Does the pH increase, decrease, or remain the same when each of the following is added? (a) sodium hydrogen carbonate (NaHCO3) to a solution of carbonic acid (H2CO3) increases decreases remains the same (b) NaHC2O4 to a solution of H2C2O4 increases decreases remains the same (c) HNO3 to a solution of NaNO3 increases decreases remains the same (d) hydrofluoric acid to a solution of sodium fluoride increases decreases remains the same (e) NaClO4 to a solution of NaOH increases decreases remains the same

Answer: both the different glycosidic linkages of the molecules and the different hydrogen bonding partners of the individual chains.

Explanation:

Glycogen is a polysaccharide of glucose which is a form of energy storage in fungi, bacteria and animals. Glycogen is primarily stored in the liver cells and skeletal muscle.

The difference in interchain stability between the polysaccharides glycogen and cellulose is due to the different glycosidic linkages of the molecules and the different hydrogen bonding partners of the individual chains.

Answer: particle in gas have more energy than the particles in a liquid

Explanation: this is because the amount of energy is directly proportional to how random the system is. gaseous molecules are in a more constant random motion than the liquid molecules

The energy change for the reaction Fe₂O₃ (s) + CO (g) → 2FeO (s) + CO₂ (g) is 1.6 kJ.

To find the energy change for the reaction Fe₂O₃ (s) + CO (g) → 2FeO (s) + CO₂ (g), according to the given information:

Fe₂O₃ (s) + 3CO (g) → 2Fe (s) + 3CO₂ (g) (ΔH = -23.4 kJ)

FeO (s) + CO (g) → Fe (s) + CO₂ (g) (ΔH = -10.9 kJ)

We need to influence these two reactions to get the desired reaction:

Step 1: Multiply reaction second by 2 to get 2FeO (s) + 2CO (g) → 2Fe (s) + 2CO₂ (g) (ΔH = -21.8 kJ)

Step 2: Reverse reaction first to obtain -2Fe (s) - 3CO₂ (g) → Fe₂O₃ (s) + 3CO (g) (ΔH = 23.4 kJ)

Step 3: Add the changed reactions together:

2FeO (s) + 2CO (g) → 2Fe (s) + 2CO₂ (g) (ΔH = -21.8 kJ)

-2Fe (s) - 3CO₂ (g) → Fe₂O₃ (s) + 3CO (g) (ΔH = 23.4 kJ)

FeO (s) - CO₂ (g) → Fe₂O₃ (s) + CO (g) (ΔH = 1.6 kJ)

The energy change for the desired reaction Fe₂O₃ (s) + CO (g) → 2Fe₀ (s) + CO₂ (g) is 1.6 kJ.

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The first ionization energy refers to the energy required to remove the outermost electron from an atom in its gaseous state. It is a measure of the tendency of an element to lose an electron and form a positive ion.

Among the elements listed, oxygen (O) has the highest first ionization energy. Oxygen is located in Group 16 (or Group VIA) of the periodic table. As we move from left to right within a period, the first ionization energy generally increases. This is due to the increasing effective nuclear charge, which results in a stronger attraction between the positively charged nucleus and the negatively charged electron. Oxygen, being the second element in Group 16, has a smaller atomic radius and higher effective nuclear charge compared to the other elements in the group.

Consequently, it requires more energy to remove an electron from an oxygen atom compared to the other elements listed. Therefore, the element with the highest first ionization energy among the options provided is D) O, oxygen.

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Here is the correct order of the transformations of energy in a power plant, from the beginning (top) to the generator (bottom):

Thermal (heat) energy is created by converting nuclear or chemical energy.

Kinetic energy is created from thermal (heat) energy.

Kinetic energy is converted to mechanical energy

Mechanical energy is converted to electrical energy

This is a generalized order and may vary depending on the specific type of power plant.

What is Power Plant?

A power plant is a facility that is designed to generate electricity from various sources of energy, such as fossil fuels (coal, oil, and natural gas), nuclear energy, hydroelectric power, wind power, solar power, and geothermal energy. The main function of a power plant is to convert the energy from its source into electrical energy that can be used to power homes, businesses, and other facilities.

The process of generating electricity in a power plant typically involves several steps, including the production of heat or mechanical energy from the source of energy, the use of turbines to convert this energy into rotational energy, and the use of generators to convert this rotational energy into electrical energy. Power plants may also include various other components, such as cooling systems, transformers, and transmission lines, to ensure the efficient and reliable distribution of electrical power to the end users.

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Answer:

Subjectivity

Explanation:

Took test Forensic Science

The Haldane effect is the ability of deoxygenated hemoglobin (a protein composed of an amino group) to carry more carbon dioxide (CO2) than in the oxygenated state.

Red blood cells include a protein called haemoglobin, which distributes oxygen to your body's organs and tissues while returning carbon dioxide to your lungs. A low red blood cell count indicates a low haemoglobin level, which can be determined by a haemoglobin test (anemia). When you have anaemia, your body doesn't produce enough strong red blood cells to supply enough oxygen to the tissues. You may experience fatigue and weakness if you have anemia, commonly known as low hemoglobin.

a decerase in the affinity of hemoglobin for oxygen caused by the binding of carbon dioxide to hemoglobin is described by the

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The chemical reaction between benzoic acid (C₆H₅COOH) and NaOH can be represented as C₆H₅COOH + NaOH → C₆H₅COONa + H₂O.

This reaction involves the displacement of the hydrogen atom from the carboxylic acid group in benzoic acid by the sodium atom from sodium hydroxide. As a result, sodium benzoate (C₆H₅COONa) and water (H₂O) are formed.

The reaction between benzoic acid and NaOH is classified as an acid-base reaction, where the acidic benzoic acid reacts with the basic NaOH to produce a salt (sodium benzoate) and water.

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Answer:

true

...................

Answer: 66.67

Explanation:

you divide distance/time. so it would be 100/1.5.

When the volume of the cylinder decreases isothermally, meaning the temperature remains constant at -10°C, several changes occur. As the volume decreases, the pressure inside the system increases.

This is due to the constant number of water vapor molecules in the container, which leads to more frequent collisions with the container walls as the available space decreases. The increased collision frequency results in an increase in pressure.

To represent this process in the P-v plane approximately to scale, we can visualize it using the provided figure. The initial state of the system is represented by point A, where the volume is V1 and the pressure is P1.

Moving along the isotherm, as the volume decreases, the pressure increases. This process is illustrated by the curved line AB.

The final state of the system is represented by point B, where the volume is V2 and the pressure is P2. The area under the curve AB on the P-v plane corresponds to the work done by the system during the isothermal process.

This work is performed as the system pushes against the piston, which resists the movement of the water vapor inside the cylinder.

In summary, as the volume of the system decreases isothermally, the pressure increases, and this relationship can be visualized on the P-v plane by tracing the path from point A to point B along the isotherm.

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The mathematical expression for h is v²/(2g) which is based on conservation of energy and the correct option is option B.

The law of conservation of energy states that energy can neither be created nor be destroyed. Although, it may be transformed from one form to another.

Example, when a fruit is falling to the bottom, potential energy is getting converted into kinetic energy.

Conservation of energy implies

KEinitial = PEfinal

mv²/2 = mgh

therefore, h = v²/2g.

Thus, the ideal selection is option B.

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Answer:

216 g of NO

Explanation:

We begin from the reaction:

4NH₃ + 5O₂ →  4NO  + 6H₂O

We determine the limiting reactant with the moles of each reactant:

4 moles of ammonia react to 5 moles of oxygen

Our 7.2 moles of ammonia may react to (7.2 . 5) /4 = 9 moles

It's ok because we have 9.6 moles of oxygen. 0.6 moles still remain.

5 moles of oxygen react to 4 moles of NH₃

Our 9.6 moles of oxygen may react to (9.6 . 4) /5 = 7.68 moles

We only have 7.2 moles of NH₃ and we need 7.68; so there is no enough ammonia and that's our limiting reagent.

Now we determine the moles of product.

4 moles of ammonia can produce 4 moles of NO

Definetely our 7.2 moles, will produce 7.2 moles of oxide.

We convert to mass: 7.2 mol . 30 g/mol = 216 g

Answer:

Counting the number of colonies that arise on a pour plate can calculate the concentration by multiplying the count by the volume spread on the pour plate. Direct counting methods are easy to perform and do not require highly specialized equipment, but are often slower than other methods

Explanation:

I hope it will help you

Answer:

B

Explanation:

The reaction will occur naturally

Answer:

B. A pE x

Explanation:

Trust

The reaction has not yet started, and the time required for 16.8% of the reactant to remain cannot be calculated using the given rate constant.

Given,The rate constant for this first-order reaction is 0.0830 s−1 at 400 ∘C.A⟶products After how many seconds will 16.8% of the reactant remain-The time taken for a first-order reaction to reach a particular percentage of completion can be calculated using the following formula:t = (ln(A/A₀))/kwhere A₀ is the initial concentration of the reactant, A is the concentration of the reactant at a given time, k is the rate constant, and t is the time elapsed since the reaction began.In this question, we are given the rate constant, k = 0.0830 s−1 at 400 ∘C, and we want to find out the time required for 16.8% of the reactant to remain.Let's assume that the initial concentration of the reactant is 100 units (we can assume any value as it does not affect the percentage of completion).Therefore, the concentration of the reactant remaining after 16.8% of completion would be: A = 16.8 units.Substituting these values in the above formula, we get:t = (ln(16.8/100))/0.0830t = (−1.7918)/0.0830t = −21.58 sThis time value is negative, which means that the reaction has not even started yet. Therefore, we need to check the given percentage of completion.

If it is less than 50%, we can assume that the reaction has not yet started. In this case, the percentage of completion is 16.8%, which is less than 50%.

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Atomic radius is defined as the distance from the centre of the nucleus of the atom to its outermost shell.

Atomic radii of elements gradually increases in a group from top to bottom. As we go down a group, the atomic number increases, thus, the number of shells increases. Also, as we move down the group, the valence electrons are present in a higher shell and thus, the distance of valence electrons from the nucleus increases. As a result of this, the force of attraction between the nucleus and the valence electron decreases. Therefore, the atomic radius increases on moving down a group.

Higher principal energy levels consist of orbitals which are larger in size than the orbitals from lower energy levels. The effect of the greater number of principal energy levels outweighs the increase in nuclear charge, and so atomic radius increases down a group.

As we move across a period from left to right, the atomic radii decreases gradually. In a period, there is gradual increases in the nuclear charge from left to right. As the atomic number increases in a period, the electron enters in the same shell. Thus, they are more and more strongly attracted towards the nucleus. As a result of this force of attraction from the nucleus, the atomic radii gradually decreases.

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Answer:

a. 0.0413 moles Zn

b. 0.0500 moles HCl

c. HCl is the limiting reactant

d. 0.0250 moles H₂

e. V = 0.56L

Explanation:

The reaction of Zn(s) with HCl is:

Zn(s) + 2HCl (aq) → ZnCl₂ (aq) + H₂(g)

Where 1 mole of Zn reacts with 2 moles of HCl.

a) To convert mass in grams to moles of a substance you need to use molar mass (Molar mass Zn: 65.38g/mol), thus:

2.70g Zn × (1mol / 65.38g) = 0.0413moles of Zn

b. Now, when you have a solution in molarity (Moles / L), you can know the moles of a volume of solution, thus:

Moles HCl:

50.0mL = 0.0500L × (1.00mol / L) = 0.0500 moles HCl

c. The limiting reactant is founded by using the chemical reaction as follows:

For a complete reaction of 0.0500 moles HCl you need:

0.0500 moles HCl × (1 mole Zn / 2 moles HCl) = 0.0250 moles Zn

As you have 0.0413 moles of Zn, and you need just 0.0250 moles for the complete reaction, Zn is the exces reactant and HCl is the limiting reactant

d.As HCl is limiting reactant and 2 moles of HCl react with 1 mole of H₂, moles of hydrogen formed are:

0.0500 moles HCl × (1 mole H₂ / 2 moles HCl) = 0.0250 moles H₂

e. Using PV = nRT, you can find volume of  gas, thus:

PV = nRT

V = nRT / P

Where P is pressure 1atm at STP, n are moles, R is gas consant 0.08206Latm/molK and T is absolute temperature 273.15K at STP.

V = 0.0250molesₓ0.082atmL/molKₓ273.15K / 1atm

V = 0.56L

The molecule O=C=S is linear and has a Lewis structure analogous to that of CO2. This molecule is polar molecule.

What are polar molecules?

Polar molecules are molecules that have two oppositely charged ends. Polar molecules exist as a result of differences in the electronegativities of the atoms of the elements found in the molecule.

With two electron domains around the central atom .the electron domain & molecular geometries are linear .sinces oxygen is more electronegative than sulphur.

The bond dipole symmetrically distributed around the carbon atom , are not identical and therefore,the bond dipole do not sum to zero.

Therefore, OCS molecule is a polar molecule not a non polar.

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Answer: A

Explanation:

Because we make hypothesis to find an answer to our observation or question. So if the Hypothesis is correct then the then a scientific explanation proves that a hypothesis is true. We also need more data and evidence to explain a scientific theory or question. A scientific expirement should be tested by many scientists to see if the results are correct. The more scientists aprove and the more evidence we have, the more correct our expirement is.

((hope this helped!)

Role does lactase play in breaking apart the disaccharide lactose is lactase prevents too many disaccharide molecules from clumping together during chemical reactions

Lactose is a disaccharide consisting of 2 monosaccharides, glucose and galactose, linked together via a β-1→4 bond and hydrolysis of this bond requires a specific enzyme called lactase which digests lactose to its components allowing the uptake of glucose and galactose from the intestine

When we eat something containing lactose, an enzyme in the small intestine called lactase breaks it down into simpler sugar forms called glucose and galactose and this glucose and galactose are disaccharide and these simple sugars are then absorbed into the bloodstream and turned into energy

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The concentration of the compounds if the gaseous decomposition of \(N_2O_5\) was studied at 35°C is,

a) \(N_2O_5\) after 12 minutes is 0.0104 mol/L.

b) \(NO_2\) after 12.0 minutes is 0.0208 mol/L.

c) \(O_2\) after 12.0 minutes is 0.0052 mol/L.

To solve this problem, we need to use the integrated rate law for a first-order reaction, which is:

ln[\(N_2O_5\)] = -kt + ln[\(N_2O_5\)]₀

PART A:

We are asked to find the concentration of \(N_2O_5\) after 12.0 minutes, given that the initial concentration is 0.100 mol/L.

First, we need to find the value of the rate constant, k, using the given slope:

slope = -k = -9.8 x \(10^{-4} s^{-1}\)

k = 9.8 x \(10^{-4} s^{-1}\)

The integrated rate law may then be used to solve for ln[\(N_2O_5\)] by including the values of k, t, and [\(N_2O_5\)]:

ln[\(N_2O_5\)] = -kt + ln[\(N_2O_5\)]₀

ln[\(N_2O_5\)] = -(9.8 x \(10^{-4} s^{-1}\)) x (12.0 min x 1/60 s/min) + ln[0.100 mol/L]

ln[\(N_2O_5\)] = -0.0066 + ln[0.100]

ln[\(N_2O_5\)] = -4.714

Finally, we can exponentiate both sides of the equation to solve for [\(N_2O_5\)]:

[\(N_2O_5\)] = \(e^{(-4.714)}\)

[\(N_2O_5\)] = 0.0104 mol/L

Therefore, the concentration of \(N_2O_5\) after 12.0 minutes is 0.0104 mol/L.

PART B:

We are asked to find the concentration of \(NO_2\) after 12.0 minutes, given that the initial concentration of \(N_2O_5\) is 0.100 mol/L.

We might derive from the synthetic condition that the molar proportion of \(NO_2\) to \(N_2O_5\) is either 4:1 or 2:1. In this way, 4 moles of \(NO_2\) are made for every 2 moles of \(N_2O_5\) that separate.

Since we know the concentration of \(N_2O_5\) at 12.0 minutes from part (A), we can use the molar ratio to find the concentration of \(NO_2\):

[\(N_2O_5\)] = 0.0104 mol/L

The molar ratio of \(NO_2\) to \(N_2O_5\) = 2:1

[\(NO_2\)] = (2/1) x [\(N_2O_5\)]

[\(NO_2\)] = 2 x 0.0104 mol/L

[\(NO_2\)] = 0.0208 mol/L

Therefore, the concentration of \(NO_2\) after 12.0 minutes is 0.0208 mol/L.

PART C:

We are asked to find the concentration of \(O_2\) after 12.0 minutes, given that the initial concentration of \(N_2O_5\) 0.100 mol/L.

We may deduce from the chemical equation that \(O_2\) and \(N_2O_5\) have a molar ratio of 1:2. Therefore, 1 mole of \(O_2\) is created for every 2 moles of \(N_2O_5\) that breakdown.

Since we know the concentration of \(N_2O_5\) at 12.0 minutes from part (A), we can use the molar ratio to find the concentration of \(O_2\):

[\(N_2O_5\)] = 0.0104 mol/L

Molar ratio of \(O_2\) to \(N_2O_5\) = 1:2

[\(O_2\)] = (1/2) x [\(N_2O_5\)]

[\(O_2\)] = 0.5 x 0.0104 mol/L

[\(O_2\)] = 0.0052 mol/L

Therefore, the concentration of \(O_2\) molecule after 12.0 minutes is 0.0052 mol/L.

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Surface over which the air mass was formed.

When adding ice to a hot soup, it is generally recommended to use ice made from potable or drinkable water.

The water used to make the ice should be clean and free from any contaminants that could affect the taste or safety of the soup.

It is advisable to use filtered or purify water to make the ice to ensure that it is of good quality. This helps prevent any unwanted flavors or impurities from transferring to the soup.

Using tap water can also be acceptable if it meets the drinking water standards in your area and is considered safe for consumption. However, if you have concerns about the quality of your tap water, using filtered water is a safer option.

Ultimately, the goal is to add ice made from water that is safe and of good quality to avoid any negative impact on the taste or safety of the soup.

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The total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

Given Potential for two inert gas (Xe) atoms at separation R :

U=λe^(-R/rho)-R^6/a^6

a) To calculate the potential energy of the two atoms at equilibrium separation R_0,

we have to put dU/dR = 0λ e^(-R_0/rho) = (6R_0^6)/(a^6)λ e^(-R_0/rho) = (6(12rho)^6)/(a^6)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12)

The potential energy can be expressed as, U=λe^(-R_0/rho) = ((6(12rho)^6)/(a^6)) * e^(12) * e^(-12rho/rho)= ((6*12^6)/a^6) * e^(-11rho)

b) Given R_0 = 12rho, λ = (6(12rho)^6)/(a^6) * e^(12)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Potential energy U = λe^(-R_0/rho) = (6 * 12^6)/(a^6) * e^(-11rho)c)

The total interaction energy in units of eV/ atom assuming λ = 4156 eV and R_0/rho = 12

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Total energy (U) = (N/2)U = (N/2)λe^(-R_0/rho) = (N/2)(6 * 12^6)/(a^6) * e^(-11rho) = 150N eV/atom.

Therefore, the total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

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The solution concentration is approximately 0.008525, or 0.8525% (assuming the concentration is expressed as a percentage).

To determine the solution concentration using the given best fit line equation and %T value, we can rearrange the equation to solve for x, which represents the solution concentration.

The equation given is: y = 7978x - 0.006

Let's substitute %T = 68.0 for y in the equation:

68.0 = 7978x - 0.006

Now, solve for x by isolating it

7978x = 68.0 + 0.006

7978x = 68.006

x = 68.006 / 7978

x ≈ 0.008525

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a. The initial pH of the analyte is approximately 2.21.

b. The new expected pH after adding 15.0 mL of NaOH is 7 (neutral).

c. The new pH after adding 10.0 mL of NaOH is approximately 2.51 (acidic).

a. The initial pH of the analyte can be calculated using the dissociation constant (Ka) of glycolic acid. Given that the Ka of glycolic acid is 1.5 x 10⁻⁴, we can set up an equilibrium expression for the dissociation of glycolic acid as follows:

Ka = [H⁺][A⁻] / [HA]

Assuming the initial concentration of glycolic acid ([HA]) is 0.15 M and neglecting the x value (change in concentration) compared to the initial concentration, we can write:

Ka = [H⁺][A⁻] / 0.15

Since glycolic acid is a monoprotic acid, the concentration of [H⁺] will be equal to the concentration of [A⁻] (once it fully dissociates). Therefore, we can substitute [H⁺] with x in the equation above:

Ka = x² / 0.15

Solving for x, we find:

x = √(Ka * 0.15)

Substituting the given values, we have:

x = √(1.5 x 10⁻⁴ * 0.15) ≈ 0.0061

Taking the negative logarithm of x to find the pH:

pH = -log[H⁺] = -log(0.0061) ≈ 2.21

The initial pH is calculated based on the dissociation constant (Ka) of glycolic acid. Using the equilibrium expression and assuming complete dissociation, we can derive an equation relating Ka, [H⁺], and [A⁻]. Solving for [H⁺] and taking the negative logarithm gives us the initial pH value. In this case, the initial pH is approximately 2.21.

b. The addition of 15.0 mL of NaOH to the analyte will result in a neutralization reaction between the acid and the base. The moles of glycolic acid can be calculated as follows:

moles of glycolic acid = initial concentration of glycolic acid * initial volume of glycolic acid = 0.15 M * 0.050 L = 0.0075 moles

Since glycolic acid and NaOH react in a 1:1 ratio, the moles of NaOH added can be calculated as follows:

moles of NaOH = concentration of NaOH * volume of NaOH added = 0.50 M * 0.015 L = 0.0075 moles

Since the moles of glycolic acid and NaOH are equal, they will react completely, resulting in a neutral solution. Therefore, the new pH is expected to be 7 (neutral).

The addition of NaOH to the analyte leads to a neutralization reaction between the acid (glycolic acid) and the base (NaOH). The moles of each substance can be calculated using their respective concentrations and volumes. As the moles of glycolic acid and NaOH are equal in this case, they will react completely, resulting in a neutral pH of 7.

c. Additionally, adding 10.0 mL of NaOH to the solution from question b will result in further neutralization of the remaining glycolic acid. Using the same approach as in question b, the moles of NaOH added can be calculated as follows:

moles of NaOH = concentration of NaOH * volume of NaOH added = 0.50 M * 0.010 L = 0.005 moles

Since the initial moles of glycolic acid were

0.0075 moles and the moles of NaOH added are now 0.005 moles, there will be an excess of glycolic acid remaining. Therefore, the solution will be acidic. To calculate the new pH, we need to determine the concentration of the remaining glycolic acid:

remaining moles of glycolic acid = initial moles - moles of NaOH added = 0.0075 - 0.005 = 0.0025 moles

The remaining concentration can be calculated as follows:

remaining concentration = remaining moles / total volume of solution = 0.0025 moles / (0.050 L + 0.015 L + 0.010 L) = 0.025 M

Using the dissociation constant (Ka) and the concentration of the remaining glycolic acid, we can set up an equilibrium expression:

Ka = [H⁺][A⁻] / [HA]

Assuming the remaining concentration of glycolic acid ([HA]) is 0.025 M and neglecting the x value compared to the initial concentration, we can write:

Ka = [H⁺][A⁻] / 0.025

Since glycolic acid is a monoprotic acid, the concentration of [H⁺] will be equal to the concentration of [A⁻]. Therefore, we can substitute [H⁺] with x:

Ka = x² / 0.025

Solving for x, we find:

x = √(Ka * 0.025)

Substituting the given values, we have:

x = √(1.5 x 10⁻⁴ * 0.025) ≈ 0.0031

Taking the negative logarithm of x to find the pH:

pH = -log[H⁺] = -log(0.0031) ≈ 2.51

Adding NaOH to the solution in question b results in further neutralization of the remaining glycolic acid. The moles of NaOH added are calculated using the concentration and volume of NaOH. Since the initial moles of glycolic acid are higher than the moles of NaOH added, there will be some glycolic acid remaining, making the solution acidic.

To determine the new pH, we need to calculate the concentration of the remaining glycolic acid and use the dissociation constant (Ka) to set up an equilibrium expression.

Solving for [H⁺] and taking the negative logarithm gives us the new pH value. In this case, the new pH is approximately 2.51.

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Carlos likes to bowl. He timed how long it took his ball to travel the length of the bowling alley's 18-meter lane. The ball will travel 12 m far after it had travelled for 2 s.

Length can be defined as a term used for identifying the size of an object and distance travelled by the object from one point to another point.

The S.I. unit of length is meter.

It can also be defined as the amount of time that something can last.

Thus, Carlos likes to bowl. He timed how long it took for his ball to travel the length of an 18-m lane in the bowling alley. The ball will travel 12 m far after it had travelled for 2 s.

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Your question is incomplete but most probably your full question was

Carlos likes to bowl. He timed how long it took for his ball to travel the length of a an 18-m lane in the bowling alley. He plotted the final distance and time on a line graph. Carlos drew a line from this point to the origin of the graph.

How far down the lane was the ball after it had traveled for 2 s?

6 m

9 m

12 m

18 m