following equation;
\(F=G \times \dfrac{M_{1} \cdot m_{2}}{R^{2}}\)
Where;
M₁ = The mass of the first object = The mass of the planet
m₂ = The mass of the second object = The mass of the satellite
R = The distance between the centers of the two planets = The distance between the center of the planet and the satellite
G = The universal gravitational constant
The force between planet X and the satellite in its orbit = \(FX=G \times \dfrac{M \times m}{(2 \cdot R)^{2}} = G \times \dfrac{M \times m}{4 \cdot R^{2}}\)
The force between planet Y and the satellite in its orbit = \(FY=G \times \dfrac{3\cdot M \times m}{(4 \cdot R)^{2}} = G \times \dfrac{3\cdot M \times m}{16 \cdot R^{2}} = G \times \dfrac{ 3\cdot M \cdot m}{16 \cdot R^{2}}\)
Therefore;
\(\dfrac{FY}{FX} = \dfrac{G \times \dfrac{ 3\cdot M \cdot m}{16 \cdot R^{2}}}{G \times \dfrac{M \times m}{4 \cdot R^{2}}} = \dfrac{3}{16} \times \dfrac{4}{1} = \dfrac{3}{4}\)
\({FY} = \dfrac{3}{4} \times FX\)
Mr X wa accued of peeding along a highway. He wa travelling at different peed,but an average peed of 80 km/h. Baed on thr given information, i Mr X gulity or innocent?
Answers
Mr. X is guilty if the average speed of the car was 80 km/h, if we consider the speed limit as 80 km/h.
Average speed i defined as the ratio of total distance and total time taken by the object to cover that distance. It may or may not be the constant speed of the whole journey. We can also say that average speed is the average of minimum speed and the maximum speed of the object during the entire journey. So there might be a point where Mr. X exceeded the speed above 80 km/h, which is the safe limit of speed. So Mr. X must be guilty for over speeding.
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two stars have the same inherent brightness (absolute magnitude). star a appears 1/16 as bright as star b. star a is 4 light years away. star b must be
Answers
Star b must be 2 light years away. The apparent brightness of a star decreases with the square of the distance. Since star a appears 1/16 as bright as star b, star b must be √16 = 4 times closer, which is 2 light years away.
The apparent brightness of a star is determined by its intrinsic brightness, also known as its absolute magnitude, and its distance from the observer. In this scenario, star a and star b have the same absolute magnitude, indicating that they have the same inherent brightness. However, star a appears 1/16 as bright as star b. Since apparent brightness is inversely proportional to the square of the distance, we can deduce that star b must be 1/4 times the distance of star a to maintain the same apparent brightness. Given that star a is 4 light years away, star b must be 2 light years away. This ensures that the apparent brightness of star b is 1/16 of star a, as observed.
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The Voyager 1 space probe was launched by NASA in 1977. It's now the most distant spacecraft from Earth, as it hurtles into space at over 60,000 km/h. It has run out of fuel, so it can't change its own motion.
One of your friends says, "If Voyager 1 doesn't collide with anything and is too far from anything to be affected by gravity, it will gradually slow down and stop."
I have to either agree or disagree with my friend, then i have to explain.
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The statement, "The Voyager 1 space probe can't change its own motion" is correct and true. The Voyager 1 space probe was launched by NASA in 1977, and since then it has traveled over 14 billion miles away from Earth. It's the most distant spacecraft from Earth.
The Voyager 1 was designed to study the outer solar system and it sent valuable data back to Earth. But, now it has run out of fuel and cannot change its own motion as the thrusters that are responsible for keeping the spacecraft’s antenna pointed toward Earth have to be continuously fired to compensate for the small natural imbalances in its motion. Therefore, the statement is correct that Voyager 1 cannot change its own motion. It is still continuing its journey into space at a speed of over 60,000 km/h and is expected to keep traveling until it reaches other stars and the next galaxy beyond our Milky Way. So, I agree with the statement that the Voyager 1 space probe can't change its own motion.For such more question on motion
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A block slides down a smooth ramp, starting from rest at a height h. When it reaches the bottom it’s moving at speed vi. It then continues to slide up a second smooth ramp. At what height is its speed equal to vi/2?
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The item has no energy at its greatest point since all of it's kinetic energy has been transformed into potential energy; as a result, the velocity is null and the object is not accelerating.
Is the only possible speed the speed of light?The best engine in the cosmos is the speed of light. A study that was earlier this month published in the scientific journal Nature revealed that it was an illusion.
What is the energy formula for height?The formula for gravitational force is P.E. Equals mgh, where g is the deceleration caused by gravity (9.8 m/s2 at the earth's surface) when h is the elevation in meters. The units for gravitational potential energy are kg m2/s2, which are the same as those for kinetic energy.
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what is all of the living organisms in an ecosystem
Answers
Answer:
species of plants, animals, and fungi, as well as all the micro-organisms.
Explanation:
what is an echo?
give me an short answer
Answers
Answer:
Echo..... when the sound reflects back
steel bars, each of length 3cm at 29°c are to be used for constructing a rail line. lf the linear expansivity of steel is 1.0×10^-5k^-1, calculate the safety gap between successive bars if the highest temperature expected is 41°c
Answers
Answer:
Hi, Im Jenna! Here is ur ansswer Pls mark as braijnliest
Explanation:
solution.
The formula for linear expansivity is
α = (If – If) / If (0f – 0i ) is used to determine the linear expansivity
If – final length,
I – initial length
0f – final tempt.
0i – initial tempt.
(b) (ii)
I = 3 m
0 = 29oC
02 = 41oC
α = 1.0 x 10 k-1
using safety gap = change in length
Δ l = α I Δ Θ
1 x I0-5 x 3.0 x (41 – 29) = 3.6 x 10-3 m = 0.0036
Question. 1 How much heat is necessary to warm 500g of water from 20°C to 65°C?
Answers
Answer:
The heat necessary to warm 500g of water from 20°C to 65°C is 37,620 J.
Explanation:
GIVEN: m = 500 gm, T₂ = 65°C AND T₁ = 20°C, we know that c (specific heat capacity) = 4180
TO FIND: The heat necessary to warm 500g of water from 20°C to 65°C.
SOLUTION:
By using the heat equation,
Q=m c ΔT
ΔT = T₂ - T1
ΔT = 65 - 20 = 45°C
In this case,
Q = 0.2 × 4180 × 45 = 37,620 J
A car traveling at 35.6m/s crashes into a concert barrier and comes to a stop in 0.35 seconds. Calculate the average force applied to the 75kg driver.A 3.2kg steel ball traveling at 4.1m/s strikes a second ball of a mass 2.3kg Initially at rest. Calculate the velocity of the second ball when the first one continues traveling in the same direction with a speed of 1.5m/s2 balls of putty are shot towards one another. Ball 1 has a mass of 4.3kg and is moving at 18.6m/s . Ball 2 has a mass of 5.8kg and is moving at 9.5m/s. They collide and stick together. Calculate their final combine velocity.I really appreciate those attempting the problems. I do know the answers but I’m unaware of the steps to get there. Please include all formulas in your response and steps so I can learn and understand.Check your answer:7629N3.6m/s2.46m/sThank you all!
Answers
The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.
We have to find the acceleration using;
v = u - at
v = final velocity = 0 m/s
u = initial velocity = 35.6m/s
a = acceleration = ?
t = time = 0.35 s
u = at
a = u/t = 35.6m/s / 0.35 s
a = 101.7 ms-2
The force on the driver = 75kg × 101.7 ms-2 = 7629 N
Using the principle of conservation of momentum;
Momentum before collision = momentum after collision
m1u1 +m2u2 = m1v1 + m2v2
Hence
(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2
13.12 = 4.8 + 2.3v2
13.12 - 4.8 = 2.3v2
v2 = 13.12 - 4.8/2.3
v2 = 3.6 m/s
Using the principle of conservation of linear momentum;
m1u1 + m2u2 = m1v1 + m2v2
(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v
v = 79.98 + 55.1/10.1
v = 13.37 m/s
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The oldest rock layer in an undisturbed rock sequence occurs
A;at the bottom of the sequence
B; below the sedimentary rock layer
C;below the unconformity
D;at the top of the sequence
Answers
Answer:
below the sedimentary rock layer
2. Under what part of the light spectrum do the petals of a rose appear red?
Answers
Answer:
Because the petals reflect the red part of the white light and the leaves reflect the green part of the white light.
Could somebody pls help me out with this?
1) You serve a Volleyball with a mass of 1.6kg. the ball leaves your hand with a speed of 25m/s. the ball has________energy. Calculate it.
2) Askateboard is sitting at the top of a hill that is 26m high. the skateboard weighs 2 N. the skateboard has _____energy. Calculate it.
Answers
2) potential
A carnival ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute. What is the acceleration of a passenger at his lowest point during the ride?.
Answers
The acceleration of the person is 4.108 m/s^2.
What is acceleration?
The acceleration is the rate of change in the velocity in a unit of time.
Angular velocity: The change in angular displacement in a unit of time is called angular velocity.
Tangential velocity: The tangential velocity can be defined as the velocity of an object which is perpendicular to the radius in the rotational motion.
The relation between angular velocity ω, tangential velocity v, and radius r from the axis when the radius is perpendicular to the tangential velocity is,
v=ω*r
Given r=15 m, and ω=5 turns/minutes, substitute these values in the above formula.
Note: 1 turn/minute = 2π/60 rad/s.
v=(5 turns/minutes)*15 m
v=(5*2π/60 rad/s)* 15 m
v=7.85 m/s
Since the motion is circular, and the person is at the lowest point of the wheel, so the acceleration due to gravity will have no effect as it is perpendicular to tangential velocity here. The acceleration a for rotational motion is given by,
a=v^2/r
Substitute v=7.85 m/s, and r=15 m in this equation and solve it.
a=(2.094)^2/(15)
a=4.108 m/s^2
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A converging lens (f = 12.2 cm) is located 29.4 cm to the left of a diverging lens (f = -5.64 cm). A postage stamp is placed 35.1 cm to the left of the converging lens.
(a) Locate the final image of the stamp relative to the diverging lens. (Include sign to indicate which side of the lens the image is on.)
___________cm
(b) Find the overall magnification.
(c) Is the final image real or virtual?
(d) With respect to the original object, is the final image upright or inverted?
(e) With respect to the original object, is the final image larger or smaller?
Answers
Therefore, the final image of the stamp is located 15.8 cm to the right of the converging lens.
To solve this problem, we can use the thin lens equation and the magnification equation for each lens, and then apply the rules for combining lenses.
(a) The converging lens forms an intermediate image of the stamp:
1/f_con = 1/do + 1/di1
1/12.2 = 1/35.1 + 1/di1
di1 = 22.9 cm (positive, since it is on the same side as the object)
This intermediate image then becomes the object for the diverging lens:
1/f_div = 1/di1 + 1/di2
1/-5.64 = 1/22.9 + 1/di2
di2 = -15.8 cm (negative, since it is on the opposite side from the diverging lens)
Therefore, the final image of the stamp is located 15.8 cm to the right of the diverging lens.
(b) The overall magnification is the product of the magnifications of each lens:
m = m_con * m_div
= (-di1/do) * (-di2/di1)
= (22.9/35.1) * (15.8/22.9)
≈ 0.686
(c) The final image is virtual, since it is formed by a diverging lens.
(d) The final image is inverted, since the magnification is negative.
(e) The final image is smaller than the object, since the magnification is less than 1.
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You exert a force of 200 N on a lever over a distance of 4.6 m. You ultimately lift an 11 kg load 2.3 m off the ground. What is the efficiency of this lever?
Answers
Answer:
56142e3456834567856783446357
Explanation:
4535x346326432x5636432784372=3853785