Do larger bodies orbit smaller bodies or do smaller bodies orbit larger bodies? Provide some examples to support your answer.

The electric force acting on a 7.80 nc charge that is located 1.69 m from a 4.54 nc point charge is: 1.115*10^-7 N

To solve this exercise the electric force formula and the procedure we will use is:

F = (k * q1 * q2)/r²

Where:

Information about the problem:

By converting the the values of the charges (q1) and (q2) from (nC) to (C) and we have that:

q1= 7.80 nC * 1 C/ 1*10^ 9 nC

q1= 7.8*10^ -9 C

q2= 4.54 nC * 1 C/ 1*10^ 9 nC

q2= 4.54 *10^ -9 C

We apply the electric force formula we have:

F = (k * q1 * q2)/r²

F = [(9 *10^9 N*m²/C² * (7.8*10^ -9 C) * (4.54 *10^ -9 C)]/ (1.69 m)²

F = 3.187*10^-7 N*m² /2.8561 m²

F = 1.115*10^-7 N

In physics the electric force is the force that attracts or repels two charges (q) separated at a distance called (r), this is expressed in the international system of units in Newton.

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Answer:

I'm not to sure but I think the answer is 1.5m/s^2

Explanation:

Acceleration = Change in Velocity over Time.

So we get 15 - 0.0 divided by 10.0 which = 1.5m/s^2

But again I'm no expert I'm learning this stuff just like you guys.

The interpretation of coefficient estimates from WLS depends on the weights that are assigned to the observations, and the rationale behind those weights.

Coefficient estimates from WLS (Weighted Least Squares) are interpreted in a similar way to those from OLS (Ordinary Least Squares) regression. The main difference is that WLS gives different weights to different observations, while OLS gives equal weights to all observations.

In WLS, the coefficient estimates represent the change in the dependent variable for a one-unit change in the independent variable, while holding all other variables constant. However, the interpretation of the coefficients depends on the weights that are assigned to the observations.

For example, if the weights are based on the reliability of the observations, then the coefficient estimates represent the change in the dependent variable for a one-unit change in the independent variable, for the most reliable observations. If the weights are based on the importance of the observations, then the coefficient estimates represent the change in the dependent variable for a one-unit change in the independent variable, for the most important observations.

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Answer:

Friction

Explanation:

edge 2022

This method of transferring charge by rubbing objects is charging by friction.

Charging is defined as the phenomenon of transferring charge between two objects by supplying electrons between the objects.

Here,

The student done an experiment of rubbing a glass rod with a piece of silk and as a result, static charge is produced.

This is because, when the two objects are rubbed against each other, there occurs a friction between them. During this process, the glass rod that has free electrons that are freely bound to it will transfer its electrons to the piece of silk cloth. As a result, the glass rod will lose electrons and will have an electron deficiency, that means the glass rod becomes positively charged. At the same time, the silk cloth will acquire the electrons and the piece of silk becomes negatively charged.

This phenomenon of transferring charge between two objects when they are rubbed against each other is called charging by friction.

Hence,

This method of transferring charge by rubbing objects is charging by friction.

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By measuring the recession velocities and therefore the distant galaxies and noticing that these parameters are intimately related to time. Option A.

Find the oldest stars, measure the expansion rate of the universe, and extrapolate back to the large Bang. a bit like a detective can trace the origin of a sphere through a hole in the wall.

Current measurements put the world at about 4.54 billion years old and therefore the universe at About 13.8 billion years. Scientists measure the dimensions of the universe in a myriad of different ways. they will measure ripples from the early universe known as baryonic acoustic oscillations that fill the cosmic microwave background. you'll also use a standard candle, like a Type 1A supernova, to live within distance.

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Answer:8.1g

Explanation:

Explanation:

you can find by using. volume = mass/ density of aluminium.

Answer: 125 m/s

Multiply 15 m/s by 5.0 minutes, because this will give you the product.

15 x 5.0 = 125.

Add the m/s sign to the 125. 125 m/s.

Answer = 125 m/s. Hope this helps!

Answer:

if we drop it and not throw it then

after 0.75 how fast the book is falling is given by its velocity as

v= at

= 9.8 × 0.75

=7.35 m/s

Answer:

down below

Explanation:

I assume you're asking about it's orbit around the sun. I believe the Earth's orbit around the sun would be shorter. If the Earth sped up, one can assume that means the days are shorter and the rate at which the Earth orbits the sun would also speed up.

This sounds like an open ended question, so I don't think there can be a wrong answer.

Hope this helps! :)

The power in watts is the energy in Joules used per second. This is:

P [W] = E[J] / t[s]

Solving for Energy:

E = P*t

We must convert the time to seconds knowing that 1 min = 60 s:

t = 6 min × 60 = 360 s

Finally:

E = P*t

E = 133 W * 360 s

E = 47880 J

Answer:

First, to be a barrier keeping the constituents of the cell in and unwanted substances out and, second, to be a gate allowing transport into the cell of essential nutrients and movement from the cell of waste products.

Explanation:

It has two functions

Answer:

Definition: poem

Explanation:

Answer:

B. Extrusive igneous

Explanation:

Its B

Answer:

The Answer Is D

Explanation:

I did it, The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Answer:

The scale diagram is in the image attached

Explanation:

The scale diagram is in the image attached.

The North direction is upwards in the diagram, the West is to the left, the East is to the right and the South is downwards.

First movement: 550m north -> 5.5 cm upwards

Second movement: 350m west -> 3.5 cm to the left

Third movement: 250m south -> 2.5 cm downwards

Fourth movement: 450m east -> 4.5 cm to the right

Fifth movement: 150m south -> 1.5 cm downwards

Hope it helps!

Answer:

The index of refraction can be calculated using Snell's law:

n1sin(theta1) = n2sin(theta2)

where n1 and theta1 are the index of refraction and angle of incidence in the first medium (glass), and n2 and theta2 are the index of refraction and angle of refraction in the second medium (unknown material).

Plugging in the given values:

1.76sin(25) = n2sin(35)

Solving for n2:

n2 = (1.76*sin(25))/sin(35)

n2 ≈ 1.29

Therefore, the index of refraction for the unknown material is approximately 1.29.

Answer:

Explanation:

Greetings!!!

Wor(W)= 2000j

Distance (d)= 4m

force(F)=?

Firstly, recall the Work-Force equation.

Substitute known variables into the equation.

Solve for Force.

If you have any questions or unclear ideas tag on comments

Hope it helps!!!

Answer:

I think the answer is D because it needs to be on two hours from 1.15pm

The specific gravity of water at exactly 4°C is 1 and the density of water depends on the temperature of water.

A substance's specific gravity is determined by dividing its material's density by that of a standard liquid. The reference liquid is generally water. As a result, the specific gravity can also be explained as the relation of the material's density to water's density.

A common tool for determining a liquid's specific gravity is the hydrometer. A hydrometer is a floating bulb with measurement markers affixed to a stalk. The relative density of the two liquids can be calculated by measuring how much of the stalk is immersed in the target liquid in comparison to a reference liquid.

Another tool for determining a liquid's density while accounting for volume is a pycnometer. The container is made of glass, and the tight-fitting lid lets any extra liquid out. The relative density of the two fluids can be determined by comparing the overall weight of the pycnometer when it is full to the weight when it is full of a known fluid.

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The merry-go-round takes approximately 29.41 seconds to complete 2.00 rotations.

Given data:

Acceleration (α) = 0.135 rad/\(s^2\)

Number of rotations (θ) = 2.00

To find the time taken (t) for 2.00 rotations, we need to use the formula:

θ = 0.5 * α * \(t^2\)

Rearranging the formula, we get:

\(t^2\) = (2 * θ) / α

Plugging in the given values, we have:

\(t^2\) = (2 * 2.00) / 0.135

\(t^2\) = 29.63

Taking the square root of both sides, we find:

t ≈ √29.63

t ≈ 5.439

Therefore, the time taken for the merry-go-round to complete 2.00 rotations is approximately 5.439 seconds.

Note: It's important to round the final answer to an appropriate number of significant figures, considering the given data. In this case, we have used four significant figures in the final answer.

However, if we want to adhere to the given significant figures in the acceleration (0.135 rad/\(s^2\)), the answer should be rounded to three significant figures. In that case, the final answer would be approximately 5.44 seconds.

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Answer:

D. Malleable

Explanation:

Gold is metallic, with a yellow colour when in a mass, but when finely divided it may be black, ruby, or purple. It is the most malleable and ductile metal; 1 ounce (28 g) of gold can be beaten out to 300 square feet. It is a soft metal and is usually alloyed to give it more strength.

Answer:

v_avg = 2.9 cm/s

Explanation:

The average velocity of the object is the sum of the distance of all its trajectories divided the time:

x_all is the total distance traveled by the object. In this case you have that the object traveled in the first trajectory 165cm-15cm = 150cm, and in the second one, 165cm - 25cm = 140cm

Then, x_all = 150cm + 140cm = 290cm

The average velocity is, for t = 100s

hence, the average velocity of the object in the total trajectory traveled is 2.9 cm/s

Answer:

They must have the same units when expressed in base units

Explanation:

Too add any two values together you need them to be in the same units. but You can convert diffrent units of the same messure to each other in order to achive this; ie you can add meeters to feet if you multiply the meters by 3.28 but you can't add mass and length together.

With the concept of  pattern we find that the answer for the sum of physical magnitudes is:

They must have the same units when expressed in base units.

To add two phsical quantities to meet some requirements:

* Must be of the same type

* Must be in the same base units

That they have the same type implies that we cannot add length with time or masses, length or speeds must be added with their pairs

The use of the same base unit guarantees that we use the same pattern, or that we must reduce the magnitudes to the same pattern, for example: we cannot add meters with inches directly, we must reduce inches to meters, which is the unit of the international system.

International System  it guarantees the existence of common and reproducible patterns for all physical quantities.

Add two phsical quantities, the correct answer is:

must have the same units in base units

In conclusion, the measurement system and units allows adding magnitude of the same type with the same units of a base unit or standard.

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Answer:

Your mass is the same no matter where you go in the universe; your weight, on the other hand, changes from place to place. Mass is measured in kilograms; even though we usually talk about weight in kilograms, strictly speaking it should be measured in newtons, the units of force

In summary, mass is a measure of how much matter an object contains, and weight is a measure of the force of gravity acting on the object. ... The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects.

Explanation:

Answer:

1. A: acceleration

2. D: torsion

3.  C: gravitational force or possibly B: frictional force

4. B: noncontact force

5. B: distance: displacement

6. C: speed

Answer:

Q = 0.015 Coulombs

Explanation:

Given the following data;

Resistance = 6 Ω

Current = 3 mA = 0.003 A

Time, t = 5 seconds

To find the quantity of charge passing through the resistor;

Mathematically, quantity of charge is given by the formula;

Quantity of charge, Q = current * time

Q = 0.003 * 5

Q = 0.015 Coulombs

Answer:

450N

Explanation:

Given parameters:

Mass of object  = 450kg

Initial velocity  = 15m/s

Final velocity  = 75m/s

Time  = 1min  = 60s

Unknown:

Force applied  = ?

Solution:

To solve this problem, from Newton's second law of motion, we know that;

  Force  = mass x acceleration

  Acceleration  = \(\frac{v - u }{t}\)

 v is the final velocity

 u is the initial velocity

 t is the time taken

Now;

    Force  = mass x  \(\frac{v - u }{t}\)

   Force  = 450 x \(\frac{75 - 15}{60}\)  = 450N

Answer:

Cassiopeia was one of the 48 constellations listed by the 2nd-century Greek astronomer Ptolemy, and it remains one of the 88 modern constellations today. It is easily recognizable due to its distinctive 'W' shape, formed by five bright stars. Visible at latitudes between +90° and −20°.

Answer:

Cassiopeia is a fascinating constellation with a rich history and cultural significance, as well as an important object of study for astronomers and scientists

Explanation:

Cassiopeia is a constellation located in the northern hemisphere of the sky. It is one of the 88 constellations officially recognized by the International Astronomical Union (IAU). The constellation is named after Queen Cassiopeia of Greek mythology, who was the wife of King Cepheus and mother of Princess Andromeda.

The constellation is easily recognizable for its distinctive shape, which looks like a "W" or "M" depending on its orientation in the sky. This shape is formed by five bright stars, which represent the Queen's throne and her legs. The brightest star in the constellation is known as Gamma Cassiopeiae, which is a massive blue-white star located about 550 light-years away from Earth.

Cassiopeia is visible in the sky all year round from most locations in the northern hemisphere, and it can be easily found by looking for its distinctive shape. It is also part of the Milky Way galaxy, which makes it a popular target for amateur astronomers who want to observe the stars and galaxies in our own galaxy.

Overall, Cassiopeia is a fascinating constellation with a rich history and cultural significance, as well as an important object of study for astronomers and scientists.