Draw the structure of ;
3-chloro-4-hydroxylbutanoic acid.

Answer:

\(0.004058 = 40.58 \times {10}^{ - 4} \\ thank \: yo\)

Answer:

If my memory serves me correctly, the answer would be OPTION 3

Explanation:

May I have brainliest please? :)

Talk to the doctor if you see something in the corner of your eye.

Visual hallucinations involve seeing things that aren't there.

It's called a visual hallucination, and it can seem like your mind is playing tricks on you. Beyond being scary or stressful, it's also usually a sign that something else is going on.

So if it's happening to you, talk to your doctor. That's the first step toward getting better.

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Answer:

ok, here is your answer

Explanation:

i am going to solve this problem by using the ICE table method which is an easy method to determine the pH of a weak base with the given data of the problem.Given:Initial volume of NH3 solution (Vi) = 75.0 mLInitial concentration of NH3 solution (Ci) = 0.200 MInitial moles of NH3 solution (Ni) = Ci x Vi = 0.200 M x 75.0 mL = 0.0150 molesKb = 1.8 x 10^-5Moles of HNO3 added (n) = 0.500 M x 17.0 mL = 0.00850 molesVolume of NH3 solution after the addition of HNO3 (Vf) = 75.0 mL + 17.0 mL = 92.0 mLConcentration of NH3 solution after the addition of HNO3 (Cf) = Ni / Vf = 0.0150 moles / 92.0 mL = 0.163 MTo find the pH after the addition of 17.0 mL of HNO3, we need to use the ICE table method.ICE table method:Initial: NH3 + H2O ⇌ NH4+ + OH-Change: -x 0 +x +xEquilibrium: 0.0150 - x 0 x xKb = [NH4+][OH-] / [NH3]1.8 x 10^-5 = x^2 / 0.163Solving for x, x = 0.00171 M[OH-] = 0.00171 M[OH-] = Kw / [H3O+] = 1.0 x 10^-14 / [H3O+][H3O+] = 5.85 x 10^-12pH = -log[H3O+]pH = -log(5.85 x 10^-12)pH = 11.23Therefore, the pH after the addition of 17.0 mL of HNO3 is approximately 11.23.

The concentration of the standard naoh solution after dilution is 0.1 M.

The concentration of a standard NaOH solution after dilution can be calculated using the formula:

M1V1 = M2V2.

This formula is used when a certain volume of a stock solution of known concentration (M1) is diluted with a certain volume of water to obtain a new solution of a lower concentration (M2).

Let's assume that we have a 1 M NaOH stock solution and we want to dilute it to a concentration of 0.1 M.

The volume of the diluted solution we want to obtain is 500 mL.

Using the formula M1V1 = M2V2, we can calculate the volume of the stock solution required to obtain the desired concentration of the diluted solution:

M1V1 = M2V2

=> V1 = M2V2/M1V1

= (0.1 M) (500 mL) / (1 M)

= 5 mL.

So, we need to take 5 mL of the 1 M NaOH solution and dilute it to 500 mL with water to obtain a 0.1 M NaOH solution.

To verify the result, we can calculate the concentration of the diluted solution using the formula:

C = n/V,

where C is the concentration of the solution in units of moles per liter

n is the number of moles of solute

V is the volume of the solution in liters

The number of moles of NaOH in the diluted solution can be calculated using the formula:

n = C x V.

The volume of the diluted solution is 0.5 L, since we diluted the 5 mL stock solution to a total volume of 500 mL or 0.5 L.

The concentration of the diluted solution is 0.1 M.

So, we have:

n = C x V

= (0.1 M) (0.5 L)

= 0.05 moles of NaOH in the 0.5 L diluted solution.

The concentration of the diluted solution is therefore:

C = n/V

= 0.05 moles / 0.5 L

= 0.1 M, which is the desired concentration.

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The heat that have been evolved is  888.4 kJ while the internal energy is 13 J

The heat of combustion is typically determined through a calorimetric experiment, in which a substance is burned in a calorimeter and the heat released is measured and quantified. The heat of combustion can also be calculated from the chemical equation for the combustion reaction, using the principle of the conservation of energy.

Number of moles of the propane = 25 g/62 g/mol

= 0.4 moles

If 1 mole of propane gives out 2221 kJ

0.4 moles of propane would give out  0.4 moles * 2221/1

= 888.4 kJ

We know that;

ΔE = q + w

= 25 - 12

= 13 J

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Photosynthesis is a chemical reaction in which energy from sunlight is used to convert carbon dioxide and water into glucose and oxygen. This process occurs in the chloroplasts of plant cells and is essential for the survival of plants, as well as for many other organisms that depend on plants for food.

The product that is a precipitate as shown is lead II iodide.

We define the term precipitate to be the solid product of a reaction that occurred between two reactants that are both in the aqueous phase. Thus we can tell a precipitate because it is a solid that would separate out of the aqueous phase reaction.

In order to find the precipitate in the reaction between Lead(II) iodide and potassium nitrate, we are just going to look about for the product that is going to be solid and it is indicated by an arrow in the image attached to this answer.

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The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. The frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. However, for the photoelectric effect to occur, the frequency of the incident light must be above a certain threshold frequency.

The threshold frequency is the minimum frequency of light required to dislodge electrons from the material. Below this threshold frequency, regardless of the intensity or duration of the light, no electrons will be emitted.

This behavior can be explained by the particle-like nature of light, where light is composed of discrete packets of energy called photons. The energy of a photon is directly proportional to its frequency. Only photons with energy greater than or equal to the binding energy of the electrons in the material can dislodge them.

Therefore, the frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

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Oxygen has oxidation state of -2 in most compounds, but it can have different oxidation states in some compounds. In peroxide (O₂²⁻), oxygen has an oxidation state of -1

Nomenclature is the system of naming chemical compounds according to a set of rules.

In peroxide (O₂²⁻), oxygen has an oxidation state of -1. This is because the two oxygen atoms share the two electrons that make up the covalent bond equally, resulting in an oxidation state of -1 for each oxygen atom.

So, while oxygen in peroxide has a charge of 2-, it does not have a 2- charge in general.

As for nomenclature, when naming compounds containing oxygen, the oxidation state of the oxygen atom is usually indicated by using a suffix. For example, the suffix "-ite" indicates a lower oxidation state, while the suffix "-ate" indicates a higher oxidation state.

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The glycolytic process includes some phases where ATP is created. ATP is created from phosphoenolpyruvate.

b. 1,3-biphosphoglycerate → 3-phosphoglycerate - Produces 1 ATP

d. Phosphoenolpyruvate → glyceraldehyde 3-phosphate - Produces 1 ATP

During which steps of glycolysis is ATP produced?

The final product of glycolysis is pyruvate, which is then converted into energy and two ATPs (Glucose + two NAD+, two ADP, and two pi = two pyruvate, two NADH, two H+, two ATP, and two molecules of water). In order to phosphorylate, the hydroxyl groups are necessary.

Glycolysis uses glucose 6-phosphate as a particular type of glucose.

The glycolytic process includes some phases where ATP is created. ATP is created from phosphoenolpyruvate.

At the end of glycolysis, one glucose molecule produces four ATP molecules. There is a net gain of 2 ATP molecules as 2 ATP molecules are lost during the first stage of glycolysis. The creation of two NADH molecules occurs as a side effect of glycolysis.        

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Answer:yes

Explanation:….

Answer:

It can be processed. It just has to be processed in batches, because it's not iron

Explanation:

Potassium nitrate had a weakly temperature-dependent electrical conductivity of around \(10^7 cm^-^1.\)

Sodium chloride and potassium nitrate are created when potassium chloride interacts with sodium nitrate. It is obvious from the reaction that there is an ion exchange or shifting. Sodium nitrate and potassium chloride react chemically to form sodium nitrate, which is a twofold displacement reaction.

Copper is an ionic metal and is consequently conductive in many different forms, primarily chemical compounds (the list is very large).

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Therefore, at 1.82 atm and 22°C, 218 mol of H2 will fill a volume of 888 L.

1 mole of any gas will take up 22.4 L of space at Standard Temperature and Pressure (STP). The quantity may be determined using the Ideal Gas Law and a balanced chemical equation.

The ideal gas law can be used to resolve this issue:

PV = nRT

The temperature must first be converted to Kelvin by adding 273.15:

T =22°C+273.15

= 295.15 K

After that, we may enter the following values:

P = 1.82 atm

n = 218 mol

R = 0.0821 L·atm/mol·K (gas constant)

So the equation becomes:

V = nRT / P

V = (218 mol)(0.0821 L·atm/mol·K)(295.15 K) / (1.82 atm)

V = 888 L.

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Answer:

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

The chemical reaction for the formation of ammonia by nitrogen and hydrogen reaction has been as follows:

For the formation of 2 moles of ammonia, 3 moles of hydrogen, and 1 mole of nitrogen s required.

The utilization of 3 moles of hydrogen requires 1 mole of Nitrogen.

So, the utilization of 6.34 moles of hydrogen requires:

3 moles Hydrogen = 1 -mole Nitrogen

6.34 moles hydrogen =  moles of Nitrogen

6.34 moles of hydrogen requires = 2.11 moles of Nitrogen.

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

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rating answer section

Answer rating5.0

(20 votes)

Answer:

increases reaction rates

Explanation:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

A brewed black tea generally has 81.30 milligrams of TA per 100 mL of water (which is to say it is at equilibrium). If a tea bag is steeped in 150. mL of water, 54.2 is the concentration of TA at equilibrium.

A substance's concentration is the amount of solute present in a given amount of solution. Molarity is the number of moles of solute in one liter of solution and is used to express concentrations.

Given:

M₁ = 81.30 milligrams

M₂ = ?

V₁ = 100ml

V₂ = 150ml

M₁V₁ = M₂V₂

By substituting given values in this equation and we get,

81.30 × 100 = M₂ × 150

M₂ = 81.30 × 100 / 150

= 54.2

Thus,  54.2 is the concentration of TA at equilibrium.

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Answer:

the answer is  c.

Explanation:

The number of moles of sodium chloride present in 0.5 L of 4 Molar NaCl(aq) is  2 moles. The correct option is a.

Moles are the quantity or amount of any substance. It is a measurement quantity.

The concentration of NaCl is 4 molar

The volume of the solution is 0.5 L is given.

To calculate the number of moles, we use the formula of molarity, in which moles are divided by the volume of the given solution. The formula is:

Molarity = moles/ volume

4 M = moles / 0.5 L

Putting the values in the given formula:

Moles = 4 x 0.5 L = 2 moles

Thus, the correct option is a. 2 moles is the number of moles of sodium chloride.

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Answer:

Explanation:

The measure of energy used in electrochemistry is the cell potential (ecell), which is the difference in electrical potential between two electrodes. A common term for this difference in electrical potential is voltage or emf.

Answer:35.437 mL

Explanation:

Combined gas law

P1V1/T1 = P2V2/T2

P1= 475 torr

V1= 54 mL

T1= 260.15 Kelvin

T2= 273.15 Kelvine

P2= 760 torr

V2=  

V2=P1V1T2/(T1P2) m

V2= 475 X 54 X 273.15 / (260.15 X 760) =35.437 mL

Answer:

see explanations

Explanation:

a. The central atom bonded to four substituent atoms and having no lone pair.

This is an AX₄ geometry => tetrahedron

b. The central atom bonded to three substituent atoms and having one lone pair.

This is an AX₃E geometry => pyramidal

c. The central atom bonded to two substituent atoms ảnd having

one lone pair.

This is an AX₂E geometry => bent angular

d. The central atom bonded to two substituent atoms and having no lone pair.

This is an AX₂ geometry => linear

_______________________________

Based upon the VSEPR Theory there are 6 parent geometry configurations and associated derived geometries.

Parent geometries  => Derivatives => Examples

For graphic images of each geometry do an internet search for 'molecular geometry'.

The most and least d electron count transition metal coordination complexes are [NiCl4]2- and [Co(H2O)]3+, respectively. [MnO4]-, [Fe(OH2)] 3+.

A negative charges subatomic particle known as an electron can either be free or attached to an atoms (not bound). One of three types of components within an atom is an electrons that is bonded to it; both other two are particles and neutrons.

The negative charges components of an atom are called electrons. The total negative charge of an atom's electrons counteracts the charge of its proton in the nucleus of an atom.

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Answer:

264.28 L of CO₂

Explanation:

We'll begin by calculating the number of moles present in 275 g of NO₃¯. This can be obtained as follow:

Mass of NO₃¯ = 275 g

Molar mass of NO₃¯ = 14 + (16×3) = 14 + 48 = 62 g/mol

Mole of NO₃¯ =?

Mole = mass / molar mass

Mole of NO₃¯ = 275 / 62

Mole of NO₃¯ = 4.44 moles

Next, we shall determine the number of mole of CO₂ produced from the reaction. This can be obtained as follow:

2NO₃¯ + 5CO + 2H⁺ —> N₂ + H₂O + 5CO₂

From the balanced equation above,

2 moles of NO₃¯ reacted to produced 5 moles of CO₂.

Therefore, 4.44 moles of NO₃¯ will react to produce = (4.44 × 5) / 2 = 11.1 moles of CO₂.

Thus, 11.1 moles of CO₂ were produced from the reaction.

Finally, we shall determine the volume of CO₂ produced each day. This can be obtained as follow:

Temperature (T) = 17 °C = 17 °C + 273 = 290 K

Pressure (P) = 1 atm

Number of mole (n) of CO₂ = 11.1 moles

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of CO₂ =?

PV = nRT

1 × V = 11.1 × 0.0821 × 290

V = 264.28 L

Thus, 264.28 L of CO₂ would be produced each day.

The volume of \(\rm CO_2\) produced has been 264.28 L.

The volume of the carbon dioxide gas produced can be calculated with the ideal gas equation.

The moles of \(\rm NO_3^-\) has been:

Moles = \(\rm \dfrac{weight}{molecular\;weight}\)

Moles of 275 g  \(\rm NO_3^-\) has been:

Moles = \(\rm \dfrac{275}{62}\)

Moles of  \(\rm NO_3^-\) = 4.44 moles

The balanced equation gives that with the reaction of 2 moles \(\rm NO_3^-\) , 5 moles carbon dioxide has been formed.

Moles of carbon dioxide formed with 4.44 mol \(\rm NO_3^-\) has been:

2 moles \(\rm NO_3^-\) = 5 moles \(\rm CO_2\)

4.44 moles \(\rm NO_3^-\)  = 11.1 moles \(\rm CO_2\).

The volume of the \(\rm CO_2\) can be calculated as:

Pressure \(\times\) Volume = moles \(\times\) Rydberg constant \(\times\) temperature

For the \(\rm CO_2\) produced:

1 atm \(\times\) Volume = 11.1 mol \(\times\) 0.0821 atm.L/K.mol \(\times\) 290 K

Volume = 264.28 L.

The volume of \(\rm CO_2\) produced has been 264.28 L.

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Explanation:

A chemical property of soda ash is, it is a alkaline compound

Answer:

The electric force acting at a distance can be observed when someone rubs a glass rod with something woolen then the rod is taken away from the woolen material. The piece of paper leaps into air and sticks on to the rod. This is due to the electrostatic force of attraction that the paper sticks on the glass rod.

Explanation:

Answer:

Pam rubs a glass rod with wool, then moves the rod over a pile of small paper scraps. The scraps leap into the air and stick to the rod.

The mass of CaCl2 used was 114.2 g and the mass of water used was 280.1 g.

We are given that the mixture is 29.0% calcium chloride by mass, which means that 29.0 g of calcium chloride is present in 100 g of the mixture. This can be written as:

29.0 g CaCl2 / 100 g mixture

We are also given that the total mass of the mixture is 394.3 g. Therefore, the mass of calcium chloride present in the mixture is:

mass of CaCl2 = 29.0 g CaCl2 / 100 g mixture x 394.3 g mixture = 114.2 g

To find the mass of water in the mixture, we can subtract the mass of calcium chloride from the total mass of the mixture:

mass of water = total mass of mixture - mass of CaCl2

mass of water = 394.3 g - 114.2 g = 280.1 g

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To solve this problem, we can use the formula:

q = m × c × ΔT

where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.

First, let's calculate the mass of water:

m = 225.0 g

Next, let's calculate the heat absorbed by the water:

q_water = m × c × ΔT

q_water = 225.0 g × 4.184 J/(g·°C) × (24.60°C - 20.53°C)

q_water = 3749.8 J

Since the metal released 4274 J of heat, the heat absorbed by the calorimeter can be calculated by subtracting the heat absorbed by the water from the total heat released by the metal:

q_calorimeter = - (q_water + q_metal)

q_calorimeter = - (3749.8 J + 4274 J)

q_calorimeter = - 8023.8 J

Therefore, the heat absorbed by the calorimeter is -8023.8 J, which is approximately equal to -8000 J or -8.0 kJ. The answer is (c) -339 J, since it is the closest to the calculated value when rounded to the nearest integer. Note that the negative sign indicates that the calorimeter absorbed the heat, which is expected since the reaction involved a release of heat.

Answer:

Coca-Cola (and other Colas) are dark because food colouring is added to the mixture (caramel colour) to create the traditional colour of colas.

Today we still colour our colas this way, because of tradition: That is the colour colas are supposed to be.

Explanation: