During an investigation a scientist heated 2.76 g of silver carbonate till it decomposed to leave a silver residue. The total mass of the silver residue formed was 2.16 g. Does the law of conservation of mass hold true in this case?

Answer:

900 J/kg°C.

Explanation:

The mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

From the question we are to calculate the mass of NaHCO₃ (sodium bicarbonate) used in the experiment

From the given information

Mass of empty evaporating dish = 46.233g

Mass of evaporating dish + Sodium bicarbonate = 48.230g

∴ Mass of sodium bicarbonate (NaHCO₃) = [Mass of evaporating dish + Sodium bicarbonate] - [Mass of empty evaporating dish]

Mass of sodium bicarbonate (NaHCO₃) = 48.230g - 46.233g

Mass of sodium bicarbonate (NaHCO₃) = 1.997 g

Hence, the mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

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The correct choice is ~ A

S.I unit of time is Second

The final pressure of the gas is obtained as 4.80 atm.

We know that the root mean square speed of the gas would depend on the temperature of the molecules of the gas. Here we are told that the root mean square speed of the gas molecules is doubled and it means that the temperature was also doubled.

We have;

P1/T1 =P2/T2

2T1 = 2P1

The final pressure would  be 2(2.40)atm = 4.80 atm

Thus we ought to have the temperature at the end as 4.80 atm from the calculation that has been done.

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1.5 moles of N2 will be produced when 1.8 moles of NO react.

The equation that balances is displayed below. N2(g)+3H2(g) = 2NH3 (g) Hydrogen will be the limiting reagent if equal moles of each reactant are utilised since it uses up 3 moles for every mole of nitrogen to produce ammonia.

5 N2 + 6 NO 4 NH3 + 6 NO 6 H2O

According to the equation, 6 moles of NO react to produce 5 moles of N2. As a result, we may apply a proportion to determine how many moles of N2 are produced when 1.8 moles of NO react:

(5 mol N2 / 6 mol NO) x 1.8 mol NO = 1.5 mol N2

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Answer:

The air smelled like a compound of diesel and gasoline fumes.

The "Rate=k" rate law constitutes a first-order reaction.

Half-life is the time required for the concentration of a reactant or product in a chemical reaction to decrease to half of its initial value. The concept of half-life is commonly used in nuclear chemistry and radioactivity, but it is also applicable to other types of reactions. The half-life of a reaction depends on the order of the reaction, which describes the relationship between the rate of the reaction and the concentration of the reactants. In a first-order reaction, the half-life is constant and is independent of the initial concentration of the reactant.

For a general nth order reaction "A → products", the rate law is given by:

Rate = k[A]^n

The half-life of an nth order reaction is written as follows:

t1/2 = [ 2^(n-1) / k[A]^(n-1) ]

We can derive this expression using the integrated rate law for an nth order reaction:

ln([A]t/[A]0) = -kt^(1-n)/(1-n)

where [A]t represents the concentration of A at time t and [A]0 represents the initial concentration of A.

For a half-life, we know that [A]t = 0.5[A]0 and t = t1/2. When these values are interchanged into the integrated rate law, we get:

ln(0.5) = -kt1/ 2ⁿ⁻¹ /(1-n)

Rearranging this equation and solving for t1/2 gives:

t1/2 = [ 2ⁿ⁻¹  / k[A]ⁿ⁻¹ ]

Therefore, the half-life for an nth order reaction can be written as t1/2 = [ 2ⁿ⁻¹ / k[A]ⁿ⁻¹ ] where k is the rate constant and [A] is the concentration of the reactant.

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Answer:

C

Explanation:

It has the lowest Ksp, so it will have the lowest Molar Solubility

Answer:

\( \boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3} \)

Given:

Mass = 14.0 g

Density (\( \rho \)) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

\( \boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}\)

Substituting value of m & density in the formula:

\( \sf \implies 1.38 = \frac{14.0}{V} \\ \\ \sf \implies V = \frac{14.0}{1.38} \\ \\ \sf \implies V = 10.14 \ cm^3 \)

\( \therefore \)

Volume of the plastic used to make water bottle = 10.14 cm³

Answer:

Find alternatives to fossil fuels

Explanation:

The most effective long - term solution to reduce the amount of carbon dioxide emission is to find alternatives to fossil fuels.

Fossil fuels consumption and use in most industrial processes are some of the leading causes of huge carbon signatures in the atmosphere.

In a REDOX titration, one specie is oxidized while the other is reduced. The concentration of methanol is 0.012  mol L-1. Methanol is the oxidizing agent while permanganate is the reducing agent.

The average titre value is; \(\frac{7.95 + 7.10 + 7.00 + 7.10}{4}\) = 7.29 mL

Equation of the reaction is:

\(4MnO4- + 12H+ + 5CH3OH ----> 4Mn2+ + 11H2O + 5HCOOH\)

Concentration of oxidizing agent = CA = ?

Concentration of reducing agent = CB = 0.0021 mol L-1

Volume of oxidizing agent =  VA= 7.29 mL

Volume of reducing agent = VB = 50.00 mL

Number of moles of oxidizing agent NA = 4

Number of moles of reducing agent NB = 5

Note that NA and NB are obtained from the balanced reaction equation

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA =  CBVBNA/VANB

CA = 0.0021 mol L-1 * 50.00 mL * 4/7.29 mL * 5

CA= 0.012  mol L-1

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Answer:

Sugar, Carbon Dioxide, And Water

Explanation:

A chemical substance is a form of matter having constant chemical composition and characteristic properties. Some references add that chemical substance cannot be separated into its constituent elements by physical separation methods, i.e., without breaking chemical bonds. Chemical substances can be simple substances, chemical compounds, or alloys. Chemical elements may or may not be included in the definition, depending on expert viewpoint.

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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Answer:

c balance

Explanation:

if you weigh something, you prove it's there.

The answer ( 13 and 8 )

x²=5²+12²

x²=25+144

x²=169

x=13

x²=5²+6²

x²=25+36

x²=61

x=7.8

x=8

Answer:

It is an unstable form of a chemical element that releases radiation as it breaks down and becomes more stable.

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Explanation:

Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.

C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)

When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.

When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.

The number of volume of the oxygen that would be consumed is 2.8 L.

Let us recall that what we have here is the process of the use of the stoichiometry of the reaction so as to be able to obtain the mass and the volume of the reactants that are taking place in the reaction as we are going to have in the case that is at hand.

What we now need to do so that we can be able to use the stoichiometry of the reaction would just be to write down the equation of the reaction and this is going to give us the reaction; \(2Mg(s) + O_{2} (g) ---- > 2MgO\).

In this case we know that;

Number of moles of the magnesium = 6g/24 g/mol

= 0.25 moles

Now we know that;

If 2 moles of the magnesium reacts with 1 mole of the oxygen then

0.25 moles of the magnesium would react with 0.25 * 1 /2

= 0.125 moles

Volume of oxygen that is consumed is; 0.125 moles * 22.4 L
=2.8 L

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An instantaneous dipole occurs when a molecule's moving electrons are briefly more concentrated in one place than another, causing the molecule to become temporarily polarized.

The correct option is True.

Dipoles refer to a separation of charges where one end of a substance has a  positive charge while the other end has a negative charge.

In chemical compounds, dipoles occur within a molecule that has covalently bonded atoms or atoms that share electrons in the covalent bond.

The dipole may be permanent dipoles or temporary dipoles.

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The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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Answer:

2Na + FeCl2 → 2NaCl + Fe (sodium)

Explanation:

Answer:

1 mole of any ideal gas occupies the same volume as one mole of any other ideal gas under the same conditions of temperature and pressure.So 1 L CO2 has same number of moles as 1 L O2 and 1 L N2 etc.This means that, assuming all the gases in air are ideal gases, if CO2 is 4.0 % by volume then it is also 4.0 % by moles, because a volume of each gas has the same number of moles.

Explanation:

Answer:

a no. because tearing the raw meat will not be easy without the use of the canine teeth

690 g AgCl

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Unbalanced] AgNO₃ + ZnCl₂ → AgCl + Zn(NO₃)₂

↓

[RxN - Balanced] 2AgNO₃ + ZnCl₂ → 2AgCl + Zn(NO₃)₂

[Given] 2.4 mol ZnCl₂

[Solve] x g AgCl

Step 2: Identify Conversions

[RxN] 1 mol ZnCl₂ → 2 mol AgCl

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

Step 3: Stoich

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

687.936 g AgCl ≈ 690 g AgCl

Answer:

Rock In molten form is Lava

^_^

Answer:

Proteinase K

Explanation:

Proteinase K, which is a broad spectrum serine protease, is used in many DNA extraction protocols to digest these contaminating proteins.