in the figure, the first number line goes with x \(\leq\)5
the second number line goes with x \(\geq\) 5
the third number line goes with x > 5
the fourth number line goes with x < 5
Two less than 3/2 of a number x is no more than 5/2 is shown as:
3/2 x- 2 \(\leq\) 5 1/2
3/2 x \(\leq\) 11/2 + 2
3/2 x \(\leq\) 15/2
3x \(\leq\) 15
x \(\leq\) 5
The sum of two times a number (x) and -2 is at least 8 is shown as :
2x+(-2) \(\geq\) 8
2x - 2 \(\geq\) 8
2x \(\geq\) 8+2
2x \(\geq\) 10
x \(\geq\) 5
Seven subtracted from 4 times a number (x) is more than 13 is shown as
4x -7 > 13
4x > 13+7
4x > 20
x > 20 ÷ 4
x > 5
Four added to 3 times a number (x) is less than 19 is shown as
3x + 4 < 19
3x < 19-4
3x < 15
x < 15 ÷ 3
x< 5
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7. Use the Unit Circle to find the exact value of the trig function,
sin(180°)
Graphing (y=x+6) (y=-2x-3)
Answer:
srry its black but thats how you would graph it
Step-by-step explanation:
Sara and her friends are knitting scarves for a school fundraiser.
• They estimate that they will have fixed expenses of $12.
In addition, they will spend $7 on yarn for each scarf.
Which graph shows the total expenses, E, for n scarves?
.
Based on the information, we can infer that graph B is the one that correctly expresses the expenses that Sara and her friends will have.
How to identify the graph that correctly expresses the information?To identify the graph that correctly expresses the information we must analyze the information. In this case we must take into account the fixed expenses that Sara and her friends will have, which is $7. This would be the starting point of the graph line.
On the other hand, all the values that represent an additional expense will mean an increase in this graph. So, we can infer that the correct chart is B because it starts at the value of $7.
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simplify √([2m5z6]/[ xy])
The simplified form of √([2m5z6]/[xy]) is (√2m√5z√6) / (√x√y).
To simplify the expression √([2m5z6]/[xy]), we can break it down step by step:
Simplify the numerator:
√(2m5z6) = √(2) * √(m) * √(5) * √(z) * √(6)
= √2m√5z√6
Simplify the denominator:
√(xy) = √(x) * √(y)
Combine the numerator and denominator:
√([2m5z6]/[xy]) = (√2m√5z√6) / (√x√y)
Thus, the simplified form of √([2m5z6]/[xy]) is (√2m√5z√6) / (√x√y).
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my father bought a robot for 670 2.50 and a toy car for 300 19.25 how much change did he get for his 1000.00
A.7.25 B.15.75cm C.27.75cm D.10.25
Answer:
Step-by-step explanation:
If it is supposed to be 672.50 and 319.25 then you can just go 1000 minus 672.50 which is 327.50 and then subtract 319.25 to get 8.25. But your answers show cm and none show the right answer. So, if it's rounding then choose A.
The perimeter of a rectangle is 360 centimetres. If the ratio of its length to its width is 11:4, find the dimensions of the rectangle.
Answer: Length 132cm, Breadth 48cm
Explanation:
Perimeter = 360cm
Let the length and breadth be x
ATQ
2(11x + 4x) = 360
22x + 8x = 360
30x = 360
x = 360/30
x = 12
Length = 11×12
= 132 cm
Breadth = 4×12
= 48cm
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Simplify: 5w^5-(-4w^5)
Answer:
9w^5
Step-by-step explanation:
If IK=JK, find mlJ
A. 72°
B. 82°
C. 122°
D. 134°
Answer:
D.134
Step-by-step explanation:
It is given that m ∠ AOB = 42 ∘ and m ∠ EOF = 66 ∘ . By the ___________, ∠ EOF ≅ ∠ BOC . Therefore, m ∠ BOC = 66 ∘ . By the ________ , m ∠ AOC = 108 ∘ , and by ________ the , m ∠ AOC + m ∠ COD = 180 ∘ . After application of the ___________, m ∠ COD = 72 ∘ .
The required appropriate properties to fit the black space is given as,
(a) Congruent angles
(b) Addition of angles
(c) straight angles
(d) Subtraction of angles.
Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.
It is given that m ∠ AOB = 42 ∘ and m ∠ EOF = 66 ∘ . By the definition of congruent angles, ∠ EOF ≅ ∠ BOC. Therefore, m ∠ BOC = 66 ∘ . In the addition, m ∠ AOC = 108 ∘ , and by definition of the straight angle, m ∠ AOC + m ∠ COD = 180 ∘ . After application of the subtraction of the angle, m ∠ COD = 72 ∘ .
Thus, the required appropriate properties to fit the black space is given as,
(a) Congruent angles
(b) Addition of angles
(c) straight angles
(d) Subtraction of angles.
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Answer:
It is given that m∠AOB = 42º and m∠EOF = 66º. By the vertical angles theorem, ∠EOF ≅ ∠BOC. By the angle addition postulate, m∠AOC = 108º, and by the linear pair theorem, m∠AOC + m∠COD = 108º. After the application of the subtraction property of equality, m∠ COD = 72º.
Step - by - step
first box: vertical angles theorem
second box: angle addition postulate
third box: linear pair theorem
fourth box: subtraction property of equality
What is 2 + 2 I'm in 11th grade and my teacher gave me this question?
Answer:
2+2=4
Step-by-step explanation:
I don't even know why this is a question
Answer:
2+2 is 4 ok tell ur thecher it is four
Step-by-step explanation: lol
if the price of gold decreases at a monthly rate of 2.1% by what percent does it decrease in a year?
We have that each month, the price of gold decreases 2.1%, then, if in a year there are 12 months, we have:
\(12\cdot(2.1)=25.2\)thus, in a year, the price of gold decreases 25.2%
1) Given h(x)=x-5
a) Determine h^2
b)determine h^3
Answer:
A) x^2-10x+25 B)X^3-15x^2+75x-125
Step-by-step explanation:
H^2=(x-5)(x-5)=x^2-10x+25
H^3=(x-5)(x-5)(x-5)=X^3-15x^2+75x-125
Angles and Parallel Lines
Answer:
a = 6
b = 25
Step-by-step explanation:
As alternative angles in a parallel line are equal to each other,
5a = 3a + 12
So, now we can find the value of a by making "a" the subject.
5a - 3a = 12
2a = 12
Divide both sides by 2.
a = 6°
And now let us find the value of b.
We know that interior angles in a triangle are added up to 180°.
So,
2b + 4b + 3a + 12 = 180
We can replace a with 6 and then we can make "b" the subject to find the value of b.
Let us solve it now.
2b + 4b + 3 × 6 + 12 = 180
6b + 18 + 12 = 180
6b + 30 = 180
6b = 180 - 30
6b = 150
Divide both sides by 6.
b = 25°
A line segment has the endpoints V(7, 2) and W(3, 10). Find the coordinates of its midpoint M.
The coordinates of the midpoint M of the line segment VW are M = (5, 6)
In this question,
We have been given a line segment having endpoints V(7, 2) and W(3, 10)
We need to find the coordinates of the midpoint M of the line segment VW.
We know that the midpoint of points (x1, y1) and (x2, y2) is
M = (x1 + x2 / 2, y1 + y2 / 2)
Using midpoint formula,
M = ((7 + 3) / 2, (2 + 10) / 2)
M = (10/2, 12/2)
M = (5, 6)
Therefore, the coordinates of the midpoint M of the line segment VW are M = (5, 6)
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which of these statements is true for 89.033
Molly's scout troop sold 148 boxes of cookies last month and 165 boxes this month. Find the percent of increase, rounded to the nearest tenth of a percent.
The percent of the increase, rounded to the nearest tenth of a percent, concerning the sales of boxes of cookies that Molly sold last month and this month, is 11.5%.
How is the percentage increase determined?The percentage increase can be determined by finding the difference or the amount of increase in sales.
This difference is divided by the previous month's sales and multiplied by 100.
The total number of boxes of cookies Molly's Scout Troop sold last month = 148
The total number sold this month = 165
The increase = 17 (165 - 148)
Percentage increase = 11.5% (17 ÷ 148 x 100)
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help pls!!!
A ball is launched upwards from a height of 4 feet. The ball’s height as a function of time, in seconds, is modeled by the function h(t)= -16t^2+80t+4. What is the time interval in which the ball has a height greater than 100 feet?
This is between 2 and 3 seconds, excluding both endpoints.
========================================================
Explanation:
t = elapsed time in seconds
h(t) = height of the ball at time t
Replace h(t) with 100. Then get everything to one side.
\(h(t)= -16t^2+80t+4\\\\100= -16t^2+80t+4\\\\0 = -16t^2+80t+4-100\\\\0= -16t^2+80t-96\\\\-16t^2+80t-96 = 0\)
Next, we'll use the quadratic formula to isolate t.
Plug in a = -16, b = 80, c = -96 which are the coefficients of the last equation mentioned above.
\(t = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\t = \frac{-80\pm\sqrt{(80)^2-4(-16)(-96)}}{2(-16)}\\\\t = \frac{-80\pm\sqrt{256}}{-32}\\\\t = \frac{-80\pm16}{-32}\\\\t = \frac{-80+16}{-32} \ \text{ or } \ t = \frac{-80-16}{-32}\\\\t = \frac{-64}{-32} \ \text{ or } \ t = \frac{-96}{-32}\\\\t = 2 \ \text{ or } \ t = 3\\\\\)
Therefore, the ball's height is greater than 100 ft in the air for the interval \(2 < t < 3\)
This is between 2 and 3 seconds, excluding both endpoints.
------------------
Check:
Let's plug in t = 2 to find that...
\(h(t)= -16t^2+80t+4\\\\h(2)= -16(2)^2+80(2)+4\\\\h(2)= -16(4)+80(2)+4\\\\h(2)= -64+160+4\\\\h(2)= 100\\\\\)
You should find that h(3) = 100 as well. I'll let you do those steps.
Since h(2) = 100 and h(3) = 100, this confirms the two solutions we found earlier.
A dog is starting a diet to get in better shape. The
dog starts at 89.5 pounds and loses 0.5 pounds
each week for a certain number of weeks. Halfway
through the diet, the dog weighs 80 pounds. How
many weeks has the dog been dieting for?
Answer:
18.5 days
Step-by-step explanation:
Count by two's on your fingers until you have nine fingers up, and that equals 9 x 2 = 18, plus that .5 eqauls 18.5 days.
The dog has been dieting for 19 weeks.
What is unitary method?
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
According to the given problem,
Starting weight of the dog = 89.5 pounds
Halfway weight of the dog = 80 pounds
Weight the dog loses per week = 0.5 pounds
Weight loss = (89.5 - 80) pounds
= 9.5 pounds
If the dog loses 0.5 pounds in 1 week,
Then the dog will lose 9.5 pounds in (9.5 × 2) weeks
⇒ The dog will lose 9.5 pounds in 19 weeks.
Hence, we can conclude that the dog has week dieting for 19 weeks and lost 9.5 pounds.
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Determine the equation of the circle with center (0, -2) containing the point
(√12,-5).
Answer:
i think its
x^2 + (y + 2)^2 = 21.
Step-by-step explanation:
A. 1/3
B. 5/13
C. 4/5
D. 12/13
Answer:
5/13
Step-by-step explanation:
OM is 5 and OL is 13 use Pythagoreans theorem
is this statistical, what is the total number of eggs in dozen?
14 less than 6 times a number
Step-by-step explanation:
14 < 6×?
6×3=18
therefore anything above 3 multiplied by 6 would be greater in value than 14
Find the value of cos
V
V rounded to the nearest hundredth, if necessary.
Answer:
image
Step-by-step explanation:
image
how many solutions does 10+5x/15=4 have
Answer:
3
Step-by-step explanation:
Standard form
1/3 x +6 = 0
Factorization
1/3 (x + 18) = 0
Solutions
x = -90/5 = 18
21x² - 2x + 1/2 =0
find the following quadratic equation by factorization method
PLESE SOMEONE HELP
Step-by-step explanation:
21x²-2x +1/2 = 0
x² - 2x ×21 + 1/2× 21 = 0
In this question take g to be 10 ms^-2
A particle of mass 0.8 kg is at rest on a rough horizontal plane. The coefficient of friction between the particle and the plane is 0.5. Find the least force required to pull the particle along the plane if the force is
(i) horizontal
(ii) at an angle of 30° to the plane.
(i) The least pull force if the force is horizontal is 4 newtons.
(ii) The least pull force if the force is at an angle of 30° to the plane is 4.619 newtons.
Determination of the least force required to pull a mass
By Newton's second law and definition of the maximum kinetic friction we derive an equation for the least force required to pull the particle along the plane (\(F\)), in newtons:
\(F = \frac{\mu_{s}\cdot m\cdot g}{\cos \theta} \) (1)
Where:
\(\mu_{s}\) - Coefficient of static friction, no unit.\(m\) - Mass of the particle, in kilograms. \(g\) - Gravitational acceleration, in meters per square second. \(\theta \) - Angle of the external force with respect to the plane, in degrees.(i) If we know that \(\mu_{s} = 0.5\) \(m = 0.8\,kg\), \(g = 10\,\frac{m}{s^{2}} \) and \(\theta = 0^{\circ}\), then the pull force is:
\(F = \frac{(0.5)\cdot (0.8\,kg)\cdot \left(10\,\frac{m}{s^{2}} \right)}{\cos 0^{\circ}}\)
\(F = 4\,N\)
The least pull force if the force is horizontal is 4 newtons. \(\blacksquare\)
(ii) If we know that \(\mu_{s} = 0.5\) \(m = 0.8\,kg\), \(g = 10\,\frac{m}{s^{2}} \) and \(\theta = 30^{\circ}\), then the pull force is:
\(F = \frac{(0.5)\cdot (0.8\,kg)\cdot \left(10\,\frac{m}{s^{2}} \right)}{\cos 30^{\circ}}\)
\(F = 4.619\,N\)
The least pull force if the force is at an angle of 30° to the plane is 4.619 newtons. \(\blacksquare\)
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What percent of the front page is taken up by the
prom story, including the prom photograph?
A. 20%
B. 22%
C. 25%
D. 45%
E. 60%
The percent of the front page taken up by the prom story is 20%
Calculating the percent of the front page taken up by the prom storyFrom the question, we have the following parameters that can be used in our computation:
The front page
From the front page, we have
Area front page = 5 * 4
Area front page = 20
Also, we have
Prom = 2 * 2
Prom = 4
So, we have
Percentage = 4/20 * 100%
Evaluate
Percentage = 20%
Hence, the percent of the front page taken up by the prom story is 20%
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Can someone help !!
2. What is the probability that you select a Jack given that it is a Club?
P(Jack∣Club)=
3. What is the probability that you select a Club given that it is a Jack?
P(Club∣Jack)=
4. What is the probability that you select a card that is NOT a Jack given that it is NOT a Club?
P(NotJack∣NotClub)=
5. What is the probability that you select a card that is NOT a Club given that is it NOT a Jack?
The probability that you select a Jack given that it is a Club P(Jack∣Club) is 1/13.
The probability that you select a Club given that it is a Jack is P(Club∣Jack) is 1/4.
The probability that you select a card that is NOT a Jack given that it is NOT a Club,P(NotJack∣NotClub) is 47/38
The probability that you select a card that is NOT a Club given that is it NOT a Jack is 38/47
The probability that you select a Jack given that it is a Club P(Jack|Club):
There are 4 Jacks in a deck (one for each suit), and since we are given that the selected card is a Club, we only need to consider the 13 cards in the Club suit.
So, the number of favorable outcomes is 1 (the Jack of Clubs), and the total number of possible outcomes is 13 (the number of cards in the Club suit)
P(Jack|Club) = 1 / 13
The probability that you select a Club given that it is a Jack
P(Club|Jack):
P(Club|Jack) = Number of favorable outcomes / Total number of possible outcomes
P(Club|Jack) = 1 / 4
The probability that you select a card that is not a Jack given that it is not a Club
P(NotJack|NotClub):
The number of cards that are not Jacks is 52 - 4 = 48 (since there are 4 Jacks in the deck), and the number of cards that are not Clubs is 52 - 13 = 39 (since there are 13 cards in the Club suit).
P(NotJack|NotClub) = Number of favorable outcomes / Total number of possible outcomes
P(NotJack|NotClub) = (48 - 1) / (39 - 1)
=47/38
P(NotClub|NotJack) = (39 - 1) / (48 - 1)
=38/47
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please help me with this problem
1. The unknown in the 'x- mean' column are 2 and -8
2. The unknown in the '(x-mean)²' square column is
25 and 106
What is Frequency table?A frequency table is simply a “t-chart” or two-column table which outlines the various possible outcomes and the associated frequencies observed in a sample.
A mean in math is the average of a data set, found by adding all numbers together and then dividing the sum of the numbers by the number of numbers.
1. X - mean = 13 - 11 =2
X - mean = 3 -11 = -8
2. (X - mean)² = 5²
= 25
The total value of (x-mean)²
= 9+ 4+25+4+4+64
= 13 +25 + 8 +64
= 106
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Find an ordered pair (x, y) that is a solution to the equation.
3x-y=6