Answer:
i thinks its 29
Step-by-step explanation:
divide 415 by 14
Answer:
The answer is 7/1 simplified
Step-by-step explanation:
consider the random experiment of rolling a pair of fair dice. what is the probability that one of the dice has the number 3 or less facing up given that the other has at least the number 3 facing up?
The probability that one of the dice has the number 3 or less facing up given that the other has at least the number 3 facing up is 3/16.
To find the probability that one of the dice has the number 3 or less facing up given that the other has at least the number 3 facing up, we can use conditional probability.
First, let's consider the possible outcomes when rolling a pair of fair dice.
There are a total of 36 possible outcomes, since each die has 6 possible outcomes (numbers 1 to 6)
and there are 6 possibilities for the second die for each outcome of the first die.
Next, let's consider the outcomes where one of the dice has the number 3 or less facing up and the other has at least the number 3 facing up.
If the first die has the number 3 or less, there are 3 possible outcomes:
(1,3), (2,3), (3,3). If the second die has at least the number 3 facing up, there are 16 possible outcomes:
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,3), (5,3), (6,3), (4,4), (4,5), (4,6), (5,4), (5,5), (5,6), (6,4), (6,5), (6,6).
Out of these 16 outcomes, 3 outcomes also satisfy the condition that the first die has the number 3 or less facing up: (3,3), (4,3), (5,3).
Therefore, the probability that one of the dice has the number 3 or less facing up given that the other has at least the number 3 facing up is 3/16.
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For a field trip, 25 students rode in cars and the rest filled eight buses. How many students
were in each bus if 321 students were on the trip?
Need help plzzz 10 points
Project Description Let x∈R (a single real number), y∈R a pair (x,y) is a training somple A trainiug set of size m is a set of m such pairs, (x
i
,y
i
) for i=1,…,m. In nuapps, your can have a single 1D array for all x
i
, and sparately a ID array for all y
i
- For a given (n+1)-limensiotal vertor w∈R
n+1
, ket h(x,w)=∑
j=−[infinity]
n
e
′
x
3
be a polynomial of n-th degree of x with coefficients wy. For example, for n=2, we will have a 2 ud degree polynomial h(x,w)=w
b
+w
1
x+w
2
x
2
(if you jrefer ax
2
+bx+c, substitute a=w
2
,b=w
1
,c=w
0
). Let L(h(x),g)=(h(x)−y)
2
be the squared error objective function L:R×R→R
4
showing how good the polynonial h specified by w is at predicting the y from x in a given training sample (x,y). The lower the value of L, the higher the accuracy; idenally, the preetiction is perfict, h(x)=y. and L=0. Given a sequenue of m pains (x
i
+,
r
ˉ
) - the training met - and the value for n(n=1,2,3,4,5), your trsk is to write a python/mumpy code to find a good x ef of values wy for that n, for the given training set. A set of values w, is good if the objective function averaged over the m training pairs is bor - the valusi w head to mostly uocunite pecedictions for all samples in the training sut, That is, the task is to write python/numpy code to solve w
gool
≈argmin
w
∑
i=1
m
L(h(x
i
,w),y)/m. How to Solve It You are required to follow the following procedure, with only minor changes if it impreves your restlta. For a given m : (1) Using peceil and paper, derive the formuln for g(x
1
,y)=∇
k
L, the gradicat of L with respect to w, rs a fuaction of training saapple values x
i+
w. Thant is, find the gradiest the vector of partial derivatives
x
j
ax
j
(x
i
,y
j
) for j=0. .., n
.
. 2 (2) Start with small (e.g. in [−0.001,0.001] range), random values for w
j
. (3) Use your formuls to enlculate g(x
i
,y
i
) for all training points, then average then: g= ∑
i
g(x
i
,w
1
)/m (4) modify of slightly: wore =w
wd
−19, where q is sone (very) small positive number, experimentally chooen to lead to good results in not-too-many iterations (5) reppent the two lines above until the quality of peedictions, ∑
i=1
m
L(h(x
i
,w),y)/m, no longer danges signiffcautly (this ean be thonesands of iterations) Once you get the good valixs of w, plot the the training samples in red color on an x−y plot with the −25 to +2.5 range of the horizontal axis. Ere scateer plot - no lines connecting the training points. On the sume plot, plot the function h(x,w)=∑
j−0
n
n
x
x
f
in blue color ( x on horizatal axis, corresponding value of h(x,w) on the vertical axis. To show the full behanviot of the function, call it with x not just from the training set, but also fot other values of x (e.g. 1se 0.01 regular spacing, ie., −2.5,−2.49,−2.48,…+2.48,+2.49,+2.5; we seatter plot with no lines conaccting these points, they should be dense enough to look like a curve). Repent for all n=1,2,3,4,5 - for each different n, prepare a separate plot.
The optimal values of w and visualize the training samples and the corresponding polynomial functions for different degrees of n.
To solve the given task of finding the optimal values of w for a polynomial h(x,w) that minimizes the squared error objective function L, we can follow the provided procedure. Here is a step-by-step guide:
Step 1: Derive the formula for the gradient of L with respect to w as a function of the training sample values x and y. This involves calculating the vector of partial derivatives of L with respect to each coefficient wj.
Step 2: Initialize the values of wj with small random values in the range [-0.001, 0.001].
Step 3: Calculate the gradient g(x,y) for each training point (x,y) and average them to obtain g.
Step 4: Update the values of w by subtracting a small positive number q times g, i.e., w_new = w_old - q * g.
Step 5: Repeat steps 3 and 4 until the quality of predictions, measured by the squared error objective function, no longer significantly changes. This may require thousands of iterations.
Step 6: Once the optimal values of w are obtained, plot the training samples as red points on an x-y plot, using a horizontal axis range of -2.5 to 2.5.
Step 7: Plot the function h(x,w) as a blue curve on the same plot, by evaluating it for various values of x within the range -2.5 to 2.5. Use a scatter plot without connecting lines.
Step 8: Repeat the above steps for different values of n, starting from n = 1 to n = 5, creating separate plots for each value of n.
By following this procedure, you will be able to find the optimal values of w and visualize the training samples and the corresponding polynomial functions for different degrees of n.
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4. A person has a beginning balance of $3,320. She charges $1,260 on the 10th day, and
she charges $270 on the 22nd day. What is her account's average daily balance?
a.
b.
d.
e.
$4,283
$4,367
$4,231
$4,345
$4,226
०२८
Ook d
Answer: (D) $4,345.
Step-by-step explanation:
PLEASE HELP!!!!!!!!.
(Please Don’t reply if you don’t know so people who do know get the points)
Answer:
true flase false true
Step-by-step explanation:
(-38) + (-4) + (-50) how do I find the answer
Answer:
Step-by-step explanation:
(-38) + (-4) + (-50) =-38-4-50
= -92
So the answer is -92
Is -2 a solution for a in the inequality 2a +6 > a
Answer:
a > −6
Step-by-step explanation:
Step 1: Subtract a from both sides.
2a + 6 − a > a − a
a + 6 > 0
Step 2: Subtract 6 from both sides.
a + 6 − 6 > 0 − 6
a > −6
Evalueate: 12(x - t)if x = 7 and t = 2
12(x - t)
if x = 7 and t = 2
12(x - t) = 12(7 - 2) = 12 * 5 = 60
Answer:
60
i can get some help please
Answer:
120°
Step-by-step explanation:
3x-105+2x+10=180
collect like terms
5x-95=180
5x=275
x=55
angle 8 is equal to angle 6 because vertically opposite angles are equal
angle 6 =(2x+10) = 120
therefore angle 8 =120 degrees
6 divided by 1/2
Which context could the expression represent?
A. Greg eats 1/2 6 pound grapes
B. Greg eats 1/2 pound of 6 pounds of grapes
C. Greg has 1/2 pound of grapes that he wants to divide into 6 bags
D. Greg has 6 pounds of grapes the he wants to divide into1/2 pound bags
Answer:
Your correct answer would be D.
Step-by-step explanation:
Answer:
The answer is D. Greg has 6 pounds of grapes that he wants to divide into pound bags.
Step-by-step explanation:
pls like!!
cashapp me $AndrewTkacs
Answer:
sure when i have money
Step-by-step explanation:
i don't have money lol
Help please!!!!! Thank you
Answer:
C
Step-by-step explanation:
So we know that:
\(f(3)=-2\text{ and } f(4)=-4\)
This is the same as saying we have two coordinates: (3,-2) and (4,-4).
Let's find the equation of the linear function.
First, let's find the slope:
\(m=\frac{y_2-y_1}{x_2-x_1}\)
Substitute (3,-2) for x₁ and y₁ and let (4,-4) be x₂ and y₂:
\(m=\frac{-4--2}{4-3}\)
Simplify:
\(m=-2/1=-2\)
So our slope is -2.
Now, use the point-slope form:
\(y-y_1=m(x-x_1)\)
Let's use (3,-2) for x₁ and y₁ and use -2 for m:
\(y+2=-2(x-3)\)
Now, we can figure out the x-intercept.
Recall that the x-intercept is when the graph touches the x-axis.
In other words, the y-value would be 0. It will be (x,0).
So, to solve for the x-intercept, substitute 0 for y and solve for x:
\(0+2=-2(x-3)\)
Simplify and distribute the right:
\(2=-2x+6\)
Subtract 6:
\(-4=-2x\)
Divide both sides by -2:
\(x=2\)
So, our x-intercept is (2,0)
Help ASAP
1. What is the volume of the cylinder shown above, rounded to the nearest hundredths?
2. What is the volume of the cylinder shown above if the radius is doubled, rounded to the nearest hundredths?
3. What is the volume of the cylinder shown above if the height is cut in half, rounded to the nearest hundredths?
Answer:
1) 169.7
2) 678.6
3) 84.9
Hope it helped!!!
De un deposito de agua lleno se sacaron 5/8 de su contenido.
despues saco la 6ta parte de lo que quedo. Calcula que parte le queda al deposito si su capacidad era de 80 litros cuantos litros de agua le sacaron?
Rafael has 118 baseball cards arranged in an album. Each page of the album can hold 9 cards. How many pages are full and how many cards are on the last page?
Answer:
Dear user,
Answer to your query is provided below
Pages full = 13
Card on last page = 1
Step-by-step explanation:
Rafael has 118 baseball cards.
Each album can hold 9.
So, using multiples of 9 or by dividing 118/9
That 1 is remainder.
So, cards on last page is 1
Verify ,
Pages full = (118-1)/9 = 13
In ΔNOP, the measure of ∠P=90°, the measure of ∠O=37°, and PN = 72 feet. Find the length of OP to the nearest tenth of a foot.
Answer:
119.6
Step-by-step explanation:
Remark
Draw a rough sketch of what is given.
You will find the NP is the side opposite of the triangle.
P is the right angle
OP is the hypotenuse.
Given
NP = 72
<O = 37
Equation
Sin(O) = NP/OP
Sin(72) = .6018
0.6018 = 72/OP Multiply both sides by OP
0.6018*OP = 72 Divide both sides by 0.6018
OP = 72/0.6018
OP = 119.6
5. Use the digits 3, 4, 5, 6, 7 and 8 to complete the statement.
Answer:
Step-by-step explanation:
i don't see a statement but use 7 i guess
The ratio of boys and girls in the class is 4:3. How many boys and girls are in the class if there are 35 students?
Answer:
20boys and 15girls
Step-by-step explanation:
Let no of boys be 4x
no of girls be 3x
4x+3x=35
7x=35
x=35/7
x=5
no of boys=4×5=20
no of girls=3×5=15
20+15=35 students
The measure of an angle is thirty-five times the measure of its complementary angle. What is the measure of each angle?
Answer:
35x + x = 180
36x = 180
x = 180/36
x = 5
Solve the following problem using proper numerical methods and time steps (Gerald, Applied numerical analysis). Report your results along with analytical solutions, comparisons, plots and MATLAB scripts. Check the table for your parameters. APP7. A vibrating string, with a damping force-opposing its motion that is proportional to the velocity, fol- lows the equation where B is the magnitude of the damping force. Solve the problem if the length of the string is 5 ft with 7-24 lb, w=0.1 lb/ft, and B= 2.0. Initial conditions are XXX--05x<3, XXX 3≤x≤5, = x(x - 5). Compute a few points of the solution by difference equations. 1/s B TP parameters Newton kg/m T W 140 2.4 14
To solve the problem of a vibrating string with damping using numerical methods and time steps, follow these steps:
1. Discretize the string into a set of points along its length.
2. Use a finite difference method, such as the central difference method, to approximate the derivatives in the equation.
3. Apply the difference equation to each point on the string, considering the damping force and given parameters.
4. Set up the initial conditions for the string's displacement and velocity at each point.
5. Iterate over time steps to update the displacements and velocities at each point using the finite difference equation.
6. Compute and store the values of the solution at selected points for analysis.
7. Compare the numerical solution with the analytical solution, if available, to assess accuracy.
8. Plot the results to visualize the behavior of the vibrating string over time.
9. If using MATLAB, write a script to implement the numerical method and generate plots.
Note: The specific equation and initial conditions are missing from the given question, so adapt the steps accordingly.
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observations consisting of pairs of variable data are required to construct a ________ chart.
Observations consisting of pairs of variable data are required to construct a scatter plot chart. A scatter plot chart is a graphical representation of the relationship between two variables.
One variable is plotted on the horizontal axis, while the other variable is plotted on the vertical axis. Each point on the chart represents an observation or data point consisting of a pair of values for the two variables being plotted. The scatter plot chart is useful for identifying patterns, trends, and relationships between the variables. It can also be used to detect outliers or unusual observations that do not follow the general pattern of the data.
The scatter plot chart can be enhanced by adding regression lines or trend lines, which provide a visual representation of the linear relationship between the two variables. Overall, the scatter plot chart is a powerful tool for analyzing and understanding the relationship between two variables in a dataset.
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Observations consisting of pairs of variable data are required to construct a scatter chart.
A scatter chart is a graphical representation of a set of observations where one variable is plotted on the x-axis and the other variable is plotted on the y-axis. Scatter charts are useful in identifying patterns and relationships between the two variables. The strength and direction of the relationship between the variables can be determined by examining the pattern of the scatter chart. If the data points are tightly clustered around a straight line, then there is a strong linear relationship between the two variables. On the other hand, if the data points are scattered without any pattern, then there is no relationship between the two variables. Scatter charts are commonly used in scientific research, marketing analysis, and other fields where two variables need to be analyzed simultaneously.
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how many solutions are there to the equation 4(x-5)=3x+7
Answer:
1, and that is 27
Step-by-step explanation:
4(x-5)=3x+7
4x-20=3x+7
4x-3x-20-7=0
x-27=0
x=27
You are managing one of the Tandoor-India's restaurant. All the table are walk-in (no reservation can be made in advance). Customers that arrive and request a table are divided as follows: 50% require a table of size two, 40% require a table of size four, and 10% request a table of size six. The average waiting times for each type of table is given as: The number of parties waiting for a table for two is on average 2 . Hint: This question is on the Little's law. a) What is the arrival rate of parties requesting of size two per hour? 12 parties per hour. b) What is the total arrival rate of parties requesting tables (of any size) per hour? 24 parties/hr. c) What is the average number of parties requesting table of size four per hour? 9.6parties/hr. d) What is the average number of parties waiting for a table for four?
a) The arrival rate of parties requesting a table of size two per hour is 50% of the total arrival rate. Therefore, it is 0.5 * 24 = 12 parties per hour.
b) The total arrival rate of parties requesting tables of any size per hour is 24 parties per hour.
c) The average number of parties requesting a table of size four per hour is 40% of the total arrival rate. Therefore, it is 0.4 * 24 = 9.6 parties per hour.
d) The average number of parties waiting for a table of size four is given as 2 parties.
a) The arrival rate of parties requesting a table of size two per hour is calculated by taking the percentage of parties requesting a table of size two out of the total arrival rate. In this case, 50% of the parties require a table of size two. So, the arrival rate for parties requesting a table of size two is 0.5 * 24 = 12 parties per hour.
b) The total arrival rate of parties requesting tables of any size per hour is simply the sum of the arrival rates for each table size. In this case, we have an arrival rate of 12 parties per hour for tables of size two, 40% of the parties require a table of size four (which corresponds to an arrival rate of 0.4 * 24 = 9.6 parties per hour), and 10% of the parties request a table of size six (which corresponds to an arrival rate of 0.1 * 24 = 2.4 parties per hour). Adding these arrival rates together gives a total arrival rate of 12 + 9.6 + 2.4 = 24 parties per hour.
c) The average number of parties requesting a table of size four per hour is calculated by taking the percentage of parties requesting a table of size four out of the total arrival rate. In this case, 40% of the parties require a table of size four. So, the average number of parties requesting a table of size four per hour is 0.4 * 24 = 9.6 parties per hour.
d) The average number of parties waiting for a table of size four is given as 2 parties. This means, on average, there are 2 parties waiting for a table of size four at any given time.
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find the length of YZ
Help!!!!!!!!!!!!!!!!!!!!!!
write the inverse of f(x) = x + 5
Answer:
f^-1(x) = x - 5
Step-by-step explanation:
f(x) = x + 5
y = x + 5
x = y + 5
y = x - 5
f^-1(x) = x - 5
Answer:
f^ -1(x) = x - 5
Step-by-step explanation:
y =x+5
To find the inverse, exchange x and y
x = y+5
Solve for y
Subtract 5 from each side
x-5 = y+5-5
x-5 = y
The inverse is x-5
the rate of growth of a fish population was modeled by the equation , where t is measured in years since 2000 and g in kilograms per year. if the biomass was 25,000 kg in the year 2000, what is the predicted biomass for the year 2020?
the predicted biomass for the year 2020 is 41,666 kg.
What is exponential?
The exponential is an example of a mathematical function that is useful in determining if something is increasing or decreasing exponentially is the exponential function. As implied by its name, an exponential function uses exponents. But take note that an exponential function does not have a variable as its exponent and a constant as its base (if a function has a variable as the base and a constant as the exponent then it is a power function but not an exponential function).
The growth rate function's units on it (along with 4t and dt) are years, therefore year = kg year will result in an integral that will show the net change in kilogrammes from 2000 to 2020.
if the biomass was 25,000 kg in the year 2000, what is the predicted biomass for the year 2020.
WE GET: 60000(-1/3) ∫(1/u)
=16666
This is the change in biomass from 2000 to 2020. Thus, the predicted biomass for 2020 is about (25000 + 16,666) = 41,666 kg.
Hence, the predicted biomass for the year 2020 is 41,666 kg.
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Which of the following is the solution of the quadratic equation xଶ 3x − 10 0?
The solutions of the quadratic equation x^2 + 3x - 10 = 0 are x = 4 and x = -1.
The solution of the quadratic equation x^2 + 3x - 10 = 0 can be found by using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
Where (a, b, and c) are 1, 3, and -10
So, the solutions of the equation x^2 + 3x - 10 = 0 are:
x = (-3 ± √(3^2 - 4(1)(-10)) ) / 2(1)
x = (-3 ± √(9 + 40)) / 2
x = (-3 ± √49) / 2
x = (-3 ± 7) / 2
x = (4, -1)
Complete question:
Which of the following is the solution of the quadratic equation x^2 - 3x − 10 = 0?
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Determine the value of x. images attached.
Answer:
The answer is option AStep-by-step explanation:
Since it's a right angled triangle we can use trigonometric ratios to find the value of x
To find the value of x we can use either sine or cosine
Using sine we have\( \sin(30) = \frac{5}{x} \\ x \sin(30) = 5 \\ x = \frac{5}{ \sin(30) } \\ x = \frac{5}{0.5} \\ \\ \\ \boxed{x = 10}\)
Using cosine we have\( \cos(60) = \frac{5}{x} \\ x \cos(60) = 5 \\ x = \frac{5}{ \cos(60) } \\ x = \frac{5}{0.5} \\ \\ \\ \boxed{x = 10}\)
Hope this helps you