Create a system of equations that can be used to determine the rental cost of each truck for the 1-day move. Be sure to specify what the variables represent.

For a right angled triangle with known measure of sides 11.2 units and 8.5 units, the unknown value of third side, i.e, x is equals to the 7.3 units.

A right triangle or right-angled triangle is defined as a triangle in which one angle is a right angle. Therefore, one of the angles must be 90 degrees and sum all interior angles is equals to 180°. See the triangle present in above figure. It is a right angled triangle because measure of one angle is 90°.

Height of triangle = x units

Base of triangle, b = x

Length of hypotenuse of triangle = 11.2

We have to determine the value of x. Using payathagaros theorem of sides in a right angled triangle, (hypothenuse)² = (base)² + (height)²

Substitute all known values in above formula,

=> (11.2)² = x² + (8.5)²

=> 125.44 = x² + 72.25

=> x² = 125.44 - 72.25

=> x² = 53.19

=> x = 7.2931 ~ 7.3

Hence, required value is 7.3 units.

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Complete question:

The above figure complete the question. Solve for x. Round your answer to the nearest tenth.

X

8. 5

11. 2

I didn't see options to pick from, but possible proportions would be

30/120  or  1/4  or any other fraction equivalent to 1/4

As a decimal, 30/120 = 0.25, which is the same as 25%.

Answer:

A square root of a number is a value that, when multiplied by itself, gives the number.

Examples:

4 multiplied by itself is 16. Therefore, the square root of 16 is 4.

(4 x 4 = 16)

The same goes for every number.

(3 x 3 = 9) square root of 9 is 3

(5 x 5 = 25) square root of 25 is 5

finding the number which was multiplied to itself giving the given product of question

Answer:

3,15

Step-by-step explanation:

took the test boi

Answer:

∠ LOE = 20°

Step-by-step explanation:

since OJ is perpendicular to OE then ∠ JOE = 90°

from the diagram

∠ JOL + ∠ LOE = ∠ JOE ( substitute values )

6x + 10 + x + 10 = 90

7x + 20 = 90 ( subtract 20 from both sides )

7x = 70 ( divide both sides by 7 )

x = 10

Then

∠ JOE = x + 10 = 10 + 10 = 20°

If a  bacteria colony triples every 4 days the population is p0 bacteria then  the population of the bacteria  pt is t days later will be P=Po\(3^{t/4}\)

Exponential function:

An exponential function is a Mathematical function in form f (x) = ax, where “x” is a variable and “a” is a constant which is called the base of the function and it should be greater than 0. The most commonly used exponential function base is the transcendental number e, which is approximately equal to 2.71828.

In this question, it is said that the bacteria triples in every 4 days and the original amount of bacteria is Po.

P(bacteria in t days)= Po(\(number of multipier^{t/days}\))

                               =Po(\(3^{t/4}\))

So when a bacteria triples in every 4 days then the population of bacteria in t days will be Po(\(3^{t/4}\))

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Answer:

+3, +1

I think this is the answer because if its asking about the chart it is adding 3 on the x-axis and adding 1 on the y-axis

Hope this helps :)

Answer: -0.6

Step-by-step explanation:

To answer the questions, we need to break down the investments and interest calculations week by week.

1. Value of the account at the end of Week 15:
Let’s assume the weekly investment is P dollars.

At the end of Week 3, the value of the account is P + rP = P(1 + r).
At the end of Week 7, the value of the account is P(1 + r) + s(P(1 + r)) = P(1 + r)(1 + s).

At the end of Week 8, the value of the account is P(1 + r)(1 + s) + r(P(1 + r)(1 + s)) = P(1 + r)(1 + s)(1 + r).

At the end of Week 11, the value of the account is P(1 + r)(1 + s)(1 + r) + s(P(1 + r)(1 + s)(1 + r)) = P(1 + r)(1 + s)(1 + r)(1 + s).

At the end of Week 12, the value of the account is P(1 + r)(1 + s)(1 + r)(1 + s) + r(P(1 + r)(1 + s)(1 + r)(1 + s)) = P(1 + r)(1 + s)(1 + r)(1 + s)(1 + r).

At the end of Week 15, the value of the account is P(1 + r)(1 + s)(1 + r)(1 + s)(1 + r) + s(P(1 + r)(1 + s)(1 + r)(1 + s)(1 + r)) = P(1 + r)(1 + s)(1 + r)(1 + s)(1 + r)(1 + s).

So, the value of the account at the end of Week 15 is P(1 + r)(1 + s)(1 + r)(1 + s)(1 + r)(1 + s).

2. Weekly investment needed to have $10,000 at the end of Week 15:
Now, we need to find the weekly investment (P) that will yield a total value of $10,000 at the end of Week 15.

Set the value of the account at the end of Week 15 equal to $10,000:
P(1 + r)(1 + s)(1 + r)(1 + s)(1 + r)(1 + s) = $10,000.


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Answer:

6xy + 18x + 6y

Hope this helps!

Answer:

i dont know the answer to this

Step-by-step explanation:

Because i just dont

Answer:

5/6

Step-by-step explanation:

Step 1:

First, let's order the number from least to greatest.

A. -0.31

B. -0.33

C. -0.38

D. -0.29

We could see that A, B, and C's numbers are already from least to greatest, so all we have to do is to move -0.29 (D) up to the top, since -0.29 is the number with the lowest value.

C. -0.38

B. -0.33

A. -0.31

D. -0.29

Step 2:

Let's look at the four number lines. Remember that we already organized the numbers from least to greatest, so the order they go in on the number line is: C, B, A, and D. Since Line C and D Don't follow that rule, we know those are not our answers. Also on line B, C is on the left of -0.4, but C's value is less than -0.4, so B is wrong. We are left with line A.

Line A: C. -0.38, B. -0.33, A. -0.31, D. -0.29

Our answer: Line A

Answer:

B: -0.3

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

Just subtract ST from RT to get RS

13-2=11

The point that represents the opposite of 3/2 is -3/2, and it should be plotted on the number line between -2 and -1.

The opposite of a number is its additive inverse, which means that when added to the original number, the result is zero. The opposite of 3/2 is -3/2 since 3/2 + (-3/2) = 0. To plot this point on the number line, we can find the midpoint between -2 and -1, which is -3/2, and mark it with a dot. Therefore, the point representing the opposite of 3/2 is -3/2, and it should be plotted on the number line between -2 and -1.

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The measure of an exterior angle of a regular polygon with 16 sides can be found by dividing 360 degrees (the sum of all exterior angles in any polygon) by the number of sides. Therefore, the measure of an exterior angle of a regular polygon with 16 sides is 22.5 degrees.

A regular polygon has equal side lengths and equal interior angles. The sum of the exterior angles of any polygon is always 360 degrees. In a regular polygon, each exterior angle has the same measure. To find the measure of an exterior angle of a regular polygon, we divide 360 degrees by the number of sides.
In this case, the polygon has 16 sides. Therefore, the measure of each exterior angle can be calculated as follows:
Measure of each exterior angle = 360 degrees / 16 sides = 22.5 degrees.
Hence, the measure of an exterior angle of a regular polygon with 16 sides is 22.5 degrees.

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RESPUESTA: no es un triangulo

EXPRICACION

The sum of any two sides must be greater than the other to be it triangle thus it will not be a triangle so option (D) is correct.

A triangle is a 3-sided shape that is occasionally referred to as a triangle. There are three sides and three angles in every triangle, some of which may be the same.

The sum of all three angles inside a triangle will be 180°.

For any triangle, the sum of any two sides must be greater than the then third side.

As per the given sides,  11, 13, 25

11 + 13 < 25

24 < 25 so it will not a triangle.

Hence "The sum of any two sides must be greater than the other to be it triangle thus it will not be a triangle".

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Answer:

1) 6.28

2) 62.8

Step-by-step explanation:

Multiply pi by the diameter to get the circumfrence.

Answer:

6.28in and 62.8m

Step-by-step explanation:

C = d(3.14)

C = 2(3.14) = 6.28

C = 20(3.14) = 62.8

Answer:

Final temperature of the solution is 14°C.

Step-by-step explanation:

Given that,

Initial temperature of the solution, \(T_i=31^{\circ}\ C\)

The change in temperature of the solution, \(\Delta T=-17^{\circ}\ C\)

We need to find the final temperature of the solution.

Change in temperature = Final temperature - initial temperature

\(\Delta T=T_f-T_i\\\\T_f=\Delta T+T_i\\\\T_f=-17+31\\\\T_f=14^{\circ} C\)

So, the final temperature of the solution is 14°C.

Answer:

Step-by-step explanation:

First, you need to be familiar with the volume equation for the object in question.

The equation is \(v= (\frac{\pi r^2h}{2})\)

For the outer  shape we are given the diameter (which is just r*2), making the radius 8

For the the first object the equation becomes\(\frac{\pi(8^2)16}{2}\) which then comes out to 1608.49 which when rounded is 1608

Since we are to assume the shaded object is in the middle, we see that the distance from the shaded object to the other object is 4. So to find the radius of the shaded object we need to subtract 4 from the radius of the bigger object. The radius of the shaded object is 4

Using the same equation above we get that the volume is equal to \(\frac{\pi 4^{2}8 }{2}\) which comes to 201.06 which when rounded is 201

If you need the outer object without the volume of the inner object just subtract 201 from 1608

Answer:

16

Step-by-step explanation:

Pemdas is the order of operations

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Answer:

16

Step-by-step explanation:

3 x 6 - 12 / 6.

18 - 2

  16

The multiples of 5 include 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80...

Given that its a straight line, so the sum of three angles is 180°

So possible angles:

..

The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x  ≥ -6

From the question, we have the following parameters that can be used in our computation:

\(f(x) = \sqrt{\frac{1}{3}x + 2\)

Set the radicand greater than or equal to 0

So, we have

1/3x + 2 ≥ 0

Next, we have

1/3x  ≥ -2

So, we have

x  ≥ -6

Hence, the domain of the function is (d) x  ≥ -6

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Answer:

it’s the first one

Step-by-step explanation:

rise 1 run 3

Answer: a

i hope this helped! have a good day

Based on the given information, we cannot prove that △EFG and △KLM are similar using the SSS or SAS similarity theorems. The correct answer is option D) No, they cannot be proven similar by SSS or SAS.

To determine if the triangles △EFG and △KLM can be proven similar using the SSS (Side-Side-Side) or SAS (Side-Angle-Side) similarity theorems, we need to compare their corresponding sides and angles.

SSS Similarity Theorem states that if the lengths of the corresponding sides of two triangles are proportional, then the triangles are similar.

SAS Similarity Theorem states that if two corresponding sides of two triangles are proportional, and the included angles are congruent, then the triangles are similar.

Let's examine the given information:

Side lengths of △EFG: EF = 18, EG = 24, FG = 15.

Side lengths of △KLM: KL = 6, KM = 8, LM = 5.

By comparing the side lengths, we can see that they are not proportional. For example, the ratio of EF/KL is 18/6 = 3, while the ratio of EG/KM is 24/8 = 3. Therefore, the corresponding sides of △EFG and △KLM are not proportional, which means we cannot establish similarity using the SSS theorem.

Now, let's consider the SAS theorem. For this, we also need to compare the included angles.

Angles of △EFG: ∠EFG, ∠EFG, ∠EGF.

Angles of △KLM: ∠KLM, ∠KML, ∠KLM.

The given information states that ∠EFG and ∠KLM are congruent. However, we don't have any information about the other angles. Without knowing the congruency of the remaining angles, we cannot establish similarity using the SAS theorem

Option D.

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Answer: Its C

Step-by-step explanation:

Answer: ok so uhmmmm whats you math class about and what its about just study on that topic and i hope you pass if you have any tests

A. The solution is x1 = -4/5 and x2 = -22/15.

B. the solution is x1 = 43/45 and x2 = 106/45.

(a) For b1 = 6 and b2 = 24:

The augmented matrix is:[ 1  -5  |  6 ][ 13 -14 | 24 ]

Performing row operations:R2 = R2 - 13R1

[ 1  -5  |  6 ] [ 0  45  | -66 ] R2 = (1/45) R2[ 1  -5  |  6 ][ 0   1  | -22/15 ]

R1 = R1 + 5R2 [ 1   0  |  -12/15 ] [ 0   1  |  -22/15 ]

The row-echelon form gives us the following equations:

x1 = -12/15 = -4/5 x2 = -22/15

Therefore, the solution is x1 = -4/5 and x2 = -22/15.

(b) For b1 = -7 and b2 = 25:

The augmented matrix is: [ 1  -5  | -7 ] [ 13 -14 | 25 ]

Performing row operations: R2 = R2 - 13R1 [ 1  -5  | -7 ] [ 0  45  | 106 ]

R2 = (1/45)R2 [ 1  -5  | -7 ] [ 0   1  | 106/45 ]

R1 = R1 + 5R2 [ 1   0  | 43/45 ] [ 0   1  | 106/45 ]

The row-echelon form gives us the following equations:

x1 = 43/45

x2 = 106/45

Therefore, the solution is x1 = 43/45 and x2 = 106/45.

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