Determine the median, quartile 1, quartile 2 and the interquartile range for the following set
of data. Then, draw the box and whisker plot.
88 56 72 67 59 48 81 62 90 75 75 43 71 64 78 84

To determine the algabraic equation that will represent the situation;

When you take a look at the diagram, when you trace 1x on the y-axis, it will fall on the second box. Each box represent 100 .

The y- axis falls on the one-fourth of the second box, which means its 125

Hence the algabraic equation to represent the situation is;

y= 125x

where x is the number of hours

and y represent the earnings

As for Part F, if you want to to determine Jerome earnings for a particular number of hours, just substitute the hours with the x and then solve for y.

Answer:

a

Step-by-step explanation:

Answer:

89.70 dollars

Step-by-step explanation:

If Juwad picked 30 bags of apples and only sold 26 of them for 3.45 each, then you would have to multiply the number of bags sold by the price, and you would get your answer. So in this case:

1. (#sold)* (price)= total amount of money made

2. 26*3.45= 89.70

3. And you can check by dividing 89.70(your answer) by the price of the apples

4. 89.70/3.45= 26

The largest possible error you could make in approximating P(a < M < b) by e is when a = 0 and b = 1. The error would be |P(0 < M < 1) - e|.

You are given an approximation of P(a < M < b) by e, where M is an integer between a and b. You want to find the largest possible error in this approximation. The range of values for M is between a and b, and both a and b are integers between 0 and 100. The largest possible error would occur when the difference between the true value and the approximation is at its maximum. Since e is an approximation of P(a < M < b), the largest error would occur when the difference between the actual probability and the approximation is at its maximum.

This would happen when the actual probability is either very close to 0 or 1, and the approximation is far from the actual value. Since a and b are integers between 0 and 100, the largest possible error would occur when the range of possible values for M is at its smallest. This means that a and b should be as close together as possible. The smallest range for M would be 1, which would occur when a = 0 and b = 1.

In this case, the largest possible error in the approximation would be |P(0 < M < 1) - e|, where P(0 < M < 1) is the true probability and e is the approximation. In summary, the largest possible error you could make in approximating P(a < M < b) by e is when a = 0 and b = 1. The error would be |P(0 < M < 1) - e|.

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-13v=182

-13    -13

v= -14

Answer:

Step-by-step explanation:

4). Surface area of front and back = 2(lengh × height)

                                                        = 2(7×3)

                                                        = 63 cm²

    Surface area of top and bottom = 2(length × width)

                                                          = 2(8×7)

                                                          = 112 cm²

     Surface area of left and right = 2(width × height)

                                                      = 2(8×3)

                                                      = 48 cm²

      Total surface area = 63 + 112 + 48

                                      = 223 cm²

5). Surface area of top and bottom = 2πr²

                                                          = 2π(4)²

                                                          = 32π

                                                          = 100.53 cm²

    Surface area of middle = h(π × d)

                                            = 4(π × 8)

                                            = 32π

                                            = 100.53 cm²

     Total surface area = 32π + 32π

                                     = 64π

                                     = 201.06 cm²

6). Surface area of front and back = \(2[\frac{1}{2}(\text{Base})(\text{Height)}]\)

                                                        = Base × Height

                                                        = 6 × 8

                                                        = 48 cm²

     Surface area of bottom = 6 × 11

                                             = 66 cm²

     Surface area of the left = 8 × 11

                                             = 88 cm²

     Surface area of right = 10 × 11

                                        = 110 cm²

      Total surface area = 48 + 66 + 88 + 110

                                      = 312 cm²  

Answer:

The point of intersection between 2x+3y=12 and 2x-y=4 is (3,2)

Step-by-step explanation:

Answer: (5x-1)(x+4)

Step-by-step explanation:what she said

Answer:

6(base) x 3.5(Height) = 21, 21 divided by 2 (x 1/2) = 10.5

10.5(area of triangle) x 7.75(width) = 81.375

Formula of an area of a triangle:

BH x 1/2

Base x Height x 1/2(basically just dividing by 2)

Now the base:

1.5 x 7.75 x 6 = 69.75

Now let's add the two given volumes:

81.375+ 69.75 = 151.125 ft^3 is your answer.

Answer:

13.3 miles to nearest 1/10.

Step-by-step explanation:

The journey forms a right triangle so by Pythagoras:

d^2 = 3^2 + 13^2

d^2 = 9 + 169

d^2 = 178

d = 13.34 miles.

The function f(x) = x³6x² + 12x - 11 has a domain of all real numbers. The critical points of the function are found by setting the derivative equal to zero, resulting in x = -2 and x = 1 as the critical points.

The function is not symmetric. The relative extrema can be determined by evaluating the function at the critical points, resulting in a relative maximum at x = -2 and a relative minimum at x = 1. The function increases on the intervals (-∞, -2) and (1, ∞), and decreases on the interval (-2, 1). The inflection points can be found by setting the second derivative equal to zero, but in this case, the second derivative is a constant and does not equal zero, so there are no inflection points. The function is concave up on the intervals (-∞, -2) and (1, ∞), and concave down on the interval (-2, 1). There are no asymptotes. A graph of the function can visually represent these characteristics.

The domain of the function f(x) = x³6x² + 12x - 11 is all real numbers because there are no restrictions on the variable x.

To find the critical points, we need to find the values of x where the derivative f'(x) equals zero. Taking the derivative of f(x), we get f'(x) = 3x² - 12x + 12. Setting f'(x) equal to zero, we solve the quadratic equation 3x² - 12x + 12 = 0. Factoring it, we have 3(x - 2)(x - 1) = 0, which gives us the critical points x = -2 and x = 1.

The function is not symmetric because it does not satisfy the condition f(x) = f(-x) for all x.

To find the relative extrema, we evaluate the function at the critical points. Plugging in x = -2, we get f(-2) = -29, which corresponds to a relative maximum. Plugging in x = 1, we get f(1) = -4, which corresponds to a relative minimum.

The function increases on the intervals (-∞, -2) and (1, ∞) because the derivative f'(x) is positive in those intervals. It decreases on the interval (-2, 1) because the derivative is negative in that interval.

To find the inflection points, we need to find the values of x where the second derivative f''(x) equals zero. However, the second derivative f''(x) = 6 is a constant and does not equal zero, so there are no inflection points.

The function is concave up on the intervals (-∞, -2) and (1, ∞) because the second derivative f''(x) is positive in those intervals. It is concave down on the interval (-2, 1) because the second derivative is negative in that interval.

There are no asymptotes because the function does not approach infinity or negative infinity as x approaches any particular value.

A graph of the function can visually represent all the characteristics mentioned above, including the domain, critical points, relative extrema, regions of increase and decrease, concavity, and absence of asymptotes.

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The actual building is tall 56.3 meters

On a scaled drawing a building measures 4.5 cm tall

The scale drawing is 25 meters per 2 cm

The first step is to calculate the equivalent of 1 cm in meters

2 centimetres= 25 meters

1 centimetre= x

cross multiply both sides

2x= 25

x= 25/2

x= 12.5

1 centimetre is 12.5 metres

4.5 centimetres in metres is

= 4.5 × 12.5

= 56.3

Hence the height of the actual building is 56.3 meters

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Step-by-step explanation:

Substitute the given values into the expression;

\(12(3) - 3( \frac{1}{3} ) \div 4(3) - 5\)

Multiply;

\(36 - 1 \div 12 - 5\)

Solve Using PEMDAS;

\(36 - \frac{1}{12} - 5\)

\(35 \frac{11}{12} - 5\)

\(\boxed{30 \frac{11}{12} } \)

Answer:

Step-by-step explanation:

Answer:  c

Step-by-step explanation:

Answer:

PG = 14 unit

Step-by-step explanation:

Given:

Equilateral triangle PQR.

GU = 7

Find:

PG

Computation:

We know that PQR is an equilateral triangle and PU is median.

Median of an equilateral triangle intersect each other at 2:1

So,

PG = 2 × GU

PG = 2 × 7

PG = 14 unit

In a sample of 26 days from the desert, the average of the high daily temperature is 114 degrees F, and the sample standard deviation is 5 degrees F.

To determine the 90% confidence interval for the average temperature, we can use the t-distribution as follows:To find the critical value of t, we can use the t-table. Since our sample has n = 26, the degrees of freedom (df) are n - 1 = 25. At a confidence level of 90%, with 25 degrees of freedom, the critical t-value is 1.708.The standard error of the mean is calculated as s / sqrt(n), where s is the sample standard deviation and n is the sample size. Therefore, the 90% confidence interval for the average temperature is (114 - 1.67, 114 + 1.67), or (112.33, 115.67) degrees F.

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The diameter of a wire significantly impacts its strength, range, and stiffness.

1. Strength: As the diameter of a wire increases, its overall strength improves. A larger cross-sectional area allows the wire to withstand greater forces before breaking. This is because the increased material can distribute force more effectively, resulting in enhanced tensile strength.

2. Range: The diameter of a wire also influences its range or length. Thicker wires tend to have shorter range capabilities compared to thinner wires. As the diameter increases, the weight and stiffness of the wire rise as well, making it harder to extend or coil over long distances. Conversely, thinner wires are more flexible and lightweight, enabling them to cover greater lengths.

3. Stiffness: Lastly, the diameter of a wire impacts its stiffness, which is the resistance of the wire to bending or deformation. With a larger diameter, the stiffness of the wire increases due to the higher amount of material present. This means that it requires more force to bend or change the shape of the wire, resulting in greater rigidity. On the other hand, wires with smaller diameters are more pliable and can easily be bent or manipulated.

In summary, the diameter of a wire plays a crucial role in determining its strength, range, and stiffness. Thicker wires exhibit enhanced strength and stiffness but may have limited range capabilities, while thinner wires are more flexible and suitable for longer distances but may not be as strong or rigid.

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yd=

yd=

16x2+12x+18=3x=2x2+6x+9=3x=

sorry i try

Answer:

D

Step-by-step explanation:

Answer:

don't know bro

sry

don't mind

<>

Given that AC is a diameter of the circle, we can conclude that triangle ABC is a right triangle, with AC being the hypotenuse. The area of the circle is not directly related to finding the lengths of BC or AB, so we will focus on the given information: AB = 16 units.

Using the Pythagorean theorem, we can find BC. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (AC) is equal to the sum of the squares of the other two sides (AB and BC):

AC² = AB² + BC²

Substituting the given values, we have:

(AC)² = (AB)² + (BC)²

(AC)² = 16² + (BC)²

(AC)² = 256 + (BC)²

Now, we need to find the length of AC. Since AC is a diameter of the circle, the length of AC is equal to twice the radius of the circle.

AC = 2 * radius

To find the radius, we can use the formula for the area of a circle:

Area = π * radius²

Given that the area of the circle is 2897 units², we can solve for the radius:

2897 = π * radius²

radius² = 2897 / π

radius = √(2897 / π)

Now we have the length of AC, which is equal to twice the radius. We can substitute this value into the equation:

(2 * radius)² = 256 + (BC)²

4 * radius² = 256 + (BC)²

Substituting the value of radius, we have:

4 * (√(2897 / π))² = 256 + (BC)²

4 * (2897 / π) = 256 + (BC)²

Simplifying the equation gives:

(4 * 2897) / π = 256 + (BC)²

BC² = (4 * 2897) / π - 256

Now we can solve for BC by taking the square root of both sides:

BC = √((4 * 2897) / π - 256)

To find the measure of angle BC (mBC), we know that triangle ABC is a right triangle, so angle B will be 90 degrees.

In summary:

BC = √((4 * 2897) / π - 256)

mBC = 90 degrees

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Answer:

250*5.0=125.0

Step-by-step explanation:

250*5.0=125.0

Considering the definition of mass-volume percent, the mass-volume percent of 5.0 g of magnesium chloride in enough water to give 250 mL of solution is 2%.

Mass-volume percent is a measure of concentration that indicates the number of grams of solute in each 100 mL of solution. It is an intensive property, that is, it does not depend on the amount of material.

Mass-volume percent is defined as the mass of solute in grams divided by the total volume of the solution in milliliters. To express this as a percent, we multiply this fraction by 100:

\(Mass-volume percent=\frac{mass of solute}{volume}x100\)

In this case, you know:

Replacing in the definition of mass-volume percent:

\(Mass-volume percent=\frac{5 g}{250 mL}x100\)

Solving:

Mass-volume percent= 2%

Finally, the mass-volume percent of 5.0 g of magnesium chloride in enough water to give 250 mL of solution is 2%.

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Answer:

Down below hope it helps :)

Step-by-step explanation:

The evidence "SAY" was only written once. It wasn't by the same article, the writer introduces two separate articles.

Kinda confused by this question but I think that's the answer.

(a) The dot product of A and B is given by: A · B = (2î + 3ĵ + 4k) · (î - 2ĵ + 3k)= 2(1) + 3(-2) + 4(3)= 2 - 6 + 12 = 8

Therefore, A · B = 8.

(b) The angle between two vectors A and B is given by:

θ = cos^(-1)((A · B) / (|A| |B|))

In this case, |A| is the magnitude of vector A and |B| is the magnitude of vector B. The magnitude of a vector is given by the square root of the sum of the squares of its components.

|A| = √(2² + 3² + 4²) = √(4 + 9 + 16) = √29

|B| = √(1² + (-2)² + 3²) = √(1 + 4 + 9) = √14

Plugging in the values:

θ = cos^(-1)(8 / (√29 √14))

(c) The scalar component of vector A in the direction of vector B is given by:

A_B = (A · B) / |B|

Plugging in the values:

A_B = 8 / √14

(d) The cross product of vectors A and B is given by:

A x B = (2î + 3ĵ + 4k) x (î - 2ĵ + 3k)

= (3(3) - 4(-2))î + (4(1) - 2(3))ĵ + (2(-2) - 3(3))k

= 17î - 2ĵ - 13k

Therefore,AXB = 17î - 2ĵ - 13k.

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(a) The dot product of A and B is given by: A · B = (2î + 3ĵ + 4k) · (î - 2ĵ + 3k)= 2(1) + 3(-2) + 4(3)= 2 - 6 + 12 = 8

Therefore, A · B = 8.

(b) The angle between two vectors A and B is given by:

θ = cos^(-1)((A · B) / (|A| |B|))

In this case, |A| is the magnitude of vector A and |B| is the magnitude of vector B. The magnitude of a vector is given by the square root of the sum of the squares of its components.

|A| = √(2² + 3² + 4²) = √(4 + 9 + 16) = √29

|B| = √(1² + (-2)² + 3²) = √(1 + 4 + 9) = √14

Plugging in the values:

θ = cos^(-1)(8 / (√29 √14))

(c) The scalar component of vector A in the direction of vector B is given by:

A_B = (A · B) / |B|

Plugging in the values:

A_B = 8 / √14

(d) The cross product of vectors A and B is given by:

A x B = (2î + 3ĵ + 4k) x (î - 2ĵ + 3k)

= (3(3) - 4(-2))î + (4(1) - 2(3))ĵ + (2(-2) - 3(3))k

= 17î - 2ĵ - 13k

Therefore,AXB = 17î - 2ĵ - 13k.

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a) After 17 years, you will have approximately $256,951.34 in the account. b) The total amount of money you will deposit into the account over 17 years is $153,000. c) The total interest you will earn after 17 years is approximately $103,951.34.

To calculate the future value of the account after 17 years, we can use the formula for compound interest:

FV = P *\((1 + r/n)^{(nt)\)

where : FV is the future value of the account

P is the monthly deposit amount ($750)

r is the annual interest rate (7.9% or 0.079)

n is the number of times the interest is compounded per year (monthly, so n = 12)

t is the number of years (17)

a) Plugging in the values, we have FV = 750 * (1 + 0.079/12)^(12*17) ≈ $256,951.34.

b) To calculate the total amount of money you will deposit into the account over 17 years, we multiply the monthly deposit amount by the number of months: Total deposits = 750 * 12 * 17 = $153,000.

c) The total interest earned can be calculated by subtracting the total deposits from the future value of the account: Total interest = FV - Total deposits = $256,951.34 - $153,000 ≈ $103,951.34.

Therefore, after 17 years, you will have approximately $256,951.34 in the account, the total deposits will amount to $153,000, and the total interest earned will be approximately $103,951.34.

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\(\\ \bull\tt\dashrightarrow f(x)=6^x\)

\(\\ \bull\tt\dashrightarrow f(-2)=6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}\)

\(\\ \bull\tt\dashrightarrow f(-1)=6^{-1}=\dfrac{1}{6}\)

\(\\ \bull\tt\dashrightarrow f(0)=6^0=1\)

\(\\ \bull\tt\dashrightarrow f(1)=6^1=6\)

\(\\ \bull\tt\dashrightarrow f(2)=6^2=36\)

We have that The midpoint M of the line segment joining the points

is

\(M=(-3,-1)\)

From the question we are told

Find the midpoint M of the line segment joining the points

Generally the equation for the midpoint is   is mathematically given as

\(M=\sqrt{\frac{x1+x2}{2},(y1+y2)^2}\\\\M=\frac{-4+-2}{2},\frac{(6+-8)}{2}}\)

\(M=(-3,-1)\)

Therefore

The midpoint M of the line segment joining the points

is

\(M=(-3,-1)\)

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The value of c at the instant when p=41 and dc/dt=15 is 2√82.

To solve for c at the given instant, we first take the derivative of the given equation with respect to t: \(2p(dp/dt)(20c)\) + \(p^2(20(dc/dt))\) = 0 We plug in p=41 and \(dc/dt=15\) and solve for \(dc/dt\):

\(2(41)(dp/dt)(20c) + (41)^2(20)(15)\) = 0

\(dp/dt = -(41c)/(60)\)

Now we can plug in \(p=41, dc/dt=15, and dp/dt=-(41c)/(60)\) to solve for c: \((41)^2 = -(41c)/(60)(20c)\) c = 2√82 Therefore, the value of c at the given instant is 2√82.

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