Drag each tile to the correct location. what types of mixtures are these? a cup of tea and sugar a bucket full of sand and gravel food coloring dissolved in water peanuts and almonds mixed together in a bowl homogeneous mixture or hetrogeneous mixture

Answer:

filtration and chromatography

Explanation:

I hope this will help you :-)

The equilibrium constant expression for the reaction is (PSiO2)4/(PSi2H6)2(PO2)7. Hence, the correct option is C.

In this expression, the concentrations of the reactants (Si2H6 and O2) are raised to the power of their respective stoichiometric coefficients, and the concentration of the product (SiO2) is raised to the power of its stoichiometric coefficient. The concentration of the liquid product (H2O) is not included in the equilibrium constant expression because it is in the liquid state.

The correct expression for the equilibrium constant (K) for the given reaction is:

C. (PSiO2)4/(PSi2H6)2(PO2)7

Therefore, the equilibrium constant expression for the reaction is (PSiO2)4/(PSi2H6)2(PO2)7.

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Answer:

YEESSS

Explanation:

Because that seems like the only logical answer.

Answer:

YES

Explanation:

YES

1.  James falls into the "Overweight" category.

2. James has experienced a weight loss of approximately 11.32% compared to his usual weight.

3. A high risk of malnutrition.

4. James's estimated resting energy needs are approximately 1713 calories per day.

5. Daily protein requirement = 59 grams of protein per day

1. To calculate James's BMI (Body Mass Index), we'll use the formula:

BMI = (weight in pounds x 703) / (height in inches x height in inches)

BMI = (196 pounds x 703) / (72 inches x 72 inches)

BMI = 137,588 / 5,184

BMI = 26.6 kg/m^2

Based on the weight classification categories, James falls into the "Overweight" category.

2. To determine the percentage weight change, we'll use the formula:

Percentage weight change = [(current weight - usual weight) / usual weight] x 100

Percentage weight change = [(196 pounds - 221 pounds) / 221 pounds] x 100

Percentage weight change = (-25 pounds / 221 pounds) x 100

Percentage weight change = -0.1132 x 100

Percentage weight change = -11.32%

James has experienced a weight loss of approximately 11.32% compared to his usual weight.

3. To categorize the patient's risk of malnutrition based on weight change, we need to consider the percentage weight change. Generally, a weight loss of more than 10% is considered significant and may indicate a high risk of malnutrition. In James's case, with a weight loss of 11.32%, he would be categorized as having a high risk of malnutrition.

4. To calculate James's resting energy needs using the Mifflin-St. Jeor equation, we'll use the formula for men:

Resting energy needs = (10 x weight in kg) + (6.25 x height in cm) - (5 x age in years) + 5

Converting weight from pounds to kilograms:

Weight in kg = 196 pounds / 2.2

Weight in kg = 89 kg

Converting height from inches to centimeters:

Height in cm = 72 inches x 2.54

Height in cm = 182.88 cm

Resting energy needs = (10 x 89 kg) + (6.25 x 182.88 cm) - (5 x 65 years) + 5

Resting energy needs = 890 + 1143 - 325 + 5

Resting energy needs = 1713 calories per day

James's estimated resting energy needs are approximately 1713 calories per day.

5. To calculate James's daily protein requirement based on 1.0 gram per kilogram of his ideal body weight, we'll use his ideal body weight of 130 pounds:

Ideal body weight in kg = 130 pounds / 2.2

Ideal body weight in kg = 59 kg

Daily protein requirement = 1.0 gram/kg x 59 kg

Daily protein requirement = 59 grams of protein per day.

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Answer:

1g Hydrogen

Explanation:

Calcium in water reacts vigorously to give a cloudy white Precipitate (compound) called Calcium hydroxide alongwith the evolution of Hydrogen gas.

\( \boxed{ \mathsf{Ca + H_2O \rightarrow Ca(OH)_2 + H_2}}\)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

This reaction is not in it's balanced form! The number of atoms of Hydrogen on the left is 2 while that on the right is 4,I.e.,they're not equal.

Adding a 2 in front of H2O solves the problem by making the number of atoms of each element on both the sides equal.

\( \mathsf{Ca +2 H_2O \rightarrow Ca(OH)_2 + H_2}\)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Looking into the equation more carefully, we see:

1 atom of Calcium reacts with 2 molecules of water to give 1 molecule of Calcium Hydroxide alongwith 1 molecule of Hydrogen gas.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Mass of one atom of Calcium = it's gram atomic mass

= 40 g

Mass of one "molecule" of Hydrogen

= it's Gram molecular mass

= gram mass of one atom × number of atoms in one molecule

= 1 × 2

= 2 g

So,

according to our observation:

One atoms of Calcium gives one molecule of Hydrogen (during the particular reaction)

=> 40g of Calcium gives = 2g of Hydrogen

•°• 1 g of Calcium gives = \( \frac{2}{40} \)

= \( \frac{1}{20} \) g Hydrogen

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

We're provided with 20g of Calcium,

=> 20g of Calcium gives = 20 × \( \frac{1}{20} \) g H2

= 1 g H2

_______________

Hope this helps!

sum all the atomic mass of the constituent atoms

To determine the molar mass of a compound containing many atoms, add all of the constituent atoms’ atomic masses. For example, the molar mass of NaCl may be computed by first determining the atomic masses of sodium (22.99 g/mol) and chlorine (35.45 g/mol) and then combining them.

Multiply the atomic weight of each element (from the periodic table) by the number of atoms of that element in the compound. 3. Add everything together and include the units of grams/mole after the number. Many (but not all) difficulties can be solved by simply rounding the atomic weights and molar masses to the closest 0.1 g/mole.

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

The mass of the iron will produce is equal to 11.16 grams and iron oxide will be the limiting reagent.

A limiting reagent can be explained as the reactant present in the chemical reaction which is consumed completely first during the completion of a reaction.

The limiting reagent in a chemical reaction decides the amount of the product when the reactants are not taken in stoichiometry.

Given, chemical reaction of iron oxide and aluminum represented as:\(Fe_2O_3 + 2Al \longrightarrow Al_2O_3 + 2Fe\)is:

The mass of the iron oxide = 16 g

The number of moles of iron oxide = 16/159.7 = 0.1 moles

The mass of aluminum powder = 8.1 g

The number of moles of Al = 8.1/27 = 0.3 mol

The 2 moles of Al react with iron oxide = 1

0.3 moles of Al react with iron oxide = 0.3/2 = 0.15 mol

Therefore iron oxide is a limiting reagent.

One mole of iron oxide will produce iron = 2 mol

0.1 mol of iron oxide will produce iron metal = 2 × 0.1 = 0.2 mol

The maximum mass of iron metal = 0.2 ×55.8 = 11.16 g

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The electrostatic potential energy between an electron and a proton that are separated by 53pm is 4.27 × 10^-18 J.

The electrostatic potential energy between two charged particles can be calculated using the

formula U = k*q1*q2/r,

where:

k is the Coulomb constant,

q1 and q2 are the charges of the two particles, and

r is the distance between them.

In this case, we have q1 = -1.60*10^-19 C (charge of the electron), q2 = 1.60*10^-19 C (charge of the proton), and r = 53 pm = 5.3*10^-10 m. Plugging these values into the formula, we get:

U = (8.99*10^9 N m2/C2)*(-1.60*10^-19 C)*(1.60*10^-19 C)/(5.3*10^-10 m)

U = 4.27 × 10^-18 J

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if the unknown solution is mixed with potassium carbonate, the reaction will proceed differently depending on whether the unknown solution is strontium nitrate or magnesium nitrate.

Mixing the unknown solution with potassium sulfate will not provide any useful information to identify whether the unknown solution is strontium nitrate or magnesium nitrate. This is because neither strontium nor magnesium sulfate has distinctive properties that allow them to be easily distinguished from one another.

However, When mixed with strontium nitrate, potassium carbonate will form a white precipitate of strontium carbonate, while no reaction will occur when mixed with magnesium nitrate. Therefore, the presence of a white precipitate after mixing with potassium carbonate indicates that the unknown solution is strontium nitrate.

In summary, to identify whether the unknown solution is strontium nitrate or magnesium nitrate, the solution should be mixed with potassium carbonate. If a white precipitate forms, the solution is strontium nitrate. If no reaction occurs, the solution is magnesium nitrate. Mixing the unknown solution with potassium sulfate will not provide any useful information.

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The cathodic protection of Cu(s) can be provided if it is connected galvanically to Zn.

The metal with the more reduction potential will act as the anode and undergo oxidation, while the metal with the more positive standard reduction potential will act as the cathode and undergo reduction.

As Cu has a greater reduction potential than Zn, it has a greater capacity to reduce than that of Zn. So by galvanically connecting to zn, we can say that the cathodic protection of Cu can be obtained.

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Answer:

Renewable energy

Explanation:

on the other hand, typically emits less CO2 than fossil fuels. In fact, renewables like solar and wind power—apart from construction and maintenance—don't emit any CO2 at all. With renewable energy, you can breathe easier, stay cooler, and create a more comfortable world for generations to come.

Answer:

renewable energy comes from natural resources that can be replenished or replaced during an average human lifetime ; eg, Hydro, solar, wind etc.

fossil fuels can take thousands or even millions of years to naturally replenish; eg, natural gas, coal, oil.

Answer:

When two distinct elements are chemically combined—i.e., chemical bonds form between their atoms—the result is called a chemical compound. Most elements on Earth bond with other elements to form chemical compounds, such as sodium (Na) and Chloride (Cl), which combine to form table salt (NaCl).

Answer:

a. Due to the evolved hydrogen from potassium to water reaction being able to reach the flash point of the reaction temperature

b. Non-metal

The molecular formula is N₂O₃

Explanation:

a. The heat of the reaction between calcium and water is given as follows

Ca + 2 H₂O → H₂ +  Ca(OH)₂    ΔH = -431.15 kJ which is exothermic, Entropy = -125.29 J/K

The heat of the reaction between potassium and water is given as follows

2 k + 2 H₂O → 2 KOH  + H₂ ΔH = -393.15 kJ Entropy = 44.91 J/K

Therefore, the reaction between potassium and water occurs more vigorously than the reaction between calcium and water such that the flash point for the released hydrogen gas is reached in the case of potassium

b. The acidic oxides are oxides of metals or non-metals that react with water to produce an acid

Given the valence of the oxide which is +3, the oxide can be aluminium, Al or nitrogen, N, however, Al₂O₃ behaves both as an acid and a base, therefore, the likely candidate is nitrogen, which shows that X is a non-metal

The molecular formula is therefore;

N₂O₃

When we multiply a reaction by 2, we double the stoichiometric coefficients of the reactants and products.

However, the standard reduction potential (E°red) is an intensive property and remains unchanged. E°red represents the potential of a single mole of electrons transferred in the redox reaction. By doubling the reaction, we effectively double the number of moles of electrons transferred, but the potential per mole of electrons remains the same. Therefore, we do not multiply E°red by 2. It is important to note that E°red values are specific to individual half-reactions and do not depend on the overall balanced equation or the reaction stoichiometry.

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Answer:

Yes under certain conditions

Explanation:

Although radioactivity is harmful, there are still safety precautions people can take to avoid disaster. Assuming that the radioactive waste is already in a specialized bin, workers would have to wear hazmat suits and load it onto a truck. It would be best if the truck was made out of at least 2 layers of some strong metal like titanium. Next, a route would need to be planed out with 2 factors in mind. 1. It has to be a relatively isolated road. 2. It has to be the shortest route taken. The truck must already be fueled to avoid running out of gas in the middle of the road or having to go off the assigned route to a gas station. It would help out a lot if the factories were relatively close to the pickup destination so it would be quicker to travel from point A to point B. There are more things that can be done in terms of safety but these are key.

Answer:

A chemical reaction is usually accompanied by easily observed physical effects, such as the emission of heat and light, the formation of a precipitate, the evolution of gas, or a color change

Answer:

i think D

Explanation:

The disaccharide shown has an alpha-1,4-glycosidic linkage. Sugar A is the alpha-D-glucose form, and Sugar B is the beta-D-fructose form.

The glycosidic linkage between the two monosaccharide units in the disaccharide shown is an alpha-1,4-glycosidic linkage. This indicates that the glucose unit is linked to the fructose unit via an alpha bond formed between C1 of the glucose unit and C4 of the fructose unit.

Sugar A is the alpha-D-glucose form because it has an alpha configuration at the anomeric carbon (C1) of the glucose unit. Similarly, Sugar B is the beta-D-fructose form because it has a beta configuration at the anomeric carbon (C2) of the fructose unit.

Therefore, the disaccharide shown has an alpha-1,4-glycosidic linkage, Sugar A is the alpha-D-glucose form, and Sugar B is the beta-D-fructose form.

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Answer:

0.416 mol CaBr₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

83.1 g CaBr₂

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Molar mass of Br - 79.90 g/mol

Molar Mass of CaBr₂ - 40.08 + 2(79.90) = 199.88 g/mol

Step 3: Convert

\(83.1 \ g \ CaBr_2(\frac{1 \ mol \ CaBr_2}{199.88 \ g \ CaBr_2} )\) = 0.415749 mol CaBr₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.415749 mol CaBr₂ ≈ 0.416 mol CaBr₂

Step 1:In order to determine the order of a reaction and its rate constant from a series of data that includes the concentration of A at varying times, graphical methods can be used. Here are the steps that need to be followed:Step 1: Plot the data. Concentration of A is plotted against time.

Step 2: Determine the order of the reaction. The order of the reaction can be determined by examining the shape of the concentration-time graph. If the concentration-time graph is linear, the reaction is a first-order reaction. If the concentration-time graph is a curved line, then the reaction is a second-order or higher-order reaction.

Step 3: Calculate the rate constant. For a first-order reaction, the rate constant can be determined by plotting the natural logarithm of the concentration of A against time and taking the slope of the resulting straight line.

For a second-order reaction, the rate constant can be determined by plotting the inverse of the concentration of A against time and taking the slope of the resulting straight line. For a zero-order reaction, the rate constant can be determined by plotting the concentration of A against time and taking the negative slope of the resulting straight line.

Step 4: Determine the rate law. The rate law can be determined by substituting the value of the rate constant into the rate equation and solving for the exponents.

In other words, the rate law gives the relationship between the rate of the reaction and the concentrations of the reactants. It can be expressed as: rate = k[A]^n, where k is the rate constant and n is the order of the reaction.

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Graphical methods, such as the method of initial rates and integrated rate laws, can be used to determine the order of a reaction and its rate constant from a series of data that includes the concentration of A at varying times.

Method of Initial Rates:

The method of initial rates involves conducting several experiments with different initial concentrations of reactants and measuring the initial rates of the reaction.

By plotting the initial rate versus the initial concentration of A, you can determine the order of the reaction.

Let's assume we have data from three experiments:

Experiment 1:

[A]₀ = 0.1 M

Initial rate = 0.05 M/s

Experiment 2:

[A]₀ = 0.2 M

Initial rate = 0.1 M/s

Experiment 3:

[A]₀ = 0.4 M

Initial rate = 0.4 M/s

By plotting the initial rate versus the initial concentration ([A]₀) on a graph, you can determine the order of the reaction. If the graph shows a linear relationship, the reaction is likely first order with respect to A. If the graph is quadratic, it suggests a second order, and so on.

Integrated Rate Laws:

Integrated rate laws can also be used to determine the order of a reaction and its rate constant. These laws express the relationship between the concentration of a reactant and time.

For example, for a first-order reaction, the integrated rate law is:

ln([A]t / [A]₀) = -kt

where [A]t is the concentration of A at time t, [A]₀ is the initial concentration, k is the rate constant, and ln is the natural logarithm.

By plotting ln([A]t / [A]₀) versus time, you can determine the order of the reaction based on the linearity of the graph. The slope of the graph is equal to -k, allowing you to calculate the rate constant.

Graphical methods, such as the method of initial rates and integrated rate laws, provide useful tools to determine the order of a reaction and its rate constant from concentration versus time data.

By analyzing the relationship between initial rates and initial concentrations or by plotting concentration ratios versus time, it is possible to establish the order of the reaction and calculate the rate constant.

These graphical techniques are valuable in understanding the kinetics of chemical reactions.

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The molarity of KMnO4 in the given solution is approximately 0.00126 M. Molarity is a measure of the concentration of a solute in a solution. It represents the number of moles of the solute present per liter of the solution.

To determine the molarity of KMnO4 in the given solution, we need to first calculate the number of moles of KMnO4 using its mass and molar mass, and then divide it by the volume of the solution.

The molar mass of KMnO4 can be calculated as follows:

(1 × atomic mass of potassium) + (1 × atomic mass of manganese) + (4 × atomic mass of oxygen)

= (1 × 39.10 g/mol) + (1 × 54.94 g/mol) + (4 × 16.00 g/mol)

= 39.10 g/mol + 54.94 g/mol + 64.00 g/mol

= 158.04 g/mol

Now, let's calculate the number of moles of KMnO4:

Number of moles = Mass / Molar mass

Number of moles = 0.0897 g / 158.04 g/mol

Number of moles ≈ 0.000567 mol

Next, we need to calculate the molarity using the number of moles and the volume of the solution:

Molarity (M) = Number of moles / Volume (in liters)

Molarity = 0.000567 mol / 0.450 L

Molarity ≈ 0.00126 M

In this case, the molarity tells us the concentration of KMnO4 in moles per liter.

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The third law of thermodynamics describes the entropy of a: solid.

The third law of thermodynamics states that the entropy of a pure crystalline substance approaches zero as the temperature approaches absolute zero (0 Kelvin or -273.15 degrees Celsius). This law implies that at absolute zero, a perfectly ordered and pure crystalline solid will have zero entropy.

The third law of thermodynamics is not specific to liquids or gases but applies to solids. In a solid, the molecules are highly ordered and have fixed positions in a regular lattice structure. As the temperature decreases towards absolute zero, the thermal motion of the molecules reduces, and the system becomes more ordered, resulting in a decrease in entropy.

In contrast, liquids and gases have higher entropy compared to solids at absolute zero because their molecules have more freedom of movement and are not as tightly arranged. Therefore, the third law of thermodynamics specifically addresses the entropy of solids and does not apply to liquids or gases.

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Answer:

I think it could be bad for some people because children could be exposed to toxic content. Without parent restrictions there could be some serious harm. Another reason, is that being on social media could distract kids from homework, chores, etc. (There is also scams and fake advertising)

I personally deleted a lot of my social media acc’s last year cause of me getting stressed and sad over it, but for now I’m pretty good I’m making friends off it having lots of fun

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 325 mL

density = 0.874 g/mL

We have

mass = 325 × 0.874

We have the final answer as

Hope this helps you

The molarity of a solution consisting of 6.0 moles of nacl dissolved in a total 3.0l of solution is 2.0 M.

The molarity of the solution is calculated by dividing the moles of solute by the volume of solution in liters. In this case, we have 6.0 moles of NaCl dissolved in a total volume of 3.0 liters of solution.

Therefore, the molarity of the solution is:
Molarity = moles of solute / volume of solution in liters
Molarity = 6.0 moles / 3.0 liters
Molarity = 2.0 M
So, by calculating the molarity of the solution, the result is 2.0 M (M stands for molar, which is a unit of concentration).

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At equilibrium, 0.313 moles of isobutane react with 0.313 moles of butene to form 0.626 moles of 2,2,3 trimethylpentane, and the mole fractions of isobutane and butene in the system are 0.313 and 0.687, respectively.

To determine the equilibrium extent of reaction and composition for the given system, we need to use the thermodynamic equilibrium constant, Kp. At constant temperature and pressure, the equilibrium constant can be written as:

Kp = exp(-ΔG* ÷ RT)

Where R is the gas constant and T is the temperature in Kelvin. Using the given value of ΔG* and the ideal gas law, we can calculate the equilibrium constant:

Kp = exp(4.10 kcal/mol ÷ (1.9872 cal/mol-K * 500 K)) = 7.78

Therefore, the equilibrium extent of the reaction is:

E = 2x ÷ (x + 1) = 2x ÷ (total moles)

To find the composition of the system at equilibrium, we can use the mole balance equation and the ideal gas law. Let y₁ and y₂ be the mole fractions of isobutane and butene, respectively, at equilibrium. Then, we have:

y₁ + y₂ = 1

And the mole balance equation for isobutane is:

x ÷ (x + 1) = y₁ ÷(1 - y₂)

Using the ideal gas law, we can express the mole fractions in terms of the partial pressures of the components:

y₁ = P₁ ÷ P

y₂ = P₂ ÷ P

where P1 and P2 are the partial pressures of isobutane and butene, respectively, and P is the total pressure of the system. Then, using the given initial conditions of the equimolar mixture and the ideal gas law, we can find the partial pressures of the components:

P₁ = P₂ = (1 ÷ 2) × P = 0.5 atm

y₁ = 0.313, y₂ = 0.687

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The complete question is:

Consider the following reaction in a closed vessel at a pressure of 1.0 atm and temperature of 500 K,

isobutane + 1-butene ⇄ 2,2,3 trimethylpentane

The standard Gibbs energy and enthalpy changes for the reaction are:

ΔG* = - 4.10 kcal/mol

ΔH* = -20.11 kcal/mol.

Determine the equilibrium extent of reaction, E (mols reacting), and the composition (in mole fractions) for this system for an initial equimolar mixture of isobutane and butene. Assume this mixture behaves as an ideal gas mixture.

Answer: 652.8 g of iron (III) oxide produced.

Explanation:

To calculate the amount of iron (III) oxide produced, we use the enthalpy change of the reaction to determine the amount of energy released and convert it to moles of Fe2O3 produced. Then, we multiply by the molar mass of Fe2O3 to obtain the mass of Fe2O3 produced. Using these calculations, we get 652.8 g of iron (III) oxide produced.

580.84 grams of iron (III) oxide will be produced when 4300 kJ of heat energy is released.

Given:

Enthalpy change (∆H) value: ∆H = -1652 kJ

Amount of heat energy released: 4300 kJ

From the balanced equation:

4Fe + 3O₂ → 2 Fe₂O₃

The molar ratio between Fe₂O₃ and ∆H is 2:1652 kJ.

To find the molar amount of Fe₂O₃ produced, the following calculation:

\(4300 \times \frac{2}{1652}\) = 5.20 mol Fe₂O₃

To convert this into grams, it is required to multiply the molar amount by the molar mass of Fe₂O₃:

5.20  × 2  × 55.85 = 580.84 g

Therefore, 580.84 grams of iron (III) oxide will be produced when 4300 kJ of heat energy is released.

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.Answer:

Periods are horizontal rows (across) the periodic table, while groups are vertical columns (down) the table. Atomic number increases as you move down a group or across a period.

Explanation: