Drag the tiles to the correct boxes to complete the pairs. Solve the inequalities for x, and match each solution to its number line graph. Two less than of a number (x) is no more than . The sum of two times a number (x) and -2 is at least 8. Seven subtracted from 4 times a number (x) is more than 13. Four added to 3 times a number (x) is less than 19.

Answers

Answer 1

in the figure, the first number line goes with x \(\leq\)5

the second number line goes with x \(\geq\) 5

the third number line goes with x > 5

the fourth number line goes with x < 5

Two less than 3/2 of a number x is  no more than 5/2 is shown as:

3/2 x- 2 \(\leq\) 5 1/2

3/2 x \(\leq\) 11/2 + 2

3/2 x \(\leq\) 15/2

3x \(\leq\) 15

x \(\leq\) 5

The sum of two times a number (x) and -2 is at least 8 is shown as :

2x+(-2) \(\geq\) 8

2x - 2 \(\geq\) 8

2x \(\geq\) 8+2

2x \(\geq\) 10

x \(\geq\) 5

Seven subtracted from 4 times a number (x) is more than 13 is shown as

4x -7 > 13

4x > 13+7

4x > 20

x > 20 ÷ 4

x > 5

Four added to 3 times a number (x) is less than 19 is shown as

3x + 4 < 19

3x < 19-4

3x < 15

x < 15 ÷ 3

x< 5

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Drag The Tiles To The Correct Boxes To Complete The Pairs. Solve The Inequalities For X, And Match Each

Related Questions

7. Use the Unit Circle to find the exact value of the trig function,
sin(180°)

Answers

The exact value is 0

Graphing (y=x+6) (y=-2x-3)

Answers

Answer:

srry its black but thats how you would graph it

Step-by-step explanation:

Graphing (y=x+6) (y=-2x-3)

Sara and her friends are knitting scarves for a school fundraiser.
• They estimate that they will have fixed expenses of $12.
In addition, they will spend $7 on yarn for each scarf.
Which graph shows the total expenses, E, for n scarves?
.

Answers

Based on the information, we can infer that graph B is the one that correctly expresses the expenses that Sara and her friends will have.

How to identify the graph that correctly expresses the information?

To identify the graph that correctly expresses the information we must analyze the information. In this case we must take into account the fixed expenses that Sara and her friends will have, which is $7. This would be the starting point of the graph line.

On the other hand, all the values that represent an additional expense will mean an increase in this graph. So, we can infer that the correct chart is B because it starts at the value of $7.

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Sara and her friends are knitting scarves for a school fundraiser. They estimate that they will have

simplify √([2m5z6]/[ xy])

Answers

The simplified form of √([2m5z6]/[xy]) is (√2m√5z√6) / (√x√y).

To simplify the expression √([2m5z6]/[xy]), we can break it down step by step:

Simplify the numerator:

√(2m5z6) = √(2) * √(m) * √(5) * √(z) * √(6)

= √2m√5z√6

Simplify the denominator:

√(xy) = √(x) * √(y)

Combine the numerator and denominator:

√([2m5z6]/[xy]) = (√2m√5z√6) / (√x√y)

Thus, the simplified form of √([2m5z6]/[xy]) is (√2m√5z√6) / (√x√y).

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my father bought a robot for 670 2.50 and a toy car for 300 19.25 how much change did he get for his 1000.00
A.7.25 B.15.75cm C.27.75cm D.10.25​

Answers

Answer:

Step-by-step explanation:

If it is supposed to be 672.50 and 319.25 then you can just go 1000 minus 672.50 which is 327.50 and then subtract 319.25 to get 8.25. But your answers show cm and none show the right answer.  So, if it's rounding then choose A.

The perimeter of a rectangle is 360 centimetres. If the ratio of its length to its width is 11:4, find the dimensions of the rectangle.​

Answers

Answer: Length 132cm, Breadth 48cm

Explanation:

Perimeter = 360cm

Let the length and breadth be x

ATQ

2(11x + 4x) = 360

22x + 8x = 360

30x = 360

x = 360/30

x = 12

Length = 11×12

= 132 cm

Breadth = 4×12

= 48cm

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Simplify: 5w^5-(-4w^5)

Answers

Answer:

9w^5

Step-by-step explanation:

If IK=JK, find mlJ
A. 72°
B. 82°
C. 122°
D. 134°

Answers

Answer:

D.134

Step-by-step explanation:

It is given that m ∠ AOB = 42 ∘ and m ∠ EOF = 66 ∘ . By the ___________, ∠ EOF ≅ ∠ BOC . Therefore, m ∠ BOC = 66 ∘ . By the ________ , m ∠ AOC = 108 ∘ , and by ________ the , m ∠ AOC + m ∠ COD = 180 ∘ . After application of the ___________, m ∠ COD = 72 ∘ .

Answers

The required appropriate properties to fit the black space is given as,
(a) Congruent angles
(b) Addition of angles
(c) straight angles
(d) Subtraction of angles.

What are the angle?

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

It is given that m ∠ AOB = 42 ∘ and m ∠ EOF = 66 ∘ . By the definition of congruent angles, ∠ EOF ≅ ∠ BOC. Therefore, m ∠ BOC = 66 ∘ . In the addition, m ∠ AOC = 108 ∘ , and by definition of the straight angle, m ∠ AOC + m ∠ COD = 180 ∘ . After application of the subtraction of the angle, m ∠ COD = 72 ∘ .

Thus, the required appropriate properties to fit the black space is given as,
(a) Congruent angles
(b) Addition of angles
(c) straight angles
(d) Subtraction of angles.

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It is given that m AOB = 42 and m EOF = 66 . By the ___________, EOF BOC . Therefore, m BOC = 66 . By

Answer:

It is given that m∠AOB = 42º and m∠EOF = 66º. By the vertical angles theorem, ∠EOF ≅ ∠BOC. By the angle addition postulate, m∠AOC = 108º, and by the linear pair theorem, m∠AOC + m∠COD = 108º. After the application of the subtraction property of equality, m∠ COD = 72º.

Step - by - step

first box: vertical angles theorem

second box: angle addition postulate

third box:  linear pair theorem

fourth box: subtraction property of equality

What is 2 + 2 I'm in 11th grade and my teacher gave me this question?

Answers

Answer:

2+2=4

Step-by-step explanation:

I don't even know why this is a question

Answer:

2+2  is 4 ok tell ur thecher it is four

Step-by-step explanation: lol

if the price of gold decreases at a monthly rate of 2.1% by what percent does it decrease in a year?

Answers

We have that each month, the price of gold decreases 2.1%, then, if in a year there are 12 months, we have:

\(12\cdot(2.1)=25.2\)

thus, in a year, the price of gold decreases 25.2%

1) Given h(x)=x-5
a) Determine h^2
b)determine h^3

Answers

Answer:

A) x^2-10x+25 B)X^3-15x^2+75x-125

Step-by-step explanation:

H^2=(x-5)(x-5)=x^2-10x+25

H^3=(x-5)(x-5)(x-5)=X^3-15x^2+75x-125

Angles and Parallel Lines

Angles and Parallel Lines

Answers

Answer:

a = 6

b = 25

Step-by-step explanation:

As alternative angles in a parallel line are equal to each other,

5a = 3a + 12

So, now we can find the value of a by making "a" the subject.

5a - 3a = 12

2a = 12

Divide both sides by 2.

a = 6°

                                                                                                     

And now let us find the value of b.

We know that interior angles in a triangle are added up to 180°.

So,

2b + 4b + 3a + 12 = 180

We can replace a with 6 and then we can make "b" the subject to find the value of b.

Let us solve it now.

2b + 4b + 3 × 6 + 12 = 180

6b + 18 + 12 = 180

6b + 30 = 180

6b = 180 - 30

6b = 150

Divide both sides by 6.

b = 25°

A line segment has the endpoints V(7, 2) and W(3, 10). Find the coordinates of its midpoint M.

Answers

The coordinates of the midpoint M of the line segment VW are M = (5, 6)

In this question,

We have been given a line segment having endpoints V(7, 2) and W(3, 10)

We need to find the coordinates of the midpoint M of the line segment VW.

We know that the midpoint of points (x1, y1) and (x2, y2) is

M = (x1 + x2 / 2, y1 + y2 / 2)

Using midpoint formula,

M = ((7 + 3) / 2, (2 + 10) / 2)

M = (10/2, 12/2)

M = (5, 6)

Therefore, the coordinates of the midpoint M of the line segment VW are M = (5, 6)

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which of these statements is true for 89.033​

Answers

Maybe if you payed attention in class you would know.

Molly's scout troop sold 148 boxes of cookies last month and 165 boxes this month. Find the percent of increase, rounded to the nearest tenth of a percent.

Answers

The percent of the increase, rounded to the nearest tenth of a percent, concerning the sales of boxes of cookies that Molly sold last month and this month, is 11.5%.

How is the percentage increase determined?

The percentage increase can be determined by finding the difference or the amount of increase in sales.

This difference is divided by the previous month's sales and multiplied by 100.

The total number of boxes of cookies Molly's Scout Troop sold last month = 148

The total number sold this month = 165

The increase = 17 (165 - 148)

Percentage increase = 11.5% (17 ÷ 148 x 100)

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help pls!!!
A ball is launched upwards from a height of 4 feet. The ball’s height as a function of time, in seconds, is modeled by the function h(t)= -16t^2+80t+4. What is the time interval in which the ball has a height greater than 100 feet?

Answers

Answer:   2 < t < 3

This is between 2 and 3 seconds, excluding both endpoints.

========================================================

Explanation:

t = elapsed time in seconds

h(t) = height of the ball at time t

Replace h(t) with 100. Then get everything to one side.

\(h(t)= -16t^2+80t+4\\\\100= -16t^2+80t+4\\\\0 = -16t^2+80t+4-100\\\\0= -16t^2+80t-96\\\\-16t^2+80t-96 = 0\)

Next, we'll use the quadratic formula to isolate t.

Plug in a = -16, b = 80, c = -96 which are the coefficients of the last equation mentioned above.

\(t = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\t = \frac{-80\pm\sqrt{(80)^2-4(-16)(-96)}}{2(-16)}\\\\t = \frac{-80\pm\sqrt{256}}{-32}\\\\t = \frac{-80\pm16}{-32}\\\\t = \frac{-80+16}{-32} \ \text{ or } \ t = \frac{-80-16}{-32}\\\\t = \frac{-64}{-32} \ \text{ or } \ t = \frac{-96}{-32}\\\\t = 2 \ \text{ or } \ t = 3\\\\\)

Therefore, the ball's height is greater than 100 ft in the air for the interval \(2 < t < 3\)

This is between 2 and 3 seconds, excluding both endpoints.

------------------

Check:

Let's plug in t = 2 to find that...

\(h(t)= -16t^2+80t+4\\\\h(2)= -16(2)^2+80(2)+4\\\\h(2)= -16(4)+80(2)+4\\\\h(2)= -64+160+4\\\\h(2)= 100\\\\\)

You should find that h(3) = 100 as well. I'll let you do those steps.

Since h(2) = 100 and h(3) = 100, this confirms the two solutions we found earlier.

A dog is starting a diet to get in better shape. The
dog starts at 89.5 pounds and loses 0.5 pounds
each week for a certain number of weeks. Halfway
through the diet, the dog weighs 80 pounds. How
many weeks has the dog been dieting for?​

Answers

Answer:

18.5 days

Step-by-step explanation:

Count by two's on your fingers until you have nine fingers up, and that equals 9 x 2 = 18, plus that .5 eqauls 18.5 days.

The dog has been dieting for 19 weeks.

What is unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

According to the given problem,

Starting weight of the dog = 89.5 pounds

Halfway weight of the dog = 80 pounds

Weight the dog loses per week = 0.5 pounds

Weight loss = (89.5 - 80) pounds

                    = 9.5 pounds

If the dog loses 0.5 pounds in 1 week,

Then the dog will lose 9.5 pounds in (9.5 × 2) weeks

⇒ The dog will lose 9.5 pounds in 19 weeks.

Hence, we can conclude that the dog has week dieting for 19 weeks and lost 9.5 pounds.

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Determine the equation of the circle with center (0, -2) containing the point
(√12,-5).

Answers

Answer:

i think its

x^2 + (y + 2)^2 = 21.

Step-by-step explanation:

A. 1/3
B. 5/13
C. 4/5
D. 12/13

A. 1/3B. 5/13C. 4/5D. 12/13

Answers

Answer:

5/13

Step-by-step explanation:

OM is 5 and OL is 13 use Pythagoreans theorem

is this statistical, what is the total number of eggs in dozen?

Answers

The total number of eggs in a dozen is 12.

14 less than 6 times a number

Answers

Step-by-step explanation:

14 < 6×?

6×3=18

therefore anything above 3 multiplied by 6 would be greater in value than 14

Find the value of cos
V
V rounded to the nearest hundredth, if necessary.

Answers

Answer:

image

Step-by-step explanation:

image

Find the value of cos VV rounded to the nearest hundredth, if necessary.
Find the value of cos VV rounded to the nearest hundredth, if necessary.

how many solutions does 10+5x/15=4 have

Answers

Answer:

3

Step-by-step explanation:

Standard form

1/3 x +6 = 0

Factorization

1/3 (x + 18) = 0

Solutions

x = -90/5 = 18

21x² - 2x + 1/2 =0

find the following quadratic equation by factorization method
PLESE SOMEONE HELP

Answers

Step-by-step explanation:

21x²-2x +1/2 = 0

x² - 2x ×21 + 1/2× 21 = 0

In this question take g to be 10 ms^-2
A particle of mass 0.8 kg is at rest on a rough horizontal plane. The coefficient of friction between the particle and the plane is 0.5. Find the least force required to pull the particle along the plane if the force is
(i) horizontal
(ii) at an angle of 30° to the plane.

Answers

(i) The least pull force if the force is horizontal is 4 newtons.

(ii) The least pull force if the force is at an angle of 30° to the plane is 4.619 newtons.

Determination of the least force required to pull a mass

By Newton's second law and definition of the maximum kinetic friction we derive an equation for the least force required to pull the particle along the plane (\(F\)), in newtons:

\(F = \frac{\mu_{s}\cdot m\cdot g}{\cos \theta} \) (1)

Where:

\(\mu_{s}\) - Coefficient of static friction, no unit.\(m\) - Mass of the particle, in kilograms. \(g\) - Gravitational acceleration, in meters per square second. \(\theta \) - Angle of the external force with respect to the plane, in degrees.

(i) If we know that \(\mu_{s} = 0.5\) \(m = 0.8\,kg\), \(g = 10\,\frac{m}{s^{2}} \) and \(\theta = 0^{\circ}\), then the pull force is:

\(F = \frac{(0.5)\cdot (0.8\,kg)\cdot \left(10\,\frac{m}{s^{2}} \right)}{\cos 0^{\circ}}\)

\(F = 4\,N\)

The least pull force if the force is horizontal is 4 newtons. \(\blacksquare\)

(ii) If we know that \(\mu_{s} = 0.5\) \(m = 0.8\,kg\), \(g = 10\,\frac{m}{s^{2}} \) and \(\theta = 30^{\circ}\), then the pull force is:

\(F = \frac{(0.5)\cdot (0.8\,kg)\cdot \left(10\,\frac{m}{s^{2}} \right)}{\cos 30^{\circ}}\)

\(F = 4.619\,N\)

The least pull force if the force is at an angle of 30° to the plane is 4.619 newtons. \(\blacksquare\)

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In this question take g to be 10 ms^-2A particle of mass 0.8 kg is at rest on a rough horizontal plane.

What percent of the front page is taken up by the
prom story, including the prom photograph?
A. 20%
B. 22%
C. 25%
D. 45%
E. 60%

What percent of the front page is taken up by theprom story, including the prom photograph?A. 20%B. 22%C.

Answers

The percent of the front page taken up by the prom story is 20%

Calculating the percent of the front page taken up by the prom story

From the question, we have the following parameters that can be used in our computation:

The front page


From the front page, we have

Area front page = 5 * 4

Area front page = 20

Also, we have

Prom = 2 * 2

Prom = 4

So, we have

Percentage = 4/20 * 100%

Evaluate

Percentage = 20%

Hence, the percent of the front page taken up by the prom story is 20%

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Can someone help !!
2. What is the probability that you select a Jack given that it is a Club?
P(Jack∣Club)=


3. What is the probability that you select a Club given that it is a Jack?
P(Club∣Jack)=


4. What is the probability that you select a card that is NOT a Jack given that it is NOT a Club?
P(NotJack∣NotClub)=


5. What is the probability that you select a card that is NOT a Club given that is it NOT a Jack?

Can someone help !! 2. What is the probability that you select a Jack given that it is a Club?P(JackClub)=3.

Answers

The probability that you select a Jack given that it is a Club P(Jack∣Club) is 1/13.

The probability that you select a Club given that it is a Jack is P(Club∣Jack) is 1/4.

The probability that you select a card that is NOT a Jack given that it is NOT a Club,P(NotJack∣NotClub) is 47/38

The probability that you select a card that is NOT a Club given that is it NOT a Jack is 38/47

The probability that you select a Jack given that it is a Club P(Jack|Club):

There are 4 Jacks in a deck (one for each suit), and since we are given that the selected card is a Club, we only need to consider the 13 cards in the Club suit.

So, the number of favorable outcomes is 1 (the Jack of Clubs), and the total number of possible outcomes is 13 (the number of cards in the Club suit)

P(Jack|Club) = 1 / 13

The probability that you select a Club given that it is a Jack

P(Club|Jack):

P(Club|Jack) = Number of favorable outcomes / Total number of possible outcomes

P(Club|Jack) = 1 / 4

The probability that you select a card that is not a Jack given that it is not a Club

P(NotJack|NotClub):

The number of cards that are not Jacks is 52 - 4 = 48 (since there are 4 Jacks in the deck), and the number of cards that are not Clubs is 52 - 13 = 39 (since there are 13 cards in the Club suit).

P(NotJack|NotClub) = Number of favorable outcomes / Total number of possible outcomes

P(NotJack|NotClub) = (48 - 1) / (39 - 1)

=47/38

P(NotClub|NotJack) = (39 - 1) / (48 - 1)

=38/47

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please help me with this problem

please help me with this problem

Answers

1. The unknown in the 'x- mean' column are 2 and -8

2. The unknown in the '(x-mean)²' square column is

25 and 106

What is Frequency table?

A frequency table is simply a “t-chart” or two-column table which outlines the various possible outcomes and the associated frequencies observed in a sample.

A mean in math is the average of a data set, found by adding all numbers together and then dividing the sum of the numbers by the number of numbers.

1. X - mean = 13 - 11 =2

X - mean = 3 -11 = -8

2. (X - mean)² = 5²

= 25

The total value of (x-mean)²

= 9+ 4+25+4+4+64

= 13 +25 + 8 +64

= 106

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Find an ordered pair (x, y) that is a solution to the equation.
3x-y=6

Answers

To find an ordered pair (x, y) that is a solution to the equation 3x - y = 6, we can choose any value of x and solve for y.

For example, if we let x = 2, then:

3x - y = 6
3(2) - y = 6
6 - y = 6
-y = 0
y = 0

So, when x = 2, y = 0, and the ordered pair (2, 0) is a solution to the equation 3x - y = 6.
The answer is 2,0 I hope that helps you
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