Describe some inconveniences which are encountered when using oil baths...

Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{2.997 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 49.784053\)

We have the final answer as

Hope this helps you

Answer:

Hope this helps!

Explanation:

To calculate the pOH of a solution you need to know the concentration of the hydroxide ion in moles per liter (molarity). The pOH is then calculated using the expression: pOH = - log [OH-] Example: What is the pOH of a solution that has a hydroxide ion concentration of 4.82 x 10-5 M?

To find the pOH, simply subtract the pH from 14. In order to calculate the pOH, take the negative log of the hydroxide ion concentration.

The poH equation and how it should be determined from pH should be explained below.

To determine the pOH of the solution here first we know the concentration of the hydroxide ion in terms of moles per liter (molarity). The pOH should be then calculated by applying the following expression.

pOH = - log [OH-]

Now for determining the pOH here we considered the negative log of the  hydroxide ion concentration.

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Answer:

B. Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.

Explanation:

What Gunther should do is to heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.

A solution is composed of a solute and a solvent. The solubility of a solute in a solvent depends on temperature. Especially for solids, solubility increased when the temperature is increased.

Now, from the question, Gunther needs to add 40 g of a solute to 100 g of water. He added 34 grams before the solute settled out. In this case, he needed to dissolve the remaining 6 grams. What Gunther should do is to  to heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.

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Answer:0

Explanation:

The reaction is a substitution reaction since bromide ion was replaced by hydroxide ion.

A chemical reaction is a change which results in a the permanent rearrangements of the atoms and constituents of a substance such that new substances are formed.

The given reaction is a as follows:

\(CH_3Br (aq) + OH^{-} (aq) \rightarrow CH_3OH (aq) + Br^{-} (aq) \\ \)

Bromide ion was replaced by hydroxide ion.

Therefore, the reaction is a substitution reaction.

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Answer: D-substitution

Other person is right its

Explanation:

Answer:

The hydroxide ion concentration in an aqueous solution, [OH-], in mol L-1, can be calculated if the pOH of the solution is known.

pOH is defined as the negative logarithm (to base 10) of the hydroxide ion concentration in mol L-1 pOH = -log10[OH-]

Explanation:

Answer:

T₂  = 244.5 K

Explanation:

Given data:

Initial pressure = 3.90 atm

Initial temperature = 298 K

Final pressure = 3.20 atm

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.90 atm / 298 K = 3.20 atm/T₂

T₂  =  3.20 atm × 298 K / 3.90 atm

T₂  = 953.6atm. K /3.90 atm

T₂  = 244.5 K

The cation of an ionic compound affects the appearance of the solution by determining the color of the solution.

An ionic compound is formed when an element that has fewer electrons loses them to another element that needs more electrons, forming an ionic bond between them. Ionic bonds are formed between oppositely charged ions. The positively charged ion is referred to as the cation while the negatively charged ion is referred to as the anion.

In an aqueous solution, the presence of a cation is an essential factor that influences the color of the solution. The concentration and identity of cations determine the color of the solution. For example, the presence of a sodium cation will make the solution turn yellow. The color of the solution changes if another cation replaces the sodium cation. The presence of another cation like copper(II) will cause the solution to turn blue.

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Answer:

0.5m

Explanation:

Answer:

thats cool mate

Explanation:

hope ya have a good day, im answering just for the points tbh

Answer:

ello thats great free points then >:3

-XxanimexX

At neutral pH, both H-indictor and OH-indicator will co-exist in an equilibrium, so the color will be a mixture of the two.

Acid base indicators are generally weak protolytes that change color in solution according to the pH.

The acid-base equilibrium of a weak acid type of indicator, i.e., H-indicator in water can be expressed as-

            HI + H₂O ⇄ H₃O⁺ + I⁻

The acid, HI, and conjugate base, I⁻, have different colors. The equilibrium expression for this process is

             K = [I⁻] [H₃O⁺]

                         [HI]

This can be expressed in logarithmic form :

            pH = pK + log [I⁻]

                                    [HI]

Now, from the equation it can be predicted whether the indicator is in its acid or base form depending on the pH.

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The charge on the iron cation in the compound with the chemical formula Fe2O3 is +3.

To determine this, follow these steps:

1. Identify the elements in the formula: Fe represents iron, and O represents oxygen.

2. Determine the charge of the oxygen anion. Oxygen typically has a charge of -2.

3. Balance the charges in the compound. In this case, there are two iron cations (Fe) and three oxygen anions (O). The total charge of the oxygen anions is -6 (3 x -2 = -6).

4. To balance the charges, the iron cations must have a total charge of +6. Since there are two iron cations, each must have a charge of +3 (6 ÷ 2 = 3).

So, the charge on the iron cation in Fe2O3 is +3.

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Answer:

The mass of chlorine gas that reacted ≅ 24.03 g

Explanation:

From the given information:

The number of moles of NaCl formed = mass of NaCl/molar mass

mass of NaCl = 39.6 g

molar mass = (23 + 35.5) g/mol = 58.5 g/mol

∴

The number of moles of NaCl formed = 39.6 g / 58.5 g/mol

The number of moles of NaCl formed = 0.6769 g/mol

Thus, the mass of chlorine gad that reacted = 0.6769 × 35.5

The mass of chlorine gas that reacted = 24.02995  g

The mass of chlorine gas that reacted ≅ 24.03 g

If compounds have the same empirical formula, they may or may not have the same molecular formula.

The empirical formula represents the simplest whole-number ratio of the atoms in a molecule, while the molecular formula gives the actual number of atoms of each element in a molecule.

For example, two compounds could have the same empirical formula of \(CH_{2}\), but have different molecular formulas of \(C_{2}\)\(H_{4}\)\(O_{8}\) (acetic acid) and glucose.

So, while compounds with the same empirical formula share the same relative ratios of atoms, their molecular formulas can differ, which affects their chemical and physical properties.

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The net ionic equation for the reaction between AgNO3 and NH4Cl is: Ag+(aq) + Cl-(aq) → AgCl(s)

When AgNO3 (silver nitrate) and NH4Cl (ammonium chloride) are mixed, a white precipitate of AgCl (silver chloride) is formed.

AgNO3 is a soluble salt that dissociates in water to form Ag+ and NO3- ions, while NH4Cl also dissociates in water to form NH4+ and Cl- ions. When these two solutions are mixed, the Ag+ ions react with the Cl- ions to form an insoluble precipitate of AgCl, which is a white solid. The ammonium ion (NH4+) and the nitrate ion (NO3-) are spectator ions and do not participate in the reaction.

The overall balanced chemical equation for the reaction is:

AgNO3(aq) + NH4Cl(aq) → AgCl(s) + NH4NO3(aq)

The net ionic equation shows only the species that are involved in the reaction and excludes spectator ions. Therefore, the net ionic equation for the reaction between AgNO3 and NH4Cl is:

Ag+(aq) + Cl-(aq) → AgCl(s)In the net ionic equation, the ammonium ion (NH4+) and the nitrate ion (NO3-) are not shown since they do not participate in the reaction.

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Answer:

maybe the third option?

The inflation rate from 2014 to 2015, assuming 2014 as the base year, is 68.09%.

The inflation rate from 2014 to 2015, assuming that 2014 is the base year, can be determined using the Consumer Price Index (CPI). The CPI measures the cost of goods and services over time and is used to calculate inflation. The formula for calculating inflation rate using CPI is as follows: Inflation rate = ((CPI year 2 - CPI year 1) / CPI year 1) x 100To solve this problem, we first need to calculate the CPI for each year using the prices and quantities of nuts and meat.

Calculating CPI for 2014:CPI 2014 = (300 x $9) + (175 x $19) = $5,625 Calculating CPI for 2015:CPI 2015 = (420 x $9) + (340 x $14) = $9,460Using the CPI formula, we can calculate the inflation rate from 2014 to 2015:Inflation rate = ((CPI 2015 - CPI 2014) / CPI 2014) x 100= (($9,460 - $5,625) / $5,625) x 100= $3,835 / $5,625 x 100= 68.09% (to 2 decimal places) Therefore, the inflation rate from 2014 to 2015, assuming 2014 as the base year, is 68.09%.

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The second ionization energy of a sodium atom isThe correct answer is option (d): Much greater than the first ionization energy because the second ionization requires the removal of a core electron.

Ionization energy refers to the amount of energy required to remove an electron from an atom or ion in the gaseous state. The first ionization energy corresponds to the removal of the outermost electron, which is typically the valence electron. In the case of sodium (Na), which is an alkali metal, the first ionization energy is relatively low because alkali metals have a single valence electron that is far from the nucleus and easily removed. However, the second ionization energy refers to the energy required to remove an additional electron after the first one has been removed. In the case of sodium, the second ionization energy is much greater because the electron being removed is a core electron, closer to the nucleus and therefore more strongly attracted to it. Removing a core electron requires overcoming a stronger electrostatic attraction, resulting in a higher energy requirement.Thus, the second ionization energy of a sodium atom is much greater than the first ionization energy because it involves the removal of a core electron, which is more difficult to remove compared to the valence electron involved in the first ionization.

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Graphite is a fantastic lubricant and a powerful electrical conductor because of these unbound electrons.

Unbound can serve as a caching server, it can also perform recursion, store records obtained from other DNS servers, and provide an authoritative service, such as if you only have a few zones.

As a result, it can act as a "glue" server or host a small zone with only a few domains, making it ideal for a lab.

Why need to utilize Unbound DNS?

With its harden-glue, access control, maximum randomization for request ID and ports, response scrubbing, case preservation, plus Denial of Service or DoS prevention capabilities, Unbound is feature-rich with DNS Security. These are only a few.

Therefore, graphite is a fantastic lubricant and a powerful electrical conductor because of these unbound electrons.

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Answer:

1.2×1023 molecules.

hope it helps

Answer:

Orion Nebula

Explanation:

That is an enormous cloud of gas and dust

Answer:

Maintains natural hair moisture.

Prevents hair frizz.

Reduces hair breakage & tangles.

Longer lasting hair styles.

Explanation:

Answer:

not enough information need more information to answer it

Answer:

There are no statements listed but.... a few ideas

Explanation:

Earth is very small in comparison to Jupiter which is the largest planet of the solar system.

The diameter of Jupiter is 11 times greater than the diameter of the earth.

Earth is a terrestrial planet, whereas Jupiter is a Jovian planet.

Mass of Oxygen : 47.9

Given

2S03 (g)⇒ 2S02 (g) + O2 (g)

240 g SO3

Required

mass of Oxygen

Solution

mol SO3 :

= 240 g : 80.1 g/mol

= 2.996

From the equation, mol O2 :

= 1/2 x mol SO3

= 1/2 x 2.996

= 1.498

mass O2 :

= 1.498 mol x 32 g/mol

= 47.9

Taking into account the reaction stoichiometry, given a 240.0 g sample of sulfur trioxide, 47.95 grams of oxygen are produced, assuming the decomposition goes to completion.

In first place, the balanced reaction is:

2 SO₃ → 2 SO₂ + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 160.2 grams of SO₃ form 32 grams of O₂, 240 grams of SO₃ form how much mass of O₂?

\(mass of O_{2} =\frac{240 grams of SO_{3}x 32 grams of O_{2} }{160.2grams of SO_{3}}\)

mass of O₂= 47.94 grams

Given a 240.0 g sample of sulfur trioxide, 47.95 grams of oxygen are produced, assuming the decomposition goes to completion.

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Answer:

Composite volcanoes. ... They are typically steep-sided, symmetrical cones of large dimension built of alternating layers of lava flows, volcanic ash, cinders, blocks, and bombs and may rise as much as 8,000 feet above their bases.Muh. 28, 1432 AH

First, we write down our reaction:

N2 + 3H2 → 2NH3

Don't forget to balance it.

We only use moles as units.

Procedure:

3 x 1 mole H2 ------------ 2 x 1 mole NH3

3.1 moles H2 ------------- x

x = 2.1 moles NH3 are produced

Answer: 2.1 moles NH3

The rate of the reaction is 1.6 × 10⁻² M/s. When the concentration of A is 0.35 M. The rate constant if the (a) First order in A = 0.0457 s⁻¹ (b) Second order in A 0.130  M  s⁻¹.

The rate of the reaction = 1.6 × 10⁻² M/s

The concentration of A = 0.35 M

(a) First order in A

Rate = k[A]

where,

k = the rate constant

By solving the value , wet

k = r / [A]

k =  1.6 × 10⁻² M/s / 0.35 M

k = 0.0457 s⁻¹

The rate constant is 0.0457 s⁻¹.

(b) Second order in A

Rate = k [A]²

where,

Rate = 1.6 × 10⁻² M/s

k = r /  [A]²

k = 1.6 × 10⁻² M/s / ( 0.35 M)²

k = 0.130 M  s⁻¹

The rate constant is 0.130  M  s⁻¹.

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