Correct structure for bromoacetone or 1‑bromopropanone.
Br
|
C - C=O
|
C
Let's discuss it further below.
To draw the correct structure for 1-bromopropanone (bromoacetone), follow these steps:
1. Identify the main components: 1-bromopropanone contains three carbon atoms (propanone), a bromine atom (bromo), and a ketone functional group (double bond between the second carbon atom and an oxygen atom).
2. Draw the carbon backbone: Arrange the three carbon atoms in a linear chain, like this:
C - C - C
3. Add the ketone functional group: Connect the second carbon atom to an oxygen atom with a double bond, like this:
C - C=O
|
C
4. Attach the bromine atom: Since it's 1-bromopropanone, the bromine atom is attached to the first carbon atom in the chain, like this:
Br
|
C - C=O
|
C
Now you have drawn the correct structure for 1-bromopropanone (bromoacetone).
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what is the pH of a solution with [H+] = 1.25 x 10^-10M?
Answer:
9.90
Explanation:
Given [H+] = 1.25 x 10^-10 M, we can calculate the pH using the formula:
pH = -log10([H+])
pH = -log10(1.25 x 10^-10)
Using logarithmic properties:
pH = -log10(1.25) - log10(10^-10)
Since log10(10^-10) is equal to -10:
pH = -log10(1.25) - (-10)
pH = -log10(1.25) + 10
Now, evaluating the logarithm using a calculator:
pH = -0.0969 + 10
pH = 9.9031
Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately 9.9031. Rounding it to two decimal places, the pH is approximately 9.90.
In certain fireworks, potassium nitrate breaks down into potassium oxide, nitrogen, and oxygen. This is an example of a
The opposite process is a synthesis reaction, and this reaction is an illustration of a decomposition reaction, especially a combustion reaction.
In some fireworks, does potassium nitrate produce potassium oxide, nitrogen, and oxygen?Potassium nitrate decomposes into potassium oxide, nitrogen, and oxygen in some fireworks. This is an illustration of an MBUSSEMENT Response. A SYNTHESIS REACTION is the opposite procedure.
Does heating cause potassium nitrate to break down into potassium nitrite and oxygen?Decomposition reactions occur when complex chemical entities disintegrate into simpler ones. In this reaction, potassium nitrate splits into potassium nitrite and oxygen, requiring heat energy.
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If you know about crystals can you tell me if this is real or fake because I purchased this item and don’t know
why are so many products made from plastic ?
Explanation:
Plastic takes time to degrade which means it has great longevity. Plastic does not break as easily as glass or other materials. It lasts long and offers great service. Plastic storage containers offer greater flexibility than any other packaging materials.
What do you understand by the terms radial node and nodal plane, as applied to AO wavefunctions? Illustrate your answer using the 2s and 2p AOs. Explain why radial nodes arise from the radial part of the wavefunction, whereas nodal planes arise from the angular part of the wavefunction
In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.
A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.
On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).
Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.
On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.
In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.
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Please help ASAP 100 points please I’ll mark you as brainlister
What is the splitting of the signal in the IH NMR spectrum for the methyl protons of I -bromo-2- methylpropane? a. singlet b. doublet c. triplet d. Nonet
The splitting of the signal in the IH NMR spectrum for the methyl protons of 1-bromo-2-methylpropane is a triplet. (C)
In proton NMR, the number of peaks and their relative intensity provides information about the number and types of hydrogen atoms in a molecule.
The splitting of the signal, or the number of peaks, is caused by the interaction between neighboring hydrogen atoms.
For 1-bromo-2-methylpropane, the methyl protons are attached to a carbon atom that is adjacent to two other hydrogen atoms, which causes the signal to split into three peaks of equal intensity, resulting in a triplet.
This splitting pattern is known as a first-order splitting pattern, and the intensity of the peaks is determined by the number of neighboring hydrogen atoms.
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A company that is concerned about the environment wants to encourage the use of their fuel cell cars, so they are putting
together information to help sell the cars. They want to be sure their material is accurate. Which piece of information is
true about fuel cell cars?
O Fuel cell cars are cheaper to buy. Fuel cell cars reduce use of non-renewable fossil fuels
Fuel cell cars are more powerful than gasoline-powered vehicles.
Fuel cell cars allow for the safe storage of hydrogen gas at filling stations.
Answer:
B. Fuel cell cars reduce use of non-renewable fossil fuels
Explanation:
What is the maximum work that could be obtained from 5.35 g of zinc metal in the following reaction at 25°C?
Zn(s) + Cu2+(aq) ---> Zn2+(aq) + Cu(s)
The maximum work that could be obtained from 5.35 g of zinc metal is calculated as - 17. 3903 kJ
Zn(s) + Cu²⁺(aq) ---> Zn²⁺ (aq) + Cu(s)
Δ G ° = Δ G° product - Δ G° reactant
= - 147 - 65.52
= - 212.52 kJ / mole
molar mass of zinc = 65.38 g/ mole
mole of Zn = \(\frac{gram of Zn}{molar mass}\)
= 5.35/ 65.38
W = - 212.52 kJ/ mole × 5.35 / 65.38 mole
= - 17. 3903 kJ
How much is Delta G?To put it another way, "G" is the change in a system's free energy as it transitions from one initial state (all reactants) to another, final state (all products). The maximum amount of usable energy that can be released (or absorbed) during the transition from the initial to the final state is shown by this value.
What is as molar mass?"Mass per mole" can be used to describe molar mass. To put it another way, a substance's molar mass is the total mass of all its atoms in one mole's worth. It is quantified in grams per mole.
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Write the (a) oxidation and (b) reduction half reactions. Then calculate the (c) standard cell potential for the following electrochemical cells.
1. Ag+(aq) + Fe(aq) --> Ag3+(ag) + Fe3+
2. Br-(ag) + Hg22+(ag) --> Br2(l) + Hg (l)
3. Be(s) + Au3+(aq) --> Be2+(ag) + Au+(ag)
4. Ac and Bi
5. Ni and Cd
6. Ce and Cr
The answers to A. oxidation, B. reduction, and C. standard cell potential (E°) are given below:
(a) The oxidation half-reaction involves the loss of electrons.
1. Ag" (aq) \(\rightarrow\) Ag (s) + e-
2. Br (l) \(\rightarrow\) Br- (aq) + e-
3. Be(aq) \(\rightarrow\) Be(s) + 2e-
4. Ac \(\rightarrow\) Ac3+ + 3e-
5. Ni \(\rightarrow\) Ni2+ + 2e-
6. Ce \(\rightarrow\) Ce4+ + 2e-
(b) The reduction half-reaction involves the gain of electrons.
1. Fe3+ (aq) + 3e- \(\rightarrow\) Fe (s)
2. Hg2+ (aq) + 2e- \(\rightarrow\) Hg (l)
3. Au3+ (aq) + 3e- \(\rightarrow\) Au (s)
4. Bi3+ (aq) + 3e- \(\rightarrow\) Bi (s)
5. Cd2+ (aq) + 2e- \(\rightarrow\) Cd (s)
6. Cr3+ (aq) + 3e- \(\rightarrow\) Cr (s)
(c) To calculate the standard cell potential (E°) for the electrochemical cells, we subtract the reduction half-reaction potential from the oxidation half-reaction potential.
The values for E° can be obtained from standard reduction potential tables.
1. E° = E°(Ag+/Ag) - E°(Fe3+/Fe)
2. E° = E°(Br2/Br-) - E°(Hg2+/Hg)
3. E° = E°(Be2+/Be) - E°(Au3+/Au)
4. E° = E°(Ac3+/Ac) - E°(Bi3+/Bi)
5. E° = E°(Ni2+/Ni) - E°(Cd2+/Cd)
6. E° = E°(Ce4+/Ce) - E°(Cr3+/Cr)
To calculate the specific values, you need to refer to a standard reduction potential table and subtract the reduction half-reaction potential from the oxidation half-reaction potential for the given pairs of half-reactions.
The standard reduction potentials can be found in various chemistry textbooks or online resources.
Therefore. please consult a standard reduction potential table to obtain the specific reduction potentials for the respective species involved in the reactions and perform the necessary subtractions to calculate the standard cell potentials for each electrochemical cell.
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where are elements heavier than iron primarily produced?
Elements heavier than iron are primarily produced in supernova explosions.
During a supernova, the intense pressure and temperature cause fusion reactions that can create elements heavier than iron.
Additionally, elements can also be created through neutron capture, where a nucleus absorbs neutrons and undergoes beta decay, producing a heavier element.
This process, known as the r-process, occurs during supernovae and other high-energy events such as neutron star mergers.
These heavy elements are then dispersed into the interstellar medium and can become part of new stars and planets.
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The pH of a 0. 20 M solution of C2H5COONa (Ka C2H5COOH = 1. 34 x 10¯5) is
Answer: The pH is 9.09.
Explanation:
This question involves the hydrolysis of a salt into a weak acid and strong base.
Fastest SolutionThe fastest solution is found by using the equation:
\(\text{pH} = \frac12 \ \text{pK}_w + \frac12 \ \text{pK}_a + \frac12 \log C\)
where C represents the concentration of the solution.
We have:
Ka = 1.34 x 10^-5, so pKa = -log(1.34 x 10^-5) = 4.873
Kw = 1.0 x 10^-14, so pKw = -log(1.0 x 10^-14) = 14.00
C = 0.20, so log(C) = log(0.20) = -0.70
Then,
\(\text{pH} = \frac12 (4.873) + \frac12 (14.00) + \frac12 (-0.70) = 9.09\)
AP Chemistry Level SolutionA solution that uses only fundamental chemistry techniques can be found by considering the chemical reactions involved.
The salt \(\text{C}_2\text{H}_5\text{COONa}\) will completely dissolve in solution into its ions:
\(\text{C}_2\text{H}_5\text{COONa} \text{ (aq)} \rightarrow \text{C}_2\text{H}_5\text{COO}^- \text{ (aq)} + \text{Na}^+ \text{ (aq)}\)
This shows that \([\text{C}_2\text{H}_5\text{COO}^-] = [\text{C}_2\text{H}_5\text{COONa}] = 0.20 \text{ M}\).
When water is added, an acid-base reaction occurs:
\(\text{C}_2\text{H}_5\text{COO}^- \text{ (aq)} + \text{H}_2\text{O} \text{ (l)} \rightleftharpoons \text{C}_2\text{H}_5\text{COOH} \text{ (aq)} + \text{OH}^- \text{ (aq)}\)
Using a RICE (Reaction-Initial-Change-Equilibrium) table, we can write the following analysis:
0.20 N/A 0 0 (initial conc.)
- x N/A + x + x (change)
-------------------------------------------------------------------------
(0.20 - x) N/A x x (equilibrium)
Then, we can write the forward base-reaction constant:
\(\text{K}_b = \frac{[\text{C}_2\text{H}_5\text{COOH}][\text{OH}^-]}{[\text{C}_2\text{H}_5\text{COO}^-]} = \frac{(x)(x)}{0.20-x} = \frac{x^2}{0.20-x}\)
We have \(\text{K}_a = 1.34 \times 10^{-5}\) and we also know that \(\text{K}_w = \text{K}_a \times \text{K}_b\). It follows that:
\(\text{K}_b = \frac{\text{K}_w}{\text{K}_a} = \frac{1.0 \times 10^{-14}}{1.34 \times 10^{-5}} = 7.46 \times 10^{-10}\)
Since Kb is very small, we may assume that \((0.20 - x) \approx 0.20\). Then,
\(7.46 \times 10^{-10} = \frac{x^2}{0.20} \quad \rightarrow \quad x \approx \sqrt{0.20(7.46 \times 10^{-10})} = 1.22 \times 10^{-5}\)
Then,
\([\text{OH}^-] = x = 1.22 \times 10^{-5}\)
\(\text{pOH} = -\log(1.22 \times 10^{-5}) = 4.91\)
Finally,
\(\text{pH} = \text{pK}_w - \text{pH} = 14.00 - 4.91 = 9.09\)
Question 1
Dull, brittle and non conductive best describes which of the following:
Mg
OPd
O Fe
S
< Previous
1 pts
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A nonmetal is a chemical element that doesn't have a lot of metallic characteristics; examples include colourless gases (like hydrogen) and glossy, solids with high melting points (like boron).
Dull, brittle and non conductive best describes which of the following:
MgPdFeS"S - Sulfur"
A Non-metallic Chemical element sulfur has the letter S and atomic number 16. It is multivalent, nonmetallic, and plentiful. Sulfur atoms normally combine to create cyclic octatomic molecules, which have the chemical formula S8. At room temperature, elemental sulfur is a crystalline solid that is brilliant yellow.
When compared to metals, nonmetals' electrons exhibit different behaviour. With a few exceptions, nonmetals don't have any moving parts, which makes them often poor heat- and electricity-conductors and brittle or crumbly when solid. Metals are good conductors since their electrons are typically free to move about, and the majority of them are also simple to flatten into sheets and draw into wires. Nonmetal atoms have varying degrees of electro negativeness, which makes them more likely to draw electrons in chemical processes and produce acidic compounds.
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1. When hydrogen burns, water vapor is produced according to the unbalanced
equation H2(g) + O2(g) H2O(g). If 12 L of oxygen are consumed, what
volume of water vapor is produced? (10 points)
The volume of water vapor produced is 19.6 L. We can use this stoichiometry to solve the problem
The balanced chemical equation for the combustion of hydrogen gas with oxygen gas to form water vapor is:
2H₂(g) + O₂(g) → 2H₂O(g)
This means that for every 2 moles of hydrogen gas reacted, 1 mole of oxygen gas is required and 2 moles of water vapor are produced.
Since we know that 12 L of oxygen gas are consumed, we can calculate the number of moles of oxygen gas as follows:
n(O2) = V(P/T) / R = 12 L(1 atm / 273 K) / (0.0821 L·atm/mol·K) = 0.44 mol
According to the balanced equation, this amount of oxygen gas will react with 2/1 x 0.44 mol = 0.88 mol of hydrogen gas, producing 2/2 x 0.88 mol = 0.88 mol of water vapor.
Finally, we can convert the number of moles of water vapor to volume using the ideal gas law:
V(H₂O) = n(H₂O)RT/P = 0.88 mol x 0.0821 L·atm/mol·K x 273 K / 1 atm = 19.6 L
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How are crystals formed?
Answer:
Crystals form in nature when molecules gather to stabilize when liquid starts to cool and harden. This process is called crystallization and can happen when magma hardens or when water evaporates from a natural mixture too. Many crystals start small but as more atoms join and create a uniform and repetitive pattern, the crystal grows. This is how crystals are formed in nature.
Explanation:
彡jessbragoliThe energy of motion is known as potential energy.
Question 1 options:
True
False
Answer:
False
Explanation:
This is because potential energy is energy that it not used yet.
select the correct answer. given: 2al 6hcl → 2alcl3 3h2 if the chemical reaction produces 129 grams of alcl3, how many grams of h2 are also produced? a. 1.22 b. 2.92 c. 3.02 d. 3.65
The grams of H₂ produced, if the chemical reaction produces 129 grams of AlCl₃ are 2.92 grams. (Option b)
To determine the grams of H₂ produced, we need to use the balanced equation and the molar ratios between AlCl₃ and H₂.
From the balanced equation:
2 moles of AlCl₃ react with 3 moles of H₂
To find the moles of AlCl₃ produced:
129 grams AlCl₃ x (1 mole AlCl₃ / molar mass AlCl₃) = moles of AlCl₃
Now, using the molar ratios, we can determine the moles of H₂ produced:
moles of AlCl₃ x (3 moles H₂ / 2 moles AlCl₃) = moles of H₂
Finally, we can convert the moles of H₂ back to grams:
moles of H₂ x (molar mass H₂ / 1 mole H₂) = grams of H₂
Let's calculate it:
Given:
Mass of AlCl₃ produced = 129 grams
Molar mass of AlCl₃:
Al: 26.98 g/mol
Cl: 35.45 g/mol x 3 = 106.35 g/mol
Total molar mass = 26.98 g/mol + 106.35 g/mol = 133.33 g/mol
Calculations:
moles of AlCl₃ = 129 g AlCl₃ / 133.33 g/mol = 0.9676 moles AlCl₃
moles of H₂ = 0.9676 moles AlCl₃ x (3 moles H₂ / 2 moles AlCl₃) = 1.4514 moles H₂
grams of H₂ = 1.4514 moles H₂ x (2.02 g/mol / 1 mole H₂) = 2.93 grams of H₂
Therefore, the correct answer is b. 2.92 grams.
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Sonya reads the element riddle below. I am shiny. I form 1 ions. There’s more! I am the most reactive metal in Period 4. Who am I? Which element is the answer to the riddle? krypton potassium sodium bromine.
Answer:
The answer should be krypton Im doing the test rn.
Explanation:
The most reactive element in period 4 which is shiny and forms a +1 cation is potassium.
The periodic table is defined as an arrangement of elements in groups and periods. The elements in the same group have similar properties while the elements in the same period has the same number of shells.
The element in period 4 that is shiny, forms a cation of +1 charge and is the most reactive in period 4 is the element potassium.
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need help with this
26 option b
27 option a
28 option c
29 option d
30 option e
(6): Calculate the maximum amount of work that can be obtained from the galvanic cells at standard conditions listed below. (Use the table for standard reduction potentials.)
(a) Cr2O72− + 14 H+ + 6 e− → 2 Cr3+ + 7 H2O
H2O2 + 2 H+ + 2 e− → 2 H2O
____ kJ
(b) 2 H+ + 2 e− → H2
Al3+ + 3e− → Al
____ kJ
Answer:
(a) The maximum amount of work that can be obtained from the first galvanic cell is -510.5kJ.
(b) The maximum amount of work that can be obtained from the second galvanic cell is -318.5kJ.
Explanation:
In this question, we need to use the standard reduction potentials to calculate the standard cell potential of each galvanic cell, and then use the formula AG = -nFE to calculate the maximum amount of work that can be obtained from each galvanic cell.
Solve the Problem
(a) Cr₂02 +14H++6e → 2Cr³++7H₂O
The standard reduction potential of Cr2O2 is 1.33V, and the standard reduction potential of His 0V. Therefore, the standard cell potential of this galvanic cell is:
E cell = reduction (Cr202) - E reduction (H+) = 1.33V
The number of electrons transferred in this reaction is 6, so the maximum amount of work that can be obtained from this galvanic cell is:
AG= -nFE = -696485C/mol 1.33J/C = −51
(b) 2H+ + 2e→ H₂
The standard reduction potential of H+ is 0V, and the standard reduction potential of Al3+ is -1.66V.
Therefore, the standard cell potential of this galvanic cell is:
EO =E0 cell reduction (H+)-E0 reduction (A13+) = 0V – (−1
The number of electrons transferred in this reaction is 2, so the maximum amount of work that can be obtained from this galvanic cell is:
AG-nFE-2 96485C/mol 1.66J/C-31
Draw the Conclusion
(a) The maximum amount of work that can be obtained from the first galvanic cell is -510.5kJ.
(b) The maximum amount of work that can be obtained from the second galvanic cell is -318.5kJ.
how do exothermic and endothermic differ
Answer:
Explanation:
exothermic reactions involve release of heat whereas endothermic reaction involve absorption of heat.
Correctly order the steps necessary to balance a chemical equation. Start with the first step at the top of the list.
A skeletal set of equations equilibrium the atoms, Make the adjustments necessary to make the coefficients the lowest whole-number coefficients possible. Make one last verification to ensure the solution is balanced.
What does a chemical reaction equation mean?A chemical equation reaction equation demonstrates the mole connections of the reactants and the products. Chemical reaction equations offer the reactants and products. The quantity of energy used in the process is frequently stated. Reaction molar ratio refers to the study of the quantitative side of chemical processes.
Which four types of chemical equations are there?Direct conjunction, analysis reactions, from another, and double dispersion are the four primary types atomic reactions.
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In the dessert presentation, what should be taken into consideration? Give one (1) and discuss briefly.
In dessert presentation one important aspect to consider is the visual appeal and aesthetics of the dessert.
The presentation of a dessert plays a crucial role in creating an enticing and memorable dining experience. The appearance of the dessert can greatly impact the perception and anticipation of its taste and quality. Therefore, attention should be given to factors such as color, texture, arrangement, and garnishments. For instance, color coordination is important to create an appealing visual impact. Harmonious color combinations can make the dessert more visually appealing. Additionally, textures should be varied to add interest and dimension to the presentation, such as incorporating crunchy elements with smooth components. Garnishments and decorations should be carefully chosen to complement the flavors and add a touch of elegance or playfulness, depending on the style and theme of the dessert. They can include edible flowers, chocolate shavings, fruit slices, or artistic drizzles of sauce. By considering the visual appeal in dessert presentation, it enhances the overall dining experience and creates an irresistible desire to indulge in the dessert.
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write a word equation for these (PLEASE!)
a) iron + oxygen ----> iron oxide
b) silver + oxygen -----> silver oxide
c) tin + chlorine -----> Tin chloride
What is a word equation?We know that a word equation is the kind of equation that does not show us the symbols of the compounds or the elements that are taking part in the reaction.
In this case we have a number of reactions that have taken place here and we have been asked to show the reactants and the products as word equations. The word equations must show the reactants and the products of the reaction here.
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Americium-241 will undergo nuclear decay to become Thallium-205. How many times does it need to undergo each time of radiation to achieve this?
The number of times that it needs to decay is nine times.
What is nuclear decay?
The term nuclear decay has to do with the situation in which a radioactive nucleus is disintegrated in order to form daughter nuclei. We know that the daughter nuclei that is formed depends on the kind of decay that has taken place.
Now we know that the decay that is undergone by the the Americium-241 is the alpha decay in which the mass number is reduced by 4. The implication of this is that from Americium-241 to Thallium-205 we have a decrease in mass of 36 units which means that there have been nine alpha decays.
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The reaction of an acid with a base produces a salt and another product. what is the identity of the other product?
An acid base reaction always produces salt and water.
In neutralization reaction, an acid and a base react together to produce salt and water.
In this chemical reaction hydrogen ions (H+ ions) come form an acid while hydroxide ions (OH- ions) are released by a base which combine together to form water.
For example, let's take the reaction between sodium hydroxide and hydrochloric acid.
NaOH + HCl -------> NaCl + H2O
the above reaction produces sodium chloride salt and water.
Overall, it is a neutral reaction because no excess ions are left behind in the solution.
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why is tin a metal and carbon is a nonmetal even though they are in the same family in terms of atomic structure
Answer:
Tin and carbon are both in the same family on the periodic table because they have similar atomic structures. Both are in group 14 of the periodic table, which means they have four valence electrons in their outermost energy level. However, they are classified as different types of elements because of their different properties.
Tin is a metal because it is a good conductor of heat and electricity, has a shiny, metallic appearance, and is malleable and ductile, meaning it can be easily shaped and molded. Carbon, on the other hand, is a nonmetal because it is a poor conductor of heat and electricity, is not shiny, and is not malleable or ductile.
One of the main factors that determine whether an element is a metal or a nonmetal is its ability to conduct heat and electricity. Metals are generally good conductors, while nonmetals are generally poor conductors. The position of an element on the periodic table can give some indication of its conductive properties, but it is not the only factor.
Suppose you carry out a titration involving 3.00 molar HCl and an unknown concentration of KOH. To bring the reaction to its end point, you add 35.3 milliliters of HCl to 105.0 milliliters of KOH. What is the concentration of the KOH solution?
Answer: The concentration of the KOH solution is 1.01 M
Explanation:
According to neutralization law:
\(n_1M_1V_1=n_2M_2V_2\)
where,
\(n_1\) = basicity of \(HCl\) = 1
\(n_2\) = acidity of KOH = 1
\(M_1\) = concentration of HCl = 3.00 M
\(M_2\) = concentration of KOH = ?
\(V_1\) = volume of HCl = 35.3 ml
\(V_2\) = volume of KOH = 105.0 ml
Putting the values we get:
\(1\times 3.00\times 35.3=1\times M_2\times 105.0\)
\(M_2=1.01\)
Thus the concentration of the KOH solution is 1.01 M
Calculate the mass percentage composition of nitrogen in acetaminophen, C8H9NO2
The mass percent composition of nitrogen in acetaminophen is 9.26 %.
The mass percent composition of an element is the percentage of the ratio of the molar mass of that element to the molar mass of the entire compound. Acetaminophen represented as C8H9NO2 is a drug that is used as a pain reliever.
First, we will calculate the molar mass of this compound. For this, we should know the mass of each element present in the compound.
mass of C = 12, mass of H = 1, mas of N = 14, mass of O = 16.
Now, we will calculate the molar mass of acetaminophen
= 12*8+ 1*9+14*1+16*2
= 151 g
Now, we have to calculate the mass percent composition of Nitrogen.
The molar mass of nitrogen = 14g
The molar mass of the entire compound = 151 grams.
Mass percent composition of N = (mm of N ÷ mm of C8H9NO2) ×100
= (14/151) × 100 = 0.0926 × 100
= 9.26 %
Therefore, the mass percent composition of nitrogen in acetaminophen (C8H9N02) is 9.26%.
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the hybridization of the nitrogen atom in the cation nh2 is: quizlet
the hybridization of the nitrogen atom in NH2 is sp2.
The hybridization of the nitrogen atom in the cation NH2 can be explained by considering the valence electrons of nitrogen. Nitrogen has five valence electrons, and in NH2, one of these electrons is used to form a bond with the hydrogen atom, leaving four electrons.
To determine the hybridization of the nitrogen atom in the NH2+ cation, follow these steps:
1. Identify the nitrogen atom's valence electrons. Nitrogen has 5 valence electrons.
2. Add the number of hydrogen atoms bonded to nitrogen (2 in this case).
3. Add any extra electrons due to the charge. Since it's a positive cation (NH2+), we need to subtract one electron.
Now, the total number of electrons in the valence shell is 5 (from nitrogen) + 2 (from the hydrogens) - 1 (from the positive charge) = 6 electrons.
4. Divide the total number of electrons by 2 to get the electron pairs: 6 electrons ÷ 2 = 3 electron pairs.
5. Determine the hybridization based on the number of electron pairs. In this case, there are 3 electron pairs:
- 2 pairs are used for bonding with the hydrogen atoms.
- 1 pair is a lone pair on the nitrogen atom.
The hybridization that corresponds to 3 electron pairs is sp2. Therefore, the hybridization of the nitrogen atom in the NH2+ cation is sp2.
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