Emily is pushing a toy sand truck. She realizes it is much harder to push the truck when it is full of sand than when it is empty. What is the reason for this?

An object with a greater mass requires a smaller force to accelerate.
An object with a greater mass requires a greater force to accelerate.
An object pushed with a greater force has a greater mass.
An object pushed with a greater force has less mass.

Oops.

That's my bad then.

Answer:

The percentage uncertainty in his calculated value of density is \(\pm 0.713\,\%\).

Explanation:

We can estimate the absolute uncertainty by the definition of total differential. That is:

\(\Delta \rho \approx \frac{\partial \rho}{\partial m}\cdot \Delta m + \frac{\partial \rho}{\partial d}\cdot \Delta d + \frac{\partial \rho}{\partial l}\cdot \Delta l\) (1)

Where:

\(\frac{\partial \rho}{\partial m}\) - Partial derivative of the density with respect to mass, measured in \(\frac{1}{mm^{3}}\).

\(\frac{\partial \rho}{\partial d}\) - Partial derivative of the density with respect to diameter, measured in grams per cubic milimeter.

\(\frac{\partial \rho}{\partial l}\) - Partial derivative of the density with respect to length, measured in grams per cubic milimeter.

\(\Delta m\) - Mass uncertainty, measured in grams.

\(\Delta d\) - Diameter uncertainty, measured in milimeters.

\(\Delta l\) - Length uncertainty, measured in milimeters.

\(\Delta \rho\) - Density uncertainty, measured in grams per cubic milimeters.

Partial derivatives are, respectively:

\(\frac{\partial \rho}{\partial m} = \frac{4}{\pi\cdot d^{2}\cdot l}\) (2)

\(\frac{\partial \rho}{\partial d} = -\frac{8\cdot m}{\pi\cdot d^{3}\cdot l}\) (3)

\(\frac{\partial \rho}{\partial l} = - \frac{4\cdot m}{\pi\cdot d^{2}\cdot l^{2}}\) (4)

And we expand (1) as follows:

\(\Delta \rho \approx \frac{4\cdot \Delta m}{\pi\cdot d^{2}\cdot l} - \frac{8\cdot m\cdot \Delta d}{\pi\cdot d^{3}\cdot l}-\frac{4\cdot m\cdot \Delta l}{\pi\cdot d^{2}\cdot l^{2}}\)

\(\Delta \rho \approx \left(\frac{4}{\pi\cdot d^{2}\cdot l}\right)\cdot \left(\Delta m -\frac{m\cdot \Delta d}{d}-\frac{m \cdot \Delta l}{l} \right)\) (5)

If we know that \(d = 2\,mm\), \(l = 25\,mm\), \(m = 6.2\,g\), \(\Delta m = \pm 0.1\,g\), \(\Delta d = \pm 0.01\,mm\) and \(\Delta l = \pm 0.1\,mm\), then the absolute uncertainty is:

\(\Delta \rho \approx \pm\left[\frac{4}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)} \right]\cdot \left[(0.1\,g)-\frac{(6.2\,g)\cdot (0.01\,mm)}{2\,mm} -\frac{(6.2\,g)\cdot (0.1\,mm)}{25\,mm} \right]\)

\(\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}\)

And the expected density is:

\(\rho = \frac{4\cdot m}{\pi\cdot d^{2}\cdot l}\) (6)

\(\rho = \frac{4\cdot (6.2\,g)}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)}\)

\(\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}\)

The percentage uncertainty in his calculated value of density is:

\(\%e = \frac{\Delta \rho}{\rho}\times 100\,\%\) (7)

If we know that \(\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}\) and \(\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}\), then the percentage uncertainty is:

\(\%e = \frac{\pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}} }{78.941\times 10^{-3}\,\frac{g}{mm^{3}} }\times 100\,\%\)

\(\%e = \pm 0.713\,\%\)

The percentage uncertainty in his calculated value of density is \(\pm 0.713\,\%\).

Distance between the particles when t = 4s:To find the distance between A and B, we need to find their positions as a function of time.

The position of particle A can be found using the equation:

\(x A = (1/2)at^2 + v0t + x0,\)

where\(v0 = 0 m/s\) (since both particles start from rest), \(x0 = 0 m\), and\(a = 6 m/s^2.\)

So,\(x A = (1/2)(6 m/s^2)(4 s)^2 = 48 m\)

The position of particle B can be found using the equation:

\(x B = (1/2)at^2 + v0t + x0,\)

where \(v0 = 0 m/s\) (since both particles start from rest), \(x0 = 0 m\), and \(a = (12t^2 - 8) m/s^2.\)

So, \(x B = (1/2)((12)(4^2) - 8) (4s)^2 = 64 m\)

The distance between the two particles at t = 4 s is \(|x A - x B| = |48 m - 64 m| = 16 m.\)

Total distance traveled by each particle in t = 4s:

The total distance traveled by particle A in 4 seconds can be found using the equation:

\(d A = (1/2)at^2 + v0t + x0\),

where\(v0 = 0 m/s\) (since both particles start from rest), \(x0 = 0 m\), and\(a = 6 m/s^2.\)

So,\(d A = (1/2)(6 m/s^2)(4 s)^2 = 48 m\)

The total distance traveled by particle B in 4 seconds can be found using the equation:

\(dB = (1/2)at^2 + v0t + x0\),

where \(v0 = 0 m/s\)(since both particles start from rest), \(x0 = 0 m\), and \(a = (12t^2 - 8) m/s^2.\)

So, \(dB = (1/2)((12)(4^2) - 8) (4s)^2 = 64 m\)

In 4 seconds, particle A travels a total of 48 m and particle B travels a total of 64 m.

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Answer:

I think B but im not sure

Explanation:

Answer: i think both mirrors are used to reflect the beam of light.

Explanation:

gr 10 science right? im almost done the semester and i learnt this already so i think the best answer is the last one

The visible range is 6.02×10^-7 m.

The refractive index of the oil film is n=1.58

The thickness of the film is , t=286 nm= 286×10^-9 m

2nt=( m+ ½) λ

m=0, 1, 2,.....

Substituting m=0, t and n

2× 1.58 ×(286×10^-9) =(0+½) λ=1.81×10^-6m (This is of infrared range)

Substituting m=1, t and n

2× 1.58 ×(286×10^-9) =(1+½) λ=1.81×10^-6=6.02×10^-7 m, this is visible range

Waves are vibrations that propagate. There are many types of waves such as sound waves, mechanical waves, to electromagnetic waves. All waves have different characteristics.

The physical characteristics of the wave are represented by the wavelength, frequency, amplitude, direction of vibration, and also the direction of propagation. Wavelength is the distance of one wave and is represented by the Greek letter Lambda (λ).

On transverse waves, length can be calculated as the distance from the peak of the wave to the crest of the next wave, or the trough of the wave to the trough of the next. Whereas in longitudinal waves, the wavelength can be calculated from one stretch to the next stretch, or the distance from one density to the next.

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Given

Procedure

Dimensions of v are L/T

The answer would be:

The letter a is multiplying to one dimension in time, so it must be a value of distance over two of time. LT^(-2)

The letter b is in the numerator so it must be a distance dimension. L

The letter c is being operated as a subtraction in the denominator so it must be time T

When electromagnetic radiation is Doppler-shifted by motion away from the detector, the observed wavelength increases.

When an object emitting electromagnetic radiation, such as light, is moving away from an observer (detector), the wavelengths of the observed radiation are stretched or increased.

This phenomenon is known as the Doppler shift. It occurs because the motion of the source affects the perceived frequency or wavelength of the radiation. When the source is moving away, the observed wavelength is longer compared to the emitted wavelength.

This effect can be observed in various contexts, such as the redshift observed in the light from distant galaxies, indicating their recession from us due to the expansion of the universe.

Additionally, it is relevant in understanding the behavior of stars, galaxies, and other astronomical objects. By analyzing the Doppler shift, scientists can infer important information about the motion and velocity of celestial objects.

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All of the above make Titan special.

Titan is the only moon in the solar system with a dense atmosphere, which is mostly made up of nitrogen, and also contains some methane and other gases. The atmosphere creates weather on Titan, including winds and rain, and can cause erosion and other forms of weathering on the moon's surface.

Cryovolcanoes, which spew liquid water and other materials, have been discovered on Titan, making it one of the few places in the solar system where active volcanism has been observed. In addition to water, these cryovolcanoes can also emit liquid methane and other compounds.

Liquid methane lakes have also been observed on Titan's surface. These lakes are made possible by the low temperatures and high atmospheric pressure on the moon, which allow methane to exist in liquid form.

Overall, Titan is a unique and fascinating moon with many special features that make it of great interest to scientists studying the solar system.

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All of the above factors make Titan unique in the solar system. Therefore, the correct option is E.

Titan is a fascinating and distinctive moon of Saturn, with a number of characteristics that set it apart from other moons in the solar system. The following are the features that make titan special:

Atmosphere: Titan is the only moon in the solar system with a thick, Earth-like atmosphere. The majority of Titan's atmosphere is nitrogen, and there are traces of other gases like methane and ethane as well. The presence of an atmosphere on Titan is one of the factors that distinguish it from other moons in the solar system, which either have no atmosphere or only a thin one.

Weathering of the Surface: Titan's surface is carved with intricate patterns that are similar to those found on Earth. There are mountains, canyons, and river systems. However, the atmosphere is responsible for the weathering of Titan's surface. The temperature on Titan is too cold for liquid water to exist, so any flowing liquid on the surface is in the form of methane.

Cryovolcanoes That Spew Liquid Water: Titan has cryovolcanoes, which spew liquid methane and other substances. Volcanoes are typically associated with hot, molten rock on Earth, but on Titan, the volcanoes spew icy substances rather than molten lava. This again sets Titan apart from other moons in the solar system.

Liquid Methane Lakes: Titan is the only moon in the solar system with large bodies of liquid on its surface. However, these are not water lakes but instead contain liquid methane and other hydrocarbons. Despite the fact that the composition of the liquid is different from that of water, the presence of lakes on Titan is still highly unusual.

All of the above factors make Titan unique in the solar system. It is the only moon with an atmosphere and has distinct weathering, cryovolcanoes, and methane lakes that all make it special.

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Yes, Terry should call 9-1-1 immediately because the man is mentally ill.

Based on the statement, if Terry is out with friends and sees a man who appears to be struggling with mental illness. And the man is ranting and waving his arms around in a very antagonistic way. He is also getting more agitated and pulls out a knife and starts jabbing it like he is attacking someone.

The man's behavior is dangerous and poses a potential threat to himself and others around him. The fact that he has pulled out a knife and is waving it in a threatening manner indicates that he may be a danger to himself or others.

In this situation, it is important to prioritize everyone's safety and call for emergency services to intervene and help the man.

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When electrons are accelerated through a potential difference, they gain kinetic energy. In this case, the electrons are accelerated through a potential difference of 890 kV, resulting in a kinetic energy of \(8.90 × 10^5 eV.\)To understand this concept, let's break it down step-by-step:

1. Potential difference: This refers to the voltage applied across the acceleration region. In this case, it is 890 kV, where "kV" stands for kilovolts.

2. Kinetic energy: This is the energy associated with the motion of an object. In this case, the electrons gain a kinetic energy of\(8.90 × 10^5 eV\), where "eV" stands for electron volts.

3. Conversion: To convert the potential difference from kilovolts to electron volts, we multiply by the elementary charge of an electron, which is approximately\(1.6 × 10^-19 C\) (coulombs). So, \(890 kV * (1.6 × 10^-19 C/eV) = 1.424 × 10^-14 eV.\)

4. Conclusion: The electrons gain a kinetic energy of \(1.424 × 10^-14 eV\)when accelerated through a potential difference of 890 kV.

In summary, the potential difference of 890 kV accelerates electrons, resulting in a kinetic energy of\(8.90 × 10^5 eV.\)

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The acceleration of the car can be obtained as  0.26 m/s^2. The force required to ove it a distance of 30 m is 11760 N.

We know that the acceleration is the change in the velocity of the object with time. Now we know from the Newton law that the force is the product of the mass of the object and the acceleration.

Now we have that;

weight = mass * acceleration due to gravity

mass = weight/ acceleration due to gravity

mass = 12,000 N / 10 m/s^2

= 1200 Kg

The we know that;

Force = mass * acceleration

acceleration = Force/mass

=  310 N/1200 Kg

= 0.26 m/s^2

For the force that that is needed to move the car a distance of 30 m we have;

F = ma

= 1200 Kg * 9.8 m/s^2

= 11760 N

This is the force that ca move the object forward.

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Answer:

A

Explanation:

Newton third law of motion state that action and reaction are equal and opposite

Answer:

Always true

Explanation:

I got it right on the test.

Answer:

"Both students are correct. When light is traveling through small openings, solids, liquids, gases, or a vacuum, it behaves like a wave. When it interacts with matter, it acts like a stream of particles."

Explanation:

just got it right

Answer:

1 -a push or a pull acting on a object.

Explanation:

force is a push or pull acting upon an object as a result of its interaction with another object.

The kinetic energy will be 4.09 x 10^14J

Use the equation for kinetic energy, which is

K = (1/2)mv²,

where K is the kinetic energy, m is the mass of the particle, and v is its velocity.

Since the electron and positron have the same speed in the lab frame, we can use the same equation for both particles.

First, we need to determine the mass of each particle. The mass of an electron is approximately 9.11 x 10^-31 kg, and the mass of a positron is the same as an electron. So we have:

m = 9.11 x 10^-31 kg

Next, plug in the values for the velocity:

v = 0.490c

where c is the speed of light (approximately 3.00 x 10^8 m/s).

Now we can calculate the kinetic energy for each particle:

K = (1/2)mv^2

K = (1/2)(9.11 x 10^-31 kg)(0.490c)^2

K = 4.09 x 10^-14 J

Therefore, the kinetic energy of each particle is approximately 4.09 x 10^-14 J.

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The approximate value for the angle of the hill when a cylinder has a radius r, it rolls down a hill with a linear acceleration a, is θ ≈ a/(g + μ).

Let's first define the variables and parameters we have in this problem:

r: radius of the cylinder

a: linear acceleration of the cylinder

θ: angle of the hill

When the cylinder rolls down the hill, there are two forces acting on it: the force of gravity (mg) and the force of friction (f). The force of gravity can be broken down into its components perpendicular (mgcosθ) and parallel (mgsinθ) to the surface of the hill.

The force of friction acts in the opposite direction of the cylinder's motion and is given by f = μN, where μ is the coefficient of friction and N is the normal force. The normal force is equal to the perpendicular component of the force of gravity, so N = mgcosθ.

The net force acting on the cylinder is given by F = mgsinθ - μmgcosθ = ma, where m is the mass of the cylinder. We can solve for θ to get:

sinθ - μcosθ = a/g

where g is the acceleration due to gravity. We can use a numerical method like Newton-Raphson to solve this equation for θ, or we can make some approximations to simplify the equation. If we assume that μ is small and sinθ ≈ θ (valid for small angles), we can rewrite the equation as:

θ ≈ a/(g + μ)

This gives us an approximate value for the angle of the hill. However, if we want a more precise answer, we can use the exact equation and plug in the values of r, a, and μ to solve for θ.

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The two aspects of the photoelectric effect challenging classical wave theory are:

The immediate onset of the effect regardless of light intensity.

The existence of a threshold frequency below which no effect occurs.

The photoelectric effect refers to the phenomenon where electrons are ejected from a metal surface when light shines on it. According to classical wave theory, light is described as an electromagnetic wave, and the energy carried by the wave should be spread out over the entire wavefront. In this view, the energy transferred to the electrons should depend on the intensity of the light, not its frequency.

However, observations showed that the photoelectric effect is immediate, with electrons being emitted almost instantly when the light reaches a certain frequency, regardless of the intensity. This contradicted the classical wave theory's prediction and required a new explanation.

Another challenge for the classical wave theory was the existence of a threshold frequency. Experimental results demonstrated that there is a minimum frequency of light below which no electrons are emitted, regardless of the intensity of the light. According to classical wave theory, increasing the intensity of light should eventually provide enough energy to liberate electrons, irrespective of the frequency. However, the threshold frequency remained a consistent feature in the photoelectric effect, which could not be explained by classical wave theory.

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Answer:

C. transverse

Answer: 180 m south

Explanation:

The displacement of the horse in this time is 180 m south. The correct option is A.

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Velocity is the time rate of change of displacement with time.

Given is a horse runs for 15 seconds to the south at a speed of 12 m/s. So, the displacement is

Displacement = Speed x Time

Put the values, we get

Displacement = 12 m/s x 15s

                      = 180 m

Thus, the displacement of the horse in this time is 180 m south.

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We have a problem about conservation and velocity, we will find that it does affect the speed of the ball, increasing it by 1.7m/s.

There is something called momentum, which we can define as the "quantity of movement", and we can simply write as the product between velocity and mass.

The momentum is conservative, then we have conservation of momentum.

This means that when you run whit the ball in your hands, the momentum of the ball will be equal to your velocity times the mass of the ball, and this must conserve after you throw the ball.

Now with this idea in mind, this means that if you run with a velocity V, and you throw the ball with a velocity V', the velocity of the ball when it leaves your hand will be:

V + V'.

So, if you run with a velocity of 1.7m/s forward and you throw the ball (assuming in the same direction) the speed of the ball will be 1.7m/s larger than if you were to throw it standing still.

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Answer:

your pretty no matter what others say

Explanation:

Answer:

two bros chillin in a hot tub five feet apart cuz there not gay

Explanation:

do you remember this vine

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

To determine the minimum required diameter of each rod, we need to consider the average normal stress limit of 150 MPa. The formula to calculate the average normal stress is σ = F/A, where σ is the stress, F is the force applied, and A is the cross-sectional area of the rod.

Assuming the force applied is the maximum force that the rod will experience, we can rearrange the formula to solve for the cross-sectional area: A = F/σ. Since we're looking for the minimum required diameter, we'll use the formula for the cross-sectional area of a circle: A = πd²/4, where d is the diameter.
Combining the two formulas, we have πd²/4 = F/σ.
Simplifying further, d² = (4F)/(πσ).

To determine the minimum diameter, we'll use the maximum force applied and the given stress limit: d² = (4 * max force)/(π * 150 MPa).
We don't have the value of the maximum force, so we can't determine the exact minimum diameter. However, you can calculate it by plugging in the appropriate values into the formula above. Remember to round the result to the nearest millimeter. To determine the minimum required diameter of each rod, you need to know the maximum force applied and the stress limit. Use the formula d² = (4 * max force)/(π * 150 MPa) and round the result to the nearest millimeter.

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The Milky Way galaxy is the home of the Sun. Over 100,000,000,000 stars are thought to be present in the Milky Way alone, according to astronomers.

One of the many billions of galaxies in the cosmos is the Milky Way galaxy. The universe is a large region of space that houses everything that has ever existed. All the galaxies, stars, and planets are in the cosmos. Unknown is the precise size of the universe. According to scientists, the universe is still growing. At least 100 billion stars, including our Sun, make up the Milky Way, a spiral galaxy with a diameter of around 100,000 light-years. We are located in one of the four primary arms of the pinwheel-shaped constellation of stars, roughly two thirds of the way from the center. It is believed that the majority of the stars in our galaxy are home to their own families of planets.

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The acceleration of a bike which increases its speed from 0 to 40 ft/s in 4 seconds will be 3 m/s².

Given, initial speed (u) = 0

Final speed (v) = 40 ft/s = 12 m/s

Time taken = 4 seconds

From the equation v = u + at, we have

12 = 0 + a x 4

12 = 4a

a = 3 m/s²

The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in meters per second squared (m/s²). Since acceleration is a vector quantity, both its magnitude and its direction are included.

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You are likely to see these items together if you are holding a phone that has headphones connected to it. This illustrates the principle of connectivity.

A perceptual bias, propensity, or readiness to perceive specific elements of a stimuli is what Allport (1955) characterized as a perceptual set. Perceptual set is the propensity to notice or perceive particular components of the sensory data that is available while ignoring others.

Perceptual set development is frequently influenced by motivations as well. People are more likely to see things in a particular manner if they are driven to do so. For instance, if they wish to think that a novel product works.

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