Determine which statement or statements are true. texts sent = 8 ; calls made = 5 For every 5 texts sent there were 8 calls made The ratio of texts sent to calls made was 8:5 For every 5 calls made there were 8 texts sent The ratio of texts sent to calls made was 5:8

Answer:

where

is

the

attachment

bruv?

Answer:

We wouldn't know because we have no information on the marbles.

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the information given:

mean life span of a brand of automobile = 35,000

standard deviation of a brand of automobile = 2250 miles.

the z-score that corresponds to each life span are as follows.

the standard z- score formula is:

\(z = \dfrac{x - \mu}{\sigma}\)

For x = 34000

\(z = \dfrac{34000 - 35000}{2250}\)

\(z = \dfrac{-1000}{2250}\)

z = −0.4444

For x = 37000

\(z = \dfrac{37000 - 35000}{2250}\)

\(z = \dfrac{2000}{2250}\)

z = 0.8889

For x = 3000

\(z = \dfrac{30000 - 35000}{2250}\)

\(z = \dfrac{-5000}{2250}\)

z = -2.222

From the above z- score that corresponds to their life span; it is glaring  that the tire with the life span 30,000 miles has an unusually short life span.

For x = 30,500

\(z = \dfrac{30500 - 35000}{2250}\)

\(z = \dfrac{-4500}{2250}\)

z = -2

P(z) = P(-2)

Using excel function (=NORMDIST -2)

P(z) = 0.022750132

P(z) = 2.28th percentile

For x =  37250

\(z = \dfrac{37250 - 35000}{2250}\)

\(z = \dfrac{2250}{2250}\)

z = 1

Using excel function (=NORMDIST 1)

P(z) = 0.841344746

P(z) = 84.14th percentile

For x = 35000

\(z = \dfrac{35000- 35000}{2250}\)

\(z = \dfrac{0}{2250}\)

z = 0

Using excel function (=NORMDIST 0)

P(z) = 0.5

P(z) = 50th percentile

a.  The z score of each life span should be -0.4444, 0.889, and 2.2222.

b.  The percentile of each life span should be 0.0228, 0.8413 and  0.5000.

Given that,

(a)

The z score should be

\(Z1 = \frac{34000-35000}{2250} = -0.4444\\\\Z2 = \frac{37000-35000}{2250} = 0.8889\\\\Z3 = \frac{30000-35000}{2250} = -2.2222\\\\\)

The tire with life span of 30000 miles would be considered unusual

(b)

The percentile should be

\(Z1 = \frac{30500-35000}{2250} = -2\)

p(Z1 < -2) = NORMSDIST(-2) = 0.0228

\(Z2 = \frac{37250-35000}{2250} = 1\)

p(Z2 < 1) = NORMSDIST(1) = 0.8413

\(Z3 = \frac{35000-35000}{2250} = 0\)

p(Z3 < 0) = NORMSDIST(0) = 0.5000

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Answer:

The approximate percentage of lightbulb replacement requests numbering between 10 and 43 is of 49.85%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 43

Standard deviation = 11

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above the mean.

What is the approximate percentage of lightbulb replacement requests numbering between 10 and 43?

43 is the mean

10 = 43 - 3*11

So 10 is 3 standard deviations below the mean.

Of the 50% of measures below the mean, 99.7% are between 3 standard deviations below the mean(10) and the mean(43). So

0.5*0.997 = 0.4985.

0.4985*100% = 49.85%.

The approximate percentage of lightbulb replacement requests numbering between 10 and 43 is of 49.85%.

Answer:

Step-by-step explanation:

volume = 1/3 π r² h

where h = 15 yd.

           r = 5 yd.

plugin values into the equation:

volume = 1/3 π r² h

            = 1/3 * π * 5² * 15

            = 392.7 yd³

Answer:

A. 392•8yd^3

Step-by-step explanation:

To divide 30 into five parts such that the first and last parts are in the ratio of 2:3, we can follow these steps:

1. Determine the ratio between the first and last parts. In this case, it is 2:3.

2. Add the ratio values together to find the total number of parts: 2 + 3 = 5.

3. Divide the total value (30) by the total number of parts (5) to find the value of each part: 30 / 5 = 6.

4. Multiply the value of each part by the respective ratio values to obtain the individual parts:

- First part: 2 * 6 = 12

- Second part: 6

- Third part: 6

- Fourth part: 6

- Last part: 3 * 6 = 18

Therefore, the five parts of 30, with the first and last parts in the ratio of 2:3, are 12, 6, 6, 6, and 18.

Answer:

2x - 2,000 = 28,000

Step-by-step explanation:

1. Define Variables

          Frank's Income = x

2. Write Equation

           2x - 2,000 = 28,000

3. Solve (if necessary)

           2x - 2,000 = 28,000

           2x = 30,000

           x = 15,000

Answer:

14

Step-by-step explanation:

Answer:

Answer:

x = 12

Step-by-step explanation:

m∠S + m∠T = 180

8x + 7x = 180

15x = 180

x = 12

does this help?

If it dilated by a factor of 2, we will multiply the coordinates by 2 to have:

A'(11, 9) B (12, 4) C (7, 3) D (6,8)

If the coordinate points A (1 1/2, 12) B (-3, 6) C (-9, 9) is dilated by a factor of 1 1/3, the resulting coordinates will be A'(3, 16) B'(-4, 8) C'(-12, 12)

Dilations is a transformation technique used to enlarge or diminish an image.

Given the coordinate points A (5.5, 4.5) B (6, 2) C (3.5, 1.5) D (3,4), it dilated by a factor of 2, we will multiply the coordinates by 2 to have:

A'(11, 9) B (12, 4) C (7, 3) D (6,8)

Similarly if the coordinate points A (1 1/2, 12) B (-3, 6) C (-9, 9) is dilated by a factor of 1 1/3, the resulting coordinates will be A'(3, 16) B'(-4, 8) C'(-12, 12)

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Answer:

9.75

Step-by-step explanation:

-25 = -4p + 19

-25 - 19 = -4p

-39 ÷ -4 = p

9.75 = p

Answer:

Perimeter of base = 18 ft

Height = 7 ft

Base area = 12ft²

SA= 150 ft² *

Step-by-step explanation:

Perimeter of base = 8+5+5=18 ft

Height = 7 ft

Base area = 1/2x8x3=12ft²

SA= (8x7)+(12+12)+2(5x7)=56+24+70=150 ft²

*There are several different way to figure out the surface area, so I’m not sure exactly how they want it displayed.  150 is the answer though.  Plus, I think there was supposed to be an addition sign between the first two parentheses.

Answer:

To one decimal place,

y = 16.3 m

Step-by-step explanation:

Using SOHCAHTOA,

In this case we need to use CAH,

WE know the angle = 25 and the hypotenuse H = 18,

so,

y = adjacent

\(cos(angle) = y/H\\y = (18)(cos(25))\\y = 16.3135\\y = 16.3\)

Answer: 16.3 in.

Step-by-step explanation:

use SOH CAH TOA

cos x = adj/hyp

cos 25  = y/18

18 cos 25  = y

y= 16.3

Answer:

k≥12

Step-by-step explanation:

if k's smallest amount is 12, k has to be bigger (greater than) or equal to 12

therefore:

k≥12

Here is the link to the answer:

bog.com

To maximize the volume, of the rectangular prism, the carton should have dimensions of approximately 10.74 inches (length), 10.74 inches (width), and 5.37 inches (height).

Assuming the height of the rectangular prism is h inches.

According to the given information, the length and width of the prism will be twice the height, which means the length is 2h inches and the width is also 2h inches.

The total surface area of the rectangular prism is given by the formula:

Surface Area = 2lw + 2lh + 2wh

Substituting the values, we have:

576 = 2(2h)(2h) + 2(2h)(h) + 2(2h)(h)

576 = 8h² + 4h² + 4h²

576 = 16h² + 4h²

576 = 20²

h² = 576/20

h² = 28.8

h = √28.8

h = 5.37

The height of the prism is approximately 5.37 inches.

The length and width will be twice the height, so the length is approximately 2 * 5.37 = 10.74 inches, and the width is also approximately 2 * 5.37 = 10.74 inches.

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The length of the fence around the enclosure not including the gates is:2l + 2w + 8 m

To find the length of the fence around the enclosure, we need to first find the perimeter of the rectangle and then subtract the combined length of the two gates from it.

Let's assume the length of the rectangle is 'l' and the width is 'w'.

From the given data, we know that each gate is 4 m wide.

Therefore, the width of the rectangle is:

Width = w + (4 m + 4 m) = w + 8 m

The perimeter of the rectangle is:

P = 2l + 2(w + 8 m) = 2l + 2w + 16 m

Now, we need to subtract the combined length of the two gates from the perimeter:

P - 2 × 4 m = 2l + 2w + 16 m - 8 m = 2l + 2w + 8 m

So, the length of the fence around the enclosure not including the gates is:2l + 2w + 8 m

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the counting number just before C5F16 is 3,072.

Answer:

224

Step-by-step explanation:

360.-136.

29 inches.

_________________

ANSWER

EXPLANATION

a) At the start of the experiment, the scientist had 276 grams of radioactive goo and after 255 minutes, the sample decayed to 17.25 grams.

To find the half-life, we can apply the formula for half-life:

where N0 = initial amount

N(t) = amount after time t

t = time elapsed

t1/2 =half-life

From the question, we have that:

We have to find the half-life, t¹/₂. That is:

Converting to logarithmic function:

Therefore, the half-life is 63.75mins.

b) Therefore, using the half-life, we have that the equation G(t) for the amount of goo remaining at time t is:

c) To find the amount of goo remaining after 68 mins, we have to find G(t) when t = 68.

That is:

That is the amount remaining after 68 minutes.

The graph of ordered pairs (0, -5), (1, -3), (2, -1), (3, 1) is given below.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is y=2x-5.

Substitute x=0, 1, 2, 3, 4, ..... in the equation y=2x-5, we get

When x=0,

y=-5

When x=1,

y=-3

When x=2,

y=-1

When x=3

y=1

So, the ordered pair is (0, -5), (1, -3), (2, -1), (3, 1) and so on.

Therefore, the graph of ordered pairs (0, -5), (1, -3), (2, -1), (3, 1) is given below.

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Answer:

At most one of the adults has high blood pressure.

Step-by-step explanation:

Answer:

William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive.

Factor number 24 and 60:

Find the greatest common factor

Hence, the greatest number of bags William can make is 12.

Each of these bags will have  cans of fruit and  cans of vegetables.

If he made fewer bags, 6 bags, each of these bags will have  cans of fruit and  cans of vegetables.

If he made fewer bags, 4 bags, each of these bags will have  cans of fruit and  cans of vegetables.

If he made fewer bags, 3 bags, each of these bags will have  cans of fruit and  cans of vegetables.

If he made fewer bags, 2 bags, each of these bags will have  cans of fruit and  cans of vegetables.

Step-by-step explanation:

I think its this question

The surface area of the square Pyramid with a side length of 2 yards and a slant height of 2 yards is 12 square yards.

The surface area of a square pyramid, we need to calculate the area of each face and then sum them up.

A square pyramid has four triangular faces and one square base. The area of the base is equal to the side length squared, while the area of each triangular face can be found using the formula: (1/2) * base * height.

Given that the side length of the square pyramid is 2 yards and the slant height is also 2 yards, we can calculate the surface area as follows:

Area of the base = (side length)^2 = 2^2 = 4 square yards

Area of each triangular face = (1/2) * base * height = (1/2) * 2 * 2 = 2 square yards

Now, let's calculate the total surface area of the square pyramid:

Total surface area = Area of the base + 4 * Area of each triangular face

Total surface area = 4 + 4 * 2 = 4 + 8 = 12 square yards

Therefore, the surface area of the square pyramid with a side length of 2 yards and a slant height of 2 yards is 12 square yards.

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Triangle ADC also has a right angle at D, making it a right-angled triangle.

The exact value of x be 2.25.

The hypotenuse's square is equal to the sum of its two other side squares of a right-angled triangle, according to the Pythagoras theorem.

Triangle ADB exists even a right-angled triangle with right-angle at D.

Therefore, Base of Triangle ADB = BD = 4,

Height of Triangle ADB = AD = 3,

Hypotenuse of Triangle ADB = AB

Using the Pythagoras Theorem, we get,

\($\left[(A D)^2+(B D)^2\right]=(A B)^2$\)

substitute the values in the above equation, we get

or,\($(A B)^2=\left[(3)^2+(4)^2\right]$\)

simplifying the equation, we get

or, \($(A B)^2=[9+16]$\)

or, \($(A B)^2=25$\)

or, \($\sqrt{(A B)^2}=\sqrt{25}$\)

or, AB = 25

Triangle ADC is also a right-angled triangle with right-angle at D.

Therefore, Base of Triangle ADC = DC = x

Height of Triangle ADC = AD = 3,

And, Hypotenuse of Triangle ADC = AC

Using the Pythagoras Theorem, we get,

\(& {\left[(D C)^2+(A D)^2\right]=(A C)^2} \\\)

simplifying the equation, we get

\(& \text { or },(A C)^2=\left[(3)^2+(x)^2\right] \\\)

\(& \text { or },(A C)^2=\left[9+x^2\right]\)

Triangle ABC is also a right-angled triangle with right-angle at A. Therefore, Base of Triangle ABC = AC,

Height of Triangle ABC = AB = 5,

And, Hypotenuse of Triangle ABC =  BC = (4 + x)

Using the Pythagoras Theorem, we get,

\(& {\left[(A C)^2+(A B)^2\right]=(B C)^2} \\\)

\(& \text { or, }(B C)^2=\left[(A C)^2+(A B)^2\right] \\\)

substitute the values in the above equation, we get

\(& \text { or, }(4+x)^2=\left[\left(9+x^2\right)+(5)^2\right] \\\)

simplifying the equation, we get

\(& \text { or, }\left[4^2+(2 \times 4 \times x)+x^2\right]=\left[9+x^2+25\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]=\left[(9+25)+x^2\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]=\left[34+x^2\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]-\left[34+x^2\right]=0 \\\)

\(& \text { or, },(16-34)+8 x+\left(x^2-x^2\right)=0 \\\)

8x - 18 = 0

8x = 18

\(& \text { or, } x=\frac{18}{8} \\\)

\(& \text { or, } x=\frac{9 \times 2}{4 \times 2} \\\)

\(& \text { or, } x=\frac{9}{4} \\\)

Therefore, the value of x be 2.25.

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Answer:

10.60%

Step-by-step explanation:

We have to solve the above we have to apply bimonial and add each one, like this:

p (x <= 3) = p (x = 0) + p (x = 1) + p (x = 2) + p (x = 3)

p (x <= 3) = 8C0 * (0.65) ^ 0 * (0.35) ^ 8 + 8C1 * (0.65) ^ 1 * (0.35) ^ 7 + 8C2 * (0.65) ^ 2 * (0.35) ^ 6 + 8C3 * (0.65) ^ 3 * (0.35) ^ 5

p (x <= 3) = 8! / (0! (8-0)!) * (0.65) ^ 0 * (0.35) ^ 8 + 8! / (1! (8-1)!) * (0.65 ) ^ 1 * (0.35) ^ 7 + 8! / (2! (8-2)!) * (0.65) ^ 2 * (0.35) ^ 6 + 8! / (3! (8-3)!) * (0.65) ^ 3 * (0.35) ^ 5

p (x <= 3) = 0.1060

therefore the probability is 10.60%

Answer:

The probability that at most 3 of the southerners believe in angels is 10.61%

Step-by-step explanation:

Given;

65% believe in angels = p

then, 35% will not believe in angel = q

total sample number, n = 8

The probability that at most 3 southerners believe in angels is calculated as;

= p( non believe in angel) or p( 1 southerner believes and 7 will not believe) or p( 2 southerner believe and 6 will not believe) or p( 3 southerner believe and 5 will not believe)

= 8C₀(0.65)⁰(0.35)⁸ + 8C₁(0.65)¹(0.35)⁷ + 8C₂(0.65)²(0.35)⁶ + 8C₃(0.65)³(0.35)⁵

= 1(1 x 0.000225) + 8(0.65 x 0.000643) + 28(0.4225 x 0.00184) + 56(0.2746 x 0.00525)

= 0.1061

= 10.61%

Therefore, the probability that at most 3 of the southerners believe in angels is 10.61%

Answer:

  B. 3x¹¹ +9x⁷ +5x³ −x +4

Step-by-step explanation:

You want to identify the polynomial that has terms written in descending order of their degree.

The degree of a term is the exponent of x in that term. In the given polynomial, the term degrees are 3, 1, 7, 0, 11.

When these are put into descending order, that order is ...

  11, 7, 3, 1, 0

The answer to this question will be the polynomial with terms written in the order of their degree as shown above:

  3x¹¹ +9x⁷ +5x³ −x +4

__

Additional comment

When the exponent of x is 0, the value of the term x^0 is 1. That is why we can say the constant term is a term that has the variable to degree 0.

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Answer:

42

Step-by-step explanation:

Answer:

Here's an interesting project idea for mathematics that can relate three different topics:

Topic 1: Fractals

Topic 2: Chaos Theory

Topic 3: Differential Equations

Research Question: Can fractals be used to model chaotic systems described by differential equations?

In this project, you can explore the concept of fractals and their applications in modeling complex systems. You can also delve into chaos theory and differential equations to understand how they are used to describe chaotic systems. By combining these three topics, you can investigate whether fractals can provide a better understanding of chaotic systems by modeling them more accurately.

Your research paper can cover the following areas:

Introduction: Provide an overview of fractals, chaos theory, and differential equations, and explain their relevance to the research question.

Fractals: Discuss the properties of fractals and how they can be used to model complex systems. Provide examples of fractals in nature and technology.

Chaos Theory: Explain the concept of chaos and how it is described by differential equations. Discuss the importance of chaos theory in understanding complex systems.

Differential Equations: Provide an overview of differential equations and their applications in physics, engineering, and other fields. Explain how differential equations are used to model chaotic systems.

Combining the three topics: Explain how fractals can be used to model chaotic systems described by differential equations. Provide examples of fractals used in modeling chaotic systems and compare the results to traditional methods.

Conclusion: Summarize the findings of your research and discuss the implications of using fractals to model chaotic systems.

Overall, this project can be a challenging and rewarding exploration of the interplay between three different mathematical topics.

Step-by-step explanation: