Describe two pieces of evidence that support the hypothesis that an asteroid impact was responsible for the iridium anomaly.

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

Answer:

The change in momentum experienced by the bowling ball is 96 kgm/s.

Explanation:

Given;

mass of the bowling ball, m = 12 kg

velocity of the bowling ball, v = 8 m/s

time  of motion, t = 10 s

The change in momentum experienced by the bowling ball is equal to the impulse experienced by the bowling ball.

ΔP = J = F x t

\(J = ft =\frac{mv}{t} \times t = mv\\\\J = 12 \times 8\\\\J = 96 \ kg.m/s\)

Therefore, the change in momentum experienced by the bowling ball is 96 kgm/s.

Table A agrees with the information in the problem. After 25.0 seconds, the velocity of the plane is 187 m/s.

Based on the given problem, we need to determine the velocity of a plane after 25.0 seconds. The plane is initially flying east at a velocity of 115 m/s, and it experiences an acceleration of 2.88 m/s² in the northwest direction.

Let's analyze each option and calculate the final velocity (Vf) of the plane after 25.0 seconds:

Option A:

Vi = 115 m/s

a = 2.88 m/s²

t = 25.0 s

Using the equation Vf = Vi + at, we can calculate:

Vf = 115 m/s + (2.88 m/s²)(25.0 s) = 115 m/s + 72 m/s = 187 m/s

Option B:

V₁ = 2.04 m/s

a = 2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 2.04 m/s + (2.04 m/s²)(25.0 s) = 2.04 m/s + 51 m/s = 53.04 m/s

Option C:

V₁ = 115 m/s

a = -2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 115 m/s + (-2.04 m/s²)(25.0 s) = 115 m/s - 51 m/s = 64 m/s

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We can see here that the diagram that reveals the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems is seen below.

A photon is a fundamental particle or quantum of light.

It is the smallest indivisible unit of electromagnetic radiation, which also includes radio waves, microwaves, X-rays, visible light, ultraviolet light, and infrared radiation. In scientific calculations, photons are represented by the symbol "c" and move at the speed of light in a vacuum while carrying energy.

Wave-particle duality is the idea that photons are both particles and have wave-like characteristics. This means that they can exhibit wave-like properties like interference and diffraction as well as discrete particle behavior, each with a distinct energy and momentum.

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The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.

The groups in periodic table is the same as vertical columns in the periodic table

These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.

Examples of elements found in the same group with similar chemical properties include;

group 7 elements.

The valence electron of elements found in the group 7 of periodic table is negative 1 (-1).

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The Phase shift is a shift in sound wave frequency that happens when the originator of the acoustic pressure is moving in relation to a listener who is stationary.

As an observer and a mobile source of waves come closer together, there appears to be an upward shift in frequency, and when they move apart, there appears to be a downward movement in frequency. This phenomenon is known as the Doppler effect.

Doppler shift is frequently demonstrated by the change in pitch that occurs as a car approaches and moves away from a viewer while sounding its horn. The received frequency increases during proximity, identical at the time of passing by, and lower when matched to the emitted frequency.

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Answer:

Yes, of course

Explanation:

Answer: 17

Explanation: Atomic number = mass number - number of neutrons

In this case, the mass number is given as 35 and the number of neutrons is given as 18. So, we can plug these values into the equation and solve for the atomic number:

atomic number = 35 - 18

atomic number = 17

Therefore, the atomic number of the atom is 17.

The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.

The percent uncertainty in measuring the light weight object is calculated as follows;

\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)

The uncertainty of the heavy object if the scale remains constant is calculated as follows;

\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)

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Answer:

the universe is everything

and it is getting bigger and bigger

galaxies are small parts of universe

Explanation:

Thats all i know

The correct order of the organization levels from smallest to largest is nucleus, cell, tissue and organ.

Living organisms have different forms of classification, one of them is from the levels of organization. This classification refers to complexity and size. The levels from least to greatest complexity are:

Thus, we can conclude that the correct order of the organization levels from smallest to largest is nucleus, cell, tissue and organ.

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The work done by the lift with a mass of 1050 kg and a gravitational field strength is 10 N/kg and a height of 15m is 157.5kJ

The work done is the amount of work done in lifting the object to a certain distance. The work done is the product of mass, gravitational field, and height.

Work done = m×g×h

mass (m) = 1050 kg

        g     = 10 N/kg

height (h) = 15m

W = m×g×h

   = 1050×10×15

  = 157.5 kJ

Thus, the work done(W) = 157.5 kJ.

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Answer:

Diffusion

Increase

I hope that helped

Answer:

static and current electricity

This question involves the concepts of heat capacity, temperature, and heat.

The heat absorbed by ethanol is "1228 cal".

The heat capacity of a substance is defined as the amount of heat absorbed by a unit amount of that substance for a degree rise in temperature. Mathematically,

\(Q = mc\Delta T\)

where,

Therefore,

Q = (50 g)(0.614 cal/g°C)(40° C)

Q = 1228 cal

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The compressive stress in the steel column is found to be approximately 397.6 MPa.

The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),

A = π*(d/2)², diameter of the column is d,

A = π*(0.4/2)²

A = 0.1257m²

The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.

σ = 50 MN/0.1257m²

σ = 397.6 MPa

Therefore, the compressive stress in the steel column is approximately 397.6 MPa.

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Explanation:

To find the acceleration of the rocket, we need to use the equations of motion for constant acceleration.

We know that the bolt was dropped 5 seconds after the rocket was launched, and that it took 10 seconds for the bolt to hit the ground. This means that the bolt was in free fall for 10 - 5 = <<10-5=5>>5 seconds.

We can use the equation d = 1/2 * a * t^2 to find the acceleration of the bolt. We know that the bolt fell a distance of 10 meters in 5 seconds, so we can plug those values into the equation to get: 10 = 1/2 * a * 5^2. Solving for a gives us a = 2 * 10 / 5^2 = 2 * 10 / 25 = 0.8.

Since the bolt was in free fall, its acceleration was due to gravity, which is about 9.8 meters per second squared. This means that the rocket must have had an acceleration greater than 9.8 meters per second squared in order to cause the bolt to fall off of it.

Therefore, the rocket's acceleration must have been greater than 0.8 meters per second squared. However, we cannot say exactly what the acceleration was without knowing more information about the rocket and its launch conditions.

The acceleration of the rocket is 197.5 m/s² if the bolt hits the ground 10.0 s later.

A branch of physics called kinematics, which was evolved from classical mechanics, defines how points, bodies, and systems of bodies (groups of objects) move without taking into account the forces that propel them. The discipline of kinematics is sometimes thought of as a subfield of mathematics and is sometimes referred to as the "geometry of motion." Any known values of the location, velocity, and/or acceleration of points inside the system are declared as initial conditions for a kinematics issue, together with the geometry of the system. The location, velocity, and acceleration of any unidentified system components can then be calculated using geometrical considerations. Kinematics, not kinematics, is the study of forces and their effects on physical objects. For further information, visit.

Given,

time of the bolt = 10-5 =5s

acceleration due to gravity =9.8m/s²

The height of the bolt s = ut+1/2at²

s = 0+ 1/2 ×9.8×5²

s = 122.5m

We cannot find the acceleration of the rocket without its final velocity (velocity of the rocket at the time of fall of bolt). Therefore Consider the final velocity of the Rocket is 220m/s

Then,

v² = u² + 2as

220² = 0 +2×a×122.5

48400 = 245 a

a = 197.5 m/s²

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The mass of a pure platinum disc can be gotten by multiplying the density with the volume.

Therefore the mass is 2418.2 grams or 2.4182 kilograms.

A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.

The kilogram is the primary mass unit in the SI.

The resistance of the body to acceleration in the presence of a net force can be measured as mass.

Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.

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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.

Give your answer in grams and kilograms.

A) The net electric flux through the closed surface S₁ is given by the equation: Net electric flux = q1/4πε0
= 4.45 nC / (4π x 8.85 x 10-12 C2/Nm2)
= 0.541 x 10-3 Nm2/C .

Electricity is a form of energy that exists in nature and is created through the movement of electrons between atoms. It is the force that powers all of the electrical appliances and devices in our homes and offices.

B) The net electric flux through the closed surface S₂ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0
= (4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10-12 C2/Nm2)
= -2.05 x 10-3 Nm2/C
C) The net electric flux through the closed surface S₃ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0
= (4.45 nC + (-7.50 nC) + 2.15 nC) / (4π x 8.85 x 10-12 C2/Nm2)
= -0.239 x 10-3 Nm2/C
D) The net electric flux through the closed surface S₄ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0
= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC) / (4π x 8.85 x 10-12 C2/Nm2)
= 0.302 x 10-3 Nm2/C

E) The net electric flux through the closed surface S₅ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0 + q2/4πε0
= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10-12 C2/Nm2)
= -1.75 x 10-3 Nm2/C.

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A) The net electric flux through the closed surface S₁ is given by the equation: Net electric flux = q1/4πε0

= 4.45 nC / (4π x 8.85 x 10⁻¹² C²/Nm²)

= 0.541 x 10⁻³ Nm²/C .

Electricity is a form of energy that exists in nature and is created through the movement of electrons between atoms. It is the force that powers all of the electrical appliances and devices in our homes and offices.

B) The net electric flux through the closed surface S₂ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0

= (4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10⁻¹² C²/Nm²)

= -2.05 x 10⁻³ Nm²/C

C) The net electric flux through the closed surface S₃ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0

= (4.45 nC + (-7.50 nC) + 2.15 nC) / (4π x 8.85 x 10⁻¹² C²/Nm²)

= -0.239 x 10⁻³ Nm2/C

D) The net electric flux through the closed surface S₄ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0

= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC) / (4π x 8.85 x 10-12 C²/Nm²)

= 0.302 x 10⁻³ Nm²/C

E) The net electric flux through the closed surface S₅ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0 + q2/4πε0

= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10⁻¹² C²/Nm²)

= -1.75 x 10⁻³ Nm²/C.

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Answer:

2 hours

Explanation:

The motorcycle travels 40 km per hour.

80km / 40km/h = 2 hours.

Answer

2 hours

Explanation:

i took it

It takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

The formula for radioactive decay is \(A = A0 * (1/2)^{(t/t1/2)}\) where: A is the final activity A0 is the initial activity is the time elapsed t1/2 is the half-life of the sample

In this problem, the initial activity A0 is given as 1.07 x 105 Bq and the final activity A is given as 100 Bq.

The half-life of the sample is given as 5.7 days.

Substituting these values into the formula, we get: \(100 = 1.07 \times 105 * (1/2)^{(t/5.7)}\)

Dividing both sides by 1.07 x 105, we get:

\(0.000934579 = (1/2)^{(t/5.7)}\)

Taking the natural logarithm of both sides, we get:\(-7.072737 = (t/5.7) * ln(1/2)\)

Dividing both sides by ln(1/2), we get:

\(t = -7.072737 \div ln(1/2) * 5.7t \approx 28.3\) days

Therefore, it takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

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Answer: 550 cm

Explanation:

Original equation: 1/f= 1/do + 1/di.

F=50.0 cm, and do=55.0.

Since we don't have di, we'll have to subtract do to the other side, making the equation: 1/f - 1/do= 1/di.

Doing the math, 1/f - 1/do is 0.0018181818

Then to get di by itself, you multiply both sides by di. Then you divide by 0.0018181818 to get di by itself. You then get: di= 1/0.0018181818

At that point, you just divide 1 by 0.0018181818, which will give you 550 cm

There could be simpler way, but that is just what I did to get the answer. Answer was right on Acellus

The weight of sulphuric acid in the acid is 488.3 grams.

Specific gravity is a comparing tool used to compare weight of a specific liquid when compared to same unit of water as standard substance.

Specific gravity can be defined as the ratio of the density of a substance to that of a standard substance. Water being the standard substance here.

Let us consider the weights for 1 Liter of acid

Weight of 1 liter of water is 1000gram

Therefore weight of 1 liter of acid=1.285 x 1000 =1285 gram

It is given that the acid is 38 percent by weight of sulphuric acid

Therefore, weight of sulphuric acid= 38% of 1285 gram

weight of sulphuric acid = 38/100 x 1285

                                         =488.3 gram

Therefore, weight of sulphuric acid in the acid is 488.3 gram

Hence, the weight of sulphuric acid in the acid is 488.3 grams

Disclaimer:

Quantity of acid has not been mentioned and hence 1 liter has been taken as the quantity.

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The answer is "the product of the object's moment of inertia and the object's angular velocity.

The correct definition of angular momentum would be that it is the product of the object’s moment of inertia and the object’s angular velocity, therefore the correct answer is option A.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem we have to find the correct definition of angular momentum,

The angular momentum of the object = the moment of the inertia of the object × the angular velocity of the particle

The right response is option A since the definition of angular momentum is that it is the product of an object's moment of inertia and its angular velocity.

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Note the rate at which oil is flowing is: 7.19 m³/s . See the computation below.

We can use the principle of continuity of flow to solve this problem. According to this principle, the mass flow rate of the oil is:

m_dot = rho * A * v: where:

rho is the density of the oil,

A is the cross-sectional area of the pipe, and

v is the velocity of the oil.

The cross-sectional area of the pipe before the constriction is:

A1 = (pi/4) * d1² = (pi/4) * (0.978 m)² = 0.7526 m²

The cross-sectional area of the pipe after the constriction is:

A2 = (pi/4) * d2² = (pi/4) * (0.5868 m)² = 0.2701 m²

The velocity of the oil can be calculated using the principle of continuity of flow:

A1 * v1 = A2 * v2

where v1 is the velocity before the constriction and v2 is the velocity after the constriction.

Solving for v1, we get:

v1 = (A2/A1) * v2 = (0.2701 m^2 / 0.7526 m^2) * v2 = 0.3590 * v2

The pressure difference across the constriction is:

deltaP = P1 - P2 = 7600 N/m² - 5700 N/m² = 1900 N/m²

Using Bernoulli's equation, we can relate the pressure difference to the velocity difference:


deltaP = (1/2) * rho * (v2² - v1²)

Substituting the expression for v1, we get:

deltaP = (1/2) * rho * (v2² - 0.1290 * v2²)

Solving for v2, we get:

v2 = sqrt(2 * deltaP / rho * (1 - 0.1290)) = 20.16 m/s

Finally, the mass flow rate of the oil is:

m_dot = rho * A1 * v1 = 821 kg/m³ * 0.7526 m² * 0.3590 * 20.16 m/s
= 5904.4 kg/s

Converting to cubic meters per second, we get:

Q = m_dot / rho = 5904.4 kg/s / 821 kg/m³ = 7.19 m³/s

Therefore, the rate at which oil is flowing is 7.19 m³/s

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Answer:

\(I_{2}=2.39*10^{-5} W/m^{2}\)

Explanation:

The definition of the intensity in terms of power is given by:

\(I=\frac{P}{A}\)

Where:

If the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.

Let's recall the area of a sphere is \(A = 4\pi R^{2}\)

To the first location we have:

\(I_{1}=3*10^{-4} W/m^{2}=\frac{P}{4\pi 22^{2}}\)

and to the second location we have:

\(I_{2}=\frac{P}{4\pi 78^{2}}\)

Now, we can divide each intensity to find the second intensity.

\(\frac{I_{2}}{I_{1}}=\frac{\frac{P}{4\pi 78^{2}}}{\frac{P}{4\pi 22^{2}}}\)

\(I_{2}=I_{1}* \frac{22^{2}}{78^{2}}\)

\(I_{2}=3*10^{-4}\frac{22^{2}}{78^{2}}\)

\(I_{2}=2.39*10^{-5} W/m^{2}\)

I hope it helps you!

Answer:

I = 2.4*10⁻⁵ W

Explanation:

       \(I = \frac{P}{4*\pi *r^{2}} (1)\)

       \(P = I*4*\pi *r^{2} = 3.0e-4*4*\pi * (22m)^{2} = 1.83 W (2)\)

       \(I = \frac{P}{4*\pi *r^{2}} = \frac{1.83W}{4*\pi *(78m)^{2}} =2.4e-5 W/m2 (3)\)

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

Answer:

I and II

Explanation:

They are made of metal so they are great conductors

Answer:

l and ll

Explanation:

Answer:

he tripped ballanced forces ballanced forces