(Essay Worth 2 points)
(12.02 MC)
Describe an adaptation to a plant's physical characteristic and explain how this adaptation helps the plant survive. (PLEASE HELP)

Answer:

Continental polar

Explanation:

Answer:

Polar air masses!

Explanation:

They form between 50 and 60 degrees latitiude, Siberia and Northern Canada are the most commonplace for these to form!

Fusion powers the sun. This creates nuclear energy, which then goes to earth in the form of radiation. The plants get sunlight and photosynthesise (the process of getting glucose by sunlight). The answer should be C.

Answer:

The water in glass A is warmer than the water in glass B therefore the particles move faster

Explanation:

Diffusion is influenced by temperature, concentration gradient and others. in this case the higher the temperature the faster the diffusion rate while when cooler it is slower

Answer:

B. The water in Glass A is warmer than the water in Glass B; therefore, the particles in Glass A move faster.

Explanation:

I took the exam

Answer:

Atomic Number - 11. Sodium

Answer:

Fibre optic technology.

Explanation:

Fibre optic technology, as the name implies, uses light pulses to transmit data via strands of glass or plastic. It's the preferred technology for the government's National Broadband Network (NBN), which offers 100Mbps+ download speeds.

Answer: B. 1 proton and 1 neutron(s)

Explanation: Founders Educere answer.

I love you, fellow summer school students good luck!

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There are 210 kilocalories in a portion of food that contains 8 g protein, 10 g fat, and 22 g carbohydrate. The amount of vitamin C and water in the food does not contribute to the number of kilocalories, as they are not sources of energy.

Proteins are large, complex molecules that are made up of long chains of amino acids. They are essential for the growth, repair, and maintenance of tissues in the body, and are involved in a wide range of biological processes.

To calculate the number of kilocalories in a portion of food, we need to use the following formula:

Calories = (grams of protein x 4) + (grams of fat x 9) + (grams of carbohydrate x 4)

Using this formula, we can calculate the number of calories in the given portion of food:

Calories = (8 g protein x 4) + (10 g fat x 9) + (22 g carbohydrate x 4)

Calories = 32 + 90 + 88

Calories = 210 kcal

Therefore, in a portion of food that contains 8 g protein, 10 g fat, and 22 g carbohydrate there are 210 kilocalories.

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The mass percentage of C in hydrochlorothiazide is 28.23%.

The mass percentage of C in hydrochlorothiazide, \(C_{7}H_{8}ClN_{3}O_{4}S_{2}\), can be calculated using the following steps:

1. Calculate the molar mass of hydrochlorothiazide:
- C: 7 atoms × 12.01 g/mol = 84.07 g/mol
- H: 8 atoms × 1.01 g/mol = 8.08 g/mol
- Cl: 1 atom × 35.45 g/mol = 35.45 g/mol
- N: 3 atoms × 14.01 g/mol = 42.03 g/mol
- O: 4 atoms × 16.00 g/mol = 64.00 g/mol
- S: 2 atoms × 32.07 g/mol = 64.14 g/mol
Total molar mass = 84.07 + 8.08 + 35.45 + 42.03 + 64.00 + 64.14 = 297.77 g/mol

2. Calculate the mass percentage of C:
= (Mass of C / Total molar mass) × 100

= (84.07 g/mol / 297.77 g/mol) × 100 = 28.23%

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Answer:

A variety of household products are hazardous. Motor oil, pesticides, oil-based paints, mothballs, flea collars, weed killers, and some household cleaners

the mass defect of Li-7 is -0.035279 u and the nuclear binding energy per nucleon is 5.60553 × 10⁻¹² J/nuclide.

Given data:

Atomic mass of Li-7, A = 7.016003

The atomic mass of Li-7 is the sum of the number of protons and neutrons in it. Therefore, the number of neutrons in Li-7 is:

Neutrons = Atomic mass - Protons= 7.016003 - 3= 4.016003The mass of 3 protons and 4.016003 neutrons in Li-7 is: Mass of protons + Mass of neutrons = (3 x 1.007276) + (4.016003 x 1.008665) = 3.021828 + 4.029454 = 7.051282 u

Therefore, the mass defect in Li-7 is:

Mass defect = Actual mass - Calculated mass

= Atomic mass - Mass of protons and neutrons

= 7.016003 - 7.051282

= -0.035279 u

Nuclear Binding Energy per nucleon (BE/A) can be calculated using the formula:

BE/A = [Δm.c² / A]

where Δm is the mass defect and c is the speed of light which is 2.998 × 10⁸ m/s.

Substituting the values in the above formula:

BE/A = [(-0.035279) × (2.998 × 10⁸)² / 7]= 5.60553 × 10⁻¹² J/nuclide

Therefore, the mass defect of Li-7 is -0.035279 u and the nuclear binding energy per nucleon is 5.60553 × 10⁻¹² J/nuclide.

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The given element nitrogen have 7 electrons and 7 protons. Mass number is the sum of number of protons and neutron. The number of neutrons is 7. Thus mass number of the isotope is  14.

Nitrogen is 7th element in periodic table. It is an electronegative element and is included in p block. Nitrogen exists as gas but sometime it can be liquified under high pressure.

Isotopes are atoms with same atomic number and different mass number. Nitrogen have two isotopes. N-14 and N-15. Mass number is the sum of number of protons and neutrons.

Even though isotopes are different in mass number their chemical properties will be similar but there exists slight changes in their physical properties.

Here, we have 7 protons and 7 electrons therefore, the mass number 14.Thus the isotope given in the diagram is N-14.

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Answer:

Aufbau Principle: Electrons occupy orbitals of lower energy first.

Pauli Exclusion Principle: An orbital can hold only two electrons and they must have opposite spin.

Hund's Rule: Electrons fill each orbital singly before any orbital gets a second electron.

Answer: I would think 4 because there are plants every were there like literally there is lots of flowers green bushes trees vines there's lots of wonderful beautiful stuff there so I think the number 4

Explanation:

A rainforest orchid. Orchids are very common plants in the tropical rainforest. The Amazon Rainforest itself is home to more than 40,000 plant species! The most common tree in the Amazon Rainforest is the açai here are some of the plants there are there

Bromeliads Plant (Bromeliaceae)

Emergent Plant

Heliconia Flower (Lobster-Claw)

Orchid Plant

Passion flowers (Passiflora spp.)

Lianas

Vines

Rubber Tree (Hevea brasiliensis)

Cacao (Theobroma cacao)

Giant Water Lilies (Victoria amazonica)

The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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11.2L is the total volume of O\(_2\) produced when 1 mole of PbO decomposes at STP for reaction 2 PbO(s) → 2 Pb(s) + O\(_2\)(g).

Lead(II) oxide, often known as lead monoxide, is an inorganic chemical having the formula PbO. PbO exists in two polymorphs: litharge, which has a tetragonal crystalline structure, as well as massicot, which has an orthorhombic crystalline structure.

The majority of modern PbO uses are already in lead-based commercial glass as well as industrial ceramics, particularly computer components. It is a kind of amphoteric oxide.

2 PbO(s) → 2 Pb(s) + O\(_2\)(g)

mole of PbO =1 mole

the mole ratio between PbO  and oxygen is 2:1

mole of oxygen = 0.5mole

volume of oxygen = mole of oxygen ×22.4L

                              = 0.5×22.4L

                              = 11.2L

Therefore,  11.2L is the total volume of O\(_2\) produced when 1 mole of PbO decomposes at STP.

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Answer:

5mol at most

Explanation:

as we hv 5mol Ca available, the 5 mol Ca can react with 5/2 = 2.5mol O2, as we have more mol of O2 than that Ca can react with, Ca is the limiting reactant. Therefore at most 5/2x2 = 5 mol of CaO can be made

A sample of gas has an initial volume of 3.50 l at a pressure of 970. torr and a temperature of 25 oc. if the sample is heated to a temperature of 40. oc and expands to a volume of 6.80 l, The final pressure of the gas sample is 1306.6 torr.

To solve this problem, we can use the combined gas law, which states:
(P1 x V1) / T1 = (P2 x V2) / T2
Where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
Plugging in the given values, we get:
(970 torr x 3.50 L) / (25 + 273.15 K) = (P2 x 6.80 L) / (40 + 273.15 K)
Simplifying and solving for P2, we get:
P2 = (970 torr x 3.50 L x (40 + 273.15 K)) / (25 + 273.15 K) / 6.80 L
P2 = 1306.6 torr
Therefore, the final pressure of the gas sample is 1306.6 torr.

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Answer:

Option D

Explanation:

As we know at

PV = nRT

at STP,

Pressure is  1 atm and temperature is 273 K

\(\frac{P_2}{P_1} = \frac{T_2}{T_1} \\P_2 = 1*(428 )/273\\P_2 = 1.567\)

Hence, option D is correct

In the picture representation of electromagnetic waves,

a) Lowest frequency - C

b) Second Highest energy - A

c) Highest energy - B

d) Shortest wavelength - B

Wavelength can be defined as the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually mentioned in meters (m), centimeters (cm), or millimeters (mm).

If the wavelength of electromagnetic waves is low, the frequency of a wave is also low and the energy is low.

If the wavelength of electromagnetic waves is short, the frequency of a wave is also high and the energy is high.

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The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.

The electrochemical cell is the cell that is capable of generating the electrical energy from the chemical reactions or by the use of the electrical energy to cause the chemical reaction. The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.  

There are the two types of the electrochemical cells is as follows : the galvanic called the electrolytic cells. the galvanic cell is also called as the voltaic cell.

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The gas particles in each sample have the same average kinetic energy.

(a) Sample B has the highest partial pressure of gas B because it occupies the smallest volume, causing its gas particles to collide with the container walls more frequently, leading to a higher number of collisions and a greater force per unit area on the container walls. This results in a higher partial pressure of gas B in sample B compared to samples A and C.

(b) Sample C has the lowest partial pressure of gas B because it has the largest volume, causing the gas particles to have more space to move around and collide with each other, reducing the number of collisions and the force per unit area on the container walls. This results in a lower partial pressure of gas B in sample C compared to samples A and B.

(c) The average kinetic energy of gas particles is directly proportional to their temperature. Therefore, the sample with the highest temperature will have gas particles with the highest average kinetic energy. From the given information, we cannot determine the temperature of each sample, but we can assume that the samples are at the same temperature because they have the same volume and pressure.

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We can see that the pressure of the gas has remained the same. Therefore, the answer is: It has stayed the same.

According to the Ideal Gas Law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.

If the volume of a fixed amount of gas is doubled, and the absolute temperature is doubled, then the new values of volume and temperature are V' = 2V and T' = 2T, respectively.

Using the Ideal Gas Law, we can write:

P'V' = nRT'

Substituting V' and T' and rearranging:

P' = (nRT') / V'

P' = (nR x 2T) / (2V)

P' = P

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question we have

\(density = \frac{15}{14} \\ =1.0714285 ...\)

We have the final answer as

Hope this helps you

Answer:

B

Explanation:

The neucles is surrounded by electrons. Electrons occupy most of the volume of the atom.

Atomic Model:

Atoms are the smallest unit of elements, which form bonds with others. In an atom, electrons revolve around the nucleus.

The nucleus is composed of positively charged protons and neutrons. The nucleus occupies a very small part of the atom.

Electrons are negatively charged particles, they are found around the nucleus and occupy most of the part of the atom.

Therefore, The neucles is surrounded by electrons. Electrons occupy most of the volume of the atom.

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Answer:

becoz vvv is always with you

Answer:

Alkali metals have one valence electron on their outer shell. They are more stable when they have eight valence electrons so they tend to loose that one electron and obtain a full octet, therefore become stable

pH of given buffer solution prepared by dissolving 0.20 mole of cyanic acid is 4.30.

Solution:

Equilibrium reaction equation for the given reaction is as follows. HCNO(aq) + H2O(l) → CNO (aq) + H₂O* (aq)

It is given that initial moles of HCNO is 0.20 mol and for NaCNO is 0.80 mol.

Ka of HCNO Is 2 x 10^-4 mol.

Now, we will assume that at equilibrium there are x moles.

HCNO(aq) + H2O(l) → CNO (aq) + H₂O+ (aq)

Initial:          0.20            0.80            0

Change:        -x                +x             +x

Equilibrium: 0.20-x       0.80 + x       x

As the volume of the given solution is 1 liter, equilibrium concentration and moles are same.

Ka = [CNO-][H30+]/[HCNO]

2.0x 10^-4 = x(0.80 + x) / (0.20 - x)

x = 5.0x10^-5 M

Then, pH = -log[H30+]

= -log(5.0 × 10^-5)

= 4.30

pH of given buffer solution is 4.30.

A weak acid and either its conjugate base or the base itself are combined in an aqueous solution to form a buffer solution. The pH scarcely changes at all when a small amount of a strong acid or basic is added to it.

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Answer:

option c

Explanation:

E = hf

E= energy

h = Planck constant

f = frequency

E = 6.6 X 10^-34 X 4 X 10^14

E = 2.64 X 10^-19J