Resultant force direction = 11.08 degrees counter-clockwise from the positive x-axis.
In order to address this issue, we must first divide these forces into their corresponding x and y components, which we must then combine to determine the final force.
Given the magnitude of force (F1) = 32kN
The angle of direction (θ1) = 30°
F1x = -32k x cos(30°) = -27.7kN
F1y = -32 x sin(30°) = -16kN
Given a triangle, let cos(θ) = 5/13 = 0.99 then θ = 67.3°
The magnitude of force F2 = 26kN
The angle of direction (θ2) = 0.99°
F2x = -26 x cos(67.3°) = 10.03kN
F2y = 26 x sin(67.3°) = 23.9kN
Frx = F1x + F2x = -37.73kN
Fry = F1y + F2y = 7.9kN
Let the resultant force = Fr then,
Fr^2 = Frx^2 + Fry^2
Fr^2 = (-37.73)^2 + (7.9)^2
Fr = √1423.55+62.41 = √1485.96 = 38.5kN
Hence the resultant force = 38.5kN
θ = tan^-1(Fry/Frx) = tan^-1(7.9/-37.73) = -11.08°
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Discuss the circuits.
Name all the
components. What
will happen to bulb
B1 if the bulb B2 is
replaced with
connecting wire in
each circuit?
The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.
Circuits are basically the pathways that allow the flow of electric current. These circuits have different components. In this context, there are two circuits, the series circuit, and the parallel circuit. The series circuit has bulbs connected in a sequence where current flows through each bulb in turn. In contrast, the parallel circuit has bulbs connected to different branches. The current flows through each bulb separately.In a series circuit, the components are a power source, resistors, and wires. A power source can be a battery or a generator that is connected in a sequence with resistors and wires. The bulbs B1 and B2 are connected in series. If bulb B2 is replaced with a connecting wire, then the circuit will become incomplete, and bulb B1 will not light up. This is because in a series circuit, if one component is disconnected, the entire circuit becomes open, and the current stops flowing. Thus, if bulb B2 is replaced with a wire, the current will bypass the bulb, and the circuit will become incomplete. In a parallel circuit, the components are a power source, resistors, and branches. The bulbs B1 and B2 are connected in parallel. If bulb B2 is replaced with a connecting wire, the circuit will still work. This is because in a parallel circuit, each bulb has its branch, and the current flows through each bulb separately. Thus, if bulb B2 is replaced with a wire, the current will still flow through bulb B1, and it will light up.For more questions on the series circuit
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what determines the size of a launch window? answer specifically and detail.
Explanation:
The size of a launch window is determined by a variety of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched.
One of the most important factors is the position of the launch site relative to the desired orbit. The launch site must be positioned in such a way that the rocket can achieve the required velocity and trajectory to reach the desired orbit. The angle and speed at which the rocket is launched are also crucial, as they affect the amount of fuel required and the trajectory of the rocket.
The position of the destination is another factor that affects the size of the launch window. For example, if the spacecraft is bound for a planet that is moving in its orbit, the launch window must be adjusted to account for the changing position of the planet.
In addition, the characteristics of the spacecraft being launched, such as its size, weight, and propulsion system, can also affect the size of the launch window. A larger spacecraft may require more fuel and a longer burn time, which may limit the available launch window.
Overall, the size of a launch window is determined by a complex set of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched. Launch planners use sophisticated computer models and simulations to calculate the optimal launch window based on these factors.
A 3.1 kg ball is thrown straight upward with a speed of 18.2 m/s. Use conservation of energy to calculate the maximum height the ball can reach.
Answer:
h = 16.9 m
Explanation:
When a ball is thrown upward, its velocity gradually decreases, until it stops for a moment, when it reaches the maximum height, while its height increases. Thus, the law conservation of energy states in this case, that:
Kinetic Energy Lost by Ball = Potential Energy Gained by Ball
(0.5)m(Vf² - Vi²) = mgh
h = (0.5)(Vf² - Vi²)/g
where,
Vf = Final Speed of Ball = 0 m/s (Since, ball stops for a moment at highest point)
Vi = Initial Speed of Ball = 18.2 m/s
g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)
h = maximum height the ball can reach = ?
Therefore, using values in the equation, we get:
h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)
h = 16.9 m
21. Make sure carts are facing so that Velcro strips can stick together when they collide. Keep an extra 250g of mass on the cart 2 which starts at rest. Change sign on velocity center. Practice giving an initial velocity to cart 1 while cart 2 starts at rest so that after the collision both carts move as a combined object with mass m1 m2. What is the type of collision now you are practicing with two carts
Answer:
his type of shock is called inelastic
Explanation:
This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.
We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.
Looking for the moments
initial. Before the crash
p₀ = m₁ v₁₀
final. After the crash
p_f = (m₁ + m₂) v
the conservation of the moment is written
p₀ = p_f
m₁ v₁₀ = (m₁ + m₂) v
This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.
what is an Electrical transformer?
Answer:
A transformer is a passive electrical device that transfers electrical energy from one electrical circuit to another, or multiple circuits.
Explanation:
Hope it helps
Answer:
A transformer with eletric abilities.
Explanation:
The momentum of a 2.5 kg hammer with a speed of 6 m/s has a downward momentum moving towards a nail. The hammer hits the nail and bounces off at 2.0 m/s and the nail is in contact with the nail for 0.002 seconds. What is the average force the nail exerts on the hammer? How could you use force vs. time to solve this problem?
The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
The equation can be used to determine the average force the nail applies to the hammer.
\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:
\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)
To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
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How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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A piano string having a mass per unit length equal to 4.80 ✕ 10−3 kg/m is under a tension of 1,200 N. Find the speed with which a wave travels on this string.
Answer:
500 m/s
Explanation:
From the question,
V = √(T/m')................. Equation 1
Where V = Speed with which the wave travels on the string, T = Tension of the string, m' = Mass per unit length of the string.
Given: T = 1200 N, m' = 4.80×10⁻³ kg/m
Substitute these values into equation 1
V = √(1200/4.80×10⁻³)
V = √(250000)
V = 500 m/s
Hence the speed of the wave in the string is 500 m/s
A student a model of isostatsy by placing a block of soon in a beaker
To answer the question: "A student made a model of isostasy by placing a block of wood in a beaker of water how can a student demonstrate isostaic rebound using her model?" If she "Press the block down and let go
What is Isostasy?The state of gravitational equilibrium between the Earth's crust and mantle known as isostasy or isostatic equilibrium causes the crust to "float" at an elevation that is dependent on its thickness and density.
This idea is used to explain how various topographic heights can occur on the surface of the Earth.
Hence, to test the model she has, she should press the block down and let go
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A student made a model of isostasy by placing a block of wood in a beaker of water how can a student demonstarte isostaic rebound using her model
A. Blow vigorously on the block
B. Press the block down and let go
C. Add water until the beaker overflow
D. Pour out all the water
What order does energy flow: sun prodecer consumer?
Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.
Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.
At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.
The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.
Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.
At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.
It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.
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On the surface of the moon astronauts do not weigh the same as they do on earth even though they have the same mass a 68 kg astronaut exerts a force of 110 N on the moon due to the reduced gravitational force produced by the moon what is the magnitude of the acceleration due to gravity on the moon
The formula for determining force is expressed as
Force = mass x acceleration
in this case, the acceleration is due to gravity.
By making acceleration the subject of the equation,
acceleration due to gravity = force/mass
From the information given,
Force = 110
mass = 68
acceleration due to gravity = 110/68
acceleration due to gravity = 1.62 m/s^2
Option B is correct
The skater lowers her arms as shown in the adjacent
figure decreasing her radius to 0.15 m. Find her new speed.
Answer:
is there more?
Explanation:
Which example best describes Newton's third law of motion?
F
When a glass slid across a table, it spilled water when it stopped suddenly.
G
An engine used less work to move a lighter car than when it moved a heavier car.
H When a passenger stepped from a boat to the shore, the boat moved away from the shore .
The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.
Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.
From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.
Thus, the ideal solution is option C.
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A piston-cylinder of gas has an initial pressure of 25 psi. The volume is increased to 2.5 times the initial volume. The temperature is increased from 290oC to 720oC. What is the final pressure. Be careful,.. SYW
We know that the product of pressure and the volume divided by the temperature is a constant if the mass of the gas remain constant, this means that:
\(\frac{P_iV_i}{T_i}_{}_{}=\frac{P_fV_f}{T_f}\)First we need to convert the temperature to the absolute scale:
\(\begin{gathered} T_i=290+273.15=563.15 \\ T_f=720+273.15=993.15 \end{gathered}\)The final volume is 2.5Vi. Plugging the values given and solving for the final pressure we have that:
\(\begin{gathered} \frac{25V_i}{290}=\frac{P_f(2.5V_i)}{720} \\ P_f=\frac{25V_i(993.15)}{2.5V_i(563.15)} \\ P_f=17.64 \end{gathered}\)Therefore the final pressure is 17.64 psi.
The skateboarder starts at the top of the ramps, and rolls down and back up the other side. Which graph shows the most Kinetic Energy?
Answer:
C
Explanation:
Usually when you are at the bottom you are at peak speed. It also shows that Kinetic Energy is the green bar and in picture C the green bar is highest.
An automobile moves forward and backward on the street highway. The graph shows the velocity of this automobile as a function of time. At t equals five seconds, how far is the automobile from its t = 0 initial position? (round to 3 significant digits)
The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.
To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.
The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.
Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).
To calculate the area, we can break it down into two separate integrals:
1. The area above the x-axis (forward motion):
Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:
Area1 = velocity * time = 20 m/s * 4 s = 80 m
2. The area below the x-axis (backward motion):
The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:
Area2 = velocity * time = -10 m/s * 1 s = -10 m
To find the total distance traveled, we add the absolute values of the areas:
Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m
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Two blocks, one of mass M and one of mass 3M, are connected by a massless string over a pulley that is a uniform disk of mass 2M and moment of inertia MR^2. The two masses are released from rest, and the masses accelerate as the pulley rotates. Assume there is negligible friction between the pulley and the axle. What is the linear acceleration, a, of the masses?
Answer:
4.9 m/s²
Explanation:
Let T be the tension in the string
If a is the linear acceleration in the direction of the 3M mass, the equation of motion on the 3M mass is
3Mg - T = 3Ma (1)
Since the mass M moves upwards, its equation of motion is
T - Mg = Ma (2)
From (2)
T = Ma + Mg
substituting T into (1), we have
3Mg - (Ma + Mg) = 3Ma
3Mg - Ma - Mg = 3Ma
collecting like terms, we have
3Mg - Mg = 3Ma + Ma
2Mg = 4Ma
dividing both sides by 4M, we have
2Mg/4M = 4Ma/4M
g/2 = a
a = g/2
Since g = 9.8 m/s²,
a = 9.8 m/s²/2
a = 4.9 m/s²
The linear acceleration 'a' of the masses M and 3M is; a = 4.9 m/s²
We are told that;
Mass of first block = M
Mass of second block = 3M
Let the tension in the strings be T.
Now for first block we can write;
T - Mg = Ma - - - (1)
For second block, we can write;
3Mg - T = 3Ma - - - (2)
Where a is linear acceleration of the masses.
Let us add eq 1 to eq 2 to get;
T - Mg + 3Mg - T = Ma + 3Ma
2Mg = 4Ma
M will cancel out to get;
2g = 4a
Using division property of equality by dividing both sides by 2 to get;
g = 2a
Thus;
a = g/2
Where g is acceleration due to gravity = 9.8 m/s²
Thus;
a = 9.8/2
a = 4.9 m/s²
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19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.
The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula
W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.
Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.
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What provides the centripetal force for the moon's orbit around Earth?
Answer:
Gravitational attraction provides the centripetal force needed to keep planets in orbit around the Sun and all types of satellite in orbit around the Earth. This centripetal force is supplied by gravity. The Earth's gravity keeps the Moon orbiting us. Centripetal force is perpendicular to velocity and causes uniform circular motion. The gravitational attraction of the Sun is an inward force acting on Earth. This force produces the centripetal acceleration of the orbital motion. Centripetal forces are always directed toward the center of the circular path.
Explanation:
Answer: C.
the gravitational pull of the Sun
Explanation: plato :3
Hope this helps!
Question 2 of 10
According to the law of conservation of energy, which statement must be
true?
A. The total energy in a system can only increase over time.
B. Energy that is transformed is neither destroyed nor created.
C. Energy can change only from nuclear to chemical.
O D. There is only one form of energy.
Answer:
B: Energy that is transformed is neither created or destroyed
Explanation:
What is the relationship Between Voltage and Cerrent source with a theorem
Answer:
As originally stated in terms of direct-current resistive circuits only, Thévenin's theorem states that "For any linear electrical network containing only voltage sources, current sources and resistances can be replaced at terminals A–B by an equivalent combination of a voltage source Vth in a series connection with a ...
Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare to this diagram?
A
Her diagram shows higher wavelengths.
B
Her diagram shows lower wave amplitudes.
С
Her diagram shows lower wave frequencies.
D
Her diagram shows higher wave amplitudes.
HELPPPP MEEE PLEASEEEE 55 POINTS!!!
Suppose that 2 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 42 cm. (a) How much work is needed to stretch the spring from 32 cm to 34 cm
Answer:
Workdone = 0.025 Joules
Explanation:
Given the following data;
Workdone = 2J
Extension = 42 - 24 = 18 cm to meters = 18/100 = 0.18m
The workdone to stretch a string is given by the formula;
Workdone = ½ke²
Where;
k is the constant of elasticity.
e is the extension of the string.
We would solve for string constant, k;
2 = ½*k*0.18²
2 = ½*k*0.0324
Cross-multiplying, we have;
4 = 0.0324k
k = 4/0.0324
k = 123.46 N/m
a. To find the workdone when e = 32, 34.
Extension = 34 - 32 = 2 to meters = 2/100 = 0.02m
Workdone = ½*123.46*0.02²
Workdone = 61.73 * 0.0004
Workdone = 0.025 Joules
Therefore, the amount of work (in J) needed to stretch the spring from 32 cm to 34 cm is 0.67.
A custodian pulls a vacuum 13.5 m
with a 33.9 N force at a 55.0°
angle, against a 14.2 N friction
force. Find the total work done on
the vacuum.
(Unit = J)
Answer:
Horizontal component of pull = (cos 55 x 33.9) = 19.4N.
Net horizontal force = (19.4 - 14.2) = 5.2N.
Work = (fd) = (5.2 x 13.5) = 70.2 Joules.
Rounded to 1 decimal place throughout.
Explanation:
The total work done on the vacuum is 70.2 J.
What is work done?
Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0° angle, against a 14.2 N friction force.
Horizontal component of pull = (cos 55 x 33.9) = 19.4N.
Net horizontal force = (19.4 - 14.2) = 5.2N.
Work done by vacuum will be
Work =5.2 x 13.5
Work =70.2 J
Thus, the total work done on the vacuum is 70.2 J.
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someone help me with this exercise ?
1. if a body with a mass of 350kg is subjected to a fare of 90n what will be its mass
?
Mass remains mass no matter what you do to it.
In order to catch a ball, a baseball player moves their hand backwards in the direction of the balls motion. Doing this reduces the force of impact on the players hand because A momentum of impact is increasedB time of impact is reducedC velocity of the hand is reducedD time of impact has decreased
Using the impulse formula:
\(\begin{gathered} F\Delta t=m\Delta v \\ so: \\ \Delta t=\frac{m\Delta v}{F} \end{gathered}\)As we can see, the time is inversely proportional to the force, so increasing the time over which the ball's momentum is brought to 0 will decrease the force required to stop it.
Answer:
B. Time of impact is reduced
When do rubber bands no longer act like springs?
Answer:
Rubbery materials act like simple springs when they're not deformed too much. Following the relation known as Hooke's law, a 10 percent increase in stretching force will make a typical rubber band 10 percent longer.
Explanation:
In Short when they become too deformed.
Answer:
yes
Explanation:
Rubbery materials act like simple springs when they're not deformed too much. Following the relation known as Hooke's law, a 10 percent increase in stretching force will make a typical rubber band 10 percent longer
correct me if im wrong
If you drop a bouncing ball from a height of 40 cm, explain why it can only bounce back up to a height of less than 40 cm.
Answer:
Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height
Explanation:
Explanation:
As we know that initially ball is held at height h = 40 cm
So here we can say that kinetic energy of the ball is zero and potential energy is given as
U = mgHU=mgH
now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies
So the ball will left rebound with smaller
14. After finishing her homework, Sue climbs up a 5.00 m high flight of stairs to her bedroom
Find the magnitude of Sue's weight
and how much
work Sue does in climbing the stairs if she
has a mass of 50.0 kg? (4.90 x 2 N, 2450J)
Explanation:
Given parameters:
Height = 5m
Mass of Sue = 50kg
Unknown:
Magnitude of Sue's weight = ?
Work done by Sue = ?
Solution:
Weight is the vertical force exerted by a body in the presence of gravity.
Mathematically;
W = mg
m is the mass
g is the acceleration due to gravity = 9.8m/s²
Weight = 50 x 9.8 = 490N
Work done = Force x distance = weight x height
Work done = 490 x 5 = 2450J
Based on the data, which statement describes the most reliable way to
encode and transmit data and tells why?
A. Digital waves are more reliable because they are less likely to
change when copied.
B. Analog waves are more reliable because they include a range of
values like the original.
C. Analog waves are more reliable because they are less likely to
change when copied.
D. Digital waves are more reliable because they are slightly different
from the original.
Answer:it’s A. right for ape x
Explanation:
Based on data, digital waves are more reliable because they are less likely to change when copied (Option A).
What is a wave?A wave is a periodic distortion capable of traveling through a suitable media (either air or water).
The waves can be classified according to their direction into transversal and perpendicular.In conclusion, based on data, digital waves are more reliable because they are less likely to change when copied (Option A).
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