Every day certain amount of water evaporates from Earth'$ oceans, lakes and land surface and forms water vapor and clouds in the atmosphere. Every day certain amount of rain falls back t0 Earth Make the reasonable assumption that, on average , the energy absorbed by the evaporation and lifting of the water is equal to the energy released by its condensation and falling back to earth. The evaporation of one mole of water requires approximately 40.6x10* J of heat. An equal amount of heat is released when a mole of water condenses The annual volume of rainfall on Earth is approximately 5.IxlOS km? and the average cloud altitude is 8.1 km above Earth'$ surface. How much energy, in joules required every day to evaporate and lift the water? Grade Summary E = 114 1018 Deductions 6 % Potential 949 Submissions sino cosu tano) HOME

The velocity of the projectile when it lands is 71.218 m/s.

The resultant velocity of the projectile when it lands is calculated by applying the following formula.

V = √ ( Vx²  + Vy² )

where;

The given parameters include the following;

the vertical velocity of the projectile = 44 m/s

the horizontal velocity of the projectile = 56 m/s

V = √ ( Vx²  + Vy² )

V = √ ( 56²  + 44² )

V = 71.218 m/s

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The capacitance of an air-filled capacitors does not change is if electric field in between plates is made weaker by discharging the plates:

The external unit's malfunctioning due to a defective capacitor impedes the cooling procedure as a whole. Second, the system must work harder to complete its task due to poor voltage distribution to outer unit components. A defective capacitor frequently causes harm to additional components.

In a simple parallel-plate capacitor, applying a voltage between 2 conducting plates creates an equal electric field between both the plates. The electrical field intensity in a capacitor is inversely related to the distance between the plates but directly proportional to the applied voltage.

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Answer:

melanie ran 8.3 meters per second

Explanation:

I think thats right, hope it helps.

Answer:

5 sig figures

Explanation:

When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called a Neutron star.

Stars are present in the galaxy that have the ability to generate their own light. They are both quite hot and very huge.

They are largely formed of hydrogen, with a trace of helium thrown in for good measure.

The sun is also a star, and its energy and light play an important part in the survival of all kinds of life on Earth.

When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called a Neutron star.

Hence the correct answer is a neutron star.

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High-intensity interval training (HIIT) can be included in a training plan to improve anaerobic power in a 16-year-old sprinter.

Anaerobic power is the ability to perform short, high-intensity bursts of activity without relying on oxygen. HIIT involves alternating periods of high-intensity exercise with periods of rest or lower intensity exercise. This type of training has been shown to improve anaerobic power in athletes. A track coach may design a HIIT program that includes sprints, plyometric exercises, and resistance training to improve the sprinter's power and speed.

However, it is important for the coach to consider the individual athlete's current fitness level and adjust the intensity and volume of the program accordingly to avoid injury and overtraining. Adequate rest and recovery time should also be included in the training plan to allow for proper adaptation and improvement in performance.

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The magnitude of the boat's velocity relative to the ground is 8.8 m/s, the direction of the boat's velocity relative to the ground is 16.4° east of due north, and it takes 35.26 seconds to cross the river.

Given:

Width of the river (d) = 140 m

Speed of the river \((v_{river})\\\) = 2.4 m/s

Speed of the boat relative to the water \((v_{boat})\) = 8.5 m/s

The angle of the boat's direction relative to due north (θ) = 29° west

(a) Magnitude of the boat's velocity relative to the ground:

by the Pythagorean theorem :

\(v_{ground} = \sqrt{((v_{boat})^2 + (v_{river})^2)}\\v_{ground} = \sqrt{((8.5 m/s)^2 + (2.4 m/s)^2)}\\v_{ground} = 8.8 m/s\)

(b) Direction of the boat's velocity relative to the ground:

\(tan \theta = \frac{(v_{river})}{(v_{boat})}\\\Theta = \frac{1}{tan} \times \frac{((v_{river})}{(v_{boat)})}\\\theta = \frac{1}{tan} \times \frac{2.4}{8.5}}\\\theta = 16.4^o\)

(c) Time is taken to cross the river:

The component of the boat's velocity perpendicular to the river is given by:

\(v_{perpendicular} = v_{boat} \times sin\theta\\v_{perpendicular} = 8.5 \times sin(29^o)\\v_{perpendicular} = 3.97 m/s\)

Time is taken to cross the river:

\(t = \frac{d}{v_{perpendicular}}\\\)

\(t = \frac{140}{3.97}\\t = 35.26 s\)

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The weight can be used to determine the force component that causes motion as the weight is the full force that acts perpendicular to the surface of the ramp. The correct option is A.

In mechanics, acceleration is widely recognized as the rate of change of an object's basic velocity with respect to the time.

Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Acceleration is basically the rate at which velocity alters over time, both in way of speed and direction.

A point or object going in a straight line is accelerated either it accelerates or decelerates. Even if the speed is constant, motion on a circle is accelerated because the direction is constantly changing.

Because the weight is the full force acting perpendicular to the surface of the ramp, it can be used to determine the force component that causes motion.

Thus, the correct option is A.

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Answer:

C. The weight times the sine of the angle of the ramp acts down along the ramp.

Explanation:

eg 2023

We can see here that the cash that Stowe-Arts Holdings Co. would get from the customer is $171,500. C. $171,500.

A customer is an individual, organization, or entity that purchases goods, services, or products from a business or supplier. Customers are the key stakeholders in business transactions and play a crucial role in driving economic activity.

To calculate the cash received by Stowe-Arts Holding Co., we can subtract the discount from the total amount owed.

Total amount owed: $175,000

Discount: 2% of $175,000 = $3,500

Cash received = Total amount owed - Discount

Cash received = $175,000 - $3,500

Cash received = $171,500

Therefore, the cash that Stowe-Arts Holdings Co. would get from the customer is $171,500.

Thus, the correct answer is C. $171,500.

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The complete question is:

Stowe-Arts Holdings Co. has a very attractive credit policy, and none of its customers pays in cash when the firm makes a sale. Stowe-Arts Holdings Co. sells to its customers on credit terms of 2/10, net 30.

If a customer bought $175,000 worth of goods and paid the firm cash eight days after the sale, how much cash would Stowe-Arts Holdings Co. get from the customer?

A. $183,750

B. $157,500

C. $171,500

D. $140,000

Testable hypotheses are the theoretical problems that operational definitions have converted into.

Scientific observation is an empirical research designed to systematically address issues about the world. Through the use of operational definitions, theoretical questions are converted into. a provable theory. The measurement process for measuring external, observable behaviour is specified in Operational Definitions. The measurements that are obtained are utilised to define and quantify the construct. A measurement process (a collection of operations) is specified in an operational definition for the purpose of measuring an external, observable behaviour, and the definition and measurement of the hypothetical construct are then based on the results of the measurement procedure. No matter how solid your conceptual definition may be, you cannot measure anything without an operational definition.

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The magnitude e of the induced electromotive force (emf) can be determined using Faraday's law of electromagnetic induction.

According to Faraday's law, the emf induced in a conductor is equal to the rate of change of magnetic flux through the conductor.

In this scenario, the magnetic field steadily decreases from B to zero during a time interval t. The change in magnetic field induces an emf in a nearby conductor.

The magnitude of the induced emf can be calculated using the formula:

e = -dΦ/dt

where e is the induced emf, dΦ/dt is the rate of change of magnetic flux, and the negative sign indicates the direction of the induced current.

Since the magnetic field decreases linearly from B to zero, the rate of change of magnetic flux can be expressed as:

dΦ/dt = -dB/dt

Substituting this into the formula, we get:

e = -(-dB/dt) = dB/dt

Therefore, the magnitude of the induced emf is equal to the rate of change of the magnetic field.

In this case, as the magnetic field steadily decreases from B to zero during the time interval t, the magnitude of the induced emf e will be equal to the rate of change of the magnetic field, dB/dt.

Please note that the specific value of dB/dt would depend on the details of the situation and how the magnetic field is changing with time.

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Wave B has a greater wavelength. Option B is correct.

The frequency and wavelength of a wave are inversely proportional to each other. Mathematically, the relationship between the two is given by the equation:

where c is the speed of light, λ is the wavelength, and f is the frequency of the wave.

Since light wave A has a greater frequency than light wave B, we can conclude that light wave B has a greater wavelength than light wave A. This is because as the frequency increases, the wavelength decreases, and as the frequency decreases, the wavelength increases. Therefore, if two waves have different frequencies, the one with the lower frequency will have a greater wavelength. Hence Option B is correct.

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Answer:

Sketch the situation.

b. Calculate the potential energy, the kinetic energy, and the total energy of the car as it leaves the cliff.

c. Make a graph displaying the kinetic, gravitational potential, and total energy of the car at each 10 m

increment of height as it drops

Explanation:

The potential energy of the car at that position is 10.6 x 10⁵ J.

Potential energy of an object is defined as the energy acquired by the object by virtue its position.

Here,

Mass of the car, m = 1200 kg

Speed of the car, v = 29 m/s

Height of the cliff, h = 90 m

Therefore,

Potential energy of the car, PE = mgh

PE = 1200 x 9.8 x 90

PE = 10.6 x 10⁵ J

Hence,

The potential energy of the car at that position is 10.6 x 10⁵ J.

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Answer:

read this it might help some

When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.

Explanation:

We have added the potential energy and kinetic energy to find the total energy of the system, which comes out to be 2.317 J.

Given,

Mass of the pendulum bob, m = 365 g

= 0.365 kg

Length of the pendulum, L = 0.760 m

Angle made with the vertical, θ = 12°

First, we need to find the total potential energy (PE) of the system.

For this, we can use the following formula,PE = mgh

Where h is the height from the reference point where we take PE as 0.

Here, we can consider the equilibrium position as the reference point.

Therefore, the height (h) can be calculated as,

h = L – L cosθ

= L (1 – cosθ)

Now, putting the values,

PE = mgh

= 0.365 × 9.81 × 0.760 (1 – cos 12)

= 2.191 J

Next, we need to find the total kinetic energy (KE) of the system.

At the highest point, the speed of the bob will be zero.

At the lowest point, the speed of the bob will be maximum.

Therefore, the KE can be calculated as,KE = 1/2 mv² Where, v is the speed of the bob at the lowest point. We can find v using the conservation of energy formula as shown below,

KE + PE = Constant

The constant value is equal to the total energy (E) of the system.

Therefore,E = KE + PE

At the highest point, the total energy of the system is equal to PE. Therefore,

E = PE = 2.191 J

At the lowest point, the total energy of the system is equal to KE + PE.

Therefore,

1/2 mv² + mgh = E

1/2 mv² + mgh = 2.191 J

1/2 × 0.365 × v² + 0.365 × 9.81 × 0.760 (1 – cos 12) = 2.191 J

V = √(2(2.191 – 0.365 × 9.81 × 0.760 (1 – cos 12)))

V = 0.777 m/s

Therefore, KE = 1/2 mv²

= 1/2 × 0.365 × 0.777²

= 0.126 J

The total energy (E) of the system is,

E = KE + PE

= 0.126 + 2.191

= 2.317 J

Therefore, the total energy of the system is 2.317 J.

In this problem, we have used the formula of conservation of energy to find the total energy of the given system. We have first calculated the potential energy (PE) of the system and then used the conservation of energy formula to find the total energy (E) of the system. Using the total energy and the potential energy, we have found the kinetic energy (KE) of the system. Finally, we have added the potential energy and kinetic energy to find the total energy of the system, which comes out to be 2.317 J.

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Answer:7.99 m/s^2

Explanation:

Explanation:

The velocity of the wave is:

v = (9.0π rad/s) / (0.1π / cm)

v = 90 cm/s

v = 0.9 m/s

Velocity of a standing wave on a stretched string is:

v = √(T / (m/L))

0.9 m/s = √(0.081 N / (M / 2.0 m))

0.81 m²/s² = 0.081 N / (M / 2.0 m)

M / 2.0 m = 0.1 kg/m

M = 0.2 kg

Answer:

a

Explanation:

The differential equation for the concentration of the chemical is given by dc/dt = (3/10⁶)(1 - 100c)

Suppose that a(t) is the amount of chemical in the pond at time t.

So, a'(t) = rate of chemical inflow - the rate of chemical outflow.

So, da/dt = (0.01)300 - (a/10⁶)300

So, da/dt = 3 - 3a/10⁴

Now,

Since, c = a/v

Then, c' = a'/v

So, c' = (3 - 3a/10⁴)/10⁶

Or, c' = 3 (1 - a/10⁴)/10⁶

So, dc/dt = 3/10⁶ (1 - cv/10⁴)

So, dc/dt = (3/10⁶) (1 - 100c)

Therefore the differential equation for the concentration of the chemical is dc/dt = (3/10⁶)(1 - 100c)

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Answer:

6970 N

Explanation:

To calculate the average force exerted on the ball, we can use the impulse-momentum theorem, which states that the impulse on an object is equal to its change in momentum. In equation form:

Impulse = Δp

where Impulse is the force applied over a given time, and Δp is the change in momentum of the object.

We can calculate the momentum of the ball before the hit as:

p1 = m * v1

where m is the mass of the ball and v1 is its initial velocity (which we assume to be zero). Substituting the given values, we get:

p1 = (0.85 kg) * 0 m/s = 0 kg m/s

The momentum of the ball after the hit is:

p2 = m * v2

where v2 is the final velocity of the ball (82 m/s). Substituting the given values, we get:

p2 = (0.85 kg) * 82 m/s = 69.7 kg m/s

The change in momentum (Δp) is therefore:

Δp = p2 - p1 = 69.7 kg m/s - 0 kg m/s = 69.7 kg m/s

The impulse on the ball is equal to the change in momentum, so we have:

Impulse = Δp = 69.7 kg m/s

Finally, we can calculate the average force exerted on the ball using the formula:

Impulse = Force * time

Substituting the given values, we get:

69.7 kg m/s = Force * 0.01 s

Solving for Force, we get:

Force = 6970 N

Therefore, the average force exerted on the ball by the bat is 6970 Newtons.

Answer:

a=845.07 m/s2

Explanation:

m=0.142kg

F=120N

a=?

F=m*a /:m

a=F/m

a=120N/0.142kg

a=845,07m/s2

Answer:

a = 845.07 m/s²

Explanation:

As we know ,

as per newton's 2nd law:-

F = ma

therefore

a = F/m

given:

a = ?

F = 120N

m = 0.142 kg

procedure:-

a = 120/0.142

therefore :

a = 845.07 m/s²

Explanation:

vertical force = 460,000 * sin(70) - 300,000

Fv = 187,717.75N

Jill's power output is 4 times greater than Jack's power output.

Let's assume that Jack's power output  \(P_j\) and the amount of work he does is \(W_j\).

According to the problem, Jill does twice as much work as Jack does, so her amount of work can be expressed as \(2W_j\).

Jill also does the work in half the time, so her time can be expressed as \(0.5t_j\), where  \(t_j\) is the time it takes for Jack to do his work.

The power output for both can be expressed as:

\(P_j = \dfrac{W_j}{t_j}\)

\(P_s = \dfrac{2W_j}{(0.5t_j)} = \dfrac{4W_j}{t_j}\)

So, the ratio of Jill's power output to Jack's power output is:

\(\dfrac{P_s}{P_j} = \dfrac{4W_j}{t_j}\times \dfrac{W_j}{t_j} = 4\)

Therefore, Jill's power output is 4 times greater than Jack's power output.

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Answer:

To foster trade between southern states and South American nations. Also to show the products and facilities to share in Europe & rest of nation.

The tension in the cable is approximately 100.69 N when the load initially accelerates upwards at 1.21 m/s².

To determine the tension in the cable while the crane is pulling a load vertically upward, we need to consider the forces acting on the load.

In this scenario, we have two forces acting on the load: the weight of the load (mg) acting downward and the tension in the cable (T) acting upward.

The net force on the load is given by the equation:

Net force = ma

where m is the mass of the load and a is the acceleration.

We can find the mass (m) of the load using the formula:

m = weight / gravitational acceleration

Given the weight of the load is 815 N, and the gravitational acceleration is approximately 9.8 m/s², we have:

m = 815 N / 9.8 m/s²

≈ 83.16 kg

Now we can calculate the net force:

Net force = m * a

= 83.16 kg * 1.21 m/s²

≈ 100.69 N

Since the tension in the cable acts upward to counterbalance the weight of the load, the tension in the cable is equal in magnitude to the net force acting on the load.

Therefore, the tension in the cable is approximately 100.69 N when the load initially accelerates upwards at 1.21 m/s².

It's important to note that in this calculation, we assume ideal conditions, neglecting factors such as friction and air resistance.

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Answer:

   V = 12V,  V = 8V

Explanation:

a) In this series circuit the equivalent resistance is

          Req - R1 + R2

          Req = 30 + 20

          Eeq = 50 Ω

b) see attached

c) the circuit current is

          i = V / Req

          i = 20/50

          i = 0.4 A

voltages are>

         V = 0.4 30

          V = 12V

           V = 0.4 20

            V = 8V

The weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

The given parameters:

The gravitational force on the satellite is calculated by applying Newton's law of universal gravitation is calculated as;

\(F = \frac{Gm_1m_2}{R^2} \\\\F_1 R_1^2 = F_2R_2^2\\\\F_2 = \frac{F_1 R_1^2 }{R_2^2} \\\\F_2 =\frac{200 \times R_1^2}{(2R_1)^2} \\\\F_2 = \frac{200 \times R_1^2 }{4R_1} \\\\F_2 = 40 \ N\)

Thus, the weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

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Answer:

c. It is incorrect because sodium phosphate is a compound that has a single composition.

Explanation:

As we know that the sodium phosphate i.e.  chemical compounds comprise of atoms that are interconnected with the bonds of the chemicals

Also the pure substance that is made by only and only one atom or element or only one type of molecule i.e. compound that contains definite and constant composition with different properties of chemicals

the pure substances could be distinct in chemical way but not in the physical manner that represents the difference between the mixture and the pure substance

Hence, the correct option is c.

Answer:

C) - It is incorrect because sodium phosphate is a compound that has a single composition.

Explanation:

Just did the test, good luck :)

Answer:

K = 9000 J

Explanation:

Given that,

The mass of a boat, m = 2000 kg

The velocity of the boat, v = 3 m/s

We need to find the kinetic energy of the boat. We know that the kinetic energy of an object is given by :

\(K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 2000\times 3^2\\\\K=9000\ J\)

So, the required kinetic energy is equal to 9000 J.