determine the period of a 1.5- m -long pendulum on the moon, where the free-fall acceleration is 1.624 m/s2

To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.

1. RR = 0.27%

2. RR = 16.03%

3. RR = 0%

4. RR = 0.003%

5. RR = 0.27%

6. RR = 2.28%

7. RR = 29.93%

8. RR = 0%

9. RR = 5.87%

Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.

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Answer:

B

Explanation:

Answer:

what is the answers? so i can't answer.

Explanation:

The statement that is true as regards movement of the box when pushed horizontally with constant velocity is given by;

Option D; The friction is equal to the applied force

The missing options are;

a) The friction is less than the applied force

b) There is no friction acting on the box

c) The friction is greater than the applied force

d) The friction is equal to the applied force

Now, if the frictional force was less than the applied force, it means the velocity of the box will gradually be increasing but we are told the velocity is constant.

Finally, if the frictional force is equal to the applied force, then the box will move with a constant motion.

Thus, in conclusion the friction is equal to the applied force.

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The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

\(V_x = Vcos(\theta)\)

Substituting the given parameters into the formula, we have;

\(\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5\)

Horizontal component, Vx = 15 m/s

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Nuclear fission should be used as the source of energy if the mentioned criteria's are met.

Nuclear fission is a reaction in which the nucleus of an atom splits into two or more smaller nuclei. The fission process often produces gamma photons, and releases a very large amount of energy.

Given is the name of a term in nuclear physics → Nuclear Fission.

It is known to us that the nuclear fission can provide sustainable and cheap energy for longer period of time. However, it cannot be neglected that it was nuclear fission only that is responsible for events at Chernobyl. The nuclear bombs, in Hiroshima and Nagasaki are responsible for deaths of more than 226,000 peoples. The generated byproducts are dangerous for human and animal health and can lead to long term health issues. According to me, the nuclear fission should be used as the source of energy under the following conditions -

Therefore, according to me, nuclear fission should be used as the source of energy if the above mentioned criteria's are met.

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Answer:

When you add ice to hot water, the ice melts and the hot water cools

Explanation:

When ice is poured in a hot cup of water, the ice melts and then mixes with the hot water cooling and lowering the temperature. The weight increases when ice added. process occurring: ice melting to liquid.

The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:

Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz

Now, we can substitute the values into the equation:

E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)

E = 8.33929859 × 10^-28 J

The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:

E = (8.33929859 × 10^-28 J) × (10^3)

E = 8.33929859 × 10^-25 J

Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

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This means that the acceleration due to gravity on the surface of this planet is 4 times greater than the acceleration due to gravity on Earth's surface.

The acceleration due to gravity on a planet's surface can be calculated using the formula:

g = (G * M) / R^2

where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.

In this case, the mass of the planet (M) is twice the mass of Earth, so M = 2 * M_earth. The radius (R) is half the Earth's radius, so R = 0.5 * R_earth.

Now, we can plug these values into the formula:

g_new = (G * (2 * M_earth)) / (0.5 * R_earth)^2

To simplify this expression, we can write the Earth's gravitational acceleration (g_earth) as:

g_earth = (G * M_earth) / R_earth^2

Now, divide g_new by g_earth:

g_new / g_earth = [(G * (2 * M_earth)) / (0.5 * R_earth)^2] / [(G * M_earth) / R_earth^2]

The G, M_earth, and R_earth^2 terms cancel out:

g_new / g_earth = 2 / 0.25

So, g_new = 4 * g_earth

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Answer:

Design 2

Explanation:

I had this same question

My answer:

"Design 2 is the well-designed one, because the air molecules are the most compact and could protect the individual better than 1,3,and no air bag."

Answer:

water

Explanation:

water is 1000 kg/m3 while air is 1.225 kg/m3

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

\(F=\dfrac{kq_1q_2}{r^2}\)

Where

q₁ and q₂ are charges

r is the distance between charges

When  each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

\(F'=\dfrac{kq_1'q_2'}{r'^2}\)

Apply new values,

\(F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F\)

So, the new force becomes 64 times the initial force.

Due to the Earth's rotation, the seas' neap tides alter every six hours or so. The Moon and the Sun's gravitational pull on the ocean's water produces the tides themselves.

Waves from deep water become breaking waves when they enter the shallow water. The water particles drag along the bottom and flatten their orbit when the wave energy contacts the ocean floor (Fig. 4.18 B). When the water depth is less than half the wavelength (D 1/2 L), transitional waves are produced.

A wave's energy release when it approaches a beach or coastline creates a current that travels parallel to the shoreline. A "longshore current" is the name given to this kind of current.

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Answer:

A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.

The two football layers will have a velocity of 3.36 m/s (to the right) immediately after the collision.

Before the collision, the total momentum of the system is given by:

p = m1v1 + m2v2

Plugging in the numbers, we get:

p = (81 kg)(6.5 m/s) + (140 kg)(0 m/s)

p = 526.5 kg m/s

The total momentum of the system after the collision is:

p' = (81 kg + 140 kg) * v

Using the principle of conservation of momentum, we can equate p and p', and solve for v:

p = p'

(81 kg)(6.5 m/s) + (140 kg)(0 m/s) = (81 kg + 140 kg) * v

Solving for v, we get:

v = (81 kg)(6.5 m/s) / (81 kg + 140 kg)

v = 3.36 m/s

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The force f (in n) the person is exerting on the mower is 18 n.

The force of friction opposing the motion refers to the force that acts in the opposite direction to the motion of an object and makes it harder to move.

According to the given statement, the force of friction opposing the motion is equal to the force f (in N) the person is exerting on the mower.

This indicates that the person's pushing force must be equal to the force of friction opposing the motion for the mower to move at a constant speed.

Using the above information, we can calculate the force f (in N) that the person is exerting on the mower as 18 n since it is equal to the force of friction opposing the motion.

Therefore, the person must push with a force f (in N) of 18 n to overcome the friction and maintain a constant speed for the mower.

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Answer:

False

Explanation:

This depends on how much air is in the ball, I think

According to the rules of continuity, if you are following a subject moving through space and the subject exits screen right (the right of the screen), they should enter the next shot from the left side of the screen. This is known as the 180-degree rule and is used to create a sense of spatial coherence between shots.

The 180-degree rule states that the camera should stay on one side of the action, meaning that a character's movement should remain consistent. To explain further, if a character is moving right, they should keep moving right as they move through the various shots. The same applies for movement left, up, and down. If a character moves off screen right, they should enter the next shot from the left. This creates a smooth and logical transition from shot to shot, which helps the audience understand the spatial relationship between characters.

In addition to the 180-degree rule, other aspects of continuity editing are used to create a cohesive narrative. Continuity editing includes matching eyelines (the direction a character is looking in a shot), matching facial expressions, and matching camera angles. All these elements, along with the 180-degree rule, help create a sense of continuity and flow between shots.

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Answer:

(A). The force acting on the rocket is mg.

(B). The initial upward acceleration of the rocket is 6.2 m/s²

Explanation:

Given that,

Mass of rocket = 5 kg

Force = 80 N

Time = 4 sec

(A). We need to draw the figure

The force acting on the rocket at each of the intervals is shown in figure.

The force acting on the rocket is mg.

(B). We need to calculate the initial upward acceleration of the rocket

Using balance equation

\(ma=F-mg\)

\(a=\dfrac{F-mg}{m}\)

Put the value in the equation

\(a=\dfrac{80-5\times9.8}{5}\)

\(a=6.2\ m/s^2\)

Hence, (A). The force acting on the rocket is mg.

(B). The initial upward acceleration of the rocket is 6.2 m/s²

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 80 × 4

We have the final answer as

Hope this helps you

Answer:

A & C

Explanation:

Answer:

A and C

Explanation:

Answer:

because they need light

Explanation:

The given statement is true.

The following information should be considered;

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Answer:

(a)   the gravitational influence on visible matter can not be explained by matter that can be seen.

Answer:

left atrium

Explanation:

its the first chamber of the heart to receive oxygenated blood from the lungs

A 2.0-kg item is subjected to a force of 6.0 n to the right across a 3.0 meter distance. The item has had 18 J of work done to it.

F=6.0 N, the rightward force

The object's mass is m=2.0 kg.

The object's force was applied across a distance of 3.0 meters.

the work carried out on the thing.

The amount of energy transferred from a source to an object by the application of an external force is measured as the work done.

The product of the applied force and the distance over which it was applied determines the amount of work that was completed.

As a result, W=f ×d provides the work performed.

When known values are substituted,

W=6×3

W=18 J

Final response:

18.0 J worth of work was done on the item.

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The proton's speed as it passes through point P is 1.66×10⁶ m/s.

The proton's speed at point P can be determined by the equation:

KE = PE + ( mv²/2 )

where,

KE= kinetic energy

PE = potential energy

m = mass of the proton

v = speed of the proton.

Given

Proton's initial speed is v₀ = 2.8×10⁶ m/s

By putting the values in the question the solution is as follows so as the Proton's speed at point P can be calculated as:

v = √(2KE/m)

= √(2 ×2.8 × 10⁶ m/s² / 1.67 × 10⁻²⁷ kg)

= 1.66 × 10⁶ m/s

Therefore, the proton's speed as it passes through point P is 1.66×10⁶ m/s.

Your question is incomplete most probably your full question was

A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.8×106 m/s.What is the proton's speed as it passes through point P?Express your answer to two significant figures and include the appropriate units.

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Answer:

A

Explanation:

They Are Smoother and the other guy makes no sense.