differentiate between metals and non metal ​

Explanation

There are three main branches of science: physical science, Earth science and life science. Let's talk about each branch and the areas of study within each branch. Physical science is the study of inanimate natural objects and the laws that govern them.

Answer:

physical change

Explanation:

Answer:

Physical Change

Explanation:

A voltaic cell is an electrochemical cell that uses spontaneous redox reactions to generate electrical energy. A Cu/Cu2+ half-cell and an Hg/Hg2+ half-cell are included in the voltaic cell. The Cu2+ + 2 e− → Cu reaction has a standard potential of +0.34 V, whereas the Hg2+ + 2 e− → 2 Hg reaction has a standard potential of +0.79 V.

A voltaic cell is an electrochemical cell that uses spontaneous redox reactions to generate electrical energy. A Cu/Cu2+ half-cell and an Hg/Hg2+ half-cell are included in the voltaic cell. The Cu2+ + 2 e− → Cu reaction has a standard potential of +0.34 V, whereas the Hg2+ + 2 e− → 2 Hg reaction has a standard potential of +0.79 V.

Net reaction of voltaic cell: Hg2+ + Cu → Hg + Cu2+

The spontaneous reaction for this voltaic cell can be written as follows: Hg2+ + Cu → Hg + Cu2+

We'll utilize the Nernst equation to calculate the cell potential since the standard reduction potentials for both half-cells are supplied. The equation for the Nernst equation is as follows: E = E° − (RT/nF) * ln(Q)

We'll utilize the following values to calculate the potential of the cell: E°cell = E°reduction (reduction half) - E°reduction (oxidation half)

E°cell = E°reduction (cathode) - E°reduction (anode)

E°cell = 0.79 - 0.34

E°cell = 0.45 Volts

Ecell = E°cell - (0.0592/n) * log(Q)

Ecell = 0.45 - (0.0592/2) * log (1/[Cu2+])

The given half-cell reactions indicate that there is 1 mol of Cu2+ for every 1 mol of Hg2+ reacting. As a result, Q = [Cu2+].

Ecell = 0.45 - (0.0592/2) * log (1/[Cu2+])

Ecell = 0.45 - (0.0296) * log (1/[Cu2+])

Ecell = 0.45 - (0.0296) * log (1/1)

Ecell = 0.45 V (rounded to 2 decimal places).

Hence, the answer is 0.45 V.

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Answer:

The interaction between the tectonic and the hydrologic systems causes constant recycling of the materials of the Earth's crust. Rocks are heated, metamorphosed, melted, weathered, sediment is transported, deposited and lithified, then it may be metamorphosed again in yet another cycle.

Explanation:

a) Chemical equation for the equilibrium that corresponds to Kb:Methylamine, CH3NH2, is a weak base. The hydroxide ions, OH-, combine with the weak base to produce a conjugate base and water.

The chemical reaction can be expressed as follows:CH3NH2 (aq) + H2O (l) ⇌ CH3NH3+ (aq) + OH- (aq)b) Using the value of Kb, calculate ΔG for the equilibrium in part a.ΔG° = -RTln(K)Kb = [CH3NH3+][OH-]/[CH3NH2]∴ ΔG° = -RTln[Kb][CH3NH2]/[CH3NH3+][OH-]Substituting values in the formula,ΔG° = -(8.3145 J/mol.K)(298K)ln(4.4x10-4)(0.120M)/(5.5x10-4M)(1.5x10-8M) = -2.3328 J/molc) The value of ΔG at equilibrium is zero. ΔG = ΔG° + RTln(Q)Since Q = K at equilibrium,ΔG = ΔG° + RTln(K) = 0d) The value of ΔG when [CH3NH3+]=[H+]=1.5*110^-8M, [CH3NH3+] = 5.5*10^-4M and [CH3NH2]=0.120M is- 17.96 kJ/mol.

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The Vostok ice core curve shows CO2 concentrations over the last 800,000 years.

The Vostok ice core, drilled in Antarctica at the Vostok Station, has provided valuable data on past climate conditions. By analyzing the ice layers, scientists can determine various parameters, including CO2 concentrations. The ice core data has allowed the reconstruction of CO2 levels in the atmosphere dating back hundreds of thousands of years, providing insights into long-term climate trends and the relationship between CO2 and global temperatures.

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Answer:

uhm

Explanation:

A new chemical waste in the lab must be started when the contents of the current container are a couple of inches below the brim of the container.

In a lab, waste chemicals are produced abundantly and are stored in a chemical waste container to avoid undesired events such as contamination, explosion, or eruption of fire.

A standard lab follows the proper guidelines and establishes strict rules and takes all the necessary measures to make sure safety of all the workers and materials.

However, the chemical waste container must be replaced with a new container when the level of chemical waste is a couple of inches below the brim.

This is because the chemical reaction keeps taking place inside the container over time which can expand the volume of the waste materials. Therefore, some space should be left in the container to avoid an overflow of hazardous material and explosions.

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Answer:

fddff s

Explanation:

v c dggbgzfx

1. Ensure Clear and Visible Placement: Machine controls should be located in a position that is easily accessible, visible, and within reach of the equipment operator. Clear and intuitive labeling or color-coding can also be used to enhance visibility and assist in identifying the controls quickly.

2. Provide Adequate Guarding: The machine controls should be positioned in a manner that minimizes the risk of accidental activation or unintended operation. This can be achieved by incorporating appropriate guarding or barriers around the controls to prevent inadvertent contact or interference.

3. Consider Ergonomics and Operator Comfort: When determining the location of machine controls, it is essential to consider ergonomic principles and operator comfort. Controls should be positioned in a way that allows operators to maintain a comfortable and natural posture while operating the equipment. This can help reduce the risk of operator fatigue, musculoskeletal disorders, and errors due to discomfort or awkward reach.

These rules aim to promote operator safety, minimize the potential for accidents, and ensure efficient and effective control of equipment involving fluid power components.

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The final temperature of the coffee in the thermos will be a result of the heat transfer between the coffee and the melting ice cubes.

When the ice cubes are dropped into the thermos containing coffee, heat transfer occurs between the two substances until they reach thermal equilibrium. The heat transfer process involves the transfer of heat from the coffee to the ice cubes, causing them to melt.

To calculate the final temperature, we can use the principle of conservation of energy. The heat gained by the ice cubes equals the heat lost by the coffee.

First, let's calculate the heat gained by the ice cubes. The specific heat capacity of ice is approximately 2.09 J/g°C. Since each ice cube weighs 11 g and starts at 0°C, the heat gained by the ice cubes is:

Q_ice = (mass_ice) x (specific heat capacity_ice) x (change in temperature)

= (11 g) x (2.09 J/g°C) x (final temperature - 0°C)

Next, let's calculate the heat lost by the coffee. The specific heat capacity of coffee is assumed to be the same as water, which is approximately 4.18 J/g°C. The initial temperature of the coffee is 85°C, and its volume is 150 cm³. Using the density of water (1 g/cm³), we can find the mass of the coffee

mass_coffee = (density_water) x (volume_coffee)

= (1 g/cm³) x (150 cm³)

Q_coffee = (mass_coffee) x (specific heat capacity_coffee) x (final temperature - 85°C)

Since the heat gained by the ice cubes is equal to the heat lost by the coffee, we can set up the equation:

Q_ice = Q_coffee

Substituting the respective values and solving the equation will give us the final temperature of the coffee.

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The total pressure of the mixture is 359.5 torr, that is calculated by using ideal gas equation.

Volume of N2, V1=4.0 L

Pressure of N2, P1=450 Torr=450/760 atm

Thus, number of moles of N2, n1= P1V1/RT

=(450/760)*4/0.082*338

=0.085 mol

Similarly,

Volume of O2, V2=3.5 L

Pressure of O2, P2=252 Torr=252/760 atm

Thus, number of moles of O2, n2= P2V2/RT

=(252/760)*3.5/0.082*338

=0.042 mol

Similarly,

Volume of CO2, V3=0.21 L

Pressure of CO2, P3=150 Torr=150/760 atm

Thus, number of moles of CO2, n3= P3V3/RT

=(2150/760)*30.21/0.082*338

=0.001 mol

Total number of moles = n1+n2+n3

=(0.085+0.042+0.21)

=0.128 mol

Total volume, V=7.5 L

Using, ideal gas law

Thus, total pressure, P=nRT/V

=0.128*0.082*338/7.5 atm

=0.473 atm

=0.473*760

=359.5 torr

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In the intestine, amino acids of the same general type compete for the same absorption sites, so a large dose of any one amino acid can limit the absorption of another. The given statement is true.

Organic substances known as amino acids have both functional groups for amino and carboxylic acids. Alpha-amino acids, which make up proteins, are by far the most significant amino acids in nature, despite the fact that there are hundreds of other types. The genetic coding only contains 22 alpha amino acids. The components of proteins are called amino acids. You need 20 of these for your body to function properly. They are the molecules that all living things require to build protein.

The use of traditional Chinese medicines at large doses has become more and more popular recently. However, the scientific significance of applying a large dose has not yet been fully elucidated.

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The binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond.  Option b

Aminoacyl-tRNA is a complex molecule that plays a crucial role in protein synthesis. It consists of a tRNA molecule covalently linked to an amino acid. The amino acid is attached to the 3' end of the tRNA molecule through an ester bond.

An ester bond is formed between the carboxyl group (-COOH) of the amino acid and the hydroxyl group (-OH) of the ribose sugar at the 3' end of the tRNA molecule. This ester bond is also referred to as an ester linkage. The formation of the ester bond is catalyzed by the enzyme aminoacyl-tRNA synthetase.

The ester bond in aminoacyl-tRNA is essential for protein synthesis. During translation, the aminoacyl-tRNA molecule carries the specific amino acid to the ribosome, where it is incorporated into the growing polypeptide chain. The ester bond is later hydrolyzed, releasing the amino acid for further use in protein synthesis.

In summary, the binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond between the carboxyl group of the amino acid and the hydroxyl group of the ribose sugar in the tRNA molecule.

Option b

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The specific heat of the glass is 1.58 J/(g°C). The amount of energy needed to raise the temperature of one unit of mass of a substance by one degree Celsius is known as a substance's specific heat.

To calculate the specific heat of the glass, use the formula:

Q = mcΔT

Where,

Q =  amount of energy transferred to the glass,

m = mass of the glass,

c = specific heat of the glass, and

ΔT = change in temperature of the glass.

The given information is:

m = 385 g

Q = 7032 J

ΔT = 24 °C – 12 °C = 12 °C

Put these values into the formula, we get:

7032 J = (385 g) × c × (12 °C)

To find  specific heat, we get:

c = 7032 J / (385 g × 12 °C)

The specific heat of the glass is 1.58 J/(g°C).

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Answer:

1) endothermic reaction - melting of ice to water

2) exothermic reactions - burning of candles

Explanation:

Endothermic reaction:

endothermic reactions are chemical reactions that absorb heat from the environment.

In this case, when ice is melting to turn into water it absorbs heat from its surroundings and melts.

Exothermic reaction:

exothermic reactions are chemical reactions that release heat as a form of energy when a reaction takes place.

In the case of burning a candle, the heat is released into the environment.

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Answer:

tetrahedral

Explanation:

it sounds like a tetrahedral shape, which is when there are four bonds and no lone pairs around the central atom in the molecule.

To make 1 liter of a 10% NaCl solution from a solid stock, you will require the following materials and containers.MaterialsSolid NaClDistilled water1-Liter volumetric flask250-mL volumetric flask 2-beakersProcedureTo prepare 1 liter of a 10% NaCl solution, the following procedure should be followed:Measure out 100g of NaCl using a balance.

Measure the weight of an empty 250-mL volumetric flask.Add the NaCl to a 250-mL beaker and add a small amount of distilled water to it to dissolve the NaCl.Carefully pour the dissolved NaCl solution into the 250-mL volumetric flask. Add distilled water to the mark on the flask to make up the volume. Stopper the flask and invert it several times to mix the solution.Measure the weight of the 1-Liter volumetric flask.Add the 250-mL volumetric flask solution to a 1-Liter volumetric flask.Add distilled water to the mark on the flask to make up the volume.

Stopper the flask and invert it several times to mix the solution.The final volume of the solution will be 1 liter of a 10% NaCl solution.PrecautionsEnsure the NaCl has completely dissolved before adding more water to avoid making a less concentrated solution.Measure the weight of the volumetric flask before and after adding the solution to calculate the volume of solution that was added.Use distilled water to prepare the solution.

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Answer:

‍♀️?sorryyyyyyyyyyyyy

Answer: C

Explanation:

Increasing the temperature increases the rate of dissolving.

The unknown product in the given chemical equation is potassium chloride (KCl).

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and potassium sulfite (\(K_2SO_3\)) is as follows,

\(\[2\text{HCl}(aq) + \text{K}_2\text{SO}_3(aq) \rightarrow \text{H}_2\text{O}(l) + 2\text{KCl}(aq)\]\)

In this reaction, hydrochloric acid (HCl) reacts with potassium sulfite             (\(K_2SO_3\)) to form water  and potassium chloride (KCl). The coefficient 2 in front of HCl indicates that two moles of hydrochloric acid react with one mole of potassium sulfite. The reaction can be understood as follows: the HCl donates a hydrogen ion (H+) to the sulfite ion , forming water and chloride ions (Cl-). At the same time, potassium ions (K+) from the \(K_2SO_3\) dissociate and combine with chloride ions to form potassium chloride (KCl). Overall, the reaction between HCl and \(K_2SO_3\) results in the formation of water and potassium chloride as the unknown product.

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Answer:

A is your answer

It is important to note that the addition of NaF to the \(Ca(OH)_2\) solution will not change the concentration of the Ca ions in the solution. This is because the reaction only involves the \(Ca(OH)_2\) and NaF, and does not involve the Ca ions.  

When a substance is added to a solution, it can react with the ions present in the solution to form new compounds. This can lead to a change in the concentration of the ions in the solution, as well as a change in the chemical equilibrium of the reaction.

In this case, if NaF is added to the beaker containing the \(Ca(OH)_2\) solution, it can react with the \(Ca(OH)_2\) to form \(CaF_2, H_2O\). The balanced equation for this reaction is:

\(Ca(OH)_2\) + NaF → \(CaF_2 + H_2O\)

The concentration of the ions in the solution will depend on the initial concentration of the ions and the amount of the substance added. If the amount of NaF added is small compared to the initial concentration of  \(Ca(OH)_2\) , the reaction will proceed to equilibrium, and the concentration of the ions in the solution will remain relatively constant.

However, if the amount of NaF added is large compared to the initial concentration of  \(Ca(OH)_2\), the reaction will proceed rapidly to completion, and the concentration of the ions in the solution will change significantly. The reaction will reach equilibrium at a new concentration of the ions that is different from the initial concentration.

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The mass of the hexane sample is 0.580 g. The mass of the bomb calorimeter is 1.900 kg, and its specific heat is 3.21 J/g·K. The change in temperature is 4.542 K. So, heat produced during the combustion of hexane is 11195.1576 J.


To calculate the amount of heat produced during the combustion of hexane, we can use the formula q = m × C × ΔT.

First, we need to determine the mass of the hexane sample, which is given as 0.580 g.

Next, we need to find the mass of the bomb calorimeter, which is given as 1.900 kg.

Note that we need to convert the mass to grams by multiplying it by 1000, so the mass is 1900 g.

The specific heat of the bomb calorimeter is given as 3.21 J/g·K.

Finally, we have the change in temperature, which is given as 4.542 K.

Now, we can substitute these values into the formula: q = (0.580 g + 1900 g) × 3.21 J/g·K × 4.542 K.

Simplifying the equation, we get:
q = 2467.8 J/g·K × 4.542 K

Calculating the product:
q = 11195.1576 J

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Polyatomic ion is OOH

Polyatomic ion are ion which consist of more than one atom and atom in a polyatomic ion are usually covalently bonded to one another and therefore stay together as a single or charged unit and here OOH there are two oxygen atom and one hydrogen atom that's it is polyatomic ion

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Answer:

+ 3

Ex planation:

Al3+ indicates an ion of aluminum having a charge of + 3. I.e., since an aluminum atom normally has 13 protons and 13 electrons, this ion has 10 electrons (-10 charge) and 13 protons (+ 13 charge) giving it a charge of + 3 (-10 + 13 = +3).

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0.0225 ml of a 0.900% (m/v) normal saline solution can be prepared from 2.50 g of sodium chloride, nacl . note that mass is not technically the same as weight, but the abbreviation % (w/v) is often used interchangeably with % (m/v).

C = m/V

0.009 = m/V

0.009 = 2.5/V

V = 2.5/0.009 = 0.0225 ml

To help prevent heat cramps brought on by excessive sweating, sodium chloride is used as an electrolyte replenisher. The normal isotonic solution of sodium chloride can also be made using this medication. This medication is accessible over-the-counter.

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