determine whether each description applies to electrophilic aromatic substitution or nucleophilic aromatic substitution.

In order to calculate the apparent weight of the person when the elevator is accelerating upward, we need to consider the forces acting on the person. The apparent weight of the person when the elevator is accelerating upward with an acceleration of 2.20 m/s^2 is 900 N.

The forces involved are the gravitational force (weight) and the normal force exerted by the scale. When the elevator accelerates, there is an additional force acting on the person due to the acceleration.

Let's calculate the apparent weight:

Calculate the gravitational force (weight):

Weight = mass × gravitational acceleration

Weight = 75 kg × 9.8 m/s^2

Weight = 735 N

Calculate the net force in the vertical direction:

Net Force = mass × acceleration

Net Force = 75 kg × 2.20 m/s^2

Net Force = 165 N

Determine the apparent weight:

Apparent Weight = Weight + Net Force

Apparent Weight = 735 N + 165 N

Apparent Weight = 900 N

Therefore, the apparent weight of the person when the elevator is accelerating upward with an acceleration of 2.20 m/s^2 is 900 N.

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From counting craters on each asteroids , astronomers have realized that the surface of ida is older than the surface of gaspra.

Ida, and Gaspra are three objects located in the asteroid belt between Mars and Jupiter.

Crater counting is a method for estimating the age of a planet's surface based upon the assumptions that when a piece of planetary surface is new, then it has no impact craters; impact craters accumulate after that at a rate that is assumed known.

Counting how many craters of various sizes there are in a given area allows determining how long they have accumulated and consequently, how long ago the surface has formed. Hence , from counting craters on each asteroids ,astronomers have realized that the surface of ida is older than the surface of gaspra.

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Answer:

Explanation:

Thus, total 4+4=8 C atoms are present per unit cell of diamond. Carbon has an electronic arrangement of 2,4. In diamond, each carbon shares electrons with four other carbon atoms - forming four single bonds.

The capacitive resistance in a 120 nf capacitor used in a standard 120 volt ac circuit with a frequency of 60hz is 26.53 ohms.

Capacitive resistance is a type of impedance that opposes the flow of alternating current in a circuit.

It is calculated using the formula Xc = 1 / (2πfC), where Xc is the capacitive reactance, f is the frequency of the alternating current, and C is the capacitance of the capacitor.
In this case, the capacitance is 120 nf, the frequency is 60hz, and using the formula, we get Xc = 1 / (2π x 60 x 120 x 10^-9) = 26.53 ohms.

Hence, the capacitive resistance in a 120 nf capacitor used in a standard 120 volt ac circuit with a frequency of 60hz is 26.53 ohms, which is calculated using the formula Xc = 1 / (2πfC).

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Answer:

Fission  - refers to splitting of a single atom into multiple atoms

Fusion - refers to multiple atoms (usually two) fusing to form a single atom

Hence frequency of the standing wave is 2 s⁻¹

Standing waves are formed when 2 waves of same wavelength and amplitude travelling in the opposite direction are superposed. Standing waves do not transport energy.

Here,

Length of the string, L = 5 m

Speed of the wave, v = 20 m/s

From the figure we can see that it is a string having two nodes and only one antinode. That means it is the first harmonic.

For first harmonic,  L = λ/2

So, wavelength, λ = 2L = 2x 5

   λ = 10 m

Therefore frequency, f = v/λ

  f = 20/10

  f = 2 s⁻¹

Hence frequency of the standing wave is 2 s⁻¹

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Your question was incomplete. Attaching the image here.

Answer:

the last one, the third one, and the first one.

Answer:

Displacement is a measurement that includes direction, displacement is the difference between a starting point and an ending point, and displacement is measured as a straight line between a starting point and an ending point.

Explanation:

Answer: D

Explanation:

B. Vesicle does NOT describe a structural feature of a volcano.

A vent, fissure, and magma chamber are all structural features, while a vesicle refers to a small cavity in volcanic rock, formed by trapped gas bubbles during the solidification of lava. A vent is an opening in the Earth's surface that allows volcanic material to escape. A fissure is a large crack in the Earth's surface that allows lava to flow. A magma chamber is a large underground reservoir containing molten rock. A vesicle is an air pocket inside rocks formed by the expansion of gases during volcanic eruptions.

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To achieve a net gravitational force of zero on a third small-sized mass placed between a 155-kg mass and a 275-kg mass, it should be positioned approximately 0.98 meters from the 155-kg mass.

To find the position where the net gravitational force on the third mass is zero, we need to consider the gravitational forces exerted by the other two masses.

Let's label the masses as follows:

Mass 1: 155 kg

Mass 2: 275 kg

Mass 3: Unknown mass to be placed

According to Newton's law of universal gravitation, the gravitational force between two masses is given by:

F = (G * m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses, and r is the distance between the masses.

Since we want the net gravitational force on the third mass to be zero, the forces exerted by Mass 1 and Mass 2 on Mass 3 must be equal in magnitude and opposite in direction.

Assuming the distance between Mass 1 and Mass 3 is x, and the distance between Mass 2 and Mass 3 is 1.50 m - x, we can equate the gravitational forces:

(G * m1 * m3) / x^2 = (G * m2 * m3) / (1.50 - x)^2

Simplifying the equation, we find:

m1 / x^2 = m2 / (1.50 - x)^2

Plugging in the given values, we can solve for x. The calculated value will give us the distance from Mass 1 where the net gravitational force on Mass 3 is zero.

Note: The numerical calculations are not provided in the response, as they require specific values for m1 and m2. However, following the outlined steps and formulas will allow you to obtain the numerical result.

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Answer: the thing that brings you life- h2o- idrk the question but if this helps your welcome ^-^have a good day

Explanation:

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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A vector is a quantity that has both direction and magnitude, especially when used to determine where one point in space is in relation to another.

The category of vector algebra includes algebraic operations on vectors. In vector algebra, the algebraic operations involving the magnitude and direction of vectors are carried out. To execute addition and multiplication operations on physical values that are represented as vectors in three-dimensional space, vector algebra is helpful in many applications in physics and engineering.

According to the question :

θ = -224+360+75.9

θ = 211.9

\(|U| = \sqrt{V^2+W^2+2VWcos\theta}\)

= \(\sqrt{448^2+336^2+2*448*336 cos 211.9 }\)°

|U| =240.85 unit.

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The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.

The launching of a cannonball is a case of projectile motion.

The formula for the range(R) of a projectile is

R = 2 u² sin(θ) cos(θ)/g

Here,

u = initial speed with which the projectile is launched = 35 m/s

θ = Angle at which projectile is launched = 50°

R = 2 (35)² sin(50) cos(50)/ 9.8

R = 2 x 1225 x 0.76 x 0.64/9.8

R = 119.1 m

Thus, The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.

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If an object is moving along a straight line at a constant speed of 20 meters/second, then the object travels 80 meters during the first four seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem we have to find out the distance traveled in the first four seconds when If an object is moving along a straight line at a constant speed of 20 meters/second,

The total distance traveled by the object = speed of the object×time

                                                                    =20 meters/second×4 seconds

                                                                    =80 meters

Thus, the correct answer is option D.

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Answer:

D. Combustion and subsequent gas expansion will not occur.

Explanation:

I got it right on the test.

If the spark plug on a heat engine is not functioning properly, combustion and subsequent gas expansion will not occur.

Heat engines refer to those engines that function via the combustion of a fuel.  This fuel is burnt in a combustion chamber and the energy generated enables the system to work.

The function of the spark plug is to create the explosion which makes the engine produce power. If the spark plug on a heat engine is not functioning properly, combustion and subsequent gas expansion will not occur.

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Answer:

Solon,

total mass (kg)= 100kg

height (h)= 25m

acceleration due to gravity = 9.8m/s²

so,

work done =m*g*h

= 100*9.8*25

= 24,500 joule

The work done by the crane in lifting the given mass of concrete to the given vertical height is 24500 Joules.

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where f is force applied and d is distance travelled.

Note that, the concrete is lifted upward, Weight of the concrete becomes mass multiply by acceleration due to gravity. g = 9.8m/s²

F = Weight = mg

Given that;

W = F × d

W = (mg) × d

W = ( 100kg × 9.8m/s² ) 25m

W = 980kgm/s² × 25m

W = 24500kgm²/s²

W = 24500J

Therefore, the work done by the crane in lifting the given mass of concrete to the given vertical height is 24500 Joules.

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Answer: the atom is mostly empty space with a tiny, dense, positively-charged nucleus

Explanation: Rutherford's gold foil experiments involved firing positively charged alpha particles at a piece of gold/metal foil. The alpha particles that were fired at the gold foil were positively charged. Most of the time, the alpha particles would pass through the foil without any change in their trajectories, which is what was expected if JJ Thomson's plum pudding model of the atom was correct. However, occasionally the alpha particles would be deflected to some degree, and sometimes an alpha particle would bounce back directly toward the experimenter. Rutherford likened this to firing a 15-inch artillery shell at a sheet of tissue paper and the shell came back to hit you.

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Rutherford's gold foil experiment demonstrated the concept of the nucleus of the atom.What is Rutherford's gold foil experiment?

Rutherford's gold foil experiment is an experiment that was conducted by Ernest Rutherford in 1911 to determine the structure of the atom. Rutherford bombarded alpha particles at thin gold foil and noted their trajectory and path.The experiment was conducted to answer the prevailing model of the atom's structure, which was the Thomson atomic model.

According to the Thomson atomic model, the atom's positive charge is evenly distributed throughout the atom, like raisins in a pudding. Rutherford's experiment refuted this hypothesis and provided a new model that supported his findings.

The findings of the gold foil experiment:

Rutherford's experiment led him to conclude that the positive charge of the atom is concentrated in the nucleus, a central part of the atom. In this model, electrons orbit the nucleus, like planets orbiting the sun.

Rutherford's gold foil experiment demonstrated that the atom is made up of mostly empty space, with a small, dense, and positively charged nucleus at the center. This discovery paved the way for further research into atomic structure and the discovery of subatomic particles like protons and neutrons.

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The smallest angle (in rad) between the beam of X-rays and the crystal planes for which a reflection occurs is approximately 0.3636 radians. According to Bragg's law, the condition for constructive interference and reflection is given by 2d sinθ = nλ, where d is the separation between the crystal planes, θ is the angle between the beam and the planes, λ is the wavelength of the X-rays, and n is an integer representing the order of the reflection.

To calculate the smallest angle θ between the beam of X-rays and the crystal planes, we can use the formula θ = λ / d, where θ is the angle, λ is the wavelength of the X-rays, and d is the separation between the crystal planes.

Given:

Wavelength of X-rays (λ) = 1.2 nm

Separation between crystal planes (d) = 3.3 nm

Substituting these values into the formula, we get:

θ = λ / d

θ = 1.2 nm / 3.3 nm

Dividing the two values, we find:

θ ≈ 0.3636 radians

Therefore, the smallest angle (in rad) between the beam of X-rays and the crystal planes for which a reflection occurs is approximately 0.3636 radians.

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The length of the rectangle is x ≈ 2.72 inches, to the nearest hundredth of an inch.

We can approach this problem using the Pythagorean theorem and some basic geometry.

We are given that the radius of the semicircle is 1.5 inches and the radius of the chamfering is 0.52 inches. Let's call the height of the rectangle h, the length of the rectangle x, and the thickness of the rectangle y. Then we have:

h + 1.5 + 0.52 = 1.3

Solving for h, we get:

h = 1.3 - 1.5 - 0.52 = -0.72

This doesn't make sense, since the height of the object should be positive. Therefore, there must be an error in the problem statement. Perhaps the height of the rectangle is actually y instead of h?

Assuming that the height of the rectangle is y, we have:

y + h + 1.5 + 0.52 = 1.3

Solving for h, we get:

h = 1.3 - y - 1.5 - 0.52

Now, let's use the Pythagorean theorem to find x. We can draw a right triangle with one leg equal to y and the other leg equal to x/2 + 1.5 + 0.52. The hypotenuse of the triangle is equal to the diameter of the semicircle, which is 3 inches. Therefore, we have:

y^2 + (x/2 + 1.5 + 0.52)^2 = 3^2

Simplifying this equation, we get:

y^2 + x^2/4 + x + 3.04y + 3.04 = 9

Multiplying both sides by 4, we get:

4y^2 + x^2 + 4x + 12.16y + 12.16 = 36

Simplifying again, we get:

x^2 + 4x + 4y^2 + 12.16y - 23.84 = 0

This is a quadratic equation in x. We can solve it using the quadratic formula:

x = (-4 ± sqrt(4^2 - 4(4y^2 + 12.16y - 23.84))) / 2

Simplifying, we get:

x = (-2 ± sqrt(16 - 4(4y^2 + 12.16y - 23.84))) / 2

x = (-2 ± sqrt(4y^2 + 12.16y - 7.84)) / 2

We want to find x to the nearest hundredth of inches. Let's plug in y = 0.35 and use a calculator to solve for x:

x = (-2 ± sqrt(4(0.35)^2 + 12.16(0.35) - 7.84)) / 2

x ≈ 2.72 or x ≈ -6.72

We reject the negative solution since x is a length, so it must be positive.

Therefore, the length of the rectangle is x ≈ 2.72 inches, to the nearest hundredth of an inch.

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Answer:

4 m/s in negative acceleration

Explanation:

Acceleration = V- U/t

Where V is the final velocity

U is the initial velocity and t is the time given.

U = 65 m/s

V= 25 m/s

T= 10 seconds

Acceleration= (25m/s - 65m/s)÷10secs

= - 40/10

= -4m/s^2

Hence, it has a negative acceleration.

Answer:

A. negative acceleration of 4 m/s2

Hope this helps!

Explanation:

Answer :Gravity is the force that attracts two objects towards each other; when an object falls under the influence of gravity alone, it is said to be in free fall and will accelerate at a constant rate; as the velocity of a falling object increases, air resistance will begin to slow it down until it reaches terminal velocity; when an object is thrown or launched, it follows a curved path known as projectile motion which is influenced by both gravity and air resistance.

Answer:

b. Photosynthesis

Explanation:

This because it is an irreversible process.

\(.\)

Explanation:

1. Force is something that pushes or pulls you

2. The 150 lbs person accelerated faster because they had less force pushing or pulling them down.

Answer:

g e c a

Explanation:

Hope I helped!

Answer:

32.99m/s

Explanation:

Using the formula for calculating the resultant velocity according to Pythagoras theorem

R² = 12²+x²

35.11² = 12²+x²

X² = 35.11²-12²

X² = 1232.7121-144

X² = 1088.8121

X = √1088.8121

X = 32.99m/s

Hence the unknown velocity produced by the plane engines is 32.99m/s

The unknown velocity produced by the plane engines will be "32.99 m/s".

Given:

Resultant velocity,

Wind speed,

By using the Pythagoras theorem, we get

→         \(R^2= 12^2+x^2\)

→    \(35.11^2=12^2+x^2\)

→ \(1232.712=122+x^2\)

→           \(x^2= 1099.8121\)

→             \(x = \sqrt{1088.8121}\)

→                \(= 32.00 \ m/s\)

Thus the answer above is right.

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A metal tape measure was calibrated to 25 °C. If you measure a plastic pipe outdoors at 15°C with a tape measure, the measured value will be less than the actual measured value. Correct option is A.

Calibration is verifying the accuracy of a measuring device by comparing it to a standard. It may also be necessary to adjust the equipment to meet standards. Calibration is the process of configuring the instrument to provide acceptable sample results. Eliminating or minimizing factors that lead to inaccurate measurements is a fundamental aspect of equipment design.

Maintaining measurement precision, uniformity, and reproducibility is crucial for obtaining trustworthy standards and outcomes. Regular calibration is essential for maintaining the quality, safety, and lifespan of your devices.

The given question is incomplete. The complete question is 'You need to measure the height of a small tree. Your metal measuring tape has been sitting in the sun on a hot summer day while your coworker's measuring tape has been in an air-conditioned car.'

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The correct option is D. the volume of the ventricle when it is most full.

The volume of the ventricle when it is most full is the most correct description of end-diastolic volume.

It can be defined as the amount of blood in the ventricle immediately before a cardiac contraction or systole occurs. End-diastolic volume is the volume of blood in the ventricles at the end of diastole, after filling with blood from the atria, before the ventricles contract to begin systole.

ventricles are hollow chambers or cavities found in the heart and brain. In the heart, there are two ventricles responsible for pumping blood, while in the brain, there are four interconnected ventricles that produce and circulate cerebrospinal fluid.

Therefore, the correct option is D. the volume of the ventricle when it is most full.

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