Critical values are considered to be part of the

Answer:

\(\frac{7}{10}\)

Step-by-step explanation:

P(R or B)=\(\frac{5}{20}+\frac{9}{20}\)

             =\(\frac{7}{10}\)

Option A is correct. The value of function (f/g)(x) is found to be  \(\sqrt[3]{3x}\)/(3x+2) where the condition is that  x ≠  -2/3.

In mathematics, function composition is an operation in which two functions, f and g, form a new function, h, in such a way that h(x) = g(f(x)). This signifies that function g is being applied to the function x. So, in essence, a function is applied to the output of another function.

The new function obtained by performing f first and then g is the combination of two functions g and f.

Given:

f(x) = \(\sqrt[3]{3x}\)

g(x) = 3x + 2

(f/g)(x) =  \(\sqrt[3]{3x}\)/(3x+2)

Also, the denominator should not be equal to 0.

So, 3x + 2 ≠ 0

     x ≠  -2/3

Therefore, the value of function  is found to be  \(\sqrt[3]{3x}\)/(3x+2) where the condition is that  x ≠  -2/3. So, Option A is correct

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Answer:

3

Step-by-step explanation:

Based on the given data, the probability that exactly 2 insects will survive is 0.1402 rounded to four decimal places.

The probability mass function for the binomial distribution is given by:

P(X=k) = (n choose k) * p^k * (1-p)^(n-k)

where X is the random variable representing the number of successes (surviving insects), k is the specific number of successes we're interested in (k=2 in this case), n is the total number of trials (n=11), p is the probability of success (p=0.3), and (n choose k) is the binomial coefficient, which is the number of ways to choose k objects from a set of n objects.

Plugging in the values, we get:

P(X=2) = (11 choose 2) * 0.3² * 0.7²

= (55) * 0.09 * 0.02825

= 0.1402

Therefore, the probability that exactly 2 insects will survive is 0.1402 (rounded to four decimal places).

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Given dimensions:

x=31 feet, y= 24 feet and z= 95 feet

We can split the shape above into 3 components: A, B, and C

To find the total area, we will find the sum of the areas of each component

For A

The shape of A is that of a semi-circle.

The area of a semi-circle is given to be

The radius will be the diameter divided by 2

y= diameter

r= radius = y/2

r=24/2 =12 feet

pi=3.14

For B

The shape is a rectangle

The area of a rectangle is given by

A = l x b

where l = 31 and b = 24

Area = 31 x 24

Area = 744 square feet

For C

The shape is a triangle

The area of the triangle is given by

base = 64 feet, height = 24 feet

The total area is

22

KM, JK, PK, and MJ are shown on the diagram.

Then the correct options are B, C, D, and F.

Since, Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.

A line segment in mathematics has two different points on it that define its boundaries.

All the line segments will be

JK, JM, KM, MP, PK, and KL

The triangle KPM.

And the angle will be ∠LKJ, ∠PKM. ∠KMP. and ∠MPK.

Then the correct options are B, C, D, and F.

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Answer:

= y + x - 4 = 0

Step-by-step explanation:

a slope or -1

The point = (0,4).

the equation =

\( \frac{y - y1}{x - x1} = m\)

y - 4 = -1

x - 0

note: Perform close multiplication

remember every whole number is over 1

y - 4 = - ( x - 0)

y - 4 = - x + 0

y + x - 4 = 0.

Answer:

1/2 yard

Step-by-step explanation:

Multiply the top numbers (the numerators). Which would give you 6.

Multiply the bottom numbers (the denominators). Which would leave you with 12.

Simplify the fraction if needed. 6/12 can be simplified down to 1/2

Answer: \(y=3.2x+8\)

Step-by-step explanation:

\(16x-5y=-40\\\\16x+40-5y=0\\\\16x+40=5y\\\\5y=16x+40\\\\\boxed{y=3.2x+8}\)

Answer:

(i) x ≤ 1

(ii) ℝ except 0, -1

(iii) x > -1

(iv) ℝ except π/2 + nπ, n ∈ ℤ

Step-by-step explanation:

(i) The number inside a square root must be positive or zero to give the expression a real value. Therefore, to solve for the domain of the function, we can set the value inside the square root greater or equal to 0, then solve for x:

\(1-x \ge 0\)

\(1 \ge x\)

\(\boxed{x \le 1}\)

(ii) The denominator of a fraction cannot be zero, or else the fraction is undefined. Therefore, we can solve for the values of x that are NOT in the domain of the function by setting the expression in the denominator to 0, then solving for x.

\(0 = x^2+x\)

\(0 = x(x + 1)\)

\(x = 0\)     OR     \(x = -1\)

So, the domain of the function is:

\(R \text{ except } 0, -1\)

(ℝ stands for "all real numbers")

(iii) We know that the value inside a logarithmic function must be positive, or else the expression is undefined. So, we can set the value inside the log greater than 0 and solve for x:

\(x+ 1 > 0\)

\(\boxed{x > -1}\)

(iv) The domain of the trigonometric function tangent is all real numbers, except multiples of π/2, when the denominator of the value it outputs is zero.

\(\boxed{R \text{ except } \frac{\pi}2 + n\pi} \ \text{where} \ \text{n} \in Z\)

(ℤ stands for "all integers")

Answer:

(i)  x ≤ 1

(ii)  All real numbers except x = 0 and x = -1.

(iii)  x > -1

(iv)  All real numbers except x = π/2 + πn, where n is an integer.

Step-by-step explanation:

The domain of a function is the set of all possible input values (x-values).

\(\hrulefill\)

\(\textsf{(i)} \quad f(x)=\sqrt{1-x}\)

For a square root function, the expression inside the square root must be non-negative. Therefore, for function f(x), 1 - x ≥ 0.

Solve the inequality:

\(\begin{aligned}1 - x &\geq 0\\\\1 - x -1 &\geq 0-1\\\\-x &\geq -1\\\\\dfrac{-x}{-1} &\geq \dfrac{-1}{-1}\\\\x &\leq 1\end{aligned}\)

(Note that when we divide or multiply both sides of an inequality by a negative number, we must reverse the inequality sign).

Hence, the domain of f(x) is all real numbers less than or equal to -1.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x \leq 1\\\textsf{Interval notation:} \quad &(-\infty, 1]\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \leq 1 \right\} \end{aligned}}\)

\(\hrulefill\)

\(\textsf{(ii)} \quad g(x) = \dfrac{1}{x^2 + x}\)

To find the domain of g(x), we need to identify any values of x that would make the denominator equal to zero, since division by zero is undefined.

Set the denominator to zero and solve for x:

\(\begin{aligned}x^2 + x &= 0\\x(x + 1) &= 0\\\\\implies x &= 0\\\implies x &= -1\end{aligned}\)

Therefore, the domain of g(x) is all real numbers except x = 0 and x = -1.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x < -1 \;\;\textsf{or}\;\; -1 < x < 0 \;\;\textsf{or}\;\; x > 0\\\textsf{Interval notation:} \quad &(-\infty, -1) \cup (-1, 0) \cup (0, \infty)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \neq 0,x \neq -1 \right\} \end{aligned}}\)

\(\hrulefill\)

\(\textsf{(iii)}\quad h(x) = \log_7(x + 1)\)

For a logarithmic function, the argument (the expression inside the logarithm), must be greater than zero.

Therefore, for function h(x), x + 1 > 0.

Solve the inequality:

\(\begin{aligned}x + 1 & > 0\\x+1-1& > 0-1\\x & > -1\end{aligned}\)

Therefore, the domain of h(x) is all real numbers greater than -1.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x > -1\\\textsf{Interval notation:} \quad &(-1, \infty)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x > -1\right\} \end{aligned}}\)

\(\hrulefill\)

\(\textsf{(iv)} \quad k(x) = \tan x\)

The tangent function can also be expressed as the ratio of the sine and cosine functions:

\(\tan x = \dfrac{\sin x}{\cos x}\)

Therefore, the tangent function is defined for all real numbers except the values where the cosine of the function is zero, since division by zero is undefined.

From inspection of the unit circle, cos(x) = 0 when x = π/2 and x = 3π/2.

The tangent function is periodic with a period of π. This means that the graph of the tangent function repeats itself at intervals of π units along the x-axis.

Therefore, if we combine the period and the undefined points, the domain of k(x) is all real numbers except x = π/2 + πn, where n is an integer.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &\pi n\le \:x < \dfrac{\pi }{2}+\pi n\quad \textsf{or}\quad \dfrac{\pi }{2}+\pi n < x < \pi +\pi n\\\textsf{Interval notation:} \quad &\left[\pi n ,\dfrac{\pi }{2}+\pi n\right) \cup \left(\dfrac{\pi }{2}+\pi n,\pi +\pi n\right)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \neq \dfrac{\pi}{2}+\pi n\;\; (n \in\mathbb{Z}) \right\}\\\textsf{(where $n$ is an integer)}\end{aligned}}\)

The part of the expression which represents the discounted price before tax is x-35.

The given expression is 0.12x+(x-35).

An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.

a) The part of the expression represents the discounted price before tax is x-35

b) The part of the expression represent the amount of sales tax in dollars is 0.12x

Hence, the part of the expression which represents the discounted price before tax is x-35.

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Answer:

first one bro, its easy just multiply 10×10×10=30and0,43

Answer: 30 x 50 = 430/10 x 0.43 = 4.3 thats all i got bc im working on the same thing

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Point B is (-2,3) then it is shifted (x, y+4)

so, x remains the same by y goes up 4 units

-2,7

If x and y be  i.i.d. unif(0, 1), then the covariance of x + y and x - y is zero.

Yes, x y are x y independent studysoup.

Here  x and y be i.i.d. unif(0, 1)

The i.i.d stands for independent and identically distributed

unif means that the uniformly distributed

Here x and y are i.i.d unif (0,1)

The covariance is defined as the relationship between the two random variables . Therefore, variance of one variable is equal to the change in another variable

Here we have to find the covariance of x + y and x - y

According to the properties of covariance

Cov(x+ y, x - y) = Cov (x, x) + Cov(y, x) - Cov(x, y) - Cov(y, y) = 0

Because Cov(x, x) = Cov (y, y)

Cov(y, x) = Cov(x, y)

Therefore, the covariance of x+y and x - y is 0.

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The answer of the given question based on the graph is ,  The locations of A′ and B′ are A′ (0, 1) and B′ (1, 0); lines f and f′ are parallel.

A scale factor is a number that scales, or multiplies, a quantity by some factor. It is used in mathematics to describe the relationship between corresponding measurements of two similar figures, such as triangles or rectangles.

To dilate line f by scale factor of one half with center of dilation at origin, we  multiply coordinates of each point on line f by 1/2.

The equation of line f can be found by using the points A and B:

slope of line f = (0 - 2)/(2 - 0) = -1

y-intercept of line f = 2

Therefore, the equation of line f is y = -x + 2.

To find the coordinates of A' and B' after dilation, we can apply the dilation factor to each point:

A' = (0, 2)*1/2 =(0, 1)

B' = (2, 0)*1/2 =(1, 0)

So A' is located at (0, 1) and B' is located at (1, 0) after dilation.

Now let's analyze the relationship between lines f and f'. The dilation was centered at the origin, so the origin is a fixed point of the dilation. This means that the point where lines f and f' intersect must be the origin.

If we plug in x = 0 into the equation of line f, we get y = 2. This means that point A is located at (0, 2) and intersects with line f at y = 2. After dilation, point A' is located at (0, 1), which means that lines f and f' intersect at point A.

To determine the relationship between lines f and f', we can compare their equations. The equation of f' can be found by using the points A' and B':

slope of f' = (0 - 1)/(1 - 0) = -1

y-intercept of f' = 0

Therefore, the equation of f' is y = -x.

Comparing the equations of f and f', we can see that they have the same slope of -1, which means they are parallel. Therefore, the correct answer is: The locations of A′ and B′ are A′ (0, 1) and B′ (1, 0); lines f and f′ are parallel.

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The number of cards left to be signed is 32 cards.

To determine the number of cards left to be signed, we need to calculate the number of cards signed by each person and subtract it from the total number of cards.First, Emily signed 2/5 of the cards, which is equal to (2/5) * 75 = 30 cards.

Next, we need to find the number of cards remaining after Emily signed. To do this, we subtract the cards Emily signed from the total number of cards:

75 - 30 = 45 cards.

Now, Josh signs 1/9 of the remaining cards, which is equal to (1/9) * 45 = 5 cards.

After Josh signs his portion, we need to find the number of cards still remaining. We subtract the cards Josh signed from the previous remaining cards:

45 - 5 = 40 cards.

Finally, Tatiana signs 20% of what Josh had left, which is equal to 20/100 * 40 = 8 cards.

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Answer:

1. a. z test for means and t test for means.

2. C. HA : mu1 - mu2 > 0

Step-by-step explanation:

Hypothesis testing is used in a situation where there are more than 1 alternative available. The t test is conducted in the mean which determines the t value and then this value is compared with p value to identify the situation whether to accept or reject the null hypothesis. The alternative hypothesis in this situation is is represented by mu.

Answer:

a. 15L will last the cafe 3 days if they're using 4L every day

b. 15L will last them 7 days if they're using 2L every day

Step-by-step explanation:

division.

when the scale factor is 1, we have:

(side length of side opposite ∠A) / (length of hypotenuse) = sin A

When the scale factor is 1, the ratio of the side length of the side opposite ∠A to the length of the hypotenuse remains the same as in the original triangle. In a right triangle, the side opposite ∠A is referred to as the "opposite" side, and the hypotenuse is the longest side.

The ratio of the side length of the side opposite ∠A to the length of the hypotenuse is commonly known as the sine of angle A (sin A). So, when the scale factor is 1, the ratio of the side length of the side opposite ∠A to the length of the hypotenuse is equal to sin A.

In mathematical terms, when the scale factor is 1, we have:

(side length of side opposite ∠A) / (length of hypotenuse) = sin A

It's important to note that this ratio holds true for any right triangle, regardless of its size or dimensions, as long as the angle A remains the same.

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Answer:

8400p.

Step-by-step explanation:

I'm assuming you're asking about the total price of the loaves here. Please specify your question further next time.

(84*100)p

= 8400p

Hope that helped!

Answer:

x=-18 or x=67

Step-by-step explanation:

you can either make it so 48 remains the largest number and so take 66 from 48 (=-18) or you can leave one as the smallest number and add 66 to one(=67)

Answer: First you have to take 20% and make it into a fraction 1/5.

Then you multiply 46.5 and multiply it by 1/5 and get 9.3

Add $46.50 and $9.30 and get $55.80

Step-by-step explanation: Hope this helps!! <3

Answer:

780

Step-by-step explanation:

In this example we will call Original Price = y

72%=0.72

218.40=0.72*y

1-0.72=0.28

218.4÷0.28=780

Answer:

The 90% confidence interval for the difference in the mean grade on test 7 for all students who attended a review session and for all students who did not attend a review session is (3.7, 12.3).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \(\mu = p\) and standard deviation \(s = \sqrt{\frac{p(1-p)}{n}}\)

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A simple random sample of 22 students who attended a review session was selected, and the mean grade on test 7 for this sample of 22 students was 85 with a standard deviation of 9.8.

This means that:

\(\mu_A = 85, s_A = \frac{9.8}{\sqrt{22}} = 2.09\)

An independent simple random sample of 47 students who did not attend a review session was selected, and the mean grade on test 7 was 77 with a standard deviation of 10.6.

This means that:

\(\mu_N = 77, s_N = \frac{10.6}{\sqrt{47}} = 1.55\)

Distribution of the difference in the mean grade on test 7 for all students who attended a review session and for all students who did not attend a review session.

Mean:

\(\mu = \mu_A - \mu_N = 85 - 77 = 8\)

Standard deviation:

\(s = \sqrt{s_A^2 + s_B^2} = \sqrt{2.09^2 + 1.55^2} = 2.6\)

Confidence interval:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.9}{2} = 0.05\)

Now, we have to find z in the Ztable as such z has a pvalue of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.05 = 0.95\), so Z = 1.645.

Now, find the margin of error M as such

\(M = zs\)

So

\(M = 1.645*2.6 = 4.3\)

The lower end of the interval is the sample mean subtracted by M. So it is 8 - 4.3 = 3.7

The upper end of the interval is the sample mean added to M. So it is 8 + 4.3 = 12.3

The 90% confidence interval for the difference in the mean grade on test 7 for all students who attended a review session and for all students who did not attend a review session is (3.7, 12.3).