Answer:
the domain is the legal values of x, while the range is all the legale values of y
Step-by-step explanation:
Jenny has saved $600 from her summer job during the school year she withdraws $20 from her account every week for her daily expenses she wants to keep more than $300 in the account for college the number of weeks w that Jenny can withdraw money from her account is represented by the inequality 600 - 20 w >300 how many weeks can Jenny continue to withdraw $20 from her account
Answer:
Step-by-step explanation:
The inequality that represents Jenny's situation is:
600 - 20w > 300
To solve for w, we can start by subtracting 600 from both sides of the inequality:
-20w > 300 - 600
-20w > -300
Next, we can divide both sides by -20, remembering to reverse the direction of the inequality because we are dividing by a negative number:
w < (-300) / (-20)
w < 15
Therefore, the number of weeks that Jenny can continue to withdraw $20 from her account is less than 15. Since Jenny cannot withdraw a fractional number of weeks, the largest whole number of weeks that satisfies the inequality is 14.
Therefore, Jenny can continue to withdraw $20 from her account for 14 weeks while still keeping more than $300 in her account for college.
Find the area and perimeter of a square whose side length is
2x+3
Answer:
Area = 4x^2 + 12x + 9
Perimeter = 8x + 12
Step-by-step explanation:
wHAT IS THE REFERENCE ANGLE -935°
Find the solution of the differential equation that satisfies the given initial condition.
Answer:
\(y = \sqrt{x^2+4}\)
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the solution of the differential equation that satisfies the given initial condition. dy/dx = x/y, y(0) = -2
Using the variable separable method.
Step 1: Separate the variables
dy/dx = x/y
x dx = y dy
Step 2: Integrate both sides of the resulting equation
\(\int\limits {x} \, dx = \int\limits{y} \, dy\\\frac{x^2}{2} = \frac{y^2}{2} \\ \frac{y^2}{2} = \frac{x^2}{2} + C\\y^2 = x^2 + 2C\\y^2 = x^2 + K; K = 2C\)
Note that the constant of integration added to the side containing x
Step 3: Apply the initial condition y(0) = -2
This means when x = 0, y = -2. From step 2:
\(y^2+x^2 = K\\(-2)^2+0^2 = K\\4 = K\)
Step 4: Substitute K = 4 into the resulting differential equation above
\(y^2=x^2+4\\y = \sqrt{x^2+4}\)
This gives the solution to the differential equation.
Is the answer (-1,1)???
Answer:
yes
Step-by-step explanation:
Answer:
(1 , -1)
Step-by-step explanation:
7( 1 ) - 3( -1 ) = 10
7 - - 3 = 10
7 + 3 = 10
10 = 10
true
Part A: Solve the equation 4(x + 5) = 9x + 4x − 34, and show your work. (5 points) Part B: Use this list of properties to justify each step of your math work. Justifications may be used more than once if needed
What fraction represents the solution of 4p5 + 3 = 37 + 5p ?
Answer:
Step-by-step explanation:
p = 8
Two same-sized triangular prisms are attached to a rectangular prism as shown below.
If a = 20 cm, b = 13 cm, c = 12 cm, d = 5 cm, and e = 8 cm, what is the surface area of the figure?
Answer:1,208 square centimeters
Step-by-step explanation:
A piece of rope falls out of a hot air
balloon from a height of 5,184 ft. If the
equation for height as a function of time
is h(t) = -16t2 - initial height where t is
time in seconds and h(t) is height in feet,
how many seconds will it take for the
piece of rope to hit the ground?
==========================================
Explanation:
The equation should be h(t) = -16t^2 + (initial height). If you subtract off the initial height, then you'll have a negative starting height, which is not correct. Try plugging t = 0 into h(t) = -16t^2 - (initial height) and you'll see what I mean.
The initial height is 5184. We want to find the t value when h(t) = 0. So we want to find the time value when the height is 0.
--------------
h(t) = -16t^2 + (initial height)
h(t) = -16t^2 + 5184
0 = -16t^2 + 5184
16t^2 = 5184
t^2 = 5184/16
t^2 = 324
t = sqrt(324)
t = 18
It takes 18 seconds for the rope to hit the ground.
Which of the scenarios below are considered seller-based discounts? options are in the picture
The scenarios that can be considered a seller-based discount are:
A. The offer by Wire and Cable
B. Carfna's Fine Foods
C. Mouser Electronics offer
E. Carchex Car Maintenance
What is a seller-based discount?A seller-based discount is a discount that is offered by a seller for the early purchase of a product. The goal of the seller in this case is to get cash as he or she is in an immediate need for cash.
The most outstanding example is that of Carchex Car Maintenance where an offer is made by the seller for the early purchase of products.
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36 divided by m over x times 9
Answer:
Step-by-step explanation:
4/mx
Simplify.
33+5⋅5
52
58
70
190
Answer:
38.5 is your answer of this questions
Answer:
58
Step-by-step explanation:
5x5= 25
33+25
=58
use BODMAS
Bracket of division, multiplication; addition, subtraction
Ms. Thomspon needs 15/2 yards of red fabric and 7 1/2 yards of silver fabric. which comparison is true.
Step-by-step explanation:
To compare the two amounts of fabric, we need to express them with a common denominator:
15/2 = 30/4
7 1/2 = 15/2
Now we can compare the two amounts:
30/4 > 15/2
This is true because 30/4 is equal to 7.5 yards, which is greater than 7.5 yards (or 15/2 yards) of silver fabric.
Therefore, Ms. Thompson needs more red fabric than silver fabric.
what is the length of segment ns
Given that x is equal to 1 and S is the centroid of the triangle NLQ, NS will have a length of 4 units.
What is centroid?The centroid of a flat figure or solid figure, also known as the geometric center or center of figure, in mathematics and physics, is the arithmetic mean position of all the points on the figure's surface. Any n-dimensional Euclidean object is included by the same definition. The centroid of a triangle is the location where the triangle's three medians connect. It may alternatively be described as the location where the three medians come together. A line connecting a side's midpoint and the triangle's opposite vertex is called the median.
Here,
We may infer from the centroid's features that it divides each median in a ratio of 2:1.
NS=2SR
7x-3=2(5x-3)
7x-3=10x-6
3x=3
x=1
NS=7x-3
=7*1-3
=4 units
The length of NS will be 4 units as the value of x is 1 and S is the centroid of triangle NLQ.
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need help asap please!!
Answer:
\(v=46\\\)
Step-by-step explanation:
Simply:
\(-v=-46\)
An election ballot asks voters to select five city commissioners from a group of eighteen candidates. In how many ways can this be done?
Number of ways to select five city commissioners from a group of eighteen candidates is equal to 8568.
As given in the question,
Total number of candidates = 18
An election ballot asks voters to select five city commissioners from 18 candidates
Number of ways to select 5 city commissioners from a group of 18 candidates
= ¹⁸C₅
= ( 18!) ) / (5!)(18 - 5)!
= (18!) / (5!)(13!)
= ( 18 ×17×16×15×14×13! ) / ( 5×4×3×2×1 )( 13! )
= 8568
Therefore, number of ways to select five city commissioners from a group of eighteen candidates is equal to 8568.
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Can someone explain this equation to me? (#66)
66. For equation -1.48 = (x - 30)/4, the value of x is 24.08. 68. For equation 0.88 = 22,000.44/σ, the value of σ is 25,000.5.
Describe Equation?An equation is a mathematical statement that shows the equality between two expressions, using symbols and mathematical operations. An equation typically contains variables, which are symbols representing unknown values, and constants, which are known values. The variables can be solved for using algebraic methods to find their specific value(s) that make the equation true.
Equations can take many forms, depending on the mathematical context. For example, a linear equation has the form y = mx + b, where y and x are variables, m is the slope of the line, and b is the y-intercept. Quadratic equations have the form ax² + bx + c = 0, where a, b, and c are constants and x is the variable. There are many other types of equations, such as trigonometric equations, logarithmic equations, and differential equations, each with their own specific form and properties.
66. -1.48 = (x - 30)/4
To solve for x, we can begin by multiplying both sides by 4:
-1.48 * 4 = x - 30
-5.92 = x - 30
Next, we add 30 to both sides to isolate x:
-5.92 + 30 = x
x = 24.08
Therefore, the solution is x = 24.08.
68. 0.88 = 22,000.44/σ
To solve for σ, we can begin by multiplying both sides by σ:
0.88σ = 22,000.44
Next, we divide both sides by 0.88 to isolate σ:
σ = 22,000.44/0.88
σ = 25,000.5
Therefore, the solution is σ = 25,000.5.
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x2 + y2 - x- 2y - 11/4= 0
What are the coordinates for the center of the circle and the length of the radius?
Answer: the answer is 21
Step-by-step explanation:
first, u divide the odd and positive numbers last u divide the both answers and it should be the answer
What is the meaning of "the notion of finiteness"?
The notion of finiteness refers to the idea that something has a definite limit or is not infinite. It is a concept that has been applied in various fields of study, such as mathematics, computer science, and philosophy.
In mathematics, finiteness is a fundamental concept used to define various mathematical objects and structures, such as sets, numbers, and sequences. It is also used to define the properties of functions and to study the properties of mathematical systems.
In computer science, the notion of finiteness is crucial for the design and analysis of algorithms and computer programs. Computer scientists use finite state machines, which are mathematical models that describe the behavior of a system that can be in one of a finite number of states.
This concept is essential to the development of computer programs that are efficient, reliable, and secure.
In philosophy, finiteness is a concept that is often used to reflect on the nature of human existence and the limits of human knowledge. It is also used to examine the concept of time and the nature of reality.
In general, the notion of finiteness is a fundamental concept that has many applications in various fields of study.
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PLEASE IT DUE SOON!!! DONT EVEN KNOW WHERE TO START IM SO CONFUSED!!!
QUESTION DOWN BELOW!! ONLY HAVE 20MIN SO PLEASE SOMEONE!!
A test point which is in the solution set for the linear inequality is: C. (-2, 4).
How to determine the true test point?In order to determine which ordered pairs is a true solution based on the given linear inequality, we would have to test each of the ordered pairs by substituting their values into the linear inequality as follows;
For ordered pair (-2, -4), we have:
2x - 9y < 0
2(-2) - 9(-4) < 0
-4 + 36 < 0
32 < 0 (False).
For ordered pair (-1, -5), we have:
2x - 9y < 0
2(-1) - 9(-5) < 0
-2 + 45 < 0
43 < 0 (False).
For ordered pair (-2, 4), we have:
2x - 9y < 0
2(-2) - 9(4) < 0
-4 - 36 < 0
-40 < 0 (True).
For ordered pair (-1, -1), we have:
2x - 9y < 0
2(-1) - 9(-1) < 0
-2 + 9 < 0
7 < 0 (False).
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what's the answer?!!!
Answer:
6(y-2) would be 6y-12
Step-by-step explanation:
new number in sequence
3, 5, 12, 55, 648, ?
A team of 5 IT specialists is to be selected to attend a lecture from 16 IT specialists. In how
many different ways can the team be formed?
124
4368
480
2880
Answer:
\( 16C5= \frac{16!}{5! (16-5)!}= \frac{16!}{5! 11!}= \frac{16*15*14*13*12*11!}{5! 11!}\)
If we simplify we got:
\( 16C5 = \frac{16*15*14*13*12}{5*4*3*2*1}=4368\)
And the best option would be:
4368
Step-by-step explanation:
For this case we have a total of 16 IT specialists and we want to select 5 IT specialists from the total of 16 so we can use the combination formula given by:
\( nC x= \frac{n!}{x! (n-x)!}\)
And replacing we got:
\( 16C5= \frac{16!}{5! (16-5)!}= \frac{16!}{5! 11!}= \frac{16*15*14*13*12*11!}{5! 11!}\)
If we simplify we got:
\( 16C5 = \frac{16*15*14*13*12}{5*4*3*2*1}=4368\)
And the best option would be:
4368
If Fran were to paint her living room alone, it would take 6 hours. Her sister Denise could do the job in 8 hours. How many hours would it take them working together? Express your answer as a fraction reduced to lowest terms, if needed.
It would take Fran and Denise (working together) approximately \(\frac{24}{7}\) hours to paint the living room.
To solve this problem, we can use the concept of "work rates."
Let's find out how much work Fran and Denise can do individually in one hour.
If Fran takes 6 hours to paint the living room alone, her work rate is \(\frac{1}{6}\) of the room per hour \((\frac{1 room}{6 hours } = \frac{1}{6}room/hour )\).
Similarly, if Denise takes 8 hours to paint the living room alone, her work rate is \(\frac{1}{8}\) of the room per hour \((\frac{1 room}{8 hours } =\frac{1}{8}room/hour )\).
When they work together, their work rates are additive.
So, their combined work rate would be:
\(\frac{1}{6} room/hour+\frac{1}{8} room/hour\)
\(=(\frac{4}{24} )room/hour + (\frac{3}{24} )room/hour\)
\(=\frac{7}{24} room/hour\)
This means that working together, Fran and Denise can paint \(\frac{7}{24}\) of the living room in one hour.
To determine the total time required for them to paint the entire room, we can invert their combined work rate:
\(\frac{(1 room) }{(\frac{7}{24}room/hour) } =\frac{24}{7}hour\)
Therefore, it would take Fran and Denise (working together) approximately \(\frac{24}{7}\) hours to paint the living room.
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Two ropes are attached to a wagon, one horizontal to the west with a tension force of 30N, and the other east and at an angle of 30 degrees northward and a tension force of 40 N. Find the components of the net force on the cart. Show all work.
The net force on the cart is 62N
and the vertical component =36.64 N
the horizontal component= 50N
What is revolution of vector?
The process of splitting a vector into its components is called resolution of the vector. We resolve a vector into two components which are. component along the x-axis called horizontal component. component along the y-axis called vertical component
30N tension on the cart is westward which mean the vertical component will be 0 and the horizontal component will be 30N.
40N tension isN 30° E which means
the vertical component= 40 sin60=36.64N
Horizontal component= 40 cos 60= 20N
sum of vertical = 36.64N +0= 36.64N
sum of horizontal= 30N+20N= 50N
60° was used for tension 40N because the angle of vector must always lie on the horizontal axis
therefore the net force F is obtained by using Pythagoras theorem
F= √(50^2+36.64^2)
= 62N to the nearest whole number.
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PLEASE HURRY! WILL MARK BRAINLIEST IF CORRECT (Screenshot)
Answer:
The length of XY is 22.5
Step-by-step explanation:
Since you need to hurry I will not write an explanation
Hope this helps! :)
૮ ・ﻌ・ა
Use the factor theorem to determine whether or not the first polynomial is a factor of the second
Answer/Step-by-step explanation:
Based on the factor theorem, a polynomial, x - a, is said to be a factor of another polynomial, f(x), if an only if f(a) = 0.
Using this theorem, let's determine whether each of the given first polynomial, is a factor of the second polynomial.
1. x - 1; x² + 2x + 5
By the factor theorem, x - 1 will be a factor of f(x) = x² + 2x + 5, if and only if f(1) = 0.
f(1) = 1² + 2(1) + 5
= 1 + 2 + 5
= 8
Since f(1) ≠ 0, therefore the first polynomial, x - 1, is NOT a factor of the second polynomial, x² + 2x + 5.
2. x + 1; x³ - x - 2
By the factor theorem, x + 1 will be a factor of f(x) = x³ - x - 2, if and only if f(-1) = 0.
f(1) = -1³ - (-1) - 2
= -1 + 1 - 2
= -2
Since f(-1) ≠ 0, therefore the first polynomial, x + 1, is NOT a factor of the second polynomial, x³ - x - 2.
3. x - 4; 2x³ - 9x² + 9x - 20
By the factor theorem, x - 4 will be a factor of f(x) = 2x³ - 9x² + 9x - 20, if and only if f(4) = 0.
f(4) = 2(4)³ - 9(4)² + 9(4) - 20
= 128 - 144 + 36 - 20
= 0
Since f(4) = 0, therefore the first polynomial, x + 4, is a factor of the second polynomial, 2x³ - 9x² + 9x - 20.
4. a - 1; a³ - 2a² + a - 2
By the factor theorem, a - 1 will be a factor of f(a) = a³ - 2a² + a - 2, if and only if f(1) = 0.
f(1) = 1³ - 2(1)² + 1 - 2
= 1 - 2 + 1 - 2
= -2
Since f(1) ≠ 0, therefore the first polynomial, a - 1, is NOT a factor of the second polynomial, a³ - 2a² + a - 2.
5. y + 3; 2y³ + y² - 13y + 6
By the factor theorem, y + 3 will be a factor of f(y) = 2y³ + y² - 13y + 6, if and only if f(-3) = 0.
f(-3) = 2(-3)³ + (-3)² - 13(-3) + 6
= -54 + 9 + 39 + 6
= 0
Since f(-3) = 0, therefore the first polynomial, y + 3, is a factor of the second polynomial, 2y³ + y² - 13y + 6.
Evaluate each expression if a=2,b=-3,C=-1, and d=4
5+d(3b-2d)
Answer:
it's simple, put the values in the equation.
5 + d( 3b-2d) = 5 + 4( 3×-3 - 2× 4)
= 5 + 4( -9-8)
= 5+ 4 × -17
= 5-68 = -63 ans.
g (1 point) Find the angle between the diagonal of a cube of side length 8 and the diagonal of one of its faces, so that the two diagonals have a common vertex. The angle should be measured in radians. (Hint: we may assume that the cube is in the first octant, the origin is one of its vertices, and both diagonals start at the origin.)
Answer:
Angle between the diagonal of a cube of side length 8 and the diagonal of one of its faces is equal to \(0.6155\) radian
Step-by-step explanation:
Please see the attached image for better understanding
Length of OB is equal to
\(\sqrt{19^2 + 19^2 }\)
\(19\sqrt{2}\)
Now the length of OE is equal to
\(\sqrt{19^2 + 19^2 + 19^2 } = 19 \sqrt{3}\)
Now Angle BOE is equal to
\(cos^{-1} (\frac{722}{19\sqrt{2}* 19\sqrt{3} }) = 0.6155\) radians
Angle between the diagonal of a cube of side length 8 and the diagonal of one of its faces is equal to \(0.6155\) radian
Rewrite each of these statements so that negations appear only within predicates (that is, so that no negation is outside a quantifier or an expression involving logical connectives). a) ¬∃y∃xP (x, y) b) ¬∀x∃yP (x, y) c) ¬∃y(Q(y) ∧ ∀x¬R(x, y)) d) ¬∃y(∃xR(x, y) ∨ ∀xS(x, y)) e) ¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU(x, y, z))
The rewritten statements are 1. ∀x∃y¬P(x, y), 2. ∃y∃x¬(P(x, y)∨Q(x, y)), 3. (∃x∃yP(x, y)∨∃x∃y¬Q(x, y)), and 4. ∃x(∀y∀z¬P(x, y, z)∧∀z∀y¬P(x, y, z)).
1. ∀x∃y¬P(x, y) - This statement states that for all x, there exists a y such that P(x, y) is not true. This rejects the statement "there exists x such that for all values of y, P(x, y) is true."
2. ∃y∃x(¬P(x, y)∧¬Q(x, y)) - This statement states that there exists a y and x such that both P(x, y) and Q(x, y) are not true. This rejects the statement, "for all the values of y and x, either P(x, y) or Q(x, y) will be true."
3. ∃x∀y¬P(x, y)∨∃x∀y¬Q(x, y) - This statement states that either there exists x such that for all y, P(x, y) is not true or there exists x such that for all y, Q(x, y) is not true. This rejects the statement, "for all the values of x, there exists y such that both P(x, y) and Q(x, y) will be true."
4. ∀x(¬∃y∃zP(x, y, z)∧¬∃z∀yP(x, y, z)) - This statement states that for all x, it is not the case that there exists y and z such that P(x, y, z) is true, and it is also not the case that there exists z such that for all y, P(x, y, z) is true. This rejects the statement "for all x, either there exists y and z such that P(x, y, z) is true, or there exists z such that for all y, P(x, y, z) is true."
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--The given question is incomplete; the complete question is
"Rewrite each of these statements so that negations appear only applied to predicates (that is, so that no negation is outside a quantifier or an expression involving logical connectives).
1. ¬∃x∀yP(x, y)
2. ¬∀y∀x(P(x, y)∨Q(x, y))
3. ¬(∃x∀y¬P(x, y)∧∀x∀yQ(x, y))
4. ¬∀x(∃y∃zP(x, y, z)∨∃z∀yP(x, y, z))"--