Answer:
If a body does 1j work in 1 sec time then the power of that body is called 1watt power
Explanation:
1 watt power can be defined as the rate of doing 1 joule work in one second time.
4. A 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a
level frictionless surface. Calculate the power output.
The power output of 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a level frictionless surface is 24.09 watts.
What is power?In science, power is the time required to do work or provide energy, expressed as work done W or energy transferred divided by the time interval t - or W/t. A fixed amount of work can be done for a long time with a low-powered engine, or for a short time with a high-powered engine. The unit of power is work (or energy) per unit of time. Such as foot pounds per minute, joules (or watts) per second, and ergs per second. Force can also be expressed as the product of the force required to move an object and the object's velocity in the direction of the force. If the magnitude of the force F is measured in pounds and the velocity ν is measured in feet per minute, then the power is equal to Fν foot pounds per minute.
Given,
Mass of object (m) = 2.00 kg
Distance covered (s) = 1.5 m
Velocity of object (v) = 3.00 m/s
For calculation of acceleration:
v² = u² + 2as
3² = 0 + 2 × a × 1.5
9 = 3a
a = 2 m/s²
For calculation of time:
s = ut + ¹/₂at²
1.5 = 0 × t + ¹/₂ × 2 × t²
1.5 = t²
t = 1.22 sec.
For calculation of gravitational force:
F = mg
F = 2 × 9.8
F = 19.6 N
For calculation of work done:
W = F × s
W = 19.6 × 1.5
W = 29.4 J
For calculation of power output:
P = W/t
P = 29.4/1.22
P = 24.09 watts
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what is centripetal motion
Answer:
abhi ham logo KO madam ne Padaya nahi hai
1. if the work done to move a box to a distance of 6 metres equals 120 joules. calculate the force
2. Calculate the potential energy of a book with a mass of 1.5 kg placed on top of a shelf with a height of 2 m.
(Knowing that the acceleration due to gravity = 10 m/s2
).
3. What is meant by?
The potential energy of an object = 20 joules.
Explanation:
1. W = F x D
F = W/D
F = 120/6 = 20Newton
2. P. E = mgh
P. E = 1.5x10x2 = 30Joules
3. It means that the energy the body possesses at that point is 20Joules
What is equilibrium?
Answer: Equilibrium is the state in which market supply and demand balance each other, and as a result prices become stable. The balancing effect of supply and demand results in a state of equilibrium.
This is the answer please ap mujhe follow kar lo please
A particular roller coaster has a mass of 3500 kg, a height of 4.0, and a velocity of 12m/s. What is the potential energy? If needed, use g=10.m/s^2
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
Gravitational Potential Energy of an object is calculated by formula ~
\( \large\boxed{\sf P = mgh}\)
where,
m = mass of the object = 3500 kgg = Acceleration due to gravity = 12 m/s²h = height attained by the object = 4 mNow, let's calculate its potential energy ~
\(3500 \times 10 \times 4\)\(140000 \: \: joules\)\(140 \: \: kj\)Answer:
Potential Energy of an object is calculated by formula:
Potential Energy (P.E)=m×g×hWhere,
m=mass of bodyg=acceleration due to gravityh=height from the earth surfaceNow, let's solve the question.
Given,
mass(m)=3500 kgheight (h)=4mvelocity (v)=10m/s²Now,
We know that,
Potential Energy (P.E)=mgh
\( = 3500 \times 10 \times 4\)
\( = 3500 0\times 4\)
\( =140000 joules \)
\(\mathfrak{\blue{DisneyPrincess29}}\)
A kid pushes a stationary
merry-go-round, creating an
acceleration of 0.135 rad/s^2.
How much time does it take the
merry-go-round to complete
2.00 rotations?
(Unit = s)
Remember: CCW is +, CW is. 1 rev= 2*pi rad
The merry-go-round takes approximately 29.41 seconds to complete 2.00 rotations.
Given data:
Acceleration (α) = 0.135 rad/\(s^2\)
Number of rotations (θ) = 2.00
To find the time taken (t) for 2.00 rotations, we need to use the formula:
θ = 0.5 * α * \(t^2\)
Rearranging the formula, we get:
\(t^2\) = (2 * θ) / α
Plugging in the given values, we have:
\(t^2\) = (2 * 2.00) / 0.135
\(t^2\) = 29.63
Taking the square root of both sides, we find:
t ≈ √29.63
t ≈ 5.439
Therefore, the time taken for the merry-go-round to complete 2.00 rotations is approximately 5.439 seconds.
Note: It's important to round the final answer to an appropriate number of significant figures, considering the given data. In this case, we have used four significant figures in the final answer.
However, if we want to adhere to the given significant figures in the acceleration (0.135 rad/\(s^2\)), the answer should be rounded to three significant figures. In that case, the final answer would be approximately 5.44 seconds.
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the abnormal backward flow of gi contents into the esophagus is called
The abnormal backward flow of gastrointestinal (GI) contents into the esophagus is known as gastroesophageal reflux (GERD) or acid reflux. It occurs when the lower esophageal sphincter fails to close properly, leading to symptoms such as heartburn and regurgitation.
Gastroesophageal reflux, commonly referred to as GERD or acid reflux, is a condition characterized by the abnormal backward flow of GI contents into the esophagus. The esophagus is a muscular tube that connects the throat to the stomach. Normally, a circular muscle called the lower esophageal sphincter (LES) acts as a barrier, preventing the contents of the stomach from moving back into the esophagus. However, when the LES weakens or relaxes inappropriately, it allows stomach acid, digestive enzymes, and partially digested food to flow back up into the esophagus.
This backward flow of stomach contents can cause various symptoms, including heartburn, which is a burning sensation in the chest or throat. Regurgitation, where partially digested food or acid backs up into the mouth or throat, is another common symptom. Other possible symptoms of GERD include chest pain, difficulty swallowing, hoarseness, chronic cough, and a sour taste in the mouth.
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I need help asap :>
Answer:
\(\huge\boxed{\sf v = 0.75\ m / s}\)
Explanation:
Given Data:
Wavelength = λ = 0.25 m
Frequency = f = 3 Hz
Required:
Speed = v = ?
Formula:
v = fλ
Solution:
v = (3)(0.25)
v = 0.75 m / sec
\(\rule[225]{225}{2}\)
Hope this helped!
~AH1807Which is a property of every heterogeneous mixture?
a.the mixture is made up of at least two different states.
b.the mixture is made up of something dissolved in a liquid.
c.the composition of the mixture is the same throughout.
d.the characteristics of the mixture change within a sample.
hana fills a cup with sandy ocean water. she pours the mixture through a filter. what does she collect that passes through the filter?
a.a sample of pure water
b.a solution of salt in water
c.a suspension of sand in water
d.a colloid of salt in water
which describe colloids? check all that apply.
1.heterogeneous mixtures
2.homogeneous mixtures
3.may have a uniform appearance
4.are made up of at least two substances
5.will settle out over time
when mixed, which states of matter form only a homogeneous mixture?
a.two liquids
b.two gases
c.a solid and
Answer: C for all of them
Explanation:
Because I'm smart
Jk
So basically its beacuse all of them have the same mixture since science can be interrelated and interchangebale in terms of formulas ok bye now
Thanks
Hope this helped you
Or not
Sorry if it didn't ig
a shopper pushes a 50-kg grocery cart 20.0 m on level ground, against a 35.0 n frictional force. he pushes in a direction 40 degrees below the horizontal. what is the work done on the cart by friction?
Work done on the cart by friction can be calculated by multiplying the magnitude of the frictional force by the displacement of the cart. In this case, the work done by friction is -700 J.
The work done by a force is given by the equation:
Work = Force * Displacement * cos(θ)
where Force is the magnitude of the force, Displacement is the magnitude of the displacement, and θ is the angle between the force and the displacement.
In this scenario, the frictional force is 35.0 N and the displacement of the cart is 20.0 m. The angle between the force and displacement is 40 degrees below the horizontal, which means the angle is -40 degrees.
To calculate the work done by friction, we substitute the given values into the equation:
Work = 35.0 N * 20.0 m * cos(-40°)
Using the cosine function with the negative angle, we find that cos(-40°) is equal to cos(40°).
Work = 35.0 N * 20.0 m * cos(40°)
Calculating this expression, we determine that the work done on the cart by friction is approximately -700 J.
Therefore, the work done on the cart by friction is -700 J, indicating that the frictional force acts in the opposite direction of the displacement, resulting in negative work.
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What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000N b. 20880N c. 2500N d. 3500N
Given values are:
Mass, m = 52 kgVelocity, v = 8.0 m/sRadius, r = 1.6 mAs we know the formula,
→ \(\Sigma f = ma\)
or,
→ \(\Sigma f = \frac{mv^2}{r}\)
By putting the values, we get
\(= \frac{52\times 8^2}{1.6}\)
\(= \frac{52\times 64}{1.6}\)
\(= 2080 \ N\)
Thus the response above is appropriate.
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A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s
Answer: Velocity = v = 35 m/s
Explanation:
Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.
Mathematically,
v = 35 m/s
A block of aluminium has a volume of 5.0 cm³ and a mass of 13.5 g. Calculate the density of the aluminium. Give your answer in g/cm³.
Explanation:
Soln:-
Given:-
Volume(v)=5.0cm^3
mass(m)=13.5 gm
density (d)=?
We know that,
d=m÷v
=(13.5÷5)g/cm^3
=2.7g/cm^3
Hence, the required density of aluminum is 2.7g/cm^3.
4. Calculate the momentum for each scenario:
a. .02 kg mass moving at 300 m/s
b. 2 kg mass moving at 40 m/s
c. 200 kg mass moving at 4 m/s
a) Answer:
Momentum = 6 kgm/s
Explanation:
Momentum = mass × velocity
Given that,
mass = 0.02 kg velocity = 300 m/s
Therefore, momentum = (0.02 × 300)kgm/s
Momentum = 6 kgm/s
b) Answer:
Momentum =80 kgm/s
Explanation:
Momentum = mass × velocity
Given that,
mass = 2 kg velocity = 40 m/s
Therefore, momentum = (40 × 2)kgm/s
Momentum = 80 kgm/s
c) Answer:
Momentum = 800 kgm/s
Explanation:
Momentum = mass × velocity
Given that,
mass = 200 kg velocity = 4 m/s
Therefore, momentum = (200 × 4)kgm/s
Momentum =800 kgm/s
a baseball weighs 1.5 n on earth. another type of ball weighs 1.5 n on the moon. the ball with the greater mass is the other type of ball. same for each. baseball. not enough information
moon has a weaker gravitational force than Earth, a greater mass is required for the other ball to have the same weight of 1.5 N on the moon.
Based on the information given, we cannot determine which ball has a greater mass. Weight is affected by both mass and gravity, so a baseball may weigh the same as a different type of ball on the moon due to the weaker gravitational pull.
Therefore, we need additional information about the mass of each ball to compare them accurately.
Based on the information provided, the other type of ball has a greater mass. This is because it weighs 1.5 N on the moon, while the baseball weighs 1.5 N on Earth. Since the moon has a weaker gravitational force than Earth, a greater mass is required for the other ball to have the same weight of 1.5 N on the moon.
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PLZ HELP ME
1. A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How far from the cliff does the stone strike the ground?
2. A ball rolls off the edge of a table 1.44m above the floor and strikes the floor at a point 2m horizontally from the edge of the table.
A) What is the time the ball was in the air?
B) What is the initial velocity of the ball?
3. A golfer hits a ball and gives it an initial velocity of 40 m/s, at an angle of 30º above the horizontal.
A) How long does the ball stay in the air?
B) How far horizontally (the range) does the ball travel before hitting the ground?
Answer:
1. The stone will strike the ground 49.46 m from the base of the cliff
2. A) Approximately 0.542 seconds
B) Approximately 3.69 m/s
3. A) The time the ball spends in the air is approximately 4.0775 s
B) The horizontal range is approximately 141.25 m.
Explanation:
1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)
∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds
The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m
The stone will strike the ground 49.46 m from the base of the cliff
2. A) The time the ball spends in the air = t = √(h/(1/2 × g)
∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds
B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s
The initial horizontal velocity ≈ 3.69 m/s
3. A) The time the ball spends in the air is given by the following equation;
t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s
t ≈ 4.0775 s
B) The horizontal range, R, of the ball is given by the equation for the range of a projectile as follows;
\(Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}\)
Substituting the known values, gives;
\(Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m\)
The horizontal range ≈ 141.25 m.
how do we learn about objects of interest to intelligence through matter/energy interaction: emission, reflection, refraction, and absorption
By studying the emission, reflection, refraction, and absorption of energy from objects, scientists can gather valuable information about their properties, composition, and behavior.
We can learn about objects of interest through matter/energy interaction using various processes such as emission, reflection, refraction, and absorption. Here's how each process provides information:
1. Emission: Objects can emit energy in the form of light or other electromagnetic radiation. By studying the emitted radiation, we can gather information about the object's composition, temperature, and other properties. For example, analyzing the emission spectra of stars helps us determine their chemical composition.
2. Reflection: When light or other forms of energy strike an object, they can bounce off or reflect from its surface. By analyzing the reflected energy, we can gather information about the object's appearance, surface properties, and color. For instance, studying the reflection of radar signals can provide information about the shape and structure of distant objects like planets or asteroids.
3. Refraction: Refraction occurs when energy, such as light, passes through a medium and changes direction. By observing how light bends or changes its path while passing through an object, we can learn about its optical properties and the medium it interacts with. Refraction is utilized in techniques like spectroscopy to analyze the composition of materials.
Absorption: When energy interacts with an object, it can be absorbed by the object's atoms or molecules. The absorption spectrum of an object provides information about the specific wavelengths of energy it absorbs. This allows us to identify the presence of certain elements or compounds. Absorption spectroscopy is commonly used in chemistry, astronomy, and other scientific fields to identify substances based on their unique absorption patterns.
By studying the emission, reflection, refraction, and absorption of energy from objects, scientists can gather valuable information about their properties, composition, and behavior. These techniques are widely used across various scientific disciplines, including astronomy, chemistry, remote sensing, and materials science.
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A quantum particle in an infinitely deep square well has a wave function given byψ₂(x) = √2/L sin ( 2πx/ L) for 0 ≤ x ≤ L and zero otherwise.(d) Argue that the result of part (a) does not contradict the results of parts (b) and (c).
The result of part (a) does not contradict the results of parts (b) and (c) because they provide different information about the quantum particle in the infinitely deep square well. The energy levels are quantized and determined by the wave function, while the probability density and expectation value of the position are determined by the specific form of the wave function.
In order to argue that the result of part (a) does not contradict the results of parts (b) and (c), we need to consider the given wave function ψ₂(x) = √2/L sin(2πx/L) for 0 ≤ x ≤ L and zero otherwise.
(a) In part (a), the result is that the energy of the particle in the square well is quantized, meaning it can only have certain discrete energy levels. This is determined by the equation E = (n²π²ħ²)/(2mL²), where n is the quantum number, ħ is the reduced Planck's constant, m is the mass of the particle, and L is the length of the well.
(b) In part (b), the result is that the probability density |ψ(x)|² represents the likelihood of finding the particle at a particular position x. In this case, the probability density is given by |ψ₂(x)|² = (2/L) sin²(2πx/L) for 0 ≤ x ≤ L and zero otherwise. The probability density is highest at the antinodes of the sine function and lowest at the nodes.
(c) In part (c), the result is that the expectation value of the position is determined by the integral ∫x|ψ(x)|² dx over the range of 0 to L. For the given wave function ψ₂(x), the calculation of leads to a value of L/2, which is the midpoint of the well.
Now, to argue that the result of part (a) does not contradict the results of parts (b) and (c), we need to consider the relationship between the energy levels, probability density, and expectation value of the position.
The wave function ψ₂(x) is a standing wave pattern with nodes and antinodes. The nodes represent points where the probability density is zero, indicating that the particle is unlikely to be found at those positions. The antinodes, on the other hand, represent points where the probability density is highest, indicating a higher likelihood of finding the particle at those positions.
The energy levels of the particle in the square well are determined by the wave function, and each energy level corresponds to a specific standing wave pattern. The different energy levels have different numbers of nodes and antinodes, leading to different probabilities of finding the particle at different positions within the well.
So, while the energy levels are quantized and determined by the wave function in part (a), the probability density and expectation value of the position are determined by the specific form of the wave function in parts (b) and (c). These quantities provide information about the likelihood of finding the particle at different positions within the well, and they do not contradict the quantization of energy levels.
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In Part C, how would the effects differ if you connected the galvanometer to the primary coil and the battery/switch to the secondary
N₂ / N₁ = 13.3
A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is
ΔV₂ = N₂ /N₁ ΔV₁
where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.
They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.
ΔV₂ /ΔV₁ = N₂ / N₁
N₂ / N₁ = 120/9
N₂ / N₁ = 13.3
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A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?
A scientist wants to learn about Earth's oceans. Which of the following
spheres should she most directly study? (2 points)
Oa
Atmosphere
Ob
Cryosphere
Oc
Geosphere
Od
Hydrosphere
When thermal energy is removed from particles, what action occurs?
A The particles' energy is destroyed.
B The particles' temperature increases.
C The particles move more quickly.
D The particles' kinetic energy decreases.
When thermal energy is removed from particles, then the particles' kinetic energy decreases (Option D).
What is particles' kinetic energy?The expression particles' kinetic energy makes reference to the amount of motion energy (i.e. energy in movement) that contain the particles of an object, which depends on the temperature of the material.
In conclusion, when thermal energy is removed from particles, then the particles' kinetic energy decreases (Option D).
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A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through the wire, it heats up and melts ice and snow on the window. For one window the wire has a total length of 11.0 mm, a width of 1.8 mmmm, and a thickness of 0.11 mmmm. The wire is connected to the car's 12.0 VV battery and draws 7.5 AA.
2.6×10\(^-8\) Ωm,A long, flat wire is used as a rear window defroster and is bonded to the window's interior surface.
Resistivity of the wire ?Electrical resistivity is a measurement of a material's degree of resistance to current flow. The SI unit for electrical resistivity is the ohm meter (m). It is frequently represented by the Greek letter rho. Materials that easily transmit current and have a low resistance are called conductors.
Length of the wire, l = 12.2 m
width of the wire, w = 1.8 mm
Thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12 V
Current in battery, I = 7.5 A
Ohms law says, V = IR.
So that, R = V/I
R = 12/7.5 = 1.6 Ω
The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length.
Resistivity if a material is:
ρ = RA/l
ρ = [1.6 × 1.8 × 10\(^-3\) × 0.11×10\(^-3\)] / 12.2
ρ = (3.168×10\(^-7\)) / 12.2
ρ = 2.596×10\(^-8\)
Therefore, the resistivity of the wire is 2.60×10\(^-8\) Ωm
Resistivity of the wire is 2.60*10^-8 Ωm
Given:
Length of the wire, I = 12.2 m
width of the wire, w = 1.8 mm
thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12
Current in the battery, I = 7.5 A
To Find:
Resistivity
Solution: A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents.
Remember, Ohms law says, V = IR
So that, RV/I
R = 12/7.5= 1.6 Q
Resistivity if a material is
p = RA/I
p = [1.6 * 1.8*10^-3* 0.11*10^-3] / 12.2
p = (3.168*10^-7)/12.2
p = 2.596*10^-8
Therefore, the resistivity of the wire is 2.60*10^-8 Ωm
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___ electrification occurs any time two objects with different levels of charge make physical contact.
Contact electrification occurs any time two objects with different levels of charge make physical contact.
Contact electrification is a word that describes a phenomenon wherein surfaces end up electrically charged, thru a number of viable mechanisms, while or greater objects come within near proximity of one another.
Static electricity is created while effective and bad costs aren't balanced. Protons and neutrons do not circulate around tons, however electrons love to jump all around the place. Whilst an item has greater electrons, it has a poor price.
Static electricity is an imbalance of electrical costs with in or at the surface of a material. The rate stays till it could pass away by an electric powered current or electric discharge.
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To what does the amplitude of a sound refer to?
Answer:
The number of molecules displaced by a vibration creates the amplitude of a sound. The strength or level of sound pressure. The number of molecules in the sound wave in b is greater than the number in the sound wave in a, therefore the amplitude of the sound wave in b is greater.
Explanation:
How can we apply our knowledge of motion in one dimension to describe motion in two or more dimensions? In other words, how can we break down two-dimensional motion so that we can apply our existing knowledge of how to describe one-dimensional motion? 2. What kind of motion do objects have in the horizontal direction (i.e. what is the acceleration)? What kind of motion do objects have in the vertical direction (i.e. what is the acceleration)? 3. In many problems the given initial velocity is at an angle between the horizontal and the vertical. How do we determine the initial velocity to put into the vertical and horizontal descriptions?
The method we use to represent the motion of an object in more than one direction is called vector addition.
To explain how objects move in more than one direction, it is essential to break down the motion into several one-dimensional motions.
The method we use to represent the motion of an object in more than one direction is called vector addition. The technique involves describing a two-dimensional motion using two one-dimensional descriptions.
Horizontal motion has constant velocity (no acceleration). The acceleration due to gravity is the only factor affecting vertical motion, which is the free-fall acceleration. It's the same for all objects on Earth: 9.81 m/s².
In such cases, it is crucial to calculate the initial velocity's vertical and horizontal components separately. The initial velocity's vertical and horizontal components are determined using the sine and cosine functions, respectively.
To separate the vertical and horizontal motions, we multiply the time by each of these velocities.
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how many types of classifications are there for a lunar eclipse?
There are three types of lunar eclipses: total, partial, and penumbral.
During a total lunar eclipse, the moon is completely shadowed by the Earth, resulting in a reddish-brown color. In a partial lunar eclipse, only a portion of the moon is shadowed, while in a penumbral lunar eclipse, the moon passes through the Earth's outer shadow, resulting in a subtle darkening of the moon's surface. These classifications are based on the degree to which the moon passes through the Earth's shadow during the eclipse.
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What is the weight of an object on the earth with a mass of 70 kg.
(g= 10 m/s2)
Answer:
700N
Explanation:
mass= 70kg
g=10m/s²
weight=mg
=70×10
=700N
a student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.
The catch in this one is: We don't know how much force the student used to push the bike.
It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.
Anyway, can we figure out how much force the student used to push with ? Stay tuned:
-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.
-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.
-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²
-- The bike's weight is 100N.
(mass) x (gravity) = 100N
Bikemass = (100N) / (9.8 m/s²)
Bikemass = 10.2 kilograms
-- F = m A
Force = (mass) x (acceleration)
Force = (10.2 kg) x (1.2 m/s²)
Force = 12.24 N
-- Work = (force) x (distance)
Work = (12.24 N) x (15 m)
Work = 183.67 Joules
-- Power = (work done) / (time to do the work)
Power = (183.67 joules) / (5 seconds)
Power = 36.73 watts
1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on
The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.
In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.
No atoms gain or lose electrons in this process.
In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.
This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.
A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.
These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.
It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.
Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.
Therefore, statement B, which suggests that each atom gains one electron, is false.
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A bus wheel has a diameter of 0.80 m and an angular velocity of 20 rad/s. What is the linear velocity of the wheel?
The linear velocity of the wheel is 16 m/s.
What is linear velocity?Linear velocity is the rate of change of displacement with regard to time when the object is moving in a straight line
To calculate the linear velocity of the wheel, we use the formula below.
Formula:
v = ωr............. Equation 1Where:
v = Linear velocityω = Angular velocityr = Radius of the wheel.From the question,
Given:
ω = 20 rad/sr = 0.80 mSubstitute these values into equation 1
v = 20(0.8)v = 16 m/s.Hence, The linear velocity of the wheel is 16 m/s.
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