Answer:
this is wrong answer
Step-by-step explanation:
Can anyone assist me with this, many thanks.
Answer:
1.a) x = g(2)
1.b) See below
2.a) See below
2.b) α = 60°
3.a) 2 + h
3.b) 2
4.a) Interval [3, 4] = 3 m/s
Interval [3, 3.1] = 2.1 m/s
4.b) 2 m/s
Step-by-step explanation:
Question 1Part (a)
Given function f(x):
\(f(x)=\dfrac{x}{x-2}\)
If the range of f is (-∞, 1) U (1, ∞), then a value of y in the range of f is y=2.
Set the function equal to the value of y and solve for x:
\(\begin{aligned}y=2 \implies \dfrac{x}{x-2}&=2\\x&=2(x-2)\\x&=2x-4\\-x&=-4\\x&=4\end{aligned}\)
The solution written as a function x = g(y) is:
x = g(2)Part (b)
Given function g(y):
\(g(y)=\dfrac{2y}{y-1}\)
Verify that g is the inverse function of f by calculating g(f(x)):
\(\begin{aligned}\implies g(f(x)) &=\dfrac{2f(x)}{f(x)-1}\\\\&=\dfrac{2\left(\frac{x}{x-2}\right)}{\left(\frac{x}{x-2}\right)-1}\\\\&=\dfrac{2\left(\frac{x}{x-2}\right)}{\left(\frac{x-(x-2)}{x-2}\right)}\\\\&=\dfrac{\left(\dfrac{2x}{x-2}\right)}{\left(\dfrac{2}{x-2}\right)}\\\\&=\dfrac{2x}{2}\\\\&=x \quad (\text{for all $x\neq 2$})\end{aligned}\)
Similarly, calculate f(g(y)):
\(\begin{aligned}\implies f(g(y))&=\dfrac{g(y)}{g(y)-2}\\\\&=\dfrac{\left(\frac{2y}{y-1}\right)}{\left(\frac{2y}{y-1}\right)-2}\\\\&=\dfrac{\left(\frac{2y}{y-1}\right)}{\left(\frac{2y-2(y-1)}{y-1}\right)}\\\\&=\dfrac{\left(\dfrac{2y}{y-1}\right)}{\left(\dfrac{2}{y-1}\right)}\\\\&=\dfrac{2y}{2}\\\\&=y \quad \text{(for all $y \neq 1$)}\end{aligned}\)
Hence verifying that g is the inverse function of f.
Question 2\(\boxed{\begin{minipage}{5 cm}\underline{Trigonometric Identities}\\\\$\tan x=\dfrac{\sin x}{\cos x}$\\\\\\$\cos \left(\arctan \left(x\right)\right)=\dfrac{1}{\sqrt{1+x^2}}$\\\\\\$\sin\left(\arctan \left(x\right)\right)=\dfrac{x}{\sqrt{1+x^2}}$\\\end{minipage}}\)
Part (a)
If y = arctan(x) then tan(y) = x.
Use the trigonometric identities to express sin(y) and cos(y) in terms of x.
\(\boxed{\begin{aligned}\tan(y) &= x\\\implies \dfrac{\sin y}{\cos y}&=x\\\sin y&=x \cos y\\ \sin y&=x \cos (\arctan x)\\ \sin y&=\dfrac{x}{\sqrt{1+x^2}}\end{aligned}}\)
\(\boxed{\begin{aligned}\tan(y) &= x\\\\\implies \dfrac{\sin y}{\cos y}&=x\\\\\dfrac{\sin y}{x}&= \cos y\\\\ \cos y&=\dfrac{\sin(\arctan x)}{x}\\\\ \cos y&=\dfrac{\dfrac{x}{\sqrt{1+x^2}}}{x}\\\\\cos y&=\dfrac{x}{\sqrt{x^2+1}x}\\\\\cos y&=\dfrac{1}{\sqrt{x^2+1}}\end{aligned}}\)
Part (b)
Given linear equation:
\(y=\sqrt{3}x+1\)
As the slope of a linear equation y = mx + b is m, then the slope (m) of the given line is √3.
If m = tan(α) then:
\(\begin{aligned}\implies m&=\sqrt{3}\\\tan (\alpha)&=\sqrt{3}\\\alpha&=\arctan \sqrt{3}\\\alpha&=60^{\circ}+180^{\circ}n\\\end{aligned}\)
If α is the angle the line forms with the x-axis, then α = 60°.
Question 3Given function:
\(f(x)=x^2-1\)
Part (a)
\(\begin{aligned}\dfrac{f(1+h)-f(1)}{h} &=\dfrac{((1+h)^2-1)-(1^2-1)}{h}\\\\&=\dfrac{(1+2h+h^2-1)-0}{h}\\\\&=\dfrac{2h+h^2}{h}\\\\&=2+h\end{aligned}\)
Part (b)
Part a used differentiating from first principles to find the gradient of f(x) at x = 1. As h gets smaller, the gradient of the straight line gets closer and closer to the gradient of the curve. Therefore, as h gets close to zero, (2 + h) gets close to 2. Therefore, the slope of the tangent line to the graph of f(x) at the point where x = 1 is 2.
Question 4A particle is moving on the x-axis and its position at time is given by
\(x(t)=t^2-4t+3\)
Evaluate the position of the particle at t = 3, t = 4 and t = 3.1:
\(x(3)=3^2-4(3)+3=0\)
\(x(4)=4^2-4(4)+3=3\)
\(x(3.1)=(3.1)^2-4(3.1)+3=0.21\)
Average velocity formula
\(\overline{v}=\dfrac{s(t_2)-s(t_1)}{t_2-t_1}\)
Therefore, the average velocity of this particle over the interval [3, 4]:
\(\overline{v}=\dfrac{x(4)-x(3)}{4-3}=\dfrac{3-0}{1}=3\;\; \rm m/s\)
The average velocity over the interval [3, 3.1] is:
\(\overline{v}=\dfrac{x(3.1)-x(3)}{3.1-3}=\dfrac{0.21-0}{0.1}=2.1\;\; \rm m/s\)
Part (b)
To find an equation for velocity, differentiate the given equation for displacement:
\(v(t)=\dfrac{\text{d}x}{\text{d}t}=2t-4\)
To calculate the instantaneous velocity of the particle at time t = 3, substitute t = 3 into the equation for velocity:
\(v(3)=2(3)-4=2\;\; \rm m/s\)
Using the graph provided, find the y-intercept.
Answer:
y-intercept = 2
Step-by-step explanation:
The y-intercept of a graph is simply the point at which the value of y, when x = 0. It is the point at which the y-axis is intercepted by the line.
In the graph provided, the line cuts the y-axis at y = 2, when x = 0.
Therefore the y-intercept of the graph provided = 2.
Instead of using the values {1,2,3,4,5,6) on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,4,5,6,8} on the other. Find the probability of rolling a sum of 6 with these dice. Be sure to reduce.
Answer:
the probability of rolling a sum of 6 with these dice is 1/6.
Step-by-step explanation:
To find the probability of rolling a sum of 6 with the given pair of dice, we can first list all possible pairs of outcomes that add up to 6:
(2,4)
(3,3)
(4,2)
For each of these pairs, we need to find the probability of rolling each number on its respective die and then multiply those probabilities together. The probability of rolling a particular number on one die is the number of times that number appears on that die divided by the total number of outcomes on that die.
For the first pair (2,4), the probability is:
(2 appears twice on one die out of six possible outcomes) × (4 appears once on the other die out of six possible outcomes) = (2/6) × (1/6) = 1/18
For the second pair (3,3), the probability is:
(3 appears twice on one die out of six possible outcomes) × (3 appears twice on the other die out of six possible outcomes) = (2/6) × (2/6) = 4/36
For the third pair (4,2), the probability is:
(4 appears twice on one die out of six possible outcomes) × (2 appears twice on the other die out of six possible outcomes) = (2/6) × (2/6) = 4/36
The total probability of rolling a sum of 6 is the sum of the probabilities of each possible pair:
1/18 + 4/36 + 4/36 = 1/6
Therefore, the probability of rolling a sum of 6 with these dice is 1/6.
3. (04.01 MC) The coordinates of point P on a coordinate grld are (-5, -6). Point P is reflected across the y-axls to obtain point Q and point P is reflected across the x-axis to obtain point R. What are the coordinates of points Q and R? (1 point) 05 61 and 5 61
The coordinates of point Q and point R are; (5, -6) and (-5, 6) respectively.
From the coordinates of point P as given to be;
(-5, -6).When the point P is reflected across the y axis to obtain point Q; the polarity of its x-ordinate changes;
In essence, the coordinate of point Q; (5, -6)When the point P is reflected across the x-axis to obtain point R; the polarity of its y-ordinate changes;
In essence, the coordinate of point R; (-5, 6)Read more on reflection of points;
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I NEED HELPP
1. Graph the numbers on the number line
1. Use <, > or = to compare
2. Graph the numbers on the number line
3. Use <, > or = to compare
4. Write in order from least to greatest
5. Write in order from greatest to least
Comparing the √17 and 29/7 using <, > or = , we have √17 < 29/7.
Define comparing.Mathematical number comparison is the process or method of comparing two numbers to determine whether one is less, bigger, or equal to the other. The comparison symbols for numbers are "=", which stands for "equal to," "=", which stands for "greater than," and " ", which stands for "less than." Comparing amounts is a technique for figuring out how much to compare units in relation to a different standard or reference unit. A common reference point is necessary for two comparing units to be compared; otherwise, they cannot be compared.
Given,
Comparing the following using <, > or = ,
Numbers:
√17 and 29/7
For √17
Simplifying,
√17 = 4.123
For 29/7
29/7 = 4.14
√17 < 29/7
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HELP PLEASE FAST!! Determine the perimeter of the right triangle shown. Round your final answer to the nearest whole number if necessary.
Answer:
26
Step-by-step explanation:
One leg measures 7.
One leg measures 8.
a² + b² = c²
7² + 8² = c²
c² = √113 = 10.630 = 11
perimeter = 7 + 8 + 11
perimeter = 26
Find the length of a circle inscribed in a rhombus if its side and angle are equal: 8 cm and 60 degrees. С=?
The length of the circle is approximately 9.237 cm.
What are the diagonals of a rhombus?
A rhombus is a quadrilateral with all sides of equal length. It also has the following properties regarding its diagonals:
The diagonals bisect each other at 90 degrees.
The diagonals are perpendicular to each other.
The diagonals have the same length.
The diagonals divide the rhombus into four congruent triangles.
In a rhombus with a side of 8 cm and an angle of 60 degrees, the diagonals are equal in length.
The length of the diagonals can be found using the formula:
\($D_1 = \frac{2a}{\sqrt{3}}$\)
where a is the length of the side. Substituting the value of a as 8 cm, we get:
\($D_1 = \frac{2(8)}{\sqrt{3}} \approx 9.237 \text{ cm}$\)
The length of the circle inscribed in the rhombus is equal to the length of the diagonals.
Therefore, the length of the circle is approximately 9.237 cm.
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Use a graphic calculator to determine the intervals on which (x)=2x^3-3x-1 is increasing or decreasing.
Please help me I don't understand this at all because when I graph it I get 8.5 but the real answer is 0.7
Answer:
im not sure of the answer but hopefully this will help
Step-by-step explanation:
basically the intervals in which its increasing and decreasing depend on the leading coefficient and the vertex
since this is opening up, the intervals will be
the function is increasing (x coord of vertex, infinity)
the function is decreasing (-infinity, x-coord of vertex)
a #6 Mrs. Cooper has a jar of
ey candies. She wants to split them
n into 25 equal groups. There are 30
candies in each group. Write an
equation that can be used to find
the total number of candies.
Answer:
25 * 30= x
x= total number of candies
The price paid forh
a $250 table after
a 30% discount is
applied
Answer: the answer is $175
Step-by-step explanation:
250*0.3 is 75
250-75 gives us 175
Compare the process of solving |x – 1| + 1 < 15 to that of solving |x – 1| + 1 > 15. Check all of the following you included in your response. Both absolute values would need to be isolated first. You would need to write a compound inequality for each. Both compound inequalities would compare x – 1 to –15 and 15. The inequality with “<” would use an “and” statement, while the “>” would use an “or” statement.
The required Comparison of the inequalities are
The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.The range of values encompassing the region's junction is (-13, 15).
If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.What is inequality?When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.Read more about inequalities
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Can someone help me please?
ASAP
Answer:
y = 12 x = 12\(\sqrt{3}\)
Step-by-step explanation:
This is a 60, 90, 30. It's a special triangle.
2z = 24
z = 12
If x = z\(\sqrt{3}\)
then x = 12\(\sqrt{3}\)
y = z itself
So y = 12
Right triangle ABC is on a coordinate plane. Segment AB is on the like y=2 and is 6 units long. Point C is on the line x=-3. What is the y-value of Point C if the area of ABC is 9 units squared
The y-coordinate value of Point C if the area of ABC is 9 units squared is: 5 or -1
How to find the coordinate of the segment?Point A is at (x, 2) and B is at (x + 6, 2). Since AB must lie on the line y=2 and be 6 units long. Point C is on the line x = -3 . So let C be at (-3, y).
Since ΔABC is a right angle, then point C must have the same x-coordinate as point A. Therefore, A(-3, 2) and B(2, 2).
The area of ΔABC is 9. So,
9 = 1/2 (b)(h)
where b is the base and h is the height.
so b = 6 and h = AC
Solving this for AC gives
9 = 1/2 (6)(AC)
18/6 = AC
3 = AC
Point C must lie 3 units above point A or 3 units below the point A. If it lies 3 units above, then it has a y-coordinate of 2 + 3 = 5.
If it lies 3 units below, it has a y-coordinate 2 - 3 = -1.
Therefore, y-coordinate is 5 or -1.
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solve this question
-4[xt3]=8
Answer:
Hello, The answer to your question is,
\(x=\) −\(\frac{2}{t^3}\)
hope this help :)
(correct me if i am wrong and im sorry)
Step-by-step explanation:
(x+1) (x-5)=16 formula cuadratica brainly
The calculated value of x in the equation (x + 1) (x - 5) = 16 is 7
From the question, we have the following parameters that can be used in our computation:
(x + 1) (x - 5) = 16
The above expression is the product of two factors
(x + 1) and (x - 5)
And the result is 16
Express 16 as 8 * 2
So, we have
(x + 1) (x - 5) = 8 * 2
By comparison, we have
x + 1 = 8 and x - 5 = 2
When evaluated, we have
x = 7 and x = 7
This means that the value of x in the equation is 7
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40% of 60 is what number?
Answer:
60×40%=24
Hope it helps!!!
if you take away 25 from a number you will be left with two and halftimes 30. what is the number?
Whats the answer to part b and above?
Answer:
4/5 would be at the 8th line, and 3/10 would be on the 3rd
Step-by-step explanation:
Determine if (2, 9) is a solution to the following system. y = 3x+3 y = x+9 a Yes b No
Answer:
B)no
Step-by-step explanation:
the correct solution is (3,12)
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*I DID THIS IRL*
I flipped 2 coins 100 times
both coins showed heads 24 times
both coins showed tails 44 times
both coins showed 1 head and 1 tail 32 times
PLS ANSWER THE QUESTIONS BELOW
1. What is the theoretical probability that a coin toss results in two heads showing?
2. What is the experimental probability that a coin toss results in two heads showing?
3. What is the theoretical probability that a coin toss results in two tails showing?
4. What is the experimental probability that a coin toss results in two tails showing?
5. What is the theoretical probability that a coin toss results in one head and one tail showing?
6. What is the experimental probability that a coin toss results in one head and one tail showing?
7. Compare the theoretical probabilities to your experimental probabilities. Why might there be a difference?
Answer:
The odds are 100 out of 200% for both to have heads.
The actual probility is 50%
Step-by-step explanation:
43.How's the economy? A poll conducted by the American Research Group asked individuals their views on how the economy will be a year from now. Respondents were given four choices: Better than today, Same as today, Worse than today, and Undecided. Are these choices nominal or ordinal?
It is nominal because they all mean the same thing
Jar A contains four liters of a solution that is 45% acid. Jar B contains five liters of a solution that is 48% acid. Jar C contains one liter of a solution that is k % acid. From jar C, 2/3 liters of the solution is added to jar A, and the remainder of the solution in jar C is added to jar B. At the end both jar A and jar B contain solutions that are 50% acid. Find k.
Answer:
k= 80%
Step-by-step explanation:
Jar A contains 4*0.45 L acid, and 4 L of a solution of acid.
Jar B contains 5*0.48 L acid., and 5 L of a solution of acid.
Jar C contains 1*k/100 = k/100 acid, and 1 L of a solution.
50% = 0.5
For jar A.
(2/3)*k/100 L acid is added to jar A.
Now jar A contains 4*0.45 L + (2/3)*k/100 L acid, and it has (4+2/3)L of a solution.
L solute/L solution = 0.5
[4*0.45 L + (2/3)*k/100 L]/(4+2/3)L = 0.5
[1.8 + (2k/300)]/[(12+2)/3] = 0.5
[1.8 + (2k/300)]/[14/3] = 0.5
[1.8 + (2k/300)]= 0.5*(14/3)
(2k/300) = 0.5*(14/3) - 1.8
2k = (0.5*(14/3) - 1.8)*300
k = (0.5*(14/3) - 1.8)*300/2 =80
k= 80%
We also can find k using jar B.
(1/3)k/100 L acid is added to jar B.
Now jar B contains 5*0.48 L+ (1/3)k/100 L acid, and it has (5+1/3) L of a solution.
L solute/L solution = 0.5
[5*0.48 L+ (1/3)k/100 L ]/(5+1/3)L= 0.5
[5*0.48 + (1/3)k/100 ]/(5+1/3)= 0.5
This equation also gives k=80%
Check.
We can check at least for jar A.
Jar A has 4L solution and 4*0.45=1.8 L acid.
2/3 L of the solution from jar C was added, and now we have 4 2/3 L of solution.
(2/3)* 80%= (2/3)*0.8 acid was added from jar C.
Now we have [1.8 +(2/3)*0.8] L acid in jar A.
L solute/L solution = [1.8 +(2/3)*0.8] L /(4 2/3) L = 0.5 or 50% as it is given that jar A has 50% at the end.
Which is the last operation when evaluating
subtraction [BODMAS 'S' comes last which means subtraction]
hope it helps...
Answer:
Subtraction
Step-by-step explanation:
at which points do the graphs of y= x+1 and y=2^2 intersection
The graphs of y = x + 1 and y = 2^x intersect at approximately (-0.3517, 0.6483) and (1.561, 3.561).
To find the points of intersection between the graphs of y = x + 1 and y = 2^x, we need to set the two equations equal to each other and solve for x.
Setting y = x + 1 equal to y = 2^x, we have:
x + 1 = 2^x
To solve this equation, we can use numerical methods or make observations to find the points of intersection. By observing the behavior of the two functions, we can see that they intersect at two points: one when x is negative, and another when x is positive.
For x < 0, the exponential function y = 2^x approaches 0 as x approaches negative infinity, while the linear function y = x + 1 continues to decrease as x becomes more negative. Thus, there is one point of intersection in this region.
For x > 0, the exponential function grows faster than the linear function, so there is another point of intersection in this region.
However, finding the exact values for the points of intersection requires numerical methods such as using a graphing calculator or solving the equation numerically. Approximate values for the points of intersection can be found as x ≈ -0.3517 and x ≈ 1.561.
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5) reflection across the x-axis
Answer:
t(2,-2),C(2,-5),z(5,-4),f(5,0)
Step-by-step explanation:
because it reflects across the x-axis the y changes to the opposite.
Explain why the equation 82.5 + 8(0.25x)= 338.5 is equivalent to the equation 82.5 + 2x = 338.5
Step-by-step explanation:
because 0.25 = 1/4.
so, it is actually
82.5 + 8×(1/4)x = 338.5
which is then simplified
82.5 + (8/4)x = 338.5
82.5 + 2x = 338.5
Step-by-step explanation:
\(\displaystyle\\8(0.25x)=8(\frac{25}{10}x)=\frac{8*25}{100} x=\frac{200}{100}x=2x\)
Thus, 82.5+8(0.25x)=338.5 ≡ 82.5+2x=338.5
Solve
-16+ 20
A. -36
B.-4
C. 4
D. 36
Answer:
C: 4
Step-by-step explanation:
We can rearrange the numbers:
\(-16+20=+20-16=20-16=4\)
Answer:
C. 4
Step-by-step explanation:
-16+20 equals 4 becase:
-16 is under zero, and if we add 20 to that, it will take 16 of that 20 to fill up the negative part, and the rest part remaining will be 4. So that four will add up to be the positive number!
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Sorting algorithms no unread replies.no replies. we are using and interacting with sorting algorithms in every day life. in your chapter reading this week, you reviewed many sorting algorithms. find an example of a place in real, everyday life where you interact with, implement or use one of the sorting algorithms covered in chapter 3. for example, while playing cards you may have found yourself implementing the insertion sort algorithm (without knowing it). for this peer interaction, post your example of a place in real, everyday life where you interact with, implement or use one of the sorting algorithms. be sure to provide your us with enough information so that we will thoroughly understand your example and use of a sorting algorithm. once you have made your post, please respond to at least two of your classmates interacting and communicating on the sorting algorithm use in real world context.
A sorting algorithm is defined as an algorithm that sorts the elements of a list. The most commonly used sequences are numerical sequence and lexicographical sequence, ascending or descending.
A sorting algorithm is used to reorder an array or list of elements according to an element comparison operator. Comparison operators are used to define a new order of elements in that data structure. Consider example, The above list of characters is sorted in ascending order by their value. That is, characters with lower values are placed before characters with higher values. It is important in real life because it supports the development of the scientific concept that things can be owned and organized into distinct groups (e.g. creatures, cars, weather types, etc.). We will now discuss some real-world examples of using sorting algorithms.
1) Your phone's contact list is sorted. This means that your data is organized in this way so you can easily access the contacts you want from your phone. That is, "I ordered."
2) Paper sorting : Imagine a teacher sorting students' work alphabetically by student name. This type of operation is similar to the functionality of sorting algorithms such as bucket sort. Sorting is more efficient process.
3) Traffic lights : Traffic lights are a good example of how algorithms are used in the real world around us. Next time you get stuck in a car at a red light, think about the algorithm that traffic lights run." Most traffic lights don't automatically switch between green, yellow, and red. This algorithm is a well-established turn-by-turn algorithm that directs traffic correctly. It's in order (it may not seem that way when you're sitting at a red light).
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A shoe manufacturer spends $2.50 to make sandals and $4 to make running shoes. During a typical month, they spend $2500 manufacturing sandals and running shoes. During the month of April, they double the pairs of sandals manufactured and spend a total of $3000.
How many pairs of sandals and running shoes does the company make during a typical month?
Step-by-step explanation:
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Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 10 people took the trip. She was able to purchase coach tickets for $160 and first class tickets for $1,120. She used her total budget for airfare for the trip, which was $3,520. How many first class tickets did she buy? How many coach tickets did she buy?
Answer:
c + f = 5
120c + 1140f = 2640
f = 5 - c
120c + 1140(5 - c) = 2640
120c + 5700 - 1140c = 2640
1020c = 3060
c = 3 coach tickets
Step-by-step explanation: