During which interval is the largest amount of energy required to stretch the spring? As illustrated in the figure, a spring with spring constant k is stretched from x = 0 to x = 3d. where x = 0 is the equilibrium position of the spring. From x = 0 to x = d From x = d to x = 2d From x = 2d to x = 3d The energy required is the same in all three intervals. This question will be shown after you complete previous question This question will be shown after you complete previous question(s).

Answers

Answer 1

The interval in which the largest amount of energy required to stretch the spring is from x = d to x = 2d. The reason is that the work done in stretching a spring is directly proportional to the square of the distance stretched from the equilibrium position.

Let’s use the following formula to determine the energy required to stretch the spring:

(1/2)kx²

where k = spring constant and x = distance stretched from the equilibrium position

Given the figure, the distances that the spring is stretched from the equilibrium position during the three intervals are:

x = d (distance stretched from x = 0 to x = d)

x = 2d - d = d (distance stretched from x = d to x = 2d)

x = 3d - 2d = d (distance stretched from x = 2d to x = 3d)

Therefore, the energies required to stretch the spring during the three intervals are:

(1/2)kd² for x = d(1/2)k(2d)² = (1/2)k4d² = 2kd² for x = 2d(1/2)k(3d)² - (1/2)k(2d)² = (1/2)k9d² - (1/2)k4d² = (1/2)k5d² for x = 3d

Since (1/2)kd² < 2kd² < (1/2)k5d², the energy required to stretch the spring is largest in the interval from x = d to x = 2d.

The formula for the energy stored in a spring is:

(1/2)kx²

where k is the spring constant, and x is the displacement from the equilibrium position. The unit of the spring constant is N/m, and that of the displacement is m. The formula shows that the energy stored in a spring is proportional to the square of the displacement of the spring from its equilibrium position.

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Related Questions

* An 10 kg box is sitting on a fairly smooth surface. Friction is still present. The coefficient of static friction
is Hs = 0.25 and the coefficient of kinetic friction is pk = 0.15. If you exert a force of 25 N, determine if
the object is moving and if so calculate the acceleration of the object

Answers

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Answers

Answer:

should be D

Explanation:

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Does earths gravitational force field act on objects that aren’t touching earths surface?

( Explanation needed ASAP NEEDED

Answers

Answer:

no the earth gravitational force field

Answer:

yes, it acts on everything within the earth

Explanation:

A vector points -43.0 units along the x axis, and 11.1 units along the y axis. Find the Direction of the vector.

Answers

Answer:

Explanation:

The direction of the vector implies only its angle, not its magnitude. The direction of the vector is found in

\(tan^{-1}(\frac{y}{x})\) so

\(tan^{-1}(\frac{11.1}{-43.0})=-14.5\) but since we are in QII (where x is negative and y is positive) we have to add 180 to this number to get a direction of 165.5 degrees

with what speed in m/s must an object be thrown to reach a height of 91.5 m (equivalent to one football field)? a

Answers

The object must be thrown with a speed of approximately 42.2 m/s to reach a height of 91.5 m (equivalent to one football field).

The conservation of energy principle can be used to calculate the starting speed necessary to reach a specific height. The object's potential energy, which is determined by its height, is at its peak and its kinetic energy, which is determined by its velocity, is zero at the highest point of its trajectory. Hence, disregarding air resistance, the object's initial kinetic energy must be equal to its potential energy at the highest point of its trajectory. This can be written mathematically as:

\((1/2)mv^2 = mgh\)

where m is the mass of the object, v is its initial speed, g is the acceleration due to gravity, and h is the maximum height reached by the object.

Solving for v, we get:

v = sqrt(2gh)

Plugging in the values of \(g = 9.81 m/s^2\)and h = 91.5 m, we get:

v =\(sqrt(2 x 9.81 x 91.5)\) = 42.2 m/s

Therefore, the object must be thrown with a speed of approximately 42.2 m/s to reach a height of 91.5 m.

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a ball dropped from a height of m makes an elastic collision with the ground. assuming no decrease in mechanical energy due to air resistance, (a) show that the ensuing motion is periodic and (b) determine the period of the motion. (c) is the motion simple harmonic? explain.

Answers

a. The ball bounces back up to its original height after each collision. b. The period of the motion depends only on the mass of the ball and the strength of gravity. c. the motion is not sinusoidal .

Define the terms "collision" and "resistance." A collision occurs when two objects come into contact with each other and exchange momentum and/or energy. Resistance, in the context of physics, refers to any force that opposes motion or energy transfer.
Now, let's apply these concepts to the question at hand. A ball dropped from a height of m undergoes an elastic collision with the ground, which means that there is no loss of mechanical energy due to the collision. This implies that the ball will rebound back up to its original height.
(a) To show that the ensuing motion is periodic, we need to demonstrate that the ball's motion repeats itself over time. Since the ball bounces back up to its original height after each collision, we can see that the motion is indeed periodic.
(b) The period of the motion is the time it takes for one complete cycle. In this case, one complete cycle consists of the ball falling from its original height, colliding with the ground, and rebounding back up to its original height. The time it takes for the ball to complete this cycle can be calculated using the formula:
T = 2 × √(m/g)
where T is the period of the motion, m is the mass of the ball, and g is the acceleration due to gravity. This formula tells us that the period of the motion depends only on the mass of the ball and the strength of gravity, and is independent of the height from which the ball is dropped.
(c) The motion of the ball is not simple harmonic because it does not follow the equation of motion for a simple harmonic oscillator, which is:
x = A × cos(ωt + Ф)
where x is the displacement of the oscillator, A is the amplitude of the motion, ω is the angular frequency, t is time, and Ф is the phase angle. In the case of the ball bouncing off the ground, the motion is not sinusoidal and does not follow this equation.

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TRUE OR FALSE the nitrogen geysers of triton carry carbon grit into the winds of its atmosphere.

Answers

The statement that the nitrogen geysers of Triton carry carbon grit into the winds of its atmosphere is false.

Triton is a moon of the planet Neptune, and it is known for its unique geological features, including nitrogen geysers. These geysers are believed to erupt from beneath the surface, expelling nitrogen gas and dust particles into space. However, there is no evidence or scientific consensus to suggest that these geysers carry carbon grit into the winds of Triton's atmosphere.

Carbon grit refers to small particles of carbonaceous material, such as soot or dust. While carbon compounds have been detected on Triton's surface, primarily in the form of organic molecules, there is no specific information or observations indicating the presence of carbon grit being transported by nitrogen geysers or carried into Triton's atmosphere.

The understanding of Triton's atmosphere and geology is based on limited direct observations, as the Voyager 2 spacecraft provided the most detailed data during its flyby in 1989. Further investigations and future missions may provide additional insights into the composition and dynamics of Triton's atmosphere and the role of geysers in its overall processes.

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A 2.9×10^−4 V/m electric field creates a 2.0×10^17 electrons/s current in a 2.0-mm -diameter aluminum wire.

a. What is the drift speed?
b. What is the mean time between collisions for electrons in this wire?

Answers

a) Therefore, the drift speed is 5.47 × 10⁻⁵ m/s.

b) The mean time between collisions for electrons in this wire is 2.28 × 10⁻⁵ s.

a. To determine the drift speed v_d, we need to use the formula:

I = nAv_dq,

where I is the current, n is the electron density, A is the cross-sectional area of the wire, q is the electron charge, and v_d is the drift speed.

Rearranging this equation, we get:

v_d = I/(nAq)

Substituting the given values, we get:

v_d = (2.0 × 10¹⁷ electrons/s)/(2.0 × 10⁻⁶ m² × 2.9 × 10⁻⁴ V/m × 1.6 × 10⁻¹⁹ C)

v_d = 5.47 × 10⁻⁵ m/s

b. To determine the mean time between collisions, we need to use the formula:

t = l/v_d,

where l is the mean free path of the electrons in the wire.

The mean free path can be estimated using the formula:

l = 1/(nσ),

where σ is the electron collision cross-sectional area.

The electron collision cross-sectional area for aluminum can be estimated to be approximately 4 × 10⁻¹⁹ m².

Substituting the given values, we get:

l = 1/(2.0 × 10²⁸ m⁻³ × 4 × 10⁻¹⁹ m²)

l = 1.25 × 10⁻⁹ m

Substituting the value of l and the drift speed v_d, we get:

t = l/v_d

t = (1.25 × 10⁻⁹ m)/(5.47 × 10⁻⁵ m/s)

t = 2.28 × 10⁻⁵ s

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What happens in both hemispheres when Earth is at position c

What happens in both hemispheres when Earth is at position c

Answers

When the Earth is at point C, Equinox happens.

In Equinox, the Sun is directly above the equitor making day and night equal in both hemispheres.

A positive charge is moving across a room from south to north. A magnetic field runs from east to west. In what direction is the magnetic force on the moving positive charge?

Answers

Answer:

the force is on the z axis, coming out of the blade

Explanation:

The direction of the magnetic force is given by the right hand rule,

For a positive charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm points in the direction of force.

In this case.

Thumb points North

The fingers extended is in the east - west direction parallel to the blade

The palm is sticking out of the leaf, in the z direction

the answer is the force is on the z axis, coming out of the blade

A rod is made up of copper and wood joined together.
After the rod is heated at the join in the centre for about a minute, where would the lowest temperature be?

Answers

my views

Explanation:

Figure (8) shows a rod made up of copper and wood joined together. The rod is heated at the joint in the centre for about a minute. At which point – A, B, C or D, would it show the lowest temperature? PLEASE GIVE REASONS ALSO(MINIMUM 2)

The room temprature (25 C) fats in unsaturated fatty acids are

Answers

Unsaturated fats have one or more double bonds inside their fatty acid chains. The two carbons on the hydrocarbon molecules each have triple or double bonds, and hydrogens cannot saturate them. They are also liquid

The distance between corresponding points on a wave's cycle is called its ____.
a. amplitude
b. wavelength
c. phase
d. frequency

Answers

The distance between corresponding points on a wave's cycle is called its wavelength.

The wavelength of a wave is the distance between two corresponding points on the wave, such as the distance between two peaks or two troughs. It is usually measured in meters, centimeters, or nanometers, depending on the type of wave. The wavelength of a wave is related to its frequency and speed by the equation: wavelength = speed / frequency. The wavelength is an important characteristic of a wave, as it affects its properties such as diffraction, reflection, and interference.

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We start with 5.00 moles of an ideal monatomic gas with an initial temperature of 133 ∘C. The gas expands and, in the process, absorbs an amount of heat equal to 1140 J and does an amount of work equal to 2160 J .
A.) What is the final temperature Tfinal of the gas? Use R = 8.3145 J/(mol⋅K) for the ideal gas constant.

Answers

The final temperature Tfinal of the gas is approximately 92.04 °C.

What is the temperature of the gas after expansion?

When a monatomic gas undergoes expansion and absorbs heat while doing work, we can analyze the process using the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat (Q) absorbed by the system minus the work (W) done by the system:

ΔU = Q - W

For an ideal monatomic gas, the change in internal energy can be expressed as:

ΔU = (3/2) nR ΔT

where n is the number of moles of the gas, R is the ideal gas constant, and ΔT is the change in temperature.

We are given that the gas absorbs 1140 J of heat (Q) and does 2160 J of work (W). Since the gas absorbs heat and does work, both Q and W have positive values in this case.

Therefore, we can rewrite the first law of thermodynamics equation as:

(3/2) nR ΔT = Q - W

Substituting the given values, we have:

(3/2) (5.00 mol) (8.3145 J/(mol⋅K)) ΔT = 1140 J - 2160 J

Simplifying the equation, we find:

24.94375 ΔT = -1020 J

Dividing both sides by 24.94375, we get:

ΔT = -1020 J / 24.94375

ΔT ≈ -40.96 °C

Finally, we can calculate the final temperature Tfinal by adding the change in temperature to the initial temperature:

Tfinal = 133 °C + (-40.96 °C)

Tfinal ≈ 92.04 °C

Therefore, the final temperature Tfinal of the gas is approximately 92.04 °C.

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(390-8) When an outlet from an underfloor raceway is discontinued, the circuit conductors supplying the outlet _____.

Answers

When an outlet from an Underfloor raceway is discontinued, the circuit conductors supplying the outlet must be disconnected, isolated, and insulated from any possible contact with other conductors. This ensures safety and prevents potential short circuits or other electrical hazards. The underfloor raceway is a system used in commercial buildings to distribute electrical power and data cabling underneath the raised floor. It typically consists of metal or plastic conduit channels installed below the floor surface, providing a concealed pathway for routing electrical conductors.

The circuit conductors supplying power to that outlet are disconnected and terminated properly. This may involve removing the outlet box, disconnecting the conductors from the circuit breaker or fuse panel, and properly capping or terminating the conductors to ensure they are safely and securely isolated from the electrical system. Following local electrical codes and best practices is essential to ensure the safe and efficient operation of the electrical system.

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An Atwood's machine consists of blocks of masses m1 = 13.0 kg and m2 = 17.0 kg
attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass M = 8.60 kg and radius r = 0.200 m. The block of mass m2 is allowed to drop, and the cord turns the pulley without slipping.
(a) Why must the tension T2 be greater than the tension T1?
(b) What is the acceleration of the system, assuming the pulley axis is frictionless? (Give the magnitude of a
c) find the tensions
T1 =
T2 =

Answers

(a) The tension T2 must be greater than the tension T1 because it is pointing downwards, supporting both masses.

(b) The acceleration of the system is 9.74 m/s².

(c) The tension in T₁ is -0.78 N and T₂ is 1.02 N.

What are the tension in the cord?

There are two tensions in the cord and their magnitude is obtained from the following equation.

T₁ = m₁a - m₁g

T₁ = m₁ (a - g )

T₂ = m₂g - m₂a

T₂ = m₂ (g - a )

The resultant tension in the cord is determined as;

( T₂ - T₁)R = Iα

where;

R is the radius of the pulleyI is the moment of inertia of the pulleyα is the angular acceleration of the system

( T₂ - T₁)R = I(aR)

where;

a is the tangential acceleration

T₂ - T₁ = Ia

m₂g - m₂a - ( m₁a - m₁g ) = Ia

m₂g - m₂a - m₁a + m₁g = Ia

- m₂a - m₁a + m₂g + m₁g = Ia

a(m₂ + m₁) + Ia = m₂g + m₁g

a (m₂ + m₁ + I ) = m₂g + m₁g

a = ( m₂g + m₁g ) / ( m₂ + m₁ + I )

I = ¹/₂MR²

I = ¹/₂ x 8.6 x 0.2²

I = 0.172 kgm²

a = ( 17 x 9.8  + 13 x 9.8 ) / ( 17 + 13 + 0.172 )

a = 9.74 m/s²

The tension in the cords is calculated as;

T₁ = m₁ (a - g )

T₁ = 13 (9.74 - 9.8 )

T₁ = -0.78 N

T₂ = 17 (9.8 - 9.74 )

T₂ = 1.02 N

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An Atwood's machine consists of blocks of masses m1 = 13.0 kg and m2 = 17.0 kgattached by a cord running

What problems would we have if Pascal had failed to give the Pascal's law? Write some points.

Answers

Hydraulic jacks, automobile brakes and even the lift generated on airplane wings can be explained using Pascal's principle. Pascal's principle is based on the idea that fluids at rest are incompressible, allowing very large forces to be transmitted with the application of a smaller force.

Answer:

Pascal's law states that a change in pressure at any point in an enclosed fluid is transmitted equally throughout the fluid.

Explanation:

Applications of Pascal's law include

>The hidden standard of the water powered jack and pressure driven press.  

>Power intensification in the slowing mechanism of most engine vehicles.  

>Utilized in artesian wells, water pinnacles, and dams.  

>Scuba jumpers must comprehend this rule. At a profundity of 10 meters submerged, pressure is double the environmental weight adrift level, and increments by around 100 kPa for each expansion of 10 m depth.[5]  

>Generally Pascal's standard is applied to bound space (static flow), however because of the consistent flow process, Pascal's rule can be applied to the lift oil instrument (which can be represented as a U tube with pistons on either end).

Without Pascal's law, none of the above could be possible.

Which list correctly names the three types of galaxies? binary, open, globular elliptical, open, binary irregular, spiral, elliptical open, irregular, spiral

Answers

The names the three types of galaxies are: spiral, elliptical, irregular.

What are galaxies?

A galaxy is a vast collection of stars, solar systems, gas, and dust. Gravity holds a galaxy together. A supermassive black hole also resides in the center of our galaxy, the Milky Way.

You see other stars in the Milky Way as you look up at the stars in the night sky. If it's truly dark and you're distant from any cities or residences with lights, you can even make out the Milky Way's dusty bands tracing a path across the sky.

A few galaxies resemble our own in spiral shape. They have curved arms that give it a pinwheel-like appearance. Others have smooth surfaces and oval shapes. We refer to them as elliptical galaxies. There are galaxies that are neither spirals nor ovals, though. They resemble blobs and have irregular forms. Each of these galaxies emits light that we can see from its stars.

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Galaxies are classified based on their shape. The three types of galaxies are spiral, elliptical, and irregular galaxies.

What is a galaxy?

Galaxies are the biggest group of stars and contain a few million stars to many billions of stars. It is also considered the vast cosmic island made up of stars, dust, and dark matter held together by gravity.

Every star in the night sky is the part of Milky Way galaxy and the solar system is present in this galaxy. The closest galaxy to the Milky Way is the Andromeda galaxy.

Galaxies are classified based on their shape and hence they are elliptical, spiral, and irregular galaxies. Spiral galaxies are galaxies that are spiral in shape and appear as a rotating disk of stars and dust. This galaxy contains lots of dust, gas, and young stars.

Elliptical galaxies are the galaxies that are elliptical in shape. The smallest elliptical galaxies are small as globular clusters and the large elliptical galaxies contain trillions of stars. This galaxy contains old stars and hence the galaxy is yellowish in colour.

The galaxies that have not come under the elliptical and spiral galaxies are called irregular galaxies. The spiral galaxies and elliptical galaxies get deformed by gravity and form irregular galaxies.

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worries that critics have, in regards to genetically engineered crops in Africa are as follows:
a. The significant impact the genetically engineered crops could have on trade in the region.
b. Dependency on foreign private sector businesses for technology needs.
c. The concern over how compatible the genetically engineered crops will be with local farming standards.

Answers

The worries that critics have regarding genetically engineered crops in Africa include potential impacts on trade, dependency on foreign technology, and concerns about compatibility with local farming practices.

a. The significant impact the genetically engineered crops could have on trade in the region: Genetically engineered crops could potentially have a significant impact on trade in the region as they could flood the market, thereby disrupting existing farming systems and potentially leading to the displacement of small-scale farmers.

b. Dependency on foreign private sector businesses for technology needs: Critics have expressed concerns about the dependency of African countries on foreign private sector businesses for technology needs related to genetically engineered crops.

c. The concern over how compatible the genetically engineered crops will be with local farming standards: Critics are also concerned about the compatibility of genetically engineered crops with local farming standards and practices, as well as their potential impact on the environment and human health.

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Critics of genetically engineered crops in Africa have several concerns, including The potential impact these crops may have on regional trade, as they could affect export markets and trading relationships.

A growing dependency on foreign private sector businesses for technology needs might lead to a loss of control over agricultural resources and practices. Compatibility issues with local farming standards, as genetically engineered crops, may not align with traditional methods or environmental considerations, potentially disrupting the local agricultural systems. Engineered refers to something that has been intentionally designed, constructed, or modified using scientific principles and specialized knowledge to achieve a specific function or purpose. The term is often used to describe products, systems, or structures that require a high degree of precision, reliability, and efficiency. Examples of engineered products include aircraft, automobiles, bridges, computers, and medical devices. Engineers are professionals who apply their scientific and technical expertise to design and develop these products, as well as to solve complex problems in various fields such as civil, mechanical, electrical, and aerospace engineering. Engineered products and solutions play a critical role in modern society, improving our quality of life and driving innovation and economic growth.

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what is the derived relationship between molar mass and delta t

Answers

The relationship between molar mass and delta t (Δt) is derived from the colligative properties of solutions. Colligative properties are those properties that depend on the number of solute particles in a given volume of solution, regardless of the type of solute particles.

One of the colligative properties is the freezing point depression, which is the difference between the freezing point of a pure solvent and the freezing point of a solution containing a solute. The freezing point depression is directly proportional to the molality (moles of solute per kilogram of solvent) of the solution, and inversely proportional to the molar mass of the solute. This can be mathematically expressed as Δt = Kf * m * (1/M), where Δt is the freezing point depression, Kf is the freezing point depression constant, m is the molality of the solution, and M is the molar mass of the solute. Therefore, as the molar mass of the solute increases, the freezing point depression decreases, and vice versa. This relationship can be useful in determining the molar mass of an unknown solute in a solution.

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The Witness Experimenter configure options include a Skip field. What does the skip value do? a. Increases the simulation run speed b. Resets the statistics for the warm up period c. Sets the length of the warm up period d. Misses out a different number of random numbers for each replication e. Changes the random number streams for each replication

Answers

The Witness Experimenter configure options include a Skip field that misses out on a different number of random numbers for each replication (Option D).

What are the Experimenter configure options?

Experimenter configure options are some basic settings of a Witness experiment. These settings influence how the experiment would behave and what output is produced. With the help of configure options, you can set the value of random number streams and skip replication.

The skip value misses out on a different number of random numbers for each replication. As a result, this provides some level of control over the replication. By changing the value of the skip, you can control which random numbers should be missed and which should not be missed. In addition, by using the skip field, you can increase the simulation run speed. As a result, you get better output in less time.

Thus, the correct option is D.

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The concept of habituation is best exemplified by which of the following situations?
a. An infant recognizes her father's voice
b. A college student is no longer kept awake by her roommate's late night typing.
c. a kitten avoids a couch after being reprimanded for sitting on it
d. A rat learns to press a bar for food when a red light is flashed
e. A motorist drives at the speed limit when there is a police driver in sight on the highway

Answers

The concept of habituation is best exemplified by situation b, where a college student is no longer kept awake by her roommate's late night typing.

Habituation refers to the decrease in responsiveness to a stimulus after repeated exposure to it. This means that over time, the student becomes less and less responsive to the sound of typing, and it no longer disrupts her sleep.

Habituation is a basic form of learning and is thought to be an adaptive mechanism, allowing organisms to conserve energy by ignoring irrelevant stimuli. It is often observed in infants and young animals, but can occur in any organism that is capable of learning.

In situation a, an infant recognizes her father's voice, this is not an example of habituation, but rather an example of classical conditioning. In situation c, a kitten avoids a couch after being reprimanded for sitting on it, this is an example of classical conditioning or a form of punishment-based learning. In situation d, a rat learns to press a bar for food when a red light is flashed, this is an example of operant conditioning. And in situation e, a motorist drives at the speed limit when there is a police driver in sight on the highway, this is an example of social learning.

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a reservoir dam holds an 8 km2 lake behind it. just behind the dam, the lake is 12.5m deep. what is the gauge pressure at the base of the dam (in pascals)?

Answers

The gauge pressure at the base of the dam will be 126,175Pa.

What is gauge pressure?
It is the pressure measured relative to the ambient atmospheric pressure. Gauge pressure is typically used in processes where pressure cannot dip below atmospheric pressure, such as when measuring and controlling tire pressure.

Now we're going to use the gauge pressure formula.

Gauge pressure = ρgh

ρ = density of liquid = 1030 kg/m³

g = earth gravity = 9.8 m/s²

h = the depth = 12.5m

Gauge pressure = 1030 * 9.8 * 12.5 = 126,175Pa

So the gauge pressure at the base of the dam is 126,175Pa

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Question 6 of 10
A scientist adds different amounts of salt to 5 bottles of water. She then
measures how long it takes for the water to boil. What is the responding
variable in this experiment?
A. The amount of salt added to the water
B. The brand of salt used
C. The kind of bottles used
D. The time it takes for the water to boil
SUBMIT

Answers

D. The time it takes for the water to boil.


If a 2 meter diameter ball representing the Sun were placed in Center Circle in Indianapolis, how far away should the Earth be placed?

Answers

By applying the correspondent change of scale, we will see that Earth should be placed 214.8m away from the scale sun.

How far the Earth should be placed?

The real radius of the Sun is:

R = 696,340 km

And the radius of the scale Sun is 1m, then we have the relation:

1m = 696,340 km

1 = (1m/696,340 km)

Now, the real distance between the Sun and Earth is:

d = 149,600,000 km

If we apply the change of scale we have above, we will get:

d =  149,600,000 km*(1m/696,340 km) = 214.8m

So the Earth should be placed at 214.8m of the ball that represents the sun.

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What is the decay mode of the following decay? 222Rn- 218Po ? A. Alpha decay B. Beta-minus decay C. Beta-plus decay D. Gamma decay

Answers

The decay mode of the decay from 222Rn to 218Po is A. Alpha decay.

In this process, a radioactive nucleus emits an alpha particle, which consists of 2 protons and 2 neutrons, resulting in a decrease in the atomic mass by 4 units and the atomic number by 2 units. In the case of 222Rn, the atomic number is 86 and the atomic mass is 222. When it undergoes alpha decay, it loses 4 mass units and 2 protons, transforming into 218Po with an atomic number of 84 and an atomic mass of 218.

This type of decay is common in heavy nuclei with an excess of protons and neutrons, as it helps stabilize the nucleus. Alpha decay is one of the most common modes of radioactive decay, and its occurrence can be predicted by analyzing the nuclear properties of the parent and daughter nuclei, such as binding energy, stability, and decay constants. So therefore the correct answer is a. alpha decay, the decay mode of the decay from 222Rn to 218Po.

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x = 3t2 - 18t . Find position when velocity is zero
x = at3+bt2+ct+d , Find dimensions of a,b,c,d. ( Where x is position and t is time)

Answers

(a) The position of the particle when velocity is zero is - 27 m.

(b) The dimensions of a, b, c, and d are LT⁻³, LT⁻², LT⁻¹ and L respectively.

Velocity of the particle

The velocity of the particle is change in position of the particle with time.

v = dx/dt

v = 6t - 18

when velocity = 0

0 = 6t - 18

6t = 18

t = 18/6

t = 3 seconds

Position of the particle at 3 seconds

x = 3(3²) - 18(3)

x = -27 m

Dimensions of a, b, c, d

x = at³ + bt²  + ct + d

if t is in seconds and x is meters, the dimensions of a, b, c, and d is calculated as;

x(m) = at³(m/s³) + bt²(m/s²) + ct(m/s) + d(m)

Thus, the dimensions of a, b, c, and d are LT⁻³, LT⁻², LT⁻¹ and L respectively.

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Suppose you drop a rock into a dark well and, using precision equipment, you measure the time for the sound of a splash to return. Neglecting the time required for sound to travel up the well, calculate the distance to the water if the sound returns in 2. 00 s.

Answers

Answer:

Approximately \(19.6\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance is negligible.)

Explanation:

Assume that the air resistance on the rock is negligible. During the descent, the acceleration \(a\) of the rock will be constant: \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\).

It is given that the descent took \(t = 2.00\; {\rm s}\). Let \(x\) denote the displacement (change in position) of the stone. Apply the SUVAT equation \(x = (1/2)\, a\, t^{2}\) to find displacement \(x\!\):

\(\begin{aligned}x &= \frac{1}{2}\, a\, t^{2} \\ &= \frac{1}{2}\, ((-9.81)\; {\rm m\cdot s^{-2}})\, (2.00\; {\rm s})^{2} \\ &\approx (-19.6)\; {\rm m}\end{aligned}\).

Note that \(x\) is negative since the water is below the initial position of the rock. Therefore, the distance to the water will be approximately \(19.6\; {\rm m}\).

Why are speeding tickets not the best punisher for reducing speeding behavior?

Because they are not given out every time one speeds
Because they are not expensive enough to be an intense punishen
Because not everyone perceives tickets as bad
Because they are a positive punisher rather than a negative punisher

Answers

Speeding tickets are not the best punisher for reducing speeding behavior because not everyone perceives tickets as bad .So  option C is correct.

Here are some other reasons why speeding tickets may not be the best punisher for reducing speeding behavior:

   They are not always given out. Police officers may not always be able to stop and ticket every driver who is speeding.    They are not always expensive enough. The cost of a speeding ticket may not be enough to deter some drivers from speeding.    They may not be immediate. The time between speeding and receiving a ticket may be long enough for the driver to forget about the speeding and continue to speed.Other methods of reducing speeding behavior, such as increased enforcement and public education, may be more effective than speeding tickets.

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Which of the following types of mirrors refracts light rays that pass through it outward and away from the optical axis?
convex mirrors
plane mirrors
concave mirrors
All of the choices are correct.

Answers

Answer:

convex mirror

Explanation:

A convex mirror or diverging mirror is a curved mirror in which the reflective surface bulges towards the light source. Convex mirrors reflect light outwards, therefore they are not used to focus light.

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