evaluate -7 5/8 + (-6 1/4)

Answer: One

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

I assume the original H-shaped polygon is the one on the left, and the scaled copy is the smaller one on the right.

To find the scale factor, find a dimension in the original polygon and the corresponding dimension in the scaled copy. Then divide the dimension of the scaled copy by the corresponding dimension of the original one.

For example, use the upper width of the left rectangle of the H shape.

A) original polygon: 4 units

B) scaled polygon: 1 unit

scale factor = (1 unit)/(4 units) = 1/4

The scale factor is 1/4. That means that if you multiply every linear dimension of the original polygon by 1/4, you find the corresponding dimension in the scaled copy.

Answer: The scale factor is 1/4

Answer:

A: The data does represent a function because there are no repeating x values. a function can have repeating y values but cannot have repeating x values. Also, there is one value of y for every value of x.

B: f(x)=1/2x

f(x)= 3x-10

f(8)=1/2(8) ----> 4

f(8)=3(8)-10 ----> 14

f(x)=3x-10 has a greater value when x=8

C:  f(x)=1/2x

f(x) = 80

80=1/2x  

80*2=x

x=160

Step-by-step explanation:

The data in the table is a function. The relation has f(x) = 3x - 10 has greater value when x = 8. And the value of x is 30 when f(x) = 80.

A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.

Part A :

The table has the data values,

x : 2  4  6  8

y : 1  2  3  4

The given data represents a function, because elements in the domain (2, 4, 6 and 8) has only one image in the Range (1, 2, 3 and 4).

Part B :

f(x) = 3x - 10

x = 2, then f(x) = y = -4

x = 4, then f(x) = y = 2

x = 6, then f(x) = y = 8

x = 8, then f(x) = y = 14

The relation f(x) = 3x - 10 has the greater value when x = 8.

Part C :

f(x) = 80

3x - 10 = 80

3x = 80 + 10

3x = 90

x = 90 / 3

x = 30

Hence the relation in the table is a function. The second relation f(x) = 3x - 10 has the greater value when x = 10 after computing the values of both the relations.

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Answer:

0.4167

Step-by-step explanation:

Here, the fraction is 5/12  means that we need to perform 5 ÷ 12

This gives the answer as 0.4167. So, 5/12 as a decimal is 0.4167

Irrespective of the methods used, the answer to 5/12 as a decimal will always remain the same.

Answer:

3x + 9

Step-by-step explanation:

multiply 3 and x and 3 and 4

Answer:

3x+9

Step-by-step explanation:

Answer:

1: B

2:D

3:C

4:D

Step-by-step explanation:

Answer:

1. B

2. D

3. C

4. D

Step-by-step explanation:

Answer:

B is the answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

Pa:

14/84 = 2/12

28/84 = 4/12

7/84 = 1/12

35/84 = 5/12

Pb:

1/8

3/8

1/8

3/8

If a simple linear regression equation based on 20 observations turned out to be y= a+bx, and the summary statistics sx=√(180.25/19), sy=√(11,326.63/19) and  r=0.82, the value of b is 6.500. The answer is option A.

To find the value of b, follow these steps:

Therefore, the value of b is 6.500. The correct answer is option A.

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Answer:

Step-by-step explanation:

May I please see the graph?

Answer:

Therefore, the length of the ladder is 13 feet.

Step-by-step explanation:

This is a classic example of a right triangle problem in geometry. The ladder serves as the hypotenuse of the triangle, while the distance from the building to the ladder and the height of the window serve as the other two sides. Using the Pythagorean theorem, we can solve for the length of the ladder:

ladder^2 = distance^2 + height^2 ladder^2 = 5^2 + 12^2 ladder^2 = 169 ladder = √169 ladder = 13

Therefore, the length of the ladder is 13 feet.

brainliest PLssssss

The index variable for the element at the last row and last column in the array x is B. x[4][6].

In Java, arrays are zero-indexed, which means the first element of an array is at index 0. The given array x is a 2D boolean array with dimensions 5x7 (5 rows and 7 columns). To access the last row and last column, we need to subtract 1 from each dimension:

- For the last row, the index is 5 - 1 = 4.
- For the last column, the index is 7 - 1 = 6.

So, the correct index variable to access the last row and last column is x[4][6]. The other options provided are incorrect as they do not accurately represent the index of the last element:

- a. x[4][5] refers to the second to last element in the last row.
- c. x[5][6] would be out of bounds, as the maximum row index is 4.
- d. x[5][7] would also be out of bounds, as both the row and column indices are too large.

Therefore, the correct option is B.

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The critical value of f(x) = 5x⁶ - 3x⁵ is x = 0.5 which is also its maxima point

f(x) = 5x⁶ - 3x⁵

differentiation w.r.t x

=> f'(x) = 30x⁵ - 15x⁴

Putting f'(x) = 0

30x⁵ - 15x⁴ = 0

=> x⁴(30x - 15) =0

=> 30x - 15 = 0

=> x = 15/30

=> x = 0.5 , 0

Critical number is 0.5 , 0

(B) To find where f(x) is increasing

for x > 0.5 ,

(30x-15) > 0 => x⁴(30x - 15) > 0

Therefore , f(x) is increasing at ( 0.5 , ∞ )

(C)To find where f(x) is decreasing

for x < 0.5 ,

(30x-15) < 0 => x⁴(30x - 15) < 0

Therefore , f(x) is decreasing at ( -∞ , 0.5)

(D) Differentiation f'(x) again w.r.t to x

f'(x) = 30x⁵ - 15x⁴

f"(X) = 150x⁴ - 60x³

Substituting critical values of x

=> 150(0.5)⁴ - 60(0.5)³

=>9.375 - 7.5

=> -1.875 < 0 , Hence , x = 0.5 is point of maxima

(E) no point of minima

Similarly , we can solve other parts

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The accounts of Kuhlmann Manufacturing Company, as of May 31, 2022, show an inventory of finished goods amounting to $12,600, with a May 1 inventory value.

The given information states that on May 1, the company had an inventory of finished goods worth $12,600. This suggests that the value of finished goods available for sale at the beginning of May was $12,600. It implies that these goods were produced or acquired by the company prior to May 1 and were not sold or consumed until May 31, as no information is provided regarding any changes in the inventory during the month. The given value represents the starting inventory of finished goods on May 1, which is $12,600 for Kuhlmann Manufacturing Company.

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Answer:

In this algebraic expression, "Negative x" represents a term with a coefficient of -1, and "x" represents a variable. "10.2" represents a constant term. The "+" sign represents addition.

Step-by-step explanation:

"minus one-half x" represents a term with a coefficient of -0.5 and variable "x". "+ y" represents a term with variable "y" and a coefficient of 1.

Simplifying the expression by combining like terms:

-x - 0.5x = -1.5x

Negative x + 10.2 - one-half x + y = 10.2 - 1.5x + y

Answer: T= 5 and s =17

Step-by-step explanation: Use the midpoint formula

Solve for T

^xm=^xC+^xD/2

15+t/2=10

15+t=20

Solve for S

^ym=^yC+^yD/2

s+3/2=10

s+3=20

Step-by-step explanation:

wheres the decimal to compare it to

Answer: a) 7        b) -4         c) 15         d) -1        e) -8

Step-by-step explanation:

7x + 9 = 58

     -9   -9

7x       =  49

÷7         ÷7  

  x      =   7

x/2 - 12 =  -14

      +12   +12

x/2       =   -2

×2          ×2  

  x      =    -4

-3x + 33 =  -12

       -33   -33

-3x         =  -45

÷-3         ÷-3  

  x         =   15

8x + 16 =    8

      -16   -16

8x        =   -8

÷8          ÷8  

  x      =    -1

2x - 2 = -18

     +2   +2

2x       = -16

÷2         ÷2  

  x      =  -8

Answer:

Area of lateral = π x radius x slanted height

You are given 12 as height so find the slanted height by pythagoras

144+25= √169= 13

π x 5 x 13 = 65π

Hope that answers your question, your welcome

Answer:Option B is correct.

Step-by-step explanation: Given:  

x+2

1

​

+

x+3

1

​

1        =

(x+3)(x+2)

x+3+x+2

1​      =

2

+5x+6

2x+5

​

1

​

       =

2x+5

x

2

+5x+6

​

The expression 1/(1/x+2) + (1/x+3) is equivalent to (x² + 4x + 44)/x(x + 11) when x > 3.

We have,

To simplify the expression 1/(1/x+2) + (1/x+3), we can apply the concept of finding a common denominator and combining fractions.

Let's start by finding the common denominator for the two fractions.

The denominators are (1/x + 2) and (1/x + 3).

To find the common denominator, we multiply the denominators together:

Common denominator = (1/x + 2) x (1/x + 3)

Expanding the expression:

Common denominator = (1/x * 1/x) + (1/x * 3) + (2 * 1/x) + (2 * 3)

Simplifying further:

Common denominator = 1/x^2 + 3/x + 2/x + 6

Combining the fractions with the common denominator:

1/(1/x+2) + (1/x+3) = (1/x) / (1/x^2 + 3/x + 2/x + 6) + (1/x+3)

To simplify the expression further, we can multiply the first fraction by x/x to clear the fraction in the numerator:

(1/x) / (1/x² + 3/x + 2/x + 6) + (1/x+3) = (x/x) * (1/x) / (1/x² + 3/x + 2/x + 6) + (1/x+3)

Simplifying:

= 1 / (x/x * 1/x) / (1/x² + 3/x + 2/x + 6) + (1/x+3)

= 1 / (1/x²) / (1/x² + 3/x + 2/x + 6) + (1/x+3)

= 1 / (1/x²) / (1/x² + (3 + 2)/x + 6) + (1/x+3)

= 1 / (1/x²) / (1/x² + 5/x + 6) + (1/x+3)

= 1 / (1/x²) / (1/x² + 5/x + 6) + (x/x) * (1/x+3)

Simplifying further:

= 1 / 1 / (1 + 5/x + 6x/x²) + (x/x² + 3x/x)

= 1 / (1 + 5/x + 6x/x²) + (x + 3x)/x²

= 1 / (1 + 5/x + 6/x) + (4x)/x²

= 1 / (1 + (5 + 6)/x) + (4x)/x²

= 1 / (1 + 11/x) + (4x)/x²

= 1 / (x + 11)/x + (4x)/x²

= x / (x + 11) + (4x)/x²

= (x² + 4(x + 11))/x(x + 11)

= (x² + 4x + 44)/x(x + 11)

Therefore,

The expression 1/(1/x+2) + (1/x+3) is equivalent to (x² + 4x + 44)/x(x + 11) when x > 3.

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The probability to select a pupil who uses the gym but not the swimming pool is approximately 0.2375 or 23.75%.

To find the probability of selecting a pupil who uses the gym but not the swimming pool, we need to determine the number of pupils who satisfy this condition and then divide it by the total number of pupils.

We are given that there are 80 pupils in total, and we know that 26 pupils use both the swimming pool and the gym. We are also given that 56 pupils use the swimming pool, and 45 pupils use the gym.

To find the number of pupils who use only the gym, we can subtract the number of pupils who use both the swimming pool and the gym from the total number of gym users. Therefore, the number of pupils who use only the gym is 45 - 26 = 19.

The probability of selecting a pupil who uses the gym but not the swimming pool is then calculated by dividing the number of pupils who satisfy this condition (19) by the total number of pupils (80):

Probability = Number of pupils who use the gym but not the swimming pool / Total number of pupils

Probability = 19 / 80

Probability ≈ 0.2375

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The correct formula for the expression is,

⇒ f (x)  = - 6 cos (π/4.5x - 2π) + 2

Since, Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have a function:

f(x) = a cos(bx + c) + d

Here a is the amplitude:

Since, The value of d is the average of maximum and minimum.

Hence,  d = (9 - 5)/2 = 4/2 = 2

And, The value of 'a' is the difference between the maximum value and d.

Hence,  a = -4 -(2) = - 6

Here, the half-period is,

= π - 3π/4) = π/4

=  b = 2π/9 = π/4.5

The value of c is the value makes the cosine zero at x= 9

⇒  (π/4.5)(9) +c = 0

⇒  c = -2π

Hence, Function is,

f (x) = - 6 cos (π/4.5x - 2π) + 2

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Answer:

The correct answer would be:

f (x) = - 6 cos (π/4.5x - 2π) + 2

Answer:

1 1/3 x 1/2 = 4/3 x 1/2 =4/6 =2/3 cups is this right

Step-by-step explanation:

If the discount rate is 4%,the present value of the savings account is $5,448.50.

From the question above, :Savings amount = $7,942

Discount rate = 4%

Time period = 9 years

We need to calculate the present value of the savings account.To calculate the present value, we will use the formula,PV = FV / (1 + r)n

Where,PV = Present value of savings account

FV = Future value of savings account

r = discount rate, and

n = Time period

In this problem,PV = ?

FV = $7,942

r = 4%

n = 9 years

Substitute the values in the formula,

PV = 7,942 / (1 + 0.04)9

PV = $5,448.50

Therefore, the present value of the savings account is $5,448.50.

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A statistical technique that would allow a researcher to cluster such traits as being talkative, social, and adventurous with extroversion is called factor analysis.

Statistical techniques are methods and procedures used in the collection, analysis, interpretation, and presentation of data. These techniques involve the use of mathematical and statistical models to draw meaningful insights and conclusions from data.

Some common statistical techniques include:

Descriptive statistics: These techniques are used to summarize and describe the key features of a dataset, such as central tendency, variability, and distribution.

Inferential statistics: These techniques are used to make inferences about a larger population based on a sample of data. This involves using probability theory to estimate population parameters and test hypotheses.

Regression analysis: This technique is used to model the relationship between one or more independent variables and a dependent variable.

Hypothesis testing: This technique is used to test the validity of a hypothesis or claim about a population using sample data.

Time series analysis: This technique is used to analyze data that varies over time, such as stock prices or weather patterns.

Cluster analysis: This technique is used to group similar observations together based on their characteristics.

Data mining: This technique involves the use of automated methods to discover patterns and relationships in large datasets.

Statistical techniques are widely used in many fields, including business, economics, social sciences, medicine, and engineering. They are used to make informed decisions, identify trends and patterns, and to understand complex systems.

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For a two-tailed hypothesis test about μ, we can use any of the following approaches except comparing the level of significance; to the confidence coefficient

To determine if the sample mean is substantially more than or significantly less than the population mean, a two-tailed hypothesis test is used. The area under both tails or sides of a normal distribution is what gives the two-tailed test its name.

Any of the following methods, with the exception of comparing the level of significance to the confidence coefficient, can be used for a two-tailed hypothesis test regarding. To create a confidence interval estimate for the population mean, approach (d) compares the level of significance which is a to the confidence coefficient which is 1- a. This method is employed to estimate the population parameter rather than test a hypothesis.

Complete Question:

For a two-tailed hypothesis test about μ, we can use any of the following approaches EXCEPT compare the _____ to the _____.

a.confidence interval estimate of μ; hypothesized value of μ

b.p-value; value of α

c.value of the test statistic; critical value

d.level of significance; confidence coefficient

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The probability that the mean diameter of the sample shafts would vary from the population mean by less than 0.3 inches exists 0.0757.

Let X the random variable that represent the diameters of interest for this case, and for this case we know the following info

Where \($\mu=205$\) and \($\sigma=1.5$\)

Let the probability be

\($P(205-0.3=204.7 < \bar{X} < 205+0.3=205.3)$$\)

For this case they select a sample of n = 79 > 30, so then we have enough evidence to utilize the central limit theorem and the distribution for the sample mean can be approximated with:

\($\bar{X} \sim N\left(\mu, \frac{\sigma}{\sqrt{n}}\right)$$\)

To simplify this problem is utilizing the normal standard distribution and the z score given by:

\($z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}$$\)

To find the z scores for each limit and we got:

\($z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$$\)

\($z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$$\)

To find this probability:

P(-1.778 < Z < 1.778) = P(Z < 1.778) - P(Z < -1.778)

simplifying the above equation, we get

= 0.962 - 0.0377

= 0.9243

The interest exists the probability that the mean diameter of the sample shafts would vary from the population mean by more than 0.3 inches utilizing the complement rule we got:

P = 1 - 0.9243 = 0.0757

The probability that the mean diameter of the sample shafts would vary from the population mean by less than 0.3 inches exists 0.0757.

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Answer:

1

Step-by-step explanation:

The probability of selecting  a girl to read the poem out loud in her class is 46.4% .

To calculate the probability of selecting a girl to read a poem out loud in a class of 28 students, we can use the formula:

Probability = Number of Desirable Outcomes / Total Number of Outcomes

Here, the desirable outcome is selecting a girl to read the poem, and the total outcomes are all the students in the class.

Number of Desirable Outcomes:

Mrs. Avery has 13 girls in her class, so there are 13 desirable outcomes.

Total Number of Outcomes:

Mrs. Avery has 28 students in her class, so there are 28 total outcomes.

Probability = Number of Desirable Outcomes / Total Number of Outcomes

Probability = 13 / 28

Probability = 0.464 or 46.4%

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Note: The complete question is -Mrs. Avery is planning to have one student read a poem out loud in class. She has a class of 28 students, consisting of 15 boys and 13 girls. What is the probability that she will select a girl to read the poem out loud?