Answer:
Kinetic energy can be used to develop electric energy which can be used as electricity.
Explanation:
The kinetic energy can be harnessed; much like some hydro power technologies harness water movement. A way to convert this kinetic energy into electric energy is through piezoelectric. By applying a mechanical stress to a piezoelectric crystal or material an electric current will be created and can be harvested.
Kinetic energy is also generated by the human body when it is in motion. Studies have also been done using kinetic energy and then converting it to other types of energy, which is then used to power everything from flashlights to radios and more.
A commercial aircraft is in steady flight. The overall lift to drag coefficient is 25. The other flight data are: (i)Weight of aircraft (including crew and passengers) = 70,000 kg (ii) Flight speed 400 km/hr (iii) Average wing span = 50 m (iv) Average wing chord = 7 m When in operation 20% of fuel power is lost. Find the power required for this steady flight. (5M)
Explanation:
weight of aircraft including crew and passengers is equal to 70000 kg therefore option is a thecorrect answer
Another name for a load-center distribution system is a A. primary radial system. B. complex radial system. C. split-radial system. D. dual-radial system.
Answer:
A
Explanation:
Primary radial system
Determine the initial void ratio, the relative density and the unit weight (in pounds per cubic foot) of the specimens for each sand.
The initial void ratio is the parameter which is used to show the structural foundations for each specimen of sand so that the method and speed of compression would be measured.
Relative density is the mass per unit volume of each specimen of sand which is measured and it has to do with the relative ratio of the density of the sand.
Unit weight is the the exact weight per cubic foot of the sand which is measured.
Please note that your question is incomplete so I gave you a general overview to help you better understand the concept
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1. A thin-walled cylindrical pressure vessel is capped at the end and is subjected to an internal pressure (p). The inside diameter of the vessel is 6 ft and the wall thickness is 1.5 inch. The vessel is made of steel with tensile yield strength and compressive yield strength of 36 ksi. Determine the internal pressure required to initiate yielding according to (a) The maximum-shear-stress theory of failure, and (b) The maximum-distortion-energy theory of failure, if a factor of safety (FS) of 1.5 is desired.
The force that keeps you from sliding on an icy
sidewalk is
Select one:
kinetic friction
normal force
weight
static friction
The force that keeps you from sliding on an icy sidewalk is static friction. Thus the correct option is D.
What is static friction?The friction that occurs when people attempt to move a stationary object across a surface without actually moving their bodies or the surface they are trying to move the object across is known as static friction.
Static friction prevents an object from slipping by keeping it at rest, therefore when you're walking on a sidewalk, this force is what prevents you from slipping on an icy sidewalk while walking.
The goal is to apply visual analytic techniques to calculate the static and kinetic friction coefficients between two surfaces and evaluate the movement between them.
Therefore, option D static friction is appropriate.
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The three bars are made of A-36 steel and form a pin-connected truss. If the truss is constructed whenT1=50∘F, determine the vertical displacement of jointAwhenT2=150∘F. Each bar has a cross-sectional area of 2 in2
To determine the vertical displacement of joint A, we can use the formula for thermal expansion:
ΔL = αLΔT
where ΔL is the change in length of the bar, α is the coefficient of thermal expansion, L is the original length of the bar, and ΔT is the change in temperature.
Assuming that the bars are initially at room temperature (T1=50∘F), we can calculate the original length of each bar using the formula:
L = √(h^2 + w^2)
where h and w are the height and width of the truss, respectively. From the diagram, we can see that h = 20 ft and w = 30 ft, so:
L = √(20^2 + 30^2) = 36.06 ft
Next, we can calculate the change in temperature as:
ΔT = T2 - T1 = 150 - 50 = 100 °F
The coefficient of thermal expansion for steel is α = 6.5 × 10^-6 in/in/°F. We need to convert the length of each bar from feet to inches, so:
L = 36.06 ft × 12 in/ft = 432.72 in
Using the formula for ΔL, we can calculate the change in length of each bar:
ΔL = αLΔT = (6.5 × 10^-6 in/in/°F) × (432.72 in) × (100 °F) = 0.2814 in
Since joint A is the midpoint of the bottom chord, it is supported by two bars. The total change in length of the bars supporting joint A is therefore:
ΔLtotal = 2 × ΔL = 2 × 0.2814 in = 0.5628 in
Since the bars are in tension, their elongation will cause joint A to move downward by an equal amount. Therefore, the vertical displacement of joint A is:
Δy = -ΔLtotal = -0.5628 in
So the answer is that joint A will move downward by 0.5628 inches when the temperature changes from 50°F to 150°F.
A 75-hp, 850 r/min, 500-V series motor has an efficiency of 90.2 percent
when operating at rated conditions. The series field has 30 turns/pole, and
the motor parameters are:
Armature
0.1414 ohms
IP + CW
0.0412 ohms
Series
0.0189 ohms
Resistance,
The motor has a maximum safe speed of 1700 r/min. Is it safe to operate the
motor with a 10-hp shaft load? Use the magnetization curve in Figure
11.16, and show all work. Neglect changes in windage and friction
It is not safe to operate the motor with a 10-hp shaft load.
Explanation :
Solution-
First, determine the rated speed and current of the motor:
Rated speed = 850 r/min
Rated current = 500 V / (0.1414 ohms + 0.0412 ohms + 0.0189 ohms) = 30.22 A
Next, determine the speed and current for a 10-hp shaft load:
Speed = 1700 r/min
Current = 10 hp / (75 hp * 0.902) = 0.1343 A
Finally, determine whether it is safe to operate the motor with the 10-hp shaft load using the magnetization curve. we can see that the current at 1700 r/min is 0.1264 A, which is less than the current for the 10-hp shaft load (0.1343 A).
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In a previous assignment, you created a set class which could store numbers. This class, called ArrayNumSet, implemented the NumSet interface. In this project, you will implement the NumSet interface for a hash-table based set class, called HashNumSet. Your HashNumSet class, as it implements NumSet, will be generic, and able to store objects of type Number or any child type of Number (such as Integer, Double, etc).
Notice that the NumSet interface is missing a declaration for the get method. This method is typically used for lists, and made sense in the context of our ArrayNumSet implementation. Here though, because we are hashing elements to get array indices, having a method take an array index as a parameter is not intuitive. Indeed, Java's Set interface does not have it, so it's been removed here as well.
The hash table for your set implementation will be a primitive array, and you will use the chaining method to resolve collisions. Each chain will be represented as a linked list, and the node class, ListNode, is given for you. Any additional methods you need to work with objects of ListNode you need to implement in your HashNumSet class.
You'll need to write a hash function which computes the index in an array which an element can go / be looked up from. One way to do this is to create a private method in your HashNumSet class called hash like so:
private int hash(Number element)
This method will compute an index in the array corresponding to the given element. When we say we are going to 'hash an element', we mean computing the index in the array where that element belongs. Use the element's hash code and the length of the array in which you want to compute the index from. You must use the modulo operator (%).
The hash method declaration given above takes a single parameter, the element, as a Number instead of E (the generic type parameter defined in NumSet). This is done to avoid any casting to E, for example if the element being passed to the method is retrieved from the array.
When the number of elements in your array (total elements among all linked lists) becomes greater than 75% of the capacity, resize the array by doubling it. This is called a load factor, and here we will define it as num_elements / capacity, in which num_elements is the current number of elements in your array (what size() returns), and capacity is the current length of your array (what capacity() returns).
Whenever you resize your array, you need to rehash all the elements currently in your set. This is required as your hash function is dependent on the size of the array, and increasing its size will affect which indices in the array your elements hash to. Hint: when you copy your elements to the new array of 2X size, hash each element during the copy so you will know which index to put each one.
Be sure to resize your array as soon as the load factor becomes greater than 75%. This means you should probably check your load factor immediately after adding an element.
Do not use any built-in array copy methods from Java.
Your HashNumSet constructor will take a single argument for the initial capacity of the array. You will take this capacity value and use it to create an array in which the size (length) is the capacity. Then when you need to resize the array (ie, create a new one to replace the old one), the size of the new array will be double the size of the old one.
null values are not supported, and a NullPointerException should be thrown whenever a null element is passed into add/contains/remove methods.
Example input / output
Your program is really a class, HashNumSet, which will be instantiated once per test case and various methods called to check how your program is performing. For example, suppose your HashNumSet class is instantiated as an object called numSet holding type Integer and with initialCapacity = 2:
NumSet numSet = new HashNumSet<>(2);
Three integers are added to your set:
numSet.add(5);
numSet.add(3);
numSet.add(7);
Then your size() method is called:
numSet.size();
It should return 3, the number of elements in the set. Your capacity() method is called:
numSet.capacity();
It should return 4, the length of the primitive array. Now add another element:
numSet.add(12);
Now if you call numSet.size() and numSet.capacity(), you should get 4 and 8 returned, respectively. Finally, lets remove an element:
numSet.remove(3);
Now if you call numSet.size() and numSet.capacity(), you should get 3 and 8 returned, respectively. The test cases each have a description of what each one will be testing.
An example of the implementation of the HashNumSet class that satisfies the requirements above is given in the image below.
What is the class?By implementing the NumSet interface, the HashNumSet class can utilize the size(), capacity(), add(E element), remove(E element), and contains(E element) methods.
Within the HashNumSet class, there exists a ListNode nested class that delineates a linked list node utilized for chaining any collisions occurring within the hash table. Every ListNode comprises of the element (data) and a pointer to the sequential node in the series.
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Para un intercambiador de calor encargado de precalentar pulpa de fruta, se utiliza agua caliente que entra a 180°C y sale a 78°C, mientras que la pulpa de fruta entra a 3°C y sube su temperatura hasta 55°C. Realizar los esquemas de perfil de temperaturas para un intercambiador de calor que funcione en paralelo y en contracorriente. Además, calcular LMTD.
Answer:
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
Explanation:
De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:
1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.
2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.
Mientras que el intercambiador de calor en contracorriente tiene que:
1) El fluido caliente y el fluido frío entran por lados opuestos.
2) El fluido caliente y el fluido frío salen por lados opuestos.
A continuación, anexamos los esquemas de perfil de cada intercambiador.
Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:
\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)
Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.
Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:
Intercambiador en paralelo
\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{1} = 177\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)
\(\Delta T_{2} = 23\,^{\circ}C\)
\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
Intercambiador en contracorriente
\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)
\(\Delta T_{1} = 125\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{2} = 75\,^{\circ}C\)
\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
Tensile testing provides engineers with the ability to verify and establish material properties related to a specific material.
a. True
b. False
Answer:
True
Explanation:
Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true
The daily average concentration of pollutants in a stream follows a lognormal distribution with a mean of 50 mg/l and a standard deviation of 12 mg/l. It is desired to calculate the following probabilities:
1.) That the average concentration of pollutants in the stream on a given day will exceed 85 mg/l; and
2.) That a critical level of 95 mg/l will only be exceeded at the most one day in a given week (seven days). Assume that the pollutant concentrations between days are statistically independent.
Answer:
1) probability that the average concentration of pollutants in the stream on a given day will exceed 85 mg/l is 0.0018
2) probability that a critical level of 95 mg/l will only be exceeded at the most one day in a given week (seven days) is 0.9993
Explanation:
Given the data in the question;
mean μ = 50 mg/l
standard deviation σ = 12 mg/l
we know that; x-score = x-μ / σ
1) probability that the average concentration of pollutants in the stream on a given day will exceed 85 mg/l
p( x > 85 ) = P( Z > 85-50 / 12 )
= P( Z > 35/12 )
= P( Z > 2.9166)
= P( Z > 2.92)
= 1 - P( Z > 2.92)
from z-score table; P( Z > 2.92) = 0.9982
= 1 - 0.9982
p( x > 85 ) = 0.0018
Therefore, probability that the average concentration of pollutants in the stream on a given day will exceed 85 mg/l is 0.0018
2) probability that a critical level of 95 mg/l will only be exceeded at the most one day in a given week (seven days). Assume that the pollutant concentrations between days are statistically independent.
p( x > 95 ) = p( Z > 95-50 / 12 )
= p( Z > 45 / 12 )
= p( Z > 3.75 )
= 1 - p( Z > 3.75 )
from z-score table; p( Z > 3.75 ) = 0.9999
= 1 - 0.9999
= 0.0001
Now; p = 0.0001 and n = ( week) = 7
x = number of days × exceeds 99 mg/l
x ¬ Binomial ( n =7 p = 0.0001 )
p(x ≤ 1) = p(x=0) + (p=1)
= ¹∑\(_{x=0}\) \(^7C_x ( 0.0001)^x\) \((0.9999)^{7-x}\)
= \(^7C_0 ( 0.0001)^0\) \((0.9999)^{7-0}\)
= 7!/(0!(7-0)!) \(( 0.0001)^0\) \((0.9999)^{7-0}\)
= (1) ( 1 ) ( 0.9993 )
= 0.9993
Therefore, probability that a critical level of 95 mg/l will only be exceeded at the most one day in a given week (seven days) is 0.9993
explain why it is not advisable to wear a ring at work shop
Answer:
Metal conducts heat so it could severely burn your finger.
Rings can create multiple hazards while working with chemicals.
Rings/Jewlery can be a "hiding place" for bacteria.
Amongst many other reasons as to why it's not advisable to wear a ring(s) at a workshop/workplace.
Lawn maintenance is an alternative energy source
-true
-false
Answer:
false
Explanation:
Answer:
THE ANSWER IS FALSE
Explanation:
GO FOR IT!!!!!
What are the benefits of using the engineering design process
Answer:
Some of the benefits are tangible for they are visible in the design and production process, while the other benefits are intangible which may not be visible directly but result in improvement in the quality of product, better control over designing and production process, reduction of stress on the designers etc.
Fuel-efficient electric and gas/electric hybrid vehicles produce very little sound at normal driving speeds, and are thus difficult for the visually impaired to detect. Does this raise problems for engineers similar to those raised by roundabouts? In what ways are these problems similar? In what ways are they different?
The issue of electric and hybrid vehicles being difficult for the visually impaired to detect does indeed raise problems for engineers, similar to those raised by roundabouts. Both issues involve the need to balance different design considerations, including safety, accessibility, and sustainability.
One similarity between the problems is that both involve designing for the needs of vulnerable road users, such as the visually impaired or pedestrians. In the case of roundabouts, engineers must consider factors such as crosswalk placement, pedestrian signals, and traffic speeds to ensure that the roundabout is safe and accessible for all users. Similarly, in the case of electric and hybrid vehicles, engineers must consider strategies for making these vehicles more detectable to visually impaired pedestrians, such as adding noise-making devices or using special road markings.
However, there are also some differences between the problems. With roundabouts, the focus is on designing a physical infrastructure that is safe and accessible for all users. With electric and hybrid vehicles, the focus is on designing a vehicle that is both fuel-efficient and safe for all users, including pedestrians. This requires a different set of design considerations and trade-offs.
Another difference is that the problem of electric and hybrid vehicles being difficult to detect is a relatively new issue, while roundabouts have been in use for many years. As a result, the solutions to the problems may require different approaches and may involve more experimentation and testing with new technologies.
Overall, both the issues of roundabouts and electric/hybrid vehicles highlight the need for engineers to consider the needs of all users when designing transportation infrastructure and vehicles. By balancing safety, accessibility, and sustainability, engineers can create solutions that meet the needs of a diverse range of users and help create more inclusive and sustainable communities.
The density of seawater at a free surface where the pressure is 98 kPa is approximately 1030 kg/m3. Taking the bulk modulus of elasticity of seawater to be 2. 34 109N/m2 and expressing variation of pressure with depth z as dp= rgdz determine the density and pressure at a depth of 2500 m. Disregard the effect of temperature. Recall that:(i) The bulk module of elasticity is defined as: (ii) Density is not assumed as constantin this problem
The pressure of seawater will be 2.14*107 N/m2 and the density will be 8.53*103 kg/m3.
What is pressure?Pressure is a type of force applied to an object by another object over a surface area. Pressure is measured in units of force per unit area and is usually expressed in terms of pascals (Pa).
The bulk modulus of elasticity, K, is a measure of the stiffness of a material and is defined as the ratio of bulk stress to the resulting strain. In this problem, we need to calculate the density and pressure at a depth of 2500 m, based on the given bulk modulus and 98 kPa pressure at the surface.
To solve this problem, we will use the equation K = -dp/dρ, where dp is the change in pressure with depth and dρ is the change in density with depth. Since we are given the bulk modulus and pressure on the surface, we can calculate the change in density with depth as follows:
dρ = -K*dp/dz
where dp = rgdz and rg is the gravity of the Earth. Substituting these values, we get:
dρ = -2.34*109*98*103/(9.8*2500) = -7.78*103 kg/m3
This means that for every metre of depth, the density of seawater decreases by 7.78*103 kg/m3. Therefore, at a depth of 2500 m, the density of seawater will be:
ρ = 1030 - 7.78*103*2500 = 8.53*103 kg/m3
Similarly, we can calculate the pressure at a depth of 2500 m using the equation P = P0 + rgdz, where P0 is the pressure at the surface. Substituting the values, we get:
P = 98*103 + 9.8*2500*8.53*103 = 2.14*107 N/m2
Therefore, at a depth of 2500 m, the pressure of seawater will be 2.14*107 N/m2 and the density will be 8.53*103 kg/m3.
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Help!
Write a C program to process weekly employee time cards for all employees of an organization. Each employee will have three data items: an identification number. the hourly wage rate, and the number of hours worked during a given Week o Each employee is to be paid time and a half for all hours worked over 36 A tax amount of 1% of gross salary will be deducted. program output should show the employee's number and net pay.
The program requires the use of loops.
Loops are simply used to perform repetitive operations.
The program in C, where comments are used to explain each line is as follows:
#include <stdio.h>
int main(){
//This declares all the variables
int n, idno, hours; float rate,pay;
//This gets input for the number of employees
printf("Employees: "); scanf("%d", &n);
//This is repeated n times
for(int i = 0; i<n; i++){
//This gets input for the identification number
printf("Identification number: "); scanf("%d", &idno);
//This gets input for the hours worked
printf("Hours worked: "); scanf("%d", &hours);
//This gets input for the hourly rate
printf("Rate: "); scanf("%f", &rate);
//This calculates the pay, after tax
pay = rate * hours * 0.99;
//This calculates the pay, after tax for hours greater than 36
if(hours > 36){
pay = 0.99 * (rate * 36 + 0.5 * rate * (hours - 36));
}
//This prints the required output
printf("Identification number: %d Pay: %f\n",idno,pay);
}
return 0;
}
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a storage tank contains liquid with a density of 0.0361 lbs per cubic inch. the height of liquid in the tank is 168 feet. what is the pressure of the liquid at the bottom of the tank give your answer in psi
Answer:
Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:
Float on water: d < 0.0361 lb/in³ (where d denotes denisity)
Do not float on water: d > 0.0361 lb/in³
Explanation:
I don't know if this works for it or not?
what is the range of sizes of rigid metal conduit that can be bent with a mechanical bender?
The range of sizes of rigid metal conduit that can be bent with a mechanical bender typically varies from ½ inch to 4 inches.
A mechanical bender is a tool used to bend rigid metal conduit, which is commonly used in electrical installations. The typical range of sizes that can be bent with a mechanical bender starts from ½ inch and goes up to 4 inches. This means that rigid metal conduits with diameters within this range can be effectively bent using a mechanical bender.
It's important to note that the specific capabilities of a mechanical bender may vary, so it's recommended to refer to the manufacturer's specifications or guidelines for precise information on the bending capacities of a particular mechanical bender model.
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1). A wastewater sample contains 1% solids, the solids concentration equals: a. 1 ppm. b. 100 mg/L. c. 10000 mg/L. d. 0.01 ppm. e. None of the above. a. 2). Which of the following statement is not true for a wastewater sample with its pH = 7.5: The pOH of the sample = 6.5. b. The [H] of the sample = 10-7.5. The sample is at near neutral pH. d. The [OH) of the sample = 106.5. c. 3). Which of the following statement is not true based on organic chemistry your learned in this course: a. Hydrocarbons in which each carbon forms four single bonds to other atoms are called saturated hydrocarbons, or alkanes. b. Molecules in which the hexagonal benzene ring occurs are called aromatic compounds. c. Compounds having the same molecular formula, but different structural formulas, are know as structural kink. d. Removing one hydrogen from CH4 produces the methyl radical (CH;-). a. 4) A hazard index of 0.001 implies: Risk = 103 b. the probability of hazard is 0.001 The RfD is small compared with the CDI d. There is little concern for potential health effects
1) The correct answer is b. 100 mg/L.
2) The statement that is not true is d. The [OH] of the sample = 10^(-6.5). The correct calculation would be: pOH = 14 - pH = 14 - 7.5 = 6.5; [OH] = 10^(-pOH) = 10^(-6.5).
3) The statement that is not true is c. Compounds having the same molecular formula, but different structural formulas, are known as isomers, not structural kink.
4) The correct answer is d. There is little concern for potential health effects. A hazard index of 0.001 means that the total exposure to a chemical is 1/1000th of the dose that is known to cause adverse health effects. This implies a low risk and little concern for potential health effects.
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Which of the following is not a presentation software term? 9 Multiple Choice Speaker Notes Speaker Image Slide Slide Master
Note that the option that is not a presentation software term is: "Speaker Image" (Option 2)
What is presentation software?A presentation program (sometimes known as presentation software) is a software package used to display information as a slide show. It includes three key functions: an editor that allows text to be input and formatted, a search engine, and a calendar. a technique for adding and modifying visual graphics and media snippets.
Speaker Notes refers to notes that speakers can utilize to assist steer their presentation are referred to as speaker notes. They are usually hidden from the audience and serve as a reference for the speaker.
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O A brass rod is stress-free at room temperature (20°C). It is heated up but prevented from lengthening. At what temperature does the stress reach -172 MPa?
The solution to the AR builder's long-standing annoyance with the pin snap ring (C-Clip) is the 'Stress Free' Ejection Port Cover Assembly.
Thus, Once you utilize the "Stress Free" rod, you won't want to use a regular C-Clip rod assembly again.
The 'Stress Free' Ejection Port Cover Assembly is our remedy for the pin snap ring (C-Clip), which has long been a source of annoyance for AR builders.
How many times have you been putting the C-Clip onto the cover rod only to see it suddenly fly across the room and into the darkest, most obscure part of your business, scattering all the metal shavings you put off cleaning up.
Thus, The solution to the AR builder's long-standing annoyance with the pin snap ring (C-Clip) is the 'Stress Free' Ejection Port Cover Assembly.
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Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years
an adiabatic compressor receives 1.5 meter cube per second of air at 30 degrees celsius and 101 kpa. The discharge pressure is 505 kpa and the power supplied is 325 kW, what is the discharge temperature
Answer:
The discharge temperature is 259.82 K
Explanation:
In this question, we are concerned with calculating the discharge temperature
Please check attachment for complete solution
A___________combines the function of a video camera and a sound recorder.
Answer:
A video camera with onboard storage(whether is a tape or digital memory) will record sound
1.) What is the purpose of measuring tape? What would you measure and why? (1 paragraph, 5 sentences)
Answer:
The measuring tape is used to measure objects. It makes objects with two faces easier to measure, as it would be more difficult to use a ruler to measure two faces. You measure to increase accuracy. If you're trying to build something out of 12 inches of wood, you can't just look at the wood and assume it is 12 inches long. In engineering, it's necessary to measure during every project.
Explanation:
will give brainliest what are 3 good projects to do with wood or cardboard or paper or an old drone when you are a beginner
if you do not have 3 good projects then please dont answer and just comment them but if you have more than 3 that would be great for you to answer.
Answer:the inflating Ballon expirement
Explanation:
Calcule la entropía de 2 moles de un gas ideal que realiza una expansión libre al triple de su volumen inicial, utilice: ∆S =n・R・ℓn (Vf / Vi)
The entropy of 2 moles of and ideal gas expanding freely to 3 times it's initial volume is 18.3J/k
How did we arrive at the above?The following formula is required:
∆S = nx R x ℓn x (Vf/Vi)
Where
n = number of moles of gas (n = 2)
R = gas constant (R = 8.314 J/(mol * K))
Vf = final volume (Vf = 3.V1)
Vi = intial volume
Vi = 1L (Asumption )
∆S = 2 x 8.314 x 1.099
∆S =18.3 j/K
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Translation:
Calculate the entropy of 2 moles of an ideal gas expanding freely to three times its initial volume, use: ∆S =n・R・ℓn (Vf / Vi)
100tons per day apple juice production
Design as much detail as possible, make reasonable assumptions.
To be included in the report:
- choice of the location of the plant
- extent of reaction (conversion); make reasonable assumption if exact information is not found or calculated;
- material balance & energy balance: the composition, temperature and flow rate of each stream;
- list of equipment: e.g. type, volume, dimensions, materials, etc.
- PFD (A3 paper), PID (A3 paper), workshop layout diagram (A4 paper), with reasoning for the choice of equipment location, etc.
- pipeline layout diagram (A4 paper)
- environmental impact analysis
- economic analysis: capital cost, operating cost, revenue, profit, etc.
The production of 100 tons of apple juice per day will require a well-designed process plant with a high level of precision to ensure the production of a high-quality product. This plant will require a choice of location based on the availability of a suitable water source and the availability of a reliable power source.
The plant should be located in an area that has low pollution levels and ample land for expansion.The extent of the reaction can be determined by the type of process being used for the production of the apple juice. Assuming that an enzymatic process will be used to produce the juice, the extent of conversion will be determined by the efficiency of the enzymes used in the process. The material balance and energy balance will involve the measurement of the composition, temperature, and flow rate of each stream, as well as the volume, dimensions, and materials used in the construction of the equipment.
The equipment required for the production of 100 tons of apple juice per day will include a crusher, a juice extractor, a pasteurizer, a holding tank, and a bottling machine. The equipment should be designed with high-quality materials that can withstand the rigors of the juice production process. The PFD (A3 paper) and PID (A3 paper) will provide a detailed diagram of the process flow and equipment design. The workshop layout diagram (A4 paper) will detail the location of each piece of equipment and the reasoning for its placement.
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2..Three formations, each 25 m thick, overlie one another. If a constant-velocity vertical flow field is set up across the set of formations with h = 120 m at the top and h = 100 m at the bottom, calculate h at the two internal boundaries. The hydraulic conductivity of the top formation is 0.0001 m/s, the middle formation 0.0005 m/s, and the bottom formation 0.0010 m/s.
The values of h at the two internal boundaries are :
h₁ = 104.625 m h₂ = 101.55 mGiven data :
Z₁ = Z₂ = Z₃ = 25 m
h top = 120 m
h bottom = 100 m
K₁ = 0.0001 m/s
K₂ = 0.0005 m/s
K₃ = 0.0010 m/s
First step : Calculate the value of Keqwe will apply the formula below since flow is perpendicular to the bedding plane
Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\) ----- ( 1 )
Insert values given above into equation 1
Therefore ; Keq = 2.307 * 10⁻⁴ m/s
Next step : determine the hydraulic gradientHydraulic gradient ( Ieq ) = head loss / length
= ( 120 - 100 ) / 3 * 25
Ieq = 0.266
Given that the flow is perpendicular to bedding plane
q1 = q2 = q3
V₁ = V₂ = V₃ = V
K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq
Hence :
V = Keq* Ieq
= 2.307 * 10⁻⁴ * 0.266
= 6.15 * 10⁻⁵ m/s .
Also;
K₁i₁ = Keq * ieq = K₂i₂ = K₃i₃
therefore :
i₁ = 0.615
i₂ = 0.123
i₃ = 0.0615
Final step : determine the value of h at the two internal boundariesPressure at point 1 ( i.e. pressure between first two formations )
h₁ = h top - i₁L₁
= 120 - 0.615 * 25
= 104.625 m
Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )
h₂ = h₁ - i₂L₂
= 104.625 - 0.123 * 25
= 101.55 m
Therefore we can conclude that The values of h at the two internal boundaries are : h₁ = 104.625 m , h₂ = 101.55 m
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