During what stage of the life cycle is an animal able to reproduce? (2 points) a Adolescent b Adult c Embryo d Infant

Answer:

ver explicacion

Explanation:

El elemento que tiene el número atómico 56 en la tabla periódica del bario. El bario es un elemento del grupo dos.

Se combina con el cloro para formar cloruro de bario. que tiene la fórmula BaCl2 de acuerdo con la valencia de ambos elementos.

El cloruro de bario es un compuesto iónico.

The ion that will form a compound with bicarbonate in a 1:1 cation to anion ratio is hydrogen ion (H+).

Bicarbonate (HCO3-) is an anion that can combine with a cation to form a salt. In a 1:1 cation to anion ratio, the cation must have a charge of +1 to balance the -1 charge of the bicarbonate anion. Hydrogen ion (H+) is a monovalent cation with a charge of +1, and it readily combines with bicarbonate to form the salt hydrogen bicarbonate (H2CO3), also known as carbonic acid. This salt is important in the regulation of pH in the body and is involved in processes such as respiration and acid-base balance.

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The cell potential (Ecell) of the zinc-air battery at 25.0 degrees Celsius and a partial pressure of oxygen of 0.15 atm is 1.65 V.

To calculate the cell potential (Ecell) of the zinc-air battery at 25.0 degrees Celsius, we can use the Nernst equation, which relates the cell potential to the standard cell potential and the concentrations or pressures of the reactants:

\(E_{\text{cell}} = E^{\circ}_{\text{cell}} - \left(\frac{RT}{nF}\right) \ln(Q)\)

Where:

E°cell is the standard cell potential (given as 1.65 V)

R is the ideal gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin (25.0 + 273.15 = 298.15 K)

n is the number of electrons transferred in the balanced cell reaction (2 in this case)

F is Faraday's constant (96485 C/mol)

Q is the reaction quotient

In this case, since we are given the partial pressure of oxygen (O2) in the air diffusing through the cathode (0.15 atm), we can use the partial pressure as a substitute for concentration.

The reaction quotient (Q) can be calculated using the partial pressures of the reactants and products (ZnO):

\(Q = \frac{{(P(\text{ZnO}))^2}}{{P(\text{O}_2)}}\)

Plugging in the values into the Nernst equation, we have:

Ecell = 1.65 V -\(\frac{{8.314 \, \text{J/(mol}\cdot\text{K)}} \times 298.15 \, \text{K}}}{{2 \times 96485 \, \text{C/mol}}} \right) \ln \left( \frac{{(P(\text{ZnO}))^2}}{{P(\text{O}_2)}} \right)\)

Let's calculate the cell potential (Ecell) using the given values:

Ecell = 1.65 V -\({{8.314 \, \text{J/(mol}\cdot\text{K)}} \times 298.15 \, \text{K}}}{{2 \times 96485 \, \text{C/mol}}} \right) \ln \left( \frac{{(0.15 \, \text{atm})^2}}{{0.15 \, \text{atm}}} \right)\)

Simplifying the equation further:

\(E_{\text{cell}} = 1.65 \, \text{V} - (0.0257 \, \text{V}) \ln \left( \frac{{0.15^2}}{{0.15}} \right)\)

Calculating the natural logarithm:

\(E_{\text{cell}} = 1.65 \, \text{V} - (0.0257 \, \text{V}) \ln(1)\)

Since ln(1) is equal to 0:

Ecell = 1.65 V - (0.0257 V) * 0

Ecell = 1.65 V

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The final volume of the balloon will be 316.6 ml

Given,

V1= 250 ml

P1= 760 mm Hg

V2=?

P2= 600 mm Hg

From the given question, the final volume can be calculated using Boyle's law.

The link between a gas's pressure, volume, and temperature is shown by Boyle's law. It asserts that under constant temperature, a gas's pressure is inversely proportional to its volume.

Boyle's law is valid only for ideal gas.

Pressure and volume are represented by a rectangular hyperbola on the graph.

P ∝ 1/V or PV = K

∴P1 x V1  = P2 x V2

⇒ 250 x 760 = 600 x V2

⇒190000 = 600 x V2

⇒190000/ 600 = V2

⇒V2 =  316.6 ml

Hence, the new volume of the balloon will be 316.6 ml.

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The solution is going to have a pH of 12.7.

The pH uses a logarithmic scale with 7 as neutral, where lower values are more acidic and higher ones are more alkaline, to represent the acidity or alkalinity of a solution. The hydrogen ion concentration (c), expressed in moles per litre, determines the pH, which is equal to log10(c).

Now we know that;

pOH = - log(0.05M)

pOH = 1.3

pH = 14 - 1.3

= 12.7

We know that the above can be justified if we remember that pH +
pOH = 14

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The substances can only be properly identified if we carry out flame tests and qualitative analysis on the samples.

We know that the only way that we can be able to identify a substances in chemistry is to be able to perform a series of tests on the substances. In this case, we are told that we have the substances potassium carbonate, potassium chloride, potassium iodide, sodium chloride in solution.

We can only be able to identify the solutions by the use of flame tests and qualitative analysis. Flame test would show the colors that are characters of the cation while we could use qualitative analysis to identity the anion present.

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First nations people along the west coast of British Columbia used smelting technology to create copper plaques is false.

Smelting process is the form of extractive metallurgy to produce a metal from its ore. it is the process of melting and separation of charges .  it is extensive energy process. Plaques are made by pouring molten metal in to a mold. and when it gets cools , it solidified into a copper solid plaque. first nation people use copper as hunting weapons, spear tools etc. copper is metal.

Thus, First nations people along the west coast of British Columbia used smelting technology to create copper plaques is false.

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ANSWER

The initial volume of the acid is 260mL

EXPLANATION

Given that;

The final volume of the ethanoic acid is 4.5L

The final concentration of the ethanoic acid is 1.0 mol/L

The initial concentration of the ethanoic acid is 17.4 mol/L

Follow the steps below to find the volume of the ethanoic acid

Step 1; Apply the dilution formula

Step 2; Substitute the given data into the formula

Therefore, the initial volume of the acid is 260mL

Thermoreceptors are stimulated by the temperature change.

The thermoreceptor is the sensory receptor or, the more accurately, it will be the receptive portion of the sensory neuron that will codes the absolute and the relative changes in the temperature, that will primarily is in the innocuous of the range.

Thermoreceptors are of the two types, the warmth and cold. The warmth fibers that are excited by the rising temperature and it will inhibited by the falling the temperature, and the cold fibers will be respond in the opposite manner. Thermoreceptors are the selectively sensitive to the specific ranges of the temperature.

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The equilibrium concentration (in M to three decimal places) of HBr for the given reaction is 0.025 M at 25 °C.

Let x be the equilibrium concentration of HBr. Then, the equilibrium concentrations of \(H_2\) and \(Br_2\) will also be x, since the stoichiometry of the reaction is 1:1:2.

Using the equilibrium constant expression for this reaction:

\(K = [HBr]^2/ ([H_2] [Br_2])\)

Substituting the initial concentrations and the equilibrium concentrations in terms of x:

0.000351 = (2x)² / (0.5 - x)²

Solving for x:

0.000351 (0.5 - x)² = 4x²

0.0001755 - 0.000702 x + 0.000351 x² = 4x²

3.99965 x² + 0.000351 x - 0.0001755 = 0

Using the quadratic formula:

x = (-0.000351 ± √(0.000351² + 4(3.99965)(0.0001755) / (2(3.99965))

x ≈ 0.025 M (rounded to three decimal places)

Therefore, the equilibrium concentration of HBr is 0.025 M.

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Answer:

8

Explain

H: Ignoring the coefficient, we know there's 5+3=8 atoms

Answer:

Any unapposed interaction that will change the motion of an object.

Explanation:

My physics teacher had us write this down last week.

It is impossible to answer this question without more information about substance x. The solubility of a substance depends on various factors such as temperature, pressure, and the chemical properties of the solute and solvent.

If substance x has a high solubility in water and is stable at 80°C, then it is likely that all of the substance will dissolve in 1 mL of water.

However, if substance x has low solubility in water, then it is possible that only a portion of the substance will dissolve.

Additionally, if substance x is unstable at 80°C, it may decompose or react with the water, which could also affect its solubility.

Therefore, without additional information about substance x, it is not possible to determine whether or not all of it will dissolve in 1 mL of water heated to 80°C.

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Answer:

42.2075 grams

Explanation:

Explanation:

first of all open the menu

Answer:

Thermal is the heat coming through  the pot . Radiation is the waves of heat coming off of the pot. Convection is the water that is being heated.

Explanation:

Answer:

Radiation: heat of the steam

Conduction: pot on your hand

Convection: ????

Explanation:

helo

When a solute dissolves, each of its atoms, molecules, or ions interacts with the solvent to become solvated and is then free to spread throughout the solution on their own.

Thus, However, this is not a one-way process. A process known as crystallization may occur if a molecule or ion happens to collide with the surface of an undissolved solute particles and solvent.

As long as there is surplus solid present, dissolution and crystallization proceed, creating a dynamic equilibrium similar to the equilibrium that maintains the vapour pressure of a liquid and solvent.

A solute's solubility is the greatest amount of that solute that can dissolve in a solvent at a given temperature and pressure. The moles of solute per volume (mol/L) or the mass of solute per mass of solvent (g/g) are other common ways to express solubility.

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The salt that would lower the freezing point of water the most is sodium chloride.

Sodium chloride is the most effective salt at decreasing the freezing point of water. This is because sodium chloride has the highest solubility of all the salts, meaning that it can dissolve and form a solution with a higher concentration of solute. This leads to a decrease in the freezing point of water, as the solute molecules interfere with the structure of the water molecules and prevent them from forming an orderly pattern. Other salts, like potassium chloride, magnesium sulfate, and calcium chloride, may still lower the freezing point of water, but to a lesser degree compared to sodium chloride.

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Calcium chloride is the salt which lower the freezing point of water the most.

The freezing point can be defined as the is the exact temperature at which a liquid becomes a solid. The freezing point of water is 32 degrees Fahrenheit. Freezing point describes the moment of transition much as the melting point captures the moment when ice turns from a solid to a liquid. Normal fresh water freezes at 32 degrees Fahrenheit and seawater freezes at about 28.4 degrees Fahrenheit because of the salt in it. Calcium chloride is highly soluble in water. It lowers the freezing point of water the most. Both calcium chloride and magnesium chloride have lower the freezing points. When calcium chloride comes in contact with ice, it rapidly lowers the freezing point of water and melts snow and ice quickly. Calcium chloride forms brine faster than other salts because of its hygroscopic properties.

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The complete question is,

Assuming all the salts below are the same concentration, which salt would lower the freezing point of water the most?

(a) magnesium chloride

(b) calcium chloride

(c) sodium chloride

We need 0.0161 liters of the 2.07 M sulfuric acid solution to make 57 milliliters of a 0.58 M solution of sulfuric acid.

We need to use the formula:

C1V1 = C2V2

Where

We want to find the volume of the 2.07 M sulfuric acid solution needed to make 57 milliliters of a 0.58 M solution. Let's plug in the values we know:

2.07 M * V1 = 0.58 M * 57 mL

Simplifying the equation, we get:

V1 = (0.58 M * 57 mL) / 2.07 M

V1 = 16.0874 mL

To convert the volume to liters, we divide by 1000:

V1 = 16.0874 mL / 1000 mL/L

V1 = 0.0161 L

Therefore, we need 0.0161 liters of the 2.07 M sulfuric acid solution to make 57 milliliters of a 0.58 M solution of sulfuric acid.

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Answer:

I think 4 I can't remember

Answer:

jznsvsjdnxb xhxbdsnbsbxbxbx

Answer:

72 g

Explanation:

n=m/mr

m=n*mr

=4*(2+16)

+72 g

30 ml volume of water have to add to 15. 0 ml of 12 m hcl to make it to 6. 0 m solution.

How do you calculate the volume of a solution needed?

Given data

So first we set up the dilution equation: M1*V1=M2*V2

M: Molarity

V: Volume

We can set these equal in a dilution equation because Molarity is Miles per Volume, and by multiplying it by Volume we get Moles on each side. Moles of solute remain equal throughout a dilution since you are just adding water.

Next, we plug in our knowns:

(12.00M HCl)(15.00ml)=(6.00M HCl)(V2)

V2 = 15 X 12 / 6 = 30ML

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Answer:

Answer is A

Explanation:

this is because selective breeding means selecting plants or animals having desired characteristics and let them breed with each other to reproduce an offspring having desired characteristics from both parents.

Answer:

A

Explanation:

7.3 mL of NaOH are used to titrate the 10.00 mL aliquot.

The balanced equation for the reaction between NaOH and HCl is:

NaOH(aq) + HCl(aq) → H₂O(l) + NaCl(aq)

To calculate the volume of NaOH used,  determine how much HCl is left after it reacts with the CaCO₃, and then how much NaOH is required to neutralize that remaining HCl.

Step 1: Calculate the moles of HCl used to react with CaCO₃

The balanced equation for the reaction between CaCO₃ and HCl is:

CaCO₃(aq) + 2HCl(aq) → CaCl₂(aq) + H2O(l) + CO₂(g)

From the balanced equation, we can see that 1 mole of CaCO₃ reacts with 2 moles of HCl. Therefore, the number of moles of HCl used to react with the CaCO₃ is:

moles HCl = (7.50 mL)(2.00 mol/L) = 0.015 mol

Step 2: Calculate the concentration of HCl in the 125.0 mL solution

Started with 7.50 mL of 2.00 M HCl, which is equivalent to 0.015 moles of HCl. We added enough water to make a 125.0 mL solution, so the concentration of HCl in the solution is:

C = moles of HCl / volume of solution in L

C = 0.015 mol / 0.125 L = 0.12 M

Step 3: Calculate the moles of HCl remaining in the 10.00 mL aliquot

moles NaOH = moles HCl remaining in aliquot

(C of NaOH)(volume of NaOH) = (C of HCl)(moles of HCl remaining in aliquot)

(0.058 mol/L)(volume of NaOH) = (0.12 mol/L)(moles of HCl remaining in 10.00 mL aliquot)

moles of HCl remaining in 10.00 mL aliquot = moles of HCl in 125.0 mL solution - moles of HCl used to react with CaCO₃

moles of HCl remaining in 10.00 mL aliquot = (0.12 mol/L)(0.125 L) - 0.015 mol = 0.0035 mol

Substituting this into the equation gives:

(0.058 mol/L)(volume of NaOH) = (0.12 mol/L)(0.0035 mol)

volume of NaOH = (0.12 mol/L)(0.0035 mol) / (0.058 mol/L) = 0.0073 L

Step 4: Convert the volume of NaOH to mL

volume of NaOH = 0.0073 L x (1000 mL / 1 L) = 7.3 mL

Therefore, 7.3 mL of NaOH are used to titrate the 10.00 mL aliquot.

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