The correct answer is E(r) = q/(4πr2ε_0)
The charge has now been extended along the z axis, so think about that scenario. Typically, this is referred to as a line charge. A line charge density is typically measured by the lambda variable, which has units of coulombs per metre (in the SI system).
The field lines must lie in planes that are perpendicular to the wire because symmetry requires that the electric field point radially outward from the wire at each point. It is recommended to utilise a cylindrical Gaussian surface with the line charge as its axis for calculating the size of the radial electric field E(r) produced by a line charge with charge density λ. The cylindrical surface's length L ought to cancel out in the expression for E. (r). The equation for E using this situation and Gauss's law (r).
E(r) = q/(4πr2ε_0)
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All matter is made up of particles called
Answer:
atoms and molecules
Explanation:
as opposed to being continuous or just including particles). On the following page, the idea is stated as one of four concepts in Dalton's theory: “All matter is composed of tiny, indivisible particles called atoms”
Answer: atoms
Matter is made of atoms, the basic building blocks. Atoms are made of protons, neutrons and electrons. The answer is atoms.
Hope it helps!
The eliptical orbit of a satellite about its primary is shown below. Select all of the quantities that remain constant at the labelled locations (A,B,C,D). D a The tidal force on the satellite Ob. The kinetic energy of the satellite c. The mechanical energy of the satellite d. The work done by the force of gravitational attraction on the satellite D. The angular momentum of the site Of The gravitational potential energy of the satellite d
The angular momentum of the satellite remains constant at the labeled locations (A, B, C, D).
How do quantities change in orbit?
Let's analyze the quantities that remain constant at the labeled locations (A, B, C, D):
A. The tidal force on the satellite: This force depends on the gravitational gradient and the satellite's position relative to the primary. Since the position changes along the elliptical orbit, the tidal force is not constant. Therefore, it does not remain constant at any labeled location.
B. The kinetic energy of the satellite: The kinetic energy of the satellite changes as it moves along its elliptical orbit. It is highest at the perigee (closest point to the primary) and lowest at the apogee (farthest point from the primary). Therefore, it does not remain constant at any labeled location.
C. The mechanical energy of the satellite: The mechanical energy of the satellite is the sum of its kinetic energy and gravitational potential energy. Since both of these quantities change along the elliptical orbit, the mechanical energy is not constant at any labeled location.
D. The work done by the force of gravitational attraction on the satellite: The work done by the force of gravitational attraction is given by the change in gravitational potential energy. As the satellite moves along its elliptical orbit, the distance from the primary changes, causing the gravitational potential energy to vary.
Therefore, the work done by the force of gravitational attraction is not constant at any labeled location.
E. The angular momentum of the satellite: The angular momentum of the satellite remains constant throughout its motion if no external torques act upon it. This is known as the conservation of angular momentum. Therefore, the angular momentum remains constant at all labeled locations (A, B, C, D).
F. The gravitational potential energy of the satellite: The gravitational potential energy of the satellite changes as it moves along its elliptical orbit. It is highest at the apogee and lowest at the perigee. Therefore, it does not remain constant at any labeled location.
In summary, the quantities that remain constant at the labeled locations (A, B, C, D) are:
The angular momentum of the satellite.
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A 3.00 m long rod (I=1/3ML2) with a mass of 10.0 kg is set so that it pivots around its end. The rod is pulled back until it is horizontal and released. A small spherical ball with a mass of 4.00 kg is placed directly under the pivot point of the rod so that the end of the rod strikes the ball when it is vertical.
What is the angular velocity at the bottom before it hits the ball?
Hi there!
Assuming the rod is pulled back 90° (π/2 radians), we can use angular kinematics to solve.
Using the equation:
\(\omega_f^2= \omega_i^2 + 2\alpha \theta\)
\(\omega_f\) = final angular velocity (? rad/sec)
\(\omega_i\) = initial angular velocity (0 rad/sec)
\(\alpha\) = angular acceleration (rad/sec², must solve for)
\(\theta\) = angular displacement (π/2 rad)
Recall Newton Second Law's rotational equivalent:
\(\Sigma \tau = I\alpha\)
τ = Torque (Nm)
I = Moment of inertia (kgm²)
α = angular acceleration (rad/sec²)
Setting the pivot point at the end, and knowing that the force of gravity works at an object's center of mass (1.5m from the rod's end), we can solve for the angular acceleration.
\(\tau= F \times r\\\\\tau = W \times r = 10(9.8) * 1.5 = 147 Nm\)
Now, solve for the moment of inertia given I = 1/3ML² at one of its ends:
\(I = \frac{1}{3}(10)(3^2) = 30 kgm^2\)
Solve for the angular acceleration:
\(147 = 30\alpha\\\\\alpha = 4.9 \frac{rad}{sec^2}\)
Now, we can use the kinematic equation to solve.
\(\omega_f^2 = 0 + 2(4.9)(\frac{\pi}{2}})\\\\\omega_f = \sqrt{2(4.9)(\frac{\pi}{2})} = \boxed{3.923 \frac{rad}{sec}}\)
The recoil (springing or flying back of the gun when shots are fired) momentum of a gun is _______________ the momentum of the bullet it fires.
a. less than
b. more than
c. the same as
d. not equal to
The recoil (springing or flying back of the gun when shots are fired) momentum of a gun is the same as the momentum of the bullet it fires.
option C is the correct answer.
What is the principle of conservation of linear momentum?
The principle of conservation of linear momentum states that in an isolated system, the sum of the initial momentum of the system is equal to the sum of the final momentum of the system.
Mathematically, the principle of conservation of linear momentum is written as;
Pi = Pf
where;
Pi is the sum of the initial momentum of the systemPf is the sum of the final momentum of the systemm₁u₁ = m₂u₂
where;
m₁ is the mass of the gunu₁ is the initial speed of the gunm₂ is the mass of the bulletu₂ is the final speed of the bulletThus, based on the principle of conservation of linear momentum the final momentum of the gun will always be equal to the final momentum of the bullet.
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X=Y=MC scourer that would be the answer for you mam or sir
Me das mas información?
Answer:
jello
Explanation:
it jiggles
The resistance to the motion of an object is
Answer:
Inertia
Explanation:
Part of Newton's Laws of Motion
Why does the skateboarder continue to move forward when he hits the
trash? What is the external force?
Answer:
According to Newton's first law: An object at rest will remain at rest unless acted on by an unbalanced force. An object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
There is a force that moves the skater and his skate forward, after the hit, his speed is reduced, but this force is not completely counteracted, and that's why he continues moving forward.
99. An airplane with an airspeed of 120 km/h encounters a
90-km/h crosswind. Convince your classmates that the
plane's groundspeed is 150 km/h.
The resultant speed of the airplane is 150 km/h, and this is the speed relative to the ground.
What is the resultant speed of the airplane?
The resultant speed of the airplane is the single speed of the airplane that will produce same effect as the two speeds acting together.
To convince your classmate about the ground speed of the airplane we need to calculate the resultant speed of the airplane.
R² = Vp² + Vw²
where;
R is the resultant speed of the airplaneVp is the speed of the airplaneVw is the speed of the windR² = Vp² + Vw²
R = √[Vp² + Vw²]
R = √[120² + 90²]
R = 150 km/h
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A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity.
A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity is maximum.
Simple harmonic motion or SHM is the alternating motion of an object that passes through a certain balance point. SHM has a fixed frequency and amplitude and is periodic, namely movements that occur regularly and are repeated at the same time.
When a spring undergoes simple harmonic motion, the mass accelerates in a direction toward the equilibrium point, then the velocity of the object at the equilibrium point is maximum. The object is accelerating in a direction toward the equilibrium point. Acceleration caused by the force recovered.
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Vector A=5.00i^+2.00j^ and vector B=3.00i^−2.00j^. What is vector C=3.00A−B ? show work A) 12.0i^+8.00j^ B) −3.00i^+−18.0j^ C) 9.00i^+10.0j^ D) 12.0i^+−8.00j^ E) If none of the above, write your answer here.
Vector A=5.00i^+2.00j^ and vector B=3.00i^−2.00j^. Vector C=3.00A−B. vector C = 3.00A - B is equal to 12.00i^ + 8.00j^.
To find vector C = 3.00A - B, we need to perform vector subtraction and scalar multiplication.
Given:
Vector A = 5.00i^ + 2.00j^
Vector B = 3.00i^ - 2.00j^
To subtract vectors, we subtract the corresponding components:
3.00A - B = (3.00 * 5.00)i^ + (3.00 * 2.00)j^ - 3.00i^ + 2.00j^
Simplifying the expression:
3.00A - B = 15.00i^ + 6.00j^ - 3.00i^ + 2.00j^
Combining like terms:
3.00A - B = (15.00i^ - 3.00i^) + (6.00j^ + 2.00j^)
Simplifying further:
3.00A - B = 12.00i^ + 8.00j^
Therefore, vector C = 3.00A - B is equal to 12.00i^ + 8.00j^.
Therefore option A is correct.
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Can someone write how to determine the viscosity of glycerin by falling ball ?
Answer:-
The terminal velocity of a steel ball 2 mm in diameter falling through glycerin is 44×10 - ²
cm/s (Given that specific gravity of steel = 8, specific gravity of steel =8, specific gravity of glycerin a 1.3, viscosity of glycerine 8.3 poise.) .
What is the density of chlorine gas at 1.21atm1.21atm and 34.934.9 degree Celsius.
The density of chlorine gas at 1.21 atm and 34.9°C is 3.21 g/L. This calculation was done using the ideal gas law
To calculate the density of chlorine gas, we can use the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. We need to rearrange the formula to solve for density, which is mass per unit volume:
density = (mass of gas) / (volume of gas)
= (n x M) / V
where M is the molar mass of chlorine (70.9 g/mol).
First, we need to convert the temperature to Kelvin:
T = 34.9°C + 273.15
= 308.05 K
Next, we can use the given pressure and temperature to find the volume of the gas using the ideal gas law:
V = (nRT) / P
where R = 0.08206 L atm/(mol K)
V = (n x R x T) / P
= (1 x 0.08206 x 308.05) / 1.21
= 2.11 L
Finally, we can use the volume and molar mass to find the density:
density = (n x M) / V
= (1 x 70.9) / 2.11
= 3.21 g/L
The density of chlorine gas at 1.21 atm and 34.9°C is 3.21 g/L. This calculation was done using the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas to its physical properties.
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how would you describe the kinetic energy of the particles in a solid? low kinetic energy high kinetic energy
Since they are tightly packed, solids vibrate in place and have the least kinetic energy.
The vibration and movement of the particles are accelerated by kinetic energy. Due to the liquid's relative higher kinetic energy, particles in it slide past one another.
Is the kinetic energy particles of a solid?The kinetic hypothesis states that matter is made up of moving parts. Kinetic energy is what propels motion. The least kinetic energy is held by solid particles, while the most is held by gaseous particles.
The particles gather kinetic energy and accelerate as the temperature rises. The actual average speed of the particles is influenced by both their mass and temperature; at a given temperature, larger particles travel more slowly than lighter ones.
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GENTE ME AJUDEM NESTA QUESTÃO POR FAVOR, TENHO PROVA ONLINE AMANHÃ! "Um sonar de um navio de pesca localizou um cardume de sardinhas a 300 m de profundidade. Sabendo que a velocidade de propagação do som na água tem o valor de 1500 m/s, calcula o tempo que decorre desde a emissão dos ultra-sons e a sua receção no navio." Por favor!
Answer:
The time between the emission of the wave and it's reception was 0.4 seconds.
Explanation:
The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:
\(\text{speed} = \frac{\text{distance}}{\text{time}}\)
We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:
\(\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}\)
The time between the emission of the wave and it's reception was 0.4 seconds.
If an object starts from rest, what is its initial velocity?
Answer:
if an object starts from rest it's initial velocity is zero
How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s2? a 0.013 N b 75 N c 108 N d 1080 N
Q5. A Michelson interferometer uses a laser with a wavelength of 530 nm. A cuvette of thickness 10 mm is placed in one arm containing a glucose solution. As the glucose concentration increases, 88 fringes are observed to emerge at the screen. What is the change in refractive index of the glucose solution?
The change in refractive index of the glucose solution is 2.34.
Michelson interferometer is an instrument used to measure the refractive index of a substance. It uses a laser beam that is divided into two equal parts, and each part travels a different path before recombining to produce an interference pattern on a screen.
A cuvette of thickness 10 mm is placed in one arm containing a glucose solution. As the glucose concentration increases, 88 fringes are observed to emerge at the screen. We need to determine the change in refractive index of the glucose solution.
The fringe order is given by:
n = (2t/λ) * δwhere,
t = thickness of the cuvette
λ = wavelength of the laser
δ = refractive index of the glucose solution
Since we know the values of t, λ and n, we can solve for
δδ = (nλ) / (2t)
= (88 × 530 nm) / (2 × 10 mm)
= 2.34
Therefore, the change in refractive index of the glucose solution is 2.34.
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Question 16 Find the flux of the vector field F across the surface S in the indicated direction. F = x 4yi - z k: Sis portion of the cone z = 3 Vx2 + y2 between z = 0 and z = 4; direction is outward 0-13
The flux of the vector field F across the surface S in the indicated direction is -24π.
We know that the flux of a vector field F across a surface S is given by the surface integral, ∫∫S F ⋅ dS. Here, dS is the surface area element, which is given by dS = ndS, where n is the unit normal to the surface S, and dS is the area element on the surface S. Let us determine the unit normal to the surface S. For the given surface S, we have the equation of the surface in cylindrical coordinates as z = 3r, where r = √(x^2 + y^2) is the radial coordinate. The unit normal to the surface S is then given by n = ( ∂z/∂r)i + ( ∂z/∂θ)j - k, where i, j, and k are the unit vectors along the x, y, and z axes respectively.
We now evaluate the first integral. ∫∫S x4y dS = ∫₀⁴ ∫₀^(2π) (r cosθ) (4r sinθ) r dz dθ = 4 ∫₀⁴ ∫₀^(2π) r^3 cosθ sinθ dz dθ = 0. Using cylindrical coordinates, we have the equation of the surface S as z = 3r. Hence, z varies from 0 to 4, and r varies from 0 to √(16 − z^2). We now evaluate the second integral. ∫∫S z dS = ∫₀⁴ ∫₀^(2π) (3r) r dθ dz = 3 ∫₀⁴ ∫₀^(2π) r^2 dθ dz = 24π. Hence, we have ∫∫S F ⋅ dS = 3 ∫∫S x4y dS - ∫∫S z dS = 3(0) - 24π = -24π.
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Un cuerpo de 480 g de masa es atraído con una fuerza de 3.9 E-6 N por otro cuerpo de 196 g de masa. Calcula la distancia a la que se encuentran.
Answer:
La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.
Explanation:
Asumamos que ambos cuerpos son partículas, la fuerza de atracción (\(F\)), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:
\(F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}}\) (1)
Donde:
\(G\) - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.
\(m_{1}, m_{2}\) - Masas de los cuerpos, en kilogramos.
\(r\) - Distancia entre los cuerpos, en metros.
Si sabemos que \(G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}\), \(m_{1} = 0.48\,kg\), \(m_{2} = 0.196\,kg\) y \(F = 3.9\times 10^{-6}\,N\), entonces la distancia entre los dos cuerpos es:
\(r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }\)
\(r \approx 1.269\times 10^{-3}\,m\)
Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.
What do the fly balls represent in the watt's governor?
The amount of fuel being let through the valve
The feedback from the outside to the engine
The speed of the engine
The centrifugal force of the spindle
In the Watt's Governor, fly balls represent the centrifugal force of the spindle.
A Watt's Governor is a device that is designed to control the speed of a steam engine or other machinery by regulating the amount of fuel delivered to the engine.
What is a Watt's Governor?
A Watt's Governor is an apparatus designed to automatically control the speed of a steam engine by regulating the fuel (coal or oil) going to the engine. The Watt's Governor was invented by James Watt in 1788. It is a simple device that consists of two rotating balls or flyballs, which are connected by a spindle. The spindle is connected to the engine and rotates as the engine speeds up or slows down.
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Which describes how chemical changes are different from physical changes?
(a) Chemical changes can be measured, but physical changes cannot. (b)Chemical changes involve the formation of a new substance. (c)Chemical changes release energy, but physical changes absorb energy.
(d) Chemical changes cannot be caused by oxygen.
Answer:
b
Explanation:
when something has to do with chemical then a new substance can be produced
How does a combinational circuit differ from a sequential circuit?
According to the information we can infer that a combinational circuit processes inputs and produces outputs based solely on the current input values, while a sequential circuit also depends on its previous state.
How does a combinational circuit differ from a sequencial circuit?Combinational circuits process inputs and produce outputs based solely on the current input values, without any memory or feedback mechanism. The output is determined by the combination of current inputs only.
Sequential circuits, on the other hand, have memory elements or feedback loops that allow them to retain information about their previous state. They consider both the current inputs and the internal state to generate outputs, as they have a concept of time and can store and recall information.
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REVIEW
1 A train travelled along a
straight track from a particular
stop back to its depot.
This 5.0 km journey took
12 minutes. Calculate the
train's average speed. (Give
your answer in km/h.)
According to given data, the average speed of train is 25 km/h.
Equation :Given data,
distance = 5 km
time = 12 minutes
average speed = ?
changing time from minute to hour
So,
hour = 12 / 60
hour = 0.2
Then to calculate speed use the formula,
s = d / t
s = 5km / 0.2hr
s = 25 km/h
What is speed?Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector value, whereas speed is a scalar value. It has a dimension of time-distance. As a result, the basic unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.
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Which type of wave moves both energy and the particles in the same direction as the medium?
Answer:
Longitudinal waves
Explanation:
With sound waves, the energy travels along in the same direction as the particles vibrate. This type of wave is known as a longitudinal wave , so named because the energy travels along the direction of vibration of the particles.
how does temperature affect chemical reaction
what is the acceleration of a proton moving with a speed of 9.5 m/s at right angles to a magnetic field of 1.5 t ?
The acceleration of the proton is approximately 3.43 x 10^15 m/s^2.
A proton that moves at right angles to a magnetic field experiences a magnetic force that causes it to follow a circular path. This is due to the fact that the magnetic force acting on a charged particle moving at right angles to a magnetic field is proportional to the product of the magnetic field, the charge, and the velocity. As a result, the acceleration of the proton can be calculated using the following formula:
a = (qvB) / m
where q is the charge of the proton, v is its velocity, B is the magnetic field strength, and m is the mass of the proton.
Given that a proton moves with a speed of 9.5 m/s at right angles to a magnetic field of 1.5 T, the acceleration can be calculated as follows:
a = (qvB) / m = (1.602 x 10^-19 C x 9.5 m/s x 1.5 T) / (1.673 x 10^-27 kg)≈ 3.43 x 10^15 m/s^2
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What is the definition of the half-life of a radioactive isotope?
A. The time it takes for half the parent nuclei in a sample to become
daughter nuclei
B. The time it takes for all the parent nuclei in a sample to become
daughter nuclei
C. The time it takes for all the daughter nuclei in a sarnple to become
parent nuclei
D. The time it takes for half the daughter nuclei in a sample to
become parent nuclei
Answer:
A
Explanation:
The amount of time necessary for half of anything to go through a process, such the amount of time needed for half of a radioactive substance's atoms to decay. Thus, option A is correct.
What half-life of a radioactive isotope?The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. An individual radioactive isotope's half-life is unaffected by environmental factors and is independent of the isotope's starting concentration.
Radiation emission stops after an atom achieves energy stability through radiation. A radionuclide's concentration falls over time, and its radioactivity declines. A (physical) half-life is the length of time required for radioactivity to degrade and diminish to half.
Therefore, The time it takes for half the parent nuclei in a sample to become daughter nuclei.
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A truck has a momentum of 5,000 units. What happens to the truck's momentum if the mass is cut in half?
If the truck is moving with the same velocity, if the mass is cut in half then the momentum of the truck will also reduce to half.
What is momentum?The momentum of a body can be described as the function of the object's mass and velocity. Momentum (p) can be determined as kinetic energy and is the product of velocity (v) and mass (m).
The momentum of an object can be determined from the mathematical formula:
p = m×v
The momentum of an object is conserved and can be equal to zero if the object is stationary and its velocity of an object is zero.
Given, the truck has a momentum, p = 5000 units
Given that the mass of the truck is reduced to half. Then the new mass of the truck is equal m/2. If the truck is still moving with the same velocity then the momentum is equal to:
p' = m' ×v
p' = (m/2) ×v
p' = mv/2
p' = p/2
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when the boat propeller pushes water backwards, the boat moves forwards.
the force on the water causes an equal and opposite force to act on the boat.
which law is this an example of?
Every action has an equal and opposite response, states Newton's third law of motion. Therefore, the boatman must push the water backward in order to move the boat forward.
What do you mean by third law of motion?
If object A pulls on item B, object B pulls back on object A with an equal and opposite force.Ball bouncing: When a ball strikes the ground, it exerts an action force on the surface. The ball bounces back due to the ground's reaction force. The air is pushed upward by the bird as a result of the air being pushed downward by the bird's wings as the bird flies.According to his third law, every force (activity) in nature has an equal and opposite response.To know more about Third law of motion here
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The sputnik one satellite orbiting earth mass equals 5.98×10 to the 24th power kilograms in a circle of radius 6.96×10 to the six power meters what was its orbital velocity
Answer:
7572 m/s
Explanation:
The force between two masses separated by a distance r is given as:
\(F=G\frac{m_1m_2}{r^2}\)
Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is \(6.674*10^-11 Nm^2/kg^2\)
The mass of the earth (\(m_1\)) is far greater than the mass of the sputnik (\(m_2\)). Therefore \(m_1m_2=m_1\). The mass of the sputnik is neglected, therefore:
\(F=G\frac{m_1}{r^2}=\frac{(6.674*10^{-11})(5.98*10^{24})}{(6.96*10^6)^2} = 8.2389N\)
But F is actually centripetal acceleration, a = v²/r
\(8.2389 = v^2 / 6.96*10^6\\v=7572m/s\)