draw the structural formula of the principal organic product formed when benzonitrile is treated with ch3mgbr followed by work-up with dilute acid.

The reaction of the hydrogen and the chlorine atoms would lead to the formation of HCl

In this reaction, each chlorine molecule (Cl2) breaks apart into two chlorine atoms (Cl), and each hydrogen molecule (H2) breaks apart into two hydrogen atoms (H). These reactive atoms then combine to form hydrogen chloride molecules (HCl).

It's worth noting that the reaction between hydrogen gas and chlorine gas is highly exothermic and releases a significant amount of energy.

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In the Lewis structure of methanol (CH3OH), the OH group is placed on the outside because it is an important functional group that influences the chemical properties and reactivity of the molecule.

The Lewis structure is a representation of a molecule that shows the arrangement of atoms and valence electrons. In methanol, carbon (C) is the central atom bonded to three hydrogen (H) atoms and one oxygen (O) atom. The oxygen atom forms a single bond with carbon and also has two lone pairs of electrons.

The placement of the OH group (hydroxyl group) on the outside of the Lewis structure is significant because it determines the chemical behavior of methanol. The OH group consists of an oxygen atom bonded to a hydrogen atom and represents the presence of an alcohol functional group.

In organic chemistry, functional groups are specific arrangements of atoms within a molecule that give rise to characteristic chemical reactions and properties. The presence and position of functional groups can greatly influence the behavior and reactivity of a compound. In the case of methanol, the hydroxyl group provides the molecule with its characteristic properties.

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8.52 m is the height of a barometer column based on 1-iodododecane.

A barometer is described as a scientific instrument that is used to measure air pressure in a certain environment.

For the given question we will use the below formula:

P = dgh, where

g = gravitational force = 9.8 m/s²

h = height

First we calculate the height of the barometer column for the mercury:

Density of mercury = 13.6g/ml (given)

Given pressure = 752 torr =100258.144 N/m²

Height of barometer for mercury = 100258.144 / (13.6×9.8) = 752.23= 0.752

Now we calculate the height of barometer by using the below formula:

d₁h₁ = d₂h₂, where

d₁ = density of 1-iodododecane = 1.20g/mol (given)

h₁ = to find?

d₂, h₂ = density & height with respect to mercury

On putting all values in the above equation we get,

h₁ = 13.6×0.752  / 1.20 = 8.52m

Hence, 8.52m is the height of barometer.

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Complete question:

The compound 1-iodododecane is a nonvolatile liquid with a density of 1.20g/ml. the density of mercury is 13.6g/ml. part a what do you predict for the height of a barometer column based on 1-iodododecane, when the atmospheric pressure is 752 torr ?

The element iodine appears in Period 5 of the Periodic Table. This means that an iodine atom has five orbitals in its electron cloud. so the correct option is (b).

As a member of group 7, iodine possesses seven outer electrons. Since it is in the fifth period, its electrons will be in orbitals 5s and 5p. The chemical formula for iodine is 5s25px25py25pz1.

total amount of electrons that could occupy each orbital

Again using iodine as an example, we can observe on the periodic table that it has an atomic number of 53. ( In neutral state it contains 53 electrons). The configuration of the entire electron cloud is 1s22s22p63s23p64s23d104p65s24d105p5.

Iodine is a trace element that can be found as a dietary supplement, as well as naturally in some foods and some forms of salt. Iodine is a necessary component of the thyroid hormones triiodothyronine (T3) and thyroxine (T4) (T3).

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Answer:

false

in chemical reaction element doesnot change into another

Explanation:

A weak acid as well as its corresponding base make up a buffered solution. The ions are represented by violet, grey, and green spheres, respectively.  The first system represents the buffer.

A buffer is indeed a solution that resists pH fluctuations and contains either one weak acid as well as its salt or even a weak base as well as its salt. To put it another way, a buffer is indeed an aqueous solution that includes a weak base as well as its conjugate acid, or a weak acid as well as its conjugate base.

A buffer may also be referred to as a buffer solution, hydrogen ion buffer, and pH buffer. A weak acid as well as its corresponding base make up a buffered solution. The ions are represented by violet, grey, and green spheres, respectively.  The first system represents the buffer.

Therefore, the first system represents the buffer.

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Answer: (2S,3S)-2-Bromo-3-phenylbutane will undergo E2 reaction and form trans product of elimination due to its thermodynamic stability

Explanation:

Answer:

The process to use this knowledge is explained as below:

Explanation:

1. Farmer should use an indicator to check the pH value of the soil of the field of the farm.

2. If the field or the farm has alkali soil add acid to reduce the pH value.

3. If the soil of the farm is acidic for the crop add alkali to increase the pH value.

4. It will be a neutralization reaction and changes the pH value of the farm.

5. Weather/leeching into the surrounding soil/plant or animal waste will lead to a change in pH value over time.

6. The pH value will need to be regularly monitored and adjusted.

Answer:

Balanced equation: H₂S₂O₇  +  H₂O →  2H₂SO₄

Theoretical yield of H₂SO₄: 1322 g

Percent yield for the H₂SO₄ production: 33%

Explanation:

First of all, we determine the balanced equation:

H₂S₂O₇  +  H₂O →  2H₂SO₄

Stoichiometry says that 1 mol of oleum reacts to 1 mol of water in order to produce 2 moles of sulfuric acid.

1.20 kg = 1200 g

We convert the grams to moles → 1200 g . 1mol/ 178.12g = 6.74 mol

Ratio is 1:2, so if we have 6.74 mol of oleum we can produce the double of moles of acid. (6.74 . 2) = 13.48 moles of acid.

This is the 100 % yield reaction, or it can be called theoretical yield.

We convert the moles to mass → 13.48 mol . 98g /1mol = 1322 g of acid may be produced.

In the problem, they said we produced 435 g of acid, so let's determine the percent yield.

Percent yield of reaction = (Produced yield / Theoretical yield) . 100

Percent yield of reaction = (435 / 1322) . 100 → 33 %

a) The Lennard-Jones potential predicts the separation r_eq at the minimum energy U_min.

b) The U_min for this interaction at T=298 K is the value obtained from the Lennard-Jones potential equation when r=r_eq.

c) The ratio of U_min to the purely attractive van der Waals component of the interaction potential at r_eq can be calculated by comparing the attractive part (-A/r^6) to the total potential energy U_min.

d) The ratio of r_eq to r_0, where u(r_0)=0.4, can be determined by finding the value of r_eq where the potential energy is equal to 0.4 times the total potential energy at r=r_0.

e) The ratio of r_s to r_0, where r_s is the separation where the magnitude of the attractive adhesion force is maximum, can be determined by finding the value of r where the derivative of the potential energy with respect to r is equal to zero.

f) The value of F_max between the two atoms can be obtained by taking the negative derivative of the potential energy equation with respect to r and evaluating it at r=r_s.

a) The Lennard-Jones potential provides information about the relationship between energy and separation between two interacting atoms.

At the minimum energy (U_min), the potential predicts the separation r_eq, which corresponds to the equilibrium distance between the atoms. This is the distance at which the energy of the system is at its lowest point.

b) To determine the value of U_min at a given temperature (T=298 K), you can substitute the equilibrium separation r_eq into the Lennard-Jones potential equation and calculate the resulting energy value.

This will give you the U_min for the interaction.

c) The Lennard-Jones potential consists of two components: an attractive component (-A/r^6) and a repulsive component (B/r^12).

The ratio of U_min to the purely attractive van der Waals component of the interaction potential at r_eq can be calculated by comparing the magnitude of the attractive component to the total potential energy at the equilibrium separation.

This ratio provides insights into the relative contribution of the attractive force to the overall potential energy at equilibrium.

d) The ratio of r_eq to r_0 can be determined by finding the value of r_eq where the potential energy is equal to 0.4 times the total potential energy at r=r_0.

In other words, you need to solve the Lennard-Jones potential equation for r_eq when the potential energy is equal to 0.4 times the potential energy at r=r_0.

e) The ratio of r_s to r_0 is obtained by finding the value of r where the magnitude of the attractive adhesion force is maximum.

This can be determined by finding the separation r where the derivative of the potential energy equation with respect to r is equal to zero.

The value of r_s represents the separation at which the attractive force between the atoms is strongest.

f) The value of F_max between the two atoms can be obtained by taking the negative derivative of the Lennard-Jones potential energy equation with respect to r and evaluating it at r=r_s.

This will give you the magnitude of the maximum attractive adhesion force between the atoms.

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Answer:

8

Explanation:

This number normally equals the number of electrons that atom needs to have a total of eight electrons (an octet) in its outer shell.

Answer:

This question is incomplete, the gravitational potential energy is 2.65 x 10^5 J

mass of the boulder = 866.7g

Explanation:

Potential energy (P.E) refers to the energy due to the position of a body. It can be calculated as follows:

P.E = m × g × h

Where;

m = mass of substance (g)

g = acceleration due to gravity (m/s²)

h = height (m)

According to the information provided in this question,

h = 31.2 m

g = 9.8m/s²

m = ?

P.E = 2.65 x 10^5 J

Using P.E = m × g × h

2.65 x 10^5 = m × 9.8 × 31.2

2.65 x 10^5 = 305.76m

265000 = 305.76m

m = 265000 ÷ 305.76

m = 866.69

mass of the boulder = 866.7g

Answer:

1. Melting

2. Freezing

3. Sublimation

4. Deposition

5. Condensation

6. Evaporation

1, 3, 6 are endothermic processes

Answer:

The balanced reaction for the decomposition of baking soda is

2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)

We can find the heat of reaction by using the Hess' Law. This is done by using this formula:

∑(Hf,products) -∑(Hf,reactants) = Heat of reaction

where Hf is the heat of formation. According to literature, these are the heats of formation for each of the compounds in the reaction:

NaHCO3: -947.68 kJ/mol

Na2CO3: -1130.94 kJ/mol

CO2: -393.51 kJ/mol

H2O: -241.8 kJ/mol

Applying Hess' Law:

[1(-1130.94) + 1(-241.82)] + 1(-393.51)] - [2(-947.68)] = 129.09 kJ

Thus, the heat of reaction is 129.09 kJ/mol NaHCO3. Since there is 1.96 mol of NaHCO3, the total heat of reaction is 253.02 kJ

Explanation:

please mark me as brainlest

Answer:

Due to the accumulation of static charges/due to static electricity

Answer:

a

Explanation:

i took the quiz

1) Chemical formula

2) Mg Lewis structure

3) O2 Lewis structure

4) MgO Lewis structure

5) Chemical formula written as Lewis dot structure

.

Answer:

False

Explanation:

I took the quiz and got it right

Answer: There are 2.161 x 10^24 molecules present in 3.6 moles CH₁.

Explanation:

Molecules are the the lowest fundamental unit of a chemical molecule that can participate in a chemical reaction is a group of bound atoms. Avogadro's number is used to calculate the number of molecules present in a mole of a substance

Avogadro's number of particles, or around 6.022 x 1023 molecules, are present in one mole of any substance. Therefore the following would be present in 3.6 moles of CH1:

2.161 x 1024 particles are equal to 3.6 moles times 6.022 x 1023 particles per mole.

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Answer: i think its (b) be abundant in the crust

Explanation:

The name of the given hydrocarbon in which 2 central carbon atoms with additional 3 methyl groups is 2-methylbutane.

Hydrocarbons are the organic compounds which are made up of by the combination of hydrogen and carbon atoms.

According to the question desired structure is attached below where:

Hence required hydrocarbon is 2-methyl butane.

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Answer:

B. 2-methylbutane

Explanation:

Correct on Edge 2022!!!

Good luck everyone, you got this! Have a great day!

Answer:

Explanation:

I think it’s mimetic. Correct me if I’m wrong.

If excess ammonium sulfate reacts with 20.0g of calcium hydroxide then liters of ammonia are produced at STP 0.081L

Ammonium sulphate is the organic solvent and the primary use of ammonium sulphate is as a fertilizer for alkaline soils

Here given reaction is

(NH₄)₂SO₄ + Ca(OH)₂ → CaSO₄ + NH₃ + H₂O

Here given data is

Calcium hydroxide  = 20.0g

We have to find liters of ammonia are produced at STP =?

20.0g of (NH₄)₂SO₄ STP = ?

Then 20.0g of (NH₄)₂SO₄×1 mol/132g×0.54L/1 mol = 0.081L

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Answer:

45673

Explanation:

Answer: −182.96 °C; −297.33 °F

I think

Answer:

162374 farenheit

Explanation:

You need to convert the 90.19k to Farenheit.

You can even use google, but if you need the formula it's (0°C × 9/5) + 32 = 32°F

(a) Using the ideal gas law, the pressure in the flask is approximately 11.43 atm.

(b) Using the van der Waals equation, the pressure in the flask is approximately 9.44 atm.

(c) There is a difference between the pressures because the van der Waals equation accounts for the volume of the molecules and the attractive and repulsive forces between them.

(d) The correction for the volume of the molecules is more significant than the correction for the attractive forces between molecules because the volume correction is proportional to the amount of gas. Since the amount of gas is relatively small compared to the square of the amount of gas, the correction for the volume of the molecules is more significant.

a) The ideal gas law is PV = nRT. Here, P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Using the ideal gas law:

PV = nRTP = (nRT)/V

Where,

P = Pressure of CO₂

n = Number of moles of CO₂

V = Volume of CO₂

T = Temperature of CO₂

R = Gas constant = 0.08206 L-atm/mol-K (This value can be converted to other units based on the unit of pressure, volume, and temperature used in the problem)

Substitute the values into the formula:

P = (0.467 mol * 0.08206 L-atm/mol-K * (159°C + 273.15)) / 0.245 L

P = 11.43 atm (approximately)

b) The van der Waals equation is given as (P + an²/V²)(V - nb) = nRT, where a and b are constants based on the properties of the gas being used. Since CO₂ is a gas composed of polar molecules, the van der Waals constant, "a," is nonzero, while the van der Waals constant, "b," accounts for the size of the gas molecules and is also nonzero for CO₂.

Using the van der Waals equation:

(P + an²/V²)(V - nb) = nRT

Solve for P. The value of a and b are 3.59 L²-atm/mol² and 0.0427 L/mol, respectively. Plug in the given values:

P = (nRT/(V - nb)) - (an²/V²)(a)

P = ((0.467 mol * 0.08206 L-atm/mol-K * (159°C + 273.15 K))/(0.245 L - (0.0427 L/mol * 0.467 mol))) - ((3.59 L²-atm/mol² * 0.467 mol²)/(0.245 L)²)(b)

P = 9.44 atm (approximately)

c) The van der Waals equation is an improvement over the ideal gas law because it accounts for the volume of the molecules and the attractive and repulsive forces between them that become significant at high pressures and low temperatures. At low pressures and high temperatures, the ideal gas law works well since the forces between molecules are negligible and the volume of the molecules is relatively small. However, at high pressures and low temperatures, the volume of the molecules and the attractive forces between them become significant, resulting in the deviation of gases from ideal behavior.

d) In this case, the correction for the volume of the molecules (represented by "b") is more significant than the correction for the attractive forces between molecules (represented by "a"). This is because the volume correction is proportional to the amount of gas, while the correction for the attractive forces is proportional to the square of the amount of gas. Since the amount of gas is relatively small compared to the square of the amount of gas, the correction for the volume of the molecules is more significant.

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29.25 grams of NaCl, m.w. 58.5 daltons, are necessary to make 1 liter of 5% saline.

Molar concentration is a unit of measurement for the concentration of a chemical species, specifically a solute, in a solution, expressed as the amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.

A solution's concentration is defined as the quantity of solute present in a given amount of solution. The concentration of any solution is defined as the solute divided by the volume of the solvent or solution. When represented as a percentage, it is known as mass by volume percent.

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