Answers
Related Questions
A roller coaster moves 85 m horizontally and then travels 45 m at an angle of 30 degrees above the ground. What is the displacement from the starting point?
Answers
The total distance covered by the roller coaster can be determined using the cosine rule. The displacement from the starting point is 126 m.
What is cosine rule?According to cosine rule, when the the movement of a particles describes a right angled triangle, then the unknown side x can be calculated by the expression as follows:
x² = a² + b² - 2a b cos θ
where a and b are the know sides of the triangle and θ be the angle opposite to the known angle.
Given that the roller coaster moves 85 m first then turn 30 degrees and move 45 m. The opposite angle of the right angled triangle here will be 180 - 30 = 150
Then the displacement x = √(85²+ 45² - 2 ×85 ×45 cos 150) = 126 m
Therefore, the displacement from of the roller coaster from the starting point will be 126 m.
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7 x 7 x 7 x.........x 7 = n (30 times)
7 is multiplied 30 times to get a number n. Which of the following will be a factor of n?
Answers
On her camping trip, Penelope was in charge of collecting firewood. The firewood she found had a mass of 120 g and a volume of 480 cm3. What is the density of the firewood? Explain the steps you took to solve this problem.
Answers
Answer:
D = .25g/cm³
Explanation:
D = m/V
D = 120g/480cm³
D = .25g/cm³
Student 1 is standing on a cart holding a small
stone, while student 2 is standing at rest on the
ground, as shown in the figure above. The cart is
moving at a constant speed v in the #r-direction,
as indicated by the coordinate system shown.
Student 1 drops the stone precisely when passing
student 2. Which of the following best represents
the path of the falling stone relative to student 1
and the path of the falling stone relative to
student 2 ?
Answers
Answer: C
Explanation: student 1 has a vel to the right
The path of the falling stone relative to student 1 is straight down while it is parabolic to student 2.
What is a motion?Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point, especially due to the action of an external force.
As shown in the image attached below, the path of the falling stone relative to student 1 is straight down while it is parabolic to student 2 because student 1 is standing on a cart that is moving at a constant speed and student 2 is stationary i.e standing at rest on the ground.
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A stone is dropped off a cliff. After this stone has traveled a distance d . A second stone is dropped. the distance between the two stones will be?
A. Decrease at first then stay constant
B. Increase at first then stay constant
C. Increase
D. Decrease
E. Stay constant
Answers
Answer:
the same stones distance will be condtant .
so option no E
What is the weight, on Earth, of a book with a mass of 1.5 kg?
0 1,5 N
0 6,5 N
O 11.3N
0 14 7 N
Answers
Answer:
\(\boxed {\tt 14.7 \ Newtons}\)
Explanation:
Weight is force due to gravity.
The formula for weight is:
\(W=m*g\)
where m is the mass and g is the acceleration of gravity.
On Earth, the acceleration due to gravity is 9.8 meters per seconds squared.
The mass of the book is 1.5 kilograms. Therefore:
\(m= 1.5 \ kg \\g=9.8 \ m/s^2\)
Substitute the values into the formula.
\(W= 1.5 \ kg *9.8 \ m/s^2\)
Multiply.
\(W=14.7 \ kg*m/s^2\)
1 kg meter per second squared is equal to 1 Newton, so our answer of 14.7 kg*m/s² is equal to 14.7 Newtons.
\(W=14.7 \ N\)
The weight of a 1.5 kilogram book on Earth is 14.7 Newtons.
Answer:
Answer:
Explanation:
Weight is force due to gravity.
The formula for weight is:
where m is the mass and g is the acceleration of gravity.
On Earth, the acceleration due to gravity is 9.8 meters per seconds squared.
The mass of the book is 1.5 kilograms. Therefore:
Substitute the values into the formula.
Multiply.
1 kg meter per second squared is equal to 1 Newton, so our answer of 14.7 kg*m/s² is equal to 14.7 Newtons.
The weight of a 1.5 kilogram book on Earth is 14.7 Newtons.
Explanation:
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In our warmup today we're looking closer at our aquariums. We need to get them clean so we can start a new aquarium setup , but there's something on the inside of the glass, the outside of the hood, and the outside of the filter.
1. What is that white residue on our aquariums?
2. How does it form?
3. Where does it come from?
4. How do we get rid of it?
Answers
The white residue on aquariums could be mineral , such as hard water stains, and it formed as a result of the hard substance remaining after water evaporation. It is from the water, and to remove it, a white vinegar and water mixture should be used.
What is the significance of the aquarium?Its significance includes that an aquarium can be a place for people to learn about aquatic animals, for the conservation of some animals, for entertainment, and also for use in research proposals, etc.
Hence, the white residue on aquariums could be mineral , such as hard water stains, and it formed as a result of the hard substance remaining after water evaporation. It is from the water, and to remove it, a white vinegar and water mixture should be used.
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Frick and Frack are standing back-to-back, leaning on each other, but not moving. If Frick weighs
165 pounds and Frack weighs 210, who is pushing harder?
Answers
Answer:
Frick is pushing harder
Explanation:
if Frack weighs more and he was pushing harder they would be moving, but if Frick pushes harder then they wont move
Answer:
they are both pushing with the SAME force
Explanation:
Since no one is moving, the system of the two friends is NOT accelerated, which means that the net force on it is zero. then, the force applied by each is of the SAME magnitude but in opposite directions.
Therefore they are both pushing with the SAME force.
A 92-kg fullback is running at 3.6 m/s to the east and is stopped in 0.85 s by a head-on tackle by a tackler running due west.
a)Calculate the original momentum of the fullback.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the momentum is to the east, and negative value if the direction of the momentum is to the west.
b)Calculate the impulse exerted on the fullback.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the impulse is to the east, and negative value if the direction of the impulse is to the west.
c)Calculate the impulse exerted on the tackler.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the impulse is to the east, and negative value if the direction of the impulse is to the west.
d)Calculate the average force exerted on the tackler.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the force is to the east, and negative value if the direction of the force is to the west.
Answers
a) The original momentum of the fullback is 331.2 kgm/s.
b) The impulse exerted on the fullback is - 331.2 kgm/s
c) The impulse exerted on the tackler is 331.2 kgm/s
d) The average force exerted on the tackler is 389.64 N
Given:Mass of the fullback, m = 92 kg
Initial velocity of the fullback , u = 3.6 m/s
Time of the motion of the fullback , t = 0.85s
The original momentum of the fullback ;
\(P_{i} = mv\\P_{i} = (92) (3.6)\\P_{i} = 331.2 kg m/s\)
The impulse exerted on the full-back;
J = ΔP = \(m v_f - m v_i\)
J = \(m ( v_f - v_i)\)
J = 92 ( 0- 3.6)
J = - 331.2 kgm/s
The impulse exerted on the tackler;
\(J _1 = - J _2\\J_2 = - J_1\\J_2 = -( - 331.2)\\J_2 = 331.2 kgm/s\)
The average force exerted on the tackler;
F= Δmv/t
\(F =\frac{331.2}{0.85} \\F = 389.64 N\)
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Gold-198 is a radioactive isotope, and it has a half-life of about 2.5 days.
You have 100 grams of Gold-198. How many grams remain after 20 days?
3.125 grams
1.5625 grams
0.78125 grams
0.390625 grams
Answers
Answer: 0.390625 grams
Explanation:
A half-life of an element is the amount of time that it takes for half the mass of the element to decay.
Gold-198 having a half-life of 2.5 days therefore means that every 2.5 days, the mass is cut in half.
If there are 20 days, find out how many half-life periods there are:
= 20 / 2.5
= 8 periods
The half life is:
= Original mass * 0.5^number of half-life periods
= 100 * 0.5⁸
= 0.390625 grams
a ford explorer traveled 100 miles the next day for 5 hours. What was the average speed of this vehicle?
Answers
Answer:
25 miles per hour
Explanation:
It was 20 miles per hour the next day. We don't have enough information to calculate the average speed for the whole trip.
Using what you have learned about research methods, what are some of the limitations of Freud’s theory of personality? 1. _______________________________________________________________________________________ 2. ________________________________________________________________________________________ 3. ________________________________________________________________________________________ 4. ________________________________________________________________________________________ 5. ________________________________________________________________________________________
Answers
Using what has been learned about research methods, some of the limitations of Freud’s theory of personality are
Scientifically, it is challenging to test his hypotheses.It is hard to quantify ideas like libido, hence they cannot be tested.Research has been done, and it tends to refute Freud's notion.Predictions of the future are too hazy.This is further explained below.
What is the Freudian theory?Generally, Id, ego, and superego, according to Freud, make up the three parts of the mind, and interactions and conflicts between these parts are what provide personality (Freud, 1923/1949).
The id, according to Freudian thought, is the psychological trait that serves as the foundation for our most primal instincts.
In conclusion,
Scientifically, it is challenging to test his hypotheses.It is hard to quantify ideas like libido, hence they cannot be tested.Research has been done, and it tends to refute Freud's notion.Predictions of the future are too hazy.Read more about Freudian theory
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5. The net external force on a rock of mass 4.2 kg is 8.0 N forward. Find the acceleration of the rock.
Answers
Answer:
1.904
Explanation:
F= ma
8 = 4.2 a
a = 8/4.2
a = 1.904
A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?
Answers
Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.
In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.
The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.
A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.
Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.
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WILL GIVE BRAINLY AND 100 POINTS A toy rocket of mass 12kg is launched upwards with an initial velocity of 3m/s. Use conservation of energy to determine how high it flies.
Answers
36 feet I'm hoping because that's what I got
Answer:
Its should be 46 feet.
Explanation:
Im so sorry if im wrong. Im learning this too rn. ahahh
What is the mass (in kg) of a Puffin flying 10 m/s with 1000 J of KE?
Answers
Answer:
20 kg
Explanation:
The kinetic energy (KE) of an object is given by:
KE = (1/2) * m * v^2
Where m is the mass of the object, and v is its velocity.
We can rearrange this formula to solve for the mass:
m = 2 * KE / v^2
Plugging in the values given:
m = 2 * 1000 J / (10 m/s)^2
m = 20 kg
Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.
The pulley is assumed massless and frictionless and rotates freely about its axle. The
blocks have masses m1 = 40 g and m2 = 20 g, and block m1 is pulled to the right by a
horizontal force of magnitude F = 0.03 N. Find the magnitude of the acceleration of block m2 and the tension in the cord if the surface is frictionless
Answers
The magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.
Acceleration of block m2
The acceleration of bock m2 is calculated from Net force exerted by the pulley.
F - T = m2a
F - m1a = m2a
F = m2a + m1a
F = a(m2 + m1)
a = F/(m1 + m2)
a = (0.03) / (0.04 + 0.02)
a = 0.5 m/s²
Tension in the cordT = m1a
T = 0.04 x 0.5
T = 0.02 N
Thus, the magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.
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after a great many contacts with the charged ball, how is any charge on the rod arranged (when the charged ball is far away)? select the best description. view available hint(s)for part b after a great many contacts with the charged ball, how is any charge on the rod arranged (when the charged ball is far away)?select the best description. positive charge on end b and negative charge on end a negative charge spread evenly on both negative charge on end a with end b remaining neutral both ends neutral positive charge spread evenly on both previous answers
Answers
After a great many contacts with a charged ball, the charge on the rod is arranged in such a way that the rod becomes neutral.
This is because of the process of electrical conduction, where electrons from the charged ball transfer to the rod, effectively neutralizing the charge on the ball and creating a charge distribution on the rod. Initially, the ball has an excess of electrons, which gives it a negative charge. When it comes into contact with the rod, some of these electrons transfer to the rod, creating a negative charge at one end and a positive charge at the other end. However, over time and with multiple contacts, the charges on the rod redistribute and balance out, effectively neutralizing the rod. The end result is that both ends of the rod become neutral, with no excess of electrons or shortage of electrons at either end. This process occurs because the electrons on the rod move freely and can move to any location on the rod where there is a shortage or excess of electrons.To know more about charges visit:
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If the same force is applied to each of these balls, which one will have the LEAST
acceleration
A
m 1.0 kg
B
m=7.3 kg 1
С
m=0.75 kg
D
m=0.5 kg
Answers
Answer:
d is the awnser
Explanation:
MABY?!??
A 12.0kg object is pushed with a horizontal force of 6.0N East across a table. If the force of
friction is 2.0N, what is the acceleration of the object?
Answers
Answer:
0.33m/\(s^{2}\) East.
Hope this helps you. Do mark me as brainliest.
Plzzz helppppp!!! I need answers A, B, C & D
Answers
Answer: the answer i for c is yes 0& 10
Explanation:
Pls help!!
Which situation describes a system with increasing gravitational potential energy?
a boy jumping down from a tree limb
a girl stretching a horizontal spring
a bicyclist riding up a steep hill
a train speeding up on a flat track
Answers
C) a bicyclist riding up a steep hill
The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:
A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.
Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.
what happens to the sh
ape of water when we pour the same volume of water in different containers of different shape
Answers
Answer:
It shapes into the form of the container because water is a liquid.
Explanation:
Which person will most likely hear the loudest sound?
A
B
C
D
Answers
Answer:
The youngest person
Explanation:
Hearing worsens with age
Please mark brainliest
Answer:
A
Explanation:
The person closest to the origin of the sound will most likely hear the loudest sound. ^^
Find the height or length of these natural wonders in km, m, and cm.A. A cave system with a mapped length of 354 miles.B. A waterfall that drops 1,235.2 ft.C. A 21320 ft tall mountain.
D. A canyon with a depth of 6630 ft.
Answers
Explanation:
Some standard unit conversion are 1 mile = 1.609344 km, 1 ft.= 30.48 cm,
1 km= 1000 m or 1 m = 0.001 km and 1 m= 100 cm or 1 cm=0.01 m.
Now, use these values to convert the given lengths.
A. length of cave = 5 miles (given)
From standard value 1 mile = 1.609344 km
\(\Rightarrow\) 5 miles = \(\times\) 1.609344 km= 8.04672 km,
\(\Rightarrow\) 5 miles =8.04672 \(\times\) 1000 m= 8046.72 m [ as 1 km = 1000 m]
\(\Rightarrow\) 5 miles = 8046.72 \(\times\) 100 cm=804672 cm
B. Height of the waterfall = 1235 ft. (given)
1 ft.= 30.48 cm [ from standard value]
\(\Rightarrow\) 1235.2 ft.= 1235.2\(\times\) 30.48 cm=37648.896 cm,
\(\Rightarrow\) 1235.2 ft.=37648.896 \(\times\) 0.01 m =376.48896 m [ as 1 cm = 0.01 m]
\(\Rightarrow\) 1235.2 ft.=376.48896 \(\times\) 0.001 km =0.37648896 km [ as 1 m = 0.001 km]
C. Height of the mountain= 21320 ft. (given)
From standard value: 1 ft.= 30.48 cm
\(\Rightarrow\) 21320 ft.= 21320 \(\times\) 30.48 cm=649833.6 cm,
\(\Rightarrow\) 21320 ft.=649833.6 \(\times\) 0.01 m =6498.336 m [ as 1 cm = 0.01 m]
\(\Rightarrow\) 21320 ft.=6498.336 \(\times\) 0.001 km =6.498336 km [ as 1 m = 0.001 km].
D. Depth of canyon =6630 ft.
From standard value: 1 ft.= 30.48 cm
\(\Rightarrow\) 6630 ft.= 6630 \(\times\) 30.48 cm=202082.4 cm,
\(\Rightarrow\) 6630 ft.=202082.4 \(\times\) 0.01 m =2020.824 m [ as 1 cm = 0.01 m]
\(\Rightarrow\) 6630 ft.=2020.824 \(\times\) 0.001 km =2.020824 km [ as 1 m = 0.001 km].
The light ray is traveling from Acrylite into air. The refractive index for air is 1.00. If the angle of incidence and the angle of refraction are known, how could you determine the refractive index of Acrylite?
Answers
Answer:
Refraction. A light ray traveling through some plastic has a frequency of 5.5 x 1014 Hz. It is ... making an angle of 32° with the normal to the interface; it passes through the ... [5 points] (a) What is the refractive index of the glass? ... What you do know is the wavelength of the light in glass, 321 nm, and you know the frequency.
Explanation:
The refractive index of Acrylate is determined as: ratio of sine of incident angle to sine of refractive angle.
What is Snell's law?The relationship between the angles of incidence and refraction for light or other waves flowing through a border between two different isotropic media, such as water, glass, or air, is described by Snell's law, a formula.
The amount a light ray bends as it travels through different media is measured by the refractive index.
Given that: The refractive index for air is 1.00.
Let the angle of incidence from medium air to Acrylate is = i
the angle of refraction from medium air to Acrylate is = r.
Let the refractive index for Acrylate = n.
Then according to Snell's law:
1×sini = n× sinr
n = sini/sinr.
Hence, the refractive index of Acrylate is ratio of sine of incident angle to sine of refractive angle.
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A 70 kg stunt pilot begins pulling out of a dive into a vertical circle. If the plane's speed at the lowest point of the circle is 80 m/s, what is the apparent
weight of the pilot at the lowest point of the pullout? The pilot experiences a force of 5g from the centripetal acceleration at the bottom of the dive.
O
3880 N
о
3430 N
0
4116 N
3986 N
Answers
Answer:
Apparent weight of pilot due to centripetal acceleration:
m v^2 / R = 5 g m = 5 * 70 * 9.8 = 3430 N
Weight of pilot = 70 * 9.8 = 686 N
Total = 3430 + 686 = 4116 N
Under a pressure of 862 Pa, a gas has a volume of 752 L. The pressure is increased, without changing the temperature, until the volume is 624 L. What is the new pressure?
Answers
Claims that if temperature is kept constant, the end result of both volume and pressure is constant. The new level is 1036 Pa, which is how this can be expressed.
How does pressure work?So either a strong force or a strong force applied over a short area can cause a lot of pressure. When we stand up compared to when we are walking, more of our feet are in proximity to the earth. Pressure would be lower if there was more surface area in contact.
Describe a force?An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. There are both living things and non-living objects in the concept of a force.
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write each of the following in scientific notation, correct to 2 decimal places.
a. 0.00000123 N
b. 417 000 000 kg
c. 246800 A
d. 0,00088 mm
Answers
Answer:
The scientific notation for the each number is given below:
Explanation:
The scientific notation for the following numbers are:
a. For 0.00000123 N
1.23 × 10^-6
b. For 417 000 000 kg
4.17 × 10^8
c. For 246800 A
2.47 × 10^5
d. For 0.00088m
8.8 × 10^-4
The above represent scientific notations of each numbers
A book sitting on a shelf have 740 J of potential energy, at a height of 1.8
m. What is the mass of the book?
13053.6 J
13053.6 m
41.950 kg
41.950 J
1 point
Answers
Formula: P.e.= mgh ->m= p.e/gh
We have :
p.e = 740j
g=9.8m/s^2
h=1.8
M= 740/1.8x9.8
=41.950kg