Answer:
its circular
Explanation:
What the full name of DNA?
Answer:
Deoxyribonucleic acid
Explanation:
Answer:
Deoxyribonucleic acid
Explanation: Hopes that helps
A car moved with the speed of 5 m/sec, and after 8 sec it speed became 77 m/sec . What's its acceleration?
Answer:
\(a = \frac{v_{f} - v_{i}}{t} \\ = \frac{77 - 5}{8} = \frac{72}{8} \\ \boxed{a = 9 \: m. {sec}^{ - 2} }\)
will give brainlist 20 points
Answer:
I think its uniform I dont really know
A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When released the spring toy pops up and reaches a maximum height of 1.5 meters.
1) How much elastic potential energy is initially stored in the spring?
2)How much internal energy is produced as the toy springs up to its maximum height?
Answer:
(1) V = 0.2 J (2) 0.05J
Explanation:
Solution
Given that:
K = 160 N/m
x = 0.05 m
Now,
(1) we solve for the initial potential energy stored
Thus,
V = 1/2 kx² = 0.5 * 160 * (0.05)²
Therefore V = 0.2 J
(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.
By using the energy conversion, we have the following
ΔV = mgh
=(0.1/9.8) * 9.8 * 1.5 = 0.15J
The internal energy = 0.2 -0.15
=0.05J
Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.
By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.
Euler's method is defined as a numerical technique which is used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.
In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.
Step 1:
We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].
Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:
Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25
Step 2:
Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:
Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125
Thus, by using Euler's method with two steps, the approximate value of Y(2) is 2.125.
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The complete question is
Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3
A boy standing throws a penny horizontally at 7.25 m/s out of the window of his apparent buliding. If the window is 10.0 m above the ground, how far from the base of the building does the penny land?
Answer:
Explanation:
This is a 2D problem (parabolic) so we have to think that way. We have to split up the problem into its 2 dimensions to solve it. Think "y-stuff" and "x-stuff".
In the y-stuff category:
v₀ = 0 (initial upwards velocity is 0 since we are told the penny is thrown horizontally)
Δx = -10.0 m (this displacement is negative because the penny lands 10.0 m below the point from which it was thrown)
a = -9.8 m/s/s
t = ? (we need to find the time in this dimension so we can use it in the x dimension to find the displacement, our unknown)
In the "x-stuff" category:
v₀ = 7.25 m/s (this is given)
Δx = ???
a = 0 (acceleration in this dimension is ALWAYS 0)
t = (we will solve for this in the y-dimension and plug it in here).
In the y dimension:
Δx = v₀t + \(\frac{1}{2}at^2\) and plugging in from the y-dimension info:
\(-10.0=0t+\frac{1}{2}(-9.8)t^2\) which simplifies to
\(-10.0=-4.9t^2\) so
\(t=\sqrt{\frac{-10.0}{-4.9} }\) which, to 2 significant digits is
t = 1.4 seconds
Now we will do the same in the x-dimension, using t = 1.4:
Δx = v₀t + \(\frac{1}{2}at^2\) and filling in the x-stuff:
Δx = \(7.25(1.4)+\frac{1}{2}(0)(1.4)^2\) Notice that the stuff after the + sign goes to 0 cuz of the multiplication of 0, so what we are left with is another form of the d = rt equation:
Δx = 7.25(1.4) + 0 so
Δx = 1.0 × 10¹ m (That's rounded correctly to 2 sig dig's: 10 m from the base of the building).
Answer:
30.2
Explanation:
c. If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, what is the net force on the box?
According to the data given in the question the net force on the box is of 5 N.
What does net force mean?All of the forces that are applied to an object are added up to form the net force. As a consequence of the fact that it (force) is a vector and therefore that two forces with identical magnitudes and opposing directions cancel each other out, the resultant force is the total of the forces, or put another way, the net force is just the total of all the forces.
Given data :
Force on box to the left side (F1) = 15 N
Force on box to the right side (F2) = 20 N
Because both forces are in opposite direction
Hence,
Net force = F2 - F1
Net force = 20 - 15
Net force = 5 N.
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Find Vn, Vout, and lout for the circuit shown below. Assume that the op amp is ideal. 6V 3ΚΩ www 1k02 www +5V 1.5mA -5V 2. Find Vn, Vout, and lout for the circuit shown below. Assume that the op amp is ideal. 6V 1k0 www 2.5KQ www +5V 3mA 2kQ www ΣΚΩ 4mA 5V 2k0 ww 8V 10k(2 -5V lout www-11 lout ww-11 Vou 5ΚΩ Vout ΣΚΩ
The voltage at the inverting terminal is 7.5 V. V out is -12.5 V. The current flowing through R4 is 0.5 mA.
Given that Vn, Vout, and lout for the circuit shown below and op amp is ideal.In the circuit, current I2 flows through the 2.5 kΩ resistor.
Therefore, the voltage drop across the 2.5 kΩ resistor is given by,
Vn = I2 x R2Vn = 3 mA x 2.5 kΩ = 7.5 V
Therefore, the voltage at the inverting terminal is 7.5 V.
Since op-amp is assumed to be ideal, no current flows into the inverting and non-inverting terminals.
Therefore, current through R3 is given by,
I3 = (Vn - Vout) / R3=> Vout = Vn - I3 x R3=> Vout = 7.5 V - 4 mA x 5 kΩ=> Vout = - 12.5 V
Therefore, Vout is -12.5 V.
Let's calculate the current flowing through R4:
This current will also flow through the 5 kΩ resistor.
Let lout be the current flowing through R4.
Therefore, current through the 5 kΩ resistor is also lout.
Now, I4 + lout = I3=> I4 = I3 - lout=> I4 = 4 mA - lout
Also, I4 = (5 V - Vout) / R4=> 4 mA - lout = (5 V - (-12.5 V)) / 5 kΩ=> 4 mA - lout = 3.5 mA=> lout = 0.5 mA
Therefore, lout is 0.5 mA.
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state the effect of momentarily touching the conductor with a finger while the charged rod is still near the conductor
\(\small\color{blue}{⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰}\)
state the effect of momentarily touching the conductor with a finger while the charged rod is still near the conductor
If Im Mistaken it Changes Access\(\small\color{blue}{⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰}\)
If you have an insulator that's charged up with a negative charge, and you touch a conductor, the negatively charged excess electrons will move to the conductor until the electrons would rather not move anywhere at all. When this happens, we say that the system has reached equilibrium
\(\small\color{blue}{⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰}\)
-PoliteCat
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\(\large\boxed{\text{Together We Go Far!}}\)
hi guys i have a question do you know how tsunami make us change
Answer:
it distroy our property house,buildings
Two frequency generators are creating sounds of frequencies 457 and 465 Hz simultaneously. Randomized Variables f 1
=457 Hz
f 2
=465 Hz
A 50% Part (a) What average frequency will you hear in Hz ? f ave
= Hints: deduction per hint. Hints remaining: Feedback: deduction per feedback. A 50% Part (b) What will the beat frequency be in Hz ?
(a) The average frequency that you will hear is 461 Hz.
(b) The beat frequency will be 8 Hz.
What average frequency will you hear in Hz?(a) When two frequencies are played simultaneously, the human ear perceives the average of the two frequencies as the perceived pitch or average frequency. In this case, the two frequencies are 457 Hz and 465 Hz.
To find the average frequency, we can simply take the arithmetic mean of the two frequencies:
Average frequency = (457 Hz + 465 Hz) / 2 = 461 Hz.
Therefore, the average frequency that you will hear is 461 Hz.
What will the beat frequency be in Hz ?b) The beat frequency is the difference between the two frequencies. In this case, the two frequencies are 457 Hz and 465 Hz.
To find the beat frequency, we subtract the lower frequency from the higher frequency:
Beat frequency = 465 Hz - 457 Hz = 8 Hz.
Therefore, the beat frequency will be 8 Hz.
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50mg/dL or 0.05g/dL is equal to how many drinks?
To answer your question, it's important to clarify that "50 mg/dL" or "0.05 g/dL" are measurements of blood alcohol concentration (BAC) and not directly equal to a specific number of drinks.
As a result, the number of drinks required to reach a BAC of 50 mg/dL (0.05 g/dL) can differ between individuals.
Generally, one standard drink contains about 14 grams of pure alcohol, which can be found in 12 ounces of beer, 5 ounces of wine, or 1.5 ounces of distilled spirits. However, the exact number of drinks it takes to reach a BAC of 50 mg/dL (0.05 g/dL) will depend on a person's specific characteristics and how quickly the drinks are consumed.It's crucial to remember that it's not safe or legal to drive with a BAC of 0.05 g/dL or higher in many countries, as it can impair cognitive and motor functions. Always drink responsibly and arrange for a safe way home if you choose to consume alcohol. BAC levels vary depending on factors such as weight, gender, and individual metabolism.
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A ball is thrown directly upward from a height 10 meters above the ground at time t = 0 (seconds). The location y(t) (in meters above the ground) of the ball at time t > 0 is given by y(t) = -2t² + t + 10. (a) Find the velocity of the object at time t.
(b) Find the acceleration of the object at time t.
(c) Find the velocity of the ball at the time when it hits the ground, i.e. the time t>0 when y(t) = 0. Hint: You could use the quadratic formula to find the value of t*.
(a) The velocity of the object at time t is given by finding the derivative of y (t):
y(t) = -2t2 + t + 10dy(t)/dt
= -4t + 1
Therefore, the velocity of the object at time t is -4t + 1.
(b) The acceleration of the object at time t is given by finding the derivative of the velocity function:
dy(t)/dt = -4t + 1d2y(t)/dt2
= -4
Therefore, the acceleration of the object at time t is -4 m/s2.
(c) The ball hits the ground when y(t) = 0, so we can solve for t by setting -2t2 + t + 10 = 0 and using the quadratic formula:
t = (-b ± (b2 - 4ac)) / (2a), where a = -2, b = 1, and c = 10.
Plugging these values into the formula, we get:
t = (-1 ± (12 - 4(-2)(10))) / (2(-2)) = (1 ± 81) / 4
We take the negative root because the positive root corresponds to the ball reaching its maximum height before falling back down. Thus,
t = (1 - 81) / 4
= -2/4
= -0.5 s
To find the velocity of the ball at this time, we plug t = -0.5 into the velocity function we found in part
(a):v = -4t + 1
= -4(-0.5) + 1
= 3 m/s
Therefore, the velocity of the ball at the time it hits the ground is 3 m/s.
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Guys this is urgent and I don’t know please help me I will mark brainliest!
Have a good day/night!!!
Answer:
Not acted upon there is no motion
Forces acted upon there is motion
You can refer to the definition stated below:
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia. ... If that velocity is zero, then the object remains at rest.
a new trend at automobile dealers is to fill tires with pure nitrogen gas rather than air. what mass of nitrogen gas would be needed to pressurize a tire with a volume of 18.0 liters to 32.0 psi at 25 degrees celsius? 14.7 psi
Therefore, about 0.255 grams of nitrogen gas would be needed to pressurize a tire with a volume of 18.0 liters to 32.0 psi at 25 degrees Celsius using pure nitrogen gas.
To solve this problem, we can use the ideal gas law, which states:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the volume to cubic meters and the pressure to Pascals:
V = 18.0 L
= 0.018 m³
P = (32.0 - 14.7) psi
= 17.3 psi
= 119310 Pa
Next, we need to calculate the number of moles of nitrogen gas needed:
n = PV/RT
where R = 8.314 J/mol·K is the gas constant for nitrogen gas, and T = 25 + 273 = 298 K is the temperature in Kelvin.
n = (119310 Pa × 0.018 m³) / (8.314 J/mol·K × 298 K)
= 0.0091 mol
Finally, we can calculate the mass of nitrogen gas using its molar mass:
m = n × M
where M = 28.014 g/mol is the molar mass of nitrogen gas.
m = 0.0091 mol × 28.014 g/mol
= 0.255 g
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Where in the dwelling policy is it stated that earth movement, landslide, mine subsidence, and mudflow are not covered unless resulting from direct loss by fire or explosion?
common exclusions, Due of their catastrophic character, the aforementioned risks—earth movement, landslide, mine material, and mudflow—are not covered by the dwelling insurance.
The Basic Form is designed on a named dangers basis and only covers the risks of fire, lightning, and internal explosion. It excludes theft and damage to trees, shrubs, and plants.
The Dwelling Policy's Coverage C for Personal Property provides coverage for damaged household and personal property that is being transported between the insured's old and new homes.
What is Dwelling Policy's?
The portion of your homeowners insurance policy known as dwelling coverage, or "dwelling insurance," may assist in covering the cost of repairing or rebuilding the physical structure of your house if a covered hazard causes damage to it.Farm property is not eligible, mobile homes must be firmly affixed to the foundation, and only incidental business is covered if the residence is utilized primarily for domestic purposes.To learn more about Dwelling Policy's visit: https://brainly.com/question/14319237
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Scarlett is playing outside. She knocks her toy train in to the lake. The train has parts that are made of stein and she has a wooden fishing rod. How can the fishing rod be changed to help her find the train?
In order to help Scarlett retrieve her toy train from the lake, the wooden fishing rod can be modified or adapted by Attaching a magnet, Adding a hook or grappling device, and Using a net or scoop.
Attaching a magnet: Scarlett can attach a strong magnet to the end of the fishing rod. Since the train contains parts made of steel, the magnet will be attracted to the metallic components. By carefully maneuvering the magnet with the fishing rod, Scarlett can potentially attract and retrieve the train from the water.
Adding a hook or grappling device: Scarlett can affix a hook or grappling mechanism to the fishing rod. By casting the hook near the location where the train fell into the lake and skillfully maneuvering the rod, she can attempt to hook onto the train or one of its parts. With a successful hook, she can slowly reel in the train and bring it back to shore.
Using a net or scoop: If the toy train is floating on the surface of the lake or near the shallow edges, Scarlett can attach a net or scoop to the end of the fishing rod. By carefully positioning the net or scoop around the train, she can scoop it up and safely retrieve it without causing any damage.
It's important to note that the success of these modifications will depend on factors such as the depth of the lake, the accessibility of the train, and the size and weight of the fishing rod. Additionally, adult supervision or assistance may be necessary to ensure safety, especially if the lake is deep or poses any hazards.
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a rubber ball bounces off of a wall with an initial speed v and reverses its direction so its speed is v right after the bounce. as a result of this bounce, which of the following quantities of the ball are conserved? (there could be more than one correct choice.) a) the momentum of the ball b) both the momentum and the kinetic energy of the ball c) the kinetic energy of the ball d) none of the above quantities are conserved.
Here, both the momentum and kinetic energy of he ball are conserved. There is no change in the magnitude of the speed thus, its kinetic energy is conserved.
What is kinetic energy ?The kinetic energy of an object is the energy generated by virtue of its motion. It is related to its mass and velocity by the expression written below:
Ke = 1/2 mv²
The momentum of an object is the product of its mass and velocity. For an elastic collision both momentum and kinetic energy is conserved. But in the case of an inelastic collision, there is some energy loss and the kinetic energy is not conserved but momentum is conserved.
Here, the ball bounces by colliding with the floor, where its direction is changing but not the magnitude of speed. Hence, both the momentum and kinetic energy are conserved.
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Halley's orbit is a very eccentric (stretched-out) ellipse, so at perihelion Halley's Comet is only about 90 million kilometers from the Sun, compared to more than 5 billion kilometers at aphelion. Does Halley's Comet spend most of its time near its perihelion distance, near its aphelion distance, or halfway in between? Explain.
if the average force of friction is equal to 0.15 of its weight, with what speed will it reach point 2? the distance traveled is 40 m .
At reach point 2, the speed V is equal to 24.9 m/s if the average friction force is equivalent to 0.15 of the its weight.
Describe friction.A force that opposes the rolling or sliding of three stationary surfaces over one another. Although frictional forces, such the traction required to walk without falling, may be advantageous, they can provide a significant amount of resistance to motion. the physical contact of two bodies.
What 3 forms of friction are there?The interaction of a car's tires with the road causes friction, specifically three types of friction: rolled friction, starting turbulence, and sliding friction. This friction is what allows humans to operate cars at all.
Briefing:speed= 1.5m/s
The Initial speed u = 1.5m/s.
point 1 $ point 2 is (39-13) =26m
40 meters is equivalent to an altitude of(40/6) =6.7
kinematics equation v^2 =u^2 + 2as
V^2 = 1.5^2 + 2*9.8 (26 + 6.7)
V = 24.9 m/s
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two reasons lightning might have changed
Lightning might have changed because of climate change and changes in land use
What is a climate change?
Climate change refers to the long-term shifts in global weather patterns, including changes in temperature, precipitation, and wind patterns, caused by human activities such as burning fossil fuels, deforestation, and industrial processes. These changes are leading to rising global temperatures and sea levels, more frequent and severe weather events such as hurricanes, droughts, and floods, and altered ecosystems and habitats for plants and animals.
Therefore, Lightning might have changed because of climate change and changes in land use
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What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?
The radioactive half-life is given by:
\(T_{1/2}=\frac{ln(2)}{\lambda}\)Where:
\(\begin{gathered} T_{1/2}=299\times10^{-9}s \\ so: \\ \lambda=\frac{ln(2)}{299\times10^{-9}} \\ \lambda=2.32\times10^6s \end{gathered}\)Hdhdhdhdhdhgsgdgs
Plls
All the answers are in the pics I have sent. I hope this will help you. Have a good day!
Can you think of a way to explain Hubble's Law other than the
standard Big Bang idea, which includes the concept of a Universe
with no center and no edge?
An alternative way to explain Hubble's Law without relying on the standard Big Bang idea of a universe with no center and no edge is through the concept of a "tired light" hypothesis.
According to this hypothesis, the redshift observed in distant galaxies is not due to their motion away from us in an expanding universe, but rather the result of photons gradually losing energy as they travel through space.
In the tired light scenario, the wavelength of light is thought to stretch over time due to interactions with matter or other unknown processes. As a result, the light from distant galaxies appears redshifted, mimicking the effect of cosmic expansion. This explanation implies that the universe may have a finite size and a center, challenging the notion of an infinite and uniformly expanding universe.
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body composition is?
Answer: body composition is the proportion of fat and non fat mass in your body.
Explanation:
Answer:
Body composition is the percentage of a body's weight
Explanation:
Body composition is the body's amount of fat relative to fat-free mass. Individuals with optimal body composition are typically healthier, move more easily and efficiently, and generally feel better.
How much momentum does a stationary 5500 kg mass have?
Answer:0
Explanation:
All stationary objects have no momentum they do not have any motion to have momentum you need mass and motion
Closed clusters are groups of closely grouped stars that are located along the spiral disk of a galaxy.
True or
False
Answer:
the answer to your question is true
Answer:
false
Explanation:
i took the test
In a tug of war, team A is pulling the rope with a force of 60N towards the right and team B also applies 60N towards the left, what is the net force?
Answer:
\(f_n_e_t=0\)
Explanation:
\(f_1+f_2=f_n_e_t\)
because there are two different forces in different directions (left: negative, right: positive, down: negative, up: positive) so 60N left will be negative, and 60N right will be positive:
\(60+(-60)=0\)
when two same forces apllied then the net force is zero.
What is the volume of the shape below?
Help me plzzzz
Answer:
20cm
Explanation:
2 × 5 × 2 = 20
Hope this helps.