The natural curve of an electrode wire is known as its "arc shape" or "arc bend."
When an electrode wire is manufactured, it typically undergoes a process called winding, where it is wound onto a spool or reel. During this process, the wire takes on a natural curve or bend due to the tension and shape of the spool. This curve is inherent to the wire and is considered its natural state.
The arc shape of the electrode wire is an important characteristic in welding applications. When the wire is fed through a welding torch, it is straightened and guided towards the workpiece. As the electric current passes through the wire, it creates an arc between the wire and the workpiece, generating the heat necessary for the welding process.
The natural curve or arc shape of the electrode wire plays a role in controlling the direction and stability of the welding arc. It helps in achieving consistent arc length, proper penetration, and controlled deposition of the filler material. The arc shape also affects the handling and maneuverability of the wire during welding.
Welders often take the natural curve of the electrode wire into account when setting up their welding equipment and adjusting the torch position. They utilize techniques such as torch angle and travel speed to ensure proper alignment of the wire with the workpiece and to maintain a stable welding arc.
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this is what truthfully struggle with can someone explain how i do this please then imma try it on my own
An athlete completes one round of a circular track of diameter 200 m in 40 s what will be the distance covered and displacement at the end of 2 min 20s
Answer:
700π m ~ 2199 m
Step-by-step explanation:
diameter = d = 200 m
2 min 20s = 140 s
1 round / 40 s
140 = 40 * 3 + 20
so the athlete will cover 3 round and half
1 round = d * π
covered = c = 3 * 200 * π + 200/2 * π = 700 * π
X: 3 6 9 12 y: -22 -43 -64 -85 point-slope form:_ slope-intercept form:
point slope form = y-(-43)=\(-\frac{2}{21}\)(x-3)
slope intercept form = -\(\frac{152}{7}\)=c
What is slope?Finding the ratio of "vertical change" to "horizontal change" between any two unique locations on a line yields the slope. Occasionally, the ratio is written as a quotient (also known as a "rise over run"), which produces the same number for every two unique points on the same line. Negative "rise" refers to a diminishing line. The line could be functional, established by a road surveyor, or depicted in a graphic that represents a road or a roof as a description or a design.
The absolute value of the slope is used to determine how steep, incline, or grade a line is. The steeper the line, the larger the absolute magnitude of the slope. A line's direction might be either horizontal, ascending, decreasing, or vertical
If a line is rising from left to right, it is increasing. Since m>0, the slope is positive.
If a line decreases from left to right, it is said to be diminishing. The slope is inverse, or m0.
A line has zero slope if it is horizontal. This function has a fixed value.
A line's slope is ambiguous if it is vertical.
Slope= \(\frac{x-x1}{y-y1}\)= \(\frac{3-5}{-22+43}\)=\(\frac{-2}{21}\)
point slope form= y-(-43)=\(-\frac{2}{21}\)(x-3)
slope intercept formy=mx+c
-22=\(-\frac{2}{21}\)*3+c
-22+\(\frac{2}{7}\)=c
-\(\frac{152}{7}\)=c
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The weather in Montana
was - 1° F one night and
12° F the next night. How
much warmer was the
temperature the second
night?
Answer:
13 degrees warmer
Step-by-step explanation:
Answer:
13 degrees Fahrenheit.
Step-by-step explanation:
The temperature started at -1 then raises to 12.
So, it goes -1,0,1,2,3,4,5,6,7,8,9,10,11,12, so it increases by 13 degrees Fahrenheit.
Find the critical points, relative extrema, and saddle points. (a) f(x, y) = x3 + x - 4xy – 2y? (b) f(x, y) = x(y + 1) – x2y. (c) f(x, y) = cos x cosh y
a) The critical point is (-1/2, 7/16).
b) The discriminant is negative, the critical points (0, -1) and (1, 1) do not have extrema.
c) all the critical points (nπ, 0) are saddle points.
a) To find the critical points, we need to find the points where the partial derivatives of f(x, y) with respect to x and y are equal to zero.
Partial derivative with respect to x:
∂f/∂x = 3x^2 + 1 - 4y
Partial derivative with respect to y:
∂f/∂y = -4x - 2
Setting these partial derivatives equal to zero and solving the resulting system of equations, we can find the critical points:
3x^2 + 1 - 4y = 0 ...(1)
-4x - 2 = 0 ...(2)
From equation (2), we have -4x - 2 = 0, which gives x = -1/2. Substituting this value of x into equation (1), we get:
3(-1/2)^2 + 1 - 4y = 0
3/4 + 1 - 4y = 0
7/4 - 4y = 0
-4y = -7/4
y = 7/16
Therefore, the critical point is (-1/2, 7/16).
To determine the nature of this critical point, we can calculate the second partial derivatives:
∂²f/∂x² = 6x
∂²f/∂y² = 0
∂²f/∂x∂y = -4
The discriminant for this point is D = (∂²f/∂x²)(∂²f/∂y²) - (∂²f/∂x∂y)² = (6x)(0) - (-4)² = 16.
Since the discriminant is positive and ∂²f/∂x² = 6x, the critical point (-1/2, 7/16) is a relative minimum.
(b) To find the critical points for f(x, y) = x(y + 1) - x²y, we need to find where the partial derivatives with respect to x and y are equal to zero.
Partial derivative with respect to x:
∂f/∂x = y + 1 - 2xy
Partial derivative with respect to y:
∂f/∂y = x - x²
Setting these partial derivatives equal to zero, we get:
y + 1 - 2xy = 0 ...(1)
x - x² = 0 ...(2)
From equation (2), we have x - x² = 0, which gives x(x - 1) = 0. This implies that x = 0 or x = 1.
Case 1: x = 0
Substituting x = 0 into equation (1), we have:
y + 1 = 0
y = -1
Therefore, one critical point is (0, -1).
Case 2: x = 1
Substituting x = 1 into equation (1), we have:
y + 1 - 2y = 0
-y + 1 = 0
y = 1
Therefore, another critical point is (1, 1).
To determine the nature of these critical points, we calculate the second partial derivatives:
∂²f/∂x² = -2
∂²f/∂y² = 0
∂²f/∂x∂y = -2
The discriminant for both critical points is D = (∂²f/∂x²)(∂²f/∂y²) - (∂²f/∂x∂y)² = (-2)(0) - (-2)² = -4.
Since the discriminant is negative, the critical points (0, -1) and (1, 1) do not have extrema.
(c) To find the critical points for f(x, y) = cos(x) cosh(y), we need to find where the partial derivatives with respect to x and y are equal to zero.
Partial derivative with respect to x:
∂f/∂x = -sin(x) cosh(y)
Partial derivative with respect to y:
∂f/∂y = cos(x) sinh(y)
Setting these partial derivatives equal to zero, we get:
-sin(x) cosh(y) = 0 ...(1)
cos(x) sinh(y) = 0 ...(2)
Equation (1) implies that sin(x) = 0, which occurs when x = nπ for n being an integer.
Equation (2) implies that sinh(y) = 0, which occurs when y = 0.
Therefore, the critical points are of the form (nπ, 0), where n is an integer.
To determine the nature of these critical points, we can calculate the second partial derivatives:
∂²f/∂x² = -cos(x) cosh(y)
∂²f/∂y² = cos(x) cosh(y)
∂²f/∂x∂y = -sin(x) sinh(y)
The discriminant for these critical points is D = (∂²f/∂x²)(∂²f/∂y²) - (∂²f/∂x∂y)² = (-cos(x) cosh(y))(cos(x) cosh(y)) - (-sin(x) sinh(y))² = cos²(x) cosh²(y) - sin²(x) sinh²(y).
Since cos²(x) and cosh²(y) are always positive, and sin²(x) and sinh²(y) are always non-negative, the discriminant D will always be non-negative.
Therefore, all the critical points (nπ, 0) are saddle points.
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Please Help!!! I NEED THIS ASAP
person is si mis iosnmasabgoiuwgaufgafuawf
A new solid waste treatment plant is to be constructed in Washington County. The initial installation will cost \( \$ 35 \) million (M). After 10 years, minor repair and renovation \( (R \& R) \) will
The capitalized cost for the solid waste treatment plant, based on a 6% MARR, is approximately $579 million.
To calculate the capitalized cost for the solid waste treatment plant, we need to determine the present value of all the costs over the project's lifespan.
The costs involved in the project are as follows:
Initial installation cost: $35 million.
Minor repair and renovation (R&R) after 10 years: $14 million.
Major R&R after 20 years: $18 million.
Operating and maintenance (O&M) costs each year, increasing at a compound rate of 6% per year.
First, let's calculate the present value of the O&M costs over the 20-year period: Using the TVM Factor Table calculator, the present value factor for a 6% MARR and 20 years is 10.206.
The total O&M costs over 20 years can be calculated as follows: O&M costs for the first year: $3 million. O&M costs for the subsequent years: $3 million * (1 + 0.06) + $3 million * (1 + 0.06)^2 + ... + $3 million * (1 + 0.06)^19.
Using the formula for the sum of a geometric series, the O&M costs over the 20-year period can be calculated as: O&M costs = $3 million * (1 - (1 + 0.06)^20) / (1 - (1 + 0.06)) = $3 million * (1 - 1.418519) / (-0.06) = $3 million * (-0.418519) / (-0.06) = $2.91038 million.
Now, let's calculate the present value of the costs: Present value of the initial installation cost: $35 million.
Present value of the minor R&R cost after 10 years: $14 million * 10.206 (present value factor for 6% MARR and 10 years) = $142.884 million. Present value of the major R&R cost after 20 years: $18 million * 10.206^2 (present value factor for 6% MARR and 20 years) = $371.001 million.
Present value of the O&M costs: $2.91038 million * 10.206 = $29.721 million. Finally, the capitalized cost of the solid waste treatment plant is the sum of all the present values: Capitalized cost = $35 million + $142.884 million + $371.001 million + $29.721 million = $578.606 million.
Rounding the final answer to the nearest whole number, the capitalized cost for the solid waste treatment plant is $579 million.
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The complete question is:
A new solid waste treatment plant is to be constructed in Washington County. The initial installation will cost $35 million (M). After 10 years, minor repair and renovation (R&R) will occur at a cost of $14M will be required; after 20 years, a major R&R costing $18M will be required. The investment pattern will repeat every 20 years. Each year during the 20 -year period, operating and maintenance (O\&M) costs will occur. The first year, O\&M costs will total $3M. Thereafter, O\&M costs will increase at a compound rate of 6% per year. Based on a 6% MARR, what is the capitalized cost for the solid waste treatment plant? Click here to access the TVM Factor Table calculator. $ Carry all interim calculations to 5 decimal places and then round your final answer to a whole number. The tolerance is ±25,000.
If p is the hypothesis of a conditional statement and q is the conclusion, which is represented by q→p?
O the original conditional statement
O the inverse of the original conditional statement
O the converse of the original conditional statement
O the contrapositive of the original conditional statement
Answer:
(c) the converse of the original conditional statement
Step-by-step explanation:
If a conditional statement is described by p→q, you want to know what is represented by q→p.
Conditional variationsFor the conditional p→q, the variations are ...
converse: q→pinverse: p'→q'contrapositive: q'→p'As you can see from this list, ...
the converse of the original conditional statement is represented by q→p, matching choice C.
__
Additional comment
If the conditional statement is true, the contrapositive is always true. The inverse and converse may or may not be true.
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Justine found 6 feet of a string which can make 8 bracelets. If each bracelet was the same length, how long was each bracelet? Enter your answer in the box in the simplest form.
Answer: 3/4 feet
Step-by-step explanation:
There are 6 feet for 8 bracelets, so we can do 6/8 = 3/4 feet
clerks at mosier data systems key in thousands of insurance records each day for a variety of client firms. samples of the work of 20 clerks are gathered. ceo donna mosier carefully examines 100 records entered by each clerk and counts the number of errors. mosier wants to set control limits to include 99.73% of the random variation in the data entry process. which type of process control chart should she use?
Donna Mosier should use an Individuals control chart to set control limits for the data entry process.
An Individuals control chart is a type of process control chart used to monitor the process when the sample size is one. In this case, Mosier is examining 100 records entered by each of the 20 clerks, making the sample size one.
To set control limits that include 99.73% of the random variation in the data entry process, Mosier can use the following steps:
Calculate the mean and standard deviation of the number of errors for each clerk based on the 100 records examined.Calculate the Upper Control Limit (UCL) and Lower Control Limit (LCL) using the formulas: UCL = mean + 3 * standard deviation and LCL = mean - 3 * standard deviation.Plot the individual data points for each clerk on the Individuals control chart, with the UCL and LCL as the upper and lower boundaries, respectively.Monitor the data points over time to detect any trends, shifts, or out-of-control points that may indicate a process issue.By using an Individuals control chart, Mosier can set control limits to monitor the data entry process and detect any issues before they become major problems.
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uh....
yeah
askasasjkas
The relevant details from the poem and the description of how they develop the subject are:
"Then there's a pair of us - don't tell!" - Being nobody does not mean being alone."They'd banish us, you know." - Being nobody is viewed as a bad thing."How dreary to be somebody!" - It can be seen as a positive to be nobody.What do the details in the poem describe?The fact that the narrator mentions how there are a pair of them means that they are not alone. It means that just because they are a nobody does not mean that they consider themselves to be alone.
The fact that they could be banished means that being a nobody is a bad thing that warrants the punishment of being banished from the society in question.
When a person is deary, it means that they are doing something that can either bring them praise or punishment which means that being somebody can either be positive or negative so it can be a positive to be a nobody.
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how many micrograms are in 65.3 kg?
The total number of micrograms present in the 65.3 kilograms is equal to 65,300,000,000 micrograms.
Conversion of units from kilogram to grams is :
1 kilogram = 1,000 grams
Conversion of units from grams to micrograms is :
1 grams = 1,000,000 micrograms
⇒ 1 kilogram = ( 1,000 × 1,000,000 ) micrograms
⇒1 kilograms = 1,000,000,000 micrograms
Substitute the required value for the converting kilogram to micrograms we get,
⇒ 65.3 kilograms = ( 65.3 × 1,000,000,000 ) micrograms
⇒65.3 kilograms = 65,300,000,000 micrograms
Therefore, the total quantity of micrograms in 65.3 kilograms is equal to 65,300,000,000 micrograms.
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What is the measure of the missing angle? 2 56 36 88° O 92° 98° 180°
Answer:
\(?+56+36=180\\?=88\)
Step-by-step explanation:
Is 5.787787778... a rational or irrational number?
Explain.
Answer:
irrational
Step-by-step explanation:
irrational number is an endless number/number that doesnt end and so are that number.
What times what is -10 but when added is -3
Thank you for your help
This is worth 50 B points
Answer:
-5 times 2 is -10
-5+2=-3
Thus the answer is -5 and 2
Step-by-step explanation:
Hope this helps!
Construct a spreadsheet simulation model to simulate 1,000 rolls of a die with the six sides numbered 1, 2, 3, 4, 5 and 6.
a. Construct a histogram of the 1,000 observed dice rolls.
b. For each roll of two dice, record the sum of the dice. Construct a histogram of the 1,000 observations of the sum of two dice.
c. For each roll of three dice, record the sum of the dice. Construct a histogram of the 1,000 observations of the sum of three dice.
d. For each roll of four dice, record the sum of the dice. Construct a histogram of the 1,000 observations of the sum of four dice.
e. Compare the histograms in parts (a), (b), (c), and (d). What statistical phenomenon does this sequence of charts illustrate?
To construct a spreadsheet simulation model that simulates 1,000 rolls of a die with the six sides numbered 1, 2, 3, 4, 5 and 6, the following steps should be followed.
Step 1: Open Microsoft Excel and create a new spreadsheet.Step 2: In cell A1, write the word "Roll". In cell B1, write the word "Outcome".Step 3: In cell A2, type the number "1". In cell B2, enter the formula "=INT(RAND()*6)+1".Step 4: Select cells A2:B2, and drag them down 999 rows.
This will create 1,000 dice rolls.Step 5: Select the data in cells A1:B1000 and click the "Insert" tab at the top of the screen. Click on the "Column" chart icon and select the type of histogram that you want to use.
Step 6: To label the x-axis and y-axis, right-click on the chart and select "Chart Elements". Choose "Axis Titles" and enter "Outcome" for the y-axis and "Roll" for the x-axis.
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Write a simplified expression that represents the perimeter of an irregular quadrilateral with some de lengths (2 1/4t - 5) (4t + 3) (1/2t - 1) (3t + 2)
Answer:
\(Perimeter = \frac{39t-4}{4}\)
Step-by-step explanation:
Given
\(Lengths: (2\frac{1}{4}t - 5), (4t + 3), (1/2t - 1), (3t + 2)\)
Required
Determine the perimeter
The perimeter is calculated as the sum of the lengths of the irregular shape.
i.e.
\(Perimeter = (2\frac{1}{4}t - 5) + (4t + 3) + (1/2t - 1) + (3t + 2)\)
Remove brackets
\(Perimeter = 2\frac{1}{4}t - 5 + 4t + 3 + 1/2t - 1 + 3t + 2\)
Collect Like Terms
\(Perimeter = 2\frac{1}{4}t +4t + 1/2t + 3t - 5 + 3 - 1 + 2\)
\(Perimeter = 2\frac{1}{4}t +4t + 1/2t + 3t -1\)
Convert mixed number to improper fraction.
\(Perimeter = \frac{9}{4}t +4t + 1/2t + 3t -1\)
Take LCM
\(Perimeter = \frac{9t + 16t + 2t + 12t}{4} -1\)
\(Perimeter = \frac{39t}{4} -1\)
Take LCM
\(Perimeter = \frac{39t-4}{4}\) --- The perimeter of the shape
We want to find the perimeter of the irregular quadrilateral given that we know its lengths. By direct computation, we will get:
P(t) = (39/4)*t - 1
Remember that for any figure, the perimeter is defined as the sum of the lengths of each side.
Here we have that the lengths of the four sides of the quadrilateral are:
(2 1/4t - 5)
(4t + 3)
(1/2t - 1)
(3t + 2)
So we must sum that, we will get:
P = (2 1/4t - 5) + (4t + 3) + (1/2t - 1) + (3t + 2)
Notice that in the first part we have a mixed number, we can rewrite it as:
2 + 1/4 = 8/4 + 1/4 = 9/4
Then the sum is:
P = ((9/4)t - 5) + (4t + 3) + (1/2t - 1) + (3t + 2)
Now we simplify this sum:
P = (9/4 + 4 + 1/2 + 3)*t + (-5 + 3 - 1 + 2)
P = (39/4)*t - 1
So the perimeter, as a function of t, is:
P(t) = (39/4)*t - 1
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Point G is on line segment
F
H
‾
FH
. Given
G
H
=
8
,
GH=8,
F
H
=
3
x
+
3
,
FH=3x+3, and
F
G
=
2
x
,
FG=2x, determine the numerical length of
F
G
‾
.
FG
.
The numerical length of the line segment FG is 10 units.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables. An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.
Point G is on FH, hence:
FH = FG + GH
Given that GH = 8, FH = 3x + 3, FG = 2x, hence:
3x + 3 = (2x) + 8
x = 5
FG = 2x = 2(5) = 10
The numerical length of the line segment FG is 10 units.
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On average, 4 customers per hour use the public telephone in the sheriff's detention area, and this use has a Poisson distribution. The length of a phone call varies according to a negative exponential distribution. with a mean of 5 minutes. The sheriff will install a second telephone booth when an arrival can expect to wait 3 minutes or longer for the phone
a. By how much must the arrival rate per hour increase to justify a second telephone booth?
b. Suppose the criterion for justifying a second booth is changed to the following: install a second booth when the probability of having to wait at all exceeds 0.6 Under this criterion, by how much must the arrival rate per hour increase to justity a second booth?
A. The arrival rate per hour must increase to at least 10 customers per hour to justify a second telephone boothe.
B. The arrival rate per hour must increase by at least 1.6 customers per hour to justify a second telephone booth under the new criterion.
How to calculate arrival rateTo get the how much arrival rate must increase, we must get the expected waiting time for a customer.
Assuming;
X is the number of customers who arrive per hour
Y is the length of a phone call in minutes.
Then, X follows a Poisson distribution with λ = 4 (since 4 customers per hour use the phone on average)
Y follows a negative exponential distribution with mean μ = 5 (since the mean length of a phone call is 5 minutes).
Total time is given as sum of waiting time and length of call;
T = W + Y
The waiting time W is the difference between the time a customer arrives and the time that the phone becomes available. waiting time follows a uniform distribution where mean= 1/λ (since the arrivals follow a Poisson process);
Then we have;
E(W) = 1/(2λ) = 1/8 hours
The expected total time T that a customer spends at the phone booth is:
E(T) = E(W) + E(Y) = 1/8 + 5/60 = 11/48 hours
For a second telephone booth to be justifiable, new customer that arrives must wait 3 minutes or longer for the phone.
E(W) ≥ 1/20
To get λ,
1/(2λ) ≥ 1/20
λ ≤ 10
This means that, the arrival rate per hour must increase to at least 10 customers per hour to justify a second telephone booth.
b. Getting how much the arrival rate per hour must increase to justify a second telephone booth under the new criterion,
we need to find the probability that a customer has to wait at all.
Let P(W > 0) be the probability that a customer has to wait.
P(W > 0) = 1 - P(W = 0)
The waiting time W follows a uniform distribution with mean 1/λ, so we have:
P(W = 0) = 1 - λ/4
The length of a phone call Y follows a negative exponential distribution with mean 5 minutes = 1/12 hours, so we have:
P(Y > t) = e^(-μt) = e^(-t/12)
The probability that a customer has to wait is given as;
P(W > 0) = 1 - P(W = 0) = λ/4
To justify a second telephone booth, the probability of having to wait at all must exceed 0.6. so we have;
P(W > 0) > 0.6
λ > 2.4
The arrival rate per hour must increase by at least 2.4 - 4 = 1.6 customers per hour to justify a second telephone booth under the new criterion.
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one side of a regular hexagon is extended to create an exterior angle. what is the measure of such exterior angle?a. 45b. 50c. 60d. 65e. it cannot be determined based on the information provided.
Since one side of a regular hexagon is extended to create an exterior angle, the measure of such exterior angle is: C. 60.
How to determine the exterior angle?In Mathematics and Geometry, the sum of the interior angles of both a regular and irregular polygon is given by this formula:
Sum of interior angles = 180 × (n - 2)
Note: The given geometric figure (regular polygon) represents a hexagon and it has 6 sides.
Sum of interior angles = 180 × (6 - 2)
Sum of interior angles = 180 × 4
Sum of interior angles = 720°.
Each interior angle = 720/6 = 120°.
When the hexagon is extended create an exterior angle, its measure is given by;
x + 120 = 180°.
x = 180° - 120°
x = 60°.
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Rick buys remote control cars to resell. He applies a markup of 20%.
Answer:
what is the question? this is a statement.
Step-by-step explanation:
urt was feeling adventurous at lunch. Rather than choosing a single drink, he decided to mix together all the drink choices. He mixed an equal amount of 7 types of soda to fill his 12-ounce cup to the brim!
How many ounces of each type of soda did Kurt get?
Kurt got about 1.71 ounces (rounded to two decimal places) of each type of soda.
Since Kurt decided to mix equal amounts of all the drinks, the number of ounces of each type of soda can be calculated as follows: dividing the total volume of soda in the cup by the number of types of soda used.
The total volume of soda in the cup is 12 ounces.
The number of types of soda used is 7.
Therefore, the number of ounces of each type of soda Kurt got is 12/7, which equals approximately 1.71 ounces
In conclusion, Kurt obtained approximately 1.71 ounces of each type of soda by mixing equal amounts of all the drinks.
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Which of the following will cause a logical error if you are attempting to compare x to 5?
Answers:
a. if (x >= 5)
b. if (x = 5)
c. if (x == 5)
d. if (x <= 5)
Logical Error: In computer programming language, a logic error is a bug or in a program or code that causes it to operate incorrectly, but not to terminate abnormally (or crash).
A logic error developed unintended or undesired output or other behavior, although it may not immediately be recognized as such.
For example, assigning a value to the wrong variable may cause a many of unexpected program errors.
These errors can be programmer mistakes or sometimes machine less memory to load the code.
if(x>=5) {
// program
}
else if(x==5) {
//program
}
else(x<=5) {
//program
}
they all do not give any error.
x=5 gave an error because it is value assigning to 5.
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A parallelogram has height 9cm and area 45cm? What
is the length of its base?
Answer: Firstly the area of parallelogram is. = b×h. so value of base is 9cm and height is 45cm . So area is equal to. base×height. = 9×45= 405² cm.
405cm²
Find a pattern for the sequence. Use the pattern to show the next two terms.
2, -6, 18, -54. . .
Answer:
34, -102
Step-by-step explanation:
Factor the following binomial using the difference of squares?
(49x^2 – 9)
Five friends are at the movie theater.Each friend has 3/4 of the money needed to buy one bag of popcorn
Answer:
your question is incomplete but I imagine that your asking how many bags of popcorn they can buy? the answer is 3 or 15/4 depending on what your asking.
Step-by-step explanation:
(3/4)5
15/4
Answer:
3 bags your welcome! :D it's right in khan!
Step-by-step explanation:
2) y =14x + 1
UhM helppp
if a person walks 1/4 of a mile in 1/8 of an hour Determined how many miles they are walking per hour
Answer:
if a person walks 1/4 of a mile in 1/8 of an hour Determined how many miles they are walking per hour
2 miles per hour
Please Help 50 POINTS!!
Answer:
D. \(\frac{(x-7)^2}{8^2} -\frac{(y-2)^2}{7^2}\)
Step-by-step explanation:
hope this helps
Answer: D has the largest perimeter
Step-by-step explanation:
The top numbers of fractions describe the vertex and the bottom number square rooted tells you how long each or wide each part of the asymptote rectangle is.
A.
P = 2(11) + 2(3)
P = 22+6
P=28
B.
P = 2(4) + 2(9)
p = 8 +18
P = 26
C.
P = 2(5) + 2(9)
P = 10 +18
P = 28
D.
P = 2(8) + 2(7)
P = 16 +14
P = 30