do logarithmic functions have horizontal asymptotes?

Answer:

x = 1

Step-by-step explanation:

Both equations can be set equal to each other since they are both equal to y:

\(x-10=-4x-5\\5x-10=-5\\5x=5\\x=1\)

equate both equations !

x - 10 = -4x - 5

5x - 10 = -5

5x = 5

x = 1

therefore x = 1

Answer:

there is 8 quadrilateral shapes

Answer:

No solutions.

Step-by-step explanation:

In this question, we have to solve for x in the inequality.

Solve:

x + 3 > x + 7

Subtract "x" from both sides to move the x over.

3 > 7

However, we don't have any x values after we cancelled the x, therefore meaning that the inequality has no solutions.

Answer:

y = 2x + 1

Step-by-step explanation:

y (the sandwich) is TWICE the price of soup (2x) plus one (+1)

good luck

Home plate to second base is located at a distance of 90√2 feet.

A square is a rectangle in which each side is the same length. The distance separating the square's opposing vertices is known as the diagonal. The Pythagoras Theorem can be used to compute the diagonals:

Diagonal² = Side² + Side²

Diagonal² = 2 Side²

Diagonal = √2 Side

The answer to the question is that it is 90 feet from home plate to first base.

This is the length of the side that makes up the baseball diamond's square shape. The diagonal of the square is the distance from home plate to second base.

Diagonal = √2 Side

Diagonal = 90√2

Hence, home plate to second base is located at a distance of 90√2 feet.

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The question is incomplete. The complete question will be -

"A baseball diamond is square. The distance from home plate to first base is 90 feet. In feet, what is the distance from home plate to second base?"

Check the picture below.

Answer: \(\dfrac{19}{40}\)

Step-by-step explanation:

Given: Fraction of goal raised on first day = \(\dfrac{1}{8}\)

Fraction of goal raised after second day  = \(\dfrac35\)

Now , Fraction of goal raised on second day = Fraction of goal raised after second day  - Fraction of goal raised on first day

\(=\dfrac35-\dfrac18\\\\=\dfrac{24-5}{40}\\\\=\dfrac{19}{40}\)

Required fraction = \(\dfrac{19}{40}\)

The graph of the system of inequalities is on the image at the end, we can see that one solution is 10 tables and 5 chairs.

We know that an online furniture store sells chairs for $100 each and tables for $350 each.

The store can ship at most 18 pieces, and the must sell no less than $3200

Then if we define:

c = number of chairs.

t = number of tables

Then the system of inequality is:

c + t  ≤ 18

c*100 + t*350  ≥ 3200

The graph of that system of inequalities can be seen below, the solutions are in the doble shaded region, then for example one solution is:

c = 5

t = 10

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Answer:

so it provides a way that organizes information of a problem in methodical way

hope this helps give brainllest please!

Step-by-step explanation:

Answer:

Its about 140 miles

Step-by-step explanation:

it takes slight over 2 hours to get from point a to b

Answer:

0.3??? sorry I'm just as confused

The equation of line is y-5 = 0 or y = 5.

The points = (2, 5) and (0, 5).

To Find: Equation of line.

Solution:

Slope = .\($=\frac{y_2-y_1}{x_2-x_1}$\)

= \($=\frac{5-5}{0-2}$\)

= 0

Equation of line =\($=y-y_1=\operatorname{slope}\left(x-x_1\right)$\)

Take any point for the equation of line.

Taking (2, 5) for equation of line.

y - 5 = 0(x - 2)

y-5=0

y = 5

Hence, the equation of line is y-5 = 0 or y = 5.

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Answer:

Step-by-step explanation:

The taller candle is 16 cm and loses 2.5 cm every hour

Equation for the taller candle:

The probability of winning by not changing the door is 25%, and the probability of winning by changing the door is 50% in this modified Monty Hall puzzle with four doors.

the Monty Hall puzzle involving four doors.

First, let's establish the initial scenario: there are four doors, and behind one door, there is a prize. You initially choose one door, and the host, who knows what is behind each door, opens a losing door among the remaining three doors.

1. Probability of winning by not changing the door:

Since you've chosen one door, the probability of having selected the winning door initially is 1/4. If you do not change your door, this probability remains the same. So the probability of winning by not changing the door is 1/4 or 25%.

2. Probability of winning by changing the door:

When the host opens a losing door, there are two unopened doors remaining among the three that you did not select. One of these doors has the prize, so the probability of winning by changing your selection is 1/2 or 50%.

In summary, the probability of winning by not changing the door is 25%, and the probability of winning by changing the door is 50% in this modified Monty Hall puzzle with four doors.

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Answer:

The mean of the random variable Y is (17/2) kilowatt hours.

Step-by-step explanation:

To find the expected value of Y, we can use the formula provided in the theorem:

E(Y) = E(51X^2 + 40X)

Using linearity of expectation, we can break this down into two separate expected values:

E(Y) = 51E(X^2) + 40E(X)

The given probability density function is, f(x) = (1/4)x, 0 ≤ x ≤ 2.

The expected value of a continuous random variable is calculated using the formula shown below, where E(x) is the expected value of x, and f(x) is the probability density function of x.

E(x) = ∫xf(x)dx

The expected value of the random variable X can be calculated as follows:

E(X) = ∫0² (1/4)x dx = (1/8) [x²]₀² = 1

E(X²) = ∫0² (1/4)x² dx = (1/12) [x³]₀² = (1/6)

Now we can substitute these values into our original equation:

E(Y) = E(51X² + 40X) = 51E(X²) + 40E(X) = 51(1/6) + 40(1) = (17/2) kilowatt hours.

Therefore, the mean of the random variable Y is (17/2) kilowatt hours.

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The relative error in the measure of the student is 0.0069

It is the quotient between the absolute error and the value that we consider as exact (average). Like the absolute error, it can be positive or negative because it can be produced by excess or defect and it has no units.

Width of a piece of paper = 36 cm

Actual width = 35.75 cm

The relative error is given by:

Relative error = (Measure value - real value)/real value

Relative error = (36 - 35.75)/35.75

Relative error = 0.0069

% Relative error = 0.0069 x 100

% Relative error = 0.69%

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The first system of equations has no solution and the second set of equations has a unique solution.

If we are having two equations as

\(a_{1} x^{2} +b_{1} x+ c_{1} =0\)

and \(a_{2} x^{2} +b_{2} x+ c_{2} =0\)

The condition at which these equations will have infinitely many solutions is

\(\frac{a_{1} }{a_{2} } =\frac{b_{1} }{b_{2} } =\frac{c_{1} }{c_{2} }\)

The condition at which these equations will have infinitely many solutions is

\(\frac{a_{1} }{a_{2} } =\frac{b_{1} }{b_{2} } \neq \frac{c_{1} }{c_{2} }\)

For, the 26th question, we have

4x +8y = -8

4x +8y +8 = 0

x +2y +2 =0 equation(1)

x =-2y +1

x +2y -1 = 0 equation(2)

On comparing these equations with the general form, we have

\(a_{1} = 1, a_{2} =1\\b_{1} = 2, b_{2} = 2\\c_{1} = 2, c_{2} = -1\)

So, \(\frac{a_{1} }{a_{2} } =\frac{b_{1} }{b_{2} } \neq \frac{c_{1} }{c_{2} }\)

Thus, this system of equations has no solution.

Now, For the 27th question, we have

2x - 3y = 6

2x -3y -6 = 0 equation(3)

\(y = \frac{2}{3}x -2 \\\\3y = 2x -6\\\\3y -2x +6 = 0\) equation (4)

On comparing these equations with the general form, we have

\(a_{1} = 2, a_{2} =3\\b_{1} = -3, b_{2} = 2\\c_{1} = -6, c_{2} = 6\)

So, \(\frac{a_{1} }{a_{2} } \neq \frac{b_{1} }{b_{2} }\)  

Thus, this system of equations has a unique solution.

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The "rise" direction represents the Recession Velocity, indicating the motion of galaxies away from us, while the "run" direction represents the X axis, representing the independent variable used to measure distance or time in the Hubble Constant equation.

The "rise" direction in the context of the slope of the Hubble Constant represents the Recession Velocity (RV). It signifies the rate at which galaxies are moving away from us in the expanding universe.

On the other hand, the "run" direction represents the X axis. It refers to the distance or time, depending on the specific interpretation, along the X axis used to measure the independent variable in the Hubble Constant equation.

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The solutions to systems of equations are the variable mappings such that all component equations are satisfied—in other words, the locations at which all of these equations intersect. To solve a system is to find all such common solutions or points of intersection.

A group of equations comprising one or more variables is known as a system of equations. The variable mappings that satisfy each component equation, or the points where all of these equations cross, are the solutions of systems of equations.

Calculating the unknown variables while keeping the equations balanced on both sides is the process of solving a system of equations. Finding the value of the variable that makes the condition of all the provided equations true is how we solve an equation system. There are several ways to solve a system of equations, including

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Answer:

D-4

Step-by-step explanation:

It is asking for the slope and is written in slope-intercept form. 4x is your slope and 3 is your y intercept.

Answer:

10

Step-by-step explanation:

14+14+18+18+22=86

6*16=96

96-86=10

Step-by-step explanation:

✧ \( \underline{ \underline{ \large{ \tt{S \: O \: L \: U \: T \: I \: O \: N}}} }: \)

Let the age of a person who entered the room be ' x '.

✧ \( \underline{ \underline{ \large{ \tt{G \: I \: V \: E \: N \: \: D \: A\: T \: A } }}} : \)

n ( number of observation ) = 6

\( \sum\) x = 14 + 14 + 18 + 18 + 22 + x = 86 + x

Mean = 16

☯ \( \boxed{ \large \tt{Mean \: = \frac{ \sum \: x}{n} }}\)

~Plug the values :

⇢ \( \large{ \tt{16 = \frac{86 + x}{6}}} \)

~Apply cross product property :

⇢ \( \large{ \tt{86 + x = 16 \times 6}}\)

⇢ \( \large{ \tt{86 + x = 96}}\)

Move 86 to right hand side and change it's sign

⇢ \( \large{ \tt{x = 96 - 86}}\)

⇢ \( \boxed{ \large{ \tt{x = 10}}}\)

\( \large{ \boxed{ \boxed{ \underline{ \large{ \tt{Our \: Final \: Answer : \underline{10}}}}}}}\)

Hope I helped ! ツ

Have a wonderful day / night ! ♪

⋆ Let me know if you have any questions regarding my answer ⋆

\( \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}\) !! ✎

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The correct answer is option  C. The first example represents reflected-appraisal; the second example represents social comparison.

Given that: When Abe was young, he learned that he could lighten the mood with humor. Others laughed at his jokes, and he began to see himself as the 'life of the party'.
In the first example, Abe's sense of humor is positively reinforced by others laughing at his jokes, leading to an enhanced self-image. This is an example of reflected appraisal, where one's self-concept is shaped by the feedback received from others.

Also given that:Abe sometimes wishes he could be more studious and serious like his peers.
In the second example, Abe is comparing himself to his peers and wishing to be more like them. This is an example of social comparison, where individuals evaluate their own abilities and attributes by comparing themselves to others.
C. The first example represents reflected appraisal; the second example represents social comparison.

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Answer:

APPRECAITE THIS D-

Step-by-step explanation:

Answer:

They are both the same numbers- its 110 and 220.

Step-by-step explanation:

GCF=   2 x 5 x 11 = 110

LCM=   2 x 2 x 5 x 11 = 220

Answer:

(5324/3) π  cm³

Step-by-step explanation:

football is a sphere.

radius = 0.5 X diameter = 0.5 (22) = 11 (cm)

volume  = (4/3) π(r)³

               = (4/3) π (11)³

              = ((4 X 11³)/3) X π

              = (5324/3) π (in cm³)

Answer:

A) One hundred random students

Step-by-step explanation:

Mrs. Byrne mowed 1/4 of her lawn. Her son mowed 2/7 of it.  Mrs. Byrne mowed most of the lawn. The lawn still needs to be mowed is 13/28.

Mrs. Byrne mowed of his lawn = 2/7

Her son mowed of his lawn = 1/4

We firstly equal the denominator of both fraction by taking the LCM of both numbers.

The LCM of 7 and 4 is 28.

So we multiply and divide by 4 in the fraction 2/7 and by 7 in fraction 1/4. Now,

Mrs. Byrne mowed of his lawn = 2/7 × 4/4 = 8/28

Her son mowed of his lawn = 1/4 × 7/7 = 7/28

Now we compare the both fraction 8/28 and 7/28. The 8/28 is greater than 7/28. So we can say that Mrs. Byrne mowed most of his lawn.

The total lawn is 28/28.

So, the remaining lawn for mowed = 28/28 - (8/28 + 7/28)

The remaining lawn for mowed = 28/28 - (8 + 7)/28

The remaining lawn for mowed = 28/28 - 15/28

The remaining lawn for mowed = (28 - 15)/28

The remaining lawn for mowed = 13/28

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The complete question is:

Mrs. Byrne mowed 2/7 of his lawn. Her son mowed 1/4 of it. Who mowed most? How much of the lawn still needs to be mowed?