Do charges exit a circuit with less energy than they had when they entered the circuit

Answer:

125 joules.

Explanation:

The work done on an object to give it a certain velocity can be calculated using the formula:

W = (1/2)mv²

where W is the work done, m is the mass of the object, and v is its final velocity.

Substituting the given values, we get:

W = (1/2)(10.0 kg)(5.00 m/s)²

W = (1/2)(10.0 kg)(25.0 m²/s²)

W = 125 J

Therefore, the work done on the 10.0-kilogram mass to give it a speed of 5.00 meters per second is 125 joules.

Answer:

I HOPE THIS IS CORRECT

Explanation:

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60oC

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60oC,Q=msΔT

S= specific heat =4200J/kgoC

              pt=msΔT

   2000×t=200×4200×60

      t=25200  

or   t=25.2×103sec.

The quantity of heat generated is 720,000 Joules or 720 kiloJoules.

Given the following data:

To find the quantity of heat generated when the electrical coil is used:

Note: the quantity of heat generated is energy.

First of all, we would convert the time in hour to seconds.

Conversion:

1 hour = 3600 seconds

Mathematically, the energy of a device is given by the formula;

\(Energy = power\) × \(time\)

Substituting the values into the formula, we have;

\(Energy = 200\) × \(3600\)

Energy = 720,000 Joules or 720 kiloJoules.

Therefore, the quantity of heat generated is 720,000 Joules or 720 kiloJoules.

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Answer:

O is an element and H2O2 is a compound.

Explanation:

O is a single element while H2O2 has 2 elements, which makes it a compound.

Answer:

We can use the kinematic equations to solve this problem.

Let a be the acceleration and d be the distance traveled at maximum speed.

First, we can use the equation:

d = vt + (1/2)at^2

where v is the maximum speed, t is the time traveled at maximum speed, and a is the acceleration.

We know that the bus takes 21 seconds to travel 270 meters, so the time traveled at maximum speed is:

21 - 2a = t

We also know that the acceleration is twice as great as the deceleration, so we can write:

a = 2d

Then, we can substitute these expressions into the first equation:

d = (20)(21 - 2a) + (1/2)(2d)(21 - 2a)^2

Simplifying and solving for d, we get:

d = 210 - 5.25a + 0.25a^2

To find the acceleration, we can use the fact that the maximum speed is reached at the midpoint of the trip, so the distance traveled at maximum speed is half the total distance:

d = 1/2(270)

Solving for d, we get:

d = 135

Substituting this value into the equation for d, we get:

135 = 210 - 5.25a + 0.25a^2

Simplifying and solving for a, we get:

a = 8 m/s^2

Finally, we can use the equation:

d = vt

to find the distance traveled at maximum speed:

d = (20)(21 - 2a)

Substituting the value of a, we get:

d ≈ 188.4 m

Therefore, the acceleration of the bus is 8 m/s^2 and the distance traveled at maximum speed is approximately 188.4 meters.

A natural force of attraction exerted by the earth upon objects, that pulls objects towards earth's center is called Gravitational force .

Answer:

Explanation:

potential energy = mgh

Given

Mass m = 3.6kg

g = 9.8m/s²

Height = 3m

Substitute

potential energy = 3.6*9.8 * 3

potential energy= 105.84 Joules

Hence the cat's potential energy is 105.84 Joules

Answer:

Role of government in regulating production

Explanation:

The role of government in regulating show , provides the legal and social framework, uphold competition, provides public goods and services.

The community's role in conserving and enhancing common-property resources is well known.

In extra, its role in helping market growth by its power to execute trade agreements among transacting parties belonging to the community network is stressed.

Thus, it provides the legal and social framework, maintains competition, and provides public goods and services.

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Answer:

what's the question? .

Answer:

Explanation:

Relation between energy and momentum is as follows .

E = h c / λ

E / c = h / λ

h /λ = momentum of a photon

momentum of a photon  = E /c

= 11 x 10³ / 3 x 10⁸

= 3.67 x 10⁻⁵

In 4 days no of photon

= 4 x 24 x 60 x 60 = 345600 .

momentum of photon released

3.67 x 10⁻⁵  x 345600 .

= 12.68 kg m/s

This momentum will be imparted to spaceship .

12.68 = mv

12 .68 = 1300 x v

v = .00975 m /s

= 9.75 mm /s

The moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

To calculate the moment M applied to the disc that holds the system in equilibrium, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the counterclockwise moments about the same point.

Let's consider point C as the pivot point. The clockwise moments are produced by the weight of BC and the unknown moment M, while the counterclockwise moments are produced by the weight of AB.

The weight of BC can be calculated as W_BC = linear density * length = 1 kg/m * 0.3 m = 0.3 kg.

The clockwise moment is given by M_clockwise = W_BC * BC = 0.3 kg * 0.3 m = 0.09 Nm.

Since the system is in equilibrium, the clockwise moments must balance the counterclockwise moments. Therefore, the counterclockwise moment produced by the weight of AB is also 0.09 Nm.

Hence, the moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

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Given :

A kayak on a lake is moving at a constant speed of 4.1 m/s in a direction 41.6° north of west.

To Find :

After 10 min :

(a) how far west the kayak has traveled km.

(b) how far north the kayak has traveled km.

Solution :

a) Time taken in seconds :

\(t=10\times 60 \ s = 600\ s\) .

Distance travelled in 600 s is :

\(D=s\times t\\\\D=4.1\times 600\ m\\\\D=2460\ m\)

Distance in km is :

\(D=\dfrac{2460}{1000}=2.46\ km\)

b) Now , distance from the north is given by :

\(d=D\times sin\ 41.6^o\\\\d=2.46 \times sin\ 41.6^o\\\\d=1.63\ km\)

Hence , this is the required solution .

The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.

To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:

F = m × a

where:

F = force

m = mass

a = acceleration

Given:

m = 68 kg

F = 1650 N

Find the acceleration (a) first. Rearranging the equation:

a = F / m

Substituting the values:

a = 1650 N / 68 kg

a ≈ 24.26 m/s²

Now, use the equation of motion to find the time (t):

v = u + at

where:

v = final velocity (0 m/s as the person comes to a stop)

u = initial velocity (27 m/s)

a = acceleration (24.26 m/s²)

t = time

Rearranging the equation:

t = (v - u) / a

Substituting the values:

t = (0 m/s - 27 m/s) / 24.26 m/s²

t ≈ -27 m/s / 24.26 m/s²

t ≈ -1.11 s

The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.

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Answer: Density = 6071.428571 kg/m³

Explanation: Given that mass m=17 kg

volume displaced v=2.8L

We know that

density = mass/volume

Here density=17kg/2.8L

Also 1L=1000m³ Hence

density=17kg/2.8×10⁻³m³

           =6071.428571 kg/m³

Suppose a hockey puck slides down a frictionless ramp with an acceleration of 4.10 m/s2 . The angle that the ramp make with respect to the horizontal will be  24.71°

F net = 0

mg sin(theta ) = mass * acceleration

sin(theta) = a /g

theta =  \(sin^{-1}\) ( a / g)

        =  \(sin^{-1}\) ( 4.10 / 9.8 )

        =  \(sin^{-1}\) ( 0.418 )

        = 24.71°

The angle that the ramp make with respect to the horizontal will be  24.71°

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Answer:

1.76 m

Explanation:

Height from which the object is dropped = 45 m

Time (t) remaining for the ball to land = 0.6 s

Height (h) in the remaining =?

The height to which the object falls in the remaining time can be obtained as follow:

Time (t) remaining for the ball to land = 0.6 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) in the remaining =?

h = ½gt²

h = ½ × 9.8 × 0.6²

h = 4.9 × 0.36

h = 1.76 m

Thus, the distance travelled in the last 0.6 s is 1.76 m

The difference between the manufacturer's claims and your findings is, the manufacturer is concerned about amount of fat in the meat while you are concerned about calories.

Your findings concluded that only fat can provide calories needed in the body, perhaps other classes of food or nutrients in the meat can provide calories as well.

In the manufacturer's claim there are about 3% fat in the lunch meat and doesn't necessary mean that all the calories needed is the 3% fat.

Thus, there are lots of difference between your findings and the manufacturer's claim. The manufacturer is concerned about amount of fat in the lunch meat while you are concerned about calories in the meat.

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Intuition involves relying on assumptions and beliefs about the world, whereas empirical observation involves making direct observations of the world.

Intuition refers to the process of using past experiences, beliefs, and assumptions to make quick, unconscious judgments or decisions about the world.

It is often associated with feelings or gut reactions and can be influenced by factors such as emotions, biases, and prior knowledge.

Empirical observation, on the other hand, refers to the process of gathering information about the world through direct sensory experience, such as seeing, hearing, touching, and measuring.

Empirical observations are the foundation of scientific inquiry as they provide the raw data that can be used to test and refine hypotheses and theories.

Unlike intuition, empirical observations are objective and uninfluenced by personal biases or assumptions.

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Answer: a

Explanation:

Answer: The resultant displacement vector is 5.6km

The resultant displacement vector of the hiker is equal to 5.6 km.

The distance can be described as the total length traveled by an object and is a scalar quantity with only magnitude. The distance should be always positive.

The displacement of an object can be described as the shortest length between two points. The displacement can be considered as a vector quantity with direction & magnitude. The displacement can be +ve, -ve, or zero and can be changed with time.

Given, a hiker moves 5.0 km along AB in the North and then 2.5 km west along BC.

The length (AC) is the resultant displacement that can be calculated by using Pythagoras' theorem:

AC² = AB² + BC²

AC² = (5.0)² + (2.5)²

AC² = 25 + 6.25

AC = 5.59 km ≈ 5.6 km

Therefore, the displacement of the hiker is 5.6 Km.

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Answer:

The height at point of release is 10.20 m

Explanation:

Given:

Spring constant : K= 5 x 10 to the 3rd power n/m

compression x = 0.10 m

Mass of block m= 0.250 kg

Here spring potential energy converted into potential energy,

mgh = 1/2 kx to the 2 power

For finding at what height it rise,

0.250 x 9.8 x h = 1/2 x 5 x 10 to the 3 power x (0.10)to the 2 power) - ( g= 9.8 m/8 to the 2 power

h= 10.20

Therefore, the height at point of release is 10.20 m

The width of the outer core is 1,350 miles.

Earth's outer core is a fluid layer about 2,200 km thick, composed of mostly iron and nickel that lies above Earth's solid inner core and below its mantle.

The outer core, about 2,200 kilometers (1,367 miles) thick, is mostly composed of liquid iron and nickel.

The width of the outer core is calculated as follows;

Δx = (3991 mi ) - (32 mi + 1821 mi + 788 mi)

Δx = 1,350 mi

Thus, from the data given, the width of the outer core is 1,350 miles.

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Here is a free body diagram of the block on the incline:

         /|

        / |

       /  |

      /   |

     /    |

    /     |

   /θ    |

  /       |

 /         |

/           |

/____________|

        N

        |

        |

        |

        |<----f_kinetic

        |_______  <----f_gravity

Static force:

f_static is less than the maximum force of static friction, the block will not slide and will remain at rest.

In this diagram, θ represents the angle of the incline, N represents the normal force exerted on the block by the incline, f_gravity represents the force of gravity pulling the block down the incline, and f_kinetic represents the force of kinetic friction opposing the motion of the block. Since the block is at rest, the net force must be zero.

We can calculate the force of gravity using the formula:

f_gravity = mgcosθ

where m is the mass of the block, g is the acceleration due to gravity (9.81 m/s^2), and θ is the angle of the incline. Substituting the given values, we get:

f_gravity = (5.0 kg)*(9.81 m/s²)*cos(30°) = 42.7 N

The normal force, N, is perpendicular to the incline and equal in magnitude to the component of the force of gravity perpendicular to the incline. We can calculate it using the formula:

N = f_gravity*sinθ

Substituting the given values, we get:

N = (5.0 kg)*(9.81 m/s²)*sin(30°) = 24.5 N

The force of static friction, f_static, can be found using the formula:

f_static = μ_static*N

where μ_static is the coefficient of static friction. Substituting the given value, we get:

f_static = (0.5)*(24.5 N) = 12.3 N

Since the block is at rest, the force of static friction must be equal in magnitude to the component of the force of gravity parallel to the incline:

f_static = f_gravitysinθ = (5.0 kg)(9.81 m/s²)*sin(30°) = 24.5 N

Since f_static is less than the maximum force of static friction, the block will not slide and will remain at rest.

We don't need to determine the force of kinetic friction since the block is not sliding.

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Moving a load without dragging it on the ground.  This cuts down on friction, so you can do the move with less energy.

Answer:

\(\rho=2.28\times 10^5\ C/m^3\)

Explanation:

Given that,

Charge, Q = 2.1 C

The radius of sphere, r = 1.3 cm = 0.013 m

We need to find the charge per unit volume for this situation. It can be calculated a follows:

\(\rho=\dfrac{Q}{\dfrac{4}{3}\pi r^3}\\\\\rho=\dfrac{2.1}{\dfrac{4}{3}\pi \times (0.013)^3}\\\\\rho=2.28\times 10^5\ C/m^3\)

So, the charge per unit volume is \(2.28\times 10^5\ C/m^3\).

Answer:

Tension of the wire(T) = 169 N

Explanation:

Given:

f = 65Hz

Length of the piano wire (L) = 2 m

Mass density = 5.0 g/m² = 0.005 kg/m²

Find:

Tension of the wire(T)

Computation:

f = v / λ

65 = v / 2L

65 = v /(2)(2)

v = 260 m/s

T = v² (m/l)

T = (260)²(0.005/2)

T = 169 N

Tension of the wire(T) = 169 N

Frequency=  30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.

(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:

frequency = wave speed / wavelength

Substituting the given values, we get:

frequency = 12 m/s / 0.4 m = 30 Hz

Therefore, the frequency of the wave is 30 Hz.

To find the period (T), we can use the equation:

period = 1 / frequency

Substituting the frequency value we just calculated, we get:

period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)

Therefore, the period of the wave is approximately 0.0333 s.

To find the wave number (k), we can use the equation:

wave number = 2π / wavelength

Substituting the given values, we get:

wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)

Therefore, the wave number of the wave is approximately 15.708 rad/m.

(b) The wave function for a transverse wave on a string is given by:

y(x, t) = A sin(kx - ωt + φ)

where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.

We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:

0 = A sin(0 + φ)

∂y/∂t = -Aω cos(0 + φ)

Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:

φ = nπ, where n is an integer

Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:

n = 0 or 2

Therefore, the possible values of φ are 0 or 2π.

Substituting the values of A, k, ω, and φ, we get:

y(x, t) = 0.05 sin(15.708x - 94.248t)

Therefore, the wave function describing the wave is:

y(x, t) = 0.05 sin(15.708x - 94.248t)

(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:

y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))

y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)

Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.

(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,

From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.

We can use the wave function we found in part (b) and set y(0.25, t) = 0:

0 = 0.05 sin(15.708(0.25) - 94.248t)

Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:

15.708(0.25) - 94.248t = nπ

Solving for t, we get:

t = (15.708(0.25) - nπ) / 94.248

To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:

t = (15.708(0.25) - 2π) / 94.248

t ≈ 0.297 s (rounded to three decimal places)

Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.

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Answer:

Table C:

Fan Speed Observations of Position vs. Time Graphs

Low:

The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.

Medium:

The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.

High:

The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.

Explanation:

hope it helps

Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.

Materials:

Smooth, inclined plane

Cart or tiny wheeled object

Stopwatches and timers

Measuring tape or meterstick

Procedure:

Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.

Place the cart or small wheeled object at the bottom of the inclined plane.

Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.

Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.

As soon as the cart is freed and begins to move, start the stopwatch or timer.

Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.

Determine the time intervals (Δt) between each position for velocity analysis

Data:

Position (m) Time (s) Time Interval (Δt) (s)

0.0                   0.00           -

0.5                   0.50        0.50

1.0                   0.75        0.25

1.5                    1.10              0.35

2.0                    1.50        0.40

Analysis:

Calculate the average velocity between each position by dividing the position change by the time interval (x/t).

Create a graph that plots average velocity (V_avg) versus time (t).

Results:

A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.

Conclusion:

The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.

Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

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A gymnast of mass 52.0 kg is jumping on a trampoline.  the trampoline stretches 0.67 m when the gymnast stands on it at rest.

Generally, To find the stretch of the trampoline when the gymnast is standing on it at rest, we need to use Hooke's law, which states that the force required to stretch (or compress) a spring is directly proportional to the distance that it is stretched (or compressed).

Mathematically, it is represented as

F = kx,

where

F is the force applied,

x is the distance stretched and k is the spring constant.

As the trampoline stretches by 67 cm when the gymnast lands, we can use the equation

F = kx to find the spring constant k. We know that the force applied is the weight of the gymnast, which is

52 kg x 9.8 m/s^2 = 508 N.

k = F/x '

= 508 N / 0.67 m

= 757 N/m

Now that we know the spring constant, we can use it to find the stretch of the trampoline when the gymnast is standing on it at rest. We can use the equation

F = kx where F = weight of the gymnast and x = stretch of the trampoline when she is standing on it at rest.

x = F/k

= 508 N / 757 N/m

= 0.67 m

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Answer:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

Explanation: